Determine the Molar mass of NI3

we need approximately 28.57 liters of a 70% alcohol solution to add to 50 liters of a 40% alcohol solution.

To find out how many liters of a 70% alcohol solution must be added to 50 liters of a 40% alcohol solution, we can use the following formula:

$$\text{Volume of 70% alcohol solution} = \frac{\text{Amount of pure alcohol needed}}{\text{Concentration of pure alcohol}}$$Let V be the volume of the 70% alcohol solution needed.

Then, the amount of pure alcohol needed is 0.7V, since the concentration of the 70% alcohol solution is 70%.Similarly, the amount of pure alcohol in 50 liters of a 40% alcohol solution is 0.4(50) = 20 liters. Therefore, we can set up an equation:$$0.7V = 20$$Solving for V, we get:$$V = \frac{20}{0.7} \ approx 28.57$$Therefore, we need approximately 28.57 liters of a 70% alcohol solution to add to 50 liters of a 40% alcohol solution.

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The quantity of heat absorbed by 20 g of water as it warms from 30 °C to 90 °C is 1200 calories. To calculate the quantity of heat absorbed by the water, we can use the formula:

Q = m * c * ΔT

Where:

Q is the quantity of heat absorbed,

m is the mass of the water (in grams),

c is the specific heat capacity of water (which is approximately 1 calorie/gram·°C),

ΔT is the change in temperature (final temperature minus initial temperature).

In this case, we have:

m = 20 g (the mass of water)

c = 1 calorie/gram·°C (specific heat capacity of water)

ΔT = 90 °C - 30 °C = 60 °C (change in temperature)

Substituting the values into the formula, we get:

Q = 20 g * 1 calorie/gram·°C * 60 °C

Q = 1200 calories

Therefore, the quantity of heat absorbed by 20 g of water as it warms from 30 °C to 90 °C is 1200 calories.

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The red-colored blocks indicate non metals in the periodic table. Nonmetals are located on the right side of the periodic table, in the p-block.

Non-metals are composed of a variety of elements, such as carbon, nitrogen, oxygen, sulfur, phosphorus, and selenium. These elements are generally non-reactive, but some of them can form compounds with other elements. They are also used in various industries, such as the production of plastics, fertilizers, and explosives. Non-metals are divided into two categories: metalloids and non-metalloids. Nonmetals are characterized by their lack of luster and their low thermal conductivity.

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Answer:

3.28

Explanation:

At some point it is best to write out an equation to cancel out the units you don't want and to get to the units that you do want.  So if you write this out in an equation, you can see how you get to the answer.

43 m           3.28 ft             ?  ft

--------   X    -----------  =   --------------

   1                  1 m                  1

You can see now that the meters on the top will cancel out the meters on the bottom so all you are left with is the feet unit.  When you write out the equation you put the unit on the bottom that you want to get rid of (meter).  You put the unit you want to get to on the top which is feet.   At this point you just have to know how many feet 1 meter is equal to and plug those number in.  1 meter is equal to 3.28 feet.

Bonding electrons are involved in the formation of chemical bonds, whereas lone pair electrons are not involved in bond formation and occupy atomic orbitals.

Bonding electrons are electrons that are involved in forming chemical bonds between atoms. In covalent bonds, atoms share electrons to achieve a full outer electron shell and attain stability. The number of bonding electrons is determined by the electron configuration of the atoms involved in the bond and their relative electronegativities.

Lone pair electrons, on the other hand, are non-bonding electrons that are not involved in forming chemical bonds. These electrons are found in the outermost electron shell of an atom and can be thought of as "unpaired" electrons. Lone pair electrons occupy atomic orbitals and do not participate in bond formation. Instead, they have a significant impact on molecular shape and reactivity due to their repulsive forces.

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Answer:

Gravity

Explanation:

Electromagnetic radiation is self-sustaining energy with electric and magnetic field components.

Answer:

Change in colour will be the answer.

At a given temperature, different liquids will have different equilibrium vapor pressures because the vapor pressure of a liquid depends on its intermolecular forces, molecular weight, and temperature. The equilibrium vapor pressure is a measure of the tendency of a liquid to evaporate and become a gas at a specific temperature.

