Describe where our solar system is located and the type of galaxy it is located in.

Answer:

B -- a single electron or one of two or more electrons in the outer shell of an atom that is responsible for the chemical properties of the atom.

Explanation:

Hope this helps! Please let me know if you need more help or think my answer is incorrect. Brainliest would be MUCH appreciated. Have a wonderful day!

The electrons in the outermost shell available for bonding are known as valence electrons. Therefore, option (B) is correct.

Valence electrons can be described as the electrons occupying the valence shell or outermost shell of an atom while the electrons filled in the inner shell are known as core electrons. Lewis structures can be helpful to evaluate the valence electrons and know the nature of bonds.

Valence electrons can be filled in several electron shells and these electrons participate in the interaction between atoms and lead to the formation of bonds.

Only electrons filled in the outermost or valence shell can participate in the formation of a chemical bond and set the trend of the reactivity of the element. Valence electrons participate in bonding to achieve the noble gas configuration.

Therefore, valence electrons are the electrons in the outermost shell available for bonding.

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The exact same.  gravity has no effect on mass.

Answer:

Explanation:

The mass and magnitude of the second particle are calculated below.

The initial velocity of an object is its velocity prior to the effect of acceleration, which causes the change. The velocity will be the final velocity after accelerating the object for some time. When a particle moves at a constant speed, it can be accelerated. When a point object moves in a horizontal circular path at a constant speed, the direction of its velocity vector changes over time. It means that in a uniform circular motion, the object's velocity vector changes over time.

Distance between the charges, r = 3.2 × \(10^{-3}\)m

initial acceleration of first particle, \(a_{1}\) = 7m / \(s^{2}\)

Initial acceleration of second particle, \(a_{2}\) = 9.0m / \(s^{2}\)

Mass of first particle, \(m_{1}\) = 6.3 × \(10^{-7}\)kg

Mas of second particle, m₂ = ?

a) Since, \(F_{1}=F_{2}\)

∴ \(m_{1}a_{1} = m_{2}a_{2}\)

mass of second particle-\(m_{2}\) =\(\frac{m_{1}\times a_{1}}{a_{2}}\)

= \(\frac{6.3\times10^{-7}\times7.0}{9.0}\)

=4.9 × \(10^{-7}\)Kg

b)As, \(F_{1} = F_{2}\)

       = \(\frac{q_{1}q_{2}}{4\pi E_{0}r^{2}}\) = \(m_{1}a_{1}\)

       = 6.3 × \(10^{-7} \times\) 7.0

       = 44.1 × \(10^{-7}\)

∴ q = 7.1 × \(10^{-11}\)C.

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Answer:

remains the same

Explanation:

Momentum refers to the quantity of motion of a body. When any body of mass moves, it possess momentum. Numerically,

Momentum =  mass x velocity

i.e. momentum is the product of the mass x velocity

Momentum of a body is always conserved.

In the context, the skateboard has certain momentum before Freddy lands on it. After Freddy lands, the momentum of skateboard remains the same, there is no change in the momentum.

This is because, here the momentum is conserved. After Freddy lands on the skateboard, the total mass on the skateboard increases and so the velocity decreases making the momentum same before the landing.

The United States of America was the first country to land a spacecraft on the moon.

The historical event occurred on July 20, 1969, when the Apollo 11 mission successfully placed the lunar module, "Eagle," on the moon's surface. Astronauts Neil Armstrong and Edwin "Buzz" Aldrin became the first human beings to walk on the moon, while Michael Collins orbited above in the command module. This achievement marked a major milestone in space exploration and demonstrated American technological superiority during the Cold War.

This mission marked the first successful soft landing on the moon and was a major milestone in space exploration. The Luna 9 spacecraft was the first of many lunar landers and rovers sent to the moon, laying the foundation for more ambitious lunar missions such as the Apollo 11 mission in 1969, which was the first mission to put humans on the moon.

