\(4+25=2+25\)
They are equal because their sums both equal \(29\).
Answer:
4 + 25 is equal to 4 + 25
Step-by-step explanation:
they are equal because both of the equations are the same so that would mean both of the equations would be equal to each other
hope this helps
how would you solve this equation?
Answer:
19,188
Step-by-step explanation:
hope this helps ;)
HELP ME PLEASE
Evaluate each one. Then tell if starting number (100) grew or decreased.
Warm Up
Evaluate.
1. 100(1.08)^20
2. 100(0.95)^25
3. 100(1 - 0.02)^10
4. 100(1 + 0.08)^-10
IS IT DECREASING OR INCREASING??!???
Answer:
Decreased
Step-by-step explanation:
Please answer correctly !!!!!!!!!!!!!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!!!!!!!!
T is a point in the line segment SU
SU = ST + TU
SU = 4x
ST = 2x + 6
TU = 4
\(4x =( 2x + 6 )+ 4 \\ 4x = 2x + 10 \\ 4x - 2x = 10 \\ 2x = 10 \\ x = \frac{10}{2} \\ \\ x = 5\)
x = 5
ST = 2x + 6 = (5×2) + 6
ST = 16HOPE THIS WILL HELP....
Pleas answer it in two minutes
Answer:
61 miles
Step-by-step explanation:
The two triangles are congruent so GF is congruent to PN.
PN = 61
Please help! PLEASEEEE
Add: -3a 2 b 2 , –52 a 2 b 2 , 4a 2 b 2 , 23 a 2 b 2
Answer:
Step-by-step explanation:
Sum of -3a 2 b 2 , –52 a 2 b 2 , 4a 2 b 2 , 23 a 2 b 2=
(-3a 2 b 2)+( –52 a 2 b 2)+ (4a 2 b 2)+(23 a 2 b 2)=
-3a 2 b 2 –52 a 2 b 2 +4a 2 b 2 +23 a 2 b 2=.-28a 2 b 2 is the answer
any point on the perpendicular bisector of a segment is
It is correct to say that any point on the perpendicular bisector of a segment is equidistant from the endpoints of the segment.
Any point on the perpendicular bisector of a segment is equidistant from the endpoints of the segment. What is a perpendicular bisector? A perpendicular bisector is a line that intersects a line segment and forms a 90-degree angle. It divides the line segment into two equal halves.Each point on the perpendicular bisector of a line segment is equidistant from the endpoints of the segment. This means that the distance from any point on the line to one endpoint of the segment is the same as the distance to the other endpoint of the segment.
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what is the domain of validity for csc 0=1/sin 0
a. all real numbers
b. all real numbers except odd multiples of pi/2
c. all real numbers except even multiples of pi/2
d. all real numbers except multiples of pi
The correct answer is (b) all real numbers except odd multiples of π/2. The domain of validity for cscθ (cosecant) is restricted because cosecant is undefined when the sine of an angle is zero.
In the trigonometric identity cscθ = 1/sinθ, the denominator sinθ becomes zero at odd multiples of π/2 (such as π/2, 3π/2, 5π/2, etc.), resulting in a division by zero error. Therefore, the cosecant function is not defined for these values of θ.
For all other real numbers θ, the sine function is non-zero and well-defined, allowing us to calculate the reciprocal of the sine and determine the value of the cosecant. Hence, the domain of validity for cscθ is all real numbers except odd multiples of π/2, as stated in option (b).
It's important to note that in trigonometry, the domain of validity is determined by avoiding any values that would lead to undefined expressions or division by zero errors.
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The domain of validity for csc θ = 1/sin θ is all real numbers except multiples of π, because at these points the sine function equals zero, and division by zero is undefined.
Explanation:In mathematics, the cosecant function (csc), is defined as the reciprocal of the sine function, or 1/sinθ. The domain of a function are all the possible input values that will yield real numbers (output). For the csc function, its domain includes all real numbers except where the denominator is zero because division by zero is undefined.
In the unit circle context, sine equals zero at 0, π, 2π, ..., and the negative counterparts. Basically, these are the multiples of π. Thus, for the csc function, the domain is all real numbers except multiples of π, which matches option d in your choices.
The domain of validity for csc θ = 1/sin θ is all real numbers except multiples of π.
