determine if a line can have a constant rate and not to be proportional. write an agreement to defend your response.

To solve for x, we just need to compute the inverse of A (if it exists) and multiply it by b. If A is invertible, then this method will give us the unique solution to the linear system Ax=b.

To solve a linear system of the form Ax=b using inverse matrices, we can first find the inverse of matrix A (if it exists) and then multiply both sides of the equation by \(A^-1\), giving us:

\(A^-1Ax = A^-1b\)

Since\(A^-1A\) is the identity matrix I, we can simplify the left-hand side to just x:

\(x = A^-1b\)

However, it's worth noting that computing the inverse of a matrix can be computationally expensive, particularly for large matrices.

So, while using inverse matrices can be a useful technique for solving small systems, it may not be the most efficient approach for larger systems. In those cases, other techniques such as Gaussian elimination or LU decomposition may be more appropriate.

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Answer:

C

Step-by-step explanation:

\( \sin(30) = \frac{y}{32} \\ y = 16 \\ \cos(30) = \frac{x}{32} \\ x = 16 \sqrt{3} \)

The kind of transformation which converts the graph of f(x)  into the graph of g(x) is vertical shrink .

What is transformation in graph?

A graph transformation is a procedure that modifies an existing graph or graphed equation to create different version of the following graph.

It is given that the functions are :

f(x) = -9(x+6)2 - 3

g(x) = -9(x-4)2 - 3

We know that if we perform transformation that meant the graph of f(x) is transformed into the graph of g(x).

i.e.,

f(x) = -9(x+6)2 - 3

f(x) = -18(x+6) - 3

f(x) = -18x - 128 - 3

f(x) = -18x - 72 - 56 - 3

f(x) = -9(x-4)2 - 3 - 56

f(x) = g(x) - 56

or g(x) =  f(x) + (-56)

So , as we are adding f(x), this suggests that the transformation is one of the vertical shrink type.

Therefore, the kind of transformation which converts the graph of f(x)  into the graph of g(x) is vertical shrink .

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The probability that it takes 4 shots for the marksman to hit the long-range target is approximately 0.1466, or 14.66%.

To calculate the probability that it takes 4 shots for the marksman to hit the long-range target, we assume each shot is independent and has a success probability of 0.623. The probability of hitting the target on the fourth shot can be calculated using the binomial distribution. The formula for the probability mass function (PMF) of the binomial distribution is:

P(X = k) = C(n, k) * p^k * (1 - p)^(n - k)

Where:

P(X = k) is the probability of exactly k successes,

n is the number of trials,

k is the number of successful trials,

p is the probability of success on a single trial, and

C(n, k) is the binomial coefficient, given by C(n, k) = n! / (k! * (n - k)!)

In this case, n = 4 (the number of shots), k = 4 (the number of successful shots), and p = 0.623 (the probability of hitting the target on each shot). Substituting these values into the formula, we can calculate the probability:

P(X = 4) = C(4, 4) * 0.623^4 * (1 - 0.623)^(4 - 4)

C(4, 4) = 4! / (4! * (4 - 4)!) = 1

P(X = 4) = 1 * 0.623^4 * (1 - 0.623)^(4 - 4)

= 1 * 0.623^4 * 1

= 0.623^4

= 0.1466

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The consumption bundle that will not be the consumer's choice, given the assumptions of choosing the optimal bundle, is option B) 30 snacks and 12 meals. To determine the optimal consumption bundle, we need to consider the consumer's budget constraint and maximize their utility.

Given that the price of snacks is $4 and the price of meals is $10, and the consumer has $240 remaining on their meal card, we can calculate the maximum number of snacks and meals that can be purchased within the budget constraint.

For option A) 5 snacks and 20 meals, the total cost would be $4 × 5 + $10 × 20 = $200. Since the consumer has $240 remaining, this bundle is feasible.

For option B) 30 snacks and 12 meals, the total cost would be $4 × 30 + $10 × 12 = $240. This bundle is on budget constraint, but it may not be the optimal choice since the consumer could potentially consume more meals for the same cost.

For option C) 20 snacks and 16 meals, the total cost would be $4 × 20 + $10 × 16 = $240. This bundle is also on budget constraint.

