Convert 1500W to horse power.0.497hp2.02hp754hp2250hp

The distance traveled by the object during the time interval from t = 2 s to t = 3s is 3m. Option C.

From the formula d = ½ at2 the displacement is proportional to the square of time. If you run twice as far from the rest, the displacement will quadruple (or 4m). Since the object has already moved 1 m in the first second, the remaining 3 m have moved in time intervals from 1 to 2 seconds.

This means that the velocity and net force in the direction normal to the plane must be zero. Assuming the plane is frictionless means that the plane exerts no force on the block parallel to the surface. For angular frictionless tilt, the acceleration is the result of the gravitational acceleration multiplied by the sine of the angle.

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The work required to move a 1 nC charge from an electric potential of 0 V to a potential of 18 V is 18 nJ (Option f).

When moving a charge in an electric field, the work done can be calculated using the formula W = qΔV, where W is the work done, q is the charge, and ΔV is the change in electric potential.

In this case, the charge is\(0.36V * 1600 kg/m^3 = 0.36 * 0.088 m^3 * 1600 kg/m^3 = 88 kg.\)) and the change in potential is 18 V. Plugging these values into the formula, we get\(W = (1 × 10^-9 C)(18 V) = 18 × 10^-9 J = 18 nJ.\)

Therefore, the correct answer is option f. No other options accurately represent the work required to move the charge in this scenario.

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Answer:m 1= 36 g=0.036 kg - the mass of ice T1= −77 ◦C. - temperature of ice m2=589 g=0.589 kg - mass of water C1=2090 J/kg · ◦C - specific heat of ice  λ = 3.33 × 10^5 J/kg - latent heat of fusion of water T2=26◦C. - temperature of water C2= 4186 J/kg · ◦C . - - specific heat of water m3=74 g=0.074kg - mass of copper T3=26◦C. - temperature of copper C3=387 J/kg ·◦C - specific heat of copper is and of ice is T - ? - final temperature  1  1 ( 0 −  1 ) −  ℎ  0  1  −  1  2 (  − 0 ) −  ℎ   2  2 (  −  2 ) −   3  3 (  −  3 ) −  m 1 ​ C 1 ​ (0−T 1 ​ )−ice heating to 0 o C m1λ−ice melting m 1 ​ C 2 ​ (T−0)−melted water heating m 2 ​ C 2 ​ (T−T 2 ​ )−water cooling m 3 ​ C 3 ​ (T−T 3 ​ )−copper cooling  1  1 ( 0 −  1 ) +  1  +  1  2 (  − 0 ) +  2  2 (  −  2 ) +  3  3 (  −  3 ) = 0 m 1 ​ C 1 ​ (0−T 1 ​ )+m1λ+m 1 ​ C 2 ​ (T−0)+m 2 ​ C 2 ​ (T−T 2 ​ )+m 3 ​ C 3 ​ (T−T 3 ​ )=0 0.036 ⋅ 2090 ⋅ 77 + 0.036 ⋅ 3.33 ⋅ 1 0 5 + 0.036 ⋅ 4186 ⋅  + 0.589 ⋅ 2090 ⋅ (  − 26 ) + 0.074 ⋅ 387 ⋅ (  − 26 ) = 0 0.036⋅2090⋅77+0.036⋅3.33⋅10 5 +0.036⋅4186⋅T+0.589⋅2090⋅(T−26)+0.074⋅387⋅(T−26)=0 1410.344 ⋅ = 14969.368  = 10.6 1  1410.344⋅T=14969.368 T=10.61 o C Answer:  = 10.6 1  T=10.61 o C

Explanation:

When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times. The density of the air filled in the polythene container is approximately 1.25 kg/m³.

The density of air filled in the polythene container can be determined by considering the change in mass and volume of the container before and after filling it with air. Given that the mass of the empty container is 0.419 kg and the mass of the container when filled with extra air is 0.428 kg, and the volume of the perplex box is 1000 cm³.

Calculate the mass of the air inside the container by subtracting the mass of the empty container from the mass of the container when filled with air:

Mass of air = Mass of filled container - Mass of empty container

= 0.428 kg - 0.419 kg

= 0.009 kg

Calculate the volume of the air inside the container using the given number of times the air inside is 7.2:

Volume of air = Volume of perplex box * Number of times air inside

= 1000 cm³ * 7.2

= 7200 cm³

Convert the volume of air to cubic meters (m³) by dividing by 1000000:

Volume of air = 7200 cm³ / 1000000

= 0.0072 m³

Calculate the density of air using the formula:

Density = Mass / Volume

Density = 0.009 kg / 0.0072 m³

≈ 1.25 kg/m³

Therefore, the density of the air filled in the polythene container is approximately 1.25 kg/m³.

