determine the energy levels and the corresponding eigenstates for a par- ticle of mass m, subject to a potential energy v (x) g
Answers
An energy eigenstate can always be written as (x,t) = (x)e-iEt/1. Probability density is equal to |(x,t)|2 (x,t) (x)e-iEt/1 * (x,t) ψ*(x)e+iEt/1 = ψ (x) The wave function *(x) = |(x)|2 exhibits time-dependent phase.
V's role in the Schrodinger equation?For the system of a particle or particles interacting with a set of constraints, V(x) is a potential energy function. These restrictions can be compared to fields that exert a force on the desired particle or particles.
What is the energy eigenvalue?The term "energy eigenvalues," which comes from the German word eigen, which means "characteristic" or "unique," refers to such particular discontinuous (step-like) energies. We refer to these energies as discrete energy eigenvalues or as quantized energies.
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The energy levels and the corresponding eigenstates of a particle of mass m subject to a potential energy v(x) g can be determined by solving the time-independent Schrodinger equation.
What is potential energy?
Potential energy is energy that is stored and can be released in the future. It is the energy of position or condition, as opposed to kinetic energy which is energy in motion. Potential energy can be stored in many forms such as gravitational, chemical, elastic, nuclear, and electromagnetic. Gravitational potential energy is the energy stored in an object due to its position in a gravitational field, while chemical potential energy is the energy stored in the bonds of chemical compounds. Elastic potential energy is energy stored in objects that can be stretched or compressed, such as a spring, while nuclear potential energy is the energy stored in the nucleus of an atom. Electromagnetic potential energy is the energy stored in the electric and magnetic fields of an object.
The energy levels and the corresponding eigenstates of a particle of mass m subject to a potential energy v(x) g can be determined by solving the time-independent Schrodinger equation:
Hψ = Eψ
Where H is the Hamiltonian operator, ψ is the wavefunction, and E is the energy. For a particle of mass m subject to a potential energy v(x) g, the Hamiltonian can be written as:
H = -(h2/2m)*d2/dx2 + v(x) g
The solution of the Schrodinger equation for this Hamiltonian yields the energy levels E and the corresponding wavefunctions ψ. The energy levels are determined by solving the equation:
E - v(x) g = 0
This equation can be solved for the different energy levels E, and the corresponding wavefunctions can then be determined by solving the Schrodinger equation. The wavefunctions represent the probability distribution of the particle, and are determined by the boundary conditions imposed by the potential energy.
In summary, the energy levels and the corresponding eigenstates of a particle of mass m subject to a potential energy v(x) g can be determined by solving the time-independent Schrodinger equation. The energy levels are found by solving the equation E - v(x) g = 0, and the corresponding wavefunctions are found by solving the Schrodinger equation.
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Related Questions
Name two organelles that contain their own genetic meterial and ribosome
Answers
Answer:
Mitochondria and plastids are the two organelles that contain their own genetic material. Both these organelles have their own DNA and ribosomes.
A drag racer starts her car from rest and accelerates at 10.9 m/s^2 for the entire distance of 226 m. How long did it take the car to travel this
distance? Answer in units of s.
Answers
u=0
a=10.9m/s^2
s=226m
v^2-u^2=2as
v^2=2 (10.9)(226)
v^2=49268
v=70.2m/s^2
v=u+at
70.2=0+10.9 (t)
70.2/10.9=t
t=6.44s
5 points) household wiring often uses 2.0 mm diameter copper wires. the wires can get rather long as they snake through the walls from the fuse box to the farthest corners of your house. what is the potential difference across a 20 m long, 2.0 mm diameter copper wire carrying an 8.0 a current?
Answers
The potential difference across the 20 m long, 2.0 mm diameter copper wire carrying an 8.0 A current is approximately 0.025 V.
To find the potential difference, we can use Ohm's law:
V = I * R
where V is the potential difference, I is the current, and R is the resistance of the wire.
The resistance of the wire can be calculated using the formula:
R = (ρ * L) / A
where ρ is the resistivity of copper, L is the length of the wire, and A is the cross-sectional area of the wire.
The resistivity of copper is approximately 1.7 x 10⁻⁸ Ω*m.