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Answer:

Normative

Explanation:

It is normal occurance but not unnatural

The star named Capella has an apparent magnitude of 0 while the star named Polaris has an apparent magnitude of 2, which means that Capella appears 2.512 brighter than Polaris in the nigh sky.

Apparent magnitude is a measure of how bright a star appears from Earth. It is a logarithmic scale, so a difference of 1 magnitude corresponds to a brightness ratio of about 2.512. This means that a star with an apparent magnitude of 0 is about 2.512 times brighter than a star with an apparent magnitude of 1, and about 6.31 times brighter than a star with an apparent magnitude of 2.Apparent magnitude is a measure of the brightness of a celestial object as seen from Earth. The lower the apparent magnitude, the brighter the object appears. In this case, Capella has an apparent magnitude of 0, which is lower than Polaris's apparent magnitude of 2. Therefore, Capella appears brighter or more luminous in the night sky compared to Polaris.

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Answer:

3 per 10 seconds.

Explanation:

If it's 30 seconds and 3 waves hit throughout that time period, dividing should get you your answer..

30/3 = 10.

Hope this helped!

Source(s) used: N/A

A sheep on a skateboard is standing still when she is pushed with a force of 59 n to the right for 1.5 seconds. if the sheep has a mass of 41 kg  a speed of approximately 2.16 m/s after being pushed with a force of 59 N for 1.5 seconds.

To determine the speed at which the sheep will move, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass.

The formula to calculate acceleration is given by:

Acceleration (a) = Net Force (F_net) / Mass (m)

In this case, the net force acting on the sheep is 59 N to the right, and the mass of the sheep is 41 kg.

Using the formula, we can calculate the acceleration:

a = 59 N / 41 kg ≈ 1.44 m/s^2

Now, we can use the formula for calculating the final velocity (v) of an object in uniform acceleration:

v = u + a * t

Given that the sheep was initially at rest (u = 0) and the time (t) is 1.5 seconds, we can substitute the values:

v = 0 + 1.44 m/s^2 * 1.5 s

v ≈ 2.16 m/s

Therefore, the sheep will move at a speed of approximately 2.16 m/s after being pushed with a force of 59 N for 1.5 seconds.

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The electric field strength at point (x,y) = (20 mm, 0cm) is 16.76 N/C and the electric field strength at point (x,y) = (0cm, 20 mm) is 16.80 N/C.

The magnitude of the point charge is ± 5. 0 nC and distance between the point charges is 3. 0 mm. Let's first find the electric dipole moment;

p = qd= 5.0 nC × 3.0 mm = 15.0 × 10^−9 C m

The electric field strength at point (20 mm,0cm) is given by;

E= kp/r²

Electric field strength, E1 at point P1 (20 mm, 0 cm) is given by;

The distance of P1 from the charges is;

r1 = √(x₁ - x₂)² + (y₁ - y₂)²= √(20² + 1.5²) = 20.03 mm = 20.03 × 10⁻³ m

Using Coulomb's law;

F = kq₁q₂/r² ; where k = 9 × 10^9 Nm²/C²;

We can find the electric field strength at P1 using the formula:

E1= kp/r1² = (9 × 10^9 Nm²/C²) (15.0 × 10^−9 C m)/(20.03 × 10⁻³ m)²= (9 × 10^9 × 15 × 10^−9)/(20.03 × 10⁻³)²= 16.76 N/C

Now, let's find the electric field strength at point (0cm,20 mm). The electric field strength, E2 at point P2 (0cm, 20 mm) is given by;

The distance of P2 from the charges is;

r2 = √(x₁ - x₂)² + (y₁ - y₂)²= √(20² + 3) = 20.01 mm= 20.01 × 10⁻³ m

Using Coulomb's law;

F = kq₁q₂/r² ; where k = 9 × 10^9 Nm²/C²;

We can find the electric field strength at P2 using the formula;

E2= kp/r2² = (9 × 10^9 Nm²/C²) (15.0 × 10^−9 C m)/(20.01 × 10⁻³ m)²= (9 × 10^9 × 15 × 10^−9)/(20.01 × 10⁻³)²= 16.80 N/C

Therefore, the electric field strength at point (x,y) = (20 mm, 0cm) is E1 = 16.76 N/C. The electric field strength at point (x,y) = (0cm, 20 mm) is E2 = 16.80 N/C.

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Answer:

1. 24500 N.

2. 191406.25 watt

Explanation:

From the question given above, the following data were obtained:

Mass (m) of car = 1000 Kg

Initial velocity (u) = 35 m/s

Distance (s) = 25 m

Final velocity (v) = 0 m/s

Time (t) = 3.2 s

Force (F) =?

Power (P) =?

Next, we shall determine the acceleration of the car. This can be obtained as follow:

Initial velocity (u) = 35 m/s

Distance (s) = 25 m

Final velocity (v) = 0 m/s

Acceleration (a) =?

v² = u² + 2as

0 = 35² + (2 × a × 25)

0 = 1225 + 50a

Collect like terms

0 – 1225 = 50a

– 1225 = 50a

Divide both side by 50

a = – 1225 / 50

a = –24.5 m/s²

1. Determination of the force.

Mass (m) of car = 1000 Kg

Acceleration (a) = –24.5 m/s²

Force (F) =?

F = m × a

F = 1000 × –24.5

F = –24500 N

The negative sign indicate that the force is in opposite direction to the motion of the car.

2. Determination of the power

Force (F) = 24500 N

Distance (s) = 25 m

Time (t) = 3.2 s

Power (P) =?

Next, we shall determine the energy.

Energy = force × distance

Energy = 24500 × 25

Energy = 612500 J

Finally, we shall determine the power. This is illustrated below:

Power = Energy /time

Power = 612500 /3.2

Power = 191406.25 watt

Answer:

Work is calculated as the force multiplied by the displacement in the force's direction. Work is defined as force times a displacement in the force's direction.

Answer:

H = 0.06 kWh

Explanation:

Given that,

Power of an electric lamp, P = 60 W

Voltage, V = 240 V

It is operated for 1 hour

We need to find the heat generated by the lamp. Heat generated is given by :

\(H=P\times t\\\\H=60\ W\times 1\ h\\\\H=60\ Wh\\\\H=0.06\ kWh\)

So, 0.06 kWh of the heat is generated by the lamp.

Leaves.

Grass clippings.

Brush trimmings.

Manure (preferably organic)

Any non-animal food scraps: fruits, vegetables, peelings, bread, cereal, coffee grounds and filters, tea leaves and tea bags (preferably minus the staples)

Old wine.

In amplifiers, the coupling and bypass capacitors appear to be shorts to ac at the mid band frequencies.

At low frequencies the capacitive reactance, XC, of these capacitors affect the gain and phase shift of signals, so they must be taken into account.

\(\alpha =\frac{1}{2\pi f}\)

At lower f, the internal capacitances have a very high Xc like opens and have no effect on the transistor’s performance. However, as the frequency goes up (at high f), the internal  capacitive reactances go down and they have a significant effect on the transistor’s gain and also it introduces a phase shift; it has the inverse effect to the coupling capacitor.

Miller’s theorem states that C effectively appears as a capacitance from input to ground is as given below-

\(Cin= C(A+1)\)

\(Cout=\frac{CA +C}{\alpha }\)

This shows the effective input and output capacitance.

Critical frequency is given as -

\(\alpha = \lim_{n \to \infty} a_n\)

= 10 log(0.5)

=-3dB

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AS-PATH is an attribute in the Border Gateway Protocol (BGP) that provides information about the autonomous systems (AS) through which a specific route has passed. It helps in determining the path taken by BGP updates in order to reach a particular destination network. In the given scenario, the AS-PATH for reaching the subnet with prefix X involves passing through AS2 and AS3 after originating from AS1 gateway router 1c.