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The amount the needle on the meter is deflected A. increases

This phenomenon can be explained by Faraday's law of electromagnetic induction. According to this law, when a magnetic field (created by the bar magnet) passes through a coil of wire, it induces an electric current in the wire. This induced current generates its own magnetic field, which interacts with the magnetic field of the bar magnet.

The deflection of the meter needle is a result of this induced current. When the number of coils of wire is increased, there is a greater number of wire loops for the magnetic field to pass through. This leads to a stronger induction of electric current, resulting in a larger deflection of the meter needle.

By increasing the number of coils, more magnetic flux is linked with the wire, resulting in a higher induced electromotive force (emf) and a greater current. This increased current produces a stronger magnetic field around the wire, leading to a larger deflection on the meter. Therefore, increasing the number of coils of wire enhances the magnetic field interaction, resulting in an increased deflection of the meter needle. Therefore, Option A is correct.

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The ranking is based on the tilt of the Earth's axis and its orbit around the Sun. The figure at 40°N in June receives the most daylight because it is located at a high latitude during the summer solstice in the Northern Hemisphere. The Earth's axis tilts towards the Sun, resulting in longer days and shorter nights. The figure at 40°S in December receives a moderate amount of daylight as it is located at a lower latitude during the summer solstice in the Southern Hemisphere.

The figure at 40°N in December experiences less daylight because it is located at a high latitude during the winter solstice in the Northern Hemisphere, with shorter days and longer nights. Lastly, the figure at 40°S in June receives the least amount of daylight as it is located at a lower latitude during the winter solstice in the Southern Hemisphere, where the days are shortest and the nights are longest. Based on the information given, the ranking of figures based on the amount of daylight they experience in a 24-hour period, from most to least.

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The mass of the ball is approximately 10.24 kg, found using the conservation of energy principle.

What is the mass of a ball thrown upward with a speed of 10 m/s from a height of 20 m, using the conservation of energy principle?

To find the answer, we can use the conservation of energy principle, which states that the total energy of a system remains constant if there is no net work done on the system.

Initially, the ball has some potential energy due to its height above the ground and kinetic energy due to its motion. As it travels upwards, its potential energy increases while its kinetic energy decreases until it reaches its highest point, at which its kinetic energy is zero and its potential energy is at its maximum. Then, as it falls back down, its potential energy decreases while its kinetic energy increases until it reaches the ground, at which its potential energy is zero and its kinetic energy is at its maximum.

Let's use the following variables:

m = mass of the ball

v_i = initial velocity of the ball (10 m/s)

v_f = final velocity of the ball (0 m/s at the highest point)

h = height of the ball above the ground (20 m)

g =  (9.81 m/s^2)

The total energy of the ball initially is:

E_i = 1/2 * m * v_i^2 + m * g * h

At the highest point, the total energy of the ball is:

E_f = 1/2 * m * v_f^2 + m * g * 2h

Since the ball is at rest at the highest point, its final velocity is zero, so:

E_f = m * g * 2h

By the conservation of energy principle, the total energy of the ball is constant, so:

E_i = E_f

Substituting the expressions for E_i and E_f and solving for the mass of the ball:

1/2 * m * v_i^2 + m * g * h = m * g * 2h

1/2 * v_i^2 + g * h = 2g * h

m = (1/2 * v_i^2 + g * h) / g

m = (1/2 * 10^2 + 9.81 * 20) / 9.81

m = 10.24 kg

Therefore, the mass of the ball is approximately 10.24 kg.

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This is projectile motion. We know that in this kind of motion the maximum height is given by:

and that, when the motion is complete (this means that the object stops at the same height it begins, like in this case) the total time of flight is given by:

In both of this equations the angle theta represents the angle of launch.

Now, in this case the student fires the cannonball upwards, this means that the angle of launch is 90°; since:

Then, for this problem, the equations above reduced to:

and

Now that we know this we can plug the initial velocity of each case in the equations above to determine the maximum height and time of flight. For example, if the initial velocity is 13 m/s then we have that:

With this procedure we have that the table would be:

a) The angle θ1 which the righthand cable makes with respect to the ceiling is  sin^(-1)(692 N / 530 N).

b) The angle θ2 which the left-hand cable makes with respect to the ceiling is  sin^(-1)(692 N / 570 N).

We may utilise the tension of the right-hand cable as well as its vertical and horizontal components to determine the angle 1. θ2 = sin^(-1)(692 N / 570 N).

