define centre of mass​

Air pressure or atmospheric pressure is the pressure as the force exerted by the collisions of particles in the air.

The key difference between air pressure and liquid pressure is that air pressure allows the gaseous state of matter to be compressible, whereas liquid pressure makes a liquid incompressible

Answer:

Atmospheric pressure, also known as barometric pressure, is the pressure within the atmosphere of Earth. The standard atmosphere is a unit of pressure defined as 101,325 Pa, which is equivalent to 760 mm Hg, 29.9212 inches Hg, or 14.696 psi.

Liquid pressure is the increase in pressure at increasing depths in a liquid. This pressure increases because the liquid at lower depths has to support all of the water above it. We calculate liquid pressure using the equation liquid pressure = mass x acceleration due to g density x depth in fluid.

The lowest possible frequency of sound for which this is possible is 85.0 Hz.

To work out the least conceivable recurrence of sound for which Abby hears a greatest in the power of the sound, we first need to find the frequency of the sound waves, which is 4.00 m. Utilizing the distance among Abby and the speaker, we can find the point between the line associating Abby to the speaker and the line interfacing the two speakers, which is 68.2 degrees. Utilizing geometry, we find the stage contrast between the waves from the two speakers that arrives at Abby is 2π. Consequently, the most minimal conceivable recurrence of sound is v/λ = 85.0 Hz.

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The complete question is:

Two identical loudspeakers 2.00 m apart are emitting sound waves into a room where the speed of sound is 340 m/s. Abby is standing 5.50 m in front of one of the speakers perpendicular to the line joining the speakers, and hears a maximum in the intensity of the sound. calculate the lowest possible frequency of sound for which this is possible? Express your answer with the appropriate units.

Answer:

Tension of rope T = 35.16 N

Explanation:

Given:

Mass of block = 8 kg

Wood of density = 696 kg/m³

Density of lead = 11,340 kg/m³

Find:

Tension in the string

Computation:

Volume of wood = Mass of block / Wood of density

Volume of wood = 8 / 696

Using Archimedes law

Mw + M  = (Vw + V) 1,000

8/1,000 + 11,340v = (Vw + V) 1,000

V = 3.47 x 10⁻⁴

Tension of rope T

T = v (11,340 - 1,000)9.8 N

T = (3.47 x 10⁻⁴)(11,340 - 1,000)9.8 N

Tension of rope T = 35.16 N

If the upper surface of the wood is just level with the water, the tension in the string is 34.2 Newton.

Mass of block of wood; \(m_w = 8.00kg\)

Density of wood; \(\delta _w = 696 kg/m^3\)

Density of lead; \(\delta _{Ld} = 11340 kg/m^3\)

Density of water; \(\delta _{water} = 1000kg/m^3\)

First we determine the volume of wood:

\(v_w = \frac{mass}{density} = \frac{m_w}{\delta w} = \frac{8.00kg}{696kg/m^3}\\\\v_w = 0.01149m^3\)

Now, using Archimedes principle:

Buoyancy force is determined using the equation:

\(F_b = V * \delta * g\)

Where:

We substitute our values into the equation

\(F_b = 0.01149m^3\ *\ 1000kg/m^3 * 9.8m/s^2\\\\F_b = 112.602 kg.m/s^2\\\\F_b = 112.602N\)

Now, buoyancy force \(F_b\) = Weight + Tension

\(F_b = mg + T\\\\T = F_b - mg\)

We substitute in our values

\(T = 112.602N - ( 8kg * 9.8m/s^2)\\\\T = 112.602N - 78.4kgm/s^2\\\\T = 112.602N - 78.4N\\\\T = 34.2N\)

Therefore, if the upper surface of the wood is just level with the water, the tension in the string is 34.2 Newton.

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a) The value of t u = 140/t`b.

b) The y position of the cannonball at the time t is  55.5 mc.

c) The initial speed of the projectile is 52.4 m/s.

