Coulomb’s law in monopole , dipole and square quadruple?!
Answers
Answer:
Coulomb's law states that the magnitude of force between two charges is directly proportional to the product of magnitude of charges and inversely proportional to the square of the separation distance between the charges.
\({ \boxed{ \rm{F \: \alpha \: \frac{q_{1} q_{2} }{ {r}^{2} } }}} \\ \)
Related Questions
what are the differences in your experimental results between the perfectly elastic and inelastic collisions?
Answers
The main difference between perfectly elastic and inelastic collisions is that In a perfectly elastic collision, the total kinetic energy of the system is conserved, while in an inelastic collision, the total kinetic energy of the system decreases.
Perfectly elastic collisions result in no loss of kinetic energy, whereas inelastic collisions result in a loss of kinetic energy. Collisions in which the kinetic energy is conserved are known as perfectly elastic collisions. Two billiard balls colliding are an example of a perfectly elastic collision because they have the same mass, and there is no deformation of the ball. As a result, in a perfectly elastic collision, both momentum and kinetic energy are conserved.In contrast, in an inelastic collision, kinetic energy is not conserved.
In an inelastic collision, two or more bodies come together and stick to one another after colliding. When two cars collide, for example, they do not bounce off each other; instead, they become deformed and stick together. A loss of kinetic energy is present in inelastic collisions because the deformation causes some of the energy to be converted to heat, sound, and other forms of energy that are not associated.
Therefore, the differences in the experimental results between perfectly elastic and inelastic collisions are due to the fact that inelastic collisions cause kinetic energy to be lost, while perfectly elastic collisions do not cause kinetic energy to be lost.
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How has this camp provided cadets with a greater understanding of opportunities within the STEM field and how to get there?
Note: Think about information you learned about the different job opportunities within the STEM field and a plan on how to achieve those career goals.
Answers
The camp has provided cadets with a greater understanding of opportunities within the STEM field and how to get there in several ways:
1. Exposure to different STEM career paths: The camp has likely exposed cadets to a variety of STEM career paths. Through workshops, presentations, and possibly guest speakers, cadets would have learned about different job opportunities within the STEM field. This exposure helps them understand the range of possibilities available to them and allows them to explore various interests within STEM.
2. Hands-on activities and projects: The camp may have included hands-on activities and projects related to STEM fields. These activities give cadets the opportunity to apply their knowledge, develop practical skills, and gain a deeper understanding of the real-world applications of STEM concepts. By engaging in these activities, cadets can see the direct link between their academic learning and potential career paths in STEM.
3. Mentoring and networking: The camp may have provided opportunities for cadets to interact with professionals working in STEM fields. This could include mentorship programs or networking events where cadets can ask questions, seek guidance, and gain insights from professionals who have already established themselves in their respective careers. By connecting with these mentors and professionals, cadets can learn about the paths they took to get to where they are and receive valuable advice on how to achieve their own career goals in the STEM field.
4. Career planning and goal-setting: The camp likely included sessions on career planning and goal-setting. Cadets may have been introduced to resources and tools to help them develop a plan for their educational and career journeys. This could involve identifying the educational requirements, internships or research opportunities, and additional skills or certifications needed to pursue specific STEM careers. By setting clear goals and understanding the steps necessary to achieve them, cadets are better equipped to navigate their way through the STEM field.
Overall, this camp has provided cadets with a greater understanding of opportunities within the STEM field by exposing them to different career paths, providing hands-on experiences, facilitating mentorship and networking, and assisting in career planning and goal-setting. These opportunities help cadets explore their interests, gain practical skills, and develop a roadmap for their future STEM careers.
A laser emits a pulse of light with energy5.0x103J. Determine the number of photons in the pulsesif the wavelenght of light is 480nm.
Answers
The number of photons in the pulse is 1.21 × 1022.
The energy of a photon can be calculated using the equation:
E = hf, where
E is the energy of a photon,
h is the Planck's constant, and
f is the frequency of the light.
Then, using the equation c = λf, where
c is the speed of light,
λ is the wavelength of the light and
f is the frequency of the light, the frequency of the light can be determined.
