Determine the electron-group arrangement, molecular shape, and ideal bond angle(s) for each of the following:
(a) CO₃²⁻

The thing that will happen to the temperature if you use 75 ml of HCl and 75 ml of NaOH instead is that it increases as more heat is released.

A neutralization occurs when NaOH and HCl are combined. Each chemical reaction has a unique heat of reaction, which is the heat exchanged during the process.

The reaction in issue is exothermic (emits heat), and the amount of heat emitted relies on the chemicals used, their concentrations, and the working temperature (it is produced at a low temperature).

The fluctuation in temperature and the mass used determine how much heat is allocated.

In this case, the thing that will happen to the temperature if you use 75 ml of HCl and 75 ml of NaOH instead is that it increases as more heat is released.

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Answer:

They both contain citric acid.

Explanation:

Citric acid is sour and is found in citrus fruits such as lemon and amla. Acids usually have a sour taste and therefore lemon and amla are sour.

Answer:Because there are so many units for energy.

Explanation:

Answer: 0.24 dm

Explanation:

Answer:

its an helium gas are contained in a 4.0L at STP? 0.17

Explanation:

because the elements in column 2.21 is what quantity of gas in holes

Answer:

the answer is gamma radiation

Answer:

hot

Explanation:

3.99 teaspoons should be administered to a person weighing 220 pounds

The adult dose of a solution is 0.2 mL/kg of body weight to be administered once daily.

If a person weighs 220 pounds, you have to first convert their weight from pounds to kilograms before you can calculate the dosage.

You should be given the conversion factor of 1 teaspoon = 5 milliliters (mL) or 1 mL

= 0.2 teaspoons (tsp).

Using the conversion factor of pounds to kilograms,1 pound = 0.453592 kilograms

220 pounds = 99.7913 kilograms

Dose = 0.2 mL/kg x 99.7913 kg = 19.95826 mL

To convert the dose from milliliters to teaspoons, use the conversion factor of 1 teaspoon = 5 milliliters.

19.95826 mL × 1 tsp / 5 mL = 3.991652 tsp

Therefore, 3.99 teaspoons should be administered to a person weighing 220 pounds, given the adult dose of 0.2 mL/kg of body weight to be administered once daily.

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Answer:

S + HNO3 = H2SO4 + NO2 + H2O

Explanation:

Answer:

Based on stoichiometry HNO3 to H2O is 6:2

Use 9 grams to find the moles of HNO3

9 grams/63g/mol=0.143 moles of HNO3

HNO3:H2O

6:2

0.143*2/6=0.048

H2O moles is 0.048moles

Mass of water =0.048moles*18g/mol=0.864g

To the nearest tenth=0.9grams

Explanation:

I think this is right

Answer:

1. Formation of a gas

2. Formation of precipitate

3. Liberation or absorption of heat, light, or some form of energy

4. Distinct change in color

Hope this helps!

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The approximately 4 moles of gas in the container at standard temperature (ST) with a volume of 99.2 L.

To determine the number of moles of gas in a container at standard temperature (ST) with a volume of 99.2 L, we need to use the ideal gas law equation:

PV = nRT

Where:

P = pressure (atmospheres)

V = volume (liters)

n = number of moles

R = ideal gas constant (0.0821 L·atm/mol·K)

T = temperature (Kelvin)

At standard temperature (ST), the temperature is 273.15 K.

Assuming the pressure is also at standard conditions (1 atm), we can rearrange the ideal gas law equation to solve for the number of moles:

n = PV / RT

Substituting the given values:

P = 1 atm

V = 99.2 L

R = 0.0821 L·atm/mol·K

T = 273.15 K

n = (1 atm) × (99.2 L) / ((0.0821 L·atm/mol·K) × (273.15 K))

Simplifying the calculation:

n ≈ 4 moles

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The approximate resistance value at 45 degrees Celsius is around 5.8 ohms.

To calculate the value of the resistance temperature coefficient at 45 degrees Celsius using linear approximation, we can use the formula:

R(T) = R0 + α(T - T0),

where R(T) is the resistance at temperature T, R0 is the resistance at a reference temperature T0, α is the resistance temperature coefficient, and (T - T0) is the temperature difference.

Given that the resistance at 25 degrees Celsius is 5 ohms (R0 = 5) and the resistance at 50 degrees Celsius is 6 ohms (R(T) = 6), we can calculate the value of α.

6 = 5 + α(50 - 25),

Simplifying the equation:

1 = 25α,

Therefore, α = 1/25 = 0.04 ohm/degree Celsius.

Using the linear approximation, we can approximate the value of the resistance at 45 degrees Celsius:

R(45) = 5 + 0.04(45 - 25) = 5 + 0.04(20) = 5 + 0.8 = 5.8 ohms.

Therefore, the value of the resistance at 45 degrees Celsius is approximately 5.8 ohms.

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Answer: 0.01 M

Explanation:

\(M_{A}V_{A}=M_{B}V_{B}\\(26.1)(0.505)=(1950)M_{B}\\M_{B}=\frac{(26.1)(0.505)}{1950} \approx \boxed{0.01 \text{ M}}\)

It is false that a substance's flashpoint is the temperature at which it will explode.

That a substance's flashpoint corresponds to the temperature at which it will ignite is untrue.

When an ignition source is provided, there will be enough flammable vapours to cause ignition at the flash point, which is actually the lowest temperature at which ignition occurs.

What is temperature?

The degree to which a body is hot or cold is known as its temperature.

Describe ignition.

The act of starting a fire with a fuel source is known as ignition.

Flammable vapours are what?

Flammable vapours (Vapor) is vapor that is beyond its lower flammable limit (LFL) concentration and comes from flammable substances like gasoline, kerosene, paint thinner, and solvents. Because the flammable vapors are frequently heavier than air, they may travel along the ground and gather in low or cramped spaces, where any source of ignition could result in an explosion or fire. Anytime a liquid is above its flash point, a zone of flammable vapor will coexist in equilibrium with it.

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Zn has a molecular mass of 65.3800 g/mol. The mass of one mole of a material, measured in grams per mole (g/mol), is known as molar mass or molar weight.

What is molar mass?

Mass per mole is a definition of molar mass. In other terms, molar mass is the total mass of all the atoms in a substance that makes up a mole. It is measured in gram-per-mole quantities.

For atoms or molecules, molar mass is displayed. The molar mass is simply the element's mass expressed in atomic mass units in the case of solitary elements or individual atoms. To put it another way, an atom's atomic mass and molar mass are precisely equal. Molar mass can be used to determine a particle's identity because it is equivalent to atomic mass for individual atoms. He, for instance, has an atomic mass of 4. There is only one helium molecule in nature, meaning that it has only one atom, so its molar mass is also 4.

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Answer:

d) group 18

Explanation:

Group 18 on the periodic table consists of noble gasses, which do not chemically interact with other elements.

Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl

To calculate the concentration of NaCl in the resulting solution in mg/L NaCl, we can use the formula; Concentration (mg/L) = (Mass of solute ÷ Volume of solution in L) × 1000 g / 1 mg NaCl is present in the stock solution of 25 mL. So, the mass of NaCl in the solution would be;0.0842 g ÷ 25 mL = 0.00337 g/mL. Now, in the resulting solution, a 1.00 mL aliquot of the stock solution is transferred to a 50.00 mL volumetric flask and diluted to volume. Therefore, the volume of the resulting solution is 50.00 mL. We will substitute these values in the formula, Concentration (mg/L) = (0.00337 g/mL ÷ 50 mL) × 1000 g / 1 mg concentration (mg/L) = 67.4 mg/L. Therefore, the concentration of NaCl in the resulting solution in mg/L NaCl is 67.4 mg/L.7.  Concentration = 67.4 mg/LTolerance = 4.28 mg/LTotal concentration = 67.4 + 4.28 mg/L = 71.68 mg/LWe round off this value to one decimal place; Total concentration = 71.7 mg/LTherefore, the concentration of NaCl in the resulting solution using propagation of error through the calculation is 67.4+0.4 mg/L.8. Two possible sources of random (indeterminate) error in the experiment are; Errors in temperature measurement. Errors in measurement of water volume. Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl.

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The first two unique options are both correct. The ring of fire is a large group of volcanoes located around the Pacific ocean.

Answer:Question

Select the correct answer. Sami was blowing soap bubbles in his room where the temperature was 23 °C and the pressure was constant. He blew a soup bubble of volume 45 mL. The bubble suddenly escaped from the window where the temperature outside was 12 °C. Explain what will happen to the soap bubble? The volume of the soap bubble will increase to 46.73 mL. The volume of the soap bubble will increase to 86.25 mL. The volume of the soap bubble will decrease to 23.47 mL. The volume of the soap bubble will decrease to 43.33 mL.​

Explanation:

Question

Select the correct answer. Sami was blowing soap bubbles in his room where the temperature was 23 °C and the pressure was constant. He blew a soup bubble of volume 45 mL. The bubble suddenly escaped from the window where the temperature outside was 12 °C. Explain what will happen to the soap bubble? The volume of the soap bubble will increase to 46.73 mL. The volume of the soap bubble will increase to 86.25 mL. The volume of the soap bubble will decrease to 23.47 mL. The volume of the soap bubble will decrease to 43.33 mL.​

The ratio of concentrations of bicarbonate to carbonic aciddin a blood sample with a pH of 6.2 is approximately 3.98:1.