We may apply the ideas of trigonometry and vector addition to address this issue.

a) The tension of the right-hand wire as well as its vertical and horizontal components can be used to determine the angle 1.

T1sin(1) calculates the vertical component of the right-hand cable's tension, which is equal to the object's weight (692 N).

T1sin(θ1) = 692 N

We may rearrange the equation to find 1:

θ1 = sin^(-1)(692 N / T1)

We can find 1 by substituting the given tension value, T1 = 530 N:

θ1 = sin^(-1)(692 N / 530 N)

b) Similarly, we can use the formula to determine the angle 2 the left-hand cable's tension and its vertical and horizontal components.

The vertical component of the left-hand cable's tension is given by T2sin(θ2), and it should also be equal to the weight of the object (692 N).

T2sin(θ2) = 692 N

To find θ2, we can rearrange the equation:

θ2 = sin^(-1)(692 N / T2)

Substituting the given tension value T2 = 570 N, we can solve for θ2:

θ2 = sin^(-1)(692 N / 570 N)

Calculating these angles using the given tension values will provide the answers in degrees.

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Answer:

Explanation:

To find the mass of an object given it's acceleration and the force acting on it we use the formula

\(mass = \frac{force}{acceleration} \\ \)

From the question

force = 500 N

acceleration = 5.0 m/s²

We have

\(mass = \frac{500}{5} \\ \)

We have the final answer as

Hope this helps you

Answer:

6 kg

Explanation:

F=ma

F is Force(newtons)

m is mass(kg)

a is acceleration(m/s^2)

Plug in the numbers

3000 = m(500)

divide both sides by 500 to cancel out the 500.

3000/500=6

6 = m

6kg is the mass

The answer is that the time the diver was in the air is 1.13 seconds.

To determine the time the diver was in the air, we can use the kinematic equation:

Δy = viΔt + 1/2at²,

where Δy is the displacement, vi is the initial velocity, a is the acceleration due to gravity (g), and t is the time.The initial velocity, vi, is given as 5.5 m/s, and since the diver jumps upwards, the displacement, Δy, is equal to the height of the board, which is 3.0 m. The acceleration due to gravity, a, is -9.8 m/s² (negative because it acts downwards).Substituting the known values into the equation:3.0

m = (5.5 m/s)t + 1/2(-9.8 m/s²)t²

Simplifying, we get:

4.9t² + 5.5t - 3.0 = 0

We can solve for t using the quadratic formula:

t = (-5.5 ± √(5.5² - 4(4.9)(-3.0))) / (2(4.9))= (-5.5 ± 1.59) / 9.8= -0.47 s or 1.13 s

Since time cannot be negative, the time the diver was in the air is 1.13 seconds.

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On the rollercoaster:

To solve this problem, apply the principles of conservation of energy. Use the following equations:

a) The Total Mechanical Energy (TME) at any point can be calculated using the formula: TME = Potential Energy + Kinetic Energy.

b) The velocity of the coaster can be calculated using the equation: Kinetic Energy = (1/2)mv², where m = mass of the rollercoaster.

c) The velocity of the coaster at point B can be calculated using the conservation of energy principle. So, equate the Potential Energy + Kinetic Energy at point A to the Potential Energy + Kinetic Energy at point B and solve for velocity at point B.

d) Calculate the height of point A using the formula: Potential Energy = mgh, where m is the mass of the rollercoaster, g is the acceleration due to gravity, and h is the height.

Given:

Mass of rollercoaster (m) = 1000 kg

Braking force (F) = 8780 N

Let's calculate each part of the problem:

a) The Total Mechanical Energy at Point A:

TME = Potential Energy + Kinetic Energy

Since the rollercoaster is at the highest point (A) and it's not moving, the Kinetic Energy is zero.

Potential Energy = mgh

Potential Energy at Point A = (1000 kg)(9.8 m/s²)(h) = TME

TME = 591,100 J

b) The velocity of the coaster at Point A:

Using the Total Mechanical Energy calculated in part a, calculate the velocity using the formula:

TME = (1/2)mv²

591,100 J = (1/2)(1000 kg)(v²)

v² = (2 × 591,100 J) / (1000 kg)

v² = 1182.2 m²/s²

v = √(1182.2) ≈ 34.4 m/s

c) The velocity of the coaster at Point B:

Using the conservation of energy principle, equate the TME at Point A to the TME at Point B:

Potential Energy at Point A + Kinetic Energy at Point A = Potential Energy at Point B + Kinetic Energy at Point B

mgh + (1/2)mv² = mgh' + (1/2)mv'²

Since the coaster starts from rