cyclopropyl chloride has been prepared by the free-radical chlorination of cyclopropane. draw the products for each equation of the stepwise mechanism for this reaction. be sure to include lone pair(s) of electrons where necessary.

70.9-gram sample of \(Cl_{2}\) gas will occupy Opton C. 22.4 liters at STP.

To determine the volume occupied by the sample of \(Cl_{2}\) (g) at STP, we can use the ideal gas law equation, PV = nRT

where P = pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature.

At STP (Standard Temperature and Pressure), the pressure is 1 atmosphere (atm) and the temperature is 273.15 Kelvin (K).

First, calculate the number of moles of \(Cl_{2}\) (g) using its molar mass. The molar mass  \(Cl_{2}\) is 70.9 grams/mol.

Number of moles (n) = mass (m) / molar mass (M)

n = 70.9 g / 70.9 g/mol

n = 1 mol

Now, we can calculate the volume using the ideal gas law:

V = (nRT) / P

V = (1 mol * 0.0821 L·atm/mol·K * 273.15 K) / 1 atm

V ≈ 22.4 L

Therefore, the correct answer is C. 22.4 L.

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Answer:

1.12L

Explanation:

multiply 0.05 ×22.4

The activation energy denoted by Ea is referred to as the minimum energy or the threshold energy required for a reaction to occur. When reactant molecules overcome the repulsion energy resulting in the collision of outer electrons by optimum kinetic energy. Higher the activation energy more easy for the reaction to take place.

When comparing two similar chemical reactions, the reaction with the smaller activation energy (Ea) because the activation energy is lower, the transition of the reactant molecules into the product species requires less energy. Accordingly, the pace of the response will be higher.

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CaCl₂ 2H₂O  contains the greatest percent of water by mass  By halving the hydrate's formula , one may compute the theoretical (real) percent hydration.

To provide with enough liquid or moisture; to make to occupy or mix with water or indeed the constituents of water. softens and moisturizes the skin. the intransitive verb "to hydrate"

Milk is one of finest liquids for hydration, according to research, even more than water or caloric beverages. Researchers attribute milk's efficiency to its protein, carbs, and natural electrolytes.

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Answer:

The answer would most likely be C

2) The precipitate which forms and then redissolves upon adding H₂SO₄ to the mixture of K⁺, [Al(H₂O)₂(OH)₄]⁻, and OH⁻ is Al(OH)₃.

Upon the addition of H₂SO₄, the OH⁻ ions from the [Al(H₂O)₂(OH)₄]⁻ complex react with the H⁺ ions from the acid to form water.

As a result, the [Al(H₂O)₂(OH)₄]⁻ complex loses its hydroxide ligands and forms Al³⁺ ions.

These Al³⁺ ions further react with the OH⁻ ions in the solution to form a precipitate of Al(OH)₃.

However, when excess H₂SO₄ is added, the acidic conditions cause the Al(OH)₃ precipitate to redissolve.

The strong acid H₂SO₄ donates additional H⁺ ions, which react with the hydroxide ions in the Al(OH)₃ precipitate, converting it back into Al³⁺ ions and water.

The overall reaction can be represented as:

[Al(H₂O)₂(OH)₄]⁻ + H⁺ → Al³⁺ + 3H₂O

Al(OH)₃ + 3H⁺ → Al³⁺ + 3H₂O

Thus, the precipitate Al(OH)₃ forms initially but redissolves upon the addition of excess H₂SO₄ due to the formation of Al³⁺ ions and water.

When H₂SO₄ is added to the mixture of K⁺, [Al(H₂O)₂(OH)₄]⁻, and OH⁻, it reacts with the hydroxide ions from the [Al(H₂O)₂(OH)₄]⁻ complex, causing the formation of a precipitate.

This precipitate is Al(OH)₃, which is formed by the reaction between the Al³⁺ ions and the OH⁻ ions.

However, when excess H₂SO₄ is added, the acidic conditions lead to the redissolution of the Al(OH)₃ precipitate.

This occurs because the strong acid donates additional H⁺ ions, which react with the hydroxide ions in the Al(OH)₃ precipitate, converting it back into Al³⁺ ions and water.

As a result, the precipitate dissolves, leaving behind Al³⁺ ions in the solution.

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Explanation:

The green color of the Statue of Liberty was due to the outer surface covered with hundreds of thin copper sheets. Copper reacts with the air to form a patina or verdigis

The residents of Kansas were overwhelmingly opposed to the Lecompton Constitution. This was large because the document protected slavery and allowed the state government to decide whether slavery should be allowed in the new state.

The people of the state saw this as an affront to their values and democratic rights and worked to defeat the constitution in a state referendum.

