Ammonium cyanate (NH₄OCN) is a salt formed by the combination of the ammonium ion (NH₄₊) and the cyanate ion (OCN-). Therefore A is correct.
When ammonium cyanate dissolves in water, the ammonium ion can donate a proton (H+) to water molecules, resulting in the formation of hydronium ions (H₃O+).
This leads to an increase in the concentration of hydronium ions and, consequently, a decrease in pH. Therefore, solutions of ammonium cyanate are acidic.
b. Anilinium cyanate (C₆H₅NH₃OCN) is a salt formed by the combination of the anilinium ion (C₆H₅NH₃₊) and the cyanate ion (OCN-). The anilinium ion is derived from aniline, which is a weak base.
In summary, solutions of ammonium cyanate are acidic, while solutions of anilinium cyanate are basic.
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predict the complete ground state electron configuration of bohrium. do not use noble gas abbreviation, show sub orbitals partially filled
Ground state electron configuration of bohrium is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s² 4f¹⁴ 5d¹⁰ 6p⁶ 5f¹⁴ 6d⁵ 7s². Atomic number of Bohrium is 107.
What is element?Elements are composed of identical atom, they cannot be distinguished from one another and are inseparable. In the entire periodic table , 118 elements have been know till the present.
What is electron configuration?Every electron in an atom has its position in the orbital system described by a set of four quantum numbers. The electron configuration uses this set of quantum numbers, to describe the distribution of an electrons present in a certain atom. For a neutral (uncharged) atom in the ground (non-excited) state, its configuration can be readily predicted from the row (period) and column (group) position of its element in the periodic table.
Bohrium is a element of group 7, period 7 and part of 'd' block.
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How many moles are there in 54g of H2O?
3
1
6.022 x 1023
162
Gallium is a metallic element in Group III. It has similar properties to aluminium.
(a) (i) Describe the structure and bonding in a metallic element.
Metallic elements exist in a solid-state and they are opaque, have a shiny surface, good conductors of electricity and heat, malleable and ductile, and are dense. The structure of metals is formed by atoms that are held together by metallic bonds. These atoms have loosely bound valence electrons that can be shared between the neighboring atoms.
Therefore, the outermost shells of these atoms are incomplete due to the sharing of valence electrons, forming a lattice structure known as a metallic bond.Metallic elements have a unique crystal structure that occurs in two forms. The most common type of metal crystal structure is the body-centered cubic structure where the atoms are arranged in a cube with one atom located at the center of the cube. The other type of metal crystal structure is the face-centered cubic structure, where each corner of the cube is an atom and there is an additional atom at the center of each face of the cube .Metallic bonding occurs due to the delocalized electrons that exist in the metal structure. The valence electrons from each atom are free to move throughout the entire metal lattice. Therefore, these electrons form a "sea of electrons" that is shared by all the atoms in the lattice. This results in the metal structure having high thermal and electrical conductivity.Metals are known for their ductility and malleability properties. These properties are due to the metallic bonding that exists in the metal structure. Since the valence electrons are shared, they can easily move past one another, allowing the metal to be hammered into different shapes without breaking.The properties of metals vary depending on their structure and bonding. Gallium, being a metallic element in Group III, has similar properties to aluminum. Therefore, it has a similar metallic bond structure with delocalized electrons that provide the metal with its unique properties.For such more question on valence electrons
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For the first-order reaction 2N2O5 -> 2N2O4 + O2 at a particular temperature. The half-life of N2O5 is 0.90 hours. What fraction of the initial concentration of N2O5 will remain after 2.4 hours?
Answer: 1/4
Explanation:
2.4/0.09=2
1=1/2
2=1/4
3=1/8
So therefore because we got 2 , so it will be 1/4.
Answers please
I will give brainliest
Answer: it is group1 or group 3 on god
Explanation:
Assertion: A mixture of camphor and Ammonium chloride cannot be
separated by sublimation. Reason: Camphor on heating sublimes,
Ammonium chloride does not.
Both Assertion and Reason are true and Reason is correct explanation of the
Assertion.
Both Assertion and Reason are true but Reason is not the correct explanation of the
Assertion.
Assertion is true but Reason is false.
Assertion is false but Reason is true.
Based on the assertion and reasons given, it can be seen that the Assertion is true, but the reason is false.
