if you 235lb traviling north at 75mph and strike a 150 lb deer going 35mph east what is the force
We need to use the formula: Force = Mass × Acceleration Let's use the given values to calculate the force exerted on the deer when it is hit by the car. The car weighs 235 lb and it is traveling north at 75 mph. The deer weighs 150 lb and it is going 35 mph east. Force = 44045 lbSince the force is a vector quantity, it has both magnitude and direction.
Step 1: Convert the velocities into feet per second.1 mile = 5280 feet1 hour = 3600 seconds So, the velocity of the car is:75 mph = (75 × 5280) ÷ 3600 = 110 feet/secondThe velocity of the deer is:35 mph = (35 × 5280) ÷ 3600 = 51.3 feet/second
Step 2: Find the components of velocity of the deer. The velocity of the deer is in the east direction, so we need to find its horizontal component, vx, and its vertical component, vy. If the angle between the deer's velocity and the x-axis is θ, then: vx = v × cosθandvy = v × sinθv = 51.3 feet/secondθ = 90° - arctan(0 / 110) = 90°So,vx = 51.3 × cos90° = 0 feet/second vy = 51.3 × sin90° = 51.3 feet/second
Step 3: Find the net velocities of the car and the deer. Since the car is moving north and the deer is moving east, the net velocity of the car and deer together can be found using the Pythagorean theorem. Net velocity = √[(vx + 110)² + vy²]Net velocity = √[(0 + 110)² + (51.3)²]Net velocity = √(12100 + 2631.69)Net velocity = √14731.69Net velocity = 121.3 feet/second
Step 4: Find the net momentum of the car and the deer. Net momentum = (mass of car × velocity of car) + (mass of deer × velocity of deer)Net momentum = (235 × 110) + (150 × 121.3)Net momentum = 25850 + 18195Net momentum = 44045 lb ft/second
Step 5: Find the force exerted on the deer. Force = Net momentum ÷ time Here, time is the duration of the collision which is not given in the problem. We will assume it to be 1 second. Force = 44045 ÷ 1
Force = 44045 lb Since the force is a vector quantity, it has both magnitude and direction. The direction of force is along the line of impact which is not given in the problem.
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Un motociclista arranca desde el reposo y mantiene una aceleración constante de 0.14 m/s^2. Calcular: a) En que tiempo recorrerá una distancia de 1.3 Km/h b) Qué rapidez llevará en ese tiempo en m/s y en Km/h *
Answer:
\(136.28\ \text{s}\)
19.08 m/s or 68.688 km/h
Explanation:
a = Aceleración = \(0.14\ \text{m/s}^2\)
s = Desplazamiento = \(1.3\ \text{km}=1300\ \text{m}\)
u = Velocidad inicial = 0
t = Tiempo empleado
De las ecuaciones cinemáticas obtenemos
\(s=ut+\dfrac{1}{2}at^2\\\Rightarrow 1300=0+\dfrac{1}{2}\times 0.14t^2\\\Rightarrow t=\sqrt{\dfrac{1300\times 2}{0.14}}\\\Rightarrow t=136.28\ \text{s}\)
El tiempo necesario para recorrer una distancia de 1,3 km es \(136.28\ \text{s}\)
\(v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 0.14\times 1300+0}\\\Rightarrow v=19.08\ \text{m/s}=19.08\times 3.6=68.688\ \text{km/h}\)
La velocidad final del automóvil es 19.08 m/s so 68.688 km/h.
An ideal gas expands isothermally performing 4.30 x 10³ of work in the process. Calculate (a)
the change in internal energy of the gas, and (b) the heat absorbed during this expansion.
Answer:
The solution of the given query is explained below in the explanation portion.