Since options A, C, and D are all feasible within the budget constraint, the only bundle that will not be the consumer's choice is option B) 30 snacks and 12 meals. The consumer could achieve a higher level of utility by reallocating some snacks to meals while staying within the budget constraint. Therefore, the correct answer is option B.

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Answer:

46$ in total

y=2r+20

If Isabella goes on 13 rides, she would have to pay a total of $46. If she rides 'r' times, the total cost would be expressed by the mathematical equation 20 + 2r.

This question relates to a linear relationship involving a fixed cost and a variable cost. In Isabella's case, the fixed cost is the admission fee, which is $20. The variable cost is the rides, where each ride costs $2.

So, if she goes on 13 rides, she will have to pay: $20 (for admission) + ($2 * 13 (rides)) = $20 + $26 = $46.

For r rides, the total cost would be: $20 (for admission) + ($2 * r (rides)). So the total cost for r rides can be expressed in a mathematical equation as: 20 + 2r.

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Answer:

my phone is gonna die u can use photomath it will give u the answer hope it helped:)))))))

The RTS of the isoquant is 1000K, indicating the rate at which labor can be substituted for capital while maintaining constant production. The labor to capital cost ratio is 0.5. To minimize the cost of producing q units per hour, the specific value of q is needed to find the optimal combination of K and L along the expansion path, represented by the cost function C(K, L) = 40K + 20L.

The RTS (Rate of Technical Substitution) measures the rate at which one input can be substituted for another while keeping the production level constant. To determine the RTS, we need to calculate the derivative of the production function with respect to L, holding q constant.

Given the production function q = 1000KL, we can differentiate it with respect to L:

d(q)/d(L) = 1000K

Therefore, the RTS of the isoquant for production level q is 1000K.

The ratio of labor to capital cost can be calculated by dividing the labor cost by the capital cost.

Labor cost = $20/hour

Capital cost = $40/machine/hour

Ratio of labor to capital cost = Labor cost / Capital cost

                              = $20/hour / $40/machine/hour

                              = 0.5

The ratio of labor to capital cost is 0.5.

To find the combination of K and L that minimizes the cost of producing q units per hour, we need to set up the cost function and take its derivative with respect to both K and L.

Let C(K, L) be the total cost function.

The cost of capital is $40 per machine per hour, and the cost of labor is $20 per hour. Therefore, the total cost function can be expressed as:

C(K, L) = 40K + 20L

To produce q units per hour at minimal cost, we need to find the values of K and L that minimize the total cost function while satisfying the production constraint q = 1000KL.

The expansion path of the firm represents the combinations of K and L that minimize the cost at different production levels q.

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Answer:

89

Step-by-step explanation:

I just multiplied 320 by 0.2 and then 250 by 0.1 and then added them  together. I hope it helps and I'm not sure what method you would use for this but that's mine.

Answer:

549.61

Step-by-step explanation:

5.5*10^2-3.9*10^-1

5.5*100-3.9*0.1

550-0.39

549.61

Answer:

Scientific notation:  5.4961 × 10²

Standard form:  549.61

Step-by-step explanation:

Scientific notation is written in the form \(a\times 10^n\), where \(1 \leq a < 10\) and \(n\) is any positive or negative whole number.

To subtract two numbers in scientific notation, first write the numbers in the same form, with the same exponent (power of 10).

To convert 3.9 × 10⁻¹ so that the base 10 has an exponent of 2, move the decimal point 3 places to the left and add 3 to the exponent:

\(\implies 3.9 \times 10^{-1} = 0.0039 \times 10^2\)

Therefore, we now have:

\(5.5 \times 10^2 - 0.0039 \times 10^2\)

Factor out the common term 10⁻¹:

\(\implies (5.5 - 0.0039) \times 10^2\)

Subtract the numbers:

\(\implies 5.4961 \times 10^2\)

The answer has been given in scientific notation. If the answer should be in standard form then:

\(\implies 5.4961 \times 10^2=549.61\)

There are 720 six-letter sequences possible that use the letters q, u, a, k, e, s once each.

A six-letter sequence that uses the letters q, u, a, k, e, s once each is known as a permutation.

