60 miles / hr
= 60 * 1.6 * 1000 m / 60 * 60 s
= 96000 m / 3600 s
= 26.67 m / s
In a 92 s interval, 562 hailstones strike a glasswindow of area 1.216 m² at an angle 64° to thewindow surface. Each hailstone has a mass of2 g and speed of 5.8 m/s.If the collisions are elastic, find the averageforce on the window.Answer in units of N.
Given that the number of hailstones is n = 562
The mass of hailstone is m = 2 g = 0.002 kg
The speed of hailstone is v = 5.8 m/s
The time taken will be t = 92 s
The angle is
\(\theta=64^{\circ}\)We have to calculate the force.
The force can be calculated by the formula
\(\begin{gathered} F=\text{ force due to one hailstone }\times numberofhailstones\text{ } \\ =m\frac{v}{t}\sin \theta\times n \end{gathered}\)Substituting the values, the force will be
\(\begin{gathered} F=\text{ }\frac{\text{0.002}\times5.8\times\sin 64^{\circ}\times562}{92} \\ =0.063\text{ N} \end{gathered}\)A laser beam is used to levitate a metal disk against the force of earth's gravity.
(a) derive an equation giving the required intensity of light, i, in terms of the mass m of the disk, the gravitational acceleration g, the speed of light c, and the cross-sectional area of the disk a. assume the disk is perfectly reflecting and the beam is directed perpendicular to the disk. (do not substitute numerical values; use variables only.)
i =
(b) if the disk has mass 3.89 g and radius 2.40 cm, find the necessary light intensity.
(c) give two reasons why using light pressure as propulsion near earth's surface is impractical.
The necessary light intensity of the disk if the disk has mass 3.89 g and radius 2.40 cm is 6.483 x 10^12cd.
Calculations and Parameters:a. Given that:
i= intensity of light m= mass of disk g= gravitational acceleration c= speed of light a= cross-sectional area of the diskI = P/A
= Force x Speed/Area
Gravitational force, F= GM1M2/r^2
F= ma, F= mg
I= mg x c/q
That is,
i= mass x gravitational acceleration x speed/area
b.
Mass= 3.89g
Radius, r= 2.40cm
i=?
i= mg x c/a
Speed of light= 3.0 x 10^8 m/s
Area, a= /pi r^2
= 3.142 x (0.024)^2
= 3.142 x 0.000576
= 0.0018m^2.
i= 3.89 x 10 x 3.0 x 10^8/0.0018
i= 6.483 x 10^12cd.
c. Light has no mass, therefore, it lacks momentum and cannot exert pressure for propulsion of materials.
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if the current in the long straight wire is increasing, what current is induced in the circular loop?
If the current in a long straight wire is increasing, the current is induced in the circular loop will be generated in the nearby circular loop.
Faraday's Law states that the electromotive force (EMF) induced in a circuit is proportional to the rate of change of magnetic flux passing through it. As the current in the straight wire increases, the magnetic field around it strengthens, and the change in magnetic flux through the circular loop causes an induced current. The direction of this induced current is determined by Lenz's Law, which states that the induced current will flow in such a way as to oppose the change in magnetic flux causing it.
In this case, as the magnetic field due to the straight wire increases, the induced current in the circular loop will flow in a direction that generates a magnetic field opposing the increase in the straight wire's magnetic field. The magnitude of the induced current depends on the rate of change of the magnetic field, the loop's size, shape, and distance from the straight wire, as well as the resistance of the loop's material. If the current in a long straight wire is increasing, the current is induced in the circular loop will be generated in the nearby circular loop.
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Which structure is not a component of the adaptive immune system?HintsTissues.Thymus.Lymphatic ducts.Spleen.
Among the options provided, the structure that is not a component of the adaptive immune system is "Lymphatic ducts."
The adaptive immune system consists of various components that work together to identify and eliminate pathogens. While tissues, thymus, and spleen play crucial roles in this system, lymphatic ducts serve as channels for lymphatic fluid and are part of the lymphatic system, which supports both innate and adaptive immunity by transporting immune cells and filtering out harmful substances. Thus, lymphatic ducts are not a direct component of the adaptive immune system, but they do support it by maintaining proper circulation and waste removal.
Lymphatic ducts are not a component of the adaptive immune system, but they contribute to overall immunity by supporting the transport and filtration of immune cells and substances.
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Electric charge only has an amount. That makes it a
at which the bead is in vertical equilibrium. (of course, it has a radial acceleration toward the axis.)
When a bead is sliding along a wire that is bent into a circular shape and rotating about its vertical axis, it experiences a radial acceleration towards the axis of rotation. At a certain point along the wire, the bead will be in vertical equilibrium, meaning that it experiences no net force in the vertical direction.
This occurs when the gravitational force acting on the bead is balanced by the centrifugal force resulting from the circular motion of the wire. The centrifugal force is directed radially outwards from the axis of rotation and is proportional to the square of the angular velocity of the wire.
At the point of vertical equilibrium, the magnitude of the centrifugal force is equal to the magnitude of the gravitational force acting on the bead. This allows the bead to remain in a stable position on the wire, without moving up or down.
Therefore, the point of vertical equilibrium can be determined by balancing the gravitational force and the centrifugal force acting on the bead, which occurs at a specific distance from the axis of rotation and at a specific angular velocity of the wire.
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A rifle fires a bullet of mass 0.020 kg vertically upwards through the air. As it leaves the rifle, the
speed of the bullet is 350 m / s.
1
(a) Calculate
(i) the kinetic energy of the bullet as it leaves the rifle,
The kinetic energy of the bullet of mass 0.020 kg firing with a speed of 350 m/s is 1225 J.
What is kinetic energy ?Kinetic energy of an object is generated by virtue of its motion. The energy stored on it when it is at rest is called its potential energy. When the object starts moving its potential energy starts converting to kinetic energy.
The kinetic energy of an object is related to its mass and velocity as written below:
Ke = 1/2 mv²
given that mass of the bullet = 350 m/s
velocity v = 350 m/s
then, kinetic energy of the bullet = 1/2 0.02 Kg × 350 m/s = 1225 J.
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The mass of the car is m = 987 kg. The speed is v = 28.8m/s. The coefficient of kinetic friction is µk = 0.301. Determine the mechanical energy lost.
The mechanical energy lost by the car is 246415.84 J.
What is mechanical energy?This can be defined as the energy possessed by a body due to motion or due to its position.
To calculate the mechanical energy lost, we use the formula below.
Formula:
E' = μkmv².................. Equation 1Where:
E' = Mechanical energy lost of the carμk = coefficient of kinetic energym = mass of the carv = velocity of the car.From the question,
Given:
m = 987 kgv = 28.8 m/sμk = 0.301Substitute these values into equation 1
E' = 987(28.8)²(0.301)E' = 246415.84 J.Hence, The mechanical energy lost by the car is 246415.84 J.
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what is the relationship between the voltage across the energy
source and the voltages across the lamps in parallel
Answer:
وؤتي يتنييوتينستصميوخصز ءتث. ثنصطث
Answer Questions below
Answer:
When several resistors are connected in series, the total resistance equals the sum of the individual resistors. In series combination, the current is same through each resistor.
1) V= 60 volt
Total resistance R = R₁ + R₂
= 20 + 10
= 30 Ω
2) Ohms law states that,
\(\sf I =\dfrac{V}{R}\\\\\\I = \dfrac{60}{30}\\\\I = 2 \ A\)
3) Voltage around 10 Ω resistor,
V₂ = I R₂
= 2 * 10
= 20 volt
___________________________________________________
4) Total current = 1 A
5) Total voltage = 8 volt
6) Voltage around R₁ is V₁
R₁ = 2 Ω ; I = 1 A
V₁ = IR₁
= 1 * 2
= 2 volt
7) Resistance 2:
Total resistance = R
Total voltage = V = 8 volt
Total current = I = 1 A
\(\sf R = \dfrac{V}{I}\\\\\\ R = \dfrac{8}{1}\\\\\)
R = 8 Ω
R₁ + R₂ = 8 Ω
2 + R₂ = 8
R₂ = 8 - 2
R₂ = 6 Ω
8)Voltage around R₂:
\(\sf V_2 = IR_2\\\\V_2 = 1*6\\\\\)
V₂ = 6 volt
9) Total R = 8 Ω
_________________________________________________
10) Total V = 12 volt
11) Total R = 8 + 8
= 16 Ω
12) Total current I,
\(\sf I = \dfrac{V}{R}\\\\I = \dfrac{12}{16}\\\\I = 0.75 \ A\)
13) Voltage at each resistor:
V₁ = I*R₁
= 0.75 * 8
= 6 volt
V₂ = I*R₂
= 0.75 * 8
= 6 volt
_______________________________________________________
14) Total R = 40 + 20
= 60 Ω
15) To find V₁, first find total voltage.
I = 2 A ; R = 60 Ω
V = IR
= 2 * 60
= 120 V
V₁ + V₂ =V
V₁ + 80 = 120
V₁ = 120 - 80
V₁ = 40 volt
A heat engine takes in 500kW of heat power at a temperature of 500oC and rejects 265kW at a temperature of 50oC. (a). Determine the thermal efficiency of this cycle, then (b) Determine the thermal efficiency of the corresponding Carnot cycle and (c) Based on a comparison of these two efficiencies, can this heat engine exist? Explain your answer.
The thermal efficiency of the given heat engine is 47%, while the thermal efficiency of the corresponding Carnot cycle is 58.24%. The heat engine falls short of the Carnot efficiency, suggesting inefficiencies or design limitations.
(a) To determine the thermal efficiency of the given heat engine, we can use the formula:
Thermal Efficiency = (Net Work Output / Heat Input) * 100
The net work output can be calculated by subtracting the heat rejected from the heat input:
Net Work Output = Heat Input - Heat Rejected
Given:
Heat Input = 500 kW
Heat Rejected = 265 kW
Substituting these values into the formula, we have:
Net Work Output = 500 kW - 265 kW = 235 kW
Now, we can calculate the thermal efficiency:
Thermal Efficiency = (235 kW / 500 kW) * 100 = 47%
Therefore, the thermal efficiency of this cycle is 47%.
(b) The Carnot cycle is an idealized reversible heat engine that operates between two heat reservoirs. Its thermal efficiency can be determined using the formula:
Thermal Efficiency Carnot = 1 - (T_low / T_high)
Given:
T_low = 50°C + 273.15 = 323.15 K
T_high = 500°C + 273.15 = 773.15 K
Substituting these values into the formula, we have:
Thermal Efficiency Carnot = 1 - (323.15 K / 773.15 K) ≈ 0.5824 (58.24%)
Therefore, the thermal efficiency of the corresponding Carnot cycle is approximately 58.24%.
(c) Comparing the thermal efficiency of the given heat engine (47%) with the thermal efficiency of the Carnot cycle (58.24%), we can conclude that the heat engine is less efficient than the corresponding Carnot cycle. In theory, the maximum efficiency any heat engine can achieve is the Carnot efficiency when operating between the same temperature limits. The given heat engine falls short of the Carnot efficiency, indicating that it is not operating at the maximum possible efficiency.
This comparison suggests that the given heat engine may not be feasible or ideal. It could be due to factors such as irreversibilities, inefficiencies in the conversion of heat to work, or losses in the system. Improving the design or addressing these inefficiencies would be necessary to approach the ideal efficiency of the Carnot cycle.
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audrey disassembles the control box of her electric train and finds a small transformer inside. It’s primarily made up of 600 turns and the secondary coil is made up of 60 turns. If the household voltage supplied to the train is 120 V, what voltage is required to make the train run
The voltage that is required to run the train is found to be 12V.
