degeneracy pressure results from the uncertainty principle. general relativity. special relativity. the exclusion principle.

Answers

Answer 1

The exclusion principle, is the degeneracy pressure, results from the uncertainty principle. Correct answer: letter C.

Since, the pressure that arises when the electrons in an atom occupy all the available quantum states, which makes it difficult for additional electrons to enter the atom.

What is the difference between the exclusion principle and the uncertainty principle?

The exclusion principle and the uncertainty principle are two distinct principles.

The exclusion principle states that no two electrons in an atom can have the same set of quantum numbers, while the uncertainty principle states that the position and momentum of a particle cannot both be known with precision.

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Related Questions

The density of 2 kilograms of iron on Earth's surface is
A. Zero.
B. The same on the moon.
C. Less on the moon.
D. Greater on the moon.
E. None of them

Answers

Answer:

B. The same on the moon.

Explanation:

The density of an object is the ratio of the mass contained by the object to the volume occupied by that mass.

\(Density = \frac{Mass}{Volume}\)

When the object is taken from the earth to anywhere in the universe, its mass remains constant. The dimensions of the object and hence its volume also remains constant anywhere in the universe.

Therefore, the density of the object will also remain the same as it depends upon the mass and the volume of the object.

So, the correct option is:

B. The same on the moon.

jack runs a company in the US He exchanges goods and services with parties and is from other countries which t activity is jack
Reset
Next

Answers

Since he runs a company in the US He exchanges goods and services with parties, Jack is engaged in international trade.

What is international trade?

International trade is the exchange of goods and services between countries. It is a major driver of economic growth and prosperity. Jack's company can benefit from international trade in a number of ways. First, it can access new markets and customers. Second, it can source lower-cost inputs from other countries. Third, it can diversify its risk by selling to customers in multiple countries.

However, Jack's company also faces some challenges when engaging in international trade. First, it must deal with different languages, cultures, and legal systems. Second, it must comply with import and export regulations. Third, it must manage the risk of currency fluctuations.

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Three 40-Ω lightbulbs and three 80-Ω lightbulbs are connected in series.(a) What is the total resistance?(b) What would be their resistance if all six were wired in parallel?

Answers

(a)

In order to find the series total resistance, we need to add all resistances:

\(R_{eq}=R_1+R_2+R_3+R_4+R_5+R_6\)

If three resistances are 40 ohms and three are 80 ohms, we have:

\(\begin{gathered} R_{eq}=40+40+40+80+80+80\\ \\ R_{eq}=360\text{ ohms} \end{gathered}\)

(b)

Now, since the resistances are in parallel, we need to use the expression below:

\(\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+\frac{1}{R_4}+\frac{1}{R_5}+\frac{1}{R_6}\)

So we have:

\(\begin{gathered} \frac{1}{R_{eq}}=\frac{1}{40}+\frac{1}{40}+\frac{1}{40}+\frac{1}{80}+\frac{1}{80}+\frac{1}{80}\\ \\ \frac{1}{R_{eq}}=\frac{3}{40}+\frac{3}{80}\\ \\ \frac{1}{R_{eq}}=\frac{6}{80}+\frac{3}{80}\\ \\ \frac{1}{R_{eq}}=\frac{9}{80}\\ \\ R_{eq}=\frac{80}{9}\text{ ohms} \end{gathered}\)

A special spring is constructed in which the restoring force is in the opposite direction to the displacement but is proportional to the cube of the displacement; i.e., F= -kx^3
this spring is placed on a horizontal frictionless surface. One end of the spring is fixed, and the other end is fastened to a mass M. The mass is moved so that the spring is stretched a distance A and then released. Determine each of the following in terms of k, A, and M
a) The potential energy in the spring at the instant the mass is released
b) the maximum speed of the mass
c) The displacement of the mass at the point where the potential energy of the spring and the kinetic energy of the mass are equal

Answers

Answer:

Explanation:

a ) Restoring force in special spring F = k x³

let it is stretched by length l and it is further stretched by dl .

