To calculate the percentage of yield we use the following formula:
percent yield = (Actual Yield/Theoretical Yield) x 100%
For trial 1:
actual yield: 0.509
theoretical yield: 0.52
percent yield: (0.509/0.52) x 100%
percent yield: 97.9%
For trial 2:
actual yield: 0.672
theoretical yield: 0.69667
percent yield: (0.672/0..69667) x 100%
percent yield: 96.5%
Answer: Trial 1: 97.9%
Trial 2: 96.5%
Which of the following substances would you predict to have the highest DHvap? Group of answer choices CH3CH2CH2CH3 CH3CH2OH HF CH3Cl HOCH2CH2OH
Answer:
a) \(CH_3CH_2CH_2CH_3\)
Explanation:
In this question we have the following answer choices:
a) \(CH_3CH_2CH_2CH_3\)
b) \(CH_3CH_2OH\)
c) \(HF\)
d) \(CH_3Cl\)
e) \(HOCH_2CH_2OH\)
We have to remember the relationship between intermolecular forces and vapor pressure. If we have stronger intermolecular forces we will have less vapor pressure because the molecules have more interactions between them, so, the molecules will prefer to stay in a liquid state rather than a gaseous state. Now, we have to check each molecule:
a) \(CH_3CH_2CH_2CH_3\) (Van der waals interactions)
b) \(CH_3CH_2OH\) (Hydrogen bonding)
c) \(HF\) (Hydrogen bonding)
d) \(CH_3Cl\) (Dipole-dipole interaction)
e) \(HOCH_2CH_2OH\) (Hydrogen bonding)
For molecules b, c and e we have hydrogen bond to a heteroatom (O, N, S, or P). In this case oxygen, therefore we will have hydrogen bonding interactions (a very strong interaction). So, we can discard these ones.
In molecule e, we have "Cl" bond to a "C" therefore we will have the presence of a dipole (due to the electronegativity difference). If we have a dipole, we will have a dipole-dipole interaction (a strong interaction, less than hydrogen bonding but still is a strong interaction).
In molecule a, we have only Van der Waals interactions because in this molecule we have only carbon and hydrogen atoms bonded by single bonds. So, we will have a non-polar molecule. These interactions are the weakest interactions of all the molecules given. So, if we have weaker interactions the molecules can be converted to a gas state more easily and we have more vapor pressure.
Disadvantage and advantage of iodine ?
- umoren sŭm..
THE ADVANTAGE OF IODIN
IODINE CAN LEAD TO GOITER AND OTHER THYROID PROBLEMS.THE DISADVANTAGE OF IODIN
IODIN MAY LEAD TO THYROIDITIS AND THYROID PAPILLARY CANCERWhat type of bonding does Ir and Hg have?
Iridium forms metallic bonds, while mercury exhibits a combination of metallic and covalent bonding. These covalent interactions give rise to the low boiling point and weak intermolecular forces in liquid mercury.
Iridium (Ir) and mercury (Hg) exhibit different types of bonding based on their electronic configurations and properties.
Iridium is a transition metal belonging to Group 9 of the periodic table. It has a partially filled d-orbital in its atomic structure, which allows it to form metallic bonds. Metallic bonding occurs when the outer electrons of metal atoms are delocalized and form a "sea" of electrons that are free to move throughout the crystal lattice. This results in the characteristic properties of metals, such as high electrical and thermal conductivity, malleability, and ductility. Iridium forms metallic bonds with other iridium atoms, contributing to its solid, dense, and lustrous nature.
Mercury, on the other hand, is a unique element. It is a transition metal, but it exhibits characteristics of both metallic and covalent bonding. At room temperature, mercury exists as a liquid, which is highly unusual for a metal. This is because mercury atoms have a weak interatomic interaction, known as metallic bonding, similar to other metals. However, due to the presence of unpaired electrons in its 6s orbital, mercury can also form weak covalent bonds. These covalent interactions give rise to the low boiling point and weak intermolecular forces in liquid mercury.