The cross-sectional area of the wire can be determined using the formula for the area of a circle:
A = π * r²
where r is the radius of the wire.
Given that the diameter of the wire is 2.0 mm, the radius is 1.0 mm or 0.001 m.
Substituting the values into the formulas, we get:
A = π * (0.001 m)² = 3.14 x 10⁻⁶ m²
R = (1.7 x 10⁻⁸ Ω*m * 20 m) / (3.14 x 10⁻⁶ m²) = 0.108 Ω
Finally, we can calculate the potential difference:
V = 8.0 A * 0.108 Ω = 0.864 V
Therefore, the potential difference across the 20 m long, 2.0 mm diameter copper wire carrying an 8.0 A current is approximately 0.864 V.
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please help me with my question I will like and mark as brainliest
Answers
Answer:
E(nergy) = 8 V * 6A * 300 sec = 14400 joules
14400 J / 4.19 J/cal = 3437 cal
Q = k m T = k 2000gm * 8 deg C = 16000 k gm-deg C
k = 3437 / 16000 = .215 cal / (gm-deg C)
a 0.6 piece of copper is heated and fashioned into a bracelet The amount of energy transferred by heat to the copper is 62,100 J if the specific heat of copper is 390 J/g .c what is the change of the copper temperature.
Answers
The change of the copper temperature if a 0.6g piece of copper is heated and fashioned into a bracelet with 62,100 J amount of energy transferred is 265.4°C.
How to calculate change in temperature?The change in temperature of a metallic substance in a calorimetry experiment can be calculated using the following formula:
Q = mc∆T
Where;
Q = quantity of heat absorbed or releasedm = mass of copper∆T = change in temperaturec = specific heat capacityAccording to this question, a 0.6g piece of copper is heated and fashioned into a bracelet The amount of energy transferred by heat to the copper is 62,100 J.
62100 = 0.6 × 390 × ∆T
62100 = 234∆T
∆T = 62100/234
∆T = 265.4°C
Therefore, the change of the copper temperature if a 0.6g piece of copper is heated and fashioned into a bracelet with 62,100 J amount of energy transferred is 265.4°C.
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How can you turn off a magnetic field produced by an electrical current?
a By placing a material with strong magnetic properties inside the coil of a solenoid b By making a loop or coil in the wire c By increasing the current in the wire d By turning the electrical current off
Answers
Answer:By turning the electrical current off
Explanation:Trust me I took the test
Answer:
d) By turning the electrical current off
Explanation:
this is the only one that fits this situation because all of the other answers help improve the magnetic field.
A child and sled with a combined mass of 26.3 kg slide down a frictionless hill. The sled starts from rest and acquires a speed of 5.34 m/s by the time it reaches the bottom of the hill. What is the height (in m) of the hill?
Answers
Answer:
12 m/s
Explanation:
What happens to the brightness of the bulb if the two resistors are exchanged?
Answers
Two light bulbs are parallel-connected in a circuit. If two more light bulbs were put in parallel to the initial ones, Each bulb's brightness would get dimmer as the circuit's overall resistance got lower. Because the circuit's overall resistance would rise, each bulb's brightness would also rise. Even if the circuit's overall resistance would decrease, each bulb's brightness would not change. Even if the circuit's overall resistance would rise, the intensity of each bulb would stay the same.
What are resistors?A resistor is a passive two-terminal electrical component used in circuits to implement electrical resistance. Resistors have a variety of purposes in electronic circuits, including lowering current flow, adjusting signal levels, dividing voltages, biassing active components, and terminating transmission lines.
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When you look at the visible surface of a gas giant planet, you are looking at that planet’s?
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When you look at the visible surface of a gas giant planet, you are looking at its cloud layer, which consists of various atmospheric gases and particles.
Gas giant planets, such as Jupiter and Saturn, have thick atmospheres composed mainly of hydrogen and helium, along with other gases and particles. These atmospheres give rise to the distinct appearance of these planets.
The visible surface of a gas giant planet is actually the uppermost layer of its atmosphere, often referred to as the cloud layer. This cloud layer consists of various gases, such as ammonia, methane, and water vapor, as well as aerosols and other particulate matter. These gases and particles interact with sunlight, scattering and absorbing certain wavelengths of light, which gives rise to the planet's characteristic colors and patterns.
Due to the opaque nature of the cloud layer, we cannot directly observe the solid or liquid surface of gas giants like we can with rocky planets. The visible surface we see is a result of the scattering and reflection of light by the gas and cloud particles present in the planet's atmosphere. Therefore, when we look at the visible surface of a gas giant planet, we are essentially observing its cloud layer.
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Bob says that if each right triangle has an acute angle with the same measure, the triangles are similar. how do you respond?
Answers
Bob's statement is incorrect. Having acute angles of the same measure in two right triangles does not necessarily guarantee that the triangles are similar.
Similar triangles have corresponding angles that are equal and corresponding sides that are proportional. While having acute angles with the same measure is a necessary condition for similarity, it is not sufficient. Two right triangles can have acute angles of the same measure and still have different side lengths, which would make them non-similar. The similarity of triangles depends on both angle measures and side ratios, not just the equality of acute angles. Additional information about the side lengths or proportions of the triangles is required to determine their similarity
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suppose that the boy stands on the edge of the merry-go-round facing outward, and suppose that he takes a step forward, away from the center of the merry-go-round, landing on the ground. how does the magnitude of the angular velocity of the merry-go-round change as he does this?
Answers
The magnitude of the angular velocity of the merry-go-round change is 0.157m/s.
What is magnitude?
Magnitude is defined as "a measure of distance or amount." It depicts an object's size, direction, or speed, whether absolute or relative. It is used to indicate the scope or magnitude of something. In physics, the term "magnitude" usually refers to a size or amount.
What is angular velocity?
A body can rotate about an axis or alter the angle between two bodies at a certain speed, which is known as its angular velocity. The angle formed by two lines on opposing bodies in the illustration represents this displacement.
By conservation of angular momentum
Lbefore = Lafter
I wi +mvisinФR = (I+mr²) wf
= (370*0.74+84*2.3²) *0.37
=273.8+175.0g V₀= 301.13
V₀= 301.13-273.8/175.0g
=0.157m/s
ΔE= 1/2 (Img +mr²) wf²-1/2mv₀²-1/2Img ²m²
As boy landed on the ground then moment of inertia decreases, so velocity increases.
Therefore, the magnitude of the angular velocity of the merry-go-round change is 0.157m/s.
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is there any way u can help me
Answers
Answer:
get help with your work
try understand your work
ask your teacher for assistance or class
or maybe cheat but understand the work first if you wanna
Look at this applet. It shows an elevator with a small initial upward velocity being raised by a cable. The tension in the cable is constant. The energy bar graphs are marked in intervals of 600 J. Part A What is the mass m of the elevator? Use g=10m/s2 for the magnitude of the acceleration of gravity. Express your answer in kilograms to two significant figures. m =
Answers
The mass of the elevator is 30 kg.
To find the mass of the elevator, we need to use the formula for gravitational potential energy: PE = mgh, where PE is the potential energy, m is the mass, g is the acceleration due to gravity, and h is the height of the elevator.
At the beginning of the motion, the elevator has a small initial upward velocity, so we can assume that it has negligible kinetic energy. Therefore, the total energy of the system is equal to the potential energy:
PE = mgh
We can read the height of the elevator from the energy bar graph at the end of the motion, which is 2400 J. The change in height is 2400 J / 600 J = 4 intervals, so the initial height is 2400 J - 4(600 J) = 0 J.
Therefore, the potential energy at the beginning of the motion is:
PE = mgh = mgh_initial = 0 J
And the potential energy at the end of the motion is:
PE = mgh_final = 2400 J
We can now use these equations to solve for the mass:
mgh_final = mgh_initial
mgh_final - mgh_initial = 0
mgh = 2400 J
mg = 2400 J / h
m = (2400 J / h) / g
Substituting the given values, we get:
m = (2400 J / 0.8 m) / 10 m/s^2
m = 30 kg (rounded to two significant figures)
Therefore, the mass of the elevator is 30 kg.