After much debate and campaigning, the Lecompton Constitution was defeated by over 10,000 votes. This was a major victory for antislavery advocates, who had worked hard to make sure the constitution was rejected in Kansas.

The residents of Kansas were overwhelmingly opposed to the Lecompton Constitution. This document was drafted by pro-slavery advocates and would have made slavery a permanent institution in the state.

The citizens of Kansas were furious, and it sparked a great deal of debate and conflict. Many residents were so opposed to the document that they decided to form an independent government and reject the Lecompton Constitution in a referendum.

The referendum passed in an overwhelming majority, and the Lecompton Constitution was rejected. This event was a major milestone in the struggle for free-state rights in the Midwest and demonstrated the power of the people to resist oppressive legislation.

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The change that can make the model of nitrogen atom more accurate is to show 7 neutrons in the nucleus. The correct option is C.

An atom is a matter unit of matter that defines a chemical element distinctively. An atom is made up of a central nucleus one or more negatively charged electrons.

The nucleus is positively charged and encompasses one or more protons and neutrons, which are relatively heavy particles.

Nitrogen is an atom with seven protons, seven neutrons, and seven electrons. The nucleus is made up of neutrons and protons that are all stuck together in the middle of the atom.

The addition0. of 7 neutrons in the nucleus can improve the accuracy of the nitrogen atom model.

Thus, the correct option is C.

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Your question seems incomplete, the complete question is:

A students drawing of a nitrogen atom is shown. What change would make the model more accurate?

A-move the electrons into the nucleus

B-add 2 more protons

C-show 7 neutrons in the nucleus

D-remove 2 electrons

There are approximately 1.56 × 10²³ formula units of Mg₃N₂ in 26.2 grams.

To determine the number of formula units in 26.2 grams of magnesium nitride (Mg₃N₂) using scientific notation, we need to use the molar mass of Mg₃N₂. The molar mass of Mg₃N₂is calculated by adding the atomic masses of three magnesium atoms and two nitrogen atoms.

The atomic mass of magnesium (Mg) is approximately 24.31 grams/mole, and the atomic mass of nitrogen (N) is approximately 14.01 grams/mole.

Therefore, the molar mass of Mg₃N₂is:
(3 * 24.31) + (2 * 14.01)

= 72.93 + 28.02

= 100.95 grams/mole.

Now we can calculate the number of moles of Mg₃N₂in 26.2 grams using the formula: moles = mass / molar mass.

moles = 26.2 grams / 100.95 grams/mole

= 0.259 moles.

Since 1 mole of Mg₃N₂contains Avogadro's number (6.022 × 10²³) formula units, we can multiply the number of moles by Avogadro's number to find the number of formula units:

0.259 moles * 6.022 × 10²³ formula units/mole = 1.56 × 10²³ formula units.

Therefore, there are approximately 1.56 × 10²³ formula units of Mg₃N₂in 26.2 grams.

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The block's speed at the point where x=0.45A is approximately 0.39 m/s.

To find the block's speed, follow these steps:

1. Convert the initial speed to m/s: 50 cm/s = 0.5 m/s.

2. Calculate the initial potential energy (PE) of the spring: PE = 0.5 * k * A², where k=13 N/m and A is the amplitude.

3. Determine the amplitude (A) by setting the initial kinetic energy (KE) equal to the initial potential energy: KE = 0.5 * m * v² = 0.5 * k * A², where m=1.00 kg and v=0.5 m/s.

4. Solve for A: A = sqrt((m * v²) / k) = sqrt((1.00 * 0.5²) / 13).

5. Calculate the block's displacement at 0.45A: x = 0.45 * A.

6. Find the potential energy at x=0.45A: PE = 0.5 * k * (0.45A)².

7. Calculate the kinetic energy at x=0.45A: KE = initial PE - PE at 0.45A.

8. Solve for the block's speed at x=0.45A: v = sqrt((2 * KE) / m).

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Answer:

warm water holds the least amount of dissolved oxygen, so I would assume the answer would be D. a small pond could heat up easily. in addition, the water is calm and not moving in a pond

The order of increasing basicity is: Aniline < Pyridine < Pyrrole < Ammonia.

To rank the nitrogen-containing aromatic molecules in order of increasing basicity, we need to consider the electron-donating ability of each molecule's nitrogen atom. The more electron-donating the nitrogen atom, the more basic the molecule.

1. Aniline (\(C_6H_5NH_2\)): Aniline is the least basic molecule among the given options. The nitrogen atom in aniline is directly attached to an aromatic ring, which has a partial negative charge. This partial negative charge reduces the electron-donating ability of the nitrogen atom, making it less basic.