Here, we will learn how many six-letter sequences are possible that use the letters q, u, a, k, e, s once each.

To solve this problem, use the formula for permutations with distinct objects.

Since there are six distinct letters,

The number of six-letter permutations is given by the formula:

P (n, r) = n!/(n - r)!

Here, we have n = 6 and r = 6, so:P(6, 6) = 6!/(6 - 6)!P (6, 6) = 720/0P (6, 6) = 720

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Answer:

yes

Step-by-step explanation:

I believe the yes is yes

The closing price of the bond will be 101 and the dollar amount will be  $1017.50. Hence option D is the required solution.

A bond is a fixed-income investment that simulates a loan from a shareholder to a borrower (typically corporate or governmental). An I.O.U. between the lender and borrower that specifies the terms of the loan and its installments is what is meant by a bond. Businesses, local governments, states, and other types of government use bonds to finance their operations and capital expenditures. The holders of bonds are the issuer's creditors or debtors.

Bond specifics typically include the conditions for the borrower's variable or fixed interest payments as well as the end date by which the loan's principal is needed to be paid to the bond owner.

A security that denotes ownership of a portion of the issuing company is referred to as a stock, also known as equity. Shares, which are units of stock, entitle its owners to a percentage of the company's assets and income based on how many shares they possess.

The closing price of the bond will be 101

and the dollar amount will be $1017.50.

Hence we get the option D as the correct answer regarding the closing price and the total dollar amount.

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Answer:

B.16

Step-by-step explanation:

4x4=16

The vertices of any planar graph can be colored in no more than 6 colors without any two adjacent vertices sharing the same color.

To prove by induction that the vertices of any planar graph can be colored in no more than 6 colors with no two vertices connected by an edge sharing the same color, we will use the concept of the Four Color Theorem.

The Four Color Theorem states that any planar graph can be colored with no more than four colors in such a way that no two adjacent vertices have the same color.

However, we will extend this theorem to use six colors instead of four.

Base case:

For a planar graph with a single vertex, it can be colored with any color, so the statement holds true.

Inductive hypothesis:

Assume that for any planar graph with k vertices, it is possible to color the vertices with no more than six colors without any adjacent vertices having the same color.

Inductive :

Consider a planar graph with k+1 vertices. We remove one vertex, resulting in a subgraph with k vertices.

By the inductive hypothesis, we can color this subgraph with no more than six colors such that no two adjacent vertices share the same color.

Now, we add the removed vertex back into the graph. This vertex is connected to some number of vertices in the subgraph.

Since there are at most six colors used in the subgraph, we can choose a color that is different from the colors of the adjacent vertices.

Thus, we have colored the graph with k+1 vertices using no more than six colors, satisfying the condition that no two adjacent vertices share the same color.

By the principle of mathematical induction, we can conclude that the vertices of any planar graph can be colored with no more than six colors, ensuring that no two adjacent vertices share the same color.

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Answer:

1200

Step-by-step explanation:

4% of 2000 is 80 then do 80*15 and you get 1200

The correct answer is option A. 495, -305.

To find a positive angle that is coterminal to the given angle, we can add 360 degrees to the given angle. This is because coterminal angles are angles that have the same initial side and terminal side, but differ in the number of rotations. Adding 360 degrees to the given angle gives us the same initial side and terminal side, but with one extra rotation.

95 + 360 = 455

To find a negative angle that is coterminal to the given angle, we can subtract 360 degrees from the given angle. This gives us the same initial side and terminal side, but with one less rotation.

95 - 360 = -265

Therefore, the positive angle that is coterminal to the given angle is 455, and the negative angle that is coterminal to the given angle is -265.

Answer: A. 495, -305.

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Thus, 420 fish were ultimately caught, with 6x standing in for "6 times as much."

x + y = 420; y = 6x

Thus, 420 fish were ultimately caught, with 6x standing in for "6 times as much."

The smallest and largest fish range in size from 1 cm to 18 m. 18 m then equals 18 x 100 or 1800 cm. ∴ The length of large fish exceeds that of little fish by 1800 times.

The number of parrotfish Carlos purchased is represented by the variable y, whereas the number of angelfish Carlos purchased is represented by the variable x.

