Determine the tangential and centripetal components of the net force exerted on the car (by the ground) in Example when its speed is 15 . The car's mass is

a) The angle θ1 which the righthand cable makes with respect to the ceiling is  sin^(-1)(692 N / 530 N).

b) The angle θ2 which the left-hand cable makes with respect to the ceiling is  sin^(-1)(692 N / 570 N).

We may utilise the tension of the right-hand cable as well as its vertical and horizontal components to determine the angle 1. θ2 = sin^(-1)(692 N / 570 N).

We may apply the ideas of trigonometry and vector addition to address this issue.

a) The tension of the right-hand wire as well as its vertical and horizontal components can be used to determine the angle 1.

T1sin(1) calculates the vertical component of the right-hand cable's tension, which is equal to the object's weight (692 N).

T1sin(θ1) = 692 N

We may rearrange the equation to find 1:

θ1 = sin^(-1)(692 N / T1)

We can find 1 by substituting the given tension value, T1 = 530 N:

θ1 = sin^(-1)(692 N / 530 N)

b) Similarly, we can use the formula to determine the angle 2 the left-hand cable's tension and its vertical and horizontal components.

The vertical component of the left-hand cable's tension is given by T2sin(θ2), and it should also be equal to the weight of the object (692 N).

T2sin(θ2) = 692 N

To find θ2, we can rearrange the equation:

θ2 = sin^(-1)(692 N / T2)

Substituting the given tension value T2 = 570 N, we can solve for θ2:

θ2 = sin^(-1)(692 N / 570 N)

Calculating these angles using the given tension values will provide the answers in degrees.

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A defining characteristic of a city is often referred to as a "landmark." A landmark is a distinctive feature or building that stands out and is used to identify or represent a location. Landmarks can be man-made, such as structures, monuments, or historical locations, or they can be natural, like mountains, rivers, or lakes.

Landmarks are significant tourist destinations for both locals and visitors because they frequently have historical, cultural, or architectural value. They can serve as a symbol of a city's identity, history, and personality and end up being recognised as the place's iconic symbols. Landmarks might be notable buildings, statues, cathedrals, museums, or bridges that have come to symbolise the city in which they are located.

Therefore, option (OB) "landmark" is the term used to describe a distinguishing feature in a city.

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Answer:

Hi there!

Your answer is:

A. Linear

Explanation:

Linear measurement is when you measure things in a straight line using tools such as a ruler, yardstick or tape measure. To measure height, they are using a ruler, which is a form of linear measurement!

I hope this helps!

Explanation:

Kinetic energy  = 1/2 m v^2

      = 1/2 ( 20 kg) * (100 m/s)^2 = 100 000 J

Answer:

The correct answer is C) Force. If the total force on an object is not zero, its motion will change according to the second law of motion by Isaac Newton.

Explanation:

Force=mass*acceleration

Mass=1000kg

Acceleration=25m/s

F=1000*25

F=25000N

The value of the elementary charge is

We have to find a charge equivalent to 3e.

The charge equivalent to 3e will be

Thus, the correct option is c.

Answer:

The initial velocity of Billy is 66.6 m/s.

Explanation:

Given;

acceleration of Billy, a = 12.3 m/s²

distance moved by Billy, d = 455 m

final velocity of Billy, v = 125 m/s

let the initial velocity of Billy = u

Apply the following equation of motion;

v² = u² + 2ad

125² = u² + 2(12.3 x 455)

15625 = u² + 11193

u² = 15625 - 11193

u² = 4432

u = √4432

u = 66.57 m/s

u = 66.6 m/s.

Therefore, the initial velocity of Billy is 66.6 m/s.

Answer:

Period of motion is approximately 0.5447  seconds

Explanation:

We start by calculating the constant "k" of the spring which can be derived from the fact that an object of mass 12 g produced a stretch of 3.4 cm: (we write everything in SI units)

F = k * x

0.012 kg * 9.8  m/s^2 = k 0.034 m

k = 0.012 kg * 9.8  m/s^2 / (0.034 m)

k = 3.46 N/m

now we use the formula for the period (T) of a spring of constant k with a hanging mass 'm':

\(T=2\pi\,\sqrt{\frac{m}{k} }\)

which in our case becomes:

\(T=2\pi\,\sqrt{\frac{0.026}{3.46} } \approx 0.5447\,\,sec\)

Explanation:

Yes, there are differences in the shapes of position-time graphs for uniform acceleration and uniform deceleration in different directions. Let's consider each case separately:\(\hrulefill\)

(1) - Uniform acceleration towards the positive direction:

In this case, the object is moving in the positive direction with a constant acceleration. The displacement-time graph will typically be a curve that starts from an initial position and shows a steady increase in displacement over time. The shape of the graph will depend on the specific acceleration value.

(2) - Uniform acceleration towards the negative direction:

In this case, the object is moving in the negative direction with a constant acceleration. The displacement-time graph will also be a curve, but it will show a steady decrease in displacement over time.

(3) - Uniform deceleration towards the positive direction:

In this case, the object is initially moving in the positive direction but is slowing down with a constant deceleration. The displacement-time graph will be a curve that starts with a positive slope and gradually levels off.

(4) - Uniform deceleration towards the negative direction:

In this case, the object is initially moving in the negative direction but is slowing down with a constant deceleration. The displacement-time graph will be a curve that starts with a negative slope and gradually levels off.

The magnitude of the force P provided that the stress in the part AB is two times that of BC part is 0.8 kN.

The magnitude of the force P provided that the stress in the part AB is two times that of BC part is calculated as follows;

Take moment about the joint to determine the magnitude of the force along part BC.

120 kN x 750 mm  =  F x 1000 mm

F = ( 120 kN x 750 mm ) / ( 1000 mm )

F = 90 kN

Stress is given as force divided by area. The following equation can be used to determine the magnitude of force P.

Stress in AB = 2 times stress in BC

P/A₁  = 2F/A₂

where;

A₁ =  πd²/4  =  π(50 x 10⁻³)²/4

A₁ = 1.96 x 10⁻⁵ m²

A₂ = πd²/4  =  π(75 x 10⁻³)²/4

A₂ = 4.42 x 10⁻³ m²

P/A₁ = 2F/A₂

P = (2F x A₁) / (A₂)

P = (2 x 90 kN x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = (2 x 90,000 N x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = 798.2 N

P = 0.798 kN

P ≈ 0.8 kN

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Based on the information, we can infer that A. represents a Mitochondria.

Mitochondria is a term to refer to the eukaryotic cell organelles responsible for supplying most of the energy necessary for cell activity through the process called cellular respiration.

Based on the information, we can infer that the element that is labeled with the letter A is a mitochondrion because its location is that of a mitochondrion. In this case, the mitochondria is red, although in other models it can be represented with another color. In general, it is given this shape and this color to distinguish it from other elements of the cell.

Note: This question is incomplete. Here is the complete information:

Attached image

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Answer:

___action__ force and __reaction___ force are really 2 parts of the same force.

Explanation:

The amount of work done by the gas in the given expansion is 1800 J.

The given parameters;

The amount of work done by the gas in the given expansion is calculated as follows;

W = PΔV

where;

Substitute the given parameters and solve for the work done;

W = 1000(2.4  -  0.6

W = 1800 J

Thus, the amount of work done by the gas in the given expansion is 1800 J.

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Answer:

oK so  here's  what you should do is  add .09 and 0.6

Explanation:

Answer:

planet that is farthest away is planet X

kepler's third law

Explanation:

For this exercise we can use Kepler's third law which is an application of Newton's second law to the case of the orbits of the planets

          T² = (\(\frac{4\pi ^2}{ G M_s}\) a³ = K_s a³

Let's apply this equation to our case

          a = \(\sqrt[3]{ \frac{T^2}{K_s} }\)

for this particular exercise it is not necessary to reduce the period to seconds

Plant W

             10² = K_s  \(a_{w}^3\)

             a_w = \(\sqrt[3]{ \frac{100}{ K_s} }\)

             a_w = \(\frac{1}{ \sqrt[3]{K_s} }\)  4.64

Planet X

             a_x = \(\sqrt[3]{ \frac{640^3}{K_s} }\)

             a_x = \frac{1}{ \sqrt[3]{K_s} } 74.3

Planet Y

              a_y = \(\sqrt[3]{ \frac{80^2}{K_s} }\)

              a_y = \frac{1}{ \sqrt[3]{K_s} } 18.6

Planet z

              a_z = \(\sqrt[3]{ \frac{270^2}{K_s} }\)

              a_z = \frac{1}{ \sqrt[3]{K_s} } 41.8

From the previous results we see that planet that is farthest away is planet X

where we have used kepler's third law

1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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The frequency of oscillation of the swing is 0.25 Hz.

The time period of oscillation of the swing is 4 s.

The length of the vine of the swing is 3.97 m.

The restoring force acting on Mohammed is 692.9 N.

Mass of Mohammed, m = 50 kg

Angle made by the vine with the vertical, θ = 45°

Number of complete swings made by Mohammed, n = 30

Time taken for this swing, t = 2 minutes = 120 seconds

a) The frequency of the swing is defined as the number of complete oscillations in one second.

So, the frequency of oscillation of the swing is,

f = n/t

f = 30/120

f = 0.25 Hz

b) The time period of oscillation of the swing is,

T = 1/f

T = 1/0.25

T = 4 s

c) The expression for the time period is given by,

T = 2π√(l/g)

T² = 4π² x (l/g)

l/g = T²/4π²

Therefore, the length of the vine of the swing is,

l = T²g/4π²

l = 4² x 9.8/4 x (3.14)²

l = 3.97 m

d) The restoring force acting on Mohammed,

F = mg sinθ

F = 50 x 9.8 x sin 45°

F = 490 x 1/√2 = 490/1.414

F = 692.9 N

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Answer:

D) conduction

Explanation:

Complete  Question

In a double-slit arrangement the slits are separated by a distance equal to 150 times the wavelength of the light passing through the slits. (a) What is the angular separation between the central maximum and an adjacent maximum? (b) What is the distance between these maxima on a screen 57.9 cm from the slits?