Planck's constant (h) is a fundamental constant in quantum mechanics that relates the energy of a photon to its frequency.
Its value is 6.626 × 10-34 joule seconds (J·s).
The frequency of the light is:
f = c / λ
= 3.00 × 108 / 480 × 10-9
= 6.25 × 1014 Hz
The energy of the photon can be calculated:
E = hf
= 6.626 × 10-34 × 6.25 × 1014
= 4.14 × 10-19 J
The number of photons can be determined by dividing the energy of the pulse by the energy of a photon:
n = E / E_photon
= 5.0 × 103 / 4.14 × 10-19
= 1.21 × 1022 photons
Therefore, the number of photons in the pulse is 1.21 × 1022.
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A teacher pushes a cart, while a student pushes a second, heavier cart
with the same amount of force. If the student's cart has three times the
mass as the teacher's, which of the following is true? *
Answers
Answer:
frictional force acting on the cart 450 N.
Given:
mass of cart = 50 kg
acceleration = 3
To find:
Frictional force = ?
Formula used:
F - = 600 N
F = ma
= frictional force
Solution:
Force on the block is given by,
F - = 600 N
F = ma
= frictional force
= 600 - m a
= 600 - (50 × 3)
= 600- 150
= 450 N
According to the given data the frictional force acting on the cart 450 N.
A 230 v mains powered electrical drill draws a current of 2.5 A calculate the power of the drill at use
Answers
The symbol EF represents the magnitude of the electric field at location F, and the symbol Ep represents the magnitude of the electric field at location D. Which of the following equations is a correct energy conservation (loop) equation for this circuit, following a path that starts at the positive end of the battery and goes clockwise? O o- 1.5 V- Ef 0.25 m ED 0.063 m - Ef 0.25 m 0+1.5 V- EF 0.25 m ED 0.063 m-Ef 0.25 m 1.5 V- EF .0.25 m 0+1.5EF 0.25 mED -0.063 mEf 0.25 m 0-1.5 VEf 0.25 m ED 0.063 mEf-0.25 m 1.5V- ED-0.063 m The symbol i represents the electron current at location F, etc. Which of the following equations is a correct charge conservation (node) equation for this circuit? Use the appropriate equation(s), plus the equation relating electron current to electric field, to solve for the factor that goes in the blank below: *ED Use the appropriate equation(s) to calculate the magnitude of ED ED Use the appropriate equation(s) to calculate the electron current at location D in the steady state: V/m
Answers
The correct energy conservation (loop) equation for this circuit is 1.5V - EF 0.25m + ED 0.063m - EF 0.25m + 1.5V - EF 0.25m + ED 0.063m - EF 0.25m + 1.5V - ED 0.063m = 0.
The correct charge conservation (node) equation is i + EF 0.25m - ED 0.063m = 0. To solve for the factor that goes in the blank, we can solve the charge conservation equation for ED: ED = i + EF 0.25m. Therefore, ED = V/m. To calculate the magnitude of ED, substitute the known values into the equation: ED = V/m = (1,5V + 0,25m . EF)/0,063m.
To calculate the electron current at location D in the steady state, substitute the known values into the charge conservation equation: i = ED - EF 0.25m = (V/m - 0.25m*EF).
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Jalen combines two substances in science class. Once combined, only one of the two substances
is visible. When he placed this combination into a filter, substance 1 stayed in the filter while
substance 2 went through it. Which of the following claims regarding Jalen's combination is the
most accurate?
a. This combination is not a mixture because he cannot see one of the substances.
b. The combination is a mixture because the substances can be separated.
c. The combination is not a mixture because the substances can be separated.
d. The combination is a mixture only because he cannot see one of the substances,
Answers
Answer: b. The combination is a mixture because the substances can be separated
Explanation: Based on the facts presented above, the combination of both both substances can be referred to as a mixture due to the following:
A mixture is obtained when two or more substances or materials are combined without a chemical reaction. This is observed when Jalen combined substance 1 and 2 with only one of the substances becoming visible after the combination.
