Could some help me with this and explain it. I really need help

Answer:

a. Volume 120km^2

Surface area 168km^2

Step-by-step explanation:

Answer:

x^2 +2x -15

Step-by-step explanation:

FOIL

(x-3)(x+5)

first x*x = x^2

outer 5x

inner -3x

last -3*5 = -15

Add them together

x^2 +5x-3x-15

Combine like terms

x^2 +2x -15

Answer:

The median is 33.5

Step-by-step explanation:

In order to solve for a median it would either be the middle or it would be the average of the middle if there are even amount of numbers. First you would put them in order. 12 17 28 31 36 54 55 and 71. This would mean the the middle number would be 31 and 36. Since you can't have two medians you would find the average of the two so add 31 and 36 which would be equal to 67 then divide by 2 which would equal to 33.5.

The median of numbers 17, 12, 54, 36, 71, 28, 31, 55 is 33.5.

The median of a set of numbers is the middle value when the numbers are arranged in ascending or descending order.

To find the median of the given numbers, we first need to arrange them in ascending order:

12 17 28 31 36 54 55 71

Since there are an even number of numbers (8), the median will be the average of the two middle values, which are 31 and 36.

To find the average, we add the two numbers and divide by 2:

(31 + 36) / 2 = 67 / 2 = 33.5

Therefore, the median of the given numbers is 33.5.

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Answer:

Its C

Step-by-step explanation:

Im not sure if its correct but heres  the best i  explination I got!!

Ok so  first negatives would be least so ignore 13   and seven

now since  theres two that could be greater than the other ( -11 3/4 or -13) next would be  -7 after u and the 7 to 13! so ur best one is C since D and E make -11 behind 7 or scrambled in greatest

Answer:

Line DC: 24

Step-by-step explanation:

All lines are parallel to each other making AB and DC; 24 and BC and AD; 33

For all values of x greater than or equal to -2, the function f(x) = √(x + 2) + 2 will yield real outputs. So, x = -2.

To determine the input value at which the function f(x) = √(x + 2) + 2 begins to have real outputs, we need to find the values of x for which the expression inside the square root is non-negative. In other words, we need to solve the inequality x + 2 ≥ 0.

Subtracting 2 from both sides of the inequality, we get:

x ≥ -2

Therefore, the function f(x) = √(x + 2) + 2 will have real outputs for all values of x greater than or equal to -2.

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Answer:

ctrl + H to go to history and delete the stuff there

or private browsing

ideally you use a vpn like Proton vpn AND use private browsing to hide history

Answer:14.70

Step-by-step explanation: 14.70

The error sum of squares, SSE, is 2592. The correct answer is option b.

As per the question, the standard error of the estimate is 18 and n is 10.

We can use the formula for the standard error of estimate to find the error sum of squares (SSE):

standard error of estimate = √(SSE / (n - 2))

Squaring both sides of the equation and solving for SSE, we get:

SSE = (n - 2) x standard error of estimate²

SSE = (10 - 2) x 18²

SSE = 8 x 324

SSE = 2592

Therefore, the error sum of squares, SSE, is 2592.

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The probability of running out of water decreases.

The given problem can be solved by using the concept of the normal distribution. Normal distribution, also called Gaussian distribution, is a probability distribution that occurs naturally in many situations. In this distribution, data values cluster around a central point, and the further away a value is from the center, the less likely it is to occur. The normal distribution has two parameters: the mean (μ) and the standard deviation (σ). The mean is the center of the distribution, and the standard deviation is a measure of how spread out the distribution is. The normal distribution is symmetric about the mean. It is a continuous distribution, meaning that it can take any value between negative infinity and positive infinity. The area under the normal curve represents the probability of a random variable taking a certain value or falling within a certain range of values. The total area under the normal curve is equal to 1.
Given:
The average person drinks 3 Liters of water when hiking the Mission Peak (with a standard deviation of 1 Liter).
You are planning a hiking trip to the Mission Peak for 10 people and will bring 35 Liters of water.
What is the probability that you will run out?
We need to find the probability that the amount of water consumed by 10 people will be greater than 35 Liters. Let X be the random variable representing the amount of water consumed by each person. X is normally distributed with mean μ = 3 Liters and standard deviation σ = 1 Liter.
Then, the total amount of water consumed by 10 people is given by the sum of 10 independent identically distributed (i.i.d.) random variables:
Y = X1 + X2 + ... + X10
where X1, X2, ..., X10 are i.i.d. random variables with the same distribution as X.
The total amount of water you bring is 35 Liters. Therefore, you will run out of water if:
Y > 35
or equivalently:
(Y - μ10) / σ10 > (35 - μ10) / σ10
where μ10 = 10μ = 30 Liters and σ10 = √(10)σ = √(10) Liters.
Thus, the probability that you will run out of water is:
P(Y > 35) = P[(Y - μ10) / σ10 > (35 - μ10) / σ10]
= P(Z > (35 - μ10) / σ10)
where Z is the standard normal variable.
Using the standard normal table, we find that:
P(Z > (35 - μ10) / σ10) = P(Z > (35 - 30) / √10)
= P(Z > 1.5811)
= 0.0564 (rounded to four decimal places)
Therefore, the probability that you will run out of water when hiking the Mission Peak with 10 people is 0.0564.
What if the hiking trip will have 20 people and the amount of water you bring also doubles to 70 Liters. What is the probability you will run out?
In this case, the number of people has doubled, so the total amount of water consumed will also double. Thus, the total amount of water consumed by 20 people is given by:
Y = X1 + X2 + ... + X20
where X1, X2, ..., X20 are i.i.d. random variables with the same distribution as X.
The total amount of water you bring is 70 Liters. Therefore, you will run out of water if:
Y > 70
or equivalently:
(Y - μ20) / σ20 > (70 - μ20) / σ20
where μ20 = 20μ = 60 Liters and σ20 = √(20)σ = 2.2361 Liters.
Thus, the probability that you will run out of water is:
P(Y > 70) = P[(Y - μ20) / σ20 > (70 - μ20) / σ20]
= P(Z > (70 - μ20) / σ20)
where Z is the standard normal variable.
Using the standard normal table, we find that:
P(Z > (70 - μ20) / σ20) = P(Z > (70 - 60) / 2.2361)
= P(Z > 4.4721)
= 0 (rounded to four decimal places)
Therefore, the probability that you will run out of water when hiking the Mission Peak with 20 people is zero.

Will the probability of running out of water increase or decrease? Why?

The probability of running out of water decreases when the number of people increases and the amount of water brought doubles. This is because the total amount of water consumed increases proportionally to the number of people, but the standard deviation of the distribution of the amount of water consumed decreases proportionally to the square root of the number of people. This means that the distribution of the total amount of water consumed becomes narrower and more concentrated around the mean as the number of people increases.

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Answer:

(x2 + 3)(2x − 5)

Step-by-step explanation:

The composite functions f ∘ g and g ∘ f is defined as follows:

f ∘ g (x) = f(g(x))

g ∘ f (x) = g(f(x))

In other words, f ∘ g is the composition of two functions f and g, such that the output of g is used as the input to f. Similarly, g ∘ f is the composition of two functions g and f, such that the output of f is used as the input to g.

It's important to note that the order in which the functions are composed matters, as f ∘ g is not necessarily equal to g ∘ f. In general, the composite function of two functions is not commutative, meaning that the order in which the functions are composed affects the result.

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Answer:

he started with either 20 or 15 i probably thought about this way to much so this is the best i could come up with

Step-by-step explanation:

Answer:

x = 94, y = 76

Step-by-step explanation:

The opposite angles of a cyclic quadrilateral sum to 180° , then

x + 86 = 180 ( subtract 86 from both sides )

x = 94

and

y + 104 = 180 ( subtract 104 from both sides )

y = 76

1. The break-even point in unit sales and in dollar sales is 4,500 units and $324,000 respectively.

2. If the variable expenses per stove increase as a percentage of the selling price, will it result in a higher break-even point.