Intermolecular forces, such as hydrogen bonding or London dispersion forces, play a significant role in determining the strength of attractions between molecules in a liquid. Liquids with stronger intermolecular forces will have lower vapor pressures because it requires more energy to overcome these forces and transition into the gas phase.

Molecular weight also influences vapor pressure. Generally, liquids with larger and heavier molecules will have lower vapor pressures compared to liquids with smaller and lighter molecules. This is because larger molecules have stronger intermolecular forces and require more energy to transition into the gas phase.

Furthermore, temperature affects the vapor pressure of a liquid. As the temperature increases, the average kinetic energy of the liquid molecules increases, resulting in more molecules with sufficient energy to overcome intermolecular forces and transition into the gas phase. Therefore, at higher temperatures, the vapor pressure of a liquid increases.

In summary, the equilibrium vapor pressure of a liquid is determined by the interplay of intermolecular forces, molecular weight, and temperature. Different liquids with varying intermolecular forces and molecular weights will exhibit different equilibrium vapor pressures at the same temperature.

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Answer:

mass number=9

atomic number=4

Explanation:

protons =4(protons is the same as atomic number)

neutrons=mass number-protons=3

electrons=4(it is the same as protons because it didn't gain or loose a charge)

Answer:

NH4Cl (s) → NH3 (g) + HCl (aq)

Answer:

its totally d

Explanation:

Answer:

The molar mass of a substance is calculated as the mass of a given chemical compound or substance, which is then divided by the amount of the substance. The mass is calculated in grams and the amount of the substance is calculated in mol. Thus, the standard unit for molar mass is g/mol.

Explanation:

According to the given question, the reaction between iron chloride and sodium carbonate will be given as:  

\(\text {3Na_{2}CO_{3}\text} \;\[+\] \;\text{ 2FeCl_{3} \text}\; \rightarrow\; \text {6NaCl}\; \[+\] \;\text { Fe_{2} (CO_3)_{3} \text}\)

Now, to calculate the mass of iron carbonate formed in the above chemical reaction, it will be given as:

\({ \text Moles\;of}\text \;\text {FeCl_{3} \text} \[=\dfrac{0.15 \;\text {moles} \times 0.015\; \text L}{1.0 { \;\text L}\text}\)

                          \(=\;0.00225\; \text {moles}\text\)

Similarly, for sodium carbonate

\(\text Moles\; of\; Na_{2}CO_{3}}\te \[=\]\dfrac{0.15 \;\text {moles} \times 0.020\; \text L}{1.0 { \;\text L}\text}\\\)

                             \(\[=\]\;0.0003\; {\text moles \text}\)

Limiting reactant is \(\text {FeCl_{3} \text}\)

Now, calculating iron chloride mass:

\(=\dfrac{0.00225 \times 1\;\text{moles}\;\text{Fe}_2 {(\text{CO}_3)}}{2\;\rm{moles\;of\;}Fecl_3}\)

\(=0.001125 \;\text {moles }\)

Now, molar mass of the \(\text{Fe}_{2}\text{CO}_{3}\)  will be  \(=291.71679\;\text{g/ mol}\)

\(\begin{aligned}\text{Mass}&=\frac{\text{Moles}}{\text{Molar mass}}\\\\&=\frac{0.001125\;\text{moles}}{291.71679\; \text{g/mol}} \\\\&=3.85648\times10^{-6} \end{aligned}\)

The percent yield of CCl₄ from the reaction of 18.0 g of carbon disulphide with 22.0 grams of Cl₂ is 77.3%

Equation of reaction:

CS₂ +  3 Cl₂ ----> CCl₄ +  S₂Cl₂

molar mass of CS₂ = 78 g/mol

molar mass of Cl₂ = 71 g/mol

molar mass of CCl₄ = 154 g/mol

78 g of CS₂ reacts with  * 71 g of Cl₂

78 g of CS₂ reacts with 213 g of Cl₂

18 g of CS₂ reacts with 213 * 18/ 78 g of Cl₂

18 g of CS₂ requires 49.1 g of Cl₂

3 moles of Cl₂ produces 1 mole of CCl₄

213 g of Cl₂ produces 154 g of CCl₄

22.0 g of Cl₂ will produce 154 * 22 / 213 g of CCl₄

22.0 g of Cl₂ will produce 15.9 g of CCl₄

Actual yield = 12.3 g

Expected yield = 15.9 g

Percent yield = 12.3/15.9) * 100%

Percent yield = 77.3 %

The percent yield of CCl₄ from the reaction of 18.0 g of carbon disulphide with 22.0 grams of Cl₂ is 77.3%

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Approximately 78% of the atmosphere is composed of nitrogen gas.

The envelope of gases surrounding the Earth or another celestial body is referred to as the atmosphere. It is held in place by the planet's gravity. The atmosphere protects life on Earth by absorbing ultraviolet solar radiation, warming the surface through heat retention (greenhouse effect), and reducing temperature extremes between day and night (the diurnal temperature variation).

The atmosphere consists of various gases, including nitrogen, oxygen, and carbon dioxide. The percentage of each gas present in the atmosphere is referred to as its composition. The atmosphere of the Earth is made up of 78.08% nitrogen, 20.95% oxygen, 0.93% argon, and trace amounts of other gases such as carbon dioxide, neon, helium, and methane.

The following are the various layers of Earth's atmosphere:

Exosphere

Thermosphere

Mesosphere

Stratosphere

Troposphere

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To find the number of moles of H₂O required, we need to determine the molar ratio between H3PO3 and H₂O in the balanced equation.

From the balanced equation:

P2O3 + 3H₂O → 2H3PO3

We can see that 2 moles of H3PO3 are produced from 3 moles of H₂O.

To calculate the number of moles of H₂O, we can set up a proportion using the molar ratios:

2 moles H3PO3 / 3 moles H₂O = 164 g H3PO3 / x moles H₂O

Cross-multiplying the proportion, we have:

2 moles H3PO3 * x moles H₂O = 3 moles H₂O * 164 g H3PO3

2x = 3 * 164

Simplifying:

2x = 492

x = 492 / 2

x = 246

Therefore, 246 moles of H₂O are required.

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Answer:

3

Explanation:

Answer:

cells, like plants and animals, also have membrane-bound nuclei and organelles (e.g., mitochondria, cytoplasmic curriculum, lysosomes). Cheek cells, like other squamous cells in animals, appear scale-like under the microscope.

Hope this helps!! if it does...

Plants and animal cell also have membrane-bound nuclei and organelles (e.g., mitochondria, cytoplasmic curriculum, lysosomes). Cheek cells, like other squamous cells in animals, appear scale-like under the microscope.

Cell is defined as the base of life as it is the structural as well as functional unit of life. Cell is made up of pre existing cells and the cell contain various cell organelles such as mitochondria, endoplasmic reticulum, ribosomes, golgi appratus, nucleus, and cytoplasm.

Basically, cell is of two type one in prokaryotic and another one is eukaryotic. The prokaryotic cell is known as pre mature cells as they do not contain cell organelles and eukaryotic cell are known as advanced and developed cells as they contain several cell organelles.

The unicellular animals are made up of single cell and all the functions carried out in a single cell like amoeba and multicellular organisms are made up of multiple cells and there is specific cell for specific functions.

Therefore, Plants and animal cell also have membrane-bound nuclei and organelles (e.g., mitochondria, cytoplasmic curriculum, lysosomes). Cheek cells, like other squamous cells in animals, appear scale-like under the microscope.

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Answer:

d

Explanation:

Answer:

D - g/mol

step by step method

The elements that make up the solid bonding patterns between atoms is the characteristic of a solid is most responsible for their structure.

When the forces binding atoms or molecules together are greater than the energy separating them, solids are created. Atomic bonding patterns are one of the most crucial elements that determine the final physical makeup of a given solid item. The more solid an object is, the stronger the bond pattern. Solids have hard, rigidly defined shapes and volumes. Around fixed axes, particles oscillate. Strong intermolecular interactions, or strong interactions between molecules, result in the tight aggregation and fixed locations of solids' molecules. Solid particles are strongly attracted to one another.

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Answer:

tell me the question i cant see the picture

Explanation:

Answer:

the correct answer is D

Explanation:

D

The diagram which shows the correct way to represent the ionic compound, magnesium oxide is option D.