work done on spring in stretching by dl

= F dl

= k l³ dl

work done in stretching by A

= ∫k l³ dl between limit 0 to A

= k [ l⁴ / 4 ] between limit 0 to A

= k A⁴ / 4 ;

b )

Let v be the maximum speed attained ,

kinetic energy of mass = potential energy of spring

1/2 M v² = k A⁴ / 4

v² = kA⁴ / 2

v = A² √( k/2 )

c ) Let the required displacement be d .

potential energy = k d⁴ / 4

at displacement d , potential energy and kinetic energy are equal so potential energy = 1 /2 of total potential energy = 1/2 x k A⁴ / 4

= k A⁴ / 8

So

k A⁴ / 8  = k d⁴ / 4

\(d = A\times ( \frac{1}{2} )^\frac{1}{4}\)

The earth rotates on its axis with a period of 24 hours. What is the frequency in Hertz?

Answers

Answer:

The answer is 0.042 Hz (rounded)

or 0.0417 Hz

Explanation:

Hope it helps

Answer:

The answer is 0.041Hz

Explanation:

The answer is 0.041Hz

I guess

a plane wall is 250mm thick and it's wall area is 4.5m^2. if the thermal conductivity is 9.35w/m°c and surface temperature are steady at 150°c and 40°c. calculate the heat flow across the plane wall and the temperature gradient in the flow direction​

Answers

The temperature gradient in the flow of direction is 294525 W.

What is Temperature gradient?

A temperature gradient is the gradual variance in temperature with distance. The slope of the gradient is consistent within a material. A gradient is established anytime two materials at different temperatures are in physical contact with each other.

Q= T/( L/ KA)

Q= ( 1500 − 450) / 0.15 / 9.35v * 4.35)

   = 294525 W

Units of measure of temperature gradients are degrees per unit distance, such as °F per inch or °C per meter.

Many temperature gradients exist naturally, while others are created. The largest temperature gradient on Earth is the Earth itself. Q= T/Ka.

Therefore, The temperature gradient in the flow of direction is 294525 W.

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how will you use the information you've learned from dan ariely's talk to inform your future decisions?

Answers

One important takeaway from Dan Ariely's talk is that our decision-making processes are frequently irrational and influenced by variables outside of our conscious consciousness.

Social norms, emotional states, and cognitive biases, for example, can all influence our choices. As a result, one method to put this knowledge to use is to become more aware of these influences and actively consider them when making decisions.

This may entail devoting more time to decision-making, seeking out diverse views, and being aware of our own biases and tendencies.

Another key takeaway from the talk is the significance of considering the long-term consequences of our choices rather than focusing solely on short-term gains or losses.

This may entail weighing the risks and benefits of various options, as well as considering the effect of decisions on others as well as ourselves.

Overall, the information presented by Dan Ariely can be used to make more thoughtful and informed decisions by becoming more aware of our own biases and tendencies, considering diverse viewpoints, and thinking critically about the potential repercussions of our decisions.

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The purpose of the chiller is to
A. remove heat from the air.
B. cool conditioned air.
C. distribute the refrigerant.
D. cool warmed water.

Answers

The purpose of the chiller is to remove heat from the air and is therefore denoted as option A.

What is a Chiller?

This is a type of device which is referred to as type of a cooling system that removes heat by circulating heat-absorbing a refrigerant through a series of mechanisms through which the heat is released.

The result of this process is that the heat in the air is removed as a result of the refrigerant being adequately circulated and then the environment becomes cooler and is therefore the reason why it was chosen as the correct choice.

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what is a shargaff rule

Answers

According to Chargaff's rule, the amounts of adenine (A), thymine (T), and guanine (G) in the DNA molecule are equal to each other. The amounts of cytosine (C) and guanine (G) are also equal.

Who is Chargaff ?

Erwin Chargaff was a biochemist, author, Bucovinian Jew who immigrated to America during the Nazi era, and professor of biochemistry at Columbia University's medical school.

Chargaff found patterns among the four bases, or chemical building blocks, of DNA, which are directly related to DNA's function as the genetic material of living things.

He was born in Austria-Hungary. Heraclitean Fire: Sketches from a Life Before Nature, an autobiography he penned, received positive reviews.

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A person walks first at a constant speed of 5.00 m.s-1
along a straight line from point A to
point B and then back along the line from B to A at a constant speed of 3.00 m.s-1
.
(a) Calculate her average speed over the entire trip.

Answers

The average speed of the person over the entire trip is 3.75 m/s.

Average speed of the person

Average speed = total distance/total time

Average speed = (d + d)/(d/Va + d/Vb)

where;

d is the distance in a single tripVa is speed from point AVb is the speed from point B

Average speed = (2Vavb)/(Va + Vb)

Average speed = (2 x 5 x 3)/(5 + 3)

Average speed = 3.75 m/s

Thus, the average speed of the person over the entire trip is 3.75 m/s.

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Plz help w answer 1:/ confused ash

Plz help w answer 1:/ confused ash

Answers

Answer:

I would say d I had the same question yesterday and I got it correct so hope that helps

Yeah that’s the same question I was asking
Plz help w answer 1:/ confused ash

Object 1 with mass 1=3.25 kg
is held in place on an inclined plane that makes an angle
of 40.0∘
with the horizontal. The coefficient of kinetic friction between the plane and the object is 0.535.
Object 2 with mass 2=4.75 kg
is connected to object 1 with a massless string over a massless, frictionless pulley. The objects are then released.
Calculate the magnitude
of the initial acceleration.
Calculate the magnitude
of the tension in the string once the objects are released.

Answers

The magnitude of the initial acceleration of the object is 4.2 m/s².

The tension in the string once the object starts moving is 13.65 N.

What is the  magnitude of the initial acceleration?

The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;

F(net) = ma

m₂g - μm₁g cosθ = a(m₁ + m₂)

where;

m₁ and m₂ are the masses of the blocksg is acceleration due to gravityμ is coefficient of frictionθ is the angle of inclinationa is the acceleration

(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)

33.5 = 8a

a = 33.5/8

a = 4.2 m/s²

The tension in the string once the object starts moving is calculated as;

T = m₁a

T = 3.25 x 4.2

T = 13.65 N

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a cheetah can run at 30 m/s but only for a but 12 s. how far will it run in that time

Answers

ANSWER: 360metres

EXPLANATION:

Distance= speed × time

=30×12

= 360metres

Explanation:speed=30m/s time=12 sec                                                                                             now,distance=speed x time taken                                                                                                                                   or,distance=30 x 12                                                                                                                                                                                                                                                                         Therefore,distance=360m

A lab cart flies off the end of a track on a lab table with a horizontal velocity of 2.08 m/s. If it lands 0.96 meters from the edge of the table, how tall is the table?
A)0.5 m
B)6.0 m
C)1.2 m
D)2.2 m

Answers

Answer:

Option C. 1.2 m

Explanation:

The following data were obtained from the question:

horizontal velocity (u) = 2.08 m/s

Horizontal distance (s) = 0.96 m

Height (h) of the table =?

Next, we shall determine the time taken for the lab cart to get to the ground. This can be obtained as follow:

horizontal velocity (u) = 2.08 m/s

Horizontal distance (s) = 0.96 m

Time (t) =?

s = ut

0.96 = 2.08 × t

Divide both side by 2.08

t = 0.96 / 2.08

t = 0.5 s

Finally, we shall determine the height of the table as illustrated below:

Time (t) = 0.5 s

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) of the table =?

h = ½gt²

h = ½× 9.8 × 0.5²

h = 4.9 × 0.25

h = 1.2 m

Thus, the height of the table is 1.2 m

Answer:

C) 1.2 m

Explanation:

Horizontal velocity = 2.08 m/s

Time taken to reach the ground :

t = 0.96 m/2.08m/s = 0.46 s

Strait down motion :

vi = 0

=> h = 4.9t^2 (a= 9.8 m/s^2)

= 4.9m/s^2*(0.46s)^2 = 1.04 m

The table is 1 m tall

How long would it take Sputnik to travel 288,320 miles?

