Answers
Answer:
Fish tank
Explanation:
It is the largest and therefore has the most volume.
Related Questions
what is math and science?
Answers
Mathematics and science are formal and exact sciences that are based on logic.
What is math and science?Mathematics is an exact science that studies the properties and relationships between entities through geometric figures and arithmetic with numbers. Mathematics then looks for common patterns that could end up leading to a theory and, if it is verifiable and true, end up being a law, such as the Pythagorean law for example.
In terms of science, it is the comparable knowledge that has been studied, explained, and has helped predict social and natural phenomena in our universe over time. This has been done and verified through the scientific method, making it then a verifiable and true logic.
Therefore, we can confirm that mathematics and science are formal and exact sciences that are based on logic.
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The following diagrams represent mixtures of NO(g) and O2(g). These two substances react as follows: 2NO(g) + O2(g)----2NO2(g) It has been determined experimentally that the rate is second order in NO and first order in O2. Based on this fact, which of the following mixtures will have the fastest initial rate? The mixture (1). The mixture (2). The mixture (3). The right answer is the mixture 1, but I do not know why. So..
Answers
Based on the given fact Mixture 1 has the fastest initial rate in the reaction 2NO(g) + O\(_2\)(g)----2NO2\(_2\)(g), where the rate is second order in NO and first order in O2.
The reaction is given as:
2NO(g) + O\(_2\)(g)----2NO2\(_2\)(g)
The rate law for this reaction can be written as:
Rate = k\([NO]^2[O_2]\)
where k is the rate constant, [NO] is the concentration of NO, and [O\(_2\)] is the concentration of O2. To determine which mixture has the fastest initial rate, we need to compare the initial concentrations of NO and O\(_2\) in each mixture.
Mixture 1:
- High concentration of NO
- High concentration of O\(_2\)
Mixture 2:
- Low concentration of NO
- High concentration of O\(_2\)
Mixture 3:
- High concentration of NO
- Low concentration of O\(_2\)
Now let's compare the mixtures based on the rate law:
Mixture 1: Rate = k(x)\([High\ NO]^2\) [High O\(_2\)] = k(High NO^2)(High O\(_2\))
Mixture 2: Rate = k([Low NO\(]^2\))[High O\(_2\)] = k(Low NO^2)(High O\(_2\))
Mixture 3: Rate = k([High NO\(]^2\))[Low O\(_2\)] = k(High NO^2)(Low O\(_2\))
Since the rate is second order in NO, the effect of NO concentration is more significant than that of O\(_2\). Mixture 1 has both high NO and high O\(_2\)concentrations, which results in the highest rate among the three mixtures.
Therefore, the fastest initial rate occurs in mixture 1.
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A local hamburger shop sold a combined total of 620 hamburgers and cheeseburgers on Wednesday. There were 70 more cheeseburgers sold than hamburgers. How many hamburgers were sold on Wednesday?
Answers
The number of hamburgers sold on Wednesday is 275.
Let's assume the number of hamburgers sold is x.
According to the given information, the number of cheeseburgers sold is 70 more than the number of hamburgers. So, the number of cheeseburgers sold can be expressed as x + 70.
The total number of hamburgers and cheeseburgers sold is given as 620, so we can set up the following equation:
x + (x + 70) = 620
Combining like terms, we get:
2x + 70 = 620
Subtracting 70 from both sides of the equation:
2x = 550
Dividing both sides by 2:
x = 275
Therefore, the number of hamburgers sold on Wednesday is 275.
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235U+n 144 Ba + Kr +3,n Which of the following is the atomic mass X of Kr in the fission reaction shown?
a) 86 u
b) 88 u
c) 89 u
d) 92 u
Answers
The atomic mass X of Kr in the fission reaction is: C. 89u.
How to determine the atomic mass X?To determine the atomic mass X of Kr in the fission reaction 235U + n -> 144Ba + Kr + 3n, we need to apply the principle of conservation of mass:
Initial mass = Final mass
Initially, we have 235U and one neutron (n), so the total initial mass is 235 + 1 = 236 units. After the fission reaction, we have 144Ba, Kr, and 3 neutrons. The total final mass should also be 236 units.