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a 7.00 g bullet is fired horizontally into a 1.20 kg wooden block resting on a horizontal surface. the coefficient of kinetic friction between block and surface is 0.20. the bullet remains embedded in the block, which is observed to slide 0.390 m along the surface before stopping.
Answers
The final velocity of the block and the bullet after the collision is 12.43 m/s.
First, we need to determine the initial velocity of the bullet. We can use the conservation of momentum principle, which states that the total momentum of a system remains constant if no external forces act on it. Thus, we have:
m_bullet x v_bullet = (m_bullet + m_block) x v_final
where m_bullet is the mass of the bullet, v_bullet is its initial velocity, m_block is the mass of the wooden block, and v_final is the final velocity of the block and the bullet after the collision. Since the bullet remains embedded in the block, we can assume that their final velocities are the same.
Substituting the given values, we get:
7.00 g x v_bullet = (7.00 g + 1.20 kg) x v_final
Simplifying, we get:
v_bullet = v_final x (1.20 kg / 7.00 g + 1.20 kg)
v_bullet = v_final x 0.994
Next, we need to find the frictional force acting on the block. We can use the formula:
f_friction = friction coefficient x normal force
where f_friction is the frictional force, friction coefficient is the coefficient of kinetic friction between the block and the surface, and normal force is the force exerted by the surface perpendicular to the block's surface. Since the block is resting on a horizontal surface, the normal force is equal to its weight, which is:
m_block x g = 1.20 kg x 9.81 m/s² = 11.772 N
Substituting the given friction coefficient, we get:
f_friction = 0.20 x 11.772 N = 2.354 N
The frictional force acts in the opposite direction to the block's motion, so we can use it to find the work done by friction, which is:
W_friction = f_friction x d
where W_friction is the work done by friction, and d is the distance the block slides along the surface. Substituting the given values, we get:
W_friction = 2.354 N x 0.390 m = 0.917 J
Finally, we can use the work-energy principle, which states that the net work done on an object is equal to its change in kinetic energy. In this case, the initial kinetic energy of the bullet is equal to zero, and the final kinetic energy of the block and the bullet is also zero, since they come to a stop. Thus, the net work done on the system is:
W_net = W_friction
Substituting the previously calculated value of W_friction, we get:
W_net = 0.917 J
This work is equal to the initial kinetic energy of the bullet, which is:
K_initial = (1/2) x m_bullet x v_bullet²
K_initial = (1/2) x 7.00 g x (v_final x 0.994)²
K_initial = 2.435 x 10⁻³ J x v_final²
Equating this to the net work done, we get:
2.435 x 10⁻³ J x v_final² = 0.917 J
v_final = 12.43 m/s
Therefore, the final velocity of the block and the bullet after the collision is 12.43 m/s.
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Desperate Please Hurry
What was the evidence that Earth was round before there were photos from space?
Answers
Answer:
?????
Explanation:
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Sushant went on an educational trip to a village. There he found a potter making pots. He found that the soil used for making pots was different from normal soil. Name the soil and also tell its characteristics.
Answers
The soil used for making pots by potters is commonly known as "Potter's Clay" or "Potter's Soil."
Characteristics of Potter's Clay:
1. Plasticity: Potter's clay has high plasticity, which means it can be easily molded and shaped into different forms without cracking or breaking.
2. Cohesiveness: It exhibits good cohesion, allowing the clay particles to stick together when moistened, forming a workable material.
3. Fine Particle Size: Potter's clay consists of fine particles that contribute to its plasticity and workability.
4. High Water Retention: It has the ability to retain water, which helps maintain the moisture content necessary for the clay to be shaped and formed.
5. Low Shrinkage: Potter's clay exhibits low shrinkage when it dries or undergoes firing, ensuring minimal distortion or cracking during the drying and firing processes.
6. Good Bonding Properties: The clay particles have the ability to bond together, creating a strong and durable structure once fired.
7. Good Porosity: After firing, the clay retains some porosity, allowing the pot to breathe and allowing for the exchange of air and moisture.
What waves are transverse waves that disturb electromagnetic fields?
Answers
Radio waves are transverse waves that disturb electromagnetic fields.