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If you are doing a linear regression, what is the slope of the line predicted by the null hypothesis?
The null hypothesis is that the linear regression model does not exist. This essentially means that the value of all the coefficients is equal to zero.
What is the null hypothesis?
The null hypothesis is a common statistical theory that contends that there is no statistical relationship or significance between any two sets of observed data and measured phenomena for any given single observed variable.
Here,
We have to find out the slope of the line predicted by the null hypothesis if we are doing a linear regression.
We concluded that the null hypothesis states that the slope is equal to zero, and the alternative hypothesis states that the slope is not equal to zero.
Hence, the null hypothesis is that the linear regression model does not exist. This essentially means that the value of all the coefficients is equal to zero.
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What will be the value stored in the variable x after the execution of the following code snippet?
int a = 10;
int b = 20;
int c = 2;
int x = b / a /*c*/;
a) 1
b) 2
c) 4
d) The code has a syntax error
The value stored in the variable x after the execution of the following code snippet will be b) 2.
The right-click context menu option or a combination of hotkeys can be used to add code snippets, which are compact chunks of reusable code, to a code file. Although try-finally and if-else blocks, for example, are frequently used code blocks found in code snippets, you can also use them to add whole classes or methods.
Learn more about using the templates tool to create reusable emails. Applications and web pages use snippets. Snippets are made to be reusable and to add functionality, like connecting various parts of a program.
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2. Which two square roots are used to estimate 43? (1 point)
R 125 and 136
V36 and 149
49 and 64
V25 and 564
Answer:
\(\sqrt{36}\) and \(\sqrt{49}\);
Step-by-step explanation:
Use the perfect square root before "43" and the perfect square root after "43"
Perfect squares roots are 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, .... . These are a number times itself (2 · 2) = 4
Please answer this question now fast in two minutes
Answer:
2 or 3
Step-by-step explanation:
2 is one of them
3 is another of them
3x - 4y =7
3x - 4y =9
Answer:
No solution
Step-by-step explanation:
The data set shows the ages of everyone in a dance class.
5, 24, 24, 24, 24, 24, 24, 25, 25
Select the statement that correctly describes the data.
A. The typical value is 5 because it is the minimum.
B. The typical value is 9 because that is the total number of people.
C. The typical value is 24. Most values are close to 24, except 5, which is an extreme value.
D. The typical value is 25 because it is the maximum.
C because the most shown value is 24
URGENT
What is the distance between the two points (-5, 6) and (8,-4)?
Given parameters:
Coordinates of the two points = (-5, 6) and (8,-4)
Unknown:
Distance between the two points.
To find the distance between two points, use the expression below;
Distance ² = (x₂ - x₁)² + (y₂ - y₁)²
where;
(-5, 6) and (8,-4)
x₂ = 8 , x₁ = -5 , y₂ = -4 and y₁ = 6
Input the parameters and solve;
Distance² = (8-(-5))² + (-4 - (6))²
= 169 + 100
= 269
Distance = \(\sqrt269}\) = 16.4
The distance between the two points is 16.4
Alex knits hats and scarves to sell at a craft market. He can make at most 20 hats and 30 scarves, but no more than 40 items altogether, in time for the market.
Write and graph a system of inequalities that shows the possible numbers of hats and scarves Alex can bring to the craft market if he wants to bring at least 25 items. Identify three (3) possible combinations, and say which he should
choose.
The three (3) possible combinations are
hats = 10, scarves = 30hats = 10, scarves = 20hats = 20, scarves = 20Alex should 20 hats and 20 scarves
How to find the possible combinations Alex can bring to the marketLet the number of scarves be x and y be the number of hats
He can make at most 20 hats and 30 scarves, but no more than 40 items altogether
x ≤ 20
y ≤ 30
x + y ≤ 40 (in time of market)
x + y ≥ 25
The possible combinations are
1 ⇒ x = 10, y = 302 ⇒ x = 10, y = 203 ⇒ x = 20, y = 20He should choose the third option x = 20, y = 20 this allows him to take more products to the show
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Collect like terms g3 add G, squared add, squared add G
Combine like terms , we get \(g^3+3g^2+2g\).