Now, let's find the atomic mass X of Kr:
Initial mass = 144Ba + Kr + 3n
236 = 144 + X + 3
Since the mass of a neutron (n) is 1 unit, the equation becomes:
236 = 144 + X + 3
Solve for X:
X = 236 - 144 - 3
X = 89
Therefore, the atomic mass X of Kr in the fission reaction is 89 units, making the correct answer (c) 89 u.
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In the video, the semipermeable membrane separates the two solutions of different concentrations. Watch the video and identify which of the following statements are correct Check all that apply. View Available Hints) The solvent can ideally move in both directions through the semipermeable membrane. Solute particles can move in both directions through the semipermeable membrane. Osmosis occurs when the solvent molecules move from a solution of higher solute concentration to a solution of lower solute concentration A pressure equal to that of the osmotic pressure will result in reverse osmosis. The movement of the solvent particles from the concentrated solution to the dilute solution is known as reverse osmosis.
Answers
In the video, the semipermeable membrane separates the two solutions of different concentrations.
B. The solvent can ideally move in both directions through the semipermeable membrane.
D. The movement of the solvent particles from the concentrated solution to the dilute solution is known as reverse osmosis.
Examples of solvents Water, ethanol, methanol, and acetone are a few typical examples of solvents. A substance that can dissolve a certain solute and combine with it to produce a solution is referred to as a "solvent."
Osmosis is the movement of a solvent through a semipermeable membrane to separate two solutions with different solute concentrations. Osmosis is the process by which a solvent is transferred from a solution with a lower solute concentration to one with a greater solute concentration.
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Which 2 layers of Erath are similar?
Answers
According to the research, the correct answer is that inner core and the outer core are geological layers of the Earth, which are similar in composition and both are extremely hot.
What is the core of the Earth?It refers to the innermost sector of the planet, being the layer formed mainly by iron and nickel whose internal pressure is higher than the pressure of the earth's surface.
In this sense, the inner core and outer core of the Earth are composed of iron-nickel or alloys thereof, with some other elements exhibiting high temperatures but unlike the solid inner core of the Earth, the outer core is liquid since there is not enough pressure to keep it in a solid state.
Therefore, we can conclude that according to the research, a wide range of concentrations of iron and nickel is found in the outer and inner core of the Earth.
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which type of compound is not classified as an aliphatic hydrocarbon?
Answers
The type of compound that is not classified as an aliphatic hydrocarbon is an aromatic compound.
What are aliphatic hydrocarbons?
Aliphatic hydrocarbons are organic compounds that consist of only hydrogen and carbon atoms arranged in an open chain. These are known as alkanes, alkenes, and alkynes.
Aromatic hydrocarbons, on the other hand, are compounds that contain benzene rings or other similar aromatic rings.
a) Alkynes:
Alkynes are hydrocarbons that have at least one triple bond between their carbon atoms. Ethyne, propyne, and butyne are examples of alkynes. They are more reactive than alkenes because the triple bond can be broken to form new bonds with other atoms.b) Aromatic hydrocarbons:
Aromatic hydrocarbons are organic compounds that contain one or more benzene rings. Benzene, toluene, and naphthalene are examples of aromatic hydrocarbons. They are more stable and less reactive than alkanes, alkenes, and alkynes. Aromatic compounds are not classified as aliphatic hydrocarbons.c) Cycloalkanes:
Cycloalkanes are hydrocarbons that have one or more rings of carbon atoms in which each carbon atom has two single bonds and two hydrogen atoms attached. Cyclopropane, cyclobutane, and cyclopentane are examples of cycloalkanes. They are more reactive than alkanes because of the strain caused by the ring structure.d) Alkenes:
Alkenes are hydrocarbons that have at least one double bond between their carbon atoms. Ethene, propene, and butene are examples of alkenes. They are more reactive than alkanes because the double bond can be broken to form new bonds with other atoms.e) Alkanes:
Alkanes are hydrocarbons that have only single covalent bonds between their carbon atoms. Methane, ethane, propane, and butane are some examples of alkanes. They are also known as saturated hydrocarbons because they contain the maximum amount of hydrogen possible, which makes them less reactive.Therefore, the type of compound that is not classified as an aliphatic hydrocarbon is an aromatic compound.