Answers

Answer:

To calculate the time taken by Sputnik to travel 288320 miles, you need to divide the distance by its speed, i.e. 288320 (miles) / 5 (miles/second) =  57664 (second)

Explanation:

We know that,

s = d/t

where s ⇒ speed

d ⇒ distance

t ⇒ time

Now as per the question,

distance to travel, d = 288320 miles

speed of Sputnik sattelite, s = 5 miles/second

Therefore,

5 (miles/second) = 288320 (miles) / t (second)

t = 288320/5 [(miles / (miles/second)]

t= 57664 (second)

Therefore, the Sputnik satellite will take 57664 seconds to travel 288320 miles.

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A body is thrown up into the air takes a time of 4s to reach the height. What is the velocity with which the body was thrown up.(g=10ms2)​

Answers

Answer:

40m/s

Explanation:

V= u + at

v= 0

a= -10

t= 4

0= u -40

u= 40m/s

just trial!!!!!!!

(Ic) Asmall ball carrying a charge of -3.0x10-12C experiences an east ward force of 8.0×10 N due to its charge when it is suspended at a certain point in space. What is the magnitude and direction of Eat that point? ​

Answers

The magnitude of the electric field is \(2.67*10^6 N/C\), and its direction is westward.

To determine the magnitude and direction of the electric field at the point where the small ball is suspended, we can use the formula for the electric field:

Electric field (E) = Force (F) / Charge (q)

Given:

Charge of the ball (q) = \(-3.0*10^{(-12)} C\)

Force experienced by the ball (F) = \(8.0*10^{(-6)}\) N (eastward)

Plugging in the values into the formula:

E = F / q

E = \((8.0*10^{(-6) }N) / (-3.0*10^{(-12)} C)\)

Let's calculate the electric field:

E = -\(2.67*10^6 N/C\)

The magnitude of the electric field is\(2.67*10^6 N/C\). The negative sign indicates that the electric field is pointing in the opposite direction to the force experienced by the ball, which in this case is westward.

Therefore, the magnitude of the electric field is \(2.67*10^6 N/C\), and its direction is westward.

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define density in thermodynamics​

Answers

Answer:

total mass (m) of that substance divided by the total volume (V) occupied by that substances

Which of the schematic diagrams (shown above) is correct?
(A, B, C, D)

Which of the schematic diagrams (shown above) is correct? (A, B, C, D)

Answers

Answer:

Explanation:

it’s really simple because if you are aware of like this ohms diagram in triangle form with V(voltage) on top, I(currenct) on the left and R (resistance) on the right

Visual: is in the photo

and what i used to do was if I’m trying to find V I’d cover it up and know since now I and R are next to each other you multiply like V=IxR

And repeat

Trying to find R just cover up R and now V is on top of I so now you divide

R=V/I


hope this helps you out even if only a little

Which of the schematic diagrams (shown above) is correct? (A, B, C, D)

What are some of the forces affecting rock climbers?​

Answers

Answer:

Gravitational force

Explanation:

Gravitational force is obviously one of the biggest obstacles in climbing. You are essentially going against this very strong force to pull your body mass up the beautiful terrain. Gravity is defined as the force of attraction between all masses in the universe, gravity is what allows the sport of climbing.

Answer:

Gravity, low oxygen, and rock slides.

Explanation:

Some rock climbers train for years but are hardly prepared for some situations.

What is the shortest wavelength of light that can be emitted by a hydrogen atom that has an initial configuration of 8p^1? Give your answer accurate to three significant figures.​

Answers

The Bohr model of the hydrogen atom allows us to find that the transition with the shortest wavelength up to the level n = 8, has a response is:

     λ = 92.4 nm

 

The spectrum of the hydrogen atom is explained by the Borhr model, where the energy of the atom is given by

              \(E_n = - \frac{13.606}{n^2} \ [eV]\)

Where Eₙ is the energy, n is an integer, the constant is the energy of the base state of hydrogen expressed in electron-volts.

It's using Planck's equation and that the light speed is related to the frequency, we can find an expression for the transition between two levels.