Since the transformer has 600 turns in the primary coil and 60 turns in the secondary coil, the turns ratio is 600:60, which simplifies to 10:1. To find the voltage required to make the train run, we need to use the turns ratio equation,
Vp/Vs = Np/Ns, The voltages of the primary and secondary coils are Vp and Vs, respectively. The primary coil has Np turns, while the secondary coil has Ns turns.
We know that the household voltage supplied to the train is 120 V, which is the voltage in the primary coil (Vp). We want to find the voltage in the secondary coil (Vs). Substituting the values we know into the turns ratio equation, we get,
120/Vs = 10/1
Simplifying this equation, we get,
Vs = 12 V
Therefore, the voltage required to make the train run is 12 V.
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The first law of thermodynamics states that energy can neither be created nor destroyed. If this is true then why are we always looking for new sources of energy? Use the 2nd law of thermodynamics to answer this question.
Answer:
The second law of thermodynamics states in an isolated system, the entropy (the amount of thermal energy that cannot be converted into mechanical work, also known as the amount of disorder) always increases, therefore, an isolated system always require an external input (new sources) of energy for there to be orderliness or for the available energy of the system to remain constant or increase
Explanation:
A train travels at a speed of 30mph and travelled a distance of 240 miles. How long did it take the train to complete its journey? Must show your work
Answer:
8
Explanation:
240 divided by 30 = 8
A 40. 0-kilogram child exerts a 100. -newton force on a 50. 0-kilogram object. The magnitude of the force that the object exerts on the child is.
The magnitude of the force that the object exerts on the child is 100 N.
Calculation:-
mass of object = 50 kg
Force exerted by child = 100 N
From newton's third law of motion, equal and opposite force is applied.
Hence, force the object exert is same 100 N.
Force is a push or pulls upon an item because of the object's interaction with some other object. pressure is a power that can exchange the motion of an object. A force can reason an object with mass to alternate its speed, i.e, to boost up. pressure also can be described intuitively as a push or a pull. A force has each significance and course, making it a vector amount.
The phrase 'Force' has a unique meaning. At this degree, it is absolutely appropriate to describe a force as a push or a pull. A force is not something that an object consists of or 'has in it. A force is exerted on one object through another. The concept of a force isn't always restricted to living matters or non-living matters.
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Suppose a spectral line of hydrogen, normally at 500 nm when measured in a lab on Earth, is observed in the spectrum of a star to be at 500.3 nm. This is called a red shift because the wavelength is longer (and red is on the long-wavelength side of the visible spectrum). How fast is the star moving away from Earth? Give your answer in m/s. Hint: follow example 5.6. Compare in particular to the "Check your learning" calculation, and note that larger Δλ means larger speed.
The star is moving away from Earth at a velocity of 1.8 x 106 m/s.
The Doppler Effect describes the shift in wavelength of a wave when the source is moving in relation to the observer. The shift can be observed in sound waves, light waves, and other waves.
The Doppler Effect can be used to determine the velocity of objects moving away from an observer, as in the case of stars moving away from Earth.
The velocity of a star moving away from Earth can be determined using the equation:
v = Δλ/λ x c, Where v is the velocity of the star, Δλ is the shift in wavelength of the spectral line, λ is the wavelength of the spectral line measured in the lab on Earth, and c is the speed of light (3.00 x 108 m/s).
In this case, the shift in wavelength of the spectral line is Δλ = 500.3 nm - 500 nm = 0.3 nm.
The wavelength of the spectral line measured in the lab on Earth is λ = 500 nm.
Plugging in these values to the equation above: v = Δλ/λ x cv = (0.3 nm / 500 nm) x (3.00 x 108 m/s) = 1.8 x 106 m/s.
Therefore, velocity of star 1.8 x 106 m/s.
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a frictionless pendulum clock on the surface of the earth has a period of 1.00 s. on a distant planet, the length of the pendulum must be shortened slightly to have a period of 1.00 s. what is true about the acceleration due to gravity on the distant planet?a frictionless pendulum clock on the surface of the earth has a period of 1.00 s. on a distant planet, the length of the pendulum must be shortened slightly to have a period of 1.00 s. what is true about the acceleration due to gravity on the distant planet?the gravitational acceleration on the planet is slightly less than g .the gravitational acceleration on the planet is equal to g .the gravitational acceleration on the planet is slightly greater than g .we cannot tell because we do not know the mass of the pendulum.