Explanation:
Given value is:
Work,
⇒ \(W=4.30\times 10^3 \ J\)
(a)
The change in the internal energy will be:
⇒ \(\Delta V=\frac{3}{2}nR(\Delta T)\)
Throughout the isothermal procedure, The temperature will be constant "ΔT = 0".
then,
⇒ \(\Delta V = \frac{3}{2}nR(0)\)
⇒ \(\Delta V = 0 \ J\)
(b)
As we know,
⇒ \(\Delta V = Q-W\)
On substituting the value, we get
⇒ \(0=Q-W\)
On adding W both sides, we get
⇒ \(W=Q-W+W\)
⇒ \(W=Q\)
On substituting the given value of "W", we get
⇒ \(Q=4.30\times 10^3 \ J\)
If a cheetah goes from 10 m/s to 30 m/s in 5 seconds, what was her acceleration?
PLS HELP!!!!
when total internal reflection happens at a plastic-air interface:
a) half the light is refracted
b) half the light is reflected
c) light hits the interface from the air side
d) light hits the interface from the plastic side
e) the law of reflection ceases to hold
When total internal reflection happens at a plastic-air interface, light hits the interface from the plastic side. The correct answer is Option D.
Total internal reflection is a phenomenon that happens when a light ray tries to pass from a medium of high refractive index to another medium with a low refractive index. When the angle of incidence becomes greater than the critical angle of the interface, the light rays are refracted and stay inside the medium of high refractive index. If the angle of incidence is even greater, the light is reflected back into the same medium as it was coming from.
In the case of total internal reflection, the incident angle is greater than the critical angle, so the light is reflected back. The total internal reflection only occurs when the light goes from a medium with a higher refractive index to a medium with a lower refractive index.
The law of reflection holds for total internal reflection. When a ray of light hits a plastic-air interface from the plastic side with an angle of incidence greater than the critical angle, then total internal reflection occurs. Therefore, the correct option is "d) light hits the interface from the plastic side."
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If you are pulling on a box with a force of 20 N, and your friend is pushing the box in the same direction with a force of 30 N, what will happen to the box?
Answer: If you are pushing a box toward your friend with a force of 20 N, and your friend is pushing the box toward you with a force of 30 N, what will happen to the box? The box will move toward your friend with a force of 50 N.
Explanation:
How are electromagnets made?
A person with a mass of 40 kg is sitting on a box. What is the value of the normal force
normal force=mass*gravitational force
normal force=40*0
normal force=40
What is the direction and magnitude of the Electric Field 4.0 m away from an 8.6 μC charge?
bert and ernie are pushing on opposite sides of the box. if they can both push with the same amount of force, what is true about the motion of the box?
The box will be in rest due to net force applied on it is zero.
What is force?The definition of force in physics is: The push or pull on a massed object changes its velocity.
An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
Given that Bert and Ernie are pushing on opposite sides of the box with force of same magnitude, let it be F.
So, net force acting om the force = F-F = 0.
As that net force acting on the box is zero, the box will be in rest.
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A man on a beach notices that four waves arrive on the shore every 20 seconds. What is the frequency of the waves?
Answer:
0.2 Hz
Explanation:
Frequency: This can be defined as the number of circles completed by a wave in one seconds. The s.i unit is hertz.
From the question,
If 4 Waves arrives on the shore every 20 seconds,
Then,
x waves will arrives on the shore in one seconds
Solving for x
x = (4×1)/20
x = 0.2 Hz
Hence the frequency of the wave is 0.2 Hz
brainliest please help
show the resultant force
8n downwards
since downwards force is greater than upwards just minus
When using the max out method to determine muscular strength, you must first do a warm-up set and a complete set before attempting your one rep max.
Answer:
True
Explanation:
I took the quiz and got it right.
TRUST
The "max out" method, also known as the "1RM" (One Repetition Maximum) method, is commonly used in strength training to determine the maximum amount of weight an individual can lift for a particular exercise.
The purpose of this method is to assess muscular strength accurately. While it is essential to perform warm-up sets to prepare the body for intense lifting, the process of determining the 1RM involves a specific protocol:
Warm-up Sets: Before attempting the 1RM, it is crucial to warm up the muscles and joints properly. Warm-up sets are typically performed with lighter weights and higher repetitions to gradually prepare the body for the heavier load.
Complete Sets: After the warm-up sets, the individual performs one or more "complete sets" with progressively heavier weights, but not at maximal effort. These sets help acclimate the body to heavier loads and prepare the nervous system for the upcoming maximal lift.
1RM Attempt: Once adequately warmed up and prepared, the individual makes an attempt to lift the heaviest weight possible for one repetition. It is essential to have a spotter or a qualified trainer to ensure safety during this maximal effort lift.
Rest: After the 1RM attempt, it is essential to allow sufficient rest and recovery, as attempting maximal lifts can be physically and mentally demanding.
It's important to note that determining 1RM carries a higher risk of injury compared to typical strength training. It's best to perform 1RM assessments under the guidance of a qualified trainer or coach who can provide proper instruction and ensure safety throughout the process. Additionally, the 1RM should be assessed periodically, as it can change over time with training and adaptation.
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Which of the following describes an action-reaction pair?
A. You push on a wall, and the wall pushes back on you.
O B. You sit on a chair, and the chair is pulled down by gravity.
O C. A cup pushes down on a table, and the table pushes down on the
ground.
D. The Moon's gravity pulls on Earth, and your gravity pulls on the
Moon.
Answer:
A) only the wall is involved for both forces (action-reaction)
SOMEONE ANSWER ME ASAPPP ILL GIVE U BRAINLIEST ANSWER
Options are
a)6.5km
b)9.0km
c)10.5km
d)2.5km
Answer:
2.5 km because displacement is xf -xi
xf = 2.5
xi= 0
2.5 - 0 =2.5 km
When ionic bonds form compound structures in a solid state, they arrange in latticed, crystalline patterns.
What does this say about the structure of the compound on the molecular level? What does it say about
the properties of that compound?
Answer:
Structures are determined by two principal factors: the relative sizes of the ions and the ratio of the numbers of positive and negative ions in the compound.
Ionic compounds at a molecular level are arranged in definite patterns to give a crystalline structure leading to a high melting point, high boiling point and high density in ionic compounds.
In ionic bond is formed when a metal transfers electrons to a nonmetal and an ion pair is formed. The ions are held together by strong electrostatic interaction as described by Coulomb's law.
However, the smallest unit of an ionic substance is called the formula unit. The compound arranges itself in definite patterns to form a crystalline lattice. Hence, the structure of ionic compound is highly ordered. This leads to a high melting point, high boiling point and high density in ionic compounds.
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What happens to the air in an air pump when being pumped into a tire? What happens to the air when allowed to escape from a tire?
An astronomical telescope is used to view distant stars. How does the angle between the just-resolvable light from two stars differ if the average light from the stars is red or if it is blue?.
With an astronomical telescope, the angle of just resolution light from two stars would be greater if the light of the average star is red or if it is blue.
What is an astronomical telescope?
An astronomical telescope consists of two lenses: objective and eyepiece.
The objective lens forms the image of a far off object at focal point while eyepiece lens just magnifies the image and make it look more clear, visible and magnified.
The formula D = 1.22λ/dФ is used to find the value of aperture of the telescope.
In general, an astronomical telescope is used to view distant stars. Thus, the angle formed would be greater if the light emitted by the average stars is red or blue.
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an outside loudspeaker (considered a small source) emits sound waves with a power output of 100 w. find the intensity 10.0 m from the source. find the intensity level in decibels at that distance. at what distance would you experience the sound at the threshold of pain, 120 db?
According to the given problem, an outside loudspeaker (considered a small source) emits sound waves with a power output of 100 W, find the intensity 10.0 m from the source.
To find the intensity at a 10.0 m distance from the source, we will use the formula given below.
Intensity (I) = Power (P) / 4πr²Where,
Power P = 100 W
Distance r = 10.0 m
Intensity (I) = 100 W / (4π × 10.0 m)²
I = 0.0796 W/m²
Therefore, the intensity of the sound wave is 0.0796 W/m² at a 10.0 m distance from the source.
To find the intensity level in decibels (dB) at a 10.0 m distance, we will use the formula given below.
Intensity level (β) = 10 log10 (I / I₀)
Where,
I₀ = 10⁻¹² W/m²
Intensity I = 0.0796 W/m²
Intensity level (β) = 10 log10 (0.0796 W/m² / 10⁻¹² W/m²)
β = 109.009 dB
Therefore, the intensity level of the sound wave at a 10.0 m distance is 109.009 dB.
To find the distance at which sound is experienced at the threshold of pain (120 dB), we will use the formula given below.
β = 10 log10 (I / I₀)
120 = 10 log10 (I / I₀)
I / I₀ = 10¹²
I / 10⁻¹² W/m² = 10¹²
I = 1
I = 1 W/m²
Now, we will use the formula given below to find the distance r.
Intensity (I) = Power (P) / 4πr²
1 W/m² = 100 W / (4π × r²)
r² = 100 W / (4π × 1 W/m²)
r = 2.82 m (approximately)
Therefore, at a distance of 2.82 m (approximately), the sound wave is experienced at the threshold of pain (120 dB).
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What's sulfur linkage for cysteine and cystine
Sulfur linkage, also known as a disulfide bond or disulfide bridge, is a covalent bond that forms between two sulfur atoms within a protein structure. This bond plays a crucial role in stabilizing protein conformation and maintaining its proper folding.
Cysteine and cystine are both amino acids, which are the building blocks of proteins. Cysteine contains a thiol group (-SH) in its side chain, while cystine is formed when two cysteine molecules create a disulfide bond.
The sulfur linkage in cystine is a direct result of the oxidation of two cysteine residues, connecting their sulfur atoms through the formation of a disulfide bond (S-S).
The disulfide bond between two cysteine residues can be reversible, and the process of breaking and forming these bonds is known as reduction and oxidation (redox) reactions. In a cellular environment, the formation of disulfide bonds usually occurs within the endoplasmic reticulum, where proteins are synthesized and folded before being transported to other cellular locations.
The presence of sulfur linkages in proteins contributes to their stability, rigidity, and resistance to denaturation. Disulfide bonds are essential in many proteins, such as antibodies and enzymes, where they help maintain the protein's three-dimensional structure and overall functionality.
In conclusion, sulfur linkages in cysteine and cystine are essential for protein folding and stability, contributing significantly to the overall structure and function of proteins in various biological systems.
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when is the acceleration of body is positive negative and zero?
Answer:
【 In vector form , if angle between velocity vector and acceleration vector is less than 90° and greater than 0° then it is positive acceleration and if it is less than 180° and greater than 90° then it is negative acceleration. If there is no acceleration vector then it is called zero acceleration. 】
the 4000 vv equipotential surface is 13.0 cmcm farther from a positively charged particle than the 5000 vv equipotential surface.
The charge on equipotential surface is found to be 0.28 micro columbs for positively charged particle.
We are given the following data:
V1=4000 V2=5000 d=10 cm
Let’s see how electric potential and charge are related.
The electric potential is given by the following formula:
V=k⋅q/r (1)
where k is the Coulomb constant which has the following value:
k=9x10^9 C2 Nm2
We have two potentials at different distances from the charge. Denote the distance of potential V1 by r1, and the distance of potential V2 by r2. According to the given data we can write the following:
r1 = r2 +d
v1/v2 = r2/r2+d
r2 = -v1.d/v1-v2
= -4000 x 13 x 0.01 /(4000-5000)
= 0.52 m
Charge, q = v2.r2 / k
= 5000 x 0.52 / 9x10^9
= 0.28 micro.C
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The complete question is :
The 4000 vv equipotential surface is 13.0 cm farther from a positively charged particle than the 5000 vv equipotential surface. find the charge on the surface.
virtual images can be projected to a screen if you turn the screen slightly true or false
False
Virtual image cannot be caught on a screen
If the pressure at a point is Im of water, what will be it's value in terms of 1m of oil? (Take, the density of oil to be 0.8 g/cm³) A. 0.8 B. 1 C. 1.25 D. 2.5
The value in terms of 1m of oil is 1.25
How to solve for the valueTo convert the pressure at a point from 1 meter of water to its equivalent value in meters of oil, we can use the following formula:
Pressure = height × density × gravity
Let's first find the pressure exerted by 1 meter of water.
1 g x 0.8 = 0,8
1 x g x 1m = 0.8 x g * h2
We are to solve for h2
h2 = 1 / 0.8
= 1.25
Hence tghe value in terms of 1m of oil is 1.25
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In 2 - 3 sentences, explain the difference in Kinetic energy and Potential energy.
The main difference between Kinetic energy and Potential energy is that kinetic energy refers to movement while potential energy refers to storage.
What are Kinetic energy and Potential energy?Kinetic energy is a type of energy in motion or energy in movement such as a turbine (mechanical energy), while Potential energy refers to the energy that is stored to be used when required (e.g. chemical bonds of foods).
Therefore, with this data, we can see that Kinetic energy is used as movement, while Potential energy is stored to be used in the future.
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Two charges separated by one meter exert a 9 N force on each other. If the charges are pushed to a 3 meter separation, the force on each charge will be 3 N.
True or False?
Answer:
False
Explanation:
The formula of force that exists between two charges is expressed as;
F = kq1q2/r²
If two charges separated by one meter exert a 9 N force on each other, the;
9 = kq1q2/1²
9 = kq1q2 ..... 1
If the charges are pushed to a 3 meter separation, then;
F = kq1q2/3²
F = kq1q2/9 .... 2
Divide both equations;
9/F = (kq1q2)/ kq1q2/9
9/F = kq1q2 * 9/ kq1q2
9/F = 9
F = 9/9
F = 1N
Hence if the charges are pushed to a 3 meter separation, then the force on EACH charge will be 1N. Hence the answer is False
An astronaut of mass m is launched from the surface of the moon in a space craft having an initial vertical acceleration of 5g, where g' is the acceleration of free fall in moon. The vertical reaction of the space craft on the astronaut is
The vertical reaction of the space craft on the astronaut is 5mg.
What is the vertical reaction of the space craft on the astronaut?The vertical reaction of the space craft on the astronaut is calculated by applying Newton's second law of motion as shown below.
F = mg
where;
m is the mass of the astronautg is acceleration due to gravity on moon = 1.67 m/s²The vertical reaction of the space craft on the astronaut is calculated as;
F = m x 5g
F = 5mg
Thus, the vertical reaction of the space craft on the astronaut is equal to the weight of the astronaut exerted downwards.
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A graduated cylinder contains 17.5 ml of water. When a metal cube is placed onto the cylinder, its water level rises to 20.3 ml.
Answer:
V=2.8 ml
Explanation:
volume of the cube is it would be 20.3 - 17.5 ml so 2.8 ml.
The horizontal velocity of the body is greatest in value at mid‐stance for ______.
a. walking
b. running
c. both gaits
d. neither gait
According to the question The horizontal velocity of the body is greatest in value at mid-stance for running. the correct option is C
Walking and running are two different ways of travelling by foot, but there are some key differences between them. Running entails a period of time when both feet are in the air and a period of time when both feet are in contact with the ground. When one foot is in contact with the ground, walking always has at least one foot in contact with the ground, whereas running requires both feet to be off the ground for a portion of the stride cycle. These differences affect the way that force is applied to the body, particularly the legs and feet.
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Will it be 200N? I am just making sure
Answer:I think it would be 0
Explanation:
Both are pushing with 100n therefore it will not move