The other reason is that, a mixture can be separated back into its original constituent, this is evident when the combination was filtered with only substance 2 going through the filter and substance 1 remaining in the filter
Imagine that a person spins a beach ball on a table so that it initially rotates at 15 rad/s. After 5.3 seconds, the ball completely stops moving. What is the average angular velocity of the ball
Answers
The average angular velocity of the beach ball is 2.83 rad/s.
Angular velocity is a measure of how fast an object is rotating. It is defined as the rate of change of angular displacement over time. In this case, the beach ball starts with an initial angular velocity of 15 rad/s and comes to a complete stop after 5.3 seconds.
To find the average angular velocity, we divide the total angular displacement by the total time.
Since the ball stops completely, its final angular velocity is zero. The initial angular velocity is 15 rad/s. Therefore, the change in angular velocity is 15 - 0 = 15 rad/s. The time taken for this change is 5.3 seconds.
To find the average angular velocity, we divide the change in angular velocity by the time taken:
Average angular velocity = Change in angular velocity / Time taken
Average angular velocity = 15 rad/s / 5.3 s = 2.83 rad/s
Therefore, the average angular velocity of the beach ball is 2.83 rad/s.
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course: Electricity and magnetism
6.1B A current of 10 amp flows through a wire of 1 mm² cross section. If the density of charge carriers in the wire is 1027/m³, find the average drift velocity of the electrons.
Answers
The average drift velocity of the electrons is is approximately 6.25 x 10^6 m/s.
To find find the average drift velocity of the electrons, we have to make use of the drift velocity formula. The drift velocity formula is used to relate the average drift velocity of charge carriers in a conductor to the applied electric field. It is used to understand the motion of electrons when an electric current is flowing.
The drift velocity formula is:
\(I = nAvq\)
Where:
I is the current (in Amperes),
n is the density of charge carriers,
A is the cross-sectional area of the wire,
v is the average drift velocity of electrons,
q is the charge of an electron.
In this case, we have been given current as 10A, cross-sectional area of the wire is 1mm². The density of charge carriers in the wire is 1027/m³. So, by substituting all the given identities in the equation and rearranging the equation to find out "v", we get:
\(v = I / (nAq)\)
\(v = (10 A) / ((10^{27} /m^{3} ) * (1 * 10^{-6} m^{2}) * (1.6 * 10^{-19} C))\)
\(v = (10 A) / (1.6 * 10^{-12} A * m^{2} * C * 10^{27} /m^{3} )\)
\(v = 6.25 * 10^{6} m/s\)
Therefore, the average drift velocity of electrons in the wire is approximately 6.25 x 10^6 m/s.
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Answer:
Average drift velocity of the electrons is Approx. 6.25*10^6 m/s.
Given, Current= 10A
Cross sectional area = 1mm^2
Density of charge= 1027/m^3
Formula to find velocity= I/(nAq)
= 10/(1027*1*10^-6*1.6*10^-19)
=6.25*10^6m/s
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If a fish in a pond looks upward at 50° to the normal, it will see
a. the sky and possibly some tall surroundings.
b. only the water's surface.
c. the pond's bottom.
d. none of the above
Answers
If a fish in a pond looks upward at 50° to the normal, it will see: a. the sky and possibly some tall surroundings.
This is because when the fish looks upward at an angle of 50° to the normal (the normal being the imaginary line perpendicular to the surface of the water), it is looking at an angle of incidence of 40° (90° - 50° = 40°). This means that the light entering the fish's eyes is refracted and bent at an angle of 32.306421° (as determined by Snell's law) as it passes from the water into the fish's eye. This bending of light allows the fish to see the sky and possibly some tall surroundings above the water's surface.
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an object experiences a force which varies with position as where -3.33 n/m and 4.4 n/m3. calculate the chan
Answers
The change in potential energy of the object is given by the above expression. ΔU = -1.665(x2^2 - x1^2) + 1.1(x2^4 - x1^4)
To calculate the change in potential energy of the object, we need to integrate the force with respect to position.
The potential energy change, ΔU, is given by:
ΔU = -∫Fdx
where F is the force and dx is the infinitesimal displacement.
