Describe how you would prepare exactly 100 mL of 0.109 M picolinate buffer, pH 5.61. Possible starting materials are pure picolinic acid (pyridine-2-carboxylic acid, FM 123.10), 1.0 M HCl, and 1.0 M NaOH. Place the given steps in order. Not all of the steps will be used.

Answer:

Model B (in image) would the best representation of aluminum chloride.

Explanation:

It's the only model the has three chlorine atoms and one aluminum atom.

Additionally, Cl can only bond once, so it can't be bonded to multiple different atoms. Also, Al needs to have more than one bond to achieve the octet rule.

Answer:

B) ethanol

Explanation:

I got a 100% on my test plus its the answer on usatestprep

0.361 moles of N₂ were required to produce 12.3 g of NH₃, using the balanced chemical equation N₂ + 3H₂ → 2NH₃.

The balanced chemical equation for the reaction is N₂ + 3H₂ → 2NH₃. We can use the balanced equation and the molar mass of NH₃ to calculate the number of moles of N₂ required to produce 12.3 g of NH₃,

1 mol NH₃ = 2 mol N₂ (from the balanced equation)

molar mass of NH₃ = 17.03 g/mol

moles of NH₃ = 12.3 g / 17.03 g/mol

moles of NH₃ = 0.722 mol

moles of N₂ = (0.722 mol NH₃) / 2

moles of N₂ = 0.361 mol

Therefore, 0.361 moles of N₂ were needed to produce 12.3 grams of NH₃.

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Complete question - For the reaction, N₂ + 3H₂ → 2NH₃. Given 12.3 grams of NH3, how many moles of N₂ were needed?​

Answer:

I ratio is

47 : 43 ratio

Answer:

40,113 years

Explanation:

To find the age of the sample, you need to use the half-life formula:

\(N(t)=N_0(\frac{1}{2})^{t/h\)

In this formula:

------> N(t) = current mass (g)

------> N₀ = initial mass (g)

------> t = time passed (yrs)

------> h = half-life (yrs)

You can plug the given values into the equation and rearrange the formula to find "t".

N(t) = 0.781 g                       t = ? yrs

N₀ = 100 g                           h = 5730 yrs

\(N(t)=N_0(\frac{1}{2})^{t/h\)                                           <----- Half-life formula

\(0.781=100(\frac{1}{2})^{t/5730}\)                                     <----- Insert values

\(0.00781=(\frac{1}{2})^{t/5730}\)                                       <----- Divide both sides by 100

\(log_{1/2}(0.00781)=log_{1/2}((\frac{1}{2})^ {t/5730})\)               <----- Take \(log_{1/2}\) of both sides

\(7.00 = \frac{t}{5730}\)                                                   <----- Solve \(log_{1/2}\)

\(40,113 = t\)                                                   <----- Multiply both sides by 5730

The given sample is 40,113 years .

Half-life, in radioactivity, is the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay.

Half-life formula,

\(\rm N(t)\;=N_0(\dfrac{1}{2})^\frac{t}{t1/2}\)   .......(1)

where,

N(t)=current mass

N₀=initial mass

t=time period

h=half -life

Given,

N(t)=0.781g, t=? yrs, N₀=100g, h=5730 years

\(\rm N(t)\;=N_0(\dfrac{1}{2})^\frac{t}{t1/2}\)

put the values, in ......(1)

0.781=100(1/2) \(t/5730\\\)

log₁/₂(0.00781)=log₁/₂ ( 1/2)\(t/5730\)

7=t/5730

40,113=t

Hence, the given sample is 40,113 years .

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Answer:

What's the gas given in the question??

The property X is an extrinsic property.

The term extensive property refers to the type of property that depends on the amount of the substance present. We must recall that an intensive property does not in any way depend on the number or the amount of the substance present in the sample.

If we have a good look at the table that is being referred to here, we would see that the mass of the substance tends to increase as a certain un named property of the substance X is increasing. This implies that the property X is affected by the mass of the object which is the quantity of matter in the object. This gives us an idea that the property that we are referring to can not be an intrinsic  property since it varies with the mass of the substance that is under study as shown.

We can then conclude that the property X is an extrinsic property.

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Missing parts;

Carrie measured mass and another property, X, of three pure samples of the same compound. She recorded her data in the table. Which of the following best describes property X?

A. X  is an intensive property because it does not vary with the size of the sample.

B. X is an extensive property because it does not vary with the size of the sample.

C. X is an extensive property because it varies directly with the size of the sample.

D. X is an intensive property because it varies directly with the size of the sample.

You could form approximately 5.8 grams of methanol (CH3OH) from the given gas mixture at STP.

