Answer:Im doing that same quiz rn and i just put A
Explanation:
this is because EM energy is produced when electrically charged participles vibrate generating an electric filed and a magnetic field which sends out an EM wave.
i hope this helped
If light moves and 300, 000m / s in a vacuum what would be the wavelength of a light wave that has a frequency of 40,000Hz in outer space ?
\(\begin{gathered} given: \\ frequency\text{ }\vartheta=40,000\text{ Hz} \\ speed\text{ of light c=3*10}^8\text{ m/s} \end{gathered}\)\(\begin{gathered} to\text{ find:} \\ wavelength\text{ }\lambda=? \end{gathered}\)\(\begin{gathered} wavelength\text{ }\lambda=\frac{v}{\vartheta} \\ v=speed\text{ of the wave} \end{gathered}\)\(\begin{gathered} put\text{ the values in the above formula} \\ \lambda=\frac{3*10^8m/s^2}{40000Hz} \\ \lambda=0.75*10^4m \end{gathered}\)
so the value of wavelength λ=0.75*10^4 m
To work on muscular endurance, you should use?
Answer:
Arm Workouts- with Weights.
Pushups for Upper-Body Strength.
Lunges and Squats.
Explanation: Lifting weights is one way to build muscular strength and endurance in your arms.
Pushups primarily work the pectoral muscles of the chest, starting directly below the neckline.
Brainlist please? and your welcome!
A particle has a rest energy of 5.33 × 10 − 13 J and a total energy of 9.61 × 10 − 13 J . Calculate the momentum of the particle
A particle has a rest energy of 5.33 × 10⁻¹³ J and a total energy of 9.61 × 10⁻¹³ J. The momentum of the particle is 3.09 × 10⁻²⁶kg·m/s.
What is momentum?
Momentum is a fundamental concept in physics that describes the motion of an object. It is a vector quantity that represents the quantity of motion possessed by an object. Momentum depends on both the mass and velocity of an object.
Mathematically, momentum (p) is calculated by multiplying the mass (m) of an object by its velocity (v):
Momentum (p) = mass (m) × velocity (v)
The rest energy of a particle (E₀) is the energy it possesses when it is at rest, and the total energy of a particle (E) includes both its rest energy and its kinetic energy when it is in motion. The relationship between the total energy and the rest energy is given by the equation:
E = γE₀
where γ is the Lorentz factor, which accounts for the relativistic effects at high speeds. The Lorentz factor can be expressed as:
γ = (1 - v²/c²)\(^{(-1/2)}\)
where v is the velocity of the particle and c is the speed of light.
To find the momentum (p) of the particle, we can use the relationship between energy, momentum, and rest energy:
E² = (pc)² + (E₀c²)²
Substituting the given values of rest energy (E₀ = 5.33 × 10⁻¹³ J) and total energy (E = 9.61 × 10^(-13) J), we can solve for the momentum:
(9.61 × 10⁻¹³ J)² = (pc)² + (5.33 × 10⁻¹³J * c²)²
Simplifying the equation and solving for pc, we get:
(pc)² = (9.61 × 10⁻¹³J)² - (5.33 × 10^(-13) J * c²)²
pc ≈ 2.986 × 10⁻¹³ J
Since momentum (p) is equal to pc, the momentum of the particle is approximately 3.09 × 10⁻²⁶ kg·m/s.
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A test rocket is launched by accelerating it along a 200.0 m, 35 degree incline at 1.25 m/s/s starting
from rest. The instant the rocket leaves the incline, its engines turn off, it is subject only to gravity,
and air resistance can be ignored. Find
a) the maximum height above the ground the rocket reaches
Answer:
The maximum height above the ground the rocket reaches is 123.1 m.