In this case, the force is given as:
F(x) = -3.33x + 4.4x^3
Substituting this into the equation for potential energy change, we get:
ΔU = -∫(-3.33x + 4.4x^3)dx
Integrating this expression with respect to x, we get:
ΔU = [-1.665x^2 + 1.1x^4] + C
where C is the constant of integration.
To find the change in potential energy between two positions x1 and x2, we need to evaluate the expression for ΔU at these two positions and take the difference:
ΔU = [-1.665x2^2 + 1.1x2^4] - [-1.665x1^2 + 1.1x1^4]
Simplifying this expression, we get:
ΔU = -1.665(x2^2 - x1^2) + 1.1(x2^4 - x1^4)
Therefore, the change in potential energy of the object is given by the above expression.
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Why do water molecules tend to stay together and hold their shape? Name and explain the phenomenon by which this happens
Answers
Answer:
because liquid and solid states of water possesses intermolecular force of attraction which held the molecules of water in fixed
what would the roche limit be for an earth-orbiting body with the same density as earth? (the earth's density is 5.5 g/cm3. give your answer in terms of rearth.)
Answers
Buying or selling the Earth will go against the rights of the inhabitants of the world (humans and other living beings).
What is the Roche limit of Earth?
Solar influence
Far from the Roche limit, the mass is practically spherical. Closer to the Roche limit, the body is deformed by tidal forces. Within the Roche limit, the mass's own gravity can no longer withstand the tidal forces, and the body disintegrates.If Earth had two moons, it would be catastrophic. An extra moon would lead to larger tides and wipe out major cities like New York and Singapore. The extra pull of the moons would also slow down the Earth's rotation, causing the day to get longer.The Moon will swing ever closer to Earth until it reaches a point 11,470 miles (18,470 kilometers) above our planet, a point termed the Roche limit. "Reaching the Roche limit means that the gravity holding it [the Moon] together is weaker than the tidal forces acting to pull it apart," Wilson said.The Roche limit for the Moon orbiting the Earth is 2.86 times radius of EarthThe nearest distance between the planet and its satellite at where the planets gravitational pull does not torn apart the planets satellite is known as Roche limit.The relation to determine Roche limit is:
\(Roche Limit=(2.423) (Rp3) {{\sqrt[3]{\frac{D_{P} }{D_{m} } } } }\)
Here is radius of planet and are density of planet and moon respectively.
According to the problem,
Density of Earth, = 5.5 g/cm³
Density of Moon, = 3.34 g/cm³
Consider be the radius of the Earth.
Substitute the suitable values in the equation (1).
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Your driver's license is at risk of being cancelled if you: O A. Lied on the license application. O B. Are caught driving under the influence. O C. Cause an accident that injures another person. O D. Have more than three traffic violations in one year
Answers
Your driver's license is at risk of being cancelled if you have more than three traffic violations in one year. The correct option is D.
What is driving license?The license by the central government to an individual to travel on road by his own vehicle on terms and conditions to be strictly followed.
When a driver is moving with his vehicle and come across the traffic signal, he must follow them. If he violates the traffic signals more than three times, he will get his license cancelled.
Thus, your driver's license is at risk of being cancelled if you have more than three traffic violations in one year. The correct option is D.
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Explain why it is dangerous to touch the live wire when a switch in the
mains circuit is open.
Answers
Answer: all the energy is rushed in the wires due to the swich turning on when touching it may start a fire or electricute
Explanation:
fs
Find the instantaneous rate of change of the position function y=f(t) in feet at the given time t in seconds. f(t)=3t−7,t=1
Find the instantaneous rate of change of the position function y=f(t) in feet at the given time t in seconds.
f(t)=3t−7,t=1
Answers
The instantaneous rate of change of the position function y=f(t) in feet at the given time t in seconds. f(t)=3t−7,t=1 is as follow:
The function is f(t) = 3t - 7 and t = 1.
Using the concept of derivatives, the instantaneous rate of change of the position function y = f(t) in feet at the given time t in seconds is given by;
f'(t) = lim (h → 0) [f(t + h) - f(t)]/h
Now, we have f(t) = 3t - 7 and t = 1.
Substitute t = 1 in the above formula to get the instantaneous rate of change of the position function.
f'(1) = lim (h → 0) [f(1 + h) - f(1)]/h
Using the given function f(t) = 3t - 7,f'(1)
= lim (h → 0) [f(1 + h) - f(1)]/h
= lim (h → 0) [3(1 + h) - 7 - (3(1) - 7)]/h
= lim (h → 0) [3h]/h= 3
Therefore, the instantaneous rate of change of the position function y = f(t) in feet at the given time t = 1 second is 3 feet per second.
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The maximum magnetic field strength of an electromagnetic field is 5×10^−6 T . Calculate the maximum electric field strength if the wave is traveling in a medium in which the speed of the wave is 0.75c.
Answers
The maximum electric field strength if the wave is traveling in a medium in which the speed of the wave is 0.75c is 4 × 10^2 V/m.
The electric field strength can be calculated using the formula E = cB, where c is the speed of light and B is the magnetic field strength. Substituting the values, we get E = (3 × 10^8 m/s) × (5 × 10^−6 T) = 1.5 × 10^2 V/m.
However, since the wave is traveling in a medium in which the speed of the wave is 0.75c, the electric field strength will be different. The speed of the wave in the medium affects the relationship between the electric and magnetic fields. When the speed of the wave decreases, the electric field strength increases and vice versa.
To calculate the electric field strength when the speed of the wave is 0.75c, we need to use the formula E = (c/v)B, where v is the speed of the wave in the medium. Substituting the values, we get E = (3 × 10^8 m/s / 0.75c) × (5 × 10^−6 T) = 4 × 10^2 V/m.
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A rope of length L and mass m is suspended from the ceiling. Find an expression for the tension in the rope at position y, measured upward from the free end of the rope.
Answers
When a rope of length L and mass m is suspended from the ceiling, the tension in the rope at position y can be found using the following expression:
T(y) = mg + λy where g is the acceleration due to gravity, λ is the linear mass density of the rope, and y is the distance measured upward from the free end of the rope.
Here's how to derive the expression: Let's consider an element of length dy of the rope at a distance y from the free end of the rope. The weight of the element is dm = λdy and acts downward. The tension in the rope on the element can be resolved into two components - one acting downward and another acting upward. Let T be the tension in the rope at point y and T + dT be the tension in the rope at point (y + dy).The upward component of tension on the element is given by Tsinθ, where θ is the angle between the element and the vertical. As the rope is assumed to be in equilibrium, the horizontal components of tension balance each other and the net vertical force on the element is zero. Therefore, we have,
Tsinθ - dm g = 0 ⇒ Tsinθ = dm g ⇒ Tsinθ = λdyg
The angle θ can be found using the equation tanθ = dy/dx ≈ dy/dy = 1. Therefore, sinθ = dy/√(dy²+dx²) ≈ dy and we have,T dy = λdyg ⇒ T = λgThis expression gives the tension in the rope at the free end of the rope. The tension in the rope at position y, measured upward from the free end of the rope is given by,T(y) = mg + λy
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the active clearance control (acc) portion of an eec system aids turbine engine efficiency by
Answers
ACC provides an optimized tip clearance, thus aiding turbine engine efficiency.
The Active Clearance Control (ACC) portion of an EEC (Electronic Engine Control) system aids turbine engine efficiency by providing an optimized tip clearance.
Electronic Engine Control (EEC) is an automated engine control system that governs engine functions like fuel management, ignition, and other engine functions, replacing manual controls. This system aims to provide precise control of engine functions to ensure efficient operation and optimal performance.In modern EEC systems, a sophisticated feedback loop is used to detect engine parameters, including air temperature, pressure, fuel flow, and many others. The data received from these sensors is then transmitted to the EEC unit, which makes decisions about the engine's functioning, such as fuel injection and ignition timing. The EEC is an essential component of many modern gas turbine engines. Its accurate engine control results in improved efficiency, lower fuel consumption, and better emissions.The Active Clearance Control (ACC) portion of an EEC systemThe Active Clearance Control (ACC) portion of an EEC system is used to regulate turbine blade tip clearances during engine operation. The ACC regulates turbine blade tip clearances by adjusting the blade angle or moving shrouds to optimize the gap between the blades and the engine's housing. It does so by receiving data from sensors that monitor the engine's operating temperature and pressure. The ACC can modify the blade angle in response to changes in temperature or pressure, ensuring that the engine operates at maximum efficiency throughout its range of operations. Therefore, ACC provides an optimized tip clearance, thus aiding turbine engine efficiency.
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d. direction
Directions: Complete the concept map using the terms below
a. velocity b. position
c. speed
An object's
acceleration
is its rate of
change of
1.
which depends
on its
2.
4.
and
which is its rate
of change of
3.
Answers
An object's acceleration is its rate of change of velocity which depends on speed which is its rate of change of position and direction.
Explanation:
The definition of acceleration is the rate of change of velocity. Velocity is a vector quantity which depends on size (magnitude) and direction. When a car speeds up, it doesn't stay in one place speeding up so the position changes. I hope my answer is correct.
Have a good day!
Acceleration of a body is the rate of change of its velocity. It depends on its speed and direction. Where, speed is the rate of change in its position.
What is acceleration ?Acceleration is a physical quantity representing the rate of change of velocity of a moving object. Acceleration and velocity are vector quantities thus, having magnitude and direction.
Velocity is the rate of speed. Hence it depends on the magnitude of speed and direction. Speed is scalar quantity measuring the rate of change in position. Thus, speed is distance by time.
Therefore, the first column is filled with velocity and second and third with speed and position. The 4th column is filled with direction.
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What is a supply chain designed to optimize both forward and reverse flows?
a. open-loop supply chain
b. closed-loop supply chain
c. bullwhip-loop supply chain
d. reverse-loop supply chain
Answers
The correct option is b. closed-loop supply chain
Closed-loop supply chain is designed to optimize both forward and reverse flows.
What is closed-loop supply chain?Businesses recycle their waste volume to make new products in such a closed-loop supply chain. This method of resource conservation and energy conservation is sustainable.
Some characteristics of closed-loop supply chain are-
Although there are many natural resources on the planet, such as freshwater and oil, they are limited and will eventually run out. Fortunately, numerous governments all across the world have created and put into effect ways to lessen resource waste.Likewise, companies can contribute to the preservation of natural resources by implementing the closed-loop supply chain (CLSC). The appeal of a CLSC or negligible supply chain is that it centers on material reuse, composting, and recycling. As a result, the closed-loop supply chain encourages manufacturers to come up with creative uses for End-of-Life (EOL) products rather than disposing of them in landfills.To know more about supply chain, here
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As the cross-sectional area of a conductor increases, its resistance .
Answers
Answer:
Yess it’s resistance
Explanation:
Answer:
DECRAAAASESSSS
Explanation:
A ford is traveling with a speed of 15m/s and is 200 meters ahead of a Chevy that is traveling in the same direction but at a speed of 20m/s. How far will the chevy travel before catching up to the Ford?
Answers
The Chevy will travel a distance f about 600m before catching up with the ford in the same direction of the motion.
The ford if travelling at 15m/s and it is 200 m ahead of the Chevy that is travelling in the same direction with a speed of 20m/s.
Now, we can use velocity = distance/time here,
Time of ford will be equal to the time of Chevy,
Time of ford = Distance/velocity of ford
Time of ford = S/15
Now, for the Chevy, the distance will be 200 more and the time will be same, so we will write,
Time of Chevy = (S+200)/20
(S+200)/20 = S/15
15S + 3000 = 20S
5S = -2000
S = -400m
Negative sign is showing the direction of the motion only, so we can ignore that.
So, the Chevy will travel 600 m before catching up with the ford.
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Two people are carrying a uniform 974.0 N log through the forest. Bubba is 1.2 m from one end of the log (x), and his partner is 1.3 m from the other end (y). The log is 5.0 m long (z). What weight is Bubba supporting?
Answers
Bubba is supporting 194.8 N of the log's weight.
Weight in physics is the force that gravity applies to an object. Weight has both a magnitude and a direction, making it a vector quantity. The weight of an item is equal to the gravitational force exerted on it, which is defined by its mass and gravitational acceleration.
Given that,
Weight of the log = 974.0 N
Distance from one end to x = 1.2m
Therefore,
Weight from one end to x = (weight of the log/length of the log) x distance from one end to x.
= (974.0 / 5.0) x 1.2
= 194.8 N
Therefore, Bubba is supporting 194.8 N of the log's weight.
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which requires the most energy to melt it: 1kg of ice, 1kg of solid lead or 1kg of solid ethanol
Answers
The substance that requires the greatest amount of energy to melt is ice.
What is the latent heat of fusion?The latent heat of fusion refers to the energy that is required to melt 1 Kg of a substance. We must note that this heat goes into the breaking of the internal bonds of the material. Thus, the nature of the internal bonds in the materials are important when we are dealing with the latent heat of fusion.
We can see that the particles of ice are held together by the strong hydrogen bonds. As such, we can see that ice has the highest latent heat of fusion.
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Please help!
A pulley system is hanged in a lift as shown below in the
figure. A and B are two masses each having m and 2m mass
respectively. If d is the distance from the floor to B and the
lift starts to move with acceleration a, the time taken by B to reach the floor is,
1)
\( \sqrt{ \frac{6d}{(g + a)} } \)
2)
\(\sqrt{ \frac{6d}{g} }\)
3)
\(\sqrt{ \frac{6d}{(g - a)} }\)
4)
\( \frac{6d}{( g+ a)} \)
5)
\(\sqrt{ \frac{2d}{(g + a)} }\)
Answers
Answer:
B
Explanation:
Find the acceleration of the system
m2>m1
further m2 = 2m
and m1 = m
The acceleration is going to be the downward force created by m2 divided by the total mass (m2 + m2)
a = (m2*g - m1*g) / (m1 + m2)
a = (2m - m)*g/ (2m + m)
a = m * g/3m
a = 1/3 * g
Formula for time
Givens
distance := d
acceleration : = a
vi = 0
Kinematic Formula
d = vi * t + 1/2 a t^2
Solution
d = 0 + 1/2 * 1/3 g * t^2
6d = g * t^2
t^2 = 6d/g
t = √(6d/g)
Answer.
B
what is the longest wavelength λmaxλmaxlambda_max that is observed?
Answers
The longest wavelength λmax, λmax, lambda_max that is observed is determined by the temperature of the object emitting the radiation. The value of 2.9 x 10^-3 is a constant known as the Wien displacement constant.
The Wien’s displacement law relates the temperature of a blackbody to the wavelength λ at which the maximum amount of energy is emitted.This can be written as:x
λmax=2.9 x 10^-3 / T
where λmax is the wavelength at which the maximum amount of energy is emitted and T is the temperature in Kelvin. The value of 2.9 x 10^-3 is a constant called the Wien displacement constant. The longest wavelength λmax that is observed is dependent on the temperature of the object emitting the radiation. This value can be determined using Wien’s displacement law which relates the temperature of a blackbody to the wavelength λ at which the maximum amount of energy is emitted. The equation x
λmax=2.9 x 10^-3 / T is used to calculate the value of λmax.
Here, λmax is the wavelength at which the maximum amount of energy is emitted and T is the temperature in Kelvin. The value of 2.9 x 10^-3 is a constant known as the Wien displacement constant.
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An object initially at rest accelerates through a distance of 1.5 m at which point the instantaneous velocity of the object is 3.5 m/s.
a) What is the average acceleration of the object?
b) The time it took the object to travel 1.5 meters?
c) The average velocity of the object during this period of motion
Answers
The average acceleration is 2.33 m/s². the total distance traveled is 1.5 meters, and the total time taken is 0.84 seconds. The average velocity of the object during this period of motion is approximately 1.79 m/s.