              E = h f

              c = λ f                  

              E = \(\frac{h c}{\lambda }\)

              ΔE = \(E_{n' } - E_n\)            n ’> n

Where  h is the Plank constnat, c the light  speed and λ the wavelength              

It's combining the equations we find

             \(\frac{1}{\lambda} = R_H ( \ \frac{1}{n_{i}^2 } - \frac{1}{n_f^2} \ )\)

where λ is the transition wavelength, \(R_H\) is the Rydberg constant

(\(R_H\) = 1.0997 10⁷ m⁻¹), n_f and n_i are the final and initial levels of the electron.

In this case, the transition is requested up to the level n = 8, the sublevel p does not influence the value of the transition for atoms with a single electron such as hydrogen.

To find which is the initial nevel we use that they ask for the shortest wavelength, for which the electron must leave the level; n_i = 1

              \(\frac{1}{\lambda}\)  = 1.0997 10⁷ ( \(\frac{1}{1^2 } - \frac{1}{8^2 }\) )

               \(\frac{1}{\lambda}\)  = 1.082517 10⁷

               λ  = 0.923772 10⁻⁷ m

               λ  = 9.23772 10⁻⁸ m

It is very common to give this wavelength in nanometers  let's reduce the magnitude and use the criterion of three significant figures indicated

              λ  = 9.23772 10⁻⁸ m (\(\frac{10^9 nm}{1m}\))

              λ = 92.4 nm

In conclusion, using the Bohr model of the hydrogen atom, we can find that the transition with the shortest wavelength for the novel n = 8, has a response of 92.4 nm

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Three fish of equal volume are swimming in a fish tank. They all have the same volume, but A has the greatest mass, B has less, and fish C has even less mass. (The differences are significant.)
The fish are swimming as shown. At that instant, how do the buoyant forces exerted by the water on the three fish rank?
A. BFB > BFA = BFC
B. BFB = BFA > BFC
C. BFB > BFA > BFC
D. BFA = BFB = BFC
E. Some other ranking
If the fish stopped swimming, fish B would remain right where it is shown.
What would happen to fish A and C? Put all the correct answers. If none of these would happen, put N.
A. Fish C would be pushed down to the bottom by the water above it.
B. Fish C would float to the top.
C. Fish A would be pushed to the top by the water below it.
D. Fish A would sink to the bottom.

Answers

Answer:

Fish C would float to the top & Fish A would sink to the bottom

Explanation:

A would sink to the bottom.Since B just remains where it is shown, its mass must balance the buoyant force and its weight must be equal to the weight of the water displaced. Since A is heavier, its weight will be greater than its buoyant force, it will sink. Since C is lighter, its buoyant force will be greater thanits weight and it will float to the top.

In a reading assignment, the main headings and key concepts are useful for which of
the following?
0000
defining vocabulary words
finding the general location of information in reading assignments
giving exact answers to exam questions
none of the above

Answers

The main headings and key concepts are useful for finding the general location of information in reading assignments. They provide a quick overview of the content and organization of the text, which can help readers to locate specific information more easily. However, they may not always be sufficient for defining vocabulary words or giving exact answers to exam questions, as these tasks often require more detailed and specific information from the text.

Assume you are driving a car at a constant speed of 78.0 km/h. Suddenly you see a deer standing on the highway and you must put on the brakes. Your reaction time (time elapsed between the moment you see the deer and your foot hitting the brakes) is 0.130 sec. The brakes provide an acceleration with a magnitude of 4.6 m/s2, and a direction opposite the initial velocity.
A) Find the distance (in m) the car travels (at 78.0 km/h) during your reaction time.
B) Calculate the total distance (in m) traveled by the car before stopping.

Answers

(a) The distance  the car travels during your reaction time is 2.83 m.

(b) The total distance traveled by the car before stopping is 97.8 m

What is the distance travelled?

To find the distance traveled during the reaction time, we need to find the velocity after the reaction time and then use it to find the distance traveled.

78 km/h = 78,000 m/h ÷ 3600 s/h = 21.67 m/s

After the reaction time, the velocity is equal to the initial velocity plus the acceleration during the reaction time:

v = v₀ + at

v = 21.67 m/s - (4.6 m/s²)(0.130 s)

v = 21.67 m/s - 0.599 m/s

Finally, the distance traveled during the reaction time is given by:

d = v₀t  + ¹/₂at²

d  = 21.67  x 0.130 s    +    ¹/₂(-4.6) x (0.130)²

d = 2.83 m

B) To find the total distance traveled before stopping, we need to find the time it takes for the velocity to reach 0.

