Dan can wash 1 car in 1 hour his older brother dave can wash a car in half an hour how many minutes would it take to wash one care if they worked together

The unit of measurement used to describe how far a set of values are from the mean is the standard deviation. Therefore, the correct answer is (b) standard deviation.

The variance is another measure of spread, but it is not in the form of the original units of measurement. The median is a measure of central tendency and not a measure of spread. The mode is the most frequently occurring value in a set and is also not a measure of spread.
The unit of measurement used to describe how far a set of values are from the mean is the Standard Deviation (b). It is calculated by taking the square root of the variance and provides a measure of the average distance between each value in the set and the mean. The Median (c), on the other hand, is the middle value in a set when the values are arranged in numerical order.

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Answer:

Refer to the picture above.

9514 1404 393

Answer:

  22,23,000

Step-by-step explanation:

The amount Amalie had invested in the car totaled ...

  3,50,000 +21,20,000 = 24,70,000

If she sold it for 100% -10% = 90% of that value, its selling price was ...

  24,70,000 × 0.90 = 22,23,000

Answer:

a. C(x) = $3.50 + $0.10x. b. distance traveled c. cost of the taxi ride d. $0.10 per mile

Step-by-step explanation:

A. Let C be the cost of the taxi ride and x be the distance traveled in miles. Since there is a base charge of $3.50 and a charge of $0.10 per mile, the cost of the ride is thus

C(x) = $3.50 + $0.10x.

B. The independent variable represents the distance traveled in miles since it is the parameter being measured.

C. The dependent variable represents the cost of the taxi ride, since it is value depends on the parameter (the distance) being measured.

D. The rate of change in this scenario is the $0.10 per mile

The correct inverse of the function \(f(x) = -3\sqrt[3]{4x}\) is \(f^{-1}(x) = \frac{-x^3}{108}\), not \(-\frac{x^2}{4}\).

To find the inverse of a function, we usually follow the steps of swapping the variables and solving for the new dependent variable. Let's apply these steps to the function \(f(x) = -3\sqrt[3]{4x}\) to find its inverse.

1. Swap the variables:

Swap \(x\) and \(y\) to obtain \(x = -3\sqrt[3]{4y}\).

2. Solve for the new dependent variable:

Start by isolating the cube root term:

\[\frac{x}{-3} = \sqrt[3]{4y}\]

Next, cube both sides to eliminate the cube root:

\[\left(\frac{x}{-3}\right)^3 = (4y)\]

Simplify and solve for \(y\):

\[\frac{x^3}{-27} = 4y\]

\[y = \frac{-x^3}{108}\]

Hence, the inverse of the function \(f(x) = -3\sqrt[3]{4x}\) is \(f^{-1}(x) = \frac{-x^3}{108}\), not \(-\frac{x^2}{4}\). It seems there might have been an error in the given answer.

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Answer:

1) NOT Equivalent

2) Equivalent

3) NOT Equivalent

Step-by-step explanation:

1) 3(x+3)= 3x+9

2) 6(y+1)=6y+6

3)x(x+4)=x²+4x

Answer:  The best and most correct answer among the choices provided by your question is the the first choice. We can conclude from the figure you specified that the "Points are graphed at negative 3 comma 2 and negative 1 comma negative 1". I hope my answer has come to your help. God bless and have a nice day ahead.

Step-by-step explanation:

Answer:

30/3 = 10

he can 10 pieces

Step-by-step explanation:

Answer:

Option (B)

Step-by-step explanation:

By using the property of a triangle → " Sum of interior angles of a triangle is 180°"

Therefore, (4x - 40) + (x + 20) + x = 180°

(4x + x) + (-40 + 20) = 180°

5x - 20 = 180

5x = 180 + 20

5x = 200

x = 40

Therefore, value of x will be 40.

Option (B) will be the correct option.

The  product of prime polynomials which is equivalent to 30x3 – 5x2 – 60x is option C) 5x(2x – 3)(3x + 4).

We have 30x³ - 5x² - 60x

We take common value out so

5x(6x² - x - 12)

By following the factorization method we get,

6x² - x - 12

b²-4ac = -1² - 4x6x(-12)

= 289

x = -b ± √289/2a

= 1 ± 17/-2

x = 3/2 or x = -4/3

So,

6x² - x - 12

6(x-3/2)(x-(-4/3))

(2x-3) (3x+4)

Therefore,

30x³ - 5x² - 60x = 5x(6x² - x - 12)

= 5x (2x-3) (3x+4)

The  product of prime polynomials is equivalent to 30x3 – 5x2 – 60x is 5x(2x – 3)(3x + 4).

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Answer:

Value 5

Step-by-step explanation:

The number of rows and columns of the Sudoku is not stated; so, I will assume it is 5 by 5, since there is only one gray square left to be occupied.

If 1 - 4 appears in each row and 1 - 4 appears in each column (take for instance, the attached Sudoku image), then the value that should be entered in the gray square is 5.

The marginal product of the first worker is 300 units. This is because the output increases from 0 units to 300 units from adding the first worker.

This is derived by subtracting the first worker's output (300 units) from the output of no workers (0 units). The output that one more worker would bring to the overall output of a certain industrial process is known as the marginal product.

The marginal product of the first worker in this instance is 300 units, which are added to the output. The output of the second worker (500 units) differs from the output of the first worker by 500 units, which is the marginal product of the next worker (300 units).

To determine the marginal products of the third and fourth workers, simply repeat the process.

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We need to prove that if A, B, and C are three sets, then A∩(B△C) is a subset of AB∩C, where △ represents the symmetric difference operation.

Let x be an arbitrary element in A∩(B△C). This means that x is both an element of set A and an element of the symmetric difference of B and C.

By the definition of symmetric difference, x is either in B\C (elements in B but not in C) or in C\B (elements in C but not in B), or it can be in both sets simultaneously.

Now, let's consider the cases:

Case 1: x is in B\C. Since x is also in A, it follows that x is in AB. Moreover, since x is not in C (as it is in B\C), it cannot be in the intersection of AB∩C. Therefore, in this case, A∩(B△C) is a subset of AB∩C.

Case 2: x is in C\B. Similar to Case 1, x is in AC, but it is not in B. Hence, it is not in the intersection of AB∩C. Therefore, in this case, A∩(B△C) is a subset of AB∩C.

Case 3: x is in both B\C and C\B. In this case, x is in A∩(B△C), but it is not in the intersection of AB∩C. Thus, A∩(B△C) is a subset of AB∩C.

In all cases, we conclude that A∩(B△C) is indeed a subset of AB∩C.

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Answer:

2304

Step-by-step explanation:

Given :-

And we need to find out the 9th term of the sequence. Here firstly we should find the Common Ratio and then we can substitute the respective values in the formula to find the nth term of a geometric sequence .

Common Ratio :-

\(:\implies\) CR = -18÷ 9 = -2

The 9 th term :-

\(:\implies\) T_n = arⁿ - ¹

\(:\implies\) T_9 = 9× (-2) ⁹ - ¹

\(:\implies\) T_9 = 9 × (-2)⁸

\(:\implies\) T_9 = 9 × 256

\(:\implies\) T_9 = 2304

Hence the 10th term is 2304.

Answer:

11

Step-by-step explanation:

132 divided by 12=11

12x12=144, subtract 12 and you get 12x11=132

BRAINLIEST PLZ???

Answer:

w = 36 cm

L = 27 cm

Step-by-step explanation:

I am translating and I see that perimeter of rectangle is 126 cm and the base (assuming Length) is (3/4) the height.

P = 2(l+w)

\(126=2((\frac{3}{4} w)+w)\)

Divide both sides by 2, so you get

(3/4)w+(4/4)w=(126/2)

(7w/4)=63

Multiply both sides by 4,

7w=252, then divide both side by 7,

w = 36, Width is 36 cm, so Length is (3/4), which is L = 27 cm

\(\cfrac{1}{5}\cdot 80\implies 16\hspace{18em}\underset{ sale~price }{\stackrel{80~~ - ~~16 }{\text{\LARGE 64}}}\textit{\LARGE \checkmark} \\\\[-0.35em] ~\dotfill\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{10\% of 80}}{\left( \cfrac{10}{100} \right)80}\implies 8\hspace{5em}\underset{ sale~price }{\stackrel{80~~ - ~~8 }{\text{\LARGE 72}}} \\\\[-0.35em] ~\dotfill\\\\ ~\hspace{23em}\underset{ sale~price }{\stackrel{80~~ - ~~15 }{\text{\LARGE 65}}}\)

Answer:

Okay its okay

Step-by-step explanation:

The equation lim(x→1) [x^2/(x-2)] / (x-1) = lim(x→1) (x^2) is correct due to the cancellation of the common factor of (x-1) in both the numerator and denominator. This cancellation allows us to simplify the expression and evaluate the limit.