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Answer:

29120

Step-by-step explanation:

if 5.6 × 0.52 = 2912

then,

0.56 × 520 = 29120

Step-by-step explanation:

Step-by-step explanation:

The general equation for a circle is

\( {(x - h)}^{2} + {(y - k)}^{2} = {r}^{2} \)

where (h, k) is the coordinates of the center of the circle and r is the radius. Since the circle passes through (4, 4) and (-4, -4), its center is located at the origin, which means its equation becomes

\( {x}^{2} + {y}^{2} = {( \sqrt{ {4}^{2} + {4}^{2} } )}^{2} = 32\)

The appropriate inference method to test for a difference between the average IQ scores of identical twins raised by birth parents and in a foster home is paired t-test.

A paired t-test is used when comparing two sets of observations that are paired or matched in some way, such as in the case of identical twins. In this scenario, the twins are matched based on their genetic makeup, and their IQ scores are compared based on their different upbringing environments (birth parents vs. foster home). The paired t-test allows us to analyze the difference between the paired observations (IQ scores) and determine if there is a statistically significant difference between the two groups.

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Answer:

-1

Step-by-step explanation:

What's the x value of a point that's considered as the y-intercept? It's 0.

With that in mind, let's solve this by plugging 0 into the function

\(f(0) = -(0+1)^2\\f(0) = -1\)

Good luck!

Answer:

i cant do it

Step-by-step explanation:

The solution set of the given equation is x = 8.39 or x = -12.39

\( \frac{1}{4} {{(x + 2} )}^{2} = 27\)

cross product

\( {1} {{(x + 2}^{} )}^{2} = 27 \times 4\)

(x + 2²) = 108

find the square root of both sides

\( \sqrt{ ({x + 2)}^{2} } = ± \sqrt{108}\)

x + 2 = ± 10.39

So,

x = 10.39 - 2 or x = -10.39 - 2

x = 8.39 or x = -12.39

Therefore, the equation has a solution set of x = 8.39 or x = -12.39

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the answer is 0 because -5 -(-3) equals 8 which cancels out when u add negative 8 :)

Answer:

5 outside of the square root symbol and 625 on the inside

If we have a large enough number of samples, the sample mean can provide a reliable estimate of the population mean.

As the number of samples increases, the sample mean can be used to approximate a population mean.

The sample mean is the average value calculated from a subset of the population, which represents the overall population mean when the sample is random and representative.

By taking multiple samples and calculating their means, we can estimate the population mean more accurately.

This is because as the number of samples increases, the sample mean values tend to converge towards the population mean.

This concept is known as the Central Limit Theorem.

Therefore, if we have a large enough number of samples, the sample mean can provide a reliable estimate of the population mean.

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Step-by-step explanation:

Hello! x = 24 This is a complementary angle so it will add up to 90 degrees in total so 24 × 3 = 72 and 72 - 6 = 66 and 66 + 24 = 90 so x = 24 HOPE THAT HELPS!

Answer:

X = 24

Step-by-step explanation:

so you will have to add all the angles and get 90

3x - 6 +x=90

4x =96

x=24

check your answer.

3 x 24

72 -6 = 66

66 +24 = 90

Answer:

\(\frac{7}{10}=\frac{14}{20}\)

\(\frac{3}{4}=\frac{15}{20}\)

so, \(\frac{7}{10}<\frac{3}{4}\)

Step-by-step explanation:

The new odds that the box picked is a special one is 4

Since, there are four boxes that look the same. in one box (the special one), half of the marbles are blue. but only 1/8 of the marbles in the other boxes are blue.

We will have this hypothesis:

The box the blue marble was picked from is the special box.

Prior confidence we had:

Ratio of special boxes to non special boxes=1:3

Now P(blue &special)=1/2, given that a box is selected from the special box, there is 1/2 chance that it is blue

And P(blue & not special)=1/8, given that a box is selected from a non-special box, there is 1/8 chance that it is blue

According to  Baye's factor ,we get:

P(B & S)/P(B & NS)=(1/2)/(1/8)

                               =4

Thus, 4 is the new odds that the box picked is the special one.

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