Why is the Assertion true?Camphor and ammonium chloride are not separated because they are volatile substances. Hence assertion is true.
Camphor on heating sublimes, only when mixed with sodium chloride so the reason is false.
The bark and wood of the camphor tree were once used to make the chemical known as camphor.
Today, turpentine oil is typically used to make camphor. The fragrance of camphor is quite distinctive. It helps with symptoms like pain and itching by stimulating the nerves, it seems.
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how many moles of carbon dioxide will form when 2.60 moles of pentane react with excess oxygen?
When 2.60 moles of pentane react with excess oxygen, 13.0 moles of carbon dioxide will form.
The balanced equation for the combustion of pentane (C₅H₁₂) with oxygen (O₂) to form carbon dioxide (CO₂) and water (H₂O) is:
C₅H₁₂ + 8O₂ → 5CO₂ + 6H₂O
From the balanced equation, we can see that for every 1 mole of pentane, 5 moles of carbon dioxide are produced. Therefore, if 2.60 moles of pentane react, we can calculate the moles of carbon dioxide formed using the mole ratio:
2.60 moles C₅H₁₂ x (5 moles CO₂ / 1 mole C₅H₁₂) = 13.0 moles CO₂
Therefore, when 2.60 moles of pentane react with excess oxygen, 13.0 moles of carbon dioxide will form.
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pls help !! - Using the graph below, what is the rule for a translation form point A to point D?
Answer:
Graph? Question is incomplete.
The first Tacoma Narrows Bridge in Washington crossed over a strait in Puget Sound. At the time the suspension bridge was built, construction workers noticed that it moved up and down in the wind. Measures to stop the bridge’s movement were ineffective, but the bridge was opened to the public on July 1, 1940. The bridge collapsed on November 7, 1940. Luckily, no people were seriously injured.
Determine which technological design criteria the Tacoma Narrows Bridge did and did not meet.
Answer:
Explanation:
The Tacoma Narrows Bridge is the historical name given to the twin suspension bridge—originally built in 1940—that spanned the Tacoma Narrows strait. It collapsed just four months later due to aeroelastic flutter. Since then, this topic has become popular, with several case studies discussing the failure phenomenon of suspension cable bridges.
In the state of Washington, the construction of the Tacoma Narrows Bridge was completed and opened to the traffic on July 1st, 1940. It was the very first bridge to incorporate a series of plate girders as roadbed support, and the first bridge of its type (cable suspension). It was also the third largest suspension bridge of its time, with a 2800-foot central span and two side spans of 1100 feet each.
A west-side approach had a continuous steel girder of 450ft, while the east side had a long reinforced concrete frame of 210ft. It had two cable anchorages of 26ft. along roadways, two 5ft. sidewalks and two 8ft. deep stiffening girders. Among several other structural details, the suspension cable anchorages to which the cables were connected were made of 20,000 cubic yards of concrete, 6 lakh pounds of structural steel, and 2.7 lakh pounds of reinforcing steel. Because of its extremely long length, it was considered a ‘narrow bridge’. The overall construction cost was estimated to be a whopping $6 Million in 1940. Considering inflation, this is equivalent to almost $1 Billion, and all of this for something that lasted just four months and seven days. Yet, this remains a great engineering feature for civil engineers to ponder over.
True or False a. Sodium chloride is the main salt found in sea water. ……………………………………………………………………. b. Potassium bromide salt is not found in sea water ……………………………………………………………………. c. Both evaporation and electric conduction techniques prove that sea water contain the dissolved salts. …………………………………………………………………….. d. The amount of fresh water is greater than 5% of the total Earth water. …………………………………………………………………….. e. In water treatment process, filter membrane is used to remove fine particles and other impurities from water. …………………………………………………………………………....
Answer:
A is true NaCl
B is false K2Br
C is true
D false its only 0.03 percent
E is true
Consider the first reaction in the first proton-proton chain (PPI): 11H+11H→12H+e++νe (a) [5] Evaluate the Gamow energy EG in units of keV. (b) [5] Evaluate the energy E0 at which the reaction is most likely, assuming a temperature T=1.6×107 K. Express your result in keV and also evaluate kT in keV. (c) [5] Find the values of C1 and ΔE (again in keV ) in the Gaussian approximation. (d) [10] For these values of EG and T, appropriate for the first step of the dominant set of fusion reactions in the core of the Sun, plot the following quantities versus E/kT. (Put them on the same plot.) (i) The term that dominates the dependence of the integrand in equation (2.8.41) on energy E, namely exp(−EEG−kTE) 75 (ii) The approximation in equation (2.8.43), C1exp[−(ΔE/2E−E0)2] Normalize both functions to the maximum value (i.e. divide by the value at E=E0) and use linear scales on the axes.
Consider the first reaction in the first proton-proton chain (PPI):
11H+11H→12H+e++νeEG is Gamow energy, E0 is the energy at which the reaction is most likely, T is the temperature, C1 is the normalization constant, and ΔE is the half-width of the Gaussian approximation.(a) Evaluating the Gamow energy EG in units of keV:
EG = (π2/2) [(me/mH) (Z1Z2 e2/ħc)] (kT)where, me = mass of electron, mH = mass of hydrogen atom = 1.67 × 10-27 kg,Z1 = atomic number of H = 1, Z2 = atomic number of H = 1, e = electronic charge, ħ = Planck's constant / 2π, c = speed of light, k = Boltzmann constant, and T = temperature.= (π2/2) [(9.11 × 10-31 kg / 1.67 × 10-27 kg) (1 × 1 e2 / (1.054 × 10-34 J s × 2.998 × 108 m/s))] (1.602 × 10-19 J)= (π2/2) × 5.31 × 10-41 × 2.306 × 10-28= 1.44 × 10-3 keV.(b) Evaluating the energy E0 at which the reaction is most likely:
From equation (2.8.39) in the textbook,ln[(C1) (EG2) / (E0)2] = − (ΔE)2 / (4k2T2) + EG/kTln[(C1) (EG2) / (E0)2] = − (ΔE)2 / (4k2T2) + ln(exp(EG/kT))ln[(C1) (EG2) / (E0)2 exp(-EG/kT)] = − (ΔE)2 / (4k2T2)ln[(C1) (EG2 / exp(EG/kT)) / (E0)2] = − (ΔE)2 / (4k2T2)ln[(C1) (EG / kT)2 / (E0)2] = − (ΔE)2 / (4k2T2) - ln(exp(EG/kT))ln[(C1) (EG / kT)2 / (E0)2 exp(-EG/kT)] = − (ΔE)2 / (4k2T2)Evaluating the above equation for T = 1.6 × 107 K, EG = 1.44 × 10-3 keV, and using k = 8.62 × 10-5 eV/K= - 5.45ln[(C1) (1.44 × 10-3 keV / (1.38 × 10-5 eV/K × 1.6 × 107 K))2 / (E0)2 exp(-1.44 × 10-3 keV / (1.38 × 10-5 eV/K × 1.6 × 107 K))]= - 5.45ln[(C1) (1.04 × 1021) / (E0)2 (0.951)]= - 3.15 + ln[(C1) / (E0)2]ln[(C1) / (E0)2] = 8.6Evaluating the above equation for the maximum value of ln[(C1) / (E0)2], i.e., 8.6, we get,(C1) / (E0)2 = 3.53 × 108C1 = (E0)2 × 3.53 × 108Putting T = 1.6 × 107 K in the equation for kT,kT = 1.38 × 10-23 J/K × 1.6 × 107 K / 1.602 × 10-19 J/eV= 13.8 keV.(c) Finding the values of C1 and ΔE in the Gaussian approximation:
Using the normalization condition,∫(C1) exp[-(E - E0)2 / (2ΔE2)] dE = 1Putting C1 = (E0)2 × 3.53 × 108,∫(E0)2 × 3.53 × 108 exp[-(E - E0)2 / (2ΔE2)] dE = 1(ΔE) (E0) √(π/2) × 3.53 × 108 = 1ΔE = 5.97 × 10-4 keV.C1 = 5.39 × 1012.(d) Plotting the given quantities:
Normalized Gaussian function = (C1 / (E0)2) exp[-(E - E0)2 / (2ΔE2)] / (C1 / (E0)2) at E = E0 = 6.4 keV = 1.Exponential function = exp[-(E - E0) / EG] exp[-(E - E0) / kT] / exp[-(E0 - E0) / EG] exp[-(E0 - E0) / kT] at E = E0 = 6.4 keV = 1.(Note that exp[-(E - E0) / kT] ≈ 1 for E ≈ E0.)Using linear scales on the axes, we get the following graph.About ReactionA chemical reaction is a process in which a substance or reactant is changed into a different substance and is called a product, a chemical reaction rearranges the atomic composition of the reactants so as to make a different substance as a product. A chemical reaction can occur when there are effective collisions with sufficient energy between the molecules of the reacting substances. The chemical reactions that take place can be identified by changes in temperature, color, and the formation of precipitates and gases. The chemical reactions that take place can be identified by changes in temperature, color, and the formation of precipitates and gases.
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What is the value proposition for consumers that Takealot
excels at? How is this different from traditional (non-online)
retailers.Don’t Confuse Platforms with Ecosystems (INSEAD
Blog), December 202
Takealot excels at providing convenience, extensive product selection, competitive pricing, and a seamless online shopping experience as its value proposition for consumers.
Convenience is a key aspect of Takealot's value proposition. As an online retailer, Takealot offers the convenience of 24/7 shopping from the comfort of one's own home.
Customers can browse a wide range of products, place orders, and have them delivered directly to their doorstep.
Takealot also offers an extensive product selection, spanning various categories such as electronics, fashion, home goods, and more.
This breadth of choices allows consumers to find and compare different products all in one place, saving them time and effort compared to traditional retailers with limited inventory.
Competitive pricing is another area where Takealot excels. By operating online, the company has lower overhead costs compared to brick-and-mortar retailers, enabling them to offer competitive prices and discounts to their customers.
The seamless online shopping experience provided by Takealot includes user-friendly interfaces, secure payment options, and efficient delivery services. This enhances customer satisfaction and convenience.
In contrast, traditional non-online retailers typically have limited operating hours, smaller product selections, and may not offer the same level of convenience and competitive pricing.
They often require customers to physically visit their stores, which can be time-consuming and may not provide the same level of ease and accessibility as online platforms like Takealot.
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What can you infer about the results of numerical models in 1966 for polar caps
made of water ice?
Answer:
Those people could sustain on Mars, by living closer to the poles
Explanation:
As it is given that caps involve the water ice instead of the carbon dioxide
And, current observations of spectrum analyzed that the polar caps are totally different from one other i.e northern one involves more water ice while on the other hand, the southern one involves most of the carbon dioxide
Moreover, the astronomers unable to see to spectrum portions as the atmosphere absorbs the wavelength
So we conclude that the people could survive on mars if they live near to poles
a) Suppose you wanted to produce 1.00L of a 3.59M solution of H2SO4
1) what is the solute?
2)what is the solvent?
3) how many grams of solute are needed to make this solution?
b) how many grams of salute are needed to make 2.50 of a 1.75M solution Ba(NO3)2?
Answer:
1. The solute in this case is H₂SO₄, which stands for sulfuric acid.
2. The solvent is the substance in which the solute is dissolved. In this case, the solvent is not explicitly mentioned, but it is typically water (H₂O) for most aqueous solutions.
3.
Given:
Molarity (M) = 3.59 M
Volume (V) = 1.00 L
The formula to calculate the number of moles (n) of solute is:
n = M * V
Substituting the given values:
n = 3.59 mol/L * 1.00 L = 3.59 mol
To determine the mass of the solute in grams, we need to know the molar mass of H₂SO₄. The molar mass of sulfur (S) is approximately 32.07 g/mol, oxygen (O) is approximately 16.00 g/mol, and hydrogen (H) is approximately 1.01 g/mol.
The molar mass of H₂SO₄ is:
2(1.01 g/mol) + 32.07 g/mol + 4(16.00 g/mol) = 98.09 g/mol
Finally, we can calculate the mass of the solute:
mass = n * molar mass
mass = 3.59 mol * 98.09 g/mol ≈ 350.96 g
Therefore, approximately 350.96 grams of H₂SO₄ are needed to make a 1.00 L solution with a molarity of 3.59 M.
Which one does not belong and why?
Concrete
Lack of conversation
Lack of object permanence
Sensorimotor
The phrase "Lack of conversation" does not belong according to Jean Piaget's theory of cognitive development.
What are Lack of object permanence and Sensorimotor?"Lack of object permanence" refers to the inability to understand that objects continue to exist even when they are out of sight, which is a characteristic of the sensorimotor stage (the first stage) of cognitive development.
"Sensorimotor" refers to the stage of cognitive development where infants and toddlers learn about the world through their senses and motor actions, which is when they develop the concept of object permanence.
"Lack of conversation", on the other hand, is not related to Piaget's theory of cognitive development, and is not a common term used in developmental psychology.
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HD:pSun =rhoMan =pTue =pWed =pThu =pFri =pSat =71 Ha : Not all proportions are equal. HD: Not all proportions are equal. Ha:pSun =pMon =pTue =rhoWed =pThu =rhoFri =rhoSat =71 HD: Not all proportions are equal. Ha:pSun =pMon =pTue =pWed =pThu =rhoFri =pSat =71 HD:pSun =pMon =pTue =pWod =pThu =pFri =pSat =71 Ha : All proportions are equal. Find the value of the test statistic. (Round your answer to three d: Find the p-value. (Round your answer to four decimal places.) p-value = State your conclusion. Do not reject H0−. We conclude that the proportion of traffic Reject HD. We conclude that the proportion of traffic acciden Reject HD. We conclude that the proportion of traffic acciden Do not reject H0−We conclude that the proportion of traffic Compute the percentaqe of traffic accidents occurring on each day What day has the highest percentage of traffic accidents? Sunday Monday Tuesday Wednesday Thursday Friday Saturday Based on 2017 sales, the six top-selling compact showed the following number of vehicles sold. Use a goodness of fit test to determine if the sample data indicate that the market shares for compact cars in the city are different than the market shares suggested by nationwide 2017 sales. Use a 0.05 level of significance. State the null and alternative hypothesis. Ha : The market shares for the compact cars in the city are different for at least one of the nationwide market shares listed. o: The market shares for the compact cars in the city do not differ from market shares nationwide. : The market shares for the compact cars in the city are different from at least one of the nationwide market shares listed. Ha : The market shares for the compact cars in the city are not different from any of the natione Ha : The market shares for the compact cars in the city do not differ from market shares nationwide. "the test statistic.(Round your answer to two decimal places.) d the rho-value. (Round your answer to four decimal places.) Reject H0. We cannot conclude that market shares for the compact cars in the city differ from the nationwide market shares. Do not reject H0. We conclude that market shares for the compact cars in the city differ from the nationwide market shares. Do not reject H0. We cannot conclude that market shares for the compact cars in the city differ from the nationwide market shares.
The p-value is greater than the significance level of 0.05, we do not reject the null hypothesis and conclude that all proportions are equal.
Firstly, let us conduct a Chi-square test of independence of categorical variables based on the information given above. We have three different cases of hypothesis testing that we have to solve one by one.
Case 1: HD:pSun =rhoMan =pTue =pWed =pThu =pFri =pSat =71
Ha : Not all proportions are equal.
Test Statistic
For this hypothesis, we need to compute the test statistic that is given as:
\($$\chi^2=\sum_{i=1}^{k}\frac{(O_i-E_i)^2}{E_i}$$\) where k is the number of groups/categories. Since we have 7 days of the week, \(k = 7. $O_i$ and $E_i$\) are the observed and expected frequencies respectively.
Here, we have equal proportions of 71 for each day of the week.
Therefore, the expected frequencies are also equal to 71.
\($$E_i = 71, i=1,2,3,4,5,6,7.$$\)
We also have to use the given information to compute the observed frequencies,
\($O_i$.$$O_1 = 90, O_2 = 99, O_3 = 122, O_4 = 123, O_5 = 130, O_6 = 160, O_7 = 126$$\)
Therefore, the test statistic can be computed as \($$\chi^2=\frac{(90-71)^2}{71} + \frac{(99-71)^2}{71} + \frac{(122-71)^2}{71} + \frac{(123-71)^2}{71} + \frac{(130-71)^2}{71} + \frac{(160-71)^2}{71} + \frac{(126-71)^2}{71}$$$$\chi^2=180.14\)
Now we have to find the p-value of this test. Since the number of degrees of freedom is k - 1 = 7 - 1 = 6, the p-value can be found using the chi-square distribution table with 6 degrees of freedom at the 0.05 significance level. The p-value is 0.000014. ConclusionSince the p-value is less than the significance level of 0.05, we reject the null hypothesis and conclude that not all proportions are equal.
The total number of accidents is \($$90+99+122+123+130+160+126=850$$\)
The percentage of accidents occurring on each day of the week can be found as follows:
\($$Sunday: $$\frac{90}{850}\times 100 = 10.59\%$$Monday: $$\frac{99}{850}\times 100 = 11.65\%$$Tuesday: $$\frac{122}{850}\times 100 = 14.35\%$$Wednesday: $$\frac{123}{850}\times 100 = 14.47\%$$Thursday: $$\frac{130}{850}\times 100 = 15.29\%$$Friday: $$\frac{160}{850}\times 100 = 18.82\%$$Saturday: $$\frac{126}{850}\times 100 = 14.82\%$$\)
From the above percentages, we can see that Friday has the highest percentage of traffic accidents.
Case 2:
HD: Not all proportions are equal.
Ha:pSun =pMon =pTue =rhoWed =pThu =rhoFri =rhoSat =71
Test Statistic
\($$E_1 = 78.57, E_2 = 86.57, E_3 = 106.86, E_4 = 107.43, E_5 = 113.57, E_6 = 139.43, E_7 = 109.14$$\)
We already know the observed frequencies,
\($$O_1 = 90, O_2 = 99, O_3 = 122, O_4 = 123, O_5 = 130, O_6 = 160, O_7 = 126.$$\)
The test statistic can be computed as:
\($$\chi^2=\frac{(90-78.57)^2}{78.57} + \frac{(99-86.57)^2}{86.57} + \frac{(122-106.86)^2}{106.86}+ \frac{(123-107.43)^2}{107.43} + \frac{(130-113.57)^2}{113.57} + \frac{(160-139.43)^2}{139.43} + \frac{(126-109.14)^2}{109.14} $$$$ \implies \chi^2=34.98$$\)
The p-value is 0.000001.
Conclusion- Since the p-value is less than the significance level of 0.05, we reject the null hypothesis and conclude that not all proportions are equal.
Case 3:
All proportions are equal.
Test Statistic
The expected frequency for each group is
\(E = \frac{850}{7} = 121.43\)
We already know the observed frequencies,
\($$O_1 = 90, O_2 = 99, O_3 = 122, O_4 = 123, O_5 = 130, O_6 = 160, O_7 = 126.$$\)
The test statistic is,
\($$\chi^2=\frac{(90-121.43)^2}{121.43} + \frac{(99-121.43)^2}{121.43} + \frac{(122-121.43)^2}{121.43} + \frac{(123-121.43)^2}{121.43} + \frac{(130-121.43)^2}{121.43} + \frac{(160-121.43)^2}{121.43} + \frac{(126-121.43)^2}{121.43}} \\\implies \chi^2=9.17$$\)
The p-value is 0.1664.
Since the p-value is greater than the significance level of 0.05, we do not reject the null hypothesis and conclude that all proportions are equal.
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What amount of heat, in KJ, would be involved in condensing 12. 9 g of ch3OH ?(hvap=38. 0 kj/mol
The amount of the heat in kJ , would be involved in the condensing 12.9v g of the CH₃OH is the 15.2 kJ.
Given that :
The mass of the CH₃OH = 12.9 g
The ΔH = 38 kJ/mol
The molar mass = 32 g/mol
The number of the moles = mass / molar mass
The number of the mole = 12.9 / 32
= 0.403 mol
The number of the moles is 0.403 mol
The amount of the heat is given as :
Q = n ΔH
Q = 0.403 × 38
Q = 15.2 kJ.
Thus, the amount of the heat is 15.2 kJ.
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What is the difference between a strong alkali and a weak alkali?
Answer:
Strong Alkali – Is an alkali which dissociates – almost completely in aqueous solution thereby producing a – high concentration of hydroxyl [OH– ] ions.
Weak alkali – Is an alkali which dissociates – only partially in aqueous solution thereby producing a – low concentration of hydroxyl [OH–] ions.
50 g of ice at -10 0c is dropped into 100 g of water at 250c in an insulating cup whose mass is negligible. only fraction of ice melts. (a) what is the final equilibrium temperature? (b) what % of ice melts? (57%) (hint: how much heat is available just to melt the ice?)
The final equilibrium temperature is approximately 247.7°C and the percentage of ice that melts is 50%.
The amount of heat transferred is given by the equation:
\(Q = m * c * \triangle T\)
First, we need to calculate the amount of heat needed to melt the ice. The heat required to melt ice is given by the equation:
\(Q = m * L\)
where L is the latent heat of fusion of ice, which is 334 J/g. Therefore, the heat required to melt 50 g of ice is:
\(Q = 50 g * 334 J/g = 16700 J\)
the heat lost by the water is equal to the heat gained by the ice:
\(Q_{water} = -Q_{ice\)
\(T_f = (Q_{ice}/m_{ice}c_{ice} + Q_{water}/m_{water}c_{water}) + T_i\)
Plugging in the values, we get:
\(T_f = (16700 J / 50 g * 2.1 J/gC + 100 g * 4.2 J/gC * (25C - T_i)) + T_i\)
Simplifying this equation, we get:
\(T_f\) = (835°C/g + 4200 J/°C + 105000 J/g) / (100 g * 4.2 J/g°C)
\(T_f\)= (104035°C/g) / (420 J/°C)
\(T_f\)= 247.7°C
Therefore, the final equilibrium temperature is approximately 247.7°C.
To calculate the percentage of ice that melts, we can use the equation:
% ice melted = (mass of ice melted / initial mass of ice) * 100%
mass of ice melted = \(Q_{ice} / L\)
mass of ice melted = 16700 J / 334 J/g
mass of ice melted = 50 g
Therefore, the percentage of ice that melts is:
% ice melted = (50 g / 100 g) * 100%
% ice melted = 50%
Thus, the percentage of ice that melts is 50%.
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How much heat is absorbed in the complete reaction of 3.00 grams of SiO2 with excess carbon in the reaction below? DH0 for the reaction is +624.6 kJ.
SiO2(g) + 3C(s) ® SiC(s) + 2CO(g)
A) 366 kJ
B.) 1.13 ´ 105 kJ
C.) 5.06 kJ
D.) 1.33 ´ 104 kJ
E.) 31.2 kJ
The amount of heat absorbed in the complete reaction of 3.00 grams of SiO2 with excess carbon can be calculated using the given DH0 value for the reaction. The correct answer is option D: 1.33 ´ 104 kJ.
To calculate the heat absorbed in the reaction, we need to use the given DH0 value and the stoichiometry of the reaction. According to the balanced equation, 1 mole of SiO2 reacts with 3 moles of C to produce 1 mole of SiC and 2 moles of CO.
First, we need to calculate the moles of SiO2 in 3.00 grams using its molar mass. The molar mass of SiO2 is approximately 60.08 g/mol. Therefore, 3.00 grams of SiO2 is equal to 3.00 g / 60.08 g/mol = 0.04996 mol.
Next, we can use the DH0 value of +624.6 kJ to calculate the heat absorbed in the reaction. Since 1 mole of SiO2 is involved in the reaction, the heat absorbed can be calculated as follows:
Heat absorbed = DH0 × moles of SiO2
= +624.6 kJ/mol × 0.04996 mol
≈ 1.33 ´ 104 kJ
Therefore, the correct answer is option D: 1.33 ´ 104 kJ, representing the amount of heat absorbed in the complete reaction of 3.00 grams of SiO2 with excess carbon.
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It takes 547 kJ to remove one mole of electrons from the atoms at the surface of a solid metal.
What is the maximum wavelength of light capable of doing this?
According to the relation of variables in the electromagnetic spectrum the maximum wavelength of light is 36.3 ×10\(^-\)³¹ m.
What is electromagnetic spectrum ?The electromagnetic spectrum consists of electromagnetic radiation consists of waves made up of electromagnetic field which are capable of propogating through space and carry the radiant electromagnetic energy.
The radiation are composed of electromagnetic waves which are synchronized oscillations of electric and magnetic fields . They are created due to change which is periodic in electric as well as magnetic fields.
In the given problem,energy is related to wavelength by the formula, λ=hc/E,λ=6.626×10\(^-34\)×3×10⁸/547×1000=36.3×10\(^-31\) m.
Thus, the maximum wavelength of light is 36.3×10\(^-31\) m.
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Because electrons are orbiting the nucleus, the nucleus is stationary
true or false
Answer:
false, The nucleus of atoms still move around like crazy, it's just the electrons move more.
What are some facts about Radon something that is unique and relatively unknown by the general population???? Helpppppp helpppppp
Answer: Radon is radioactive
Explanation: thats all i know
Which percentage is in the appropriate range for a snack to be considered a “good source” of nutrients?
15 percent
35 percent
40 percent
50 percent
Answer:
15
Explanation:
Which set of numbers will balance the following equations? 1's have been included for clarity.__Mn3N4 + __NaF --> __MnF4 + __Na3N a 1; 4; 1; 4 b 1; 4; 3; 2 c 1; 12; 3; 4 d 3; 2; 3; 2
ANSWER
Option C
EXPLANATION
Given that;
\(\text{ ----- Mn}_3N_4\text{ }+\text{ ---- NaF }\rightarrow\text{ ---- MnF}_4\text{ }+\text{ ---Na}_3N\)In the reaction above, we have the following data
At the reactants side;
3 atoms of manganese
4 atoms of nitrogen
1 atom of sodium
1 atom of fluorine
At the products side
1 atom of manganese
4 atoms of fluorine
3 atoms of sodium
1 atom of nitrogen
To balance the above equation, apply the law of conservation mass
Law of conservation of mass states that matter can neither be created nor destroyed but can e transformed from one formato another.
To balance the equation, 1 mole of Mn3N4 reacts with 12 moles of Na Tto give 3 moles of MnF4 and 4 moles of Na3N
So, the new equation becomes
\(\text{ Mn}_3N_4\text{ }+\text{ 12NaF }\rightarrow\text{ 3MnF}_4\text{ }+\text{ 4Na}_3N\)The following data can be deduced in the above equation
At the reactants side
3 atoms of Mn
4 atoms of N
12 atoms of Na
12 atoms of F
At the products side
3 atoms of Mn
12 atoms of F
12 atoms of Na
4 atoms of N
Looking atthe vabove data, the number of atoms of each element at the reactants side is equal to the number of atoms of same elements at the products side.
Hence, the correct answer is option Ce
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what is the purpose of the following reagents in the experiment?
Depending on the particular experiment being conducted and the chemicals being used, the purpose of the reagents employed can change.
In chemical studies, reagents are substances that are employed to induce a certain reaction or outcome. Depending on the specific experiment, the type of reaction being carried out, and the anticipated result, the purpose of the reagents can change. One reagent could, for instance, operate as the acid and another as the base in a reaction combining an acid and a base. The reagents' function is to fuel the reaction between the acid and base and generate the desired outcome, which results in the formation of salt and water. Reagents may be utilised in a different experiment as catalysts to speed up the reaction or as markers.
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A student claims that if she wanted to make a solution quickly, she should use small pellets instead of powder along with heating and stirring. Do you agree or disagree with the student's claim? I am confused on this so I would greatly appreciate anyone’s help.
Answer: Yes, the student is right, one should use pellets of the reactant should be heated and stirred for mixing properly.
Explanation:
In case of smaller particles the surface area that is being exposed increases and the due to this the reaction occurs faster.
Increasing the temperature of the temperature, increases the kinetic energy of the particles which helps in easy mixing of the particles.
The collision in between the particles also increase while stirring and thus the rate of reaction increases.
So, the heating and stirring is more preferred over powered reactant for making a solution quickly.
The pH reading of a sample of each substance is given. Calculate the hydrogen ion concentration of the substance. (a) Vinegar: pH = 3.0 (b) Milk: pH= 6.5
The hydrogen ion concentration of the substance in Vinegar is 1.098 and in case of milk it is 1.871
pH is a measure of how acidic or basic water is. The pH scale actually ranges from 0 - 14, with 7 being neutral. pHs that are less than 7 indicate that it is acidic in nature , whereas a pH of greater than 7 indicates that it is basic in nature. pH is really a measure of the relative amount of free hydrogen and hydroxyl ions present in the water.
The formula to find pH is as follows;
pH = -log\([H]^{+}\), In the above given question we need to find out the hydrogen ion concentration so we can rearrange the formula as;
\([H]^{+}\) = Antilog pH
In case of Vinegar \([H]^{+}\) = Antilog of 3 ⇒ 1.098
In case of Milk \([H]^{+}\) = Antilog of 6.5 ⇒ 1.871
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Which piece of evidence is an indication that a chemical reaction has occurred?
boiling of a substance
a change in color of a substance
melting of a substance
freezing of a substance
Answer:
change of color of substance
Explanation:
I hope it helps
Which is the smallest?
A) 1.3 x 1020
B) 2.9 x 1021
C) 9.5 x 1032
d) 8.4 x 1019