The velocity after the reaction time is equal to 21.67 m/s - 0.599 m/s = 21.07 m/s.

Using the equation v = v₀ + at, we can find the time it takes to come to a stop:

t = -v₀ / a

t = -21.07 / -4.6

t = 4.58 s

The total distance traveled can be found using the equation:

d =  v₀t  + ¹/₂at²

d  = 21.67 x 4.58  + ¹/₂(-4.6) x 4.58

d = 97.8 m

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People who do very detailed work close up, such as jewellers, often can see objects clearly at much closer distance than the normal 25 cm. a. What is the power in D of the eyes of a woman who can see an object clearly at a distance of only 8.5 cm

Answers

This question is incomplete, the complete question is;

People who do very detailed work close up, such as jewelers, often can see objects clearly at much closer distance than the normal 25 cm.

a) What is the power in D of the eyes of a woman who can see an object clearly at a distance of only 8.50 cm? (Assume the lens-to-retina distance is 2.00 cm.)

b) What is the size in mm of an image of a 8.00 mm object, such as lettering inside a ring, held at this distance? (Include the sign of the value in your answer.)  __ mm

Answer:

1) the power in D of the eyes of a woman is 61.7647 D

2) the size in mm of an image of a 8.00 mm object is -1.882 mm

Explanation:

Given the data in the question;

a) power in D of the eyes of woman who can see an object clearly at a distance of only 8.5 cm and the lens-to-retina distance is 2.00 cm,

so

u = 8.5 cm = ( 8.5 / 100 )m = 0.085 m

v = 2.00 cm = ( 2 / 100 )m =  0.02 m

Now, we know that power of lens p = 1 / u + 1 / v

so we substitute

p = ( 1 / 0.085 ) + ( 1 / 0.02 )

p = 11.7647 + 50

p = 61.7647 D

Therefore,  the power in D of the eyes of a woman is 61.7647 D

b) What is the size in mm of an image of a 8.00 mm object, such as lettering inside a ring, held at this distance? (Include the sign of the value in your answer.)

we know that;

m = -v / u

we substitute

m = -0.02 / 0.085

m = -0.2353

since H₀ = 8.0 mm

H\(_i\) = m × H₀

H\(_i\) = -0.2353 × 8.0

H\(_i\) = -1.882 mm

the size in mm of an image of a 8.00 mm object is -1.882 mm

23.15. Can an object carry a charge of 2.0 10-19 C?​

Answers

Answer:

Ok, the minimal quantity of charge that we can find is on the electron or in the proton (the magnitude is the same, but the sign is different)

Where the charge of a single proton is:

C = 1.6x10^-19 C

Now, you need to remember that when we are working with charges, we are working with discrete math:

What means that?

If the minimum positive is the charge of one proton, then the consecutive charge will be the charge of two protons (there is no somethin in between)

So the consecutive charge will be:

C = 2*1.6x10^-19 C = 3.2x10^-19 C.

So, because we are working in discrete math, we can not have any object that has charge between  1.6x10^-19 C and 3.2x10^-19 C.

Particularly, 2.0x10^-19 C is in that range, so we can conclude that:

No, an object can not carry a charge of 2.0x10^-19 C.

Un péndulo de 4 m de longitud tiene una frecuencia de 5Hz. Calcular la longitud de otro péndulo que en el mismo lugar tiene una frecuencia de 4Hz

Answers

Conociendo la longitud y frecuencia de un péndulo, queremos encontrar la longitud de otro pendulo de tal forma que tenga otra frecuencia.

Veremos que la longitud del nuevo péndulo debe ser 6.25m

Sabemos que un péndulo de 4m de longitud tiene una frecuencia de 5Hz.

La frecuencia de un péndulo está dada por:

\(f = \frac{1}{2*\pi} *\frac{g}{l}\)

Donde g es la aceleración gravitatoria y l es la longitud del péndulo, remplazando los datos que tenemos en esa ecuación obtenemos:

\(5 Hz = \frac{1}{2*3.14} *\sqrt{\frac{g}{4m} } \\\\(5Hz*2*3.14)^2*4m = g = 3,943.8 m/s^2\)

Ahora debemos encontra la longitud de tal forma que la frecuencia sea 4Hz, entonces debemos resolver:

\(4Hz = \frac{1}{2*3.14} *\sqrt{ \frac{3943.8m/s^2}{l} }\\\\4hz*2*3.14 = \sqrt{ \frac{3943.8m/s^2}{l} }\\\\l =\frac{3943.8m/s^2}{ (4hz*2*3.14)^2} = 6.25m\)

La longitud del nuevo péndulo deve ser 6.25m

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Last week Tasha and Amy got into a fight at school. Tasha is accusing Amy of talking behind her back. Since the fight, Tasha has been
spamming Amy's social media profile with posts calling her a backstabber, a liar, and a cheat, among other things, Amy insists the matter was
all a misunderstanding, but some of her friends have started to turn against her.
In this situation Amy should try to confront Tasha face to face to sort the matter out. (5 points)
O True
O False

Answers

Answer:

True

Explanation:

Answer:

True

Explanation:

I feel that if she tries sorting it out herself that it could go two ways.

The changing appearance of the Moon during the lunar cycle is the result of the changing -
relative positions of Earth, the Moon and the Sun.
Earth's shadow on the surface of the Moon.
amounts of light emitted by the Moon.
gravitational pull of the Moon as it orbits Earth.

Answers

Answer:

relative positions of Earth, the Moon and the Sun.

Explanation:

A lunar eclipse is a phenomenon that occurs when the Earth comes between the Moon and the Sun thereby causing it to cover the Moon with its shadow.

Simply stated, lunar eclipse takes place when the Moon passes or moves through the Earth's shadow thereby blocking any ray of sunlight from reaching the Moon. Thus, the full moon appears deep red (blood moon).

Also, a lunar eclipse would occur only when the Sun, Earth, and Moon are closely aligned to form a straight line known as the syzygy.

There are three (3) types of lunar eclipse and these are;

1. Total lunar eclipse.

2. Partial lunar eclipse.

3. Penumbra lunar eclipse.

Hence, the changing appearance of the Moon during the lunar cycle is the result of the changing relative positions of Earth, the Moon and the Sun.

What is evidence used by Galileo to disprove Aristotle and Ptolemy?

Answers

Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe.

Galileo Galilei played a crucial role in challenging the prevailing geocentric model of the universe proposed by Aristotle and supported by Ptolemy. He provided several lines of evidence that effectively disproved their theories and supported the heliocentric model proposed by Nicolaus Copernicus. Some of the key evidence used by Galileo includes:

1. Observations through a telescope: Galileo was one of the first astronomers to use a telescope to observe the heavens. His telescopic observations revealed several important discoveries that contradicted the Aristotelian-Ptolemaic worldview. He observed the phases of Venus, which demonstrated that Venus orbits the Sun and not Earth. He also observed the four largest moons of Jupiter, now known as the Galilean moons, which provided evidence for celestial bodies orbiting a planet other than Earth.

2. Sunspots: Galileo's observations of sunspots provided evidence that the Sun is not a perfect celestial body, as suggested by Aristotle. Sunspots indicated that the Sun has imperfections and undergoes changes, challenging the notion of celestial perfection.

3. Mountains on the Moon: Galileo observed the rugged and uneven surface of the Moon, which contradicted Aristotle's belief in celestial spheres made of perfect, unchanging material. The presence of mountains on the Moon suggested that celestial bodies are subject to the same physical laws as Earth.

4. Phases of Venus: Galileo's observations of the phases of Venus provided direct evidence for the heliocentric model. As Venus orbits the Sun, it goes through phases similar to the Moon, ranging from crescent to full. This observation strongly supported the idea that Venus revolves around the Sun.

These lines of evidence presented by Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe. His work marked a significant turning point in the history of science and laid the foundation for modern astronomy.

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