AS-PATH represents a sequence of AS numbers in the order in which they are traversed. In this case, the AS-PATH would be AS2 AS3. This indicates that the BGP update, carrying the reachability information for the subnet with prefix X, has passed through AS2 and AS3 before reaching AS1 gateway router 1c. AS2 is the immediate neighbor of AS1, and AS3 is the subsequent AS in the path.

The AS-PATH attribute is significant in BGP for various purposes, such as loop prevention, route selection, and policy enforcement. It enables routers to make informed decisions about the best path to a destination based on the AS-PATH length or specific AS numbers within the path. Network administrators and ISPs utilize AS-PATH information to implement routing policies, influence traffic flows, and ensure efficient and reliable inter-domain routing.

In summary, the AS-PATH for reaching the subnet with prefix X, starting from AS1 gateway router 1c, includes AS2 and AS3 in the sequence AS2 AS3.

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According to the question the frog travels approximately 0.214 meters (or 21.4 centimeters) in the horizontal direction.

To determine the horizontal distance traveled by the frog, we need to analyze the horizontal and vertical components of its initial velocity.

Given:

Initial velocity magnitude (v0) = 2.5 m/s

Launch angle (θ) = 35°

Vertical displacement (Δy) = 9.0 cm = 0.09 m

First, we can find the vertical component of the initial velocity:

v0y = v0 * sin(θ)

v0y = 2.5 m/s * sin(35°)

v0y ≈ 1.43 m/s

Next, we can find the time it takes for the frog to reach the maximum height:

The vertical motion can be modeled as free fall with an initial vertical velocity (v0y) and a vertical displacement (Δy).

Using the kinematic equation:

Δy = v0y * t + (1/2) * g * t^2

Substituting the known values:

0.09 m = 1.43 m/s * t + (1/2) * (-9.8 m/s^2) * t^2

This equation is a quadratic equation in t. Solving for t using the quadratic formula or factoring, we find two possible solutions: t ≈ 0.105 s and t ≈ 0.964 s.

Since the frog cannot spend more time descending than ascending, we take the shorter time interval:

t ≈ 0.105 s

Now, we can calculate the horizontal distance traveled by the frog:

The horizontal distance (d) is given by the formula:

d = v0x * t

To find the horizontal component of the initial velocity (v0x), we use:

v0x = v0 * cos(θ)

v0x = 2.5 m/s * cos(35°)

v0x ≈ 2.04 m/s

Substituting the values into the equation for d:

d = 2.04 m/s * 0.105 s

d ≈ 0.214 m

Therefore, the frog travels approximately 0.214 meters (or 21.4 centimeters) in the horizontal direction.

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Answer:

The acceleration during the take-off from the moon is 4.3 m/s²

Explanation:

Given;

the mass of the fully-loaded module, m = 2000 kg

The thrust of its engines,  F =  8600 N

Apply Newton's second law of motion to determine the acceleration during the take-off from the moon;

F = ma

where;

a is the acceleration

a = F / m

a = 8600/2000

a = 4.3 m/s²

Therefore, the acceleration during the take-off from the moon is 4.3 m/s²

(1) The ball is in the air for 1.4 seconds.

(2) The horizontal velocity of the ball as it rolls off the table is 6.32 m/s.

(3) The vertical velocity of the ball right before it hits the ground is 13.72 m/s.

(4) The horizontal velocity of the ball right before it hits the ground is 6.32 m/s.

(5) The initial vertical velocity as soon as the ball comes of the cliff is 13.72 m/s​.