Given that a cannonball is fired horizontally from the top of a cliff. The cannon is at height H = 55.5 m above ground level, and the ball is fired with initial horizontal speed u. The projectile lands at a distance D = 140 m from the cliff. Assume that the cannon is fired at time t = 0 and that the cannonball hits the ground at time t.Now,We have to find the value of t, y position of the cannonball at the time t and the initial speed of the projectile.

a. To find the value of t:Here, we have to use the formula of distance

i.e.,S = ut + (1/2)gt², Where S = 140 m, u = u and g = 9.8 m/s².Hence,140 = u×t ………..(1)We know that, time taken by the cannonball to hit the ground can be calculated as,`(2H)/g`

Since the height of the cannon from the ground is 55.5m, the total height of the cannonball from the ground is

(2H) = 2 × 55.5

= 111 m`2H/g

= 111/9.8`

= 11.32653 s

From equation (1),u×t = 140u = 140/t

Therefore, `u = 140/t`b.

b)To find the y position of the cannonball at the time t:

Here, we have to use the formula of height i.e.,y = u×t – (1/2)gt²,

Where, y = height of the cannonball at time t, u = 140/t, t = time taken by the cannonball to hit the ground and g = 9.8 m/s².

We have already calculated the time taken by the cannonball to hit the ground in the previous step.`

y = 140 - (1/2) × 9.8 × t²`

On substituting the value of t as `t = 11.32653`,

we get,y = 140 - (1/2) × 9.8 × (11.32653)²= 55.5 mc.

c)  To find the initial speed of the projectile:

To calculate the initial speed of the projectile, we need to use the formula of range of projectile

.i.e.,R = u²sin2θ/g

Where R = 140 m, g = 9.8 m/s², θ = 0° (horizontal)

u² = R × g/sin2θ

   = 140 × 9.8/sin0°  

   = 2744m²/s²u  

   = \(\sqrt(2744m^2/s^2)\)

   = 52.4 m/s

Hence, the initial speed of the projectile is 52.4 m/s.

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The potential energy is at the maximum when you reach the top of your jump on a trampoline. The correct answer is option B.

Potential Energy is the type of energy an object possesses by virtue of its position relative to others, stresses within itself, electric charge, and other factors. Potential energy exists in various forms, including gravitational potential energy, elastic potential energy, chemical potential energy, and electrical potential energy.

This type of energy can be converted into another type of energies. Examples, a charged battery has potential energy and it can be used as electrical potential energy. Petrol, diesel and and gas have chemical potential energy and be used as kinetic energy.

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Answer:

The focal length of the mirror is 10.4 cm.

Explanation:

So substitute the values of object distance and image distance in the mirror equation,

1/f = 1/(-18cm) + 1/(-25.0cm)

1/f = -25cm/(-18cm x -25cm) - 18cm/(-18cm x 25cm)

1/f = ( -25cm - 18cm)/(18cm x 25cm)

1/f = -43.0/450.0

f = -10.4651 cm.

The focal length of the mirror is approximately -10.4 cm.

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1. The force between the two charges is 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.

2. The resistance of 10 gauge aluminum wire over a 40 ft distance would be 0.506 ohms.

3. The cost of electricity from the automobile battery is 38.6 cents per kWh.

4. The current that would be carried through the body is 0.8 mA if dry.

1. The force between two point charges can be calculated using Coulomb's law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them.

Using the values given, the force can be calculated as F = (k * q1 * q2) / r², where k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them. Plugging in the values, the force can be calculated as 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.

2. The resistance of a wire is determined by its length, cross-sectional area, and resistivity. The resistivity of aluminum is higher than that of copper, so a larger cross-sectional area is required to achieve the same resistance. Using the gauge size conversion chart, 10 gauge aluminum wire has a cross-sectional area of 5.26 mm², which is approximately 83% of the cross-sectional area of 12 gauge copper wire.

Thus, the resistance of 10 gauge aluminum wire over a 40 ft distance can be calculated as R = (rho * L) / A, where rho is the resistivity of aluminum, L is the length, and A is the cross-sectional area. Plugging in the values, the resistance can be calculated as 0.506 ohms.

3. To calculate the cost of electricity per kWh, the total cost and the total amount of energy supplied must be known. Since the battery supplies 12 V and 51 A for one hour, the total energy supplied can be calculated as E = V * I * t, where V is the voltage, I is the current, and t is the time.

Plugging in the values, the total energy supplied can be calculated as 612 watt-hours (Wh). Since one kWh is equal to 1000 Wh, the total energy supplied can be converted to 0.612 kWh. Dividing the total cost by the total energy supplied gives the cost per kWh, which is 38.6 cents.

4. The current through the body can be calculated using Ohm's law, which states that current is equal to voltage divided by resistance. Using the values given, the resistance can be either 100,000 ohms or 300 ohms depending on whether the skin is dry or wet.

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Answer:

\(a=0.2*10^{-5}g\)

Explanation:

From the question we are told that:

Mass \(M=180=>0.18kg\)

Charge \(Q=18mC=18*10^-^3C\)

Velocity \(v=2.2m/s\)

Length of Wire \(L=8.6cm=>0.086\)

Current \(I=30A\)

Generally the equation for Magnetic Field of Wire B is mathematically given by

 \(B=\frac{\mu_0*I}{2\pi*l}\)

 \(B=\frac{4*3.14*10^-^7*I}{2*3.14*8.6}\)

 \(B=6.978*10^{-5}T\)

Generally the equation for Force on the plane F is mathematically given by

 \(F=qvB\)

Therefore

 \(ma=qvB\)

 \(a=\frac{qvB}{m}\)

 \(a=\frac{18*10^{-5}83.4*6.978*10^{-5}}{0.18kg}\)

 \(a=2.37*10^{-5}\)

Therefore in Terms of g's

 \(a=\frac{2.37*10^{-5}}{9.8}\)

 \(a=0.2*10^{-5}g\)

Answer:

11.34 i think

Explanation:

The mass of the picture is approximately 5.19 kilograms.

The deformation in this case is called shear deformation, a type of deformation that occurs when parallel internal surfaces slide past one another. It is caused by shear stress in the structure. The shear stress (τ) is the force (F) applied divided by the cross-sectional area (A) of the nail. The shear strain (γ) is the displacement (Δx) divided by the original length (L0).

The relationship between shear stress and shear strain is given by the shear modulus (G) in the formula:

τ = G * γ

To find the weight of the picture, we need to calculate the shear stress first:

The cross-sectional area A of the nail is given by the formula for the area of a circle:

A = πr² = π(d/2)² = π(0.0015 m / 2)² = 1.767 x 10^-6 m².

The shear strain γ is given by:

γ = Δx / L0 = (1.80 x 10^-6 m) / (5 x 10^-3 m) = 0.36.

The shear stress τ can now be calculated by rearranging the formula:

τ = G * γ

=> τ = (80 x 10^9 N/m²) * 0.36 = 28.8 x 10^9 N/m²

The force F on the nail is equal to the weight w of the picture, and it can be calculated from the shear stress:

τ = F / A

=> F = τ * A = (28.8 x 10^9 N/m²) * (1.767 x 10^-6 m²) = 50.89 N.

Since weight w = m * g, where m is mass and g is the acceleration due to gravity (approximately 9.81 m/s²), we can find the mass m:

m = w / g = (50.89 N) / (9.81 m/s²) = 5.19 kg.

So, the mass of the picture is approximately 5.19 kilograms.

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Answer:

1.142

Explanation:

Answer:

A wave with a frequency of 60 hertz will have 60 successive wave crests occurring every second

Explanation:

A crest is the highest point the medium rises to in a wave. That means that the crest is a point on the wave where the displacement is at a maximum.

Frequency is the number of oscillations of a wave in one second. Hence, frequency of a wave is the number of successive crests occurring in a second.

Therefore a wave with a frequency of 60 hertz will have 60 successive wave crests occurring every second.

We can achieve this design by adding weight to the second rocket, such as by adding a heavier nose cone, fins, or other components.