What is electromagnetic fields?Electromagnetic field, a feature of space brought on by the movement of an electric charge. Only an electric field will be generated by a stationary charge in the surrounding area. A magnetic field is also created if the charge is in motion.
A changing magnetic field can also create an electric field. An electromagnetic field is created by the mutual interaction of electric and magnetic fields. This field is thought to exist independently of any charges or currents (a stream of moving charges) to which it may be related. It is possible to think of this electromagnetic field in some situations as an electromagnetic energy-transporting wave.
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‼️‼️EMERGENCY ITS DUE SOON‼️‼️
A box weighing 2000N is sliding across a cement floor. The force pushing the box is 500N, and the coefficient of sliding friction between the box and the floor is 0.20. What is the acceleration of the box? 
Answers
Answer:
1.96m/s^2
Explanation:
According to Newtons second law;
F = ma
a = F/m
a = nR/m
a = nmg/m
a = ng
n is he coefficient of friction = 0.2
g = 9.8m/s^2
a = 0.2 * 9.8
a = 1.96m/s^2
Hence the acceleration of the box is 1.96m/s^2
"Please include all relevant working out as detailed as possible
and all relevant diagram to find the answer. Much appreciated! I
will upvote! Thank you so much"
Find total response of the system (transient+steady state). Do not solve for coefficients. Determine the frequency of applied force at which resonance will occur? M = 20 kg F, = 90 N Given: -6 rad/s M
Answers
Given the following information:Mass of the system, m = 20 kg.Damping coefficient, b = 6 Ns/m.Force, F = 90 N.Frequency of applied force, f = ?Applied force angular frequency, w = 6 rad/s.Forced vibration equation:F(t) = F0 sin(wt)where F0 = 90 N and w = 6 rad/s.Under the action of the force F, the mass m will oscillate.The equation of motion for the mass-spring-damper system is given by:$$\mathrm{m\frac{d^{2}x}{dt^{2}}} + \mathrm{b\frac{dx}{dt}} + \mathrm{kx = F_{0}sin(\omega t)}$$where k is the spring constant.x(0) = 0 and x'(0) = 0.As we have the damping coefficient (b), we can calculate the damping ratio (ζ) and natural frequency (ωn) of the system.Damping ratio:$$\mathrm{\zeta = \frac{b}{2\sqrt{km}}}$$where k is the spring constant and m is the mass of the system.Natural frequency:$$\mathrm{\omega_{n} = \sqrt{\frac{k}{m}}}$$where k is the spring constant and m is the mass of the system.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$At resonance, the amplitude of the system will be maximum when forced by a sinusoidal force of frequency equal to the resonant frequency.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$$$\mathrm{\omega_{d} = \sqrt{(6.57)^{2}-(-2.88)^{2}} = 6.98 rad/s}$$Hence, the frequency of applied force at which resonance will occur is 6.98 rad/s.
The frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.
To determine the frequency of the applied force at which resonance will occur, resonance happens when the frequency of the applied force matches the natural frequency of the system. The natural frequency can be determined using the formula:
ωn = √(K / M),
where ωn is the natural frequency, K is the spring constant, and M is the mass of the system.
Substituting the given values of K = 400 N/m and M = 20 kg into the equation, we can calculate the natural frequency ωn.
ωn = √(400 N/m / 20 kg) = √(20 rad/s²) = 2√5 rad/s.
Therefore, the frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.
The correct question is given as,
M= 20kg
Fo = 90 N
ω = 6 rad/s
K = 400 N/m
C = 125 Ns/m
Determine the frequency of applied force at which resonance will occur?
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1) how can you show that atmospheric exerts pressure?
2) how do you measure the volume of an irregular solid ? explain an experiment with diagram.
Answers
Answer:
1. While boiling replace the cap and allow it to cool. Vapours inside condense and form water creating vacuum above them. Observation - The can crumbles due to air pressure from outside. This proves that air exerts pressure.
2. Measure the volume of the liquid displaced when the object is submerged. Measure the initial volume of water in graduated cylinder. Submerge the irregular object. Measure the final volume of the water.
— The difference between the initial volume and the final volume is the volume of the object.
hope can help ^_^
what is the magnitude of the force on the 1.0ncnc charge in the middle of (figure 1) due to the four other charges?
