convert 3.9cm to hm​

Answer:

D. 144

Step-by-step explanation:

find the volume of the shipping container and divide it by the volume of a box.

\(2\frac{2}{3}\) × \(1\) × \(2\) = \(\frac{16}{3}\)

\(\frac{1}{3}\) × \(\frac{1}{3}\) × \(\frac{1}{3}\) = \(\frac{1}{27}\)

\(\frac{16}{3}\) divided by \(\frac{1}{27}\) is 144.

The null hypothesis is given as follows:

\(H_0: \mu = 175\)

The alternative hypothesis is given as follows:

\(H_1: \mu \neq 175\)

The claim in the context of this problem is given as follows:

"The mean weight of male aerobics instructors in a certain city is equal to 175 lbs".

At the null hypothesis, we test if there is not enough evidence to verify if the claim is false, that is:

\(H_0: \mu = 175\)

At the alternative hypothesis, we test if there is enough evidence to verify if the claim is false, that is:

\(H_1: \mu \neq 175\)

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Answer:

10 triangles can we find in this figure

Answer:

72

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

When multiplying exponents, you would add the degrees.

A, B, and D's degrees add up to \(5^{-2}\) , which is equal to 1/25.

C adds up to \(5^{2}\), which is 25, therefore making it C

Answer:

8 significant figures should be provided.

Step-by-step explanation:

I believe I am correct, but check your answer anyways.

Answer:

4.01

Step-by-step explanation:

The square root of 9 by long division method will give an answer of 3.

1: Group the digits of 9 into pairs from right to left. Since 9 is a single-digit number, we can consider it as a pair by itself.

2: Find the largest number whose square is less than or equal to the leftmost pair. In this case, the largest number whose square is less than or equal to 9 is 3.

3: Write 3 as the divisor on the left, and the quotient on the top right.

3 √ 9 |  0

4: Multiply the divisor (3) by the quotient (3), and write the result under the 9.

3 √ 9 |  0

      - 9

5: Subtract the result (9) from the leftmost pair (9), and write the difference (0) below the line.

3 √ 9 |  0

      - 9

       0

6: Bring down the next pair (0) to the right of the difference.

3 √ 9 |  0

      - 9

       0

     -----

7: Double the quotient (3) and write a blank space to the right.

3 √ 9 |  0

      - 9

       0

     -----

       0

      ?

8: Find a digit to fill in the blank space, such that when the new divisor (37) is multiplied by the digit, the result is less than or equal to the current dividend (0). In this case, the largest digit we can use is 0.

9: Write the digit (0) as the new quotient, and write the product of the new divisor (37) and the new quotient (0) below the line.

3 √ 9 |  0

      - 9

       0

     -----

       0

      0

10: Subtract the product (0) from the current dividend (0), and write the difference (0) below the line.

3 √ 9 |  0

      - 9

       0

     -----

       0

      0

      - 0

11: Since there are no more pairs to bring down, we have reached the end of the division. The square root of 9 is 3.

√9 = 3.

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Answer:

2z+(2j-3)z+(5-j)=0

2z +2jz-3z+5-j=0

2z-3z+2jz-j=-5

-z+2jz-j=-5

2jz-z-j=-5

I hope this help

Answer:

Your answer is correct

Step-by-step explanation:

This is because the rate of production is the programs divided by the days. There are 5 programs and he worked for 6 days, therefore your program is correct.

Answer:

THE ANSWER IS CORRECT

Step-by-step explanation:

BECAUSE HE DID 5 PROGRAMS FOR 6 DAY SO THAT WOULD BE 5 OVER 6

OR 5 DIVIDED BY 6   MARK AS BRAINLIEST PLZ

Answer:

Step-by-step explanation:

4 sides that will be a square.

The maximum distance that the sailοr can see frοm the deck οf the ship is 0 miles.

A special kind οf relatiοn knοwn as a functiοn is οne in which each input has precisely οne οutput. In οther wοrds, the functiοn generates exactly οne value fοr each input value. Because οne is mapped tο twο different values, the abοve graph depicts a relatiοnship rather than a functiοn. Hοwever, if οne were instead mapped tο a single value, the relatiοnship mentiοned abοve wοuld becοme a functiοn.

Additiοnally, οutput values can be equal tο input values. We knοw that the square rοοt functiοn is an increasing functiοn, which means that the value οf the functiοn increases as the input value increases.

Therefοre, tο find the maximum value οf the functiοn, we need tο find the maximum value οf h.

Assuming that the lighthοuse is οn the hοrizοn, which is apprοximately 3 miles away, we can use the Pythagοrean theοrem tο find the height οf the lighthοuse:

\(h^2 = (3)^2 - (15)^2h^2 = 9 - 225h^2 = -216\)

Since we cannοt take the square rοοt οf a negative number, there is nο real height fοr the lighthοuse that wοuld make it visible frοm a ship 15 feet abοve the water level.

Therefοre, the maximum distance that the sailοr can see frοm the deck οf the ship is 0 miles.

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Answer:

I think its C

Step-by-step explanation:

Let's use Thales theorem

Answer:

See below ~

Step-by-step explanation:

Let's get started!