The time of motion of the ball is calculated by applying the following equation.

t = √(2h/g)

where;

t =  √(2h/g)

t = √(2 x 9.63 / 9.8)

t = 1.4 seconds

The horizontal velocity of the ball is calculated as follows;

v = d/t

where;

v = 8.85 m / 1.4 s

v = 6.32 m/s

The vertical velocity of the ball before it hits the ground is calculated as;

vf = vi + gt

vf = 0 + 9.8 x 1.4

vf = 13.72 m/s

The horizontal velocity of the ball right before it hits the ground is calculated as;

the initial velocity of a projectile = final horizontal velocity

vxf = vxi = 6.32 m/s

The initial vertical velocity as soon as the ball comes off the cliff = final vertical velocity = 13.72 m/s

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Answer:

the mathematical models, Newton's second law, improve the response of our designs and allow us to modify them to be more resistant.

Explanation:

When an object is designed it is done based on some models or guides, specifically Newton's second law is given in the form

            ∑ F = m a

We can make a design and test with forces applied in several different places and with different intensity, to find weak points in the design, this is done a lot today in the construction of tall buildings, in the design of airplanes; The great advantage of this is that it allows you to see problems without significant cost of money and human lives.

There are also designs that can be modified to improve the response of our system to different external stimuli, this is widely used in the design of bridges, to see the response of the structure before load changes and different climatic conditions.

In summary, the mathematical models, Newton's second law, improve the response of our designs and allow us to modify them to be more resistant.

Answer:

C. a disturbance that travels through a medium with a transfer of energy and without a transfer of matter

Explanation:

A wave is any disturbance that transfers energy from one location to the other via a substance called medium. It is important to note that a wave only conveys energy and not matter. For example, sound wave is a type of wave that carries sound energy from one place to another via mediums such as water, air etc.

Hence, according to this question, a wave can be described as a disturbance that travels through a medium with a transfer of energy and WITHOUT A TRANSFER OF MATTER.

Answer:

ground Waves

Explanation:

Answer:

Density is the degree of compactness in an object.

Explanation:

S.I unit is kg/m3

Answer:

The mass of the paraffin is 70g

Explanation:

You have to subtract the mass of the empty beaker from that of the empty beaker and paraffin oil to get the mass of the paraffin oil

Answer:

\(\huge\boxed{\sf Option \ A}\)

Explanation:

When we stir the solution such that it forms a mixture and the sugar is completely dissolved, we still find some ice cubes floating in the tea which shows that it is a heterogeneous mixture.

A Heterogeneous Mixture:

It is a mixture which has two or more phases that can be separated by physical means.

\(\rule[225]{225}{2}\)

Hope this helped!

Answer: Some ice cubes are floating in the tea.

Explanation:

A. Some ice cubes are floating in the tea.

B. Some water droplets form on the outside of the glass.

C. The mixture looks the same throughout.

D. The sugar crystals are no longer visible in the tea.

Answer:

coins

Explanation:

A Coin sliding On an table experiences a friction force, if you give it some speed and let go it will stop.

The magnitude of the magnetic force is approximately \(1.92 * 10^{-15} N\) .

To calculate the magnitude of the magnetic force acting on an electron moving perpendicular to a uniform magnetic field, you can use the formula:

F = q * v * B

where F is the magnetic force, q is the charge of the electron, v is its speed, and B is the magnetic field strength.

For an electron, q = -\(1.6 * 10^{-19}\) C. Given the speed v = \(3.0 * 10^{4}\) m/s and magnetic field B = 0.40 T, the magnetic force can be calculated as:

F = (-\(1.6 * 10^{-19}\) C) * (\(3.0 * 10^{4}\) m/s) * (0.40 T)

F ≈ -\(1.92 * 10^{-15} N\)

Since we're interested in the magnitude of the force, we can ignore the negative sign and say:

The magnitude of the magnetic force is approximately\(1.92 * 10^{-15} N\)

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Answer:

Positive I believe... because if you drop it it is negative so picking up a book means positive. thanks for the points though!

Explanation:

Can I have brainliest please? <3