Electron dot structure is a representation of the valence electrons of an element, represented by the dots around the symbol of the element.

An ionic compound is formed by the combination of two or more ions. Note that the two ions that compose an ionic bond are held purely by electrostatic interaction of the oppositely charged ions.

The correct depiction of MgO is the arrangement in which the two ions, \(Mg^{2+}\) and \(O^{2-}\) are placed in different brackets and the oxygen ion has a complete octet as seen in option D.

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Kilocalorie is a unit of measuring the amount of energy of a reaction, but this is not the only unit, we can also have Joules as a unit, and the conversion is:

1 Kcal = 4184 Joules

Therefore if we have 3.25 Kcal, we will have:

3.25 * 4184 = 13600 Joules of energy, therefore letter D

The neutral atom with an atomic number of 1 and a mass number of 1 is Hydrogen (H).

The neutral atom with an atomic number of 11 and a mass number of 23 is Sodium (Na).

The neutral atom with an atomic number of 7 and a mass number of 14 is Nitrogen (N).

The atomic number of an element corresponds to the number of protons in its nucleus, which determines its identity. The mass number represents the total number of protons and neutrons in an atom.

For the first atom, with an atomic number of 1 and a mass number of 1, there is only one proton and no neutrons, which corresponds to Hydrogen (H).

The second atom, with an atomic number of 11 and a mass number of 23, has 11 protons and 12 neutrons. This corresponds to the element Sodium (Na).

The third atom, with an atomic number of 7 and a mass number of 14, has 7 protons and 7 neutrons, which corresponds to Nitrogen (N).

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The amount of solid iron (III) acetate required to make an aqueous solution of 0.167 M  of iron (III) acetate using 125 ml volumetric flask is 13.5g.

To address this problem, molarity, number of moles, ion molarity

To determine the molarity of a solution, divide the amount of solute in moles by the volume of the solution in liters. Calculate the number of moles by dividing the substance's mass by its molar mass. To calculate the ion concentration, multiply the molarity of the ionic compound by the mole ratio.

The formula for calculating the molarity of a solution is

M = n/V

Here, n is the number of moles of solute and V is the volume of solution in liters.

The number of moles of a substance, use the formula

n = m/MM

where MM represents the molar mass of the substance and m stands for the mass of the substance.

The molarity iron (III) acetate is 0.167 M

Volume of a solution is 0.125 mL

So V = 125ml(1L/1000ml)

        = 0.125L

The molarity  of a solution is calculated as:

M = n/V

Rearrange the above equation for .

n=MxV

Substitute 0.167 M for M and 0.125 L for V

n=0.167 Mx0.125 L =0.0208 (mel 1) = 0.0208 mol

The molar mass of iron (III) acetate, Fe(C,H,02),  is 650.9 g/mol .

The number of moles  of a substance is calculated as:

n = m/MM

Rearrange the above equation for .

m=nx MM

Substitute 0.0208 mol for n  and 650.9 g/mol for MM  in the above equation.

m=0.0208 mol x 650.9 g/mol = 13.5 g

Hence the mass of solid iron (III) acetate is 13.5g

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The solubility product constant expression for copper(II) oxalate is:

CuC₂O₄(s) ⇌ Cu²⁺(aq) + C₂O₄²⁻(aq)

The Ksp value given is 2.9 x 10⁻⁸ at 25°C.

Let's assume that "x" is the molar solubility of C₂O₄²⁻   in water, then the equilibrium concentrations of Cu²⁺ and C₂O₄²⁻ ions are also "x" because 1 mol of C₂O₄²⁻ produces 1 mol of Cu²⁺ and 1 mol of C₂O₄²⁻

So, it can be written as:

Ksp = [Cu²⁺ ][C₂O₄²⁻ ] = x²

Substituting the given Ksp value, we get:

2.9 x 10⁻⁸ = x²

Taking the square root of both sides gives:

x = 1.7 x 10⁻⁴ M

Therefore, the solubility of copper(II) oxalate at 25°C is 1.7 x 10⁻⁴ moles/litre, rounded to two decimal places.

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