In summary, iridium forms metallic bonds, while mercury exhibits a combination of metallic and covalent bonding.
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How many MOLES of sulfur hexafluoride are present in 2.33x1022 molecules of this compound
Answer:
0.0387 moles SF₆
Explanation:
To find the moles of sulfur hexafluoride (SF₆), you need to multiply the number of molecules by Avogadro's number. Avogadro's number is a ratio between molecules and moles. It is important to arrange the conversion in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs to match the sig figs of the given value (2.33 x 10²²).
Avogadro's Number:
6.022 x 10²³ molecules = 1 mole
2.33 x 10²² molecules SF₆ 1 mole
--------------------------------------- x ------------------------------------ = 0.0387 moles SF₆
6.022 x 10²³ molecules
An empty balloon sits 10 meters away from a golf ball. Jamie wants to increase the
gravitational force between the two objects by filling the balloon with a substance. Which
of the following substances will most likely increase the gravitational force between the
balloon and the golf ball?
An empty balloon sits 10 meters away from a golf ball. Jamie wants to increase the
gravitational force between the two objects by filling the balloon with a substance. Which
of the following substances will most likely increase the gravitational force between the
balloon and the golf ball?
water
cotton
air
lead pieces
To increase the gravitational force between the balloon and the golf ball, It should be filled with lead pieces. Option D
What should be done?A substance's density, which measures its mass in relation to its volume, determines how much gravitational force it produces.
Lead bits are one of the suggested materials, and they are the one that would most likely boost the gravitational force. The density of lead is much higher than that of the other listed materials.
The high density of lead will result in an increase in the gravitational pull between the balloon and the golf ball if Jamie fills the balloon with lead bits.
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Is the cell wall factory part or worker? And please explain what the worker or factory part does. (Don’t tell me it’s on quizlet bc I can’t find it)
For the reaction
2NH3(g)↽−−⇀ 3H2(g)+N2(g)
the equilibrium concentrations were found to be [NH3]=0.250 M, [H2]=0.470 M, and [N2]=0.800 M. What is the equilibrium constant for this reaction?
eq=
Rounding to the appropriate number of significant figures, the equilibrium constant (Kc) for the reaction is approximately 1.66.
To calculate the equilibrium constant (Kc) for the given reaction, we can use the formula:
Kc = ([H2]^3 * [N2]) / [NH3]^2
Plugging in the given equilibrium concentrations, we have:
Kc = (0.470^3 * 0.800) / (0.250^2)
Calculating the numerator:
(0.470^3 * 0.800) = 0.1037032
Calculating the denominator:
(0.250^2) = 0.0625
Now, dividing the numerator by the denominator:
Kc = 0.1037032 / 0.0625 = 1.6592512
The equilibrium constant represents the ratio of the concentrations of products to reactants at equilibrium. In this case, the equilibrium constant is greater than 1, indicating that the products (H2 and N2) are favored at equilibrium. This means that the forward reaction is favored, leading to the formation of more products compared to reactants.The equilibrium constant value of 1.66 suggests that the forward reaction is moderately favored at equilibrium, but without additional context, it is difficult to determine the extent of the reaction or the relative concentrations of reactants and products at the beginning of the reaction.
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Which of the following limits a population's growth?
Answer: Limitations to population growth are either density-dependant or density-independent. Density-dependent factors include disease, competition, and predation. Density-dependant factors can have either a positive or a negative correlation to population size.
Explanation:
Calcular la normalidad de 1 Kg de sulfuro de aluminio en 5000 ml de solucion.
Calculate the normality of 1 Kg of aluminum sulfide in 5000 ml of solution.