Part (a) :

Statement 1 : ∠A = ∠E = 90° (indicated in diagram)

Statement 2 : ∠C = ∠C (common angle)

⇒ ΔABC ~ ΔBDC (AA similarity)

Part (b) :

Now that we have proved the triangles to be similar, we can take their corresponding sides in proportion.

⇒ \(\frac{EC}{AC} = \frac{ED}{AB}\)

⇒ \(\frac{160}{160+50} = \frac{120}{AB}\)

⇒ \(\frac{16}{21} = \frac{120}{AB}\)

⇒ \(AB = \frac{120\times21}{16}\)

⇒ \(AB = \frac{2520}{16}\)

⇒ AB = 157.5

Answer:

  104 inches

Step-by-step explanation:

No window dimensions are given. We might assume that the shape of the window can be defined by these coordinates:

   (18,64), (28,40), (18,16), (8,40)

A graph of the points reveals the window to be a rhombus, so we can figure the length of one side to determine the lengths of all sides.

On edge of the window will have a length determined by the distance formula:

  d = √((x2 -x1)^2 +(y2 -y1)^2)

For (x1, y1) and (x2, y2) as (8, 40) and (18, 64), the edge length is ...

  d = √((18 -8)^2 +(64 -40)^2) = √(10^2 +24^2) = √676

  d = 26 . . . . . the length of one of the four edges

The total length of the four window edges is ...

  4 × 26 = 104

104 inches of tape are needed.

Answer:

0.266 percent

Step-by-step explanation:

With labor increasing by 1 percent, we are to find how much level of production would also increase given the coubglas function in the question.

Level of production = ∆Q/Q

We differentiate the function Q with respect to Labour, L.

∆Q/∆L = 0.266Q/L

∆Q/Q = 0.266∆L/L

∆L/L = 1

∆Q/Q x 100 = 1 *0.266

= 0.266%

Please refer to the attachment

Answer:

Well you have to post on here first

Step-by-step explanation:

The total surface area of solid is,

S = 220 m²

And,  The volume of the prism is, 200 m³

We have to given that;

A solid prism is shown in figure.

Since, The surface area of a prism is,

S = (2 × Base Area) + (Base perimeter × height)

Where, "S" is the surface area of the prism.

Hence, We get;

base area = 5 x 10 = 50 m²

height = 4 m

Base Perimeter = 2 (5 + 10) = 30

Hence, We get;

S = (2 x 50) + (30 x 4)

S = 100 + 120

S = 220 m²

Since, A prism is a solid shape that is bound on all its sides by plane faces. The volume of a prism is expressed as;

V = base area × height.

Now, For given figure,

Volume of the prism = base area × height

base area = 5 x 10 = 50 m²

height = 4 m

Hence, Volume = 50 × 4 m³

= 200 m³

Thus, The volume of the prism is, 200 m³

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The five-number summary for this data set is 29, 32, 43.5, 50.5, and 53, and the interquartile range is 18.5.

Measures of statistical dispersion, or the spread of the data, include the interquartile range. In addition to the IQR, other names for it include the midspread, middle 50%, fourth spread, and H-spread.

To find the five-number summary and interquartile range for this data set, we first need to find the quartiles.

Step 1: Find the median (Q2)

When a data collection is sorted from least to largest, the median is the midway value. Since there are 12 values in this data set, the median is the average of the sixth and seventh values:

Median (Q2) = (41 + 46)/2 = 43.5

Step 2: Find the lower quartile (Q1)

The lower quartile is the median of the lower half of the data set. Since there are 6 values below the median, we take the median of those values:

Q1 = (32 + 32)/2 = 32

Step 3: Find the upper quartile (Q3)

The upper quartile is the median of the upper half of the data set. Since there are 6 values above the median, we take the median of those values:

Q3 = (50 + 51)/2 = 50.5

Now we have all the information we need to construct the five-number summary and interquartile range:

Minimum: 29

Lower quartile (Q1): 32

Median (Q2): 43.5

Upper quartile (Q3): 50.5

Maximum: 53

Interquartile range (IQR) = Q3 - Q1 = 50.5 - 32 = 18.5

the five-number summary for this data set is 29, 32, 43.5, 50.5, and 53, and the interquartile range is 18.5.

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Answer:

24

Step-by-step explanation:

Thanks to their discount, they get 10 dollars off. The result is 14.

(24 - 10 = 14)

Answer: The equation used to find the value of x is 5x - 4 = 3x + 10. The value of x is determined to be 7.

Step-by-step explanation:

Four less than the product of a number (x) and 5 = 5x - 4

8 more than 2 added to 3 times the number = 3x + 2 + 8 = 3x + 10

Four less than the product of a number (x) and 5 is equal to 8 more than 2 added to 3 times the number => 5x - 4 = 3x + 10

                                                         5x - 3x = 10 + 4

                                                         2x = 14

                                                         x = 14/2

                 therefore,                      x = 7

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After 4 half-lives, only 1/16th (or 0.0625) of the initial amount of the radioactive isotope will remain.

