Craig has 80 cents in nickels (n) and dimes (d). He has four more nickels than dimes.
Write a system of equations that models the situation.
Solve the system of equations using any method.
PLEASE I NEED HELP!!!!

Answer:

It should be 56, sorry if i am wrong

Step-by-step explanation:

28 divided by 14 is 2

56 divided by 14 is 4

Answer:

56

Step-by-step explanation:

First, you simplify 2/4 to 1/2. Then you figure that 28 * 2= 56/1= 56.

To double check your answer, put 56 in the box and see if the two fractions equal each other.

Answer:

(1 ,3)

Step-by-step explanation:

i took the quiz on k12

The graphs of the system of equations are attached below. then the correct solution is (1,3)

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be one degree.

We have been given a system of the equation as;

y= 3 x

y =−x+4

Then all critical points of the function f(x, y) = x. 2 y -x. 2 -3xy +. 2y + 5

Solving;

y = 3x

Then 3x = -x + 4

4x = 4

x = 1

Y = 3x = 3

Hence, the intersection point is (1, 3)

The graphs of the system of equations is attached below.

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Answer:

35

Step-by-step explanation:

20 + 15 = 35

hope this helps

The amount of money she earn would be; 22 dollar

Since the unitary method is a technique by which we find the value of a single unit from the value of multiple devices and the value of more than one unit from the value of a single unit.

Given that Nancy earns $8 a week for her house chores.

We have that;

1 week = 8

2 and 3/4 week= 11/4

= 11/4 x 8

= 11 x 2

= 22 dollar

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The direction of the wind blowing is in 202°.

Given data

Air Speed = 280 mph

Heading = 190°Course= 195°

Wind Speed = 23 mph

Ground Speed = 275 mph

To find Direction of Wind Blowing

Let's break the given data and analyze them in parts.

Using the rule of Triangle.

Let P = Ground Speed,

W = Wind Speed and

A = Air Speed

Angle B = Heading = 190°

and Angle C = Course = 195°

Now, Ground Speed is defined as the speed of an aircraft relative to the ground.

It is the sum of true airspeed and the effect of wind.

Thus we get

P = A*cos(B-W) + W*cos(W)

The formula is given as

Follow the steps to solve for W in the above formula.

Put the given values in the formula.

P = 275 mph

A = 280 mph

B = 190°C = 195°

Substituting the values we get

P = 280*cos(190-W) + 23*cos(W)------------------ (1)

Now, let's solve for W

To solve W, we need to transform equation (1) into a single function of W

Then we can take derivative of the function of W and set it equal to zero.

The value of W that satisfies this equation is the value that minimizes P.

The expression derived above is not so simple to solve, thus we use trial and error method to find the value of W

The following table shows some values of P at different W from the range of 0° to 360°Wcos(W) cos(190-W) P(degrees)(degrees)(mph)

00.64-0.85323.

1830.64-0.85323

3820.64-0.85323

3810.64-0.85323.

1800.64-0.85323.

18350.64-0.85323.

38360.64-0.85323.

38270.64-0.85323.

180.64-0.85323.18

Hence, the value of W is 202°.

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Answer:

u₂ =  5

u₃ =  53

u₄ =  5621

Step-by-step explanation:

u₁ = 1

uₙ₊₁ = 2(uₙ)² + 3

u₂ = u₁₊₁ = 2ₓu₁² + 3 = 2*1² + 3 = 5

u₃ = u₂₊₁ = 2*u₂² + 3 = 2*5² + 3 = 53

u₄ = 2*u₃² + 3 = 2*53² + 3 = 5621

Answer:

9 and 5/6

Step-by-step explanation:

sorry for the other guy ealier he isnt ganna asnwer report him he needs a ban

The coordinates of point M is located between lines d and e

From the question, we have the following parameters that can be used in our computation:

M = (3 1/2, 1)

The above means that the x and the y coordinates of M are

x = 3 1/2 and y = 1

From the attached figure, we can see that

The point M with the given coordinates is located between lines d and e

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Question

Miley will place point m at the coordinate (3 1/2, 1) on the coordinate grid below

Point M will be between which 2 lines

The test statistic: X² = 42.620, Critical values: X²=38.932.

What are critical values?

A critical value is one that can be used to compare the test statistic to determine if the null hypothesis can be rejected or not.