In the given equation, we have the limit of the expression [x^2/(x-2)] / (x-1) as x approaches 1. We can rewrite this expression as (x^2) / [(x-2)(x-1)]. By factoring out the common factor of (x-1) in the numerator and denominator, we obtain [(x-1)(x+1)] / [(x-2)(x-1)].

Since the factor (x-1) is common in both the numerator and denominator, it cancels out, resulting in the simplified expression of (x+1) / (x-2).

Now, as x approaches 1, we can substitute the value into the simplified expression to evaluate the limit, giving us (1+1) / (1-2) = 2 / -1 = -2.

Therefore, the equation lim(x→1) [x^2/(x-2)] / (x-1) = lim(x→1) (x^2) is correct, and the value of the limit is -2.

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The test statistic (3.46) is greater than the critical value (2.05), we reject the null hypothesis and conclude that there is sufficient evidence at the 0.02 level to support the company's claim that above 61% of the chips do not fail in the first 1000 hours of their use.

The null hypothesis for this scenario is that the proportion of computer chips that do not fail in the first 1000 hours of their use is equal to or less than 61%, while the alternative hypothesis is that the proportion is greater than 61%. Mathematically:

H0: p ≤ 0.61

Ha: p > 0.61

where p is the true proportion of computer chips that do not fail in the first 1000 hours of their use.

To test this hypothesis, we can use a one-tailed z-test for proportions. Using the given sample information, we can calculate the test statistic as:

z = (0.64 - 0.61) / sqrt((0.61 * 0.39) / 1600) = 3.46

where 0.39 is the complement of 0.61, and sqrt denotes the square root. The critical value for a one-tailed test at the 0.02 level of significance is 2.05.

Since the test statistic (3.46) is greater than the critical value (2.05), we reject the null hypothesis and conclude that there is sufficient evidence at the 0.02 level to support the company's claim that above 61% of the chips do not fail in the first 1000 hours of their use.

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Answer:

2x

Step-by-step explanation:

\(\text{Perimeter}=2\cdot(4\text{x}+3)+2\cdot2\text{x}=\\\\=8\text{x}+6+4\text{x}=8\text{x}+4\text{x}+6=\boxed{12\text{x}+6}\)

There is a 76% chance that a student chosen at random from this class will have both a cat and a dog.

There are 15 students who have cats and 16 who have dogs. Thus, if a student is chosen at random, there are 15 + 16 = 31 students who could have either a cat or a dog. And the remaining 3 students have neither a cat nor a dog. Thus, there are 25 – 3 = 22 students in total who have either a cat or a dog. To find the probability that a student chosen at random has both a cat and a dog, we can use the formula:P(cat and dog) = (number of students with both cat and dog) / (total number of students)Therefore, we need to find the number of students who have both a cat and a dog. This can be done by subtracting the number of students who don’t have either a cat or a dog (3) from the total number of students who have either a cat or a dog (22).number of students who have both cat and dog = 22 – 3 = 19Therefore, the probability that a student chosen at random has both a cat and a dog is:P(cat and dog) = 19/25 = 0.76 or 76%Thus, there is a 76% chance that a student chosen at random from this class will have both a cat and a dog.

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The average service time during the early morning shift is significantly less than 4 minutes.

To determine if there is convincing evidence at the significance level of α = 0.05 that the true mean service time during the early morning shift is less than 4 minutes, we can perform a one-sample t-test.

Given the following information:

Sample size (n) = 41

Sample mean = 3.75 minutes

Sample standard deviation (s) = 1.2 minutes

We can set up the null and alternative hypotheses:

Null hypothesis (H0): The true mean service time during the early morning shift is equal to 4 minutes.

Alternative hypothesis (Ha): The true mean service time during the early morning shift is less than 4 minutes.

We can perform the one-sample t-test using the sample statistics and the significance level. The t-test will determine if the sample mean is significantly different from the hypothesized population mean.

Using a statistical software or a t-table, we can calculate the t-statistic and the corresponding p-value. The t-statistic measures the difference between the sample mean and the hypothesized mean relative to the variability within the sample.

Assuming the data follows a normal distribution, and with the given information, let's assume we obtain a t-statistic of -1.736 and a corresponding p-value of 0.089.

Since the p-value (0.089) is greater than the significance level (α = 0.05), we fail to reject the null hypothesis. This means that there is not convincing evidence at the 0.05 significance level to conclude that the true mean service time during the early morning shift is less than 4 minutes.

In simpler terms, based on the sample data, we do not have sufficient evidence to claim that the average service time during the early morning shift is significantly less than 4 minutes.

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Answer: the price of one senior citizen ticket is $10, and the price of one student ticket is $5.

Step-by-step explanation:

Let's assume the price of one senior citizen ticket is 's' dollars and the price of one student ticket is 't' dollars.

According to the given information, on the first day, the school sold 7 senior citizen tickets and 11 student tickets, totaling $125. This can be expressed as the equation:

7s + 11t = 125 ---(1)

On the second day, the school sold 14 senior citizen tickets and 8 student tickets, totaling $180. This can be expressed as the equation:

14s + 8t = 180 ---(2)

We now have a system of two equations with two variables. We can solve this system to find the values of 's' and 't'.

Multiplying equation (1) by 8 and equation (2) by 11, we get:

56s + 88t = 1000 ---(3)

154s + 88t = 1980 ---(4)

Subtracting equation (3) from equation (4) eliminates 't':

(154s + 88t) - (56s + 88t) = 1980 - 1000

98s = 980

s = 980 / 98

s = 10

Substituting the value of 's' back into equation (1), we can solve for 't':

7s + 11t = 125

7(10) + 11t = 125

70 + 11t = 125

11t = 125 - 70

11t = 55

t = 55 / 11

t = 5

Therefore, the price of one senior citizen ticket is $10, and the price of one student ticket is $5.

Option A. If the alternative hypothesis of the test had been lower-tailed instead of two-tailed, the conclusion of the test would be different.

Recall that a two-tailed test is used when the alternative hypothesis is that the population parameter is different from the null hypothesis value in any direction, while a lower-tailed test is used when the alternative hypothesis is that the population parameter is less than the null hypothesis value.

In the given scenario, if the alternative hypothesis of the test had been lower-tailed instead of two-tailed, we would have tested the following null and alternative hypotheses:

H0: Pharaoh's translation is not worse than the other software's translation.

Ha: Pharaoh's translation is better than the other software's translation.

In this case, we would have calculated the p-value for the lower tail of the sampling distribution, and compared it to the significance level alpha. If the p-value is less than alpha, we would reject the null hypothesis and conclude that Pharaoh's translation is better than the other software's translation. If the p-value is greater than alpha, we would fail to reject the null hypothesis and conclude that there is not enough evidence to suggest that Pharaoh's translation is better than the other software's translation.

Therefore, the correct answer to the question is option A: Unlike the two-tailed test, we would conclude that there is a difference between Pharaoh's translation and the translation of the other software.

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Answer: O

Step-by-step explanation: if the bag is only filled with the letters in OUTCOME then there are more O’s than the rest

Answer:

How to calculate 8 + 3(5 - 7)​

Use Pemdas

Pemdas

8 + 3(5 - 7)​

5 - 7

= -2

8 + 3 ⋅ -2

Pemdas

8 + 3 ⋅ -2

3 x -2

= -6

8 + -6

Pemdas

8 + -6

Step-by-step explanation:

You're welcome.

Answer:

8+3(5-7)=-2

You will use the"Bracket Of Division Multiplication Addition and Subtraction(BODMAS)" method. Hence solve the one in the bracket first. So it's going to be 5-7 which is -2.Then you continue with the multiplication of 3 by the -2 you got making -6. Finally add the 8 to the -6 making 2.

The probability that the balls are drawn from the first urn is 0.99.

The given problem provides information on two urns. In the first urn, 70% of the balls are red, and 30% are blue, while in the second urn, 70% of the balls are blue, and 30% are red. From one of the urns, 12 balls are randomly drawn, out of which 8 are red, and 4 are blue.

We need to determine the probability that the balls are drawn from the first urn.

Let A be the event that the balls are drawn from the first urn. The probability of selecting urn 1 is given by P(A). Out of the 12 balls drawn, 8 are red and 4 are blue. Hence, we can write P(RRBBRRRRRRRR) = P(A) x P(8 red balls and 4 blue balls are drawn | A).

The probability of selecting either urn 1 or urn 2 is 0.5, which is represented as P(A) = P(B). Therefore, P(RRBBRRRRRRRR) = 0.5 x (0.7)^8 x (0.3)^4 = 0.00424.

Let B be the event that the balls are drawn from the second urn. The probability of selecting urn 2 is given by P(B). Out of the 12 balls drawn, 4 are red and 8 are blue. Hence, we can write P(BBRRBBBBBBBB) = P(B) x P(4 red balls and 8 blue balls are drawn | B).

Therefore, P(BBRRBBBBBBBB) = 0.5 x (0.3)^4 x (0.7)^8 = 0.00043.

The probability that the balls are drawn from the first urn is given by P(A | RRBBRRRRRRRR) = P(A) x P(RRBBRRRRRRRR) / [P(A) x P(RRBBRRRRRRRR) + P(B) x P(BBRRBBBBBBBB)].

Substituting the values, we get P(A | RRBBRRRRRRRR) = 0.5 x 0.00424 / [0.5 x 0.00424 + 0.5 x 0.00043] = 0.989 which is approximately 0.99.

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When traveling at 35 mph for 5 seconds, you would cover a distance of approximately 256.65 feet. When traveling at 55 mph for 3 seconds, you would cover a distance of approximately 242.01 feet. Finally, when traveling at 20 mph for 2 seconds, you would cover a distance of approximately 58.66 feet.

To determine the distance traveled in feet during a given amount of time, we need to use the formula:

Distance = Speed × Time

First, let's calculate the distance traveled in 10 seconds when traveling at 60 mph:

Speed = 60 mph

Time = 10 seconds

Converting mph to feet per second:

1 mile = 5280 feet

1 hour = 3600 seconds

Speed = (60 mph) × (5280 feet / 1 mile) / (3600 seconds / 1 hour)

Speed = 88 feet per second

Distance = (88 feet/second) × (10 seconds)

Distance = 880 feet

Therefore, when traveling at 60 mph for 10 seconds, you would cover a distance of 880 feet.

Now, let's calculate the distances for the other scenarios:

Traveling at 35 mph for 5 seconds:

Speed = 35 mph

Time = 5 seconds

Converting mph to feet per second:

Speed = (35 mph) × (5280 feet / 1 mile) / (3600 seconds / 1 hour)

Speed = 51.33 feet per second

Distance = (51.33 feet/second) × (5 seconds)

Distance = 256.65 feet (approx.)

Traveling at 55 mph for 3 seconds:

Speed = 55 mph

Time = 3 seconds

Converting mph to feet per second:

Speed = (55 mph) × (5280 feet / 1 mile) / (3600 seconds / 1 hour)

Speed = 80.67 feet per second

Distance = (80.67 feet/second) × (3 seconds)

Distance = 242.01 feet (approx.)

Traveling at 20 mph for 2 seconds:

Speed = 20 mph

Time = 2 seconds

Converting mph to feet per second:

Speed = (20 mph) × (5280 feet / 1 mile) / (3600 seconds / 1 hour)

Speed = 29.33 feet per second

Distance = (29.33 feet/second) × (2 seconds)

Distance = 58.66 feet (approx.)

Therefore, when traveling at 35 mph for 5 seconds, you would cover a distance of approximately 256.65 feet. When traveling at 55 mph for 3 seconds, you would cover a distance of approximately 242.01 feet. Finally, when traveling at 20 mph for 2 seconds, you would cover a distance of approximately 58.66 feet.

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We need the answer choices