Answer:
Statistical
Step-by-step explanation:
You need to collect data to determine the answer of that.
Answer:
Yes
Step-by-step explanation:
"How many apps do my classmates have on their phones?" This is a statistical question because a statistical question has to be a question that can be used to collect data. If the question was something like "How many apps does Melissa have on her phone?" it would NOT be a statistical question because it is only asking about one specific person and you wouldn't be collecting data.
I wasn't really sure how to explain it but I hope it makes sense! :)
Anastasia has been accepted into a 4- year University as an architect student. She was offered a scholarship of $17,800 per year. The cost per year is $17,400 in tuition and fees, $10,350 for room and board, and 850 for books. What would the cost be after attending school for four years?
Answer:
256,800 I believe
Step-by-step explanation:
you add up all the numbers and multiply by 4
Find the value of θ for 0≤ϑ≤2π cot ϑ= √3
Please answer & explain wholly.
Furthermore, is my answer correct?
Seeing as the value is positive, is in
quadrants 1 & 3, the values of ϑ
The value of θ for the equation cot(ϑ) = √3 is approximately 0.588 radians (in the range 0 ≤ ϑ ≤ 2π).
To find the value of θ for the equation cot(ϑ) = √3, we need to solve for ϑ in the range 0 ≤ ϑ ≤ 2π.
The cotangent function is the reciprocal of the tangent function, so we can rewrite the equation as follows:
cot(ϑ) = √3
1/tan(ϑ) = √3
tan(ϑ) = 1/√3
To find the angle ϑ that satisfies this equation, we can use the inverse tangent function (arctan or tan⁻¹) on both sides:
ϑ = tan⁻¹(1/√3)
Now, let's calculate the value of ϑ:
ϑ = tan⁻¹(1/√3)
ϑ ≈ 0.588 radians (rounded to three decimal places)
The value of ϑ is approximately 0.588 radians.
Regarding the quadrants, the cotangent function is positive in the first and third quadrants. Since ϑ = 0.588 radians is positive, your answer is correct.
The values of ϑ satisfying the equation cot(ϑ) = √3 lie in the first and third quadrants.
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the variance and standard deviation are the most widely used measures of central location.
T/F
False , the variance and standard deviation are not measures of central location
Given data ,
The variance and standard deviation are not measures of central location but measures of dispersion or spread of a dataset
Measures of central location include the mean, median, and mode, which represent the typical or central value of a dataset
The variance and standard deviation are measures of dispersion or spread in a dataset. They provide information about how the values in a dataset are spread out around the mean.
In order to understand the variability or dispersion of data points within a dataset, one must take into account both the variance and standard deviation. They provide information on the range of values and aid in calculating how far away from the mean certain data points are. In statistics and data analysis, these metrics are frequently used to comprehend and evaluate the variance of various datasets.
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the radius of a circle is increasing at a rate of 8 centimeters per minute. find the rate of change of the area when the radius is 2 centimeters.
The rate of change of the area when the radius is 2 centimeters is 32π square centimeters per minute.
To find the rate of change of the area of a circle with respect to its radius, we can use the formula for the area of a circle, which is A = πr², where A is the area and r is the radius.
We are given that the radius is increasing at a rate of 8 centimeters per minute, so we can express this as dr/dt = 8 cm/min.
To find the rate of change of the area when the radius is 2 centimeters, we need to differentiate the area formula with respect to the radius:
dA/dt = d/dt (πr²)
Using the chain rule, we have:
dA/dt = dA/dr * dr/dt
Since we want to find the rate of change of the area when the radius is 2 centimeters, we substitute r = 2 into the derivative:
dA/dt = dA/dr * dr/dt = (π(2)²) * 8 = 4π * 8 = 32π
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Find the probability of rolling a 6 -sided dice and getting a number that is a divisor of 20.
Explanation:
On the die, the divisors or factors of 20 are: 1, 2, 4, 5
We have 4 faces we want out of 6 faces total
So 4/6 = 2/3 is the probability of getting a divisor of 20.
does anything in the plot of the semimajor axis versus the period change when the eccentricity is changed?
Yes, the connection between the semimajor axis and an orbit's period varies as the eccentricity of the orbit changes.
What is eccentricity?In geometry, the eccentric definition is the distance from any point on a conic section to the focus divided by the perpendicular distance from that point to the nearest directrix. In general, eccentricity aids in determining the curvature of a form. The eccentricity grows as the curvature lowers.
Here,
In general, an orbit's period is proportional to the square root of the semimajor axis multiplied by three. This connection, however, is only valid for circular orbits with zero eccentricity. When the eccentricity is larger than zero, the period of the orbit is still determined by the magnitude of the semimajor axis, but it is also determined by the form of the orbit as given by the eccentricity. The relationship between the semimajor axis and the period in this situation is not as straightforward as a proportionate relationship.
As a result, modifying an orbit's eccentricity modifies the connection between the semimajor axis and the period.
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Urgent help!! PLEASE
what is the ratio then what is the value of the ration?
Answer:
For example, if there are eight oranges and six lemons in a bowl of fruit, then the ratio of oranges to lemons is eight to six (that is, 8∶6, which is equivalent to the ratio 4∶3).
prove that if p is an odd prime and p = a 2 b 2 for integers a, b, then p ≡ 1 (mod 4).
To prove that if p is an odd prime and p = a^2 * b^2 for integers a, b, then p ≡ 1 (mod 4), we can use the concept of quadratic residues and the properties of modular arithmetic.
Let's start with the given assumption that p is an odd prime and can be expressed as p = a^2 * b^2, where a and b are integers. We want to prove that p ≡ 1 (mod 4), which means p leaves a remainder of 1 when divided by 4.
We can begin by considering the possible residues of perfect squares modulo 4. When a is an even integer, a^2 ≡ 0 (mod 4) since the square of an even number is divisible by 4. Similarly, when a is an odd integer, a^2 ≡ 1 (mod 4) since the square of an odd number leaves a remainder of 1 when divided by 4.
Now, let's examine the expression p = a^2 * b^2. Since p is a prime number, it cannot be factored into smaller integers, except for 1 and itself. Therefore, both a and b must be either 1 or -1 modulo p. We can express this as:
a ≡ ±1 (mod p)
b ≡ ±1 (mod p)
Now, let's consider the value of p modulo 4:
p ≡ (a^2 * b^2) ≡ (±1)^2 * (±1)^2 ≡ 1 * 1 ≡ 1 (mod 4)
We know that a^2 ≡ 1 (mod 4) for any odd integer a. Therefore, both a^2 and b^2 ≡ 1 (mod 4). When we multiply them together, we still obtain the residue of 1 modulo 4.
Hence, we have proven that if p is an odd prime and p = a^2 * b^2 for integers a, b, then p ≡ 1 (mod 4).
To provide an explanation of the proof, we used the concept of quadratic residues and modular arithmetic. In modular arithmetic, numbers can be classified into different residue classes based on their remainders when divided by a given modulus. In this case, we focused on the modulus 4.
We observed that perfect squares, when divided by 4, can only have residues of 0 or 1. Specifically, the squares of even integers leave a remainder of 0, while the squares of odd integers leave a remainder of 1 when divided by 4.
Using this knowledge, we analyzed the expression p = a^2 * b^2, where p is an odd prime and a, b are integers. Since p is a prime, it cannot be factored into smaller integers, except for 1 and itself. Therefore, a and b must be either 1 or -1 modulo p.
By considering the possible residues of a^2 and b^2 modulo 4, we found that both a^2 and b^2 ≡ 1 (mod 4). When we multiply them together, the resulting product, p = a^2 * b^2, also leaves a remainder of 1 modulo 4.
Thus, we concluded that if p is an odd prime and p = a^2 * b^2 for integers a, b, then p ≡ 1 (mod 4).
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Write an equation of a line in slope-intercept form that is parallel to y=-3x-5 and goes through the point (-1,8)
Answer:
y=-3x+5
Step-by-step explanation:
A line that is parallel to y=-3x-5 will have the same slope, which is -3.
Using the point-slope form, we can write the equation of the line as:
y - 8 = -3(x + 1)
Simplifying:
y - 8 = -3x - 3
Adding 8 to both sides:
y = -3x + 5
Therefore, the equation of the line in slope-intercept form that is parallel to y=-3x-5 and goes through the point (-1,8) is y = -3x + 5.
60 = 15r^((3-1))
Solve for R
Answer:
r=2 or r=-2
Step-by-step explanation:
find each product by factoring the tens.
3×2, 3×20, and 3×200
Product by factoring the tens the product of 3 x 200 is 600.
To find each product by factoring the tens we need to first look at each number and identify their tens digit and ones digit before multiplying by 3 to find their product. Let's consider each of the numbers:
1. 3 x 2 The tens digit in 2 is 0 since it has no tens, and the ones digit is 2.
We can then multiply the tens digit by 3, giving us 0, and multiply the ones digit by 3,
giving us 6. So:3 x 2 = 0 tens
and 6 ones Therefore,
the product of 3 x 2 is 6.2. 3 x 20
The tens digit in 20 is 2 and the ones digit is 0. We can then multiply the tens digit by 3, giving us 6, and multiply the ones digit by 3, giving us
0. So:3 x 20 = 6 t
ens and 0 ones Therefore,
the product of 3 x 20 is 60.3. 3 x 200
The tens digit in 200 is 0 and the ones digit is 0. We can then multiply the tens digit by 3, giving us 0, and multiply the ones digit by 3, giving us 0. So:3 x 200 = 0 tens and 0 ones
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The trustees of a college have accepted a gift of $400,000, but are required to deposit it in an account paying 12% per year, compounded semiannually. They may make equal withdrawals at the end of each six-month period, but the money must last 5 years.
a. Find the amount of each withdrawal.
b. Find the amount of each withdrawal if the money must last 7 years.
Put the steps in order to find the inverse of
y=\(x^{2}\)+2
A 10-pound sack of flour costs $8.
How much does 40 pounds of flour cost?
What is the cost per pound of flour?
cynthia has earned 1,000 and wants to put it in a savings account that earns 5% simple interest assuming she makes no additional deposits or withdrawals what will be the total value of cynthias account after 48 months
Answer:
6746734
Step-by-step explanation:
first fo 45 minus 45 get 0 add then 56 plus 34
Answer:
1200
Step-by-step explanation:
1000(1+.05x4)
5%=.05
convert the months into years
train leaves in 12 minutes and you are 1 mile from the station. you can walk 4 mph and run at 8 mph. how much time can you afford to walk before you must being to run in order to catch the train
Answer:
i think its 8
Step-by-step explanation:
find a vector equation and parametric equations for the line. (use the parameter t.) the line through the point (7, 0, −4) and parallel to the line x = 4 − 4t, y = −1 2t, z = 6 7t
Vector equation: r = <7, 0, -4> + t<4, 2, 7>
Parametric equations: x = 7 + 4t, y = 2t, z = -4 + 7t
To find the vector equation and parametric equations for the line parallel to the given line and passing through the point (7, 0, -4), we can use the direction vector of the given line, which is <4, 2, 7>.
The vector equation of a line is given by r = r0 + td, where r is the position vector of a point on the line, r0 is a known point on the line (in this case, (7, 0, -4)), t is the parameter, and d is the direction vector of the line.
Substituting the values, we have r = <7, 0, -4> + t<4, 2, 7>. This is the vector equation for the line.
To obtain the parametric equations, we can express the vector equation component-wise. Thus, we have x = 7 + 4t, y = 0 + 2t, and z = -4 + 7t. These equations represent the line in terms of the parameter t.
In summary, the vector equation for the line is r = <7, 0, -4> + t<4, 2, 7>, and the corresponding parametric equations are x = 7 + 4t, y = 2t, and z = -4 + 7t. These equations describe the line passing through the given point and parallel to the given line in three-dimensional space.
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Justify if the point (6, 5) is on the parabola with a focus at (2, 2), a vertex at (2, 1) and the directrix is on the x-axis (y = 0). Be sure to use words, numbers or both in your justification.
The equation
We can tell that this parabola opens upwards since the directrix lies on the horizontal axis and the vertex is higher (positive p), so we know this is an x² parabola.
The form of parabola equation we will use with the given information will be (x-h)²=4p(y-k), where h,k is the vertex.
p refers to the distance between either the focus and the vertex or the vertex and the directrix. The y value of the focus is 2, and the y value of the vertex is 1. 2-1=1, so p=1.
From the vertex, (2,1), we know that h = 2 and k = 1.
Therefore, the equation is
(x-2)²=4(1)(y-1)
Verifying
From this, we can now plug in 6 and 5 for x and y in the equation respectively to see if that point falls on it.
(6-2)²=4(5-1)
4²=4*4
16=16
This statement is true, so the point (5,6) does fall on the parabola.
Step-by-step explanation:
To determine whether the point (6, 5) lies on the parabola with a focus at (2, 2), a vertex at (2, 1), and the directrix on the x-axis (y = 0), we can use the definition of a parabola.
A parabola is the set of all points that are equidistant from the focus and the directrix. This distance is also equal to the distance between the point and the vertex.
Let's first find the equation of the parabola. Since the vertex is (2, 1) and the directrix is the x-axis, the axis of symmetry is the line x = 2. This means that the parabola has the equation:
(y - 1)^2 = 4p(x - 2)
where p is the distance between the vertex and the focus, which we need to find. Since the focus is at (2, 2), which is one unit above the vertex, we know that p = 1/4. Substituting this value into the equation above, we get:
(y - 1)^2 = (x - 2)
Now we can check whether the point (6, 5) satisfies this equation. Plugging in x = 6 and y = 5, we get:
(5 - 1)^2 = (6 - 2)
16 = 4
This equation is clearly false, which means that the point (6, 5) does not lie on the parabola with the given focus, vertex, and directrix. Therefore, we can conclude that the point (6, 5) is not equidistant from the focus and the directrix and therefore does not lie on the parabola
The Water Department checks the city water supply on a regular basis for
contaminants such as trihalomethanes (THMs). The Water Department takes
200 samples and estimates that the concentration of THMs in your drinking
water is 3 ppb (parts per billion), with a standard deviation of 0. 3 ppb.
Assuming the samples were random and unbiased, how much confidence
can you have in this data?
We can be 95% confident that the true mean concentration of THMs in your drinking water lies within the range [2.9584 ppb, 3.0416 ppb]. This was calculated using a confidence interval formula for the mean.
The confidence interval for the mean concentration of THMs can be calculated using the formula x ± z * (s/√n), where x is the sample mean, z is the z-score for a given confidence level, s is the sample standard deviation and n is the sample size.
In this case, we have x = 3 ppb, s = 0.3 ppb, and n = 200. To calculate the confidence interval at a certain confidence level (e.g. 95%), we need to find the corresponding z-score. For a 95% confidence level, the z-score is approximately 1.96.
Substituting these values into the formula above gives us:
3 ± 1.96 * (0.3/√200) = [2.9584, 3.0416]
So we can be 95% confident that the true mean concentration of THMs in your drinking water lies within the range [2.9584 ppb, 3.0416 ppb].
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What is the value of Select one: 1 O a. 3 O b.-1 O c. 1 O d. 3 when x = 27, given that f(x) = 2x - sina and f¹(2m) = π ?
The answer is not provided among the given options (a, b, c, or d).The given information states that f(x) = 2x - sina, where "a" is an unknown constant. We also know that f¹(2m) = π.
To find the value of f(x) when x = 27, we need to first determine the value of "a" by using the second piece of information.
f¹(2m) = π means that the derivative of f(x) evaluated at 2m is equal to π.
Taking the derivative of f(x) = 2x - sina:
f'(x) = 2 - cosa
Substituting 2m for x:
f'(2m) = 2 - cos(2m)
We know that f'(2m) = π, so we can set up the equation:
2 - cos(2m) = π
Solving for cos(2m):
cos(2m) = 2 - π
Now, we can substitute the value of "a" back into the original function f(x) = 2x - sina.
f(x) = 2x - sina
f(x) = 2x - sin(acos(2m))
Finally, we can substitute x = 27 into the expression:
f(27) = 2(27) - sin(a * cos(2m))
Without knowing the specific value of "a" and "m" in the given context, we cannot determine the exact value of f(27). Therefore, the answer is not provided among the given options (a, b, c, or d).
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The circumference of a frisbee is 8 in. Find
the radius. Use 3. 14 for pi
The radius of the frisbee is approximately 1.273 inches when the circumference is 8 inches, and we use the value of pi as 3.14.
To calculate the radius, we can use the formula that relates the circumference and radius of a circle. The formula is:
Circumference = 2 * π * radius
Where "Circumference" represents the total distance around the circle, "pi" is a mathematical constant approximately equal to 3.14, and "radius" is the distance from the center of the circle to any point on its boundary.
Now, let's solve the equation for the radius:
Circumference = 2 * π * radius
Substituting the given value of the circumference (8 inches) and the value of π (3.14) into the equation, we get:
8 = 2 * 3.14 * radius
To isolate the radius, we need to divide both sides of the equation by 2 * 3.14:
8 / (2 * 3.14) = radius
Simplifying the right side of the equation, we have:
8 / 6.28 = radius
Calculating the value on the right side, we find:
radius ≈ 1.273
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A gas station offers a lucky draw to customers.
each time you spend more than $20 on gas, you can make a draw to win a prize.
the probability of winning a prize is 1/12
suppose you buy gas 4 times. what is the probability of you winning a prize each time?
Answer/Step-by-step explanation:
Given:
A gas station offers a lucky draw to customers. Each time you spend more than $20 on gas, you can make a draw to win a prize. The probability of winning a prize is 1/12 suppose you buy gas 4 times.
To Find:
what is the probability of you winning a prize each time?
Solve:
Since, it given that you buy gas 4 times. Thus that means:
1/12 × 1/12 × 1/12 × 1/12 or 1/12⁴
Now solving it:
1/12 × 1/12 × 1/12 × 1/12 = 1/20736
Which also means (0.0048%) in decimal form since, 1 divide by 2076 equal to 0.0048%
Kavinsky
Point Suppose that we change the Action-Cost function in the 8-puzzle so that all the actions cost 2 instead of 1 . What changes would this have on our problem and solutions? (Select all that apply) Optimal solutions would have twice as many actions There would be no effect on optimal solution path length or state space The state space would be doubled in size Optimal solutions would have half as many actions
The changes that would occur are Optimal solutions would have twice as many actions and The state space would be doubled in size.
The changes that would occur if we change the Action-Cost function in the 8-puzzle so that all the actions cost 2 instead of 1 are as follows:
Optimal solutions would have twice as many actions: This statement is true. Since the cost of each action is doubled, optimal solutions would require taking twice as many actions compared to the original cost function.
There would be no effect on optimal solution path length or state space: This statement is false. The change in the action cost function affects the calculation of the path length and the exploration of the state space. The optimal solution path length would be longer, and the exploration of the state space might differ due to the change in costs.
The state space would be doubled in size: This statement is false. Changing the action costs does not directly affect the size of the state space. The state space remains the same, consisting of all possible configurations of the 8-puzzle.
Optimal solutions would have half as many actions: This statement is false. As mentioned earlier, optimal solutions would have twice as many actions, not half as many, due to the increased cost of each action.
Therefore, the correct options are:
Optimal solutions would have twice as many actions
The state space would be doubled in size
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formula of area of circle and the circumference
Answer:
A= πr2
Step-by-step explanation:
The area of circle can be calculated by using the formulas: Area = π x r2, in terms of radius 'r'. Area = (π/4) x d2, in terms of diameter, 'd'. Area = C2/4π, in terms of circumference, 'C'.
What is the total cost of a $350 laptop with a 8% tax rate
Answer:
It should be $378. sorry if I am wrong.
Step-by-step explanation:
The population of a small town is increasing at a rate of 325 people per year. Write and solve a multiplication equation to find how long it will take the population to increase by 6, 825
Answer:
21 years
Step-by-step explanation:
For this problem, you only need to divide 6,825 by 325.
6,825/325=21
21 years
find the coordinates of the midpoint of a segment with the given points
To find the midpoint
(0,4 ) (4,8)
x₁ = 0 y₁=4 x₂=4 y₂=8
Formula for finding mid-point is;
[ x₁+x₂ /2 y₁+ y₂ /2]
Substituting the values into the above formula;
x₁+x₂ /2 = 0+4 /2 = 4/2 = 2
Similarly,
y₁+ y₂ /2 = 4+8 /2 = 12/2 =6
The coordinates of the midpoint are (2 , 6)
use the diagram to find the given length in the diagram qr=st=12
The missing lengths in the diagram are CU = 18 and UR = 6
Finding the missing lengths in the diagramFrom the question, we have the following parameters that can be used in our computation:
QR = ST = 12
Also, we have
CU = 7x - 10
CV = 3x + 6
The length of the chords QR and ST have the same measure
This means that
CU = CV
Substitute the known values in the above equation, so, we have the following representation
7x - 10 = 3x + 6
Evaluate the like terms
So, we have
4x = 16
This gives
x = 4
Next, we have
UR = 1/2 * 12
UR = 6
And, we have
CU = 7(4) - 10
CU = 18
Hence, the missing lengths are CU = 18 and UR = 6
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Please help me on this question thanks ! I will mark you brainliest
Answer:
3x+2°=65° (vert opp angles)
3x=65°-2°
=63°
x=63÷3
=21