The average acceleration of the object can be calculated by dividing the change in velocity by the distance traveled. In this case, the object started from rest and reached an instantaneous velocity of 3.5 m/s over a distance of 1.5 m. The change in velocity is 3.5 m/s - 0 m/s = 3.5 m/s. Therefore, the average acceleration is 3.5 m/s divided by 1.5 m, which equals 2.33 m/s².
distance = (initial velocity × time) + (0.5 × acceleration × time²). Given that the initial velocity is 0 m/s, the distance is 1.5 m, and the average acceleration is 2.33 m/s², we can solve for time. Rearranging the equation, we have 1.5 m = 0.5 × 2.33 m/s² × time². Solving for time, we find that it took approximately 0.84 seconds for the object to travel 1.5 meters. In this case, the total distance traveled is 1.5 meters, and the total time taken is 0.84 seconds. Therefore, the average velocity is 1.5 m divided by 0.84 s, which equals approximately 1.79 m/s.
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Deimos, a satellite of Mars, has an average radius of 6.3 km. If the gravitational force between Deimos and a 3.0 kg rock at its surface is 2.5 * 10−2 N what is the mass of Deimos?
Answers
The mass of Deimos is approximately 9.52 x 10^15 kg.
To find the mass of Deimos, we can use the formula for gravitational force:F = G * (m1 * m2) / r^2. where F is the gravitational force between two objects, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between their centers of mass.
In this problem, we know the radius of Deimos (r = 6.3 km = 6.3 x 10^3 m), the mass of the rock on its surface (m1 = 3.0 kg), and the gravitational force between them (F = 2.5 x 10^-2 N). We can also look up the value of G: G = 6.674 x 10^-11 N(m/kg)^2.
We want to solve for the mass of Deimos (m2). Rearranging the formula, we get: m2 = (F * r^2) / (G * m1). Substituting the given values, we get: m2 = (2.5 x 10^-2 N) * (6.3 x 10^3 m)^2 / (6.674 x 10^-11 N(m/kg)^2 * 3.0 kg). m2 = 9.52 x 10^15 kg.Therefore, the mass of Deimos is approximately 9.52 x 10^15 kg.
It is worth noting that this calculation assumes that the rock on Deimos' surface is not affecting its orbit significantly. In reality, the gravitational force between the rock and Deimos would cause some perturbations in Deimos' orbit, but they are likely to be very small due to the small mass of the rock compared to Deimos.
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To find the mass of Deimos, we can use the gravitational force formula:
F = G * (m1 * m2) / r^2
Where F is the gravitational force (2.5 * 10^(-2) N), G is the gravitational constant (6.674 * 10^(-11) Nm^2/kg^2), m1 is the mass of Deimos (which we want to find), m2 is the mass of the rock (3.0 kg), and r is the distance between their centers, which is equal to Deimos' radius (6.3 km or 6300 m).
Rearranging the formula to solve for m1 (the mass of Deimos):
m1 = (F * r^2) / (G * m2)
m1 = (2.5 * 10^(-2) N * (6300 m)^2) / (6.674 * 10^(-11) Nm^2/kg^2 * 3.0 kg)
After calculating, we find that the mass of Deimos is approximately 1.0 * 10^15 kg.
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a pendulum of mass 0.8 kg has 20 joules of potential energy at the top of its path. its kinetic energy at the bottom of its swing is:
Answers
The law of conservation of energy tells us that the total energy of a system remains constant. Therefore, the potential energy at the top of the pendulum's swing (20 J) must be equal to the kinetic energy at the bottom of its swing.
We can use the formula for kinetic energy:
Kinetic energy = 1/2 * mass * velocity^2
Since the pendulum's mass is given as 0.8 kg, we just need to solve for the velocity at the bottom of its swing.
20 J = 1/2 * 0.8 kg * v^2
Solving for v, we get:
v = √(40/0.8)
v ≈ 8.94 m/s
Now that we know the velocity at the bottom of the pendulum's swing, we can calculate its kinetic energy:
Kinetic energy = 1/2 * 0.8 kg * (8.94 m/s)^2
Kinetic energy ≈ 32 J
Therefore, the kinetic energy at the bottom of the pendulum's swing is approximately 32 joules.
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