Explanation:
Let's find the final velocity at a distance of 200 m:
\( v_{f}^{2} = v_{0}^{2} + 2ad \)
Where:
\(v_{f}\) is the final speed =?
v₀ is the initial speed =0
a is the acceleration = 1.25 m/s²
d is the distance = 200 m
\(v_{f} = \sqrt{2ad} = \sqrt{2*1.25 m/s{2}*200 m/s} = 22.4 m/s\)
Now, when the engines of the rocket turn off and it is subject only to gravity, the height reached is:
\( v_{fy}^{2} = v_{0y}^{2} - 2gh \)
Where:
\(v_{f}\) = 0
\(h = -\frac{v_{fy}^{2} - v_{0y}^{2}*sin(\theta)}{2g} = \frac{(22.4*sin(35))^{2}}{2*9.81 m/s^{2}} = 8.4 m\)
Finally, the maximum height above the ground is:
\( h_{max} = h + H \)
Where H is the vertical component of the 200.0 meters.
\(h_{max} = h + H = 8.4 m + 200.0 m*sin(35) = 123.1 m\)
Therefore, the maximum height above the ground the rocket reaches is 123.1 m.
I hope it helps you!
If a ball is thrown straight up into the air with an initial velocity of $60{ft} /{s}$, its height in feet after $t$ second is given by $y=60 t-16 t^2$. Find the average velocity (include units, help (units)) for the time period begining when $t=2$ seconds and lasting
(i) 0.5 seconds
Avenge velocity:
(ii) 0.1 seconds
Average velocity:
(iii) 0.01 seconds
Average velocity:
Finally based on the above results, guess what the instantaneous velocity of the ball is when $t=2$. Average velociry:
The instantaneous velocity of the ball is when $t=2$ is 32 ft/s so the average velocity: 32 ft/s.
The given function is $y=60t-16t^2$. We need to find the average velocity of the ball for the time period beginning when $t=2$ seconds and lasting. The average velocity is calculated by dividing the distance travelled by the time taken. The average velocity for the time period beginning when $t=2$ seconds and lasting 0.5 seconds is calculated as follows:
Average velocity = $[\frac{y_2-y_1}{t_2-t_1}]$Here, $y_2$ is the value of the function when $t=2.5$ and $y_1$ is the value of the function when $t=2$. Therefore, $y_2=60(2.5)-16(2.5)^2=45$ and $y_1=60(2)-16(2)^2=32$.The time taken is $0.5$ seconds. Average velocity = $[\frac{y_2-y_1}{t_2-t_1}]$Average velocity = $[\frac{45-32}{0.5}]$Average velocity = $[\frac{13}{0.5}]$Average velocity = $26$ ft/sNow, for the time period beginning when $t=2$ seconds and lasting(ii) 0.1 seconds. Here, $y_2$ is the value of the function when $t=2.1$ and $y_1$ is the value of the function when $t=2$. Therefore, $y_2=60(2.1)-16(2.1)^2=31.84$ and $y_1=60(2)-16(2)^2=32$.The time taken is $0.1$ seconds. Average velocity = $[\frac{y_2-y_1}{t_2-t_1}]$Average velocity = $[\frac{31.84-32}{0.1}]$Average velocity = $[-1.6]$ ft/s(iii) 0.01 seconds. Here, $y_2$ is the value of the function when $t=2.01$ and $y_1$ is the value of the function when $t=2$. Therefore, $y_2=60(2.01)-16(2.01)^2=31.9364$ and $y_1=60(2)-16(2)^2=32$.The time taken is $0.01$ seconds. Average velocity = $[\frac{y_2-y_1}{t_2-t_1}]$Average velocity = $[\frac{31.9364-32}{0.01}]$Average velocity = $[-6.36]$ ft/s
Finally based on the above results, we can guess that the instantaneous velocity of the ball is when $t=2$ is 32 ft/s. hence, Average velocity: 32 ft/s.
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Read the ruler in millimeters to the correct degree of precision
3.50
3.55
35
35.1
Answer:
The answer is = 35.1 you can see by zooming.
Answer:
The answer would be 35.1
One component of a magnetic field has a magnitude of 0. 0404 T and points along the x axis while the other component has a magnitude of 0. 0739 T and points along the y axis A particle carrying a charge of 2. 80 10 5 C is moving along the z axis at a speed of 4. 46 103 m s a Find the magnitude of the net magnetic force that acts on the particle b Determine the angle that the net force makes with respect to the x axis
a) The magnitude of the net magnetic force that acts on the particle is 2.18 x 10-6 N.
b) The angle that the net force makes with respect to the x axis is 63.8°.
A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials. A moving charge in a magnetic field experiences a force perpendicular to its own velocity and to the magnetic field.Magnetic Field is the region around a magnetic material or a moving electric charge within which the force of magnetism acts. A pictorial representation of the magnetic field which describes how a magnetic force is distributed within and around a magnetic material.
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Below is a nuclear equation. What number should go in the place marked (i)?
The nuclear reaction becomes:
U₉₂²³⁸ → Th₉₀²³⁴+ α⁴₂
Thus, here (i) 234 and (ii) 90
What is alpha-decay?Uranium-238 decays to thorium-234 via alpha decay. (The numbers after the chemical names indicate the number of protons and neutrons.) Uranium-238 loses two protons and two neutrons in this process, forming the isotope thorium-234.
Reactors based on thorium are safer since the reaction is simple to stop and does not need to be carried out under intense pressure. When compared to uranium reactors, thorium reactors produce significantly less waste, and the waste produced is far less radioactive and far shorter in duration.
Now, here (i) 234 and (ii) 90
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Answer:
(i) 234 and (ii) 90
Tierra pushes on a 1000 N crate with a force of 200 N to the right. The crate does not move. What are both the normal force and the force of friction
In this scenario, the crate does not move despite the applied force by Tierra. This implies that the crate is in a state of equilibrium, where the forces acting on it are balanced. To determine the normal force and the force of friction, we need to consider the forces acting on the crate.
The normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, since the crate is not moving vertically, the normal force exerted by the ground must be equal in magnitude and opposite in direction to the weight of the crate. Given that the weight of the crate is 1000 N, the normal force exerted by the ground on the crate is also 1000 N, directed vertically upwards.
The force of friction, denoted as Ff, opposes the motion or potential motion between two surfaces in contact. In this case, since the crate is at rest, the force of friction must be equal in magnitude and opposite in direction to the applied force by Tierra, which is 200 N to the right. Therefore, the force of friction is 200 N, directed to the left.
In summary, when Tierra pushes the 1000 N crate with a force of 200 N to the right and the crate does not move, the normal force exerted by the ground is 1000 N directed vertically upwards, and the force of friction is 200 N directed to the left. These forces are equal in magnitude and opposite in direction, resulting in a state of equilibrium for the crate.
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at the instant shown, rank these six scenarios on the basis of the magnitude of the current in the light bulb.
At the instant shown, the six scenarios can be ranked in terms of the magnitude of current in the light bulb as follows:
1) Scenario 1 - Here, the battery is directly connected to the light bulb without any other resistors in the circuit. Therefore, the current flowing through the bulb will be the maximum among all the scenarios.
2) Scenario 3 - In this case, the battery is connected to the light bulb through a resistor. However, the resistance is less compared to other scenarios, so the current will be higher than in other cases.
3) Scenario 4 - Here, the battery is connected to the light bulb through a higher resistance compared to scenario 3. This will result in a lesser current in the bulb.
4) Scenario 5 - In this scenario, the battery is connected to the light bulb through a much higher resistance than in the previous two scenarios. Therefore, the current flowing through the bulb will be lower.
5) Scenario 6 - Here, the battery is connected to the circuit in such a way that the current will bypass the light bulb. Therefore, the bulb will not light up and the current flowing through it will be zero.
6) Scenario 2 - This scenario is similar to scenario 6 where the switch is open, so the circuit is not complete, and hence there will be no current flowing through the light bulb.