Normality comes out to be 8.11
Given Mass of solute: 1000gVolume of solution (V): 5000 ml = 5 liters Equivalent mass of solute (E) = molar mass / n-factorn-factor for \(Al_{2}S_{3}\) is 6 and molar mass is 148g
So, on calculating equivalent mass is equal to 24.66g
FORMULAE of Normality (N) = (Mass of the solute) / (Equivalent mass of the solute (E) × Volume of the solution (V)
N=\(\frac{1000}{24.66*5}\)
N=8.11
Therefore, normality of 1 kg aluminum sulfide is 8.11
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How many moles of KBr are dissolved in 50.2 mL of a 1.50 M solution?
Answer:
There are 0.0753 moles of KBr.
Explanation:
The molarity of the solution tells us that there are 1.50 moles of KBr in 1000mL of solution.
But we only have 50.2mL of solution, so with a mathematical rule of three we can calculate the amount of moles in 50.2mL:
\(\begin{gathered} 1000mL-1.50moles \\ 50.2mL-x=\frac{50.2mL*1.50moles}{1000mL} \\ x=0.0753moles \end{gathered}\)So, there are 0.0753 moles of KBr.
i need help with chemistry equation
The volume of concentrated acid that must be added to obtain a total volume of 50ml is = 0.967ml.
What is an acid?An acid is defined as the substance that is capable of donating it's hydrogen ion as the only positive ion in a chemical reaction.
The concentration of stock solution (M¹) = 6.00M.
The concentration of dilution that is needed (M²) = 0.116M.
The volume of the dilution to be used (V²) = 50.0 ML.
The volume of the stock solution to be used (V¹) = xML.
Using the formula;
M¹V¹= M²V²
Make V¹ = M²V²/M¹
V¹= 0.116 × 50/ 6
V¹= 5.8/6
V¹= 0.967ml
Therefore, the amount of concentrated acid (which is the stock solution) that would be used for dilution= 0.967ml.
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Name the following compound: H₂SO₄ *
Answer:
Sulfuric acid
Explanation:
Hope that helps!
How to polymers work?
Answer:
A polymer is any of a class of natural or synthetic substances composed of very large molecules, called macromolecules, which are multiples of simpler chemical units. Polymers make up many of the materials in living organisms and are the basis of many minerals.
Explanation:
Explanation:
The first man-made polymers were actually modified versions of these natural polymers. Celluloid, the stuff from which silent-movie film was made, was a plastic created from chemically modified cellulose. The first completely synthetic polymer (that is, made by people through chemical synthesis), invented in the early years of the twentieth century, was Bakelite: a plastic made by reacting phenol and formaldehyde under pressure at high temperatures.
# be careful #
what is the heat of fusion of water in calories per mole? Answer with explanation
Answer:
1436.2 calories per mole H2O
Explanation:
one mole of water has mole weight of 2 * H + O =
2 * 1.008 + 15.999 = 18.015 gm
the heat of fusion for water (the heat required to turn ice to water )
is 79.72 cal/gm
18.015 gm * 79.72 cal/gm = 1436.2 cal
PLEASE HELP 85 POINTS!
Aluminum chloride is a white compound that contains one aluminum atom and three chlorine atoms.
Which model is the best representation of aluminum chloride?
O A.
B.
Al
Cl
Al
Cl
O C.
D.
Cl
Al
Al
Cl
Answer:
Model B (in image) would the best representation of aluminum chloride.
Explanation:
It's the only model the has three chlorine atoms and one aluminum atom.
Additionally, Cl can only bond once, so it can't be bonded to multiple different atoms. Also, Al needs to have more than one bond to achieve the octet rule.
Strontium hydroxide reacts with hydrobromic acid to produce Strontium bromide and
water.
Write and balance the chemical reaction above, use it for problems 1-4 below:
1. If 5.50 moles of strontium hydroxide were consumed, how much moles of water are
produced?
2. Find the mass of hydrobromic acid used to produce 7.50 moles water.
3. If 10.8 g of strontium hydroxide were used, how much moles of strontium bromide are
produced?