Which type of compound is not classified as an aliphatic hydrocarbon?
a) alkyne
b) aromatic
c) cycloalkane
d) alkene
e) alkane
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Which of the following solutions will have a pH of 11.0?
a. 11 M Sr(OH)2
b. 1 × 10-11 M NH3
c. 1 × 10-11 M HCl
d. 1 × 10-3 M NH4+
e. 1 × 10-3 M NaOH
Answers
Among the given solutions, option (e) 1 × 10-3 M NaOH is the only one that will have a pH of 11.0.
NaOH is a strong base that dissociates completely in water to form Na+ and OH- ions. The OH- ions react with water to form hydroxide ions, which are responsible for the basic nature of the solution.
The pH of a basic solution is determined by the concentration of hydroxide ions present in the solution. A pH of 11.0 corresponds to a hydroxide ion concentration of 1 × 10-3 M.
Options (a) and (b) are basic solutions, but their concentrations are much higher or lower than the required concentration for a pH of 11.0. Options (c) and (d) are acidic solutions and cannot have a pH of 11.0.
Therefore, the correct option is (e) 1 × 10-3 M NaOH, which will have a pH of 11.0 due to the high concentration of hydroxide ions.
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What is the coordination number for Potassium Nitrate?
Answers
Answer:
The coordination number is 8
Potassium nitrate has an octahedral coordination structure
What coeffecient should be placed in the blanks in order to balance the chemical
equation?
PCL5 +
H20
HCl + H3PO4
2.2
4, 5
3,8
1,6
Answers
Answer:
Sorry I am not good at chemistry.
Explanation:
Which of the following is true for the equilibrium constant of a reaction?
A. It is a ratio of coefficients of reactants to products.
B. It has a different value at different temperatures.
C. It is represented by the symbol H.
D. Its value is always less than 1.
Answers
The equilibrium constant of a reaction, represented by the symbol K, is a measure of the extent to which a reaction proceeds to form products at a given temperature. The correct answer is B.
It is calculated as the ratio of the concentrations (or partial pressures) of the products to the concentrations (or partial pressures) of the reactants, each raised to the power of its stoichiometric coefficient in the balanced chemical equation. The value of K is not necessarily less than 1, and it is not represented by the symbol H. However, option B is correct, as the value of K depends on the temperature at which the reaction occurs.
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Sugar could be classified as which of the following?Question 5 options:compoundsolution (homogenous)elementmechanical mixture (heterogenous)
Answers
Compound, according to our last session.
What is the pressure in millimeters of mercury inside a container of gas.
Answers
The chemical equation, Cr + Fe(NO3)2 → Fe + Cr(NO3)3, is an example of which type of reaction?
Answers
Answer:
Redox type
Explanation:
The reaction is:
2Cr + 3Fe(NO₃)₂ → 2Fe + 2Cr(NO₃)₃
2 moles of chromium can react to 3 moles of iron (II) nitrate in order to produce 2 moles of iron and 2 moles of chromium nitrate.
If we see oxidation state, we see that chromium changes from 0 to +3
Iron changed the oxidation state from +2 to 0
Remember that elements at ground state has 0, as oxidation state.
Iron is being reduced while chromium is oxidized. Then, the half reactions are:
Fe²⁺ + 2e⁻ ⇄ Fe (Reduction)
Cr ⇄ Cr³⁺ + 3e⁻ (Oxidation)
When an element is being reduced, while another is being oxidized, we are in prescence of a redox reaction.
The elasticity coefficient for an enzyme in a multistep pathway depends on:
A) the concentration of the enzyme itself.
B) the levels of regulatory molecules.
C) the amounts of substrate molecules present at each step.
D) both A and C.
E) both B and C.
Answers
The elasticity coefficient for an enzyme in the multistep pathway will depends on the concentration of the enzyme itself and the amounts of the substrate molecules present at each step. Option D is correct.
The elasticity coefficient is a measure of the sensitivity of the rate of the overall reaction to changes in the concentrations of the individual enzymes or substrates in the pathway. A higher elasticity coefficient indicates that the reaction rate is more sensitive to changes in that particular component.
In a multistep pathway, the elasticity coefficient of each enzyme depends on its own concentration as well as the concentrations of the substrates and products that it interacts with in its particular step of the pathway.