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swings a 5.5 kg cup of water in a vertical circle of radius 1.9 m. (a) What minimum speed must the cup have in this demo if the front row is not to get wet or spill any water
Answer:
4.32
Explanation:
The centripetal acceleration of any object is given as
A(cr) = v²/r, where
A(c) = the centripetal acceleration
v = the linear acceleration
r = the given radius, 1.9 m
Since we are not given directly the centripetal acceleration, we'd be using the value of acceleration due to gravity, 9.8. This means that
9.8 = v²/1.9
v² = 1.9 * 9.8
v² = 18.62
v = √18.62
v = 4.32 m/s
This means that, the minimum speed the cup must have so as not to get wet or any spill is 4.32 m/s
two long parallel wires are placed side by side on a horizontal table. the wires carry equal currents in the same direction. which of the following statements are true?check all that apply.two long parallel wires are placed side by side on a horizontal table. the wires carry equal currents in the same direction. which of the following statements are true?check all that apply.the magnetic force between the two wires is attractive.the magnetic field at a point midway between the two wires is zero.the magnetic field is a maximum at a point midway between the two wires.the magnetic force between the two wires is repulsive.request answer
The correct statements are:1. The magnetic force between the two wires is attractive. 2. The magnetic field at a point midway between the two wires is zero.
The magnetic force between the two wires is repulsive. This is because the currents in the wires are flowing in the same direction, which creates magnetic fields that interact with each other in a way that causes them to repel.
- The magnetic force between the two wires is attractive: This statement is false because, as mentioned above, the currents in the wires are flowing in the same direction, which causes them to repel each other.
- The magnetic field at a point midway between the two wires is zero: This statement is also false. The magnetic field at a point midway between the two wires is actually a maximum because the magnetic fields created by each wire add together constructively at this point.
- The magnetic field is a maximum at a point midway between the two wires: This statement is true, as explained above.
- The magnetic force between the two wires is repulsive: This statement is true, as explained above.
1. When two parallel wires carry equal currents in the same direction, their magnetic fields interact with each other in such a way that the magnetic force between the wires is attractive. This is due to the alignment of the magnetic fields produced by the currents, causing the fields to combine and pull the wires towards each other.
2. The magnetic field at a point midway between the two wires is zero because the magnetic fields produced by the two wires cancel each other out at this point. Since the wires are carrying equal currents in the same direction, the magnetic fields have equal magnitudes and opposite directions at the midpoint, thus their net effect is zero.
The other two statements are incorrect because:
- The magnetic field is not a maximum at a point midway between the two wires, as explained in statement 2.
- The magnetic force between the two wires is not repulsive, as explained in statement 1.
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where can nuclear fusion be found
Answer:
In the core of stars
Explanation:
Nuclear fusion is usually found in the cores of stars.
In nuclear fusion, there is a combination of atomic nuclei to form a larger one.
The process is accompanied with the release of a large amount of energy. The energy released is used to set up another fusion reaction. In the sun, two hydrogen nuclei are combining to give a helium nuclei with the release of a large amount of energy.Answer:
Nuclear fusion of hydrogen to form helium occurs naturally in the sun and other stars.
A baseball with a mass of 0. 15 kilograms collides with a bat at a speed of 40 meters/second. The duration of the collision is 8. 0 x 103 seconds. The
ball moves off with a speed of 50 meters/second in the opposite direction. What is the value of the force?
The value of force is 1.7 × 10⁻³ N, with the direction opposite to that of the bat's motion.
When an object collides with another object, they exchange energy. For example, a baseball and bat collision or a car collision. When two objects collide, the force of the collision has to be equal on both sides of the collision according to Newton's Third Law. So, to find the value of force, we will apply the equation:
F = ΔP / ΔT
where F is the force, ΔP is the change in momentum, and ΔT is the time of collision. The equation represents the impulse momentum theorem.
Now, let's apply the given values to the above equation.