Answers
The net force on the middle charge due to the four other charges is zero.
The given parameters:
q₁ = -2 nCq₂ = 2 nCq₃ = 2 nCq₄ = -2 nCmiddle charge, q₀ = 1 nCWhat is the force between two charges?The attractive or repulsive force between two charges is determined by Coulomb's law.The magnitude of the force on the middle charge due to the four other charges is calculated as follows;
\(F_0{net} = F_{01} + F_{02} + F_{03} + F_{04}\\\\F_0{net} = \frac{k\times q_0(-q_1)}{r^2} + \frac{k\times q_0(q_2)}{r^2} + \frac{k\times q_0(q_3)}{r^2} + \frac{k\times q_0(-q_4)}{r^2}\\\\F_0{net} = - \frac{k\times q_0q_1}{r^2} + \frac{k\times q_0q_2}{r^2} + \frac{k\times q_0q_3}{r^2} - \frac{k\times q_0q_4}{r^2}\\\\F_0{net} = \frac{kq_0}{r^2} (-q_1 + q_2 + q_3 - q_4)\\\\recall, \ |q_1| = q_2 = |q_3| = |q_4| = 2 \ nC\\\\F_0{net} = \frac{kq_0}{r^2} (-2 + 2+ 2-2)\\\\F_0{net} = \frac{kq_0}{r^2}(0)\\\\\)
\(F_0{net} = 0\)
Thus, the net force on the middle charge due to the four other charges is zero.
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Students are designing an experiment to test how the mass of an object
impacts how fast the object falls to earth due to gravity by dropping balls
of different mass to the ground. list three variables in the experiment that
the students would need to keep constant: *
Answers
In order to experiment how the mass of an object impacts how fast the object falls to earth due to gravity by dropping balls of different mass to the ground , three variables in the experiment that the students would need to keep constant are acceleration, gravity as well as velocity.
When something falls, gravity is the cause of the fall. That object experiences a force, which causes it to accelerate, increasing its fall velocity. Gravitational force—the force the Earth exerts on objects—is a sort of acceleration. Everything feels the exact same amount of pull from Earth. Everything accelerates in the same manner toward the Earth. Even though objects of different masses experience different amounts of force, they all accelerate at the same rate on Earth. The amount of material multiplied by the rate at which it is being drawn toward the Earth or any other planet or moon produces weight, which is the force acting on the mass as a result of gravity.
If things of different masses are dropped from the same height, they will still impact the ground at the same time because Earth provides everything the exact same acceleration.
Everyone has dropped a marble and a feather at the same moment and they all landed on the floor at various times, so when you tell it for the first time, no one will believe you. The reason for this is because air is pushing against the item in the direction that the Earth is tugging, not variations in acceleration, which are constant on Earth. Air resistance is what generates this force.
A piece of paper, for instance, has a lot of surface area that is exposed to the air resistance if it is dropped horizontally. However, there is less area exposed to the air resistance if the paper is dropped vertically and on the thin side. This indicates that the paper will experience the same pull from the Earth and less push from the air in that position. The floor won't be struck simultaneously by two pieces of paper of equal mass dropped from the same height but with one in the horizontal position and the other in the vertical position.
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Use the drop-down menus to complete the sentences describing what happens when the temperature of a fluid
ncreases.
The kinetic energy of the molecules
The speed of the molecules
The density of the fluid
The fluid
Answers
Answer:
The kinetic energy of the molecules increases as it heats up causing it to vibrate faster and faster.
Explanation:
why should it not be surprising that some galaxies contain a little more than 25 percent helium but it would be very surprising if some galaxeies contaiend less
Answers
It should not be surprising that some galaxies contain a little more than 25% helium because helium is the second most abundant element in the universe, after hydrogen.
During the Big Bang, approximately 75% hydrogen and 25% helium were formed. As stars form within galaxies, they undergo nuclear fusion, converting hydrogen into helium. This process increases the overall helium content in a galaxy over time.
The Big Bang is the prevailing cosmological model that describes the early development of the Universe. It suggests that the Universe began as a singularity and has since expanded and cooled, leading to the formation of galaxies, stars, and planets.