The Henderson-Hasselbalch equation can be used to calculate the ratio of bicarbonate to carbonic acid. The equation is given by pH = pKa + log([HCO3-]/[CO2]).

Given a pH of 6.2 and a pKa of carbonic acid as 6.37, we can rearrange the equation and solve for the ratio [HCO3-]/[CO2].

Using the equation, we find that log([HCO3-]/[CO2]) = pH - pKa = 6.2 - 6.37 = -0.17.

Taking the antilog of -0.17, we find that [HCO3-]/[CO2] ≈ 0.445.

To obtain the ratio of bicarbonate to carbonic acid, we can invert the value: [CO2]/[HCO3-] ≈ 1/0.445 ≈ 2.24.

Converting to a whole number ratio, the ratio of concentrations of bicarbonate to carbonic acid is approximately 3.98:1.

The ratio of bicarbonate to carbonic acid in a blood sample with a pH of 6.2 is approximately 3.98:1. This ratio is crucial for maintaining the acid-base balance in the body and plays a significant role in regulating blood pH and bicarbonate buffering.

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Answer:

Parasitism. A symbiotic relationship between two species in which one benefits and the other is harmed.

Explanation:

:)

Answer:

4Fe + 3O2 → 2Fe2O3

Answer:

The velocity of the bb when it reaches a height of 203 m can be determined using the laws of projectile motion. Since the bb is moving vertically upwards, its velocity at that height will be zero.

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Answer: v = 83.96 m/s

Assuming the acceleration due to gravity is approximately 9.8 m/s^2, we can use the principles of projectile motion and energy conservation.

Using the equation for the vertical displacement of an object in free fall:

Δy = (v₀² - v²) / (2g)

Δy = vertical displacement (203m)

v₀ = initial velocity (105 m/s)

v = final velocity (not known yet)

g = accerlation due to gravity (9.8 m/s^2)

Lets rearrange the equation to solve for the final velocity:

v = v = √(v₀² - 2gΔy)

Substituting the given values:

v = √(105² - 2 * 9.8 * 203)

v ≈ √(11025 - 3979.6)

v ≈ √(7054.4)

v ≈ 83.96 m/s

Therefore, when the BB pellet is at the height of 203m, its velocity will be approximately 83.96 m/s.

So, at STP, there are around 891 grammes of nitrogen gas in every 759 litres.

The two stable isotopes of naturally occurring nitrogen (7N) are nitrogen-14 and nitrogen-15, with nitrogen-14 constituting 99.6% of all naturally existing nitrogen. Along with one nuclear isomer, 11mN, fourteen radioisotopes with atomic masses ranging from 10 to 25 are also known.

Assuming "ST" refers to standard temperature and pressure (0°C and 1 atm), we can use the ideal gas law to calculate the mass of nitrogen gas:

PV = nRT

where n is the number of moles, P is the pressure, V is the volume, and T is the temperature, and R is the gas constant.

The temperature and pressure are 273.15 K and 1 atm, respectively, at STP.

To solve for n, the number of moles, we can rearrange the ideal gas law equation as follows:

n = PV / RT = (1 atm) * (759 L) / (0.0821 L·atm/(mol·K) * 273.15 K) = 31.8 mol

Now we can calculate the mass of nitrogen gas:

mass = n * molar mass = 31.8 mol * 28.01 g/mol ≈ 891 g.

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Answer:

4.75 or 4.8

Explanation:

density = mass / volume

57 / 12 = 4.75

from here you can leave it as is or round up.

hope this helps!!

Answer:

liquid ethanol can be separated from a mixture of ethanol and water by fractional distillation. This method works because the liquids in the mixture have different boiling points. When the mixture is heated, one liquid evaporates before the other.

Explanation:

hope this helps :3

Answer:

really?!

Explanation:

this is a test your suppose to answer it

Answer:

See explanation

Explanation:

In looking at molecules to determine whether they are polar or not we have to look at two things basically;

i) presence of polar bonds

ii) geometry of the molecule

Now, we know that CCI2F2 is a tetrahedral molecule, but the molecule is not symmetrical. It has four polar bonds that are not all the same hence the molecule is polar.

In an electric field, polar molecules orient themselves in such a way that  the positive ends of the molecule are being attracted to the negative plate while the negative ends of the molecules are attracted to the positive plate.

So the positive ends of CCI2F2  are oriented towards the negative plate of the field while the negative ends of CCI2F2 are oriented towards the positive ends of the field.