Final momentum (p2) = mass × final velocity (v2)
p2 = 0.15 kg × (-50 m/s)
p2 = -7.5 kg.m/s
Initial momentum (p1) = mass × initial velocity (v1)
p1 = 0.15 kg × (40 m/s)
p1 = 6 kg.m/s
Change in momentum (ΔP) = p2 - p1
ΔP = -7.5 kg.m/s - 6 kg.m/s
ΔP = -13.5 kg.m/s
Time of collision (ΔT) = 8.0 × 10³ s
Now, putting the values of ΔP and ΔT in the equation of impulse momentum theorem, we get:
F = ΔP / ΔT
F = -13.5 kg.m/s ÷ 8.0 × 10³ s
F = -1.7 × 10⁻³ N
Thus, the value of force is 1.7 × 10⁻³ N, with the direction opposite to that of the bat's motion.
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When light of frequency 3 × 10&14 Hz travels through a transparent material, the wavelength of the light in the material is 600 nm.
What is the index of refraction of this material?
Group of answer choices
6/5
5/4
5/3
10/9
3/2
The index of refraction of the transparent material where light has a wavelength of 600 nm and a frequency of 3 × 10¹⁴ Hz is 5/3. The correct option is 5/3.
To find the index of refraction (n) of a material, we can use the formula:
n = c / v
Where c is the speed of light in vacuum and v is the speed of light in the material.
Frequency of light, f = 3 × 10¹⁴ Hz
Wavelength of light in the material, λ = 600 nm = 600 × 10⁻⁹ m
The speed of light in vacuum is a constant, approximately 3 × 10⁸ m/s.
To find the speed of light in the material, we can use the formula:
v = f * λ
Substituting the given values:
v = (3 × 10¹⁴ Hz) * (600 × 10⁻⁹ m)
Calculating the value of v:
v = 1.8 × 10⁸ m/s
Now we can find the index of refraction:
n = c / v
n = (3 × 10⁸ m/s) / (1.8 × 10⁸ m/s)
Simplifying the expression:
n = 1.67
Among the given answer choices, the closest value to the calculated index of refraction is 5/3.
Therefore, the correct answer is 5/3.
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the amount of gravitational force exerted on each other between two objects depends on their
Answer:
Explanation:
The strength of the gravitational force between two objects depends on two factors, mass and distance. the force of gravity the masses exert on each other. If one of the masses is doubled, the force of gravity between the objects is doubled.
a battery supplies a cell phone a 2600 ma current. how many electrons can this battery supply to the phone during an hour-long conversation?
The battery can supply approximately 5.83 × 10^22 electrons to the phone during an hour-long conversation.
To calculate the number of electrons supplied by a battery to a cell phone during an hour-long conversation, we can use the equation relating current, time, and charge.
The equation is as follows:
Charge (in coulombs) = Current (in amperes) × Time (in seconds)
Given that the current supplied by the battery is 2600 mA (which is equivalent to 2.6 A) and the duration of the conversation is 1 hour (which is equivalent to 3600 seconds), let's calculate the charge:
Charge = 2.6 A × 3600 s
Charge = 9360 C
Now, we know that one coulomb (C) corresponds to the charge of approximately 6.242 × 10^18 electrons. Using this conversion factor, we can calculate the number of electrons supplied by the battery:
Number of electrons = Charge × (6.242 × 10^18 electrons/C)
Number of electrons = 9360 C × (6.242 × 10^18 electrons/C)
Number of electrons ≈ 5.83 × 10^22 electrons
Therefore, the battery can supply approximately 5.83 × 10^22 electrons to the phone during an hour-long conversation.
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What kind of energy transfer occurs when an earthquake produces a large ocean wave called a tsunami
Answer: Mechanical waves transfer energy from rock to water.
Explanation: The particles of the medium just vibrate in place. As they vibrate, they pass the energy of the disturbance to the particles next to them, which pass the energy to the particles next to them, and so on. Particles of the medium don't actually travel along with the wave.
Answer:
Mechanical Waves
Explanation:
Mechanical waves are waves that require a medium for the transfer of their energy to occur. Water waves are an example of mechanical waves. Tsunami waves released after an earthquake transfer the energy of the quake to distant shorelines.
Hope this helps.
If the current through a resistor is tripled, how does the power dissipated by
the resistor change?
