density is never uniform even when the cross sectional area is uniform and the potential difference across the conductor is maintained

Answer:

speed =distance /time

speed =4/1

speed 4m/s

The final volume is therefore equal to 3.0 mm3 * (1 atm) / (4 atm) = 0.75 mm3.

The volume of an ideal gas is proportional to its temperature and inversely proportional to its pressure. Since the temperature of the air in the bubble stays the same, the ratio of the initial pressure to the final pressure is equal to the ratio of the final volume to the initial volume.

Since the pressure inside the bubble at a depth of 4 times atmospheric pressure is 4 times atmospheric pressure, the pressure inside the bubble at the surface is equal to atmospheric pressure.

The final volume is therefore equal to 3.0 mm3 * (1 atm) / (4 atm) = 0.75 mm3.

Learn more on ideal gas here https://brainly.com/question/20348074

#SPJ1

Explanation:

Answer:

the stone hits the gound with a speed of  20.7 m/s

Explanation:

Becuase gravity is constant we know that the initial upward velocity will be equal to the downward velocity when the stone has returned to its intal location.

Answer:

distance(d)=.....

time(t)=....

speed =?

we know that

speed =distance /time

Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.

Explanation:

Consult the attached free body diagram. The only forces doing work on the wagon are the frictional force opposing the wagon's motion and the horizontal component of the applied force.

By Newton's second law, the net vertical force is

• ∑ F [v] = n + (80.0 N) sin(30.0°) - mg = 0

where a is the acceleration of the wagon.

Solve for n (the magnitude of the normal force) :

n = (10.0 kg) g - (80.0 N) sin(30.0°) = 58.0 N

Then

f = 0.500 (58.0 N) = 29.0 N

Meanwhile, the horizontal component of the applied force has magnitude

(80.0 N) cos(30.0°) ≈ 69.3 N

Now calculate the work done by either force.

• friction: -(29.0 N) (10.0 m) = -290. J

• pull: (69.3 N) (10.0 m) = 693 J

Answer:

A lunar eclipse occurs when the Moon enters the Earth’s shadow. A solar eclipse occurs when the Moon’s shadow falls on the Earth. They do not happen every month because the Earth’s orbit around the sun is not in the same plane as the Moon’s orbit around the Earth.

Explanation:

Answer:

fem = 7.58 10⁻⁵ V

Explanation:

For this exercise we use Faraday's law

          fem =   \(- \frac{d \Phi _B}{dt}\)

the magnetic flux is

          Ф_B = B. A = B A cos θ

Tje bold are vectros.  Suppose the case where the normal to the surface of the red blood cell is parallel to the field, therefore the angle is zero and the cos 0 = 1

The red blood cell area is

          A =π r²

indicate that the diameter is r = 8.00 mm = 8.00 10⁻³ m

the magnetic field has a frequency of f=60 Hz, and B₀ = 1.00 10⁻³T,  therefore we can write it

          B = B₀ sin (wt) = B₀ sin( 2π f t)

we substitute

           fem = - A dB / dt

           fem = - A B₀  \(\frac{ d (sin ( 2\pi f t)}{dt}\)

           fem = - π r² Bo (2πf  cos 2πft)

the maximum electromotive force occurs when the function is ±1

           fem = 2 π² r² B₀ f

let's calculate

           fem = 2π²  (8.00 10⁻³)²  1.00 10⁻³ 60

           fem = 7.58 10⁻⁵ V

Explanation:

Resistors in circuits can either be connected in series or in parallel.

For a series connected resistors, the same current flows through the resistors while different voltages is passed across them. The formula for calculating effective resistances in a circuit is expressed as

\(R_T = R_1+R_2+R_3...+R_n\) where R1, R2, R3 etc. are the resistances connected in series.

The effective resistances for series connected resistors is the sum of the individual resistors

For a parallel connected resistors, different current flows through the resistors while same voltage is passed across them. The formula for calculating effective resistances in a circuit is expressed as:

\(\frac{1}{R_T} = \frac{1}{R_1} +\frac{1}{R_2} +\frac{1}{R_3} +...\frac{1}{R_n}\)

The effective resistances for parallel connected resistors is the sum of the reciprocal of the individual resistors

Answer:

B. 2.3 x 10⁶

Explanation:

To calculate scientific notation for the number 2,300,000, we have to follow this notation

Step 1 :

To find a we have to write the non-zero digits placing a decimal after the first non-zero digit.

Step 2 :

Now, to find b count how many numbers of digits are there to the right of the decimal.

Hence, there are 6 digits to the right of the decimal.

Step 3 :

Since, we had found the value of a and b, we can now reconstruct the number into scientific notation.

a = 2.3

b = 6

Therefore, option b is correct.

Answer:

The correct option is (a).