3. Income statements before and after changes are implement net income of $36,000 and $(28,000) respectively.

4. The company has to sell 5,401 units to achieve the target profit of $35,000 per month.

1. The break-even point in unit sales and dollar sales is computed as follows:

Break-Even Point in Unit Sales = Fixed Costs / Contribution Margin per Unit = $108,000 / ($50 - $32) = 4,500 units

Break-Even Point in Dollar Sales = Fixed Costs / Contribution Margin Ratio = $108,000 / ($50 / $18) = $324,000

2. If variable expenses per stove increase as a percentage of selling price, it will result in a higher break-even point. Since variable expenses would have a higher percentage of revenue, contribution margin would be lower, making it more challenging to cover fixed costs.

3. Present Income Statement

Sales (8,000*$50) $400,000

Less variable expenses (8,000*$32) (256,000)

Contribution Margin $144,000

Less fixed expenses 108,000

Net Income $36,000

Income Statement if Changes are Implemented

Sales (8,000*$45) $360,000

Less variable expenses (8,000*$35) (280,000)

Contribution Margin $80,000

Less fixed expenses 108,000

Net Loss $(28,000)

4. The contribution margin ratio is 36% ($18/$50). So, the sales revenue required to achieve the target profit is:

$35,000 / 0.36 = $97,222

The number of units required to be sold is:

$97,222 / $18 = 5,401 units

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Answer: Quarters

Step-by-step explanation:

Answer:T

Step-by-step explanation:

The paths that will stay outside or on the boundary of the square-2≤ x≤2, -2≤y ≤2 at each step will be 1698

We'll make advantage of the complementary counting idea. If you enter the square, you must exit by the boundaries and by the designated points because otherwise, you would touch another point in one of the sets of points in the connection (Call it S). Since y=x is symmetric, we simply need to take into account (1,-1), (1,0), and (1,1). We can only investigate one scenario and multiply it by two since (1,1) can cross the barrier in two different ways. We may just multiply (1,0) by two and (1,-1) by two. Therefore, we count the routes from (-4,4) to each of these sites and multiply that number by the total number of routes from the starting position.

\((\left {{16} \atop {8}} \right.) -2[(\left {{8} \atop {3}} \right.) (\left {{7} \atop {2}} \right.) +(\left {{9} \atop {4}} \right.) (\left {{6} \atop {2}} \right.) +(\left {{10} \atop {5}} \right.) (\left {{5} \atop {2}} \right.)] =1698\)

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Your question is incomplete, but most probably, the full question was:

A 16-step path is to go from (-4,-4) to (4,4) with each step increasing either the x-coordinate or the y-coordinate by 1. How many such paths stay outside or on the boundary of the square -2≤ x≤2, -2≤y ≤2 at each step?

A.92

B.144

C.1568

D.1698

E.12800

The cost of each printer is $568.

To find the cost of each printer, we need to use a system of equations.

Let's call the cost of each printer "p" and the cost of each camera "c".

The first equation we can create is: 6p + 3c = 4773

The second equation we can create is: 4p + 6c = 5002

Now we can use the elimination method to solve for one of the variables.

Let's eliminate the "c" variable by multiplying the first equation by -2: -12p - 6c = -9546

And then add the two equations together: -8p = -4544

Now we can solve for "p" by dividing both sides by -8: p = 568

So the cost of each printer is $568.

To find the cost of each camera, we can plug the value of "p" back into one of the original equations and solve for "c":

6(568) + 3c = 4773

3408 + 3c = 4773

3c = 1365

c = 455

So the cost of each camera is $455.

Therefore, the cost of each printer is $568 and the cost of each camera is $455.

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In summary, the equation for the tangent plane can be written as z - z0 = ∂f/∂x(x0, y0)(x - x0) + ∂f/∂y(x0, y0)(y - y0), where (x0, y0, z0) represents the coordinates of the given point. This equation represents a linear approximation of the surface near the point of tangency.

To understand the equation for the tangent plane, we start by considering the first-order partial derivatives of the function f(x, y) with respect to x and y. These partial derivatives, denoted as ∂f/∂x and ∂f/∂y, represent the rates of change of the surface with respect to x and y, respectively. At the point (x0, y0), the tangent plane approximates the behavior of the surface near that point.

The equation for the tangent plane is derived by using the point-slope form of a linear equation, where the slope of the plane in the x-direction is given by ∂f/∂x(x0, y0) and in the y-direction by ∂f/∂y(x0, y0). The equation is then written as z - z0 = ∂f/∂x(x0, y0)(x - x0) + ∂f/∂y(x0, y0)(y - y0), which relates the changes in x and y coordinates to the change in z-coordinate on the tangent plane.

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Answer:well what is it

Step-by-step explanation:

Question 4 is about calculating the probability of having a jury pool of less than 60 members. If the probability of that happening is extremely low, then it is unlikely that the jury-selection process was carried out properly. However, the logic of Question 4 only applies to jury pools with less than 60 members.

Therefore, jury pools with 61, 62, . . . , 99 members do not need to be considered when rendering a verdict about whether or not the jury-selection process was carried out properly. My verdict would depend on the actual probability calculated in Question 4. If the probability of having a jury pool of less than 60 members is extremely low, then it is likely that the jury-selection process was not carried out properly. If the probability is relatively high, then it is more likely that the jury-selection process was carried out properly.

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the Taylor polynomials of degree 2 and 3 centered at $a=0$ for the function $f(x) = \cosh(4)$ are $P_{2}(x) = 8x^2$ and $P_{3}(x) = 8x^2 + \frac{8}{3}x^3$, respectively.

To find the Taylor polynomials of degree 2 and 3 centered at $a=0$ for the function $f(x) = \cosh(4)$, we need to calculate the function's derivatives at $x=0$ up to the desired degree.

First, let's find the derivatives of $f(x) = \cosh(4)$:

\begin{align*}

f(x) &= \cosh(4) = \frac{e^{4}+e^{-4}}{2} \

f'(x) &= \frac{d}{dx}\left(\frac{e^{4}+e^{-4}}{2}\right) = \frac{e^{4}-e^{-4}}{2} \

f''(x) &= \frac{d}{dx}\left(\frac{e^{4}-e^{-4}}{2}\right) = \frac{e^{4}+e^{-4}}{2} \

f'''(x) &= \frac{d}{dx}\left(\frac{e^{4}+e^{-4}}{2}\right) = \frac{e^{4}-e^{-4}}{2}

\end{align*}

Next, we can use the Taylor series formula to find the Taylor polynomials:

\begin{align*}

P_{2}(x) &= f(0) + f'(0)x + \frac{f''(0)}{2!}x^2 = 1 + 0x + \frac{1}{2}(16)x^2 = 8x^2 \

P_{3}(x) &= f(0) + f'(0)x + \frac{f''(0)}{2!}x^2 + \frac{f'''(0)}{3!}x^3 = 1 + 0x + \frac{1}{2}(16)x^2 + \frac{1}{3!}(16)x^3 = 8x^2 + \frac{8}{3}x^3

\end{align*}

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Answer:

please see analysis

step by step explanation

\(if \: y \: varies \: inversely \: as \: \: as \: x \ \: meanc \\ y = \frac{k}{x} \\ where \: y = 1 \: \: x = 3 \\ 1 = \frac{k}{3} \\ k = 3 \times 1 = 3 \\ equation \: connecting \: x \: and \: y \\ y = \frac{3}{x} \\ finding \: y \: when \: x = 9 \\ y = \frac{3}{9} \\ y = \frac{1}{3} \)

The total change in the consumed quantity of x₁ as per given price and income  is equal to 213.

x₁ = (21/7)P₁

x₂ = (51/7)P₂

P₁ = 10

P₂ = 5

P₁' = 81

To calculate the total change in the quantity consumed of x₁ when the price of P₁ changes from P₁ to P₁',

The difference between the quantities consumed at the original price and the new price.