Therefore, both the concentration of the enzyme and the amounts of substrate molecules present at each step can affect the elasticity coefficient of an enzyme in a multistep pathway. The levels of regulatory molecules (option B) may also affect the elasticity coefficient of an enzyme, but this is not the only factor that determines it.
Hence, D. is the correct option.
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Select all of the following that have a standard enthalpy of formation equal to zero at
25°C and 1. 0 atm?
Si (s)
H20 (1)
N2 (g)
Al (s)
CH4 (g)
H2O(g) Br2 (l)
Answers
At 25°C and 1.0 atm, the substances with a standard enthalpy of formation equal to zero are Si (s), N2 (g), and Al (s).
The standard enthalpy of formation (∆Hf°) is defined as the change in enthalpy when one mole of a substance is formed from its constituent elements in their most stable form under standard conditions (25°C and 1.0 atm). For an element in its most stable form at these conditions, the standard enthalpy of formation is zero.
Si (s), N2 (g), and Al (s) have a standard enthalpy of formation equal to zero at 25°C and 1.0 atm because they are in their most stable elemental forms under these conditions.
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3. Elemental phosphorus can be reacted with elemental chlorine to form phosphorus pentachloride, used to make lithium ion batteries. The AH° = -886 kJ for this reaction. How much heat can be released in kJ if 75 grams of phosphorus are reacted with excess chlorine?
Answers
The amount of heat released in kJ when 75 grams of phosphorus react with excess chlorine is 858.848 kJ.
Heat of reactionMolar mass of P = 30.97 g/molMolar mass of PCl5 = 208.24 g/mol.Moles of P = mass of P / molar mass of P = 75 g / 30.97 g/mol = 2.42 moles
From the balanced chemical equation, 2 moles of P react with 5 moles of Cl2 to form 2 moles of PCl5.
Moles of PCl5 = (2.42 moles P / 2 moles PCl5) x (2 moles PCl5 / 5 moles Cl2) = 0.968 moles
Heat released = moles of PCl5 x AH° = 0.968 moles x (-886 kJ/mol) = 858.848 kJ
In other words, the amount of heat released in kJ when 75 grams of phosphorus react with excess chlorine is approximately 858.848 kJ.
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what is the density of an 85.7 g sample of unknown susbstance if the sample occupies 32.4mL
Answers
Answer:
m= 85.7g
V= 32.4mL
d= m/V
d= 2.65g/mL
Arne and Nancy use a metal alloy that is 21.174% copper to make jewelry. How many ounces of an alloy that is 17% oopper must be mixed with an alloy that is 25%. copper to form 138 ounces of the desired alloy? Round to the nearest whole number. A. 72 ounces B. 77 ounces C. 68 ounces D. 66 ounces
Answers
The number of ounces of the 17% copper alloy needed is approximately 66 ounces (D).
To solve this problem, we'll set up a system of equations to represent the given information.
Let x be the number of ounces of the 17% copper alloy.
Let y be the number of ounces of the 25% copper alloy.
We know that the total weight of the two alloys combined is 138 ounces, so we have the equation:
x + y = 138 (Equation 1)
We also know that the desired alloy should have a copper content of 21.174%, so we have the equation:
(0.17x + 0.25y) / 138 = 0.21174 (Equation 2)
To solve this system of equations, we can use the substitution method.
From Equation 1, we can solve for x:
x = 138 - y
Substituting this value of x into Equation 2, we have:
(0.17(138 - y) + 0.25y) / 138 = 0.21174
Simplifying the equation:
23.46 - 0.17y + 0.25y = 29.21212
Combining like terms:
0.08y = 5.75212
Dividing both sides by 0.08:
y = 71.9
Rounding to the nearest whole number, y ≈ 72 ounces.
Substituting this value of y back into Equation 1, we can solve for x:
x = 138 - y
x = 138 - 72
x = 66
Therefore, the number of ounces of the 17% copper alloy needed is approximately 66 ounces (D).
To form 138 ounces of an alloy that is 21.174% copper, Arne and Nancy need to mix approximately 66 ounces of an alloy that is 17% copper with approximately 72 ounces of an alloy that is 25% copper.