The first model rocket has a mass of 0.2 kg and is powered by a motor that can provide a force of 200 N.

Using Newton's second law of motion, we can calculate the acceleration of the rocket:

F = ma

where;

Rearranging the equation, we can solve for the acceleration:

a = F/m

Plugging in the values, we get:

a = 200 N / 0.2 kg

a = 1000 m/s^2

So the first model rocket accelerates at 1000 m/s².

The second model rocket is being designed to accelerate one-fourth as much as the first rocket. This means that its acceleration will be:

a' = 1/4 * a

a' = 1/4 * 1000 m/s²

a' = 250 m/s²

So we need to design the second rocket so that it accelerates at 250 m/s².

We can use the same motor, so the force applied to the rocket will still be 200 N. Therefore, we need to change the mass of the rocket to achieve the desired acceleration.

Using the equation for acceleration, we can solve for the mass needed to achieve an acceleration of 250 m/s²:

a' = F/m'

250 m/s² = 200 N / m'

m' = 200 N / 250 m/s^2

m' = 0.8 kg

So the mass of the second rocket needs to be 0.8 kg in order to achieve an acceleration of 250 m/s² with the same motor.

Thus, we can achieve this by adding weight to the second rocket, such as by adding a heavier nose cone, fins, or other components. Alternatively, we could also increase the size of the second rocket while keeping the same mass, which would decrease its acceleration but also increase its overall speed and altitude.

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OB

mmnjnjlkdhfutydjfyiudtkcgvyftdcgvjyiluftgyiuyu  ( had to do that cuz it wouldn't let through)

Recall that

v² - u² = 2 a ∆x

where u and v denote initial and final velocities, respectively; a is acceleration; and ∆x is the distance traveled.

Then we get

(18 m/s)² - (26 m/s)² = 2 a (52 m)

a = ((18 m/s)² - (26 m/s)²) / (104 m)

a ≈ -3.4 m/s²

Answer:

The distance is \(D = 2.6 \ m\)

Explanation:

From the question we are told that

    The wavelength of the light is  \(\lambda = 476.1 \ nm = 476.1 *10^{-9} \ m\)

      The  distance between the slit is  \(d = 0.29 \ mm = 0.29 *10^{-3} \ m\)

       The  between the first and second dark fringes is  \(y = 4.2 \ mm = 4.2 *10^{-3} \ m\)

Generally  fringe width is mathematically represented as

       \(y = \frac{\lambda * D }{d}\)

Where D is the distance of the slit to the screen

   Hence

        \(D = \frac{y * d}{\lambda }\)

substituting values

       \(D = \frac{ 4.2 *10^{-3} * 0.29 *10^{-3}}{ 476.1 *10^{-9} }\)

        \(D = 2.6 \ m\)

Information technology has greatly impacted the economy, leading to increased productivity, efficiency, and innovation across industries.

The widespread adoption of information technology in the business world has led to a significant transformation in the way companies operate. Through the use of computers, software, and other digital tools, businesses are now able to streamline their operations, automate processes, and access vast amounts of data that can inform decision-making.

This has resulted in increased productivity, efficiency, and cost savings for companies. Additionally, information technology has facilitated the rise of new industries, such as e-commerce and digital marketing, while also enabling existing industries to adapt and innovate in response to changing market conditions.

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--The complete question is, How has information technology impacted the economy?--

Answer:

Dₓ = -155 sin 23° i + 0 j

Explanation:

The diagram showing the vector has been attached to this response.

As shown in the diagram,

The vector D has an x-component (also called horizontal component) of -D sinθ i. i.e

Dₓ = -D sin θ i   [The negative sign shows that D lies in the negative x direction]

Where;

D = magnitude of D = 155m

θ = direction of D = 23°

Therefore;

Dₓ = -155 sin 23° i

Since Dₓ represents the x component, its unit vector, j component has a value of 0.

Therefore, Dₓ can be written in terms of D, θ and the unit vectors i and j as follows;

Dₓ = -155 sin 23° i + 0 j

The x-component of the vector is written as \(D_x = (-60.56 \ i + 0j)\ m\).

The given parameters;

The x-component of the vector is calculated as;

\(D_x = D \ \times sin\theta \\\\D_x = 155 \times sin(23)\\\\D_x = 60.56 \ m\)

Since the direction of the vector is in negative x-axis, the x-component of the vectors is written as;

\(D_x = (-60.56 \ i + 0j)\ m\)

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The amount of damping force that allow shortest possible time is called​ critical damping of the system.

Critical damping is the threshold between overdamping and underdamping  at which the oscillator returns to the position of equilibrium quickly as possible.

Critical damping is frequently desired because such a system returns to and maintains equilibrium quickly. Furthermore, a constant force applied to a critically damped system moves the system to a new equilibrium position as quickly as possible without overshooting or oscillating around the new position.

Critical damping thus provides the rapid approach to zero amplitude for a damped oscillator.

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Answer:

mass = 5 [kg]

Explanation:

The difference between weight and mass should be clarified, the weight is equal to the product of the mass by the gravity of the place. While the mass will always be conserved regardless of the place, it will never change.

weight = mass * gravity of the place

}Therefore the mass is the same in the earth as in the moon

The change in volume over the 3 year period is 400,000 m3.

Volume is a measure of the three-dimensional space an object occupies. It is commonly measured in liters, cubic meters, or gallons. In physics, volume is the measure of an object's capacity to contain matter or energy.

The change in volume over the 3 year period is calculated using the formula:
Change in Volume = Total Volume * (1 - Final Water Content/Initial Water Content)
In this scenario, the Total Volume is 1,000,000 m3, the Initial Water Content is 120%, and the Final Water Content is 72%. Plugging these values into the formula, we get:
Change in Volume = 1,000,000 m3 * (1 - 72%/120%)
Change in Volume = 1,000,000 m3 * (1 - 0.6)
Change in Volume = 1,000,000 m3 * 0.4
Change in Volume = 400,000 m3
Therefore, the change in volume over the 3 year period is 400,000 m3.

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Answer:

Tension

Explanation:

Answer:

3rd sentence

Explanation:

Answer:

Different organelles play different roles in the cell — for instance, mitochondria generate energy from food molecules; lysosomes break down and recycle organelles and macromolecules; and the endoplasmic reticulum helps build membranes and transport proteins throughout the cell.

Explanation:

Hopefully this helped!

The change in velocity of an object is given by the equation Δv = F * t / m, where Δv is the change in velocity, F is the force applied, t is the time over which the force is applied, and m is the mass of the object.

In this case, the impulse applied to the block is 24 Ns, and the mass of the block is 6 kg. The time over which the force is applied can be calculated as t = Impulse / Force = 24 Ns / 24 N = 1 s.

Using these values, we can calculate the change in velocity of the block as follows:

Δv = F * t / m = 24 N * 1 s / 6 kg = 4 m/s

So, the velocity of the block after the impulse is applied would be v = v0 + Δv = 8 m/s + 4 m/s = 12 m/s.

Answer: It is b.

Explanation:

The correct statement is (d) The charge on the plates is increased four times its original value.

What is parallel plate capacitor?  

A parallel plate capacitor is a type of capacitor that consists of two parallel conductive plates separated by a dielectric material. It is a type of capacitor used in electrical circuits to store electrical energy. The plates are usually made of metal and the dielectric material is usually a thin non-conductive material like paper or plastic. The size of the capacitor is determined by the distance between the plates and the dielectric material.

This is because the charge on the capacitor plates is proportional to the voltage across the plates and the capacitance, which is given by the formula C = ε_0 * A / d, where ε_0 is the electric constant and A is the area of the plates.

When the plate separation is decreased to d/4, the capacitance of the capacitor becomes C' = ε_0 * A / (d/4) = 4 * ε_0 * A / d, and thus the charge on the plates becomes Q' = C' * V = 4 * Q.

Therefore, The charge on the plates is increased four times its original value is the correct answer.

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Answer: true

Explanation: idek