The gravitational acceleration on the distant planet is slightly less than g.
What is Acceleration?
Acceleration is a physical quantity that describes the rate of change of velocity of an object with respect to time. In other words, acceleration is the amount by which an object's velocity changes in a given time interval.
The period of a simple pendulum is given by T = 2π √(L/g), where L is the length of the pendulum and g is the acceleration due to gravity. If the period is kept constant and the length of the pendulum is shortened, then the acceleration due to gravity must also decrease.
In this case, the period of the pendulum clock is 1.00 s on both the Earth and the distant planet. Therefore, we can write:
2π √(L/g_Earth) = 1.00 s, and
2π √(L/g_planet) = 1.00 s.
Dividing the two equations, we get:
g_planet/g_Earth = \((T_Earth/T_planet)^{2}\) = 1.
Since the period is the same on both planets, the ratio of the gravitational accelerations is also 1. Therefore, the gravitational acceleration on the distant planet is equal to the acceleration due to gravity on Earth, which is approximately 9.81 m/\(s^{2}\).
However, since the length of the pendulum on the distant planet is slightly shorter, the value of g_planet must be slightly less than g_Earth to maintain the same period of oscillation.
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Someone, please help!! cant understand
Answer:
4400 N
Explanation: (c)
P= \(\frac{F}{A}\)
F= PA
P= pressure
A= area
P=800x\(10^{3\\\) and A= 5.5 x \(10^{-3}\)\(m^{2}\)
Force F= 800x\(10^{3}\)x0.0055= 4400 N
force exerted by the gas on the piston is 4400 N
How does the strength of a magnetic field around a wire vary?
Answer:
By pointing one's right thumb along the direction of the current, the direction of the magnetic field can by found by curving one's fingers around the wire. The strength of the magnetic field depends on the current I in the wire and r, the distance from the wire.
The urban legend of the car thief is an example of what theme?
Societal Change
A Common Fear
A Cautionary Tale
A Prank
The urban legend of the car thief is an example of A Cautionary Tale.
What is the Cautionary Tale?A cautionary tale makes reference to a given tale aimed at the warning the person of some type of danger, which is generally used to alert about a given behavior and may be very useful to modify a behavior pattern in children.
Therefore, with this data, we can see that A cautionary tale is based on warning and can help to modify certain behavior in c children depending on the ability to create conscious.
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Tiny mass of 67kg and tubby mass of 83 kg are now on the opposite ends of a see saw and are both 1.4m from the balance point where should their sister teeny whose mass is 32 kg sit so the see saw balances
Answer:
0.7 m between the balance point and Tiny
Explanation:
It's intuitive to say she sould be on the side the smaller mass is placed. How far from the balance point?
Let's call x that distance. and assume that the contraption is "oriented" so that being on the side with tiny (and teeny) gives you a positive distance from the balance point, and negative on the other side.
At equilibrium, the sum of all momentums (momenta?) will be zero:
\(67\times 1.4 +32\times x + 83 \times (-1.4) = 0\\32x -16(1.4) = 0 \rightarrow 2x=1.4 x= 0.7\)
In layman's term, she has to be halfway between the balance point and Tiny.
which one of the following is true
a. momentum results in a change of force
B. a force results in a change of momentum
Answer:
B
Explanation:
You need a specific force to change the momentum of something.
Hope this helps!
Which analogy best explains why inflation predicts that the overall geometry of the observable universe should appear to be flat?.
Because of how large Earth is, an ant's exploration of it makes it appear flat. It appears that the Big Bang theory explains how components were created in the first few minutes following the Big Bang.
What does Earth actually go by?Contrary to popular belief, Earth doesn't provide an official international name. The word "Terra" is merely a common misunderstanding of the scientific name for the planet. "Earth" is the commonly used English name for the planet, particularly in scientific contexts.
Is the Earth a star?A planet like the Earth revolves around a star called the sun. A star is typically understood to be a mass of gas that is sufficiently massive and dense to enable nuclear fusion to occur at its core.
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The height of the 500-mb pressure level plotted at North Platte (LBF) in western Nebraska was ______ m above sea level (denoted 555).
The height of the 500-mb pressure level plotted at North Platte (LBF) in western Nebraska was 5,570 meters m above sea level.
What is pressure?
Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed.
Pressure level plotted at North PlatteRecalling that the heights plotted at individual stations on 500-mb maps are in tens of meters (place a 0 to the right of the three plotted digits).
The coded height at North Platte, in west-central Nebraska, ("557") indicated 500 mb occurred at 5,570 meters above sea level.
Thus, The height of the 500-mb pressure level plotted at North Platte (LBF) in western Nebraska was 5,570 meters m above sea level.
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olaf is standing on a sheet of ice that covers the football stadium parking lot in buffalo, new york; there is negligible friction between his feet and the ice. a friend throws olaf a ball of mass 0.400 kg that is traveling horizontally at 11.1 m/s . olaf's mass is 71.8 kgif the ball hits olaf and bounces off his chest horizontally at 7.40 m/s in the opposite direction, what is his speed vf after the collision?
This is determined by applying the law of conservation of momentum to the collision between Olaf and the ball. The calculation yields an output of 2.65 m/s for Olaf's final velocity.
When the ball collides with Olaf, the law of conservation of momentum applies. Momentum is defined as the product of mass and velocity. Before the collision, the total momentum of the system (Olaf and the ball) is given by the sum of their individual momenta: (mass of ball * velocity of ball) + (mass of Olaf * velocity of Olaf).
Since the ball is traveling horizontally and Olaf is at rest initially, the momentum before the collision is simply the momentum of the ball.
After the collision, the ball bounces off Olaf's chest and moves in the opposite direction with a velocity of 7.40 m/s. At this point, Olaf acquires a velocity in the opposite direction as well.
To find Olaf's final velocity, we can use the law of conservation of momentum again. The total momentum after the collision is equal to the total momentum before the collision. Since the ball is the only object in motion after the collision, its momentum is equal to its mass multiplied by its final velocity.
Therefore, we have (mass of ball * final velocity of ball) = (mass of Olaf * final velocity of Olaf).
Using the given values, we can calculate Olaf's final velocity:
(0.400 kg * 7.40 m/s) = (71.8 kg * vf)
Simplifying the equation, we find vf = (0.400 kg * 7.40 m/s) / 71.8 kg = 0.0416 m/s.
Therefore, after the collision, Olaf's speed is 0.0416 m/s, which can be rounded to 2.65 m/s.
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1. Infer What phrase is repeated in the title and the questions in the
first stanza? What does this repetition indicate about the poem's
speaker?
1. The phrase "What if we were alone?" is repeated in the title and the questions in the first stanza. This repetition indicates that the poem's speaker is contemplating the idea of solitude and isolation. The speaker is questioning the impact of being alone and how it would affect the way they see themselves, the world, and their place in it.
2. In line 5, a dash appears at the end of the third question to create a pause and emphasize the speaker's uncertainty about what would happen in the scenario they are imagining. The dash gives the reader a chance to consider the implications of being alone, and it creates a sense of tension and anticipation as the speaker waits for an answer that may never come.
3. The poet suggests that both space and the earth itself are mysterious by emphasizing their vastness and the unknown possibilities they contain. The speaker wonders about what would happen if they were alone in space or on earth, highlighting the vastness of the universe and the endless possibilities that exist beyond our comprehension.
4. The human need for connection and the fear of being alone. The poem suggests that humans are social creatures who need to be part of a community and that the idea of being alone can be frightening and overwhelming. The speaker's questions reveal their fear of isolation and their desire for human connection.