It would be very surprising if some galaxies contained less than 25% helium because this would imply that either the initial conditions during the Big Bang were different in those galaxies or some process is removing helium from those galaxies.
Both of these scenarios are highly unlikely and inconsistent with our current understanding of the formation and evolution of galaxies in the universe.
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PLEASE HELP ME
NEED IT FAST WILL GIVE B !! If correct
Answers
Answer:
25% :)
Explanation:
You push the sofa across the floor. Which force is NOT present on the sofa?
a)gravity
b)normal
c)tension
d)applied
Answers
Answer:
c) tension ........ ........
Answer:
gravity
Explanation:
because it cannot be move across if there is present gravity force
Immediately after stepping off a branch to swing over to another tree, is Tarzan's acceleration zero or not zero?
Answers
When Tarzan steps off a branch to swing over to another tree, his acceleration is not zero. This is because Tarzan is experiencing a change in velocity as he swings from one tree to another.
Acceleration is defined as the rate at which an object's velocity changes over time. When Tarzan swings, his velocity changes from zero to a certain speed, and then back to zero when he reaches the next tree.As he swings, Tarzan experiences the force of gravity pulling him down towards the ground, which causes his velocity to increase. This force is counteracted by the tension in the vine or rope that he is using to swing, which provides the necessary centripetal force to keep him moving in a circular path. This centripetal force also causes Tarzan's velocity to change, resulting in acceleration.Therefore, Tarzan's acceleration is not zero when he steps off a branch to swing over to another tree. It is important to note that his acceleration is not constant, but rather changes throughout the swing as he experiences different forces.
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nalyze the scatterplot graph.
Which trend does the graph show?
As age increases, weight increases.
As weight decreases, age increases.
As age increases, weight remains the same.
As weight increases, age remains the same.
Answers
As we see in the scatterplot graph and the briefing given below the most appropriate option is A-As age increases, weight increases.
Briefing:If you follow the arrow's trajectory, your finger will move to the right, increasing age (on the horizontal axis).
Additionally, as your finger rises, the weight (on the vertical axis) does as well.
Age and weight increase in tandem since both processes are ongoing.
What do scatterplot graphs display?The association between two numerical variables measured for the same individuals is displayed in a scatterplot. One variable's values are displayed on the horizontal axis, and the other variable's values are displayed on the vertical axis. On the graph, each individual in the data is represented by a point.
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The complete question is-
Analyze the scatterplot graph.
Which trend does the graph show?
A-As age increases, weight increases.
B-As weight decreases, age increases.
C-As age increases, weight remains the same.
D-As weight increases, age remains the same.
If an electron (with a charge of 1.6 x10−19c) Experiences a force of 500 N at a certain point in an electric field, then find the strength of the electric field in that location
Answers
Answer:
3.125×10²¹ N/C
Explanation:
Electric Field: This can be defined as the force experienced per unit charge. The S.I unit of electric Field is N/C
Applying,
E = F/q.................. Equation 1
Where E = Electric Field, F = Force experienced, q = Charge of an electron.
From the question,
Given: F = 500 N, q = 1.6×10⁻¹⁹ C
Substitute these values into equation 1
E = 500/(1.6×10⁻¹⁹)
E = 312.5×10¹⁹
E = 3.125×10²¹ N/C
calculate the speed of sound on a day when a 1500 hz frequency has a wavelength of 0.221 m.
Answers
Answer:
Answer is 331.5 m/s
Explanation:
This is done by using the equation wave speed = wavelength x frequency.
On a day when the wavelength of a 1500 Hz frequency is 0.221 meters, the speed of sound is about 331.5 meters per second.
The air's humidity, pressure, and temperature all affect how quickly sound travels through it. To get the sound speed in air, use the following formula:
v = f * λ
where the sound wave's wavelength, frequency, and speed are represented by the letters v, f, and.
Frequency times wavelength equals sound speed.
We may enter these numbers into the formula: where the wavelength is 0.221 m and the frequency is 1500 Hz.
Speed of sound = 1500 Hz x 0.221 m
Speed of sound = 331.5 m/s.
Therefore, the speed of sound on the given day is approximately 331.5 meters per second.
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