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HELP please, 50 points 5 minutes timed
Answers
Answer:
Coordinate geometry is one of the most important and exciting ideas of mathematics. In particular it is central to the mathematics students meet at school. It provides a connection between algebra and geometry through graphs of lines and curves. This enables geometric problems to be solved algebraically and provides geometric insights into algebra.
The invention of calculus was an extremely important development in mathematics that enabled mathematicians and physicists to model the real world in ways that was previously impossible. It brought together nearly all of algebra and geometry using the coordinate plane. The invention of calculus depended on the development of coordinate geometry.
Explanation:
How much more average Kinetic Energy do molecules have at 50°C compared to 25°C?
Answers
The kinetic energy is 0.5177 × 10⁻²¹ J more at 50°C compared to 25°C.
The average kinetic energy of a molecule is directly proportional to the absolute temperature of a gas.
KE = ( 3/2 ) ( R / Nₐ ) T
Where T is the temperature of the molecule, R is the gas constant, and Nₐ is Avogadro's number.
Now, R = 8.314 J/mol.K
Avogadro's number, Nₐ = 6.022 × 10²³ atoms/ mol
The average kinetic energy at 50° C is:
T = 50° C = 323 K
KE₁ = ( 3/2 ) × ( R / Nₐ ) × T₁
KE₁ = ( 3 × 8.314 × 323 ) / ( 2 × 6.022 × 10²³ )
KE₁ = 668.90 × 10⁻²³ J
KE₁ = 6.6890 × 10⁻²¹ J
The average kinetic energy at 25°C is:
KE₂ = ( 3/2 ) × ( R / Nₐ ) × T₂
KE₂ = ( 3 × 8.314 × 298 ) / ( 2 × 6.022 × 10²³ )
KE₂ = 617.13 × 10⁻²³ J
KE₂ = 6.1713 × 10⁻²¹ J
Now,
The average kinetic energy of the molecules at 50° C compared to 25° C is:
KE = KE₁ - KE₂
KE = 6.6890 × 10⁻²¹ - 6.1713 × 10⁻²¹
KE = 0.5177 × 10⁻²¹ J
Hence, the average kinetic energy is 0.5177 × 10⁻²¹ J more at 50° C compared to 25° C.
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ethane and ethene are both reacts with water and sulfuric acid as catalyst. what are the resulting products?
Answers
Ethanol is produced when ethane and ethene react with water and a catalyst like sulfuric acid. Adding concentrated sulfuric acid to hot ethanol (acts as a catalyst).
To eliminate carbon dioxide and sulphur dioxide that are created as byproducts, the gases are passed through a sodium hydroxide solution. The main product that is gathered over water is ethene. As a result, dehydration of ethanol produces ethene rather than ethane. The names Mattling acid and Oil of Vitriol are other names for sulfuric acid. It is highly caustic and acidic in nature. It dehydrates and oxidises when present in higher amounts. It is a clear, syrup-like liquid with no colour or smell. A substance having the chemical formula C 2H 6, ethane is an organic chemical.
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An unknown gas diffuses 0.25 times as fast as He, What is the molecular mass of the
unknown gas?
Answers
The molecular mass of the unknown gas = 64g/mol
The rate of diffusion of a gas is inversely proportional to the square root of its molecular mass. Let the molecular mass of the unknown gas be M. Then, we have:
Rate of diffusion of unknown gas / Rate of diffusion of He = sqrt(MHe / M)
Since the rate of diffusion of the unknown gas is 0.25 times that of He, we can write:
0.25 = sqrt(MHe / M)
Squaring both sides, we get:
0.0625 = MHe / M
M = MHe / 0.0625
The molecular mass of He is approximately 4 g/mol. Substituting this value, we get:
M = 4 / 0.0625
M = 64 g/mol
Therefore, the molecular mass of the unknown gas is approximately 64 g/mol.
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The ions formed when ch₃oh dissociates in water are?
Answers
The ions formed when ch₃oh dissociates in water are Hydrogen ions (H+) and hydroxide ions (OH-).
What ions are formed when ch₃oh dissociates in water?