2. Pyridine (\(C_5H_5N\)): Pyridine is more basic than aniline. The nitrogen atom in pyridine is also attached to an aromatic ring, but the nitrogen atom in pyridine is less affected by the partial negative charge of the ring. As a result, the nitrogen atom in pyridine can donate electrons more easily, making it more basic than aniline.

3. Pyrrole (\(C_4H_5N\)): Pyrrole is more basic than pyridine. The nitrogen atom in pyrrole is directly involved in a conjugated pi-system, which provides additional electron density to the nitrogen atom. This increased electron density allows the nitrogen atom in pyrrole to donate electrons more readily, making it more basic than pyridine.

4. Ammonia (\(NH_3\)): Ammonia is the most basic molecule among the given options. Unlike the previous three molecules, ammonia is not aromatic. However, it is still a nitrogen-containing compound. The lone pair of electrons on the nitrogen atom in ammonia is not involved in any aromatic or conjugated pi-system, making it highly available for donation. This makes ammonia the most basic among the given molecules.
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If 170 milligrams of a radioactive substance decays to 85 g after 16 hours. Then, after 21 hours, approximately 75.2 mg of the radioactive substance will remain.

The decay of the radioactive substance follows an exponential decay equation of the form:

\(N(t) = N_{o} \times e^{-kt}\)

Where:

N(t) is the amount of substance remaining at time t

N₀ is the initial amount of substance

k is the decay constant

t is the time elapsed

Given to us is N₀ = 170 mg and N(16) = 85 mg. We can use this information to find the decay constant, k.

\(85 = 170 \times e^{-k \times 16}\)

Dividing both sides by 170:

\(0.5 = e^{-k \times 16}\)

To solve for k, we can take the natural logarithm (ln) of both sides:

ln(0.5) = -k × 16

from this, the value of k comes out to be:

k = 0.0431

Now we can use the decay equation to find the amount of substance remaining after 21 hours, N(21):

\(N(21) = 170 \times e^{-0.0431 \times 21}\)

Calculating this expression:

N(21) = 75.2

Therefore, after 21 hours, approximately 75.2 mg of the radioactive substance will remain.

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Answer:

33.6 i think

Explanation:

Answer:

D. It would have a net negative charge

Explanation:

In an atom, there are electrons, protons and neutrons collectively called SUBATOMIC PARTICLES. The charge of an atom is determined by the number of electrons and protons in that atom. A neutral or uncharged atom possess the same number of electrons and protons.

The charge can thus be calculated as follows:

Charge of atom = no. of protons - no. of electrons.

Hence, when the number of electrons in an atom is higher than that of the protons, it means that the atom has gained negatively charged electrons, making that atom have a net negative charge. For example, In an atom that contains 10 protons and 11 electrons, the charge of that atom will be (10 - 11) = -1. The net charge of that atom will be -1, which is NEGATIVE.

The orbitals are accountable to the law of octaves are: 1s 2s 2p 2p 3s 3p 3d  4s 4p 4d 5s 5p 4f 5d 6s 6p 5f 6d 7s .

The law of octaves introduced by the English chemist named J.A.R Newlands. According to it if we arranged the chemical elements in the periodic table according to their atomic mass then those that have the similar physical and the chemical properties will occur after the each interval of the seven elements.

The last element that is known was the thorium with the atomic mass of 232. Newlands' law of octave was firstly applicable only up to the calcium with atomic mass of 40. Now there are more ninety elements known up to the thorium.

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Answer:

26.98°C

Explanation:

Applying,

Q = cm(t₂-t₁)................ Equation 1

Where Q = Heat transferred to the soil, c = specific heat capacity of dry soil, m = mass of the soil, t₂ = final temperature, t₁ = initial temperature.

From the question,

Given: Q = 11 kJ = 11000 J, m = 2300 g = 2.3 kg, t₁ = 21°C

Constant: c = 800 J/kg.°C

Substitute these values into equation 1

11000 = 800×2.3(t₂-21)

Solving for t₂

t₂-21 = 11000/(800×2.3)

t₂-21 = 11000/1840

t₂-21 = 5.98

t₂ = 5.98+21

t₂ = 26.98°C

Alkali metals have only one electron in their outermost energy levels, and they can lose this one electron to form a mono positive ion only. Hence, alkali metals do not form dispositive ions.

Answer:

c

Explanation:

Answer:

 4Al  + 3O₂  →  2Al₂O₃

Explanation:

The problem here is in balancing the equation below:

     Al  + O₂  →  Al₂O₃

In balancing a chemical equation, the number of atoms on both sides of the expression must be the same;

   put the alphabets a, b and c before each specie;

                  aAl  + bO₂  →  cAl₂O₃

Conserving Al;

                    a  = 2c

Conserving  O:

                     2b  = 3c

  Now, let c  = 1, a  = 2

                b  = \(\frac{3}{2}\)  

Multiply through by 2;

           c  = 2, a  = 4 and b  = 3

          4Al  + 3O₂  →  2Al₂O₃

Answer:

true.................