The amount of a radioactive isotope remaining after a certain number of half-lives can be calculated using the formula:

Amount remaining = Initial amount × (1/2)^(number of half-lives)

In this case, we are given the initial amount as "grams" and we want to find out the amount remaining after 4 half-lives.

So, the equation becomes:

Amount remaining = Initial amount × (1/2)^4

Since each half-life reduces the quantity to half, (1/2)^4 represents the fraction of the initial amount that will remain after 4 half-lives.

Simplifying the equation:

Amount remaining = Initial amount × (1/16)

Therefore, after 4 half-lives, only 1/16th (or 0.0625) of the initial amount of the radioactive isotope will remain.

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The missing statement in the proof specified is given by: Option B: ∠BCA≅∠DCB

What is the reflexive property of congruence?

According to the reflexive feature of congruence, the geometric quantity under consideration—be it an angle, a line segment, a form, etc.—is congruent to itself.

The third step's key concept in this instance is the "Reflexive Property of Congruence."

The fourth phase comes to the conclusion that the ΔABC~ΔBDC criteria for similarity are met.

Since it was established in the second stage that ∠ABC≅∠BDC

Therefore, in order for the fourth step to apply angle-angle similarity, which requires the angles of two considered triangles to be congruent, we must demonstrate another angle pair of triangles ΔABC and ΔBDC being congruent in the third step.

Internal angle C is the common angle in the triangles ABC and BDC.

As a result, it is consistent with itself due to its reflexive characteristic.

We obtain the following notation for internal angle C from triangle ABC:

Angle ACB and BCA(both will work)

Triangle BDC gives us the following notation for internal angle C:

Angle DCB and BCD(Both will function.)

They fit together. The second choice takes angle C into account, so:

∠BCA≅∠DCB (second option) is the missing statement.

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The total points scored by Eduardo in the first three games is 97.

We are given a table that shows the points scored by Eduardo during three games.

In game 1, he scored 52 points.

In game 2, he scored 19 points.

In game 3, he scored 26 points.

In game 4, he scored 10 points.

We need to find the sum of the total points scored by him in the first three games.

A summation, also known as a sum, is the outcome of adding numbers or quantities arithmetically. A summation always has an even number of terms.

The points are 52 + 19 + 26 = 97.

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The product and the quotient of the functions are as follows:

(rs)(4) =8

(r / s)(3) = 2

A function relates input and output. It relates an independent variable with a dependent variable.

Therefore, let's solve the function as follows:

r(x) = 2√x

s(x) = √x

Therefore, let's find

(rs)(4) = r(4) × s(4) = 2√4 × √4 = 4 × 2 = 8

Let's find

(r / s)(3) = r(3) / s(3) = 2√3 / √3 = 2

Therefore,

(rs)(4) =8

(r / s)(3) = 2

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Step-by-step explanation:

Using that fact that,

\( \cos(u) = \frac{x}{r} \)

and

\( {r}^{2} = {x}^{2} + {y}^{2} \)

We need to find sin which that formua is

\( \sin(u) = \frac{y}{r} \)

We know what r and x is so we need to find y.

\( {8}^{2} = { - 3}^{2} + {y}^{2} \)

\(64 = 9 + {y}^{2} \)

\(55 = {y}^{2} \)

\( \sqrt{55} = y\)

Sin is positve on the interval pi/2 to pi. so we get

\( \sin(u) = \frac{ \sqrt{55} }{8} \)

b.

\( \tan(u) = \frac{y}{x} \)

so

\( \tan(u) = - \frac{ \sqrt{55} }{3} \)

c.

\( \sec(u) = \frac{r}{ x} \)

\( \sec(u) = - \frac{8}{3} \)

d.

\( \sin(2u) = 2 \sin(u) \cos(u) \)

\(2 ( \frac{ \sqrt{55} }{8} )( - \frac{3}{8} ) = \frac{ - 6 \sqrt{55} }{64} = \frac{ - 3 \sqrt{55} }{32} \)

e.

\( \cos {}^{} (2u) = \cos {}^{2} (u) - \sin {}^{2} (u) \)

\(( \frac{ - 3}{8} ) {}^{2} - ( \frac{ \sqrt{55} }{8} ) {}^{2} = \frac{ - 46}{64} = - \frac{23}{32} \)

3.3333333e+22 is the answer.

Answer:

\(g(x)\) is the image of \(f(x)\) after stretched horizontally by scale factor = 4

Step-by-step explanation:

The statement that best compares the graph of \(g(x)\) with the graph of \(f(x)\) says \(g(x)\) is the image of \(f(x)\) after stretched horizontally by scale factor = 4 because:

Given the function

\(f(x) = x^2\) and \(g(x) = (\frac{1}{4} x)^2\) the image of \(f(x)\) after one transformation.  

The transformation shows that \(g(x)\) stretches away from y-axis.  

Since the transformation is stretched horizontally. So \(g(x)\) is the image of \(f(x)\) after stretched horizontally by scale factor (I.e. by 1).

Then we use the scale factor to divide \(g(x)\)

\(1 \div \dfrac{1}{4} = 1 \times \dfrac{4}{1} = 4\)

So therefore, \(g(x)\) is the image of \(f(x)\) after stretched horizontally by scale factor = 4