Explanation:

Given that,

Radius of a horizontal circle, r = 80 cm = 0.8 m

Angular velocity, ω = 5 rev/minute = 0.523 rad/s

We need to find the magnitude of its centripetal acceleration. The formula that is used to find the centripetal acceleration is given by :

\(a=\omega^2 r\\\\a=(0.523)^2\times 0.8\\\\a=0.218\ m/s^2\)

or

\(a=0.22\ m/s^2\)

So, the magnitude of its acceleration is \(0.22\ m/s^2\).

Answer:

mass

Explanation:

Answer:

Mass wind water ice gravity

Let \(u\) be the initial velocity of the soccer ball at an angle of inclination of \(\theta_0\) with the positive x-axis.

Given that:

\(\theta_0=45^{\circ}\)

The horizontal distance covered by the projectile=20 m

Time of flight, \(t_f=2\) seconds

Acceleration due to gravity, \(g= 10 m/s^2\) downward.

As "north" and "up" as the positive x ‑ and y ‑directions, respectively.

So, \(g= -10 m/s^2\)

As the acceleration due to gravity is in the vertical direction, so the horizontal component of the initial velocity remains unchanged.

The x-component of the initial velocity, \(u_x=u\cos\theta_0\).

The horizontal distance covered by the projectile \(= u_x\times t_f\)

\(\Rightarrow u_x\times t_f=20\)

\(\Rightarrow u_x\times 2=20\)

\(\Rightarrow u_x=10\) m/s

So, the horizontal component of the velocity is 10 m/s which is constant and the graph has been shown in the figure (i).

Now,  \(u\cos(45^{\circ})=10\) [as \(u_x=u\cos\theta_0\)]

\(\Rightarrow u=10\sqrt{2}\) m/s.

The vertical component of the initial velocity,

\(u_y= u\sin\theta_0\)

\(\Rightarrow u_y=10\sqrt{2}\sin(45^{\circ})\)

\(\Rightarrow u_y=10\) m/s

Let v be the vertical component of the velocity at any time instant t.

From the equation of motion,

\(v=u+at\)

where u: initial velocity, v: final velocity, a: constant acceleration, and t: time taken to change the velocity from u to v.

In this case, we have \(u=u_y, a= -10 m/s^2\).

So at any time instant, t.

\(v=u_y+(-10)t\)

\(\Rightarrow v=10-10t\)

The vertical component of the velocity, v, is the function of time and related as \(v=10-10t\).

This is a linear equation.

At 2 second, the vertical component of the velocity

v=10-10x2=-10 m/s.

The graph has been shown in figure (ii).

Answer:

The more the mass, the more the gravity. The more the distance the less the gravity.

Explanation:

I just learned about it on E_d_g_e_n_u_i_t_y

Answer:

it is double the temperature change of iron

Answer: NO, there are many examples of non-conservative forces.

Explanation: Conservatives forces are special forces whose work is zero in a closed path.

The impulses and changes in momentum are identical because equal forces are applied over equal periods of time.

The momenta of the two carts are identical since they both begin at rest and experience equal changes in momentum. We are aware that force is the same as mass multiplied by acceleration. Due to the initial resting state of both carts, u = 0 m/s, and the plastic cart moves 1 m. Newton's second law states that when the same force is applied to the two carts, the plastic cart will have more final momentum than the lead cart because of the momentum principle. Newton's third law states that every object feels the same force for the same length of time, which results in the same impulse and consequent change in momentum.

To learn more about momentum click here https://brainly.com/question/29113044

#SPJ4

Due to equivalent forces being delivered over equal times, the impulses and changes in momentum are identical.

The acceleration is determined by dividing the net force by the mass. An object's acceleration doubles if the net force exerted on it also doubles. Increased mass will result in a halving of acceleration.

Second Law of Motion: Force In accordance with his second law, a force is defined as the change in momentum (mass times velocity) per change in time. The definition of momentum is the product of the mass m and the velocity V of an object.

To know more about momentum visit:-

https://brainly.com/question/24030570

#SPJ4

Work is referred to as the displacement of an object when a force (push or pull) is applied to it while energy is referred to as the capacity to do the work. It exists in various forms like potential, kinetic, chemical, thermal, nuclear, electrical energy and so on. Power is the work done per unit of time.

power and energy are the same.
Work is usualy doing a task that gets rid of said energy.

For a disk of mass m and radius r that is rolling without slipping, is B. Its kinetic energy of translation is the same as its kinetic energy of rotation.

When a disk is rolling without slipping, it means that the point of contact with the ground does not slide. In such a scenario, the total kinetic energy (K.E.) can be divided into two components - the translational kinetic energy (K.E. translation) and the rotational kinetic energy (K.E. rotation).

The translational kinetic energy of the disk is given by the equation: K.E. translation = (1/2)mv^2, where m is the mass and v is the linear velocity of the center of mass of the disk.

The rotational kinetic energy of the disk is given by the equation: K.E. rotation = (1/2)Iω^2, where I is the moment of inertia and ω is the angular velocity of the disk. For a disk, the moment of inertia is (1/2)mr^2, where r is the radius of the disk.

Now, for a rolling disk without slipping, the relationship between linear velocity and angular velocity is v = ωr. Substituting this into the equation for K.E. rotation, we get K.E. rotation = (1/2)((1/2)mr^2)(v/r)^2 = (1/2)mv^2.

Comparing both kinetic energies, we see that K.E. translation = K.E. rotation. Therefore, the kinetic energy of translation is the same as the kinetic energy of rotation for a disk rolling without slipping. Therefore the correct option is B

Know more about kinetic energy here:

https://brainly.com/question/30337295

#SPJ11  

A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.

To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).

The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:

E_initial = KE_initial + PE_initial

The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:

E_final = KE_final + PE_final

The nonconservative work done on the boy is equal to the change in mechanical energy:

Work_nonconservative = E_final - E_initial

Let's calculate each term:

KE_initial = (1/2) * m * v_initial^2

= (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = m * g * h_initial

= 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * m * v_final^2

= (1/2) * 66.1 kg * (8.51 m/s)^2

PE_final = m * g * h_final

= 66.1 kg * 9.8 m/s^2 * 0

Since the boy ends at ground level, the final potential energy is zero.

Substituting the values into the equation for nonconservative work:

Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)

Simplifying:

Work_nonconservative = KE_final - KE_initial - PE_initial

Calculating the values:

KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2

Substituting the values:

Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]

Calculating the result:

Work_nonconservative ≈ -42.7 kJ

Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.

For more such questions on nonconservative work done, click on:

https://brainly.com/question/19988788

#SPJ8

Answer:

The mass will stay the same if the bag stays sealed.

Explanation:

Answer:

PE = 137.2931 J

Explanation:

PE = 137.2931 J

Below are the required answers and explanations for each of the scenarios listed.

1. A machine that pulls all thermal energy out of a refrigerated space: This violates the second law of thermodynamics. This is because the second law of thermodynamics states that no heat engine can have an efficiency of 100 percent, and no heat transfer can occur from a colder to a warmer object without external work being done.

2. A machine that can pull 1000J of heat out of a refrigerated space and into a warmer space without external work: This violates the second law of thermodynamics. The second law of thermodynamics states that no heat transfer can occur from a colder to a warmer object without external work being done.

3. A machine that can turn 1000J of heat directly into 1000J of electricity: This does not violate any of the laws of thermodynamics.

4. A machine that can create 1000J of heat from 100J of electricity: This does not violate any of the laws of thermodynamics.

5. A machine that can pull 1000J of heat out of a refrigerated space and put 1500J of heat into a warmer space if it uses 500J of external work: This does not violate any of the laws of thermodynamics.

a) Option 2 is correct answer.

b) Option  2 is correct answer.

c) Option 4 is correct answer.

d) Option 4 is correct answer

e) Option 4 is correct answer.

For more question  thermodynamics

https://brainly.com/question/13059309

#SPJ8

A

Explanation: sorry sir but its required step up transformer for high voltage not step

386.59 J  mechanical energy is lost due to friction acting on the runner and he slide 37.35 cm .

The type of materials being used affects the frictional force. As an illustration, rubber on tarmac has a high coefficient of friction, which stops the materials from moving past one another as easily as ice on steel, that has a lower coefficient of friction.

Kinetic energy of the runner

= 1/2 m v²

= .5 x 71 x 3.3²

= 386.59 J

The runner's ultimate kinetic energy is zero.

mechanical energy loss

= 386.59 J

The frictional force that is at work is what causes this mechanical energy loss.

b )

Let the sliding distance be.

due to frictional force, slowing down

= μmg/m

.7 x 71 x 9.8 / 71

a = - 6.86 m s⁻¹

v² = u² - 2 a s

0 = 3.3² - 2x6.86 s

s = 3.3² / 2x6.86

= .3735 m

37.35 cm

To know more about coefficient of friction visit:

https://brainly.com/question/8139435

#SPJ4

According to research, development is always towards complexity.

The term research has to do with the process that we have to go through to obtain new knowledge or to confirm a piece of information. Let us say that we have some disconnected pieces of evidence that tend to point towards a particular fact, we would need to use the process of research to establish the truth in the research.

Now we can see that there is a movement towards the complexity of organisms at each particular level in the developmental process. We can then conclude that according to research, development is always towards complexity.

Learn more about research:https://brainly.com/question/14693819

#SPJ1