4. If 13.3 g of hydrobromic acid were consumed, find the mass of the water produced.
how many core electrons does magnesium ion have
Answer:
10 core electrons
Explanation:
Answer:
Magnesium has 10 core electrons
which is an example of a colloid? a mixture that settles out, a mixture that scatters light, a mixture that is separated by filtration, or a salt and water mixture?
These substances have dispersed particles that are large enough to scatter light, making the beam visible. Therefore, out of the options provided, a mixture that scatters light is an example of a colloid. Option B)
A colloid is a type of mixture in which particles are dispersed throughout a medium, creating a homogeneous appearance. Unlike solutions, where the particles are completely dissolved, and suspensions, where the particles settle out, colloids have particles that are larger than those in solutions but smaller than those in suspensions. One characteristic of colloids is that they can scatter light due to the size of the particles. This scattering of light is known as the Tyndall effect. Examples of colloids include milk, fog, and aerosol sprays. These substances have dispersed particles that are large enough to scatter light, making the beam visible. Therefore, out of the options provided, a mixture that scatters light is an example of a colloid. Therefore option B) is correct
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Note Complete Question
which is an example of a colloid?
a mixture that settles out,
b mixture that scatters light,
c mixture that is separated by filtration,
d salt and water mixture?
A 20.0 g sample of aluminum (specific heat = 0.902) g-1 oC-1) with an initial temperature of 2.5°C is heated with 427 J of
energy. What is the final temperature of the sample?
O 72.3°C
O 23.7°C
0 26.2°C
0 74.8°C
O 24.9°C
Answer:
T(final) = 26.2°C (3 sig. figs.)
Explanation:
Q = m·c·ΔT
m = mass of sample of interest = 20.0g
c = specific heat of sample of interest = 0.902j·g⁻¹·C⁻¹
ΔT = Temperature change = T(final) - T(initial) = T(f) - 2.5°C
Q = 427 joules
Q = m·c·ΔT => = ΔT = Q/m·c => T(f) = Q/m·c + T(i) = (427j/20.0g·0.902j·g⁻¹·C⁻¹) + 2.5°C = 26.16962306°C (calc. ans.) ≅ 26.2°C (3 sig. figs.)
The location oon the surface of the Earth directly above the focus of an earthquake
is called the
A.focus point
B.seismic wave
C.epicenter
Answer:
I think its epicenter
Explanation:
The epicenter is the point on the earth's surface vertically above the hypocenter, point in the crust where a seismic rupture begins.
Ag(s) | Agtay) || Cl2(9) Claq)
For the cell notation shown, which species is undergoing reduction?
OA) Cl2(g)
B) Agtag)
C) Ag(s)
D) Claa)
If you have 25 moles of water, H2O, how many molecules of water do you have?
Answer:
The number of molecules of water us 1.50× 10²⁵ molecules
Explanation:
From N=nL
where L =avogadro number ( 6.02× 10^²³ entities)
The number of the molecules of water =1
n (amount of substance)=25 moles
hence (N) = 25×1×6.02×10^²³
=1.50×10²⁵ molecules of H2O
A 25 ml solution of 0.5 M NaOH is titrated until neutralized into a 50 ml sample of HCl?
The concentration of the acid is \(0.25 M\).
Titration is a laboratory technique used to determine the concentration of a substance in a solution by reacting it with a standardized solution of known concentration.
The titration formula can be given by,
(Volume of the Base) \(\times\) (Normality of the Base) = (Volume of the Acid) \(\times\) (Normality of the Acid)
\(\Rightarrow V_1N_1=V_2N_2\)
Given, the volume of the base (\(NaOH\)), \(V_1 =25 ml\).
The concentration of the base (\(NaOH\)), \(M_1=0.5 M\).
The equivalence of the base (\(NaOH\)) is \(1\).
Hence, the normality of the base (\(NaOH\)), \(N_1=\frac{0.5}{1}N=0.5N\).
Given, the volume of the acid (\(HCl\)), \(V_2 =50 ml\).
Let us assume that the normality of the acid (\(HCl\)) \(N_2\).
Substitute the values in the given formula of titration.
\((25\times0.5)=(50 \times N_2)\\\Rightarrow 12.5=50N_2\\\Rightarrow N_2=\frac{12.5}{50} N\\\Rightarrow N_2=0.25 N\)
Hence, the normality of the acid (\(HCl\)), \(N_2=0.25 N\).
The equivalence of the acid (\(HCl\)) is \(1\).
Therefore, the concentration of the acid, \(M_1=\frac{0.25}{1}=0.25 M\).
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What type of human problems can arise from acid rain?
Answer:
ooooo okkk
Explanation:
so if there was acid rain some problems would be like finding food and shelter. the world would go even weirder then it is now lol. but our food would be gone and we would need to adaot and find acid proof shelter. many people would be lost and ya our water would also get poisened ands such
Answer:
Contanimation of food and water sources; this is even more serious because all life is interconnected, and the negative effects of acid rain therefore spread throughout; respiratory problems could arise in people; negative effects on infrastructure (corrosion)
Learning task 1: as you start exploring the subject answer the following question write your answer on your answer sheet
need help pls
In this exercise, it is necessary to know the systems that our bodies have and complete the sheet that will correspond to these answers:
1- Digestive
2- Urinary
3- Respiratory
4- Skeletal
5- Muscular
6- Integumentary
7- Cardiovascular
8- Endocrine
9- Nervous
10- Reproductive
So looking in more detail, the number one corresponds to the digestive system because it is the digestive process that starts in the mouth. The second is related to the urinary system, which is responsible for the filtration and elimination of excess water. The respiratory system corresponds to the third option, which is the gas exchange that occurs in the pulmonary alveoli.
The numbers 4, 5, and 6 are very important systems for the support of the human body, being respectively the skeleton system, the muscular system, and the integumentary system. The first system is responsible for support while the second is better known for locomotion and finally the third is known for covering the human body by the dermis.
The cardiovascular system is responsible for getting the blood transported throughout the body and pumped by the heart, so this system is related to number 7. Then the endocrine system is responsible for the hormones and how these hormones acted in the body and are number 8.
The number 9 corresponds to one of the most complex and principal systems, the nervous system, which has neurons as its cells and transmits the nervous impulse in response.
The last treated system is the reproductive system, known for its reproductive gametes, and its most important role is to maintain the reproduction of the species.
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When zinc reacts with copper sulfate solution, zinc sulfate solution and copper are formed.(i) An experiment was carried out to measure the temperature change when zinc powder reactswith copper sulfate solution.initial temperature of copper sulfate solution = 20 °Cfinal temperature of mixture after the reaction = 46 °CExplain what the temperature readings show about the type of heat change that occurs duringthis reaction.
The temperature increase from 20 °C to 46 °C indicates that the reaction between zinc and copper sulfate solution is exothermic, with heat being released into the surroundings.
In the given reaction between zinc and copper sulfate solution, the temperature change can provide insights into the type of heat change occurring during the reaction. Based on the provided information, the initial temperature of the copper sulfate solution was 20 °C, and the final temperature of the mixture after the reaction was 46 °C.
The temperature increase observed in this reaction indicates an exothermic heat change. An exothermic reaction releases heat energy into the surroundings, resulting in a temperature rise. In this case, the reaction between zinc and copper sulfate solution is exothermic because the final temperature is higher than the initial temperature.
During the reaction, zinc displaces copper from copper sulfate to form zinc sulfate and copper metal. This displacement reaction is known as a single displacement or redox reaction. Zinc is more reactive than copper and therefore replaces copper in the compound.
The formation of new chemical bonds during the reaction releases energy in the form of heat. This energy is transferred to the surroundings, leading to an increase in temperature. The heat released is greater than the heat absorbed, resulting in a net increase in temperature.
The exothermic nature of this reaction can be explained by the difference in bond energies between the reactants and products. The breaking of bonds in the reactants requires energy input, while the formation of new bonds in the products releases energy.