If the current that is circuit is tripled, the power is increased by a factor of 9. Option D
What is power?The term power refers to the rate of doing work. Now if we have to obtain the work done by the use of the formula; P = I^2R
Now if the current that is circuit is tripled, the power is now obtained by;
P = (3I)^2R = 9I^2R hence the power is increased by a factor of 9.
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The Switch in this circuit has been closed for a long time and is opened at time t = 0. Determine the value of the voltage V just after the switch is opened at t=0+ t=0 24 Ω + V 60 V 0.01 H 16 2 - 26 22 w A.-21.6 Volts B.- 19.2 Volts C.-19.5 Volts D.-17.5 Volts E.-22.5 Volts
The value of the voltage V just after the switch is opened at t=0+ t=0 is -21.6 Volts.
The given circuit can be drawn as follows:
The voltage in the inductor just before the switch is opened (t = 0-) can be given as,
V = L × di/dt
When the switch is closed for a long time, the circuit reaches steady-state and the current in the circuit becomes constant, given as,
I = 60 V / (24 Ω + 16 Ω)I = 60 V / 40 ΩI = 1.5 A
Taking current as the initial current just before the switch is opened (t = 0-) and the final current just after the switch is opened (t = 0+), we can write the expression for di as,
di = 0 A – 1.5 A = -1.5 A
The time constant of the circuit is given as,τ = L/R = 0.01 H / 40 Ωτ = 0.00025 sec
Now, we can write the expression for voltage across the inductor just after the switch is opened (t = 0+),V = L × di/dt + I × R
Substituting the given values,
V = 0.01 H × (-1.5 A) / 0.00025 + 1.5 A × 16 ΩV = -60 V + 24 VV = -36 V
Now, the voltage across the 16 Ω resistor can be given as,
V = I × R = 1.5 A × 16 ΩV = 24 V
The voltage V just after the switch is opened at t=0+ t=0 is the difference between the voltage across the inductor and the voltage across the resistor, given as,
V = -36 V + 24 V
V = -12 V
Therefore, the value of the voltage V just after the switch is opened at t=0+ t=0 is -21.6 Volts (Option A).
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A wire of resistance R is cut into ten equal parts which are then connected in parallel. The equivalent resistance of the combination is
Answer:
The equivalent resistance of the combination is R/100
Explanation:
Parallel Connection of Resistances
If resistances R1, R2, R3,...., Rn are connected in parallel, the equivalent resistance is calculated as follows:
\(\displaystyle \frac{1}{R_e}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+...+\frac{1}{R_n}\)
The electric resistance of a wire is directly proportional to its length. If a wire of resistance R is cut into 10 equal parts, then each part has a resistance of R/10.
It's known the 10 parts or resistance R/10 were connected in parallel, thus the electric resistance is:
\(\displaystyle \frac{1}{R_e}=\frac{1}{R/10}+\frac{1}{R/10}+\frac{1}{R/10}+...+\frac{1}{R/10}\)
Note the sum consists of 10 equal terms. Operating on each term:
\(\displaystyle \frac{1}{R_e}=\frac{10}{R}+\frac{10}{R}+\frac{10}{R}+...+\frac{10}{R}\)
The sum of 10 identical fractions yields 10 times each fraction:
\(\displaystyle \frac{1}{R_e}=10\frac{10}{R}=\frac{100}{R}\)
Solving for Re needs to take the reciprocal of both sides of the equation:
\(R_e=R/100\)
The equivalent resistance of the combination is R/100
the energy stored in chemical bonds *
Answer:
Chemical energy (Also considered potential energy)
Explanation:
he 420-turn primary coil of a step-down transformer is connected to an ac line that is 120 v (rms). the secondary coil is to supply 15.0 a at 6.30 v (rms). 1) assuming no power loss in the transformer, calculate the number of turns in the secondary coil. (express your answer to two significant figures.)
The number of turns in the secondary coil is 30 turns.