5. In the first stanza, the "words of the wiser" are spoken by Galileo. In the final stanza, the "wise" words belong to the speaker themselves. The speaker's realization that they would still be themselves even if they were alone is a moment of insight that reveals the poem's underlying message about the importance of self-awareness and self-acceptance.
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complete question: “WHAT IF WE WERE ALONE?” Poem by William Stafford 1. Infer What phrase is repeated in the title and the questions in the first stanza? What does this repetition indicate about the poem’s speaker? 2. Interpret In line 5, why do you think a dash appears at the end of the third question? 3. Compare How does the poet suggest that both space and the earth itself are mysterious? 4. Draw Conclusions What do you think is the theme of “What If We Were Alone?” Why do you think so? 5. Notice & Note In the first stanza, you read some “words of the wiser” as spoken by Galileo. Whose “words” are described in the final stanza? What makes these “wise” words, too?
a movable bin and its contents have a combined weight of 2.1 kn determine the shortest chain sling acb that can be used to lift the loaded bin if the tension in the chain is not to exceed 5 kn. the shortest chain sling acb that can be used is m.
The shortest chain sling ACB for a movable bin is 1.228 m.
The question is not complete. A similar question is in the attachment. Use the image in a similar question for this problem. Look at the picture. In the system works
Tension in the chain T₁ and T₂The weight of a movable bin = wTriangle ABC is an isosceles triangle. If ∠ CAB = ∠ CBA = θ.
T₁ = T₂ ≤ 5 kNAccording to Newton's first law, in the y-axis
∑ F = 0
w - T₁y - T₂y = 0
T₁y + T₂y = 2,100
T₁ sin θ + T₂ sin θ = 2,100
5,000 sin θ + 5,000 sin θ = 2,100
10,000 sin θ = 2,100
sin θ = 2,100 ÷ 10,000
sin θ = 0.21
θ = sin⁻¹ (0.21)
θ = 12.12°
Look at AOC
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What is the relation between each of the following in the ocean [ direct or inversed]?1- Deepness and light intensity. [ direct or inversed ]2- Deepness and temperature. [ direct or inversed ]3- Deepness and water pressure. [ direct or inversed ]
Answer:
Deepness and water temp
If Charge A is positive, then Charge B must be:
A. not enough info
B. Negative
C. Positive
D. Neutral
Answer:
b
Explanation:
negativity sure ans bro
HELP PLEASE!!
You throw a rock with sufficient speed to put it into orbit around the asteroid 234 Ida very close to its surface. How long would it take the rock to make one orbit around the asteroid? Assume 234 Ida is spherical. Ida's mass is 4 x 1016 kg and its radius is 16 km.
A) 0.62 hr
B) 2.2 hr
C) 1.6 hr
D) 3.4 hr
Answer:
The correct option is;
B) 2.2 hr
Explanation:
The location of the rock in the orbit of the asteroid = Close to the surface of the asteroid
The required equation is given as follows;
\(\dfrac{G \times M \times m}{r^2} = \dfrac{m \times v^2}{r}\)
\(\therefore v^2 = \dfrac{G \times M}{r}\)
Where;
v = The orbital velocity
G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²
r = The radius of the planet = 16 km = 16,000 m
M = The mass of the planet = 4 × 10¹⁶ kg
∴ v² = 6.67430 × 10⁻¹¹ × 4 × 10¹⁶/16,000 = 166.8575
v = √(166.8575) = 12.92 m/s
The orbital velocity = v = 12.92 m/s
The time it takes for the rock to make one orbit round the asteroid is given as follows
The length of the orbit = The circumference of the asteroid = 2 × π × r
The length of the orbit = 2 × π × 16,000 ≈ 100530.965 m
The time it takes for the rock to make one orbit round the asteroid = The length of the orbit/(The speed of the asteroid)
The time it takes for the rock to make one orbit round the asteroid = 100530.965/(12.92) ≈ 7781.034 seconds or 2.2 hours (by approximation by one decimal place)
The time it takes for the rock to make one orbit round the asteroid ≈ 2.2 hours.