Here, we have

Given: In one town, monthly incomes for men with college degrees are found to have a standard deviation of $650. A random sample of 22 men without college degrees resulted in incomes with a standard deviation of $926.

s = 926, n = 22

The null and alternative hypotheses:

H₀ : σ = 650; H₁ : σ > 650

Test statistic:

X² = (n-1)s²/σ²

X² = (22-1)926²/650²

x = 42.62

Critical values:

X² = X²a(n-1)

X² = X²(0.01)(21)

X² = 38.932.

Hence, the test statistic: X² = 42.620, Critical values: X²=38.932.

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Answer:

15.5 m/s

Step-by-step explanation:

Using the equation, d = ut+1/2gt² where all the variables have meaning as given above, making u subject of the formula, we have

d = ut+1/2gt²

d - 1/2gt² = ut

d/t - 1/2gt²/t = u

u = d/t - 1/2gt

Since d = 200 m, t = 5 s and g = 9.8m/s², substituting the values of the variables into the equation, we have

u = d/t - 1/2gt

u = 200 m/5 s - 1/2 ×  9.8m/s² × 5 s

u = 40 m/s - 49 m/s ÷ 2

u = 40 m/s - 24.5 m/s

u = 15.5 m/s

So, the initial speed of the snowball is 15.5 m/s

Answer:

The properties of trapezoid apply by definition (parallel bases).

The legs are congruent by definition.

The lower base angles are congruent.

The upper base angles are congruent.

Any lower base angle is supplementary to any upper base angle.

The diagonals are congruent.The bases are parallel by definition.

Each lower base angle is supplementary to the upper base angle on the same side.

The value of the expression (x-4) minus -8x² - 8 is \(8x^{2}\)+x+4.

According to the question,

We have the following information:

x - 4 minus -8x² - 8

Now, we will convert this into an expression only using mathematical signs. So, we have the following expression:

(x-4)-(-8x² - 8)

Now, we know that the multiplication of two negative integers gives us the positive results and the multiplication of one positive and one negative integer give us the negative results.

So, we have the following expression after multiplying -1 into the bracket :

x-4+8\(x^{2}\)+8

\(8x^{2}\)+x+4

Hence, the value of the expression (x-4) minus -8x² - 8 is \(8x^{2}\)+x+4.

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Answer:

10 gallons were poured out

Step-by-step explanation:

2/3's of the 15 gallons of water is 10 gallons. Therefore 10 gallons were poured out.

T is the linear transformation described by T(w,z) in L(C2). This indicates that the linear transformation T changes two-dimensional vectors of the type (w,z) to (-z,w).

To get T's eigenvalues, solve the equation T(v) = v, where is the eigenvalue and v is the eigenvector. By solving this equation, we discover that T's eigenvalues are λ1 = -1 and λ2 = 1.

For each eigenvalue, the associated eigenspaces are the subspaces of C2 that are spanned by the eigenvectors of T. The eigenspace is the subspace covered by the eigenvector λ1= -1 is (1,0). The eigenspace is the subspace spanned by the eigenvector λ2= 1 is (0,1).

As a result, the subspaces covered by (1,0) and (1,1) are the generalized eigenspaces corresponding to the different eigenvalues of T. (0,1).

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The difference quotient for the given function is 9 -2/h.

The difference quotient for the given function can be calculated as:

[f(x+h) - f(x)]/h

= [(3(x+h)² - 2(x+h) + 5) - (3x² - 2x + 5)]/h

= (3x² + 6xh + 3h² - 2x - 2h + 5 - 3x² + 2x - 5)/h

= (6xh + 3h² - 2h)/h

= (6x + 3h -2)/h

Simplifying the expression further, we get:

(6x + 3h -2)/h = 6 + 3h/h -2/h

= 6 + 3 -2/h

= 9-2/h

Therefore, the difference quotient for the given function is 9 -2/h.

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"Your question is incomplete, probably the complete question/missing part is:"

Find the difference quotient [f(x+h)-f(x)]/h, where h≠0, for the function below.

f(x)=3x² -2x+5. Simplify your answer as much as possible.

2a , 1st exp= a2 + ab

= a(a+b)

2nd exp = a2-b2

= (a+b) (a-b)

HCF = (a+b)

b, 1 st exp= (a+b)2

= (a+b)(a+)

2 nd exp = a2-b2

= (a+b) ( a-b)

HCF = (a+b)

c, 1 st exp= (a-1)2

= (a+1) (a-1)

2nd exp= a2-1

= (a+1)(a-1)

HCF = (a-1)

d, 1st exp= (x-2)(x-3)

= x(x-3)-2(x-3)

= x2 - 3x - 2x + 6

= x2- 5x+ 6

= x2 - (3+2)x + 6

=x2 -3x-2x+ 6

= x(x-3) -2(x-3)

=(x-3)(x-2)

2 nd exp = (x+2) (x-3)

= x( x-3) + 2 (x-3)

= x2 - 3 x+ 2x -6

= x(x-3) + 2(x-3)

=(x-3) ( x+ 2)

HCF = (x-3)

This is the Taylor series expansion for the function f(x) = x⁴ - 6x² + 1 centered at a = 2.

What is Taylor Series?

In mathematics, the Taylor series or Taylor expansion of a function is an infinite sum of terms that are expressed in terms of the derivative of the function at a single point. For most common functions, the function and the sum of its Taylor series near this point are the same.

To find the Taylor series for the function f(x) = x⁴ - 6x² + 1 centered at a = 2, we can use the formula for the Taylor series expansion:

f(x) = f(a) + f'(a)(x - a)/1! + f''(a)(x - a)²/2! + f'''(a)(x - a)³/3! + ...

First, let's find the values of f(a) and its derivatives at x = a = 2:

f(2) = (2)⁴ - 6(2)² + 1 = 16 - 24 + 1 = -7

f'(x) = 4x³ - 12x

f'(2) = 4(2)³ - 12(2) = 32 - 24 = 8

f''(x) = 12x² - 12

f''(2) = 12(2)² - 12 = 48 - 12 = 36

f'''(x) = 24x

f'''(2) = 24(2) = 48

Now, we can substitute these values into the Taylor series formula:

f(x) = f(a) + f'(a)(x - a)/1! + f''(a)(x - a)²/2! + f'''(a)(x - a)³/3! + ...

f(x) = -7 + 8(x - 2)/1! + 36(x - 2)²/2! + 48(x - 2)³/3! + ...

Simplifying the terms:

f(x) = -7 + 8(x - 2) + 18(x - 2)² + 8(x - 2)³ + ...

This is the Taylor series expansion for the function f(x) = x⁴ - 6x² + 1 centered at a = 2.

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The probability of a Type II error is represented by beta. Thus, the correct answer is option B.

Beta represents the probability of failing to reject the null hypothesis when it is false.

On the other hand, Type I error (alpha) represents the probability of rejecting the null hypothesis when it is true. A Type II error occurs when a false null hypothesis is not rejected. Hence, beta is the probability of making a Type II error.

The null hypothesis is rejected when the p-value is less than or equal to the level of significance, not exceeds it.

The p-value is the probability of obtaining a result as extreme as or more extreme than the observed result when the null hypothesis is true. If the p-value is less than the level of significance, the null hypothesis is rejected, and vice versa.

Hence, the statement "The null hypothesis is rejected when the p-value exceeds the level of significance" is false.

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Answer:

Yes, they are their just switched around to counfuse you  :)

Step-by-step explanation:

Answer:

(-4,-9)

Step-by-step explanation:

vertex form: y=a(x-h)^2+k

hk=vertex of x and y

inside parentheses=horizontal (opposite signs)

that’s why it’s -4 instead of 4 for h (x) while -9 stays the same since it’s not inside the parentheses

Answer:14

Step-by-step explanation:

Answer:14

Step-by-step explanation:

The largest possible value of f(8) is 14.

Since f is continuous on [4,8] and differentiable on (4,8), we can apply the Mean Value Theorem (MVT) on the interval [4,8]. The MVT states that there exists a c in (4,8) such that

f(8) - f(4) = f'(c)(8-4)

or equivalently,

f(8) = f(4) + f'(c)(8-4).

Since f(4) = -6 and f'(x) ≤ 10 for all x in (4,8), we have

f(8) = -6 + f'(c)(8-4) ≤ -6 + 10(8-4) = 14.

Therefore, the largest possible value of f(8) is 14. This maximum value can be achieved by a function that is increasing at the maximum rate of 10 on the interval (4,8) and passes through the point (4,-6).

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The thickness of the clay layer, which drains only from the upper surface, can be determined based on the consolidation settlement observations. With 50% of consolidation settlement occurring in 1 hour for a 25 mm thick specimen, and a total primary consolidation settlement of 35 mm occurring over many years, the thickness of the clay layer is approximately 87.5 mm.

The consolidation settlement of a clay specimen can be used to estimate the thickness of a clay layer that drains only from the upper surface. In this case, the observed settlement data provides valuable information.

Firstly, we know that 50% of the consolidation settlement occurs in 1 hour for a 25 mm thick clay specimen. This is an important parameter for calculating the coefficient of consolidation (Cv) using Terzaghi's theory. From the Cv value, we can estimate the time required for full consolidation settlement.

Secondly, we are given that the same clay settles 10 mm over 10 years and eventually settles a total of 35 mm over a longer period. This long-term settlement is known as the total primary consolidation settlement. By comparing this settlement value with the settlement data from the oedometer test, we can determine the thickness of the clay layer.

To calculate the thickness, we can use the concept of the consolidation settlement ratio. The ratio of the total primary consolidation settlement to the consolidation settlement at 50% completion is equal to the ratio of the total thickness to the thickness at 50% completion. Applying this ratio, we can determine that the thickness of the clay layer, which drains only from the upper surface, is approximately 87.5 mm.

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O f(x) = 4(1.02)"

O f(x) = 0.5(1.02)

O f (x) =3/4 (1.35)

Of(x) = 7(5/4)

The soluation will be

Of(x) = 7(5/4)

Answer:

79 degrees

Step-by-step explanation:

79 degrees is parallel to a. The line below is the same as the line above, since they are parallels, beaning d and b also are both 79 degrees

Answer:

\(79^{\circ}\)

Step-by-step explanation:

From vertical angles, \(m\angle a=79^{\circ}\)

From corresponding angles, \(m\angle b=m\angle a\)

Therefore, we have \(m\angle b=m\angle a=\boxed{79^{\circ}}\)

The Second Shape Theorem states that if two figures have the same shape and their corresponding linear dimensions are proportional, then their areas are proportional to the squares of the ratios of their corresponding linear dimensions.

This theorem is closely related to the First Shape Theorem, which states that if two figures are similar, their corresponding angles are congruent, and their corresponding sides are proportional.
The converse of the First Shape Theorem states that if the corresponding angles of two figures are congruent and their corresponding sides are proportional, then the two figures are similar. While the Second Shape Theorem does not directly include the converse of the First Shape Theorem, the two theorems are interconnected as they both deal with the properties of similar figures.
In summary, the Second Shape Theorem focuses on the relationship between the areas of similar figures and the ratios of their linear dimensions, while the First Shape Theorem and its converse deal with the conditions for figures to be considered similar.

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Answer:

33 blue marbles

Step-by-step explanation:

sum up all the ratio

4+2+3+8=17

since we are looking for blue then we take a ratio of the blue marbles multiplied by the total number of marbles

3/17 *187

= 33

Answer:

33 blue marbles

Explanation:

As we are finding only how many blue marbles are there, we can make the ratio 3:14 instead, 3 being the blue marbles and 14 being other colors. This ratio is 17 then. There are 187 marbles in the bag, and there are eleven 17s in 187 (this can be calculated by doing 187 ÷ 17 to get 11) so you just multiply 3 and 11 to get 33.

Hope this helps! :D

Answer:

The car is marked down by 9.09090909 %

Step-by-step explanation:

Given

The price of car = $22,000

Markdown amount = $2,000

To determine

what percent is the car marked down

The percent of the car marked down can be determined by dividing the Markdown amount by the price of the car and multiplying the result by 100.

Markdown % = [Markdown amount / The price of car] × 100

                      =[ 2000 / 22000 ] × 100

                      = 0.0909090909  × 100

                      = 9.09090909 %

Therefore, the car is marked down by 9.09090909 %

The numerical coefficient is -7

From the question,  the expression is given as

-7x

Considering an expression given as

Ax

The numerical coefficient of the above expression is A

When compared to the expression -7x, we have

The numerical coefficient is -7

So, we can conclude that the numerical coefficient of -7x is -7

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Answer:

-7

Step-by-step explanation:

The numerical coefficient is -7