In a step-down transformer, the voltage in the secondary coil is lower than the voltage in the primary coil. The ratio of the number of turns in the primary coil to the number of turns in the secondary coil determines the voltage transformation ratio of the transformer. The voltage transformation ratio is given by:
Vp/Vs = Np/Ns
where Vp and Vs are the voltages in the primary and secondary coils respectively, and Np and Ns are the number of turns in the primary and secondary coils respectively.
Given that Vp = 120 V and Vs = 6.30 V, we can rearrange the equation to solve for Ns:
Ns = (Vs/Vp) x Np
Substituting the given values, we get:
Ns = (6.30 V/120 V) x 420 turns ≈ 30 turns
So, the number of turns in the secondary coil is approximately 30 turns.
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A steel cable initially 7m long is used to strap three logs of timber onto a vehicle. The cable is under a tension of 400N. If the diameter of the cable is 4cm, i) By how much has it to be extended under this tension. ii) How much work has been done in producing this extension. (Young's modulus for steel is 2.0×10^11 N\m^2)
Answer:
i) The extension of the cable can be calculated using the formula:
ΔL/L = F/(A*Y)
where ΔL is the extension in length, L is the original length, F is the tension force, A is the cross-sectional area of the cable, and Y is the Young's modulus of steel.
First, we need to calculate the cross-sectional area of the cable:
A = πr^2 = π(0.02m)^2 = 0.00126 m^2
Now we can calculate the extension:
ΔL/L = 400N/(0.00126m^2 * 2.0×10^11 N/m^2) = 1.5873×10^-6
ΔL = (1.5873×10^-6)(7m) = 1.11×10^-5 m
So the cable has to be extended by 1.11×10^-5 m under this tension.
ii) The work done in producing this extension can be calculated using the formula:
W = (1/2)FΔL
where W is the work done, F is the tension force, and ΔL is the extension in length.
Substituting the given values:
W = (1/2)(400N)(1.11×10^-5 m) = 2.22×10^-3 J
Therefore, the work done in producing this extension is 2.22×10^-3 J.
Explanation:
2. an object slides off a roof 10 meters above the ground with an initial horizontal speed of 5 meters per second as
The object will travel a horizontal distance of 7.15 meters before hitting the ground.
When an object slides off a roof 10 meters above the ground with an initial horizontal speed of 5 meters per second, it will experience two types of motion: horizontal motion and vertical motion. The horizontal speed of the object will remain constant throughout its motion since there are no forces acting in the horizontal direction. On the other hand, the object will experience a vertical motion due to the force of gravity pulling it downward.
The initial velocity of the object can be broken down into its horizontal and vertical components. The horizontal component will remain constant at 5 meters per second, while the vertical component will change as the object falls. The vertical distance the object travels can be calculated using the formula:
d = 1/2 * g * t^2
Where d is the distance traveled, g is the acceleration due to gravity (9.8 m/s^2), and t is the time. The time it takes for the object to hit the ground can be found using the formula:
t = sqrt(2 * d / g)
Substituting the given values, we get:
d = 10 meters (since the object falls from a height of 10 meters)
t = sqrt(2 * 10 / 9.8) = 1.43 seconds
Therefore, it will take the object 1.43 seconds to hit the ground. The horizontal distance the object travels can be calculated using the formula:
d = v * t
Where d is the distance traveled, v is the horizontal velocity, and t is the time. Substituting the given values, we get:
d = 5 * 1.43 = 7.15 meters
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gas particles can change to solid particles if the temperature
Gas particles can change to solid particles if the temperature decreases.
The state of matter of a substance is determined by its temperature and pressure. When the temperature of a gas decreases, its particles lose kinetic energy and slow down. This decrease in kinetic energy leads to a decrease in the average speed of gas particles.
As the temperature continues to decrease, the particles lose energy and move closer together. At a certain temperature known as the condensation point or the freezing point, the gas particles no longer have enough energy to overcome the intermolecular forces holding them together.
At this point, the gas undergoes a phase transition and changes into a solid. The process of gas turning into a solid is called condensation or freezing, depending on the specific substance.
During condensation, the gas particles arrange themselves in a more orderly and structured manner, forming a solid. The transition from gas to solid involves the release of energy, known as heat of fusion.
In summary, when the temperature of a gas decreases below its condensation or freezing point, the gas particles lose energy, slow down, and eventually come together to form a solid.
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A girl takes her dog for a walk on a sunny beach. Find the force of gravity between the 45-kg girl and her 11-kg dog when they are separated by a distance of 2.00m
The gravitational force acting between them is \(8.25*10^-^9N\)
Data given;
M1 = 45kgM2 = 11kgr = 2.0mG = \(6.67*10^-^1^1m^3kg^-^1s^-^1\)To solve this question, we need to apply gravitational force or energy formula.
Gravitational ForceThis states that the force of attraction between two bodies is equal to the product of their bodies and inversely proportional to the square of their distance apart.
Mathematically;
\(F = \frac{GM_1M_2}{r^2} \\\)
let's substitute the values and solve
\(F = \frac{Gm_1m_2}{r^2}\\F = \frac{6.67*10^-^1^1 * 45 * 11}{2^2}\\F = 8.25*10^-^9N\)
The force of gravity acting between them is \(8.25*10^-^9N\)
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A circuit calls for a 0.600 mm -diameter copper wire to be stretched between two polnts. You don't have any copper wire, but you do have aluminum wire in a wide variety of diametars Part A What diameter aluminum wire will provide the same resistance? Express your answer with the appropriate units. Value Units Submit Request Answer Provide Feedback Next >
The diameter of the aluminum wire that will provide the same resistance as that of a 0.600 mm-diameter copper wire is 0.78 mm.
Firstly, we will find the resistance per unit length (R/L) of the copper wire using the formula:
R/L = ρ/(πr²), where ρ is resistivity and r is the radius.
Now, we have to determine the resistivity values for copper and aluminum.
The resistivity of copper is approximately 1.68 × 10⁻⁸ Ωm, and the resistivity of aluminum is approximately 2.82 × 10⁻⁸ Ωm.
Now, we will calculate the resistance per unit length for the copper wire:
R/L (copper) = (1.68 × 10⁻⁸ Ωm) / (π × (0.3 × 10⁻³ m)²) ≈ 5.942 × 10⁻² Ω/m
Now, we have to find the diameter of the aluminum wire by equating the resistance per unit length of both wires and solving for the radius of the aluminum wire:
R/L (copper) = R/L (aluminum)
(5.942 × 10⁻² Ω/m) = (2.82 × 10⁻⁸ Ωm) / (π × r²)
Now, solve for the radius of the aluminum wire:
r² = (2.82 × 10⁻⁸ Ωm) / (π × 5.942 × 10⁻² Ω/m)
r ≈ 3.9 × 10⁻⁴ m
Converting the radius to diameter:
Diameter = 2 × r
≈ 2 × 3.90 × 10⁻⁴ m
≈ 7.80 × 10⁻⁴ m
≈ 0.78 mm
So, the diameter of the aluminum wire that will provide the same resistance as a 0.600 mm-diameter copper wire is approximately 0.78 mm.
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How do charging and discharging compare? How can charging go unnoticed,
but discharging is often accompanied by a shock?
if the maximum distance between two protons (and other nuclei) such that they fuse together were considerably higher than the actual required distances, then fusion
Fusion reactions would be much less likely to occur, and the process of creating energy from fusion would be much more difficult to achieve.
If the maximum distance between two protons (and other nuclei) such that they fuse together were considerably higher than the actually required distances, then fusion reactions would not occur as frequently or efficiently. Fusion occurs when two nuclei come close enough together for the strong nuclear force to overcome the electrostatic repulsion between positively charged protons. If the required distance for fusion was much greater, it would be much more difficult for the nuclei to overcome this repulsion and approach each other close enough to fuse. As a result, fusion reactions would be much less likely to occur, and the process of creating energy from fusion would be much more difficult to achieve.
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