ans: 4m/s²
and 2m/s²
step:
f=m.a
in first condition
f=12N , M=3kg
so,
12=3.a
a=12/3
a=4m/s².
similarly
in second condition
f=12N ,M=6Kg
so,
12=a.6
a=12/6
a=2m/s²
relationship between magnetism and electromagnetism
Answer:
The key difference between the two is that magnetism refers to the phenomena associated with magnetic fields or magnetic forces, whereas the term electromagnetism is the type of magnetism produced by electric current, and is associated with both magnetic fields and electric fields.
1. A ball is at rest on the top of a hill (see the figure).
At the top of the hill, the ball will have [the maximum value of its, no, the minimum value of its] gravitational potential energy and [no, the maximum value of its] kinetic energy. If the ball rolls down the hill then, its [gravitational potential energy, kinetic energy] is converted to [gravitational potential energy, kinetic energy] when it gets to the ground.
2. Get your stopwatch ready and prepare to drop the object from the height h you selected in the previous step. You should drop the object so its [bottom, top, middle] part is initially at the height h. The initial speed of the ball [zero, 9.8 m/s, 9.8 m/s^2, depends on the height h] You'll need to measure the time from when the ball leaves your hand to exactly when it hits the ground [ for the first time it bounces, after it bounces and then comes to rest, both the first time and then after it bounces; then average the two times]
.
If a 3.5 kg object is accelerating at 0.80 /s^2, the net force F causing this motion is ____ N.
A) 2.2
B)2.8
C)3.4
D)4.0
Answer:
The answer is option BExplanation:
To find the force acting on an object we use the formula
force = mass × accelerationFrom the question
mass = 3.5 kg
acceleration = 0.80 m/s²
We have
Force = 3.5 × 0.8
We have the final answer as
2.8 NHope this helps you
Which mode of kinetic energy contributes to temperature?
Answer:
Kinetic energy Temperature
Explanation:
how long does it take for light to travel 2.5m in water?
reflection in general physics
Explanation:
Reflection is the change in direction of a wavefront at an interface between two different media so that the wavefront returns into the medium from which it originated. Common examples include the reflection of light, sound and water waves.
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What did Michael Faraday Discover?
A. The unit for measuring electric currents
B. Gravity
C. Electricity
D. Electric current can create magnetic field
Answer:
D
Explanation:
Michael Faraday is probably best known for his discovery of electromagnetic induction, his contributions to electrical engineering and electrochemistry or due to the fact that he was responsible for introducing the concept of field in physics to describe electromagnetic interaction.
Electromagnetic or magnetic induction is the production of an electromotive force across an electrical conductor in a changing magnetic field.
Electrical engineering is an engineering discipline concerned with the study, design and application of equipment, devices and systems which use electricity, electronics, and electromagnetism.
Electrochemistry is the branch of physical chemistry that studies the relationship between electricity, as a measurable and quantitative phenomenon, and identifiable chemical change, with either electricity considered an outcome of a particular chemical change or vice versa.
Find the magnitude of acceleration (ft/s^2) a person experiences when he or she is texting and driving 58mph, hits a wall, and comes to a complete stop .24 seconds after impact.
Answer:
350 ft/s²
Explanation:
First, convert mph to ft/s.
58 mi/hr × (5280 ft/mi) × (1 hr / 3600 s) = 85.1 ft/s
Given:
v₀ = 85.1 ft/s
v = 0 ft/s
t = 0.24 s
Find: a
v = at + v₀
a = (v − v₀) / t
a = (0 ft/s − 85.1 ft/s) / 0.24 s
a = -354 ft/s²
Rounded to two significant figures, the magnitude of the acceleration is 350 ft/s².
A parallel plate capacitor with plates of area (A) and plate separation (d) is charged so that the potential difference between its plates is (V). While the capacitor is still connected to the power source and its plate separation is decreased to d/4, which statement is correct? The charge on the plates is decreased to one-fourth its original value. The capacitance is unchanged. The voltage between the plates is decreased to one-fourth its original value. The charge on the plates is increased four times its original value. The voltage between the plates is increased four times its original value. The charge on the plates is unchanged.
The correct statement is (d) The charge on the plates is increased four times its original value.
What is parallel plate capacitor?
A parallel plate capacitor is a type of capacitor that consists of two parallel conductive plates separated by a dielectric material. It is a type of capacitor used in electrical circuits to store electrical energy. The plates are usually made of metal and the dielectric material is usually a thin non-conductive material like paper or plastic. The size of the capacitor is determined by the distance between the plates and the dielectric material.
This is because the charge on the capacitor plates is proportional to the voltage across the plates and the capacitance, which is given by the formula C = ε_0 * A / d, where ε_0 is the electric constant and A is the area of the plates.
When the plate separation is decreased to d/4, the capacitance of the capacitor becomes C' = ε_0 * A / (d/4) = 4 * ε_0 * A / d, and thus the charge on the plates becomes Q' = C' * V = 4 * Q.
Therefore, The charge on the plates is increased four times its original value is the correct answer.
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Which statement does not describe brainstorming?
A Keep a record of ideas.
B Keep criticism of other's ideas to yourself.
C Collect only a few ideas.
D Use all of the information found when researching
Answer:
d
Explanation:
i just know (pls check out my question pls i will give nayone who answers brainiest)
A car goes by 20 m/sec for 3 minutes. Find traveled distance?
A distributor of outdoor yard lights has four suppliers. This past season she purchased 40% of the lights from Franklin Lighting, 30% from Wilson & Sons, 20% from Evergreen Supply, and the rest from A. L. Scott. In prior years, 3% of Franklin's lights were defective, 6% of the Wilson lights were defective, 2% of Evergreen's were defective, and 8% of the Scott lights were defective. When the lights arrive at the distributor, she puts them in inventory without identifying the supplier. Suppose that a defective light string has been pulled from inventory; what is the probability that it was supplied by Franklin Lighting?
The statistical likelihood that it has been delivered by Franklin Lighting is 0.285714. When an outdoor lighting distributor has four suppliers.
What is the primary function of lighting?All lighting serves the purpose of providing illumination. A lamp's light output is measured. A 100-watt warm white lamp produces approximately 1600 lumens. The intensity of luminance is measured.
What are the advantages of good lighting?Appropriate lighting, free of glare and shadows, can start reducing eye fatigue and cramps; it can also help to prevent workplace accidents by increasing visibility of moving parts of machinery and many other safety hazards.
defective P(D)=0.012+0.018+0.004+0.008
=0.042
probability that it was supplied by Franklin Lighting if it is found defective =P(F)*P(D|F)/P(D) =0.012/0.042
=0.285714
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The force between a pair of charges is 900 newtons. The distance between the charges is 0.01 meters. If one of the charges is 2e-10 C what is the strength of the other charge ?
Answer:
\( \fbox{strength \: of \: the \: other \: charge = - 0.0196 Ke \: Coulomb}\)
Explanation:
Given:
Force between pair of charges= 900 newtons
The distance between the charges = 0.01 meters
Strength of Charge first q1 = 2e-10 Coulomb
To find:
Strength of Charge second q2 = ____ Coulomb?
Solution:
We know that,
Force between two charges separate by distance r is given by the equation,
\(|F| = K_e \frac{q1 \cdot \: q2}{ {r}^{2} } \\ 900 =K_e \frac{(2e - 10)\cdot \: q2}{ {0.01}^{2} } \\ 900 \times {10}^{ - 4} = K_e {(2e - 10)\cdot \: q2} \\ q2 = \frac{9 \times {10}^{ - 2} }{(2e - 10) K_e} \\ \\ \fbox{We \: know \: that \: e = 2.71 } \\ substituting \: the \: value \: \\ q2 = \frac{9 \times {10}^{ - 2} }{(2 \times 2.71 - 10)K_e} \\ q2 = \frac{0.09}{ - 4.58 K_e} \\ q2 = \frac{-0.0196}{K_e}\: coulomb\)
\( \fbox{strength \: of \: the \: other \: charge = - 0.0196 Ke \: Coulomb}\)
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What do we call the small changes that
could result in large future changes?
A. the "butterfly effect"
B. the "snowflake effect"
C. the "ripple effect"
D. the "trickle-down effect"
Answer:
The "butterfly Effect"
Explanation:
The "butterfly effect" will probably have big changes in the future.
A 52 kg and a 95 kg skydiver jump from an airplane at an altitude of 4750 m, both falling in the pike position. Assume all values are accurate to three significant digits. (Assume that the density of air is 1.21 kg/m3 and the drag coefficient of a skydiver in a pike position is 0.7.) If each skydiver has a frontal area of 0.14 m2, calculate their terminal velocities (in m/s). 52 kg skydiver m/s 95 kg skydiver m/s How long will it take (in s) for each skydiver to reach the ground (assuming the time to reach terminal velocity is small)
Answer: 52 kg skydiver: 9.09 m/s and 522.55 s
95 kg skydiver: 12.3 m/s and 386.2 s
Explanation: Drag Force is an opposite force when an object is moving in a fluid.
For skydivers, when falling through the air, the forces acting on it are gravitational and drag forces. At a certain point, drag force equals gravitational force, which is constant on any part of the planet, producing a net force that is zero. Since there is no net force, there is no acceleration and, consequently, velocity is constant. When that happens, the person reached the Terminal Velocity.
Drag Force and Velocity are proportional to the squared speed. So, terminal velocity is given by:
\(F_{G}=F_{D}\)
\(mg=\frac{1}{2}C \rho Av_{T}^{2}\)
\(v_{T}=\sqrt{\frac{2mg}{\rho CA} }\)
where
m is mass in kg
g is acceleration due to gravitational force in m/s²
ρ is density of the fluid in kg/m³
C is drag coefficient
A is area of the object in the fluid in m²
Calculating:
The 52kg skydiver has terminal velocity of:
\(v_{T}=\sqrt{\frac{2(52)(9.8)}{(1.21)(0.7)(0.14)} }\)
\(v_{T}=\) 9.09
The 95kg skydiver's terminal velocity is
\(v_{T}=\sqrt{\frac{2(95)(9.8)}{(1.21)(0.7)(0.14)} }\)
\(v_{T}=\) 12.3
The 52 kg and 95kg skydivers' terminal velocity are 9.09m/s and 12.3m/s, respectively.
The time each one will reach the floor will be:
52 kg at 9.09 m/s:
\(t=\frac{4750}{9.09}\)
t = 522.5
95 kg at 12.3 m/s:
\(t=\frac{4750}{12.3}\)
t = 386.2
The 52 kg and 95kg skydivers' time to reach the floor are 522.5 s and 386.2 s, respectively.
A 200 W engine generates 4000 J of energy. How long did it run for?
A. 20 s
B. 200 s
C. 0.2 s
D. 2 s
Answer:
A
Explanation:
power = energy/time
200 = energy / t
200 = 4000/t
t = 4000/200= 20 sec
nozz 12. Figure P14.43 shows a stream of water in steady flow from a kitchen faucet. At the faucet the diameter of the stream is 0.960 cm. The stream fills a 125-cm3 container in 16.3 s. Find the diameter of the stream 13.0 cm below the opening of the faucet.
The diameter of the stream below the opening of the faucet is 1.94 cm.
How to find diameter?The diameter of the stream can be found using the formula for the velocity of steady flow in a cylindrical stream:
v = Q / (πr²)
Where Q is the volume flow rate (volume per time), v is the velocity, and r is the radius of the stream.
By rearranging this equation and using the known values of the volume and time, find the radius of the stream 13.0 cm below the opening of the faucet:
r² = Q / (πv) = (125 cm³) / (π x (13.0 cm)² / 4)
r = √(125 / (π x (13.0 cm)² / 4)) = 0.97 cm
2r = 2 x 0.97cm = 1.94 cm
So the diameter of the stream 13.0 cm below the opening of the faucet would be 1.94 cm.
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You are sitting at your dinner table and notice three peas have fallen off of your plate as shown. Each pea has a mass of 0.22g and d=3.6cm. A. Find the magnitude and direction (CCW from the +axis) of the net gravitational force on the pea labeled M1 B. Find the direction (CCW from the +axis) of the net gravitational force on the pea labeled m1
Answer:
force = 2.73 x 10^ -15 N
angle = 153.435
Explanation:
Let us redraw the diagram
Let us call
F13 = force on m1 due to m3
F12 = force on m1 due to m2
Now along the x-axis, we have
\(F_x=F_{13}\sin \theta\; \hat{i}\)and along the y-axis, we have
\(F_y=F_{13}\cos \theta+F_{12}\; \hat{j}\)Now,
\(F_{13}=G\frac{m_1m_3}{d^2+(2d)^2}\)and
\(F_{12}=G\frac{m_1m_2}{d^2}\)Therefore, the force along the x-axis becomes
\(\begin{gathered} F_x=F_{13}\sin \theta\; \hat{i} \\ \Rightarrow F_x=G\frac{m_1m_3}{d^2+(2d)^2}\sin \theta\; \hat{i} \end{gathered}\)and the force along the y-axis becomes
\(\begin{gathered} F_y=F_{13}\cos \theta+F_{12}\; \hat{j} \\ \Rightarrow F_y=G\frac{m_1m_3}{d^2+(2d)^2}\cos \theta+G\frac{m_1m_2}{d^2}\hat{\; j} \end{gathered}\)Since
\(\sin \theta=\frac{2d}{\sqrt[]{d^2+(2d)^2}}=\frac{2d}{d\sqrt[]{5}}=\frac{2}{\sqrt[]{5}}\)and
\(\cos \theta=\frac{d}{\sqrt[]{d^2+(2d)^2}}=\frac{d}{d\sqrt[]{5}}=\frac{1}{\sqrt[]{5}}\)The above equations become
\(F_x=G\frac{m_1m_3}{d^2+(2d)^2}\times\frac{2}{\sqrt[]{5}}\; \hat{i}\)\(\Rightarrow\boxed{F_x=G\frac{m_1m_3}{5d^2}\times\frac{2}{\sqrt[]{5}}\; \hat{i}}\)and
\(\boxed{F_y=G\frac{m_1m_3}{5d^2}\times\frac{1}{\sqrt[]{5}}+G\frac{m_1m_2}{d^2}\hat{j}}\)To find the numerical value, we now put
G = 6.67 x 10^-11
m_1 = m_2 = m_3 = 2.2 x 10^-4 kg
d = 0.036 m
into the above equations and get
\(F_x=(6.67\times10^{-11})\frac{(2.2\times10^{-4})^2}{5(0.036)^2}\times\frac{2}{\sqrt[]{5}}\; \hat{i}\)\(\boxed{F_x=4.46\times20^{-16}\; \; \hat{i}}\)and
\(F_y=(6.67\times10^{-11})\frac{(2.2\times10^{-4})^2}{5(0.036)^2}\times\frac{1}{\sqrt[]{5}}+(6.67\times10^{-11})\frac{(2.2\times10^{-4})^2}{(0.036)^2}\hat{j}\)\(\Rightarrow\boxed{F_y=2.7\times10^{-15}\; \hat{j}}\)Therefore, the net gravitational force is
\(F_{\text{tot}}=4.46\times20^{-16}\; \; \hat{i}+2.7\times10^{-15}\; \hat{j}\)the magnitude of this net force is
\(|F_{\text{tot}}|=\sqrt[]{(4.46\times20^{-16})^2+(2.7\times10^{-15})^2}\)\(\boxed{|F_{\text{tot}}|=2.73\times10^{-15}}\)Finally, we need to find the direction of this force.
To specify, the direction, we need to find the angle this force makes counterclockwise with respect the x-axis.
The angle is given by
\(\cos \theta=\frac{1}{\sqrt[]{5}}\)\(\Rightarrow\theta=63.435^o\)adding additional 90 degrees gives the angle with respect to the positive x-axis.
\(\theta+90^o=153.435^o\)Hence, the force is directed at about 153 degrees counterclockwise with respect to the x-axis.
A car starts from rest at a stop sign. It accelerates at 4.0 m/s^2 for 6 s, coasts for 2.0 s, and then slows down at a rate of 3.0 m/s^2 for the next stop sign How far apart are the stop signs?
The motion of the car between the first and last stops is divided in three parts:
• The motion where the car speeds up with acceleration of 4m/s^2.
,• The motion without acceleration (when the car coasts for 2 seconds).
,• The motion where the car slows down with acceleration of 3 m/s^2.
To determine how far apart the stop signs are we need to calculate how much distance the car traveled in each part. Let's analyze each situation.
First part of the motion.
For this part of the motion of the car we have a constant acceleration, this means that we have an uniform accelerated motion. To determine the distance traveled in this part we can use the equation:
\(x=x_0+v_0t+\frac{1}{2}at^2\)where x is the final position, x0 is the initial position, v0 is the initial velocity, a is the acceleration and t is the time.
In this case the initial position is zero (in here we are putting the origin of the motion at the stop sign), the initial velocity is zero (since the car starts from rest), the acceleration is 4 m/s^2 and the time is 6 seconds; plugging this values in the equation above we have that:
\(\begin{gathered} x=0+0(6)+\frac{1}{2}(4)(6)^2 \\ x=(2)(36) \\ x=72 \end{gathered}\)Hence, in this part of the motion the car travelled 72 meters.
We will need the final velocity for this part of the motion in order to calculate the distance traveled in the second part of the motion so let's calculate it. The final velocity can be obtained from the equation:
\(a=\frac{v_f-v_0}{t}\)plugging the values we know and solving for the final velocity we have that:
\(\begin{gathered} 4=\frac{v_f-0}{6} \\ v_f=(6)(4) \\ v_f=24 \end{gathered}\)Therefore the car is traveling at 24 m/s when it starts to coast.
Second part of the motion.
In this part of the motion the car coasts, this means that it is not accelerating, and for this reason, the car does not change its velocity. For this reason we have an uniform rectilinear motion. The change in position in a rectilinear motion is given by:
\(x=x_0+vt\)Changing our origin of the motion to where the car starts to coast we have that the initial position is zero, the velocity is 24 m/s (the velocity in which the car stopped accelerating) and the time is 2 seconds. Plugging this values in the equation we have that:
\(\begin{gathered} x=0+(24)(2) \\ x=48 \end{gathered}\)And then, we conclude, the car travelled 48 meters in this part of the motion.
Third part of the motion.
In here we know that the car is slowing down with an acceleration of 3 m/s^2 until it stops in the next stop sign. Since the acceleration is constant once again we have an uniform accelerated motion. To determine the distance the car traveled in this part we can use the equation:
\(v^2_f-v^2_0=2a(x-x_0)\)In this case we know that the final velocity is zero (since the car stops), the initial velocity is 24 m/s (since the car was moving in an uniform rectiliniar motion in the previous part of the motion) and that the acceleration is -3 m/s^2 (we have to use a negative sign since the car is slowing down, this means that the acceleration is negative); plugging the values we have that:
\(\begin{gathered} 0^2-24^2=2(-3)(x-0) \\ -576=-6x \\ x=\frac{-576}{-6} \\ x=96 \end{gathered}\)Hence in this part in the motion the car travelled 96 meters.
Finally, now that we know how much the car travelled in each part of the motion, we can calculate how far apart the stop signs are; to do this we add the distance the car travelled in each part, then we have:
\(72+48+96=216\)Therefore, the stops signs are 216 meters apart.
1. A roller coaster car rapidly picks up speed it as it rolls down a slope. As it starts
down the slope, its speed is 4 m/s. But 3 seconds later, at the bottom of the
slope, its speed is 22 m/s. What is its average acceleration?
Answer:
Average acceleration = 6m/s²
Explanation:
Given the following data;
Initial velocity, u = 4m/s
Final velocity, v = 22m/s
Time, t = 3 seconds
To find the average acceleration;
Acceleration = (v - u)/t
Substituting into the equation, we have;
Acceleration = (22 - 4)/3
Acceleration = 18/3
Acceleration = 6m/s²
what happens to the cereal underneath the clear container when it's near a wool?
Answer:
they can't breath and they gon dead
Explanation:
yum yum yum yum yum
Answer:
the answer is in my mind but not coming in the mouth I'll tell you when I remember ''sorry ''
Which has more mass electron or ion?
what will you use to measure the length of a copper wire of 50cm long?
Answer:
BS33
Explanation:
its a cable length meter used for measuring length of all kinds of wires.
A horizontally launched projectile lands 75.72 m below the launch point and a horizontal distance of 104.42 m/s from the launch point. How long did it take to hit the ground?
With an initial horizontal velocity of 32.31 m/s and a time of 3.23 seconds to impact the earth, the projectile was launched.
Is the projectile's velocity in the y direction zero when it is fired horizontally?When an object is hurled horizontally in projectile motion, it has zero initial vertical velocity and only a horizontal initial velocity. Through the projectile's entire motion, the original horizontal velocity is maintained.
\(y = 1/2 * a_y * t^2\)
\(t^2 = 2y / a_y\)
\(t = sqrt(2y / a_y)t = sqrt(2*75.72 m / 9.81 m/s^2)\)
t = 3.23 s (rounded to two decimal places)
\(x = vi_x * t\)
\(vi_x = x / t\)
\(vi_x = 104.42 m / 3.23 s\)
\(vi_x = 32.31 m/s\)(rounded to two decimal places)
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HOMEWORK:A piece of metal has a weight of 6.5 N when it is in air and 3.0 N when it is submerged into water. What is the buoyant force on the piece of iron?(A) 3.5 N (B) 2.0 N (C) 1.5 N (D) 1.0 N (E) 0.5 N
The buoyant force = 3.5 N
Option A is correct
Explanation:Weight of the metal in air = 6.5 N
Weight of the metal in water = 3.0 N
The buoyant force = Weight in air - Weight in water
The buoyant force = 6.5 N - 3.0 N
The buoyant force = 3.5 N
Cool the matter back down to a solid state. How does its shape compare to its original shape?Why? *
Answer:
i am just answering what this guy said this answer isnt mine ok -v-/ Both soaps and emulsifiers contain only one nonpolar tail group Both soaps and emulsifiers consist of fatty acid chains and a polar head group Both soaps and emulsifiers work in the same manner
Soaps contain two polar tail groups, but emulsifiers have only one polar tail group ,Soaps contain only one nonpolar tail group, but emulsifiers have two nonpolar tail group
2. The term fluids refers to.....
Answer:
In physics, the term "fluids" refers to substances that have no fixed shape and are capable of flowing. Fluids can be categorized into two main types: liquids and gases. Both liquids and gases are considered fluids because they can flow and take the shape of their container. Examples of liquids include water, oil, and blood, while examples of gases include air, helium, and carbon dioxide. The study of fluids is known as fluid mechanics and is an important field in physics and engineering.
Explanation:
A flat sheet of paper of area 0.450 m2 is oriented so that the normal to the sheet is at an angle of 600 to a uniform electric field of magnitude 18 N C-1. What is the magnitude of the electric flux through the sheet? A. 3.22 N m2 C-1 B. 21.42 N m2 C-1 C. 5.04 N m2 C-1 D. 11.72 N m2 C-1 E. 4.05 N m2 C
The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).
The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.
In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²
(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:
Electric flux = Electric field strength × Area
Electric flux = 18 N C⁻¹ × 0.450 m²
Electric flux = 8.1 N m² C⁻¹
In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.
The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).
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When ice melts at 0C its volume decreases. Is the internal energy change greater than, less than, or equal to the heat added? How can you tell?
In this case W is negative, the heat input is less than in the constant volume case, and CP is less than CV. If the ice melts it is as if it were being compressed because its volume is reduced.
MyHeritageExplain why aircraft are carefully designed so that parts do not resonate.
Answer:
See the answer Explain why aircraft are carefully designed so that parts do not resonate. Expert Answer This virtually takes place, however maximum usually in small piston-engined airplanes, in particular dual-engined airplanes. The resonant frequency of the fuselage of a small plane goes to have numerous nodes, withinside the low loads of hertz.