Using the Ideal gas equation;

n = PV / RT

n = (1 atm * 7.82 L) / (0.0821 L·atm/(mol·K) * 273.15 K)

From the question;

nCO = n / 2

nH2 = n / 2

Then;

n = (1 atm * 7.82 L) / (0.0821 L·atm/(mol·K) * 273.15 K)

n = 0.362 mol

nCO = n / 2 = 0.362 mol / 2 = 0.181 mol

nH2 = n / 2 = 0.362 mol / 2 = 0.181 mol

By stoichiometry;

methanol= nCO = 0.181 mol

Mass of methanol =  0.181 mol * 32.04 g/mol

= 5.8 g

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The heat of combustion of the material is obtained as  35.5 kJ/g.

The heat of combustion refers to the heat that is given off when a substance is burnt in oxygen. Now we are told that a 3.743 g sample of a new organic material is combusted in a bomb calorimeter. The temperature of the calorimeter and its contents increase from 23.97 ∘C to 27.16 ∘C.

Thus;

Heat evolved can be obtained by the use of the formula;

H = cdT

c = heat capacity

dT= temperature change

H =  41.93 kJ/ ∘C * (27.16 ∘C - 23.97 ∘C)

H = 133.8 kJ

The  heat of combustion per gram of the material is;

133.8 kJ/ 3.743 g  = 35.5 kJ/g

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The heat of combustion per gram of the material is 35.74 kJ/g

The heat of combustion per gram of the substance is calculated as follows:

Heat change = specific heat capacity * temperature change

mass of sample = 3.743 g

The heat capacity of the calorimeter = 41.93 kJ/ ∘C

temperature change = 27.16 - 23.97 = 3.19

Heat change = 41.93 * 3.19

Heat change = 133.76 kJ

The heat of combustion per gram =  133.76 kJ / 3.743 g

The heat of combustion per gram = 35.74 kJ/g

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Between water with a pH of 4 and one with a pH of 7.4, I will rather go swimming in the one with a pH of 7.4.

The pH of a substance is the degree of acidity of alkalinity of the substance.

The pH scale ranges from 0 to 14. A pH of 7 is considered neutral.

Any pH below 7 is acidic. The further the pH is the downside of 7, the more acidic the substance.

Any pH above 7 is considered basic. The further the pH is the upside of 7, the more basic or alkaline the substance is.

Substances with very high or very low pH are usually corrosive and will harm the human body. The human body's pH ranges between 7.35 to 7.45.

Thus, swimming in water with a pH of 4 would be totally harmful to the body. Swimming in water with a pH of 7.4 would be safe.

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Answer:

Osmosis is the movement of solvent particles across a semipermeable membrane from a dilute solution into a concentrated solution. ... Diffusion: Diffusion is the movement of particles from an area of higher concentration to lower concentration. The overall effect is to equalize concentration throughout the medium.

Osmosis is a special case of diffusion. Water, like other substances, moves from an area of higher concentration to one of lower concentration. ... In this example, the solute cannot diffuse through the membrane, but the water can. Water has a concentration gradient in this system.

Answer:

It's heat energy

Explanation:

which is transmitted through radiation.  The sun warms us.

Explanation:

First element

1s2 2s2 2p6 3s2 3p6

Atomic Number = 18

Element = Argon

Second Element

1s2 2s2 2p6 3s2

Atomic Number = 12

Element = Magnesium

Second Element

1s2 2s2 2p6 3s2 3p6 4s1

Atomic Number = 19

Element = Potassium

In the periodic table;

The general trend is for ionization energy to increase moving from left to right across an element period. It would decrease down the group.

Both Argon and Magnesium are on the same period. Potassium is o the period below.

This leads us to;

Magnesium - 0.7377 MJ/mol

Argon -  1.505 MJ/mol

Potassium - 0.4189 MJ/mol

The atomic radius of atoms generally decreases from left to right across a period.  It would increase down the group.

This leads to;

Magnesium - 1.60

Argon -  0.94

Potassium - 2.35

The following are some things you do to help you learn and remember new words and they mean:-

Reading is one of the only methods to teach vocabulary and normal learning is the approach that gives college students the possibility to exercise and grasp the stages of crucial reading that result in studying success and progressed word utilization.

One of the maximum impactful mastering techniques is allotted practice spacing out your analyzing over several brief intervals of time over several days and weeks. The only exercise is to work a quick time on every elegance every day.

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Explanation:

If 2.54 g of PbS is burned with 1.88 g of O2, approximately 2.20 grams of Pb will be produced.

The balanced equation for the reaction of lead sulfide (PbS) with oxygen (O2) to produce lead (Pb) and sulfur dioxide (SO2) is as follows:

2PbS + 3O2 -> 2Pb + 2SO2

From the balanced equation, we can see that the stoichiometric ratio between PbS and Pb is 2:2 or 1:1. This means that for every 1 mole of PbS, 1 mole of Pb is produced.

To calculate the number of moles of PbS, we need to divide the given mass (2.54 g) by its molar mass:

Molar mass of PbS = 207.2 g/mol (Pb) + 32.07 g/mol (S) = 239.27 g/mol

Moles of PbS = 2.54 g / 239.27 g/mol = 0.0106 mol

Since the stoichiometric ratio between PbS and Pb is 1:1, the number of moles of Pb produced is also 0.0106 mol.

To calculate the mass of Pb, we multiply the number of moles by its molar mass:

Molar mass of Pb = 207.2 g/mol

Mass of Pb = 0.0106 mol x 207.2 g/mol = 2.20 g

This calculation is based on the stoichiometric ratio between PbS and Pb, where 1 mole of PbS produces 1 mole of Pb. By converting the given mass of PbS to moles and then multiplying by the molar mass of Pb, we can determine the mass of Pb produced.

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Answer:

3.2877204

Explanation:

Answer:

0.9 g (approximately)

Explanation:

Answer: \(MgS\), \(MgBr_2\), \(V_2S_5\) and \(VBr_5\) are four binary ionic compounds that could be formed.

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

Mg is having an oxidation state of +2 called as \(Mg^{2+}\) cation and \(S^{2-}\) is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral \(MgS\). Also \(Mg^{2+}\) cation and \(Br^{-}\) can combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral \(MgBr_2\).

Also Vanadium is having an oxidation state of +5 called as \(V^{5+}\) cation and \(S^{2-}\) is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral \(V_2S_5\). Also \(V^{5+}\) cation and \(Br^{-}\) anion can combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral \(VBr_5\).

Answer:

To convert joules to calories, you can use the conversion factor:

1 calorie = 4.184 joules

To find out how many calories are in 4,180 joules, divide the given value by the conversion factor:

4,180 joules / 4.184 joules per calorie = 0.9 calories (approximately)

Therefore, there are approximately 0.9 calories in 4,180 joules.

Answer:

your cool

Explanation:

owa owa owa owa owa bob

The substance in red blood cells that carbon monoxide from cigarette smoke combines with is called hemoglobin.

Hemoglobin is a protein molecule found in red blood cells that is responsible for transporting oxygen from the lungs to the rest of the body. Hemoglobin consists of four subunits, each containing a heme group. The heme group contains an iron ion, which binds to oxygen molecules in the lungs.

Carbon monoxide (CO) from cigarette smoke can bind to the iron ion in the heme group with a much greater affinity than oxygen. When CO binds to hemoglobin, it forms a stable complex called carboxyhemoglobin (COHb).

This reduces the amount of hemoglobin available for binding with oxygen, which can lead to a reduction in the amount of oxygen that can be transported to the tissues.

The formation of COHb can also affect the release of oxygen from hemoglobin in the tissues. Hemoglobin releases oxygen in response to a decrease in oxygen concentration, which is sensed by the heme group. However, when CO binds to the heme group, it alters the shape of the hemoglobin molecule and reduces its ability to release oxygen.

As a result, the presence of carbon monoxide in the blood can lead to a range of health problems, including headaches, dizziness, shortness of breath, and even death in severe cases.

The best way to prevent carbon monoxide poisoning is to avoid exposure to smoke from tobacco products and other sources of combustion, such as gas heaters and stoves.

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Answer:humis

Explanation:because I looked it up

Answer:

It is C humus! also this is correct!

Explanation:

The statement which accurately describes a light-year is " It is the distance that light travels in a year."

A light-year would be the actual distance a light beam is able to travel in one year on Earth, that would be roughly 6 trillion miles.

The region of the electromagnetic spectrum that the human eye perceives as light, as well as visible light, has been made up of electromagnetic radiation.

The statement which accurately describes a light-year is " It is the distance that light travels in a year."

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Answer: B

Explanation:

Answer:

a molecule is the smallest particle of a substance that can normally exist independenty

Answer:

32.52×10¹⁹ atoms

Explanation:

Given data:

Mass of gold = 0.106 g

Number of atoms of gold = ?

Solution:

We will calculate the number of moles first.

Number of moles = mass/molar mass

Number of moles = 0.106 g/ 197 g/mol

Number of moles = 5.4×10⁻⁴ mol

Number of atoms:

1 mole contain 6.022×10²³ atoms

5.4×10⁻⁴ mol ×  6.022×10²³ atoms /1 mol

32.52×10¹⁹ atoms

Answer:

First is battery acid with a pH of 1, second is stomach acid with a pH of 1.5-3.5 (depends), third is antacid with a pH of 7, fourth is baking soda with a pH of 9, and finally, fifth is household ammonia with a pH of 11.

Here is a picture of the pH levels to better help you understand.

Answer:

b

Explanation: