A longitudinal wave is a wave in which particles of the medium move in a direction parallel to the direction that the wave moves.
These waves are always characterized by particle motion being parallel to wave motion.
In a longitudinal wave, particles of the medium are displaced in a direction parallel to energy transport.
Need help solving this question.
(a) The magnitude of the angular momentum of the system is 5,252 kg m²/s.
(b) The rotational energy of the system is 2,826 J.
(c) The new moment of inertia is 31.25 Kgm².
(d) The new speed of each astronaut is 420.15 m/s.
(e) The new rotational energy of the system is 65.82 kJ.
(f) The work is done by the astronauts in shortening the rope -45,317,098 KJ.
(a) To calculate the magnitude of the angular momentum of the system, we can use the following equation:
L = Iω
where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity. Since we are treating the astronauts as particles, we can assume they are point masses and use the formula for the moment of inertia of a point mass:
I = mr²
where m is the mass of each astronaut and r is the distance between them. The angular velocity can be found from the linear velocity and the distance between the astronauts:
ω = v/r
Putting in the given values, we get:
r = 5.00 m
m = 90.5 kg
v = 5.80 m/s
I = 2(mr²) = 2(90.5 kg)(5.00 m)²
= 4,525 kg m²
ω = v/r = 5.80 m/s / 5.00 m
= 1.16 rad/s
L = Iω = (4,525 kg m²)(1.16 rad/s)
= 5,252 kg m²/s
Therefore, the magnitude of the angular momentum of the system is 5,252 kg m²/s.
(b) To calculate the rotational energy of the system, we can use the following equation:
E = (1/2)Iω²
Putting in the values for I and ω that we found in part (a), we get:
E = (1/2)(4,525 kg m²)(1.16 rad/s)²
= 2,826 J
Therefore, the rotational energy of the system is 2,826 J.
(c) When the distance between the astronauts is shortened to 5.00 m, the moment of inertia of the system changes. We can calculate the new moment of inertia using the parallel axis theorem:
I = Icm + md²
where Icm is the moment of inertia about the center of mass (which remains the same), m is the mass of each astronaut, and d is the distance between each astronaut and the center of mass (which is half the original distance, or 2.50 m).
The new moment of inertia is:
I = Icm + 2md²
= 2(m(2.50 m)²)
= 31.25 kg m²
Therefore the new moment of inertia is 31.25 Kgm².
(d) To find the new speeds of the astronauts, we can use the conservation of angular momentum:
L = Iω = L'
where L is the initial angular momentum (which we found in part (a)) and L' is the new angular momentum (which we can find using the new moment of inertia and the new distance between the astronauts, which is 5.00 m).
Solving for ω', we get:
ω' = L' / I = L / I'
Putting in the values, we get:
L' = L = 5,252 kg m²/s
I' = 31.25 kg m²
ω' = 5,252 kg m²/s / 31.25 kg m² = 168.06 rad/s
The new speed of each astronaut is the tangential velocity at a distance of 2.50 m from the center of mass, which can be found using the formula:
v = ω'r
where r is the distance from the center of mass. Putting in the values, we get:
v = 168.06 rad/s * 2.50 m = 420.15 m/s
Therefore, the new speed of each astronaut is 420.15 m/s.
(e) To find the new rotational energy of the system after the astronauts have shortened the rope to 5.00 m, we can use the conservation of angular momentum:
L = Iω
where L is the angular momentum of the system, I is the moment of inertia of the system, and ω is the angular speed of the system. Since the rope is assumed to have negligible mass, we can treat the system as two point masses moving in a circle around their center of mass. The moment of inertia of this system can be calculated as:
I = 2mr²/5
where m is the mass of each astronaut and r is the distance between them. Initially, the moment of inertia of the system is:
I = 2 * 90.5 kg * (10.0 m / 2)² / 5
= 3638 kg m²
The initial angular momentum of the system is:
L = Iω = 3638 kg m² * (5.80 m/s) / (10.0 m / 2)
= 4213.6 kg m²/s
After the astronauts have shortened the rope to 5.00 m, the moment of inertia of the system is:
I' = 2 * 90.5 kg * (5.00 m / 2)² / 5
= 1352.5 kg m²
Since the angular momentum of the system is conserved, the new angular speed of the system is:
ω' = L/I' = 4213.6 kg m²/s / 1352.5 kg m² = 3.115 rad/s
E' = (1/2)I'ω'² = (1/2) * 1352.5 kg m² * (3.115 rad/s)²
= 65,817.6 J
= 65.82 kJ
Therefore, the new rotational energy of the system is 65.82 kJ.
(f) The work done by the astronauts in shortening the rope is:
W = ∫F dl = (F' - F) ∫dl
= (6,043,064.25 N - 630.56 N) * (-7.50 m)
= -45,317,098 KJ
Therefore, the work is done by the astronauts in shortening the rope -45,317,098 KJ.
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cycling at 13.0 m/s on your new aero carbon fiber bike, how much times would it take a pro cyclist to ride in 120 km? Give your answer in seconds, minutes, and hours
We have that the time in seconds, minutes, and hours is
\(t=1.083*10^{-4}s\)
\(T_{min}=1.805*10^{-6}min\)
\(T_{hours}=3.0083*10^{-8}hours\)
From the Question we are told that
Velocity \(v=13.0m/s\)
Distance \(d=120 km\)
Generally the equation for the Time is mathematically given as
\(t=\frac{13}{120*10^3}\\\\t=1.083*10^{-4}s\)
Therefore
\(T_{min}=1.083*10^{-4}s/60\)
\(T_{min}=1.805*10^{-6}min\)
And
\(T_{hours}=T_{min}/60\)
\(T_{hours}=3.0083*10^{-8}hours\)
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Which best describes friction?
Answer:
It is the force that opposes motion between two surfaces touching each other. ( OR ) The force between two surfaces that are sliding or trying to slide across each other.
Explanation:
Answer:
a constant force that acts on objects that rub together
Explanation:
a constant force that acts on objects that rub together
Which kind of kinetic energy is a rolling ball?
car driving on a circular test track shows a constant speedometer reading of 100 kph for one lap. a. Describe the car's speed during this time. b.
Answer:
Speed = 100 km/h
Explanation:
Given:
Speedometer reading = 100 kph for one lap
Assume;
Time taken to complete one lap = 1 hour
Computation:
Speed = Distance / Time
Speed = 100 / 1
Speed = 100 km/h
What impact could lowering the pH of ocean water have? choose all that apply
O sea level rise
O shellfish decreasing
O decreasing amount of coral
Ofish being "burned by the acid"
Traumatic brain injury such as concussion results when the head undergoes a very large acceleration. Generally, an acceleration less than 800 m/s2 lasting for any length of time will not cause injury, whereas an acceleration greater than 1,000 m/s2 lasting for at least 1 ms will cause injury. Suppose a small child rolls off a bed that is 0.50 m above the floor. If the floor is hardwood, the child's head is brought to rest in approximately 2.3 mm. If the floor is carpeted, this stopping distance is increased to about 1.4 cm. Calculate the magnitude and duration of the deceleration in both cases, to determine the risk of injury. Assume the child remains horizontal during the fall to the floor. Note that a more complicated fall could result in a head velocity greater or less than the speed you calculate
The acceleration and distance:
a2 = 2,168 m/s²
t2= 1.3 msa2= 196 m/s²t2 = 0.015 s = 15 msWhat is the magnitude and duration of the deceleration in both cases, to determine the risk of injury. ?In general, the following tactic constitutes the overall strategy:
(I) To begin, you will need to determine the child's velocity v at the point of impact.
(II) after that, determine the amount of deceleration based on the stopping distance.
These two equations, which originate from the explanation of what it means to "accelerate," are used in both calculations:
v = at (1) (1)
s = at²/2 (2) (2)
where
a stands for acceleration.
t is the amount of time needed to go from having no velocity to having a certain velocity, or vice versa.
The value s represents the total distance covered during the allotted time t.
Let's get ready to perform the algebraic operations that are listed below.
From (2) t = √(2s/a) (3)
From (1) and (3) v = a√(2s/a) = √(2sa) (4)
From (4) a = v²/2s (5)
Let
s1 = 0.42 m be the distance of the fall,
s2 = 1.9 mm or 1.2 cm be the stopping distance,
t1 will be an unknown value representing the amount of time it takes to fall,
t2 will be an unknown value representing the amount of time it takes to decelerate, v will be an unknown value representing the velocity at impact, and a1 will be the gravitational acceleration (experienced during fall)
a2 is an unknown value that represents the deceleration felt during the impact.
(I)
To calculate v, use equation (4) substituting s = s1, a = a1
Then
v = √(2s1a1) (6)
(II)
To calculate a2 and t2, substituting s = s2, a = a2, and v from (6).
Then using (5) and (6)
a2 = v²/2s2 = 2s1a1/2s2 = (s1/s2)a1
Using (3)
t2 = √(2s2/a2) = √(2s2/((s1/s2)a1) = √(2s2²/(s1a1) = s2√(2/(s1a1))
Now substitute actual numbers:
The case of hardwood
a2 = (0.42/0.0019)×9.81 = 2,168 m/s²
t2 = 0.0019×√(2/(0.42×9.81) = 0.0013 s = 1.3 ms
The case of carpet
a2 = (0.42/0.021)×9.81 = 196 m/s²
t2 = 0.021×√(2/(0.42×9.81) = 0.015
s = 15 ms
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Give two examples of situations or application where electronic circuits are used
If the hydraulic lift in question 1 needs to lift a car with a weight of 6000 N, what is the surface area of the lifting platform to balance the pressures?Question 1 for reference:1.If a hydraulic lift uses a force of 400 N on a piston of area 0.065 m2, what is the pressure on the piston? (10 points) Approximately 6153.84 Pa
Given:
Piston 1 has an area
\(A_1=0.065\text{ m}^2\)and the force applied on this piston is
\(F_1=\text{ 400 N}\)The force on piston 2, which is the weight of the car, is
\(F_2=6000\text{ N}\)Required: The area of piston 2.
Explanation:
The formula that can be obtained by balancing the pressures is
\(\begin{gathered} P_1=P_2 \\ \frac{F_1}{A_1}=\frac{F_2}{A_2} \\ A_2=\frac{F_2A_1}{F_1} \end{gathered}\)On substituting the values, the area of the second piston will be
\(\begin{gathered} A_2=\frac{6000\times0.065}{400} \\ =0.975\text{ m}^2 \end{gathered}\)Final Answer: The area of the piston lifting the car is 0.975 meter-squared.
a block with a mass of m slides at a constant velocty v0 on a horizontal frictionless surface. if the spring constant iis k , what ii the maximm compresion in the spring
If the block's mass is m, block's initial velocity is v and the spring constant is k, the maximum compression in the spring is sqrt(mv² /k)
Applying the law of conservation of energy, since it is a frictionless surface, all the kinetic energy of the block will be converted to the potential energy of the spring.
The kinetic energy of the block:
Ek = 1/2 . mv²
Where:
m = mass of block
v = block's initial velocity
The potential energy of the spring:
Ep = 1/2 . kx²
Where:
k = spring constant
x = maximum compression in the spring
It holds:
Ek = Ep
1/2 . mv² = 1/2 . kx²
x = sqrt(mv² /k)
Hence, the maximum compression in the spring is sqrt(mv² /k)
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who is the Prime Minister of India
Answer:
Narendra Modi
Explanation:
The answer depends on what year you are talking about on, Narendra Modi was a prime minister of india since 2014. If you are missing information on your question tell me so I can try and tell you the answer,
Hope this helped,
have a good day :]
Add the following two vectors if \vec{A} + \vec{B} = \vec{C} Keep a few digits. |\vec{A}| = 10N \theta_{A} = 30^{\circ} |\vec{B}| = 8N \theta_{B} = 10^{\circ}
The addition of vectors allows us to find that the resulting vector is
c = 17.73 N with an angle of θ = 21.1º
Giving parameters
The vector A a = 10 N θ = 30º The vector B B = 8 N θ = 10ºTo find
the vector adds
Vector magnitudes have magnitude and direction, so their addition must be done using the vector aliebre.
Analytical method is one of the easiest ways to use vectors, it consists of the following parts:
Decompose vectors into a coordinate system Perform the algebraic sum of the components Find the resultant vector.
Let's decompose the two vectors into a coordinate system with the horizontal x axis and the vertical y axis, in the attachment we can see a diagram of the vectors
Vector A
cos 30 = \(\frac{A_x}{A}\)
sin 30 = \(\frac{A_y}{A}\)
Aₓ = A cos 30
\(A_y\) = A sin 30
Aₓ = 10 cos 30
A_y = 10 sin 30
Aₓ = 8.66 N
A_y = 5.00 N
Vector B
cos 10 = \(\frac{B_x}{B}\)
sin 10 = \(\frac{B_y}{B}\)
Bₓ = B cos 10
\(B_y\) = B sin 10
Bₓ = 8 cos 10 = 7.878 N
B_y = 8 sin 10 = 1.389 N
We perform the algebraic sum
x-axis
x = Aₓ + B_y
x = 8.66 +7.878
x = 16.54 N
y-axis
y = A_y + B_y
y = 5.00 + 1.389
y = 6.39 N
We construct the resulting vector
For the module we use the Pythagoras' theorem
c = \(\sqrt{x^2+y^2}\)
c =\(\sqrt{16.54^2 + 6.39^2}\)
c = 17.73 N
For the direction we use trigonometry
tan θ = \(\frac{y}{x}\)
θ = tan⁻¹ \(\frac{y}{x}\)
θ = tan⁻¹ \(\frac{6.39} { 16.54}\)
θ = 21.1º
measured counterclockwise from the positive side of the x-axis
In conclusion using vector addition we can find the resulting vector is
c = 17.73 N with an angle of θ = 21.1º
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dark matter was first detected because the _____________ for the amount of gravity that could be present due to the luminous mass.
Galaxies were originally found to rotate at a rate that was too fast for said amounts of gravity that might be produced by the luminous mass. This led to the discovery of dark matter.
What is the plain meaning of gravity?The force that pulls items toward the center of a planetary or other entity is called gravity. Each one of the planets are kept in orbits around the sun by gravity.
What is the cause of gravity?Albert Einstein discovered the solution in 1915 when he released his general relativity theories. All entities with mass, including our Earth, really bend and curve spacetime, which is what causes gravity to pull you toward the ground.
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3. The Impact was the first commercial electric car to be developed in over 60
years. During performance tests in 1994, the car reached a top speed of nearly
296 km/h. Suppose the car started at rest and then underwent a constant
acceleration of 1.6 m/s² until it reached its top speed. How long did it take the
Impact to reach its top speed?
According to the question, the impact of an electric car to reach its top speed is found to be 51 sec.
What is Acceleration?Acceleration may be defined as the process of the rate of change of the velocity of an object with respect to time. It is a vector quantity as it has both magnitude and direction.
According to the question,
The acceleration of an electric car = 1.6 m/s²
The speed of an electric car = is 296 km/hour = 1000 m/hour. = 82.2 m/sec.
The acceleration of any moving object is calculated with the help of the following formula:
Acceleration, a = change in velocity/time taken.1.6 m/s² = 82.20 - 0/t
t = 51.45 sec ≅ 51 seconds.
Therefore, the impact of an electric car to reach its top speed is found to be 51 sec.
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The liquid pressure
A. Decreases as the depth increases
B. increases as the depth increases
C. independent of area of container
D. The same everywhere
Answer:
B. increase as the depth increase
Which of the following correctly ranks the magnitude of the average acceleration of the cart during the four sections of the graph?
a) Acd > Aab > Abc > Ade
b) Abc > Aab > Acd > Ade
c) Aab > Abc > Ade > Acd
d) Acd > Aab > Ade > Abc
The magnitude of the average acceleration of the cart: a(CD) > a(AB) > a(DE) > a(BC). Therefore, option (d) is correct.
What is average acceleration?Acceleration can be defined as the rate of change of velocity and is denoted by ‘a. It is measured in the units of m/s². For a particular interval, the average acceleration is the change in velocity for that specific time interval.
Average acceleration is calculated by the following formula,
Average acceleration = Δv/Δt
Where Δ v is the change in velocity and Δt is the total time in the velocity is changing.
For the curve AB:
Average acceleration = \(a =\frac{v_f-v_i}{t_f-t_i}\)
a = (8 -0)/(0.6 - 0) = 13.3 m/s²
For the curve BC:
Average acceleration = \(a =\frac{v_f-v_i}{t_f-t_i}\)
a = (8 -8)/1 - 0.6) = 0 m/s²
For the curve CD:
Average acceleration = \(a =\frac{v_f-v_i}{t_f-t_i}\)
a = (0-8)/(1.2 -1.0) = -40 m/s²
For the curve DE:
Average acceleration = \(a =\frac{v_f-v_i}{t_f-t_i}\)
a = (-4-0)/(2.0 - 1.2) = 5 m/s²
Therefore, the magnitude of the average acceleration of the cart: Acd > Aab > Ade > Abc
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A 50.0-kg wagon is pulled with a constant force of 380 N. Neglecting friction, the wagon's acceleration will be
A 50.0-kg wagon is pulled with a constant force of 380 N. Neglecting friction, the wagon's acceleration will be 7.6 m/s².
When a constant force acts on a wagon, it causes the wagon to accelerate We can calculate the wagon's acceleration using Newton's second law, which states that the force acting on an object is directly proportional to its acceleration, and the acceleration is inversely proportional to the mass of the object.A = F/mHere,A = AccelerationF = Force acting on the wagon m = mass of the wagon Substituting the given values, we getA = 380 N/50.0 kgA = 7.6 m/s²Therefore, the acceleration of the wagon is 7.6 m/s² when it is pulled with a constant force of 380 N, neglecting friction.For such more question on Newton's second law
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A girl rides her bicycle 1.40 kilometers west, 0.70 kilometer south, and 0.30 kilometer east in 12 minutes. The vector diagram below represents the girl's fist two displacements in sequence
from point P. The scale used in the diagram is 1.0 centimeter = 0.20 kilometer.
8. Determine the measure of the angle, in degrees, between the resultant and the 1.40-
kilometer displacement vector.
Answer:
See below
Explanation:
For a right triangle, remember that tan = opposite leg / adjacent leg:
The angle will be found by using the inverse tangent function
arctan ( .3/1.4) = 12°
The measure of the angle, in degrees, between the resultant and the 1.40-kilometer displacement vector is 12.
What is vector?In physics, a vector is a quantity with both magnitude and direction. It is often represented by an arrow whose length is proportional to the magnitude of the quantity and whose direction is the same as that of the quantity.
A vector does not have position, while having magnitude and direction. In other words, a vector's shape is unaltered if it is shifted parallel to itself as long as its length is unaltered.
Ordinary quantities with a magnitude but no direction are referred to as scalars in contrast to vectors. For instance, while speed (the amount of velocity), time, and mass are scalars, displacement, velocity, and acceleration are vector quantities.
Therefore, The measure of the angle, in degrees, between the resultant and the 1.40-kilometer displacement vector is 12.
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What principle of fitness means that if you stop exercising your fitness level will decrease?
A.
Reversibility
B.
Overload
C.
Specificity
D.
Individuality
Answer:
A. Reversibility
Explanation:
Because if you don't progress then you do the opposite, you reverse.
Sorry if my explanation is confusing it made sense in my head i just didn't know how to put it.
hope this help. ;)
Answer:
A. Reversibility
Explanation:
What is the net force for this? (please don't forget it's direction and magnitude)
Answer:
Explanation:
As the sum of the two right directed forces match exactly the left directed force, the only unbalanced force, and thus the net force, is the upward 25 N force.
A farmhand pushes a 26-kg bale of hay 3.9 m across the floor of a barn. If she exerts a horizontal force of 88 N on the hay, how much work has she done
Answer:
W = 343.2 J
Explanation:
Given that,
Mass of bale of hay = 26 kg
Horizontal force exerted = 88 N
Distance moved, d = 3.9 m
Work done, W = Fd
Put all the values,
W = 88 N × 3.9 m
= 343.2 J
So, the work done is 343.2 J.
If a student were to measure the ball's speed at each position above, at which position would
the ball be traveling the fastest?
A
B
C
D
The image only shows the path of the ball and its different positions at different times during the flight.
To determine the speed of the ball at each position, additional information such as the time elapsed between each position and the distance traveled would be needed. Only with this information would it be possible to calculate the speed at each position and determine where the ball is traveling the fastest.
Speed is the measure of the distance traveled by an object over a specified period. It is a scalar quantity and is typically expressed in units of distance per unit of time, such as miles per hour, kilometers per hour, or meters per second. Speed can be calculated as the ratio of the distance covered by an object to the time taken to cover that distance. It is an important concept in physics and plays a critical role in determining the motion of objects, particularly in the field of mechanics.
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Variable Radius Mass (kg) Period (s) 3 2 Radius (m) 1 2 3 3 Tangential speed (m/s) 3.14 3.14 3.14 3.14 3.14 4 Centripetal Force (N) 29.6 14.8 9.87 7.40 5.92 6 www 8 4 10 5 Analysis: Force vs Circle Radius 1. Looking at the Variable Radius table, what can you conclude about the relationship between the centripetal force and radius? What is the functional form of this relationship?
We can infer from the Variable Radius table that as the radius grows, the centripetal force decreases.
The centripetal force and radius have an inverse connection, which means that as one quantity changes, the other changes proportionally.
The mathematical formula for the functional form of this connection is F = k/r, where F is the centripetal force, k is a proportionality constant, and r is the radius.
The centripetal force equation, which describes this relationship, is a key idea in comprehending circular motion.
The Variable Radius table reveals that there is an inverse proportionality between the centripetal force and radius. The centripetal force reduces as the radius grows, and vice versa.
The centripetal force equation, F = k/r, where F is the centripetal force, k is a proportionality constant, and r is the radius, describes this relationship.
The travel of planets around the sun or the movement of cars around a curve are only two examples of how comprehending this relationship is crucial to understanding circular motion.
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What do you mean by Secondary colours?
For example
If you mix up red and yellow you will get orange colourWhich shows the correct steps in the formation of an ionic bond between these atoms?
A magnesium atom accepts six electrons from the fluorine atoms → Each fluorine atom donates three of the electrons → The magnesium atom becomes a -2 ion → Each fluorine atom becomes a +1 ion
A magnesium atom donates two electrons to the fluorine atoms → Each fluorine atom accepts one of the electrons → The magnesium atom becomes a -2 ion → Each fluorine atom becomes a +1 ion
A magnesium atom accepts two electrons from the fluorine atoms → Each fluorine atom donates one of the electrons → The magnesium atom becomes a -2 ion → Each fluorine atom becomes a +1 ion
A magnesium atom donates two electrons to the fluorine atoms → Each fluorine atom accepts one of the electrons → The magnesium atom becomes a +2 ion → Each fluorine atom becomes a -1 ion
Answer:
D) A magnesium atom donates two electrons to the fluorine atoms → Each fluorine atom accepts one of the electrons → The magnesium atom becomes a +2 ion → Each fluorine atom becomes a -1 ion
Explanation:
sorry if its a bit late
The correct steps in the formation of an ionic bond are A magnesium atom donates two electrons to the fluorine atoms → Each fluorine atom accepts one of the electrons → The magnesium atom becomes a +2 ion. The correct option is D.