In water, CH3OH, generally referred to as methanol, splits into hydrogen ions (H+) and hydroxide ions (OH-). The hydrogen and oxygen atoms in the CH3OH molecule interact with one another as a result of the solvent effect of water molecules, dissolving the molecule into its component ions. The solution is electrically conductive because these ions are free to move about and take part in chemical processes. Ionization, the process of turning a neutral substance into ions, is illustrated by the dissociation of CH3OH in water. The pH of the solution—a measurement of how acidic or basic the solution is—can be impacted by this ionisation. Biological and chemical processes may be significantly impacted by the dissociation of CH3OH in water.Hence the ions formed are Hydrogen ions (H+) and hydroxide ions (OH-).
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what is represented by the line ab? enter one of the following choices: solid, liquid, gas, melting solid, boiling liquid what constant do you use to calculate the heat absorbed here? enter one of the following: csolid, cliquid, cgas, heat of fusion, heat of vaporization what is represented by the line bc? enter one of the following choices: solid, liquid, gas, melting solid, boiling liquid what constant do you use to calculate the heat absorbed here? enter one of the following: csolid, cliquid, cgas, heat of fusion, heat of vaporization what is represented by the line cd? enter one of the following choices: solid, liquid, gas, melting solid, boiling liquid what constant do you use to calculate the heat absorbed here? enter one of the following: csolid, cliquid, cgas, heat of fusion, heat of vaporization what is represented by the line de? enter one of the following choices: solid, liquid, gas, melting solid, boiling liquid what constant do you use to calculate the heat absorbed here? enter one of the following: csolid, cliquid, cgas, heat of fusion, heat of vaporization what is represented by the line ef? enter one of the following choices: solid, liquid, gas, melting solid, boiling liquid what constant do you use to calculate the heat absorbed here? enter one of the following: csolid, cliquid, cgas, heat of fusion, heat of vaporization
Answers
Solid, Heat of fusion, Liquid, Heat of vaporization, and Gas are the answers for the following questions represented by the graph.
At phase transition temperature is constant so BC & DE represent phase transition.
1)AB represents solid here \(C_{solid}\) constant use to calculate heat absorbed here.
2)BC represents melting solid here heat of fusion is constantly used to calculate heat absorbed here.
3)CD represents liquid here \(C_{liquid}\) constant use to calculate heat absorbed here.
4)DE represents Boiling liquid here Heat of vaporization is constant used to calculate heat absorbed here.
5)EF represents gas here \(C_{gas}\) constant used to calculate heat absorbed here.
An alteration in the state from one phase to another is known as a phase transition. A phase transition is identified by a sudden change in one or more physical attributes accompanied by a minute change in temperature.
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We wish to determine how many grams
of solid silver chromate will precipitate
when 150. mL of 0.500 M silver nitrate
solution is added to excess potassium
chromate.
2AgNO3(aq)
How many moles of AgNO3 are present
in 150. mL of 0.500 M AgNO3?
+ K₂ CrO4 (aq) → Ag₂ CrO4(s) + 2KNO3(aq)
Answers
Approximately 12.45 grams of solid silver chromate will precipitate when 150 mL of 0.500 M silver nitrate solution is added to excess potassium chromate.
To determine the number of moles of AgNO3 present in 150 mL of a 0.500 M AgNO3 solution, we can use the formula:
moles = concentration × volume
Given:
Concentration of AgNO3 solution = 0.500 M
Volume of AgNO3 solution = 150 mL
First, we need to convert the volume from milliliters (mL) to liters (L) since the concentration is given in moles per liter (M).
1 L = 1000 mL
Therefore, the volume of the AgNO3 solution in liters is:
150 mL × (1 L / 1000 mL) = 0.150 L
Now we can calculate the moles of AgNO3 using the formula:
moles = concentration × volume
moles = 0.500 M × 0.150 L
moles = 0.075 mol
So, there are 0.075 moles of AgNO3 present in 150 mL of the 0.500 M AgNO3 solution.
Now, let's proceed to determine how many grams of solid silver chromate (Ag2CrO4) will precipitate when the AgNO3 solution reacts with excess potassium chromate (K2CrO4).
From the balanced chemical equation:
2AgNO3(aq) + K2CrO4(aq) → Ag2CrO4(s) + 2KNO3(aq)
We can see that the molar ratio between AgNO3 and Ag2CrO4 is 2:1. Therefore, for every 2 moles of AgNO3, we will form 1 mole of Ag2CrO4.