Let's calculate the quantity consumed at the original price,

x₁ orig

= (21/7)P₁

= (21/7) × 10

= 30

x₂ orig

= (51/7)P₂

= (51/7) × 5

= 36.4286 (approximated to 4 decimal places)

Now, let's calculate the quantity consumed at the new price,

x₁ new

= (21/7)P1'

= (21/7) × 81

= 243

x₂ new

= (51/7)P2

= (51/7) × 5

= 36.4286

The total change in the quantity consumed of x₁ can be calculated as the difference between the new quantity and the original quantity,

Change in x₁

= x₁ new - x₁ original

= 243 - 30

= 213

Therefore, the total change in the quantity consumed of x₁ is 213.

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The above question is incomplete, the complete question is:

The optimal amount of x1, x2, P1, P2 and income are given by the following:

x1= 21/ 7p1 x2= 51 / 7p2

The original prices are: P1=10 P2=5 The original income is: I =4189 The new price of P1 is the following: P1'=81 Assume that the price of x1 has changed from P1 to P1'. What is the total change in the quantity consumed of x1?

Please answer step by step

The best measure of variability for the data and the player which was more consistent include the following: B. Player B is the most consistent, with a range of 9.

In Mathematics and Statistics, interquartile range (IQR) of a data set and it is typically calculated as the difference between the first quartile (Q₁) and third quartile (Q₃):

Interquartile range (IQR) of Player A = Q₃ - Q₁

Interquartile range (IQR) of Player A = 4 - 1.5

Interquartile range (IQR) of Player A = 2.5.

Range of Player A = Highest number - Lowest number

Range of Player A = 8 - 1

Range of Player A = 7

Interquartile range (IQR) of Player B = Q₃ - Q₁

Interquartile range (IQR) of Player B = 5 - 1.5

Interquartile range (IQR) of Player B = 4.5.

Range of Player B = Highest number - Lowest number

Range of Player B = 10 - 1

Range of Player B = 9

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Answer:

4

Step-by-step explanation:

The graph of the function is attached in the solution.

A graph is a diagram or a pictorial representation of data or values that show the relationship between quantities or objects.

Given is an equation, y = 2x-4, we need to determine its graph,

So, for the same, finding the coordinates,

y = 2x-4

Put x = 0

y = -4

(0, -4)

Put x = 1

y = -2

(1, -2)

Put the coordinates on the graph and the join them, the line obtained by this will represent the graph of the function given.

Hence. the graph of the function is a straight line.

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The lifting force if the speed is 220 miles per hour is F' = 708.53 N.

The force of light, or simply light, is the sum of all forces on an object that cause the object to move perpendicular to the direction of flow.

The most common type of lift is the wing lift. But there are many other common uses, such as propellers on airplanes and ships, rotors on helicopters, fan blades, sails on sailboats, and wind turbines.

We have,

The lifting force, F, exerted on an airplane wing varies jointly as the area, A, of the wing's surface and the square of the plane's velocity, v. It, means that,

\(F=kAv^{2}\)

Where

k is constant

If, A = 190 Ft², v = 220 mph, F = 950 pounds

Now, find k first from the above data. So,

    \(k=\frac{F}{Av^{2} }\)

⇒ \(k=\frac{950}{190* (220)^2}\)

⇒ k = 0.0001033

It is required to find the lifting force on the wing if the plane slows down to 190 miles per hour.

Let F' is a new force. So,

    F' = 0.0001033 × 190 × (190)²

⇒ F' = 708.53 pounds.

So, the lifting force is 708.53 pounds if the plane slows down to 190 miles per hour.

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