V = IR
30 = 15 I
I = 2 A
.....................
2. A ball is thrown 45 m into the air. It takes the ball 5 s to hit the ground. What is the
velocity of the ball when it hits the ground?
Answer:
9m/s
Explanation:
45m÷5s=9m/s
Hope it helps!!!
The distance of object is 10cm from convex mirror of focal length is 15 cm. Find the position of image? pic attached below
The position of the image is 30 cm behind the mirror.
According to the mirror formula,
1/f = 1/u + 1/v
where f is the focal length, u is the distance of the object from the mirror, and v is the distance of the image from the mirror.
Substituting the given values, we get:
1/15 = 1/10 + 1/v
Simplifying, we get:
1/v = 1/15 - 1/10 = (2 - 3)/30 = -1/30
Taking the reciprocal on both sides, we get:
v = -30 cm
The negative sign indicates that the image is virtual and located behind the mirror. Therefore, the position of the image is 30 cm behind the mirror.
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What is the speed acquired by a freely falling object 4 seconds after being dropped from a rest position? Use units of meter per second (m/s) and assume acceleration from gravity is 10 m/s2.
speed = 40 m/s
Explanation:
Since the object is dropped, V0y = 0.
Vy = V0y - gt
= -(10 m/s^2)(4 s)
= -40 m/s
This means that its velocity is 40 m/s downwards. Its speed is simply 40 m/s.
The speed acquired by a freely falling object 4 seconds after being dropped from a rest position would be 40 meters/seconds.
What are the three equations of motion?There are three equations of motion given by Newton
The first equation is given as follows
v = u + at
the second equation is given as follows
S = ut + 1/2×a×t²
the third equation is given as follows
v² - u² = 2×a×s
Keep in mind that these calculations only apply to uniform acceleration.
As given in the problem, we have to find the speed acquired by a freely falling object 4 seconds after being dropped from a rest position,
By using the first equation of motion,
v = u + at
initial velocity(u) = 0 m/s
acceleration(a) = 10 m/s²
v = 0 + 10×4
v = 40 meters/seconds
Thus, the speed acquired by a freely falling object 4 seconds after being dropped from a rest position would be 40 meters/seconds.
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An object is placed at several different distances to the left of the lenses and mirrors (focal length = f). For each case, draw the 3 principal rays to locate the image and then (S.A.L.T.) [Size, Attitude, Location, Type] the image.
To determine the image characteristics using the 3 principal rays and SALTS (Size, Attitude, Location, Type), we'll consider both lenses and mirrors separately. Here's how you can analyze each case:
Lenses:
Place an object at different distances to the left of a lens with a focal length (f).
a) Object placed beyond 2f:
In this case, the object is placed far beyond twice the focal length of the lens.
Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.
Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.
Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.
The image will be formed on the opposite side of the lens, between the focal point and twice the focal length.
SALTS:
Size: The image will be smaller than the object.
Attitude: The image will be inverted.
Location: The image will be located between the focal point and twice the focal length.
Type: The image will be real.
b) Object placed at 2f:
In this case, the object is placed at twice the focal length of the lens.
Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.
Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.
Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.
The image will be formed on the opposite side of the lens at twice the focal length.
SALTS:
Size: The image will be the same size as the object.
Attitude: The image will be inverted.
Location: The image will be located at twice the focal length.
Type: The image will be real.
c) Object placed between f and 2f:
In this case, the object is placed between the focal point and twice the focal length of the lens.
In this case, the object is placed far beyond twice the focal length of the mirror.
Principal ray 1: A ray parallel to the principal axis will reflect through the focal point on the same side.
Principal ray 2: A ray passing through the focal point on the object side will reflect parallel to the principal axis.
Principal ray 3: A ray passing through the center of curvature will reflect back along the same path.
The image will be formed on the opposite side of the mirror, between the focal point and twice the focal length.
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An electromagnet is made by wrapping many turns of wire around an iron bar and
causing a current to flow through the wire. How would increasing the electrical current
affect the electromagnet?
Increasing the electrical current flowing through the wire in an electromagnet would have several effects on its magnetic properties.
Increased magnetic field strength: The magnetic field strength produced by an electromagnet is directly proportional to the current passing through the wire.
By increasing the electrical current, the magnetic field strength of the electromagnet would also increase. This means that the electromagnet would have a stronger magnetic pull and be able to attract or magnetize nearby magnetic materials more effectively.
Increased magnetic field range: As the current flowing through the wire increases, the magnetic field generated by the electromagnet expands and reaches a larger area. This means that the electromagnet's influence on magnetic objects in its vicinity would extend over a greater distance.