Answer:

Thermal energy that is transferred from one substance to another,moves from warmer to cooler objects. So True.

Explanation:

Answer:

carbon

Explanation:

Answer:

Carbon

Carbon is the second most common molecule in the human body

if 4.50 grams of aluminum hydroxide reacts with 7.65 grams of sulfuric acid 7.44 grams of water are formed? molar mass aluminum hydroxide

Aluminum hydroxide is amphoteric in acid it acts as a Bronsted Lowry base it neutralizes the acid, yielding a salt

Here given data is

Aluminum hydroxide = 4.50 grams

Sulfuric acid = 7.65 grams

We have to calculated grams of water are formed = ?

Molar mass aluminum hydroxide =  78.00 g/mol, molar mass of sulfuric acid = 98.08 g/mol, molar mass of water = 18.02 g/mol

Then the reaction is

2Al(OH)₃ + 3H₂SO₄ → Al₂(SO₄)₃ + 6H₂O

4.50 grams/ 78.00 g/mol = 0.057mole

7.65 grams/98.08 g/mol = 0.077mole

Then 0.057mole + 0.077mole = 0.134 mole

Al₂(SO₄)₃ =  0.134 mole

So, 0.134 mole/18g/mol = 7.44g

7.44 grams of water are formed

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Answer:

\(\boxed {\boxed {\sf 75 \ radioactive \ nuclei}}\)

Explanation:

Radioactive decay occurs in unstable atom nuclei. The ratio of protons to neutrons is off, causing the instability. The nuclei release particles and radiation to change into different atoms.

The half-life is the time it takes for half of the nuclei to decay. We don't know the half-life of the sample, but we know it undergoes 3 half-lives. Therefore, the number of radioactive nuclei halves every time the sample undergoes a half-life.

We can divide the number of nuclei in half 3 times to find the amount left after 3 half-lives.

After 3 half-lives, 75 radioactive nuclei remain undecayed.

Answer:

An organism is made up of four levels of organization: cells, tissues, organs, and organ systems. These levels reduce complex anatomical structures into groups; this organization makes the components easier to understand

Explanation:

Answer:

its proprionic acid which do not cause any hazardous effect on environment it only effect internal body of human if it is ingested.

Explanation:

Answer:

El volumen que ocupará la misma masa de aire es 839.49 mL.

Explanation:

Las condiciones normales de presión y temperatura (abreviado CNPT) o presión y temperatura normales (abreviado PTN o TPN), son términos que implican que la temperatura referenciada es de 0ºC (273,15 K) y la presión de 1 atm (definida como 101.325 Pa).

La ley de Boyle dice que “El volumen ocupado por una determinada masa gaseosa a temperatura constante, es inversamente proporcional a la presión”  y se matemáticamente como

Presión*Volumen=constante

o P*V=k

La ley de Charles es una ley que dice que cuando la cantidad de gas y de presión se mantienen constantes, el cociente que existe entre el volumen y la temperatura siempre tendrán el mismo valor:  

\(\frac{V}{T} =k\)

La ley de Gay-Lussac​ establece que la presión de un volumen fijo de un gas, es directamente proporcional a su temperatura. Se expresa matemáticamente como:

\(\frac{P}{T} =k\)

Combinando estas tres leyes se obtiene:

\(\frac{P*V}{T} =k\)

Siendo un estado inicial 1 y un estado final 2, la expresión anterior queda determinada como:

\(\frac{P1*V1}{T1} =\frac{P2*V2}{T2}\)

En este caso:

Reemplazando:

\(\frac{101325 Pa*773 mL}{273,15 K} =\frac{93300 Pa*V2}{273.15 K}\)

y resolviendo obtenes:

\(V2=\frac{273.15 K}{93300 Pa} *\frac{101325 Pa*773 mL}{273,15 K}\)

V2= 839,49 mL

El volumen que ocupará la misma masa de aire es 839.49 mL.

The arrangement of the gases in terms of  deviations from ideal behavior is; chlorine > fluorine > oxygen > Nitrogen.

We know that gases tend to follow the idea gas law. The gases that have ideal behavior tend to show this behavior at high temperatures and low pressure such that the interactions between the gas molecules could be regarded as non existent.

Now; we know that the greater the molar mass of the gas, the greater the gas tends to depart from ideal behavior. As such we would tend to arrange the gases in order of decreasing molar mass.

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