Answer:

a

  \(\theta = 0.3819^o\)

b

  \(y = 0.00386 \ m\)

Explanation:

From the question we are told that

    The slit separation is  \(d = 150 \lambda\)

    The  distance from the screen is  \(D = 57.9 \ cm = 0.579 \ m\)

Generally the condition for constructive interference is mathematically represented as

            \(dsin (\theta ) = n * \lambda\)

=>        \(\theta = sin ^{-1} [\frac{n * \lambda }{ d } ]\)

where  n is the order of the maxima  and value is 1 because we are considering the central maximum and an adjacent maximum

     and  \(\lambda\) is the wavelength of the light

So

       \(\theta = sin ^{-1} [\frac{ 1 * \lambda }{ 150 \lambda } ]\)

       \(\theta = 0.3819^o\)

Generally the distance between the maxima is mathematically represented as

       \(y = D tan (\theta )\)

=>    \(y = 0.579 tan (0.3819 )\)

=>    \(y = 0.00386 \ m\)

Answer:

here ya go

Explanation:

When a force is applied to a car, the change in motion is proportional to the force divided by the mass of the car.

An open cart with a mass of 50.0 kg is moving to the left at the a speed of 5.00 m/s at a freight company distribution centre. Don't think about the cart's contact with the floor

Fast speed test: What is it?

Your current Web speed can be estimated with the FAST.com speed test. For users who are accessing content online, download speed is extremely important, and we want Suitable for the target market to be an incredibly easy and quick speed test. Your download speed and link latency can be seen when you select.

What is an object's speed?

The speed that an object travels a distance can be conceived of as its speed. A slow-moving object travels a relatively short distance in a given length of time, whereas a fast-moving object travels a big distance in a short amount of time.

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Answer:

F= 4.3N

the question (for seo and search engine optimization to get this question to the top)

Calculate the force of gravity on the 1-kg mass if it were 3.2×106m above Earth's surface (that is, if it were one and a half Earth radii from Earth's center).

F= 4.3N

Answer:

Recuerda que la Ley de gravitación universal de Newton puede enunciarse así: “Toda partícula de

materia en el universo atrae a todas las demás partículas con una fuerza que es directamente

proporcional a las masas de las partículas e inversamente proporcional al cuadrado de la distancia que

las separa”. Ley que se puede expresar simbólicamente de la siguiente forma:

2

1 2

d

m m F ⋅ ∝

Podemos expresar la proporcionalidad de la ley de gravitación universal en forma de una ecuación

exacta introduciendo la constante de proporcionalidad G, llamada constante de gravitación universal:

2

1 2

d

m m F G ⋅ = ⋅ donde

2

Answer:

a) v = 1524.7 m/s

b) T = 8.47*10^-4 s

   λ = 1.29 m

Explanation:

a) First, in order to calculate the speed of the sound wave, you take into account that the velocity is constant, then, you use the following formula:

\(v=\frac{d}{t}\)

d: distance traveled by the sound wave, which is twice the distance to the ocean bottom = 2*324 m = 648 m

t: time that sound wave takes to return to the sub = 0.425

\(v=\frac{648m}{0.425s}=1524.7\frac{m}{s}\)

hence, the speed of the sound wave is 1524.7 m/s

b) Next, with the value of the velocity of the wave you can calculate the wavelength of the wave, by using the following formula:

\(v=\lambda f\\\\\lambda=\frac{v}{f}\)

f: frequency = 1.18*10^3 Hz

\(\lambda=\frac{1524.7m/s}{1.18*10^3s^{-1}}=1.29m\)

And the period is:

\(T=\frac{1}{f}=\frac{1}{1.18*10^3s^{-1}}=8.47*10^{-4}s\)

hence, the wavelength and period of the sound wave is, respectively, 1.29m and 8.47*10^-4 s

As the temperature of the balloon is lowered, its volume will decrease as well.

The kinetic theory of matter  says that all matter consists of many, very small particles which are constantly moving or in a continual state of motion.

According to Charles law, the volume of a fixed mass of a gas is directly proportional to its absolute temperature.

Based on Charles law, as the temperature of the balloon is lowered, its volume will decrease as well because the average kinetic energy of the gas molecules has reduced, the rate of gas collision decreased, which will cause a drop in the volume of the balloon.

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A) larger particles are more polarizable and experience stronger dispersion forces and c) dispersion forces are strongest for small particles since they can get closer together in space

Polarizability is the ability of a molecule or atom to become polarized when subjected to an external electric field. It is the measure of the ease with which the electrons in a molecule or atom can be redistributed in response to an external electric field. Polarizability is a characteristic of all molecules, atoms, and ions, and governs their behavior in electric and magnetic fields. Polarizable molecules tend to be more reactive and more capable of forming strong bonds with other molecules or atoms. Polarizability is an important factor in determining a molecule's behavior in a variety of biological, chemical, and physical processes.

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Answer:

The moon does not stay at the same distance of the earth because the ortbit of the moon is slightly elliptical. If earth is not tilted at an angle of 66.5°, there will be no change in the season and the earth will have equal length of days and night.

Explanation:

mark me brainlest