Increased lifting capacity: The force exerted by the electromagnet on magnetic materials is directly proportional to the magnetic field strength. By increasing the electrical current, the electromagnet's lifting capacity would also increase. It would be able to lift or hold larger and heavier magnetic objects.
Increased heat generation: Increasing the electrical current would result in a higher power dissipation in the wire, leading to increased heat generation. This is due to the Joule heating effect, where the resistance of the wire causes it to heat up as current passes through.
Therefore, it is important to ensure that the wire and the electromagnet are designed to handle the increased current and dissipate the generated heat to prevent overheating and damage.
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A ball traveling in a circle with a constant speed of 8 m/s has a centripetal acceleration of 20 m/s2. What is the radius of the circle?
The radius of the circle is ____
m.
Answer:
The radius of the circle will be 20
Explanation:
First we will get the time from the given
time =velocity÷acceleration, 8÷20= 0.4s
then we are going to get the distance (circumference)
d=velocity ×time, 8×0.4=3.2
since that the circumference =2/pi (r)²
2×22÷7×r²=3.2 , 3.2 ÷44÷7=0.509 root 0.509
radius=0.71
A man pushing a crate of mass
m = 92.0 kg
at a speed of
v = 0.855 m/s
encounters a rough horizontal surface of length
ℓ = 0.65 m
as in the figure below. If the coefficient of kinetic friction between the crate and rough surface is 0.359 and he exerts a constant horizontal force of 289 N on the crate.
A man pushes a crate labeled m, which moves with a velocity vector v to the right, on a horizontal surface. The horizontal surface is textured from the right edge of the crate to a horizontal distance ℓ from the right edge of the crate.
(a) Find the magnitude and direction of the net force on the crate while it is on the rough surface.
magnitude
N
direction
Opposite Direction or Same Direction
(b) Find the net work done on the crate while it is on the rough surface.
J
(c) Find the speed of the crate when it reaches the end of the rough surface.
m/s
(a) The magnitude and direction of the net force on the crate while it is on the rough surface is 34.7 N in opposite direction.
(b) The net work done on the crate while it is on the rough surface is -22.6 J.
(c) The speed of the crate when it reaches the end is 0.5 m/s.
What is the net force on the crate while it is on the rough surface?
The magnitude and direction of the net force on the crate while it is on the rough surface is calculated as follows;
F (net) = F - Ff
where;
F is the applied forceFf is the frictional force on the crateF (net) = F - μmg
where;
μ is the coefficient of frictionm is massg is gravityF (net) = 289 N - (0.359 x 92 X 9.8)
F (net) = -34.7 N
The negative sign indicates opposite direction to the applied force.
The net work done on the crate while it is on the rough surface is calculated as follows;
W = F(net) x L
where;
L is the distance travelled by the crateW = -34.7 x 0.65
W = -22.6 J
The speed of the crate when it reaches the end is calculated as follows;
acceleration of the crate = F(net) / m
a = -34.7 N / 92 kg
a = -0.377 m/s²
v² = u² + 2aL
v² = ( 0.855)² + ( 2 x -0.377 x 0.65)
v² = ( 0.855)² - ( 2 x 0.377 x 0.65)
v² = 0.24
v = √ 0.24
v = 0.5 m/s
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5. What are 3 ways you can alter pH for the benefit of you and
your family?
WHat does that mean?
A sphere has a surface uniformly charged with 3.30 C. At what distance from its center is the potential 4.50 MV
Answer:
r = 6.6 x 10³ m = 6600 m
Explanation:
The potential at a distance from a charged sphere can be given as follows:
\(V = \frac{kq}{r}\\\\r = \frac{kq}{V}\)
where,
r = distance = ?
k = Colomb Constant = 9 x 10⁹ Nm²/C²
q = charge on sphere = 3.3 C
V = potential = 4.5 MV = 4.5 x 10⁶ V
Therefore,
\(r = \frac{(9\ x\ 10^9\ Nm^2/C^2)(3.3\ C)}{4.5\ x\ 10^6\ V}\)
r = 6.6 x 10³ m = 6600 m
solve for a in the acceleration equation
To calculate acceleration, you use the equation a =Δv/Δt, where Δv is the change in velocity, and Δt is the time it takes for the change to occur.
In physics, acceleration is the change in velocity in a given unit of time. The acceleration of an object is caused by a force acting on the object, as explained in Newton's second law. The SI unit for acceleration is meters per second squared (m/s). Acceleration is the product of the velocity (m/s) divided by the time (s). So, the resulting formula is a = v/t.
Acceleration and the most basic velocity in acceleration are how fast a car can increase its speed, while velocity looks at how fast a car travels a certain distance.
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Please help I only have 2 minutes left
Answer:
I believe it is C
Explanation:
Because salt makes everything taste bitter if you add to much of it.
Dominic made the table below to organize his notes about mixtures. A 1-column table. The first column labeled properties of mixtures has entries has no set composition, must have more than one state of matter, must have more than one substance. What mistake did Dominic make? The title should read “Properties of Solutions” because some mixtures do not have all of the properties listed. There is a definite recipe to make each mixture, so the composition of a mixture is set. Although it is possible to have more than one state, it is also possible to have only one state. A single substance can be used to make a mixture if the substance is composed of more than one element.
Answer:
The is: Although it is possible to have more than one state, it is also possible to have only one state.
Explanation:
Hope this helps! ;-)
Answer:
Although it is possible to have more than one state, it is also possible to have only one state.
Explanation:
What is sound waves
Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.
Characteristics of sound wavesFrequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).
Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.
Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.
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1. What are Earth's natural climate cycles?
Help ASAP). Describe the Net Force lab and explain what the lab demonstrated? Will Mark Brainliest. Working on it now can someone please help
Answer: The net force acting on an object is the sum of all the force acting on it, and the net force of an object is zero. I f the forces acting on it tend to cancel each other. For example you are sit in a chair, the earth's gravity is pulling you down, but the chair is pushing you up with an equal amount of force.
There is my answer from my notebook .I hope its good :)
who predict the black hole
Answer:
Albert Einstein
Explanation:
He first predicted the existence of black holes in 1916
2. The muscles on the right side of your body are controlled by what part of your brain? the right cortex the right hemisphere the left cortex the left hemisphere
Answer:
Motor cortex
Both hemispheres have a motor cortex, with each side controlling muscles on the opposite side of the body (i.e, the left hemisphere controls muscles on the right side of the body).
Explanation:
I need help with this table pleasecalculate relative density of steel. Use table 3
Take into account that the relative density is given by:
\(\rho_{\text{rel}}=\frac{\rho}{\rho_{\text{water}}}\)where ρ, in this case, is the density of the steel and ρwater is the density of water (1000 kg/m^3).
The density of the steel is:
\(\rho=\frac{\text{mass}}{\text{volume}}\)Based on table 3, you have:
mass = 50.7 g = 0.0507 kg
volume = 0.0000063 m^3
\(\rho=\frac{0.0507kg}{0.0000063m^3}\approx8047.62\frac{kg}{m^3}\)Then, for the relative density you obtain:
\(\rho_{\text{rel}}=\frac{\rho}{\rho_{\text{water}}}=\frac{8047.62\frac{kg}{m^3}}{1000\frac{kg}{m^3}}\approx8.048\)Hence, the relative density of steel is 8.048
c = speed of light = 3.00 × 108 m/s
A gamma ray has a very high frequency of about 1019 s−1. What is the wavelength of the gamma ray?
A.
3.00 × 10−11 m
B.
3.00 × 1027 m
C.
3.33 × 1010 m
D.
3.33 × 10−12 m
URGENT!!!!!!!!!!
Answer:
The correct answer is option A: 3.00 × 10^(-11) m.
Explanation:
To find the wavelength of a gamma ray with a frequency of about 10^19 s^(-1), we can use the equation:
wavelength = speed of light / frequency
Given:
Speed of light (c) = 3.00 × 10^8 m/s
Frequency (f) = 10^19 s^(-1)
Substituting the values into the equation:
wavelength = (3.00 × 10^8 m/s) / (10^19 s^(-1))
To simplify the expression, we can rewrite the denominator as (1 / 10^(-19)) s:
wavelength = (3.00 × 10^8 m/s) / (1 / 10^(-19)) s
To divide by a fraction, we multiply by its reciprocal:
wavelength = (3.00 × 10^8 m/s) × (10^(-19) s)
Applying the properties of exponents, we can add the exponents when multiplying with the same base:
wavelength = 3.00 × 10^(-11) m
Therefore, the wavelength of the gamma ray is approximately 3.00 × 10^(-11) m.
wires which have protective covers for them are called
Answer:
plastic cover
Explanation:
Plz mark as brainliest and follow me plz
Consider the mass and velocity values of Objects A and B below.
Compared to Object B, Object A has
momentum
Object A
Object B
4kg
2 kg
=4m's
v=4m's
O the same
O two times the
O one fourth the
O four times the
O eight times the
O impossible to tell without knowledge of the F and a
O one half the
Answer:
the same
Explanation:
please tell fast plzzzzzz
Define conductor and insulator, including how the resistance is different in the two, and give at least one example of each.
Answer:
Those substances which can conduct electricity are called conductors, while those substances which don't conduct electricity are called insulators.
Resistance is the obstruction provided by the material through which the current passes,so since conductors conduct electricity and insulators don't,so the obstruction i.e resistance provided by the conductor must be less,while insulators being unable to conduct electricity,has very high resistance.
Example of conductor is copper
Example of insulator is plastic
The electrostatic force between two charges is originally F. Which expression represents the new electrostatic force between the two charges if one charge doubles and the other one is divided by three?
• 1/6
• 3/2
• 2/3
• 6
Answer: c)• 2/3
Explanation:
Lets say q1 and q2 are two charges with r distance far apart.
So electrostatic force
F = (k q1 q2) / r²
as k = Coulomb's constant
Now
q1' = 2q1
q2' = q2/3
Therefore the new electrostatic force
F' = (k q'1 q'2) / r²
F' = (k 2q1 q2) / 3r²
F' = 2/3 [(k q1 q2) / r²]
so F' = 2/3F
New electrostatic force is 2/3F
The expression that represents the new electrostatic force between the two charges if one charge doubles and the other one is divided by three is;
Option C; F_new = ²/₃F
Formula for electrostatic force is;
F = kq₁q₂/r²
where;
k = Coulomb's constant
q₁ = first charge
q₂ = second charge
r = distance between charges
Now, we are told that one charge doubles and the other one is divided by three. Thus, the new charges are now;
2q₁ and q₂/3
Thus;
F_new = k(2q₁ × q₂/3) / r²
F_new = ²/₃kq₁q₂/r²
F_new in terms of F is;
F_new = ²/₃F
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What two structures help ecoli move
Escherichia coli use long, whip-like structures called flagella to propel themselves.
What is E.coli.?Escherichia coli, also known as E. coli, is a Gram-negative, facultative anaerobic, rod-shaped, coliform bacterium of the genus Escherichia that is commonly found in the lower intestine of warm-blooded organisms
Given is to find what two structures help E.coli move.
Escherichia coli use long, whip-like structures called flagella to propel themselves. Motors in the cell's wall spin the flagella into bundles that rotate counter-clockwise, creating a twist that causes the bacterium to rotate clockwise, or towards the right when viewed from above.
Therefore, Escherichia coli use long, whip-like structures called flagella to propel themselves.
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Question 12 of 34
A water faucet has a circular handle with radius 2.5 cm attached to a central
shaft with radius 0.50 cm. What is the mechanical advantage of the faucet
handle?
OA. 0.20
OB. 1.3
OC. 5.0
OD. 2.0
Answer:
C: 5
Explanation:
MA = radius of wheel/ radius of axle
MA =2.5/0.5
MA = 5.0
Brainlist!! Help!! Atom A consists of 10 protons, 12 neutrons, and 10 electrons.
Atom B consists of 10 protons, 10 neutrons, and 12 electrons.
The atoms are isotopes of each other.
The atoms are not isotopes of each other.
Atom A has 10 protons, 12 neutrons, and 10 electrons, while Atom B has 10 protons, 10 neutrons, and 12 electrons.
Atom A and Atom B are not isotopes of each other. Isotopes are atoms of the same element that differ in the number of neutrons but have the same number of protons. In this case, Atom A and Atom B have different numbers of protons, which means they are not isotopes of each other.
The number of protons determines the element, and since Atom A and Atom B have different numbers of protons, they belong to different elements.
Isotopes, on the other hand, have the same number of protons but differ in the number of neutrons.
This variation in the number of neutrons gives isotopes different atomic masses while retaining the same chemical properties.
However, Atom A and Atom B do not fulfill this criterion, so they cannot be considered isotopes of each other.
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Which example represents a class 2 lever? (1 point)
O salad tongs picking up salad
O tweezers plucking hairs
O a car door being opened and shut
a screwdriver opening a paint can
The example that represents a class 2 lever is: D. a screwdriver opening a paint can.
Which example represents a class 2 lever?The load is situated in a class 2 lever halfway between the fulcrum and the effort. The screwdriver's resting place against the paint can's rim serves as the fulcrum in this scenario.
The paint can's lid serves as the load, and the force exerted by the hand on the screwdriver's handle serves as the effort. A class 2 lever can be identified by the load being situated between the fulcrum and the effort.
Tweezers, salad tongs, and opening and closing a car door are not examples of class 2 levers. Class 1 levers include things like tweezers and salad tongs, whereas class 3 levers include things like car doors that open and close.
Therefore the correct option is D.
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A material that reflects or absorbs all the light that strikes it is
A. opaque.
B. transparent.
C. translucent.
D. primary.
Answer:
b. transparent
Explanation:
Photons interact with an object by some combination of reflection, absorption and transmission. Some materials, such as plate glass and clean water, transmit much of the light that falls on them and reflect little of it; such materials are called optically transparent.