What are ionic bonds?The electrical attraction between two ions with opposing charges creates an ionic bond, also known as an electrovalent bond, in a chemical molecule.
Ionic compounds are created by ionic bonds, while covalent bonds create covalent compounds. Ionic bonds are created by a complete transfer of electrons, whereas covalent bonds are created by sharing electrons.
Covalent bonds are weaker than ionic ones. Ionic compounds have higher melting and boiling points.
Therefore, the correct option is D.
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What is the Kinetic Energy of a pie with a mass of 5 kg travelling at a velocity of 9m/s towards your face ?
Answer:
K = 202.5 J
Explanation:
Given that,
Mass of pie is 5 kg
Velocity of pie is 9 m/s
We need to find the kinetic energy of a pie. The kinetic energy of an object is due to its motion. It can be given by the formula as follows :
\(K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 5\times (9)^2\\\\K=202.5\ J\)
So, the kinetic energy of the pie is 202.5 J.
The distance to the other planets in the Solar System from the Earth depends on where they are in their orbit. The closest that Mars gets to the Earth is 0.5 AU. At this time it is observed to have an angular diameter of 18 arcseconds. The furthest it gets from Earth is 2.5 AU. What would its angular diameter be for this observation
Answer:
3.6 arcsec
Explanation:
angular diameter = diameter / distance
diameter is constant
so angular diameter ∝ 1 / distance
angular diameter = k / distance
For first case ,
18 = k / .5
for second case let angular diameter be D .
D = k / 2.5
dividing ,
D / 18 = .5 / 2.5 = 1 / 5
D = 18 / 5 = 3.6 arcsec
3.6 arcsec is the answer .
A metal bar has a volume of 32 cm3. The mass of the bar is 256 g. What is the density of the metal? A. 290 g/cm3 6 B. 8,200 g/cm C. 8.0 g/cm3 O D. 220 g/cm
The density of the metal is ρ = 8.0g/cm³.
Why is density important?The measure of material how densely it is packed together is called density. As the mass per unit volume, it has that definition. Symbol for density: D or Formula for Density: When is the density, m is the object's mass, and V is its volume, the equation is: = m/V.
Because it enables us to predict which compounds will float and which will sink in a liquid, density is a crucial notion. As long as an object's density is lower than the liquid's density, it will often float.
Equation :To the given equation we have :
mass of the bar = 256g
volume of metal bar = 32cm³
So according to the formula of density
ρ = m/V
So, putting values
ρ = 256g /32cm³
ρ = 8.0g/cm³
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(a) if a long rope is hung from a ceiling and waves are sent up the rope from its lower end, why does the speed of the waves change as they ascend? (b) does the sp
In response to questions (a) and (b), I will say that wave speed each component of the rope must help to sustain the rope's weight, and as a result, tension will tend to rise with height.
What impact does the rope's tension have on the waves?A wave's speed increases as a string's tension does, increasing the frequency (for a given length). By applying pressure in various locations, you may alter the string's length, the standing wave's wavelength, and consequently, its frequency.
If the rope does not expand, take note that the increase is linear. Thus, when height rises, the wave speed v= √ T/μ
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Question:-
(a) If a long rope is hung from a ceiling and waves are sent up the rope from its lower end, why does the speed of the waves change as they ascend? (b) Does the speed of the ascending waves increase or decrease? Explain.
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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