Since we have 0.075 moles of AgNO3, we can calculate the moles of Ag2CrO4 formed:
moles of Ag2CrO4 = 0.075 mol / 2 = 0.0375 mol
To determine the mass of Ag2CrO4, we need to multiply the moles by its molar mass. The molar mass of Ag2CrO4 is calculated by summing the atomic masses of each element in the compound:
Ag2CrO4 = 2(Ag) + 1(Cr) + 4(O) = 2(107.87 g/mol) + 1(52.00 g/mol) + 4(16.00 g/mol) = 331.87 g/mol
mass of Ag2CrO4 = moles of Ag2CrO4 × molar mass of Ag2CrO4
mass of Ag2CrO4 = 0.0375 mol × 331.87 g/mol = 12.45 g
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Which of the following best represents Boyle's Law?A) The pressure of a gas exerted on the walls of its container is directly proportional to the volume of the gas when the temperature of the gas remains constant.B) The volume of a gas inside a container is inversely proportional to the temperature of the gas when the pressure of the gas remains constant.C) The volume of a gas inside a container is directly proportional to the temperature of the gas when the pressure of the gas remains constant.D) The pressure of a gas exerted on the walls of its container is directly proportional to the temperature of the gas when the volume of the gas remains constant.E) The pressure of a gas exerted on the walls of its container is inversely proportional to the temperature of the gas when the volume of the gas remains constant.F)The pressure of a gas exerted on the walls of its container is inversely proportional to the volume of the gas when the temperature of the gas remains constant.
Answers
Answer
F) The pressure of a gas exerted on the walls of its container is inversely proportional to the volume of the gas when the temperature of the gas remains constant.
Explanation
Boyle's law states that the volume of a given mass of gas varies inversely with the pressure when the temperature is kept constant. An inverse relationship is described in this way. As one variable increases in value, the other variable decreases. He discovered that doubling the pressure of an enclosed sample of gas, while keeping its temperature constant, caused the volume of the gas to be reduced by half.
can you also include how you solved it(;´༎ຶٹ༎ຶ`)
Answers
Answer:
1=
25000 ml
2=
300 mm
3=
350m
Which is more reactive, calcium or potassium ?
Answers
Answer:
the answer is potassium
Explanation:
Potassium has only one valence electron. ... Whereas, calcium has two valence electrons, so it requires more energy for the removal of a valence electron. Due to this potassium is more reactive than calcium.
Bye Have A Great Day! =)Indicate the charge the following elements as they achieve the noble gas configuration.
Ga O Br P Rb As
S Mg Al Se Li I
Answers
Answer:
See explanation
Explanation:
Ga is in group 13 hence it must loose three electrons to form Ga^3+ in order to achieve the noble gas configuration because it has three electrons on its outermost shell.
O is in group 16 hence it must accept two electrons in order to attain the noble gas configuration to form O^2- since oxygen has six electrons on its outermost shell.
Br in group 17 has seven electrons in its outermost shell hence it must form Br^- (gain one electron) in order to attain the noble gas configuration.
P in group 15 must accept three electrons and form P^3- in order to attain the noble gas configuration since it has five electrons on its outermost shell.
S is in group 16 hence it must accept two electrons in order to attain the noble gas configuration to form S^2- since sulphur has six electrons on its outermost shell.
Mg in group 2 has two electrons on its outermost shell and must loose both to attain the noble gas configuration forming Mg^2+.
Al is in group 13 hence it must loose three electrons to form Al^3+ in order to achieve the noble gas configuration because it has three electrons on its outermost shell.
Se is in group 16 hence it must accept two electrons in order to attain the noble gas configuration to form Se^2- since selenium has six electrons on its outermost shell.
Lithium is in group 1 and must loose its only outermost electron in order to attain the noble gas configuration to form Li^+.
Rb is in group 1 and must loose its only outermost electron in order to attain the noble gas configuration to form Rb^+.
As in group 15 must accept three electrons and form As^3- in order to attain the noble gas configuration since it has five electrons on its outermost shell.
I in group 17 has seven electrons in its outermost shell hence it must form I^- (gain one electron) in order to attain the noble gas configuration.