What are Like Terms ?In Algebra, the like terms are defined as the terms that contain the same variable which is raised to the same power. In algebraic like terms, only the numerical coefficients can vary. We can combine the like terms to simplify the algebraic expressions so that the result of the expression can be obtained very easily.
For example, 4x + 10x is an algebraic expression with like terms. In order to simplify this algebraic expression, we can add the like terms. Thus, the simplification of the given expression is 14x. In the same way, you can perform all the arithmetic operations on the like terms.
Collect like terms:
\(g^3+g^2+g+2g^2+g\)
Combine like terms:
\(g^3+3g^2+2g\)
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A coordinate plane. Quadrant 1 is the top right quadrant, quadrant 2 is the top left, quadrant 3 is the bottom left, and quadrant 4 is the bottom right.
A point with a positive x-coordinate and a negative y-coordinate will lie in which quadrant?
Quadrant I
Quadrant II
Quadrant III
Quadrant IV
Answer:
D. im answering for the purpose of the first person getting brainliest
Step-by-step explanation:
Noah is a waiter at a restaurant. Each day he works, Noah will make a guaranteed wage of $30, however the additional amount that Noah earns from tips depends on the number of tables he waits on that day. From past experience, Noah noticed that he will get about $7 in tips for each table he waits on. How much would Noah expect to earn in a day on which he waits on 16 tables? How much would Noah expect to make in a day when waiting on tt tables?
Answer:
noah would make 30+(7x16)=30+112=142$
Step-by-step explanation:
also, what the flip is "tt"
Answer:
$142
Step-by-step explanation:
7 x 16 =112
112 + 30 =142
if the demand curve shifts to the left, what happens to price and quantity?
Answer:
A lower price and quantity would result.
Write the equation of the tangent line to the graph of y = (6x² − 6x + 3)(1 + 2x) at x = 1. Check the reasonableness of your answer by graphing both the function and the tangent line.
To find the equation of the tangent line to the graph of y = (6x^2 − 6x + 3)(1 + 2x) at x = 1, we need to find the slope of the tangent line at that point and use the point-slope form of a line equation. Here's a summary of the solution:
Calculate the derivative of the function y = (6x^2 − 6x + 3)(1 + 2x) using the product rule and simplify the expression.
Evaluate the derivative at x = 1 to find the slope of the tangent line.
Substitute the coordinates of the point (1, f(1)) into the point-slope form of the line equation, where f(1) is the value of the function at x = 1.
Simplify the equation to obtain the equation of the tangent line.
To check the reasonableness of the answer, graph both the function and the tangent line using a graphing tool or software. Plot the function and the tangent line on the same graph to visually verify that the line is indeed tangent to the function at x = 1.
By taking the derivative of the function, evaluating it at x = 1, and applying the point-slope form, you can determine the equation of the tangent line. Graphing both the function and the tangent line together allows you to visually confirm the tangent relationship at x = 1.
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A process gas cylinder sits on a programmable scale. The cylinder weighs 500 lbs empty, and 700 lbs when full of gas. In order to keep the cylinder from running dry, you need to set 2 alarms of scale: a warning for when the gas is 80% gone, and a fault for when the gas is 90% gone. What set points would you enter on the scale for the warning and fault values?
By setting the warning set point to 660 lbs and the fault set point to 680 lbs, you can ensure that the scale will trigger a warning when the gas is 80% gone and a fault when the gas is 90% gone, based on the weights of the cylinder.
To determine the set points for the warning and fault values on the scale, we need to calculate the weights corresponding to 80% and 90% of the total gas in the cylinder.
Given that the cylinder weighs 500 lbs when empty and 700 lbs when full, the total weight of the gas in the cylinder is:
Total Gas Weight = Full Weight - Empty Weight
= 700 lbs - 500 lbs
= 200 lbs
To find the warning set point, which corresponds to 80% of the total gas, we calculate:
Warning Set Point = Empty Weight + (0.8 * Total Gas Weight)
= 500 lbs + (0.8 * 200 lbs)
= 500 lbs + 160 lbs
= 660 lbs
Therefore, the warning set point on the scale should be set to 660 lbs.