In this case, the energy released during the formation of zinc sulfate and copper metal is greater than the energy required to break the bonds in copper sulfate and zinc.
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How are solutions and compounds similar?
Answer:
hope you liked it!!!!!!
A compound is a pure substance that is composed of elements chemically bonded in definite proportions. A compound can be broken down into simpler substances only by chemical reactions, such as electrolysis.
A solution is a homogeneous mixture, meaning that it is the same throughout. A solution is composed of one or more solutes dissolved in a solvent. The proportions of the solute(s) can vary, as the components of a solution are not chemically bonded. The components of a mixture can be separated by physical means, such as filtration and distillation
What mass of sucrose, C12H22O11, Would be added to 3200g of water to make it boil at 101.3
Explanation:
To make water boil at 101.3°C, we need to increase its boiling point from 100°C to 101.3°C. This means we need to increase the boiling point elevation by ΔTb = 1.3°C.
The boiling point elevation is given by the formula:
ΔTb = Kb * m
where Kb is the molal boiling point constant for water (0.512°C/m) and m is the molality of the solution.
We can rearrange this formula to solve for m:
m = ΔTb / Kb
m = 1.3°C / 0.512°C/m
m = 2.54 m
This tells us that the molality of the solution must be 2.54 m in order to increase the boiling point of water by 1.3°C.
The molality of a solution is defined as the number of moles of solute per kilogram of solvent. We can use the molecular weight of sucrose to convert from mass to moles:
Molecular weight of sucrose = 12*12 + 22*1 + 11*16 = 342 g/mol
To find the mass of sucrose needed to make a 2.54 m solution in 3200 g of water, we can use the following equation:
molality = moles of solute / (mass of solvent in kg)
Rearranging this equation gives:
moles of solute = molality * mass of solvent in kg
moles of sucrose = 2.54 mol/kg * (3200 g / 1000 g/kg) = 8.128 mol
mass of sucrose = moles of sucrose * molecular weight of sucrose
mass of sucrose = 8.128 mol * 342 g/mol = 2775.936 g
Therefore, we need 2775.936 g (or about 2.78 kg) of sucrose to add to 3200 g of water to create a 2.54 m solution that will boil at 101.3°C.
Wireless Internet networks, including many used in homes, often make use of high-frequency radio waves. High-frequency waves are useful because they can carry a lot of information. However, high-frequency waves are less capable of passing through objects than are low-frequency waves. As a result, waves traveling from a person's wireless laptop computer, for example, could be interrupted by objects between the computer and the modem.
Due to this limitation of high frequency waves, which of the following statements best explains why digital waves are commonly used in high-frequency wireless networks instead of analog waves?
Digital waves are commonly used in high-frequency wireless networks instead of analog waves because digital signals are less susceptible to interference from obstacles and noise.
Analog signals vary continuously over time and can be affected by various forms of interference, such as distortion or attenuation, which can result in the loss or corruption of information.
In contrast, digital signals are represented as a series of discrete values or binary digits, which are more resilient to interference and can be easily reconstructed at the receiving end. Digital signals are also easier to compress, allowing for more efficient use of the available bandwidth and higher data transfer rates.
Therefore, digital signals are the preferred choice for high-frequency wireless networks as they provide reliable, high-speed data transmission while minimizing the impact of interference and signal loss caused by obstacles.
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Zoey makes sweetened ice tea by mixing ice tea powder and sugar in water. What changes occur in the physical properties of the ingredients in the sweetened iced tea solution?
Is it:
A: The iced tea powder remains a solid, and the sugar dissolves in the water
B: The iced tea powder dissolves in the water, and the sugar remains a solid.
C: The iced tea powder becomes a gas in the water, and the sugar dissolves in the water.
D: Both the iced tea powder and the sugar dissolve in the water
Answer:
D both iced tea powder and sugar dissolves in water.
Both are soluble in water and will dissolve in water.