Describe the relationship of the Earth’s lithosphere to the asthenosphere.

The asthenosphere is composed of rigid plates that “float” on top of the lithosphere.
The lithosphere is composed of rigid plates that “float” on top of the asthenosphere.
The lithosphere is a solid wall around the asthenosphere, and they move as one unit.
The asthenosphere is found in the Earth’s core and is protected by the lithosphere.

Answer:

Increases

Explanation:

Atomic size is the amount of space between the nucleus of an atom and the outermost electron. So, as each additional energy level is added, the overall amount of space between the nucleus and the outermost electron increases because there is now an extra shell of electrons that is farther out.

Answer:Glucose, Oxygen and Water

Explanation:

Answer:

Hello i have don this... : )

Explanation:

It is oxygen and glucose

Have a good day im 100% sure this is... i forgot but it is before or after the asexual and sexual lessons

I added a meme for no reason you will only get it if you have read heroes of Olympus

The speed of light changes when light moves from one medium to another

option c is the correct answer as to why light is refracted

Answer:

C. chromium is a metal that is less reactive than sodium.

Explanation:

Hello.

Given the options:

A. chromium is a nonmetal and therefore a good conductor of heat and electricity .

B. chromium is a metal that is more reactive than potassium .

C. chromium is a metal that is less reactive than sodium .

D. chromium is a noble gas that is not reactive.

In this case, since chromium is in period 4 group VIB we infer it is a transition metal which slightly reacts with acids and poorly reacts with oxygen and other oxidizing substances. Thus, in comparison with both sodium and potassium which are highly reactive even with water as they get on fire, we can say that it is less reactive than both potassium and sodium, therefore, answer is: C. chromium is a metal that is less reactive than sodium.

Best regards.

Answer: 57.8g

Explanation:

We can find molar mass by adding up the masses of each component, nitrogen is 14 and hydrogen is 1, this gives us 17g/mol.

Multiplying molar mass by number of moles will give us the grams in that many moles, 3.4x17=57.8g.

Answer:

In a chemical reaction, reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products.

Explanation:

Answer: A model would be useful because the model makes the concepts easier to understand.

Explanation:

Models are helpful tools in science education that can be used to enhance explanations, spark discussion, make predictions, provide visual representations of abstract concepts, and create mental models.

An atom is chemically stable when it's outer orbit  is completely filled with eight electron. An atom is indeed a particle made up of a nucleus.

An atom is indeed a particle made up of a nucleus of neutrons and protons surrounding by such an electron cloud. The atom is the fundamental component of the chemical components, as well as the starting materials are characterized by the amount of protons in their atoms.

For example, every atom with 11 protons becomes sodium, while any atom with 29 protons becomes copper. An atom is chemically stable when it's outer orbit  is completely filled with eight electron.

Therefore, an atom is chemically stable when it's outer orbit  is completely filled with eight electron.

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Based on the information provided, we have a reaction between hydrogen iodide (HI) gas and hydrogen gas (H₂) to form iodine gas (I₂). The equilibrium is represented by the equation:

2HI(g) = H₂(g) + I₂(g)

The concentration values given in the table correspond to the concentrations of H₂ and HI at different times.

a) From t=0 s to t=5 s: Without the specific graph mentioned in Figure 7.10, it is difficult to provide a precise explanation of the physical situation in the container during this time period. However, based on the equilibrium reaction given, we can make some general observations. At the start (t=0 s), the concentrations of H₂ and HI may be high. As time progresses, the reaction proceeds, and the concentrations of H₂ and HI may decrease while the concentration of I₂ increases. The specific behavior will depend on the rate of the forward and reverse reactions.

b) External factor altered at t=5 s: To bring about a change in the shape of the graph at t=5 s, some external factor must have been altered. The most likely factor is the total pressure within the container. Since the reaction involves gases, changes in pressure can affect the equilibrium position. However, according to the information given, a change in pressure will not affect equilibrium in this case since the number of moles of gas is the same on both sides of the equation. Therefore, if the shape of the graph changes at t=5 s, some other external factor, such as temperature or the addition of a catalyst, must have been altered.

c) Calculation of K at t=3 s: The equilibrium constant (K) can be calculated at any given time using the concentrations of the reactants and products. However, the concentrations of H₂ and HI at t=3 s are not provided in the information given. Without the necessary data, it is not possible to calculate K at t=3 s.

Lastly, the statement "1 dm³ COCI, decomposes" seems incomplete. If you provide additional information or clarify the question, I'll be happy to assist you further.

Answer: 4.5 moles

Explanation:

To understand how to solve this problem, you must understand the ratios written in this chemical equation.

The equation shows that 4 moles of Al forms 2 moles Al₂O₃. This creates the ratio 2:4 or \(\frac{2}{4}\)

To solve, you can set the two ratios to each other and cross multiply.

\(\frac{2}{4} = \frac{x}{9}\)

18 = 4x

x = 4.5 mol Al₂O₃

*both \(\frac{2}{4}\) and \(\frac{4.5}{9}\) can be simplified as \(\frac{1}{2}\), which verifies your answer*

Answer:

see below

Explanation:

K.E. = 1/2 * m * v^2

      = 1/2 * 2 * 5^2     j

Answer:

50g

Explanation:

At the end of the burning process, the mass of the jar and smoke should be 50g after the candle burning is done.

In most systems, the law of conservation of matter finds expression. According to this law "matter is neither created nor destroyed but atoms are rearranged".

In this kind of system, no matter is allowed to escaped and the starting mass of the reactants compared to that of the product will be the same.

The moles of NaOH used is 0.0008 moles

The molarity of the acid  is 0.008 M

The molarity of the acid is found as follows:

Moles of NaOH used = concentration of NaOH × volume of NaOH used

the average volume of NaOH used = 8.0 mL

moles of NaOH = 0.1 M × 8.0 mL

moles of NaOH = 0.0008 moles

Molarity of acid:

Assuming the acid is monobasic, the mole ratio of acid to base is 1 : 1

The volume of acid used is 100 mL

The molarity of acid = moles of acid / volume of acid in liters

The molarity of acid = 0.0008 moles / 0.1 L

The molarity of acid  = 0.008 M

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CuI2 is not a known compound. Copper compounds typically have different oxidation states for copper, resulting in various compound names.

Copper(II) oxide (CuO): It is a black solid compound where copper is in the +2 oxidation state. It is commonly used as a pigment and in catalytic reactions.

Copper(II) sulfate (CuSO4): It is a blue crystalline compound in which copper is in the +2 oxidation state. It is used in various applications such as agriculture, electroplating, and as a laboratory reagent.

Copper(I) oxide (Cu2O): It is a red crystalline compound in which copper is in the +1 oxidation state. It is used as a pigment, in solar cells, and as a catalyst.

Copper(II) chloride (CuCl2): It is a greenish-brown solid compound in which copper is in the +2 oxidation state. It is utilized in various chemical processes, including etching and catalyst synthesis.

Copper(II) nitrate (Cu(NO3)2): It is a blue crystalline compound where copper is in the +2 oxidation state. It is commonly used in the production of catalysts, as a coloring agent, and in electroplating.

These are just a few examples of copper compounds with different oxidation states and properties. It's important to note that the compound CuI2 mentioned in the question, if it exists, would be an exception to the typical nomenclature for copper compounds.

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Approximately 766.08 grams of oxygen are required to completely react with 240g of C₂H₆.

To determine the amount of oxygen required to completely react with 240g of C₂H₆ (ethane), we need to set up a balanced chemical equation for the combustion of ethane.

The balanced equation for the combustion of ethane is as follows:

C₂H₆ + O₂ → CO₂ + H₂O

From the balanced equation, we can see that the stoichiometric ratio between C₂H₆ and O₂ is 1:3. This means that for every one mole of C₂H₆, three moles of O₂ are required for complete combustion.

To calculate the amount of oxygen required, we need to convert the given mass of C₂H₆ to moles using its molar mass, and then use the stoichiometric ratio to determine the moles of O₂ required. Finally, we can convert the moles of O₂ back to grams using the molar mass of oxygen.

The molar mass of C₂H₆ is calculated as follows:

(2 x atomic mass of carbon) + (6 x atomic mass of hydrogen)

(2 x 12.01 g/mol) + (6 x 1.01 g/mol) = 30.07 g/mol

Now, we can proceed with the calculation:

Calculate the moles of C₂H₆:

moles of C₂H₆ = mass of C₂H₆ / molar mass of C₂H₆

moles of C₂H₆ = 240 g / 30.07 g/mol ≈ 7.98 mol

Determine the moles of O₂ using the stoichiometric ratio:

moles of O₂ = moles of C₂H₆ x (3 moles of O₂ / 1 mole of C₂H₆)

moles of O₂ = 7.98 mol x 3 ≈ 23.94 mol

Convert moles of O₂ to grams:

mass of O₂ = moles of O₂ x molar mass of O₂

mass of O₂ = 23.94 mol x 32.00 g/mol = 766.08 g

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Answer:C

Explanation:I took the test

Answer:

It is a south pole because the field lines enter the magnet at this end.

Explanation:

Answer:

The best and most correct answer among the choices provided by your question is the fourth choice.

The data explains that sodium atoms hardly ever form 2+ ions.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

Explanation:

Answer:

Six

Explanation:

I just took it and that is the correct answer.

Carbonic acid is formed by the reaction of carbon dioxide and water. There are total six bonds in carbonic acid. Four bonds between carbon and oxygen and two bonds between oxygen and hydrogen.

Carbonic acid is an inorganic acid formed by reaction water with carbon dioxide. The structure of carbonic acid H₂CO₃ is drawn in the uploaded image. Where, carbon bonds a double bond with one oxygen.

Carbon has a valency of 4 thus it forms 4 bonds with other atoms. Carbonic acid contains two OH groups where oxygen and hydrogen forms covalent bonds by sharing electron with each other.

The two oxygens in the OH group forms a single bond with carbon. Remaining one oxygen forms double bond with carbon.Thus, there are total 6 bonds formed between atoms. Hence, option b is correct.

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Answer:

50.4 mL

Explanation:

Step 1: Given data

Step 2: Convert the temperatures to Kelvin

We will use the following expression.

K = °C + 273.15

K = 15.0°C + 273.15 = 288.2 K

K = 30.0°C + 273.15 = 303.2 K

Step 3: Calculate the final volume occupied by the gas

We will use the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

V₂ = P₁ × V₁ × T₂/ T₁ × P₂

V₂ = 785.0 torr × 45.5 mL × 303.2 K/ 288.2 K × 745.0 torr = 50.4 mL

The frequency of the cesium-133 atom's ground state is 9,192,631,770 hertz, which is equivalent to a period of 1/9,192,631,770 seconds, or approximately 0.0000000011 seconds. Therefore, the length of 9,192,631,770 radiation periods of the cesium-133 atom's ground state is approximately 0.00000099 seconds.

What is the  length?

The length of a 100-word essay that is plagiarism-free depends on the complexity of the topic and the essay structure. Generally, a 100-word essay should be about 3 to 5 paragraphs and take up about half a page. This length may vary depending on the font, font size, and other formatting factors.The definition of a second is based on the ground state hyperfine transition frequency of the caesium-133 atom, which is the unperturbed ground-state hyperfine transition frequency of the caesium-133 atom in a vacuum. This frequency is 9,192,631,770 Hz, and is known as the caesium frequency. One second is defined as the time it takes for the caesium atom to undergo 9,192,631,770 radiation periods, which is equivalent to 9,192,631,770 cycles of the photon's frequency.

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The International Union of Pure and Applied Chemistry (IUPAC) provides a standard system for naming organic compounds.

It is essential to learn this nomenclature system to communicate correctly about the chemical structures of compounds and how they relate to each other. Here is the IUPAC name of the following substance.Below is the structure of the given compound: In the given compound, there are four carbon atoms that are connected with single bonds. Carbon atoms are also attached to hydrogen atoms. Since it has four carbons in the main chain, the root name will be "but-". The functional group present in the molecule is the carboxylic acid group (-COOH), which gives the suffix "-oic acid." Therefore, the IUPAC name of the given substance is Butanoic acid.Thus, the IUPAC name of the given compound is Butanoic acid. It is essential to know the IUPAC naming of organic compounds to communicate correctly about the chemical structures of the compounds.

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1 moles of a monoatomic gas increases its volume from 1 to 3 while the pressure also increases from 250 to 1000. So, the temperature of the gas increased from 30.1 K to 120.3 K.

If the temperature and the number of moles of the gas remain constant, the pressure and volume of the gas are inversely proportional to each other. This relationship is described by the ideal gas law:

PV = nRT

where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of the gas, R is the universal gas constant, and T is the temperature of the gas. In this case, you have given that the number of moles of the gas (n) is 1 mole, the temperature (T) is constant, and the pressure (P) and volume (V) both change. We can use the ideal gas law to solve for the final temperature of the gas.

First, we can rearrange the ideal gas law to solve for T:

T = (PV)/(nR)

We can then use the initial and final values of P and V to calculate the initial and final temperatures of the gas.

Initial temperature: T1 = (250 * 1)/(1 * 8.31) = 30.1 K

Final temperature: T2 = (1000 * 3)/(1 * 8.31) = 120.3 K

Therefore, the temperature of the monoatomic gas increased from 30.1 K to 120.3 K as the volume increased from 1 to 3 while the pressure increased from 250 to 1000.

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Question- 1 moles of a monoatomic gas increases its volume from 1 to 3 while the pressure also increases from 250 to 1000. What is the change in temperature of gas is?

The correct match is as follows:

Pressure and heat - Metamorphic rock

Cooling magma - The Intrusive igneous rock

Cooling lava - The Extrusive igneous rock

Erosion and Deposition - Sedimentary rock

This is because Metamorphic rocks are formed as a result of past existing rocks changing form. If the igneous and sedimentary rocks are exposed to high temperature and pressure, they then become metamorphic rocks.

Intrusive igneous rocks form when magma cools slowly. This process soon results in the formation of large-crystal like structures. Whereas, when exposed to the atmosphere lava cools rather quickly. This faster cooling process forms extrusive igneous rocks. The fast cooling lava creates smaller crystals and a smoother surface.

The sediments that are formed as a result of weathered rocks are usually deposited on the surface of Earth, or at the bottom of rivers and oceans. Over time, sediments collect and form layers over the most recent layer. This leads to the formation of sedimentary rocks.

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Answer:

I believe this is your answer, or wait I know this is your answer

Explanation:

Answer:

it's answer is lithium and boron.

Answer:

See explaination

Explanation:

please kindly see attachment for the step by step solution of the given problem

Explanation:

Elements present in group 18 are known as noble gases. The outermost shell of these elements are completely filled.

Hence, they have low reactivity towards any kind of chemical reaction.

Elements of noble gas family are helium, neon, argon, krypton, xenon, and radon.

Thus, we can conclude that family of noble gases in the periodic table is least likely to enter into chemical reactions.

Answer:

Noble gases are considerded non reactable gases, because they're reluctant to share electrons from their filled outer electron shells. Hence, the are the least likely to enter into chemical reactions.

At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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