Similarly, to find the fault set point, which corresponds to 90% of the total gas, we calculate:
Fault Set Point = Empty Weight + (0.9 * Total Gas Weight)
= 500 lbs + (0.9 * 200 lbs)
= 500 lbs + 180 lbs
= 680 lbs
Therefore, the fault set point on the scale should be set to 680 lbs.
By setting the warning set point to 660 lbs and the fault set point to 680 lbs, you can ensure that the scale will trigger a warning when the gas is 80% gone and a fault when the gas is 90% gone, based on the weights of the cylinder.
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. How many days will it take for $9500 to earn $800 at 8.25% p.a.?
It will take approximately 39.532 days for $9500 to earn $800 at an annual interest rate of 8.25%.
To find the number of days it will take for $9500 to earn $800 at an annual interest rate of 8.25%, we need to use the formula for simple interest:
Interest = Principal * Rate * Time
In this case, we are given the interest ($800), the principal ($9500), and the annual interest rate (8.25%). We need to solve for time.
Let's denote the time in years as "t". Since we're looking for the number of days, we'll convert the time to a fraction of a year by dividing by 365 (assuming a standard 365-day year).
$800 = $9500 * 0.0825 * (t / 365)
Simplifying the equation:
800 = 9500 * 0.0825 * (t / 365)
Divide both sides by (9500 * 0.0825):
800 / (9500 * 0.0825) = t / 365
Simplify the left side:
800 / (9500 * 0.0825) ≈ 0.1083
Now, solve for t by multiplying both sides by 365:
0.1083 * 365 ≈ t
t ≈ 39.532
Therefore, it will take approximately 39.532 days for $9500 to earn $800 at an annual interest rate of 8.25%.
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I’ve tried so many things but I can’t find the Answer
Answer:
\(let \: that \: be \: \: x \\ 20\% \: of \: x \: is \: 6 \\ \frac{20}{100} \times x = 6 \\ 20x = 600 \\ x = 30\)
30
☞EXPLANATION☜20 percent (calculated percentage %) of what number equals 6? Answer: 30.
Please help I don't understand
An electronics company finds that 5 out of 1,535 capacitors produced are damaged. How many damaged items can they expect if the company produces 23,025 capacitors?
Answer:
the damaged items expected in the case when the 23,025 capacitors produced is 75
Step-by-step explanation:
The computation of the damaged items expected in the case when the 23,025 capacitors produced is shown below:
= (5 × 23,025 capacitors) ÷ (1,535 capacitors)
= 75
Hence, the damaged items expected in the case when the 23,025 capacitors produced is 75
In order for a vaccine to be effective, it should reduce a person's chance of acquiring a disease. Consider a hypothetical vaccine for malaria—a tropical disease that kills between 1.5 and 2.7 million people every year.1 Suppose the vaccine is tested with 700 volunteers in a village who are malaria free at the beginning of the trial. Three hundred of the volunteers will get the experimental vaccine and the rest will not be vaccinated. Suppose that the chance of contracting malaria is for those who are not vaccinated.
Here is the full question.
In order for a vaccine to be effective, it should reduce a person's chance of acquiring a disease. Consider a hypothetical vaccine for malaria‚- a tropical disease that kills between 1.5 and 2.7 million people every year.1 Suppose the vaccine is tested with 700 volunteers in a village who are malaria-free at the beginning of the trial. Three hundred of the volunteers will get the experimental vaccine and the rest will not be vaccinated. Suppose that the chance of contracting malaria is 10% for those who are not vaccinated.
Construct a two-way table to show the results of the experiments if:
(a) The vaccine has no effect
(b) The vaccine cuts the risk of contracting malaria in half
Answer:
Step-by-step explanation:
From the given information above:
Suppose, there is no effect from the vaccine, the risk of having malaria for vaccine & no vaccine is equal to 0.1
Now, the Probability of not having malaria if vaccinated or no vaccinated = 1 - 0.1 = 0.9
Therefore: the table is shown below as follows:
Malaria No Malaria Total
Vaccinated 300 × 0.1 = 30 300 × 0.9 = 270 300
No Vaccine 400 × 0.1 = 40 400 × 0.9 = 360 700-300 = 400
Total 40 + 30 = 70 270 + 360 = 630 700
(b)
The risk of malaria for vaccinated if the vaccine cuts the risk of contracting malaria in half are equal to 0.1/2 = 0.05
Thus; the probability of not getting malaria if vaccinated = 1 - 0.05 = 0.95
The table can then be computed as follows:
Malaria No Malaria Total
Vaccinated 300 × 0.05 = 15 300 × 0.95 = 285 300
No Vaccine 400 × 0.1 = 40 400 × 0.9 = 360 700-300 = 400
Total 40 + 15 = 55 285 + 360 = 645 700
Help please I need help with this
Answer:
π/6 ≈ 11/21 cubic units
Step-by-step explanation:
Use the given values in the formula for the volume of a sphere:
V = 4/3πr³
V = (4/3)(22/7)(1/2)³ = 4·22/(3·7·8) = 11/21 . . . . cubic units
We know,
\({\qquad { \longrightarrow \pmb {\sf Volume_{(Sphere)} = \dfrac{4}{3} \pi {r}^{3} }}}\)
Here,
Radius of the sphere is \( \sf\dfrac{1}{2} .\) We will take the value of π as \( \sf\dfrac{22}{7} .\)⠀
Substituting the values in the formula :
\( { \longrightarrow {\qquad {\sf Volume_{(Sphere)} = \dfrac{4}{3} \times \dfrac{22}{7} \times {\bigg(\dfrac{1}{2} \bigg)}^{3} }}}\)
\( { \longrightarrow {\qquad {\sf Volume_{(Sphere)} = \dfrac{4}{3} \times \dfrac{22}{7} \times \dfrac{1}{8} }}}\)
\({ \longrightarrow {\qquad {\sf Volume_{(Sphere)} = \dfrac{ \cancel4}{3} \times \dfrac{22}{7} \times \dfrac{1}{ \cancel8} }}}\)
\({ \longrightarrow {\qquad {\sf Volume_{(Sphere)} = \dfrac{ 1}{3} \times \dfrac{22}{7} \times \dfrac{1}{ 2} }}}\)
\({ \longrightarrow {\qquad {\sf Volume_{(Sphere)} = \dfrac{22}{3 \times 7 \times 2} }}}\)
\({ \longrightarrow {\qquad {\sf Volume_{(Sphere)} = \dfrac{22}{42} }}}\)
\({ \longrightarrow {\qquad {\bf Volume_{(Sphere)} = \dfrac{11}{21} }}}\)
⠀
Therefore,
Radius of the sphere is \( \bf \dfrac{11}{21} \) units³.Integrate by hand the following functions: adr b) (42³-2r+7) dz Upload Choose a File
The integral of (42³ - 2r + 7) dz is equal to (42³ - 2r + 7)z + C.
To integrate the function (42³ - 2r + 7) dz, we treat r as a constant and integrate with respect to z. The integral of a constant with respect to z is simply the constant multiplied by z:
∫ (42³ - 2r + 7) dz = (42³ - 2r + 7)z + C
where C is the constant of integration.
Note: The integral of a constant term (such as 7) with respect to any variable is simply the constant multiplied by the variable. In this case, the variable is z.
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suppose you have 100 dollars in your bank account and you earn 2.25% interest per year. let mn be the amount of money in your account after n years. determine the amount of money you have in your account after years 1, 2, 3, and 4 to 2 decimal places:
The amount of money you have in your account after years 1, 2, 3, and 4 are $102.25, $204.5, $306.75 and $409 respectively.
What is interest?Interest is the price you pay to borrow money or the cost you charge to lend money. Interest is most often reflected as an annual percentage of the amount of a loan.
Given that, you have 100 dollars in your bank account, and you earn 2.25% interest per year.
We need to find the amount of money you have in your account after years 1, 2, 3, and 4 years
Find for Simple interset :-
Simple interset = PRT / 100
P = Principal amount, r = rate and t = year
For 1 year, put t = 1
A = 100×1×2.25 / 100 + 100
= $102.25
To find the amount for 2nd, 3rd and 4th year, just multiply these numbers to the interset earned in 1st year,
For 2 year,
A = $102.25×2
A = $204.5
For 3 year,
A = $102.25×3
A = $306.75
For 4 year,
A = $102.25×4
A = $409
Hence, the amount of money you have in your account after years 1, 2, 3, and 4 are $102.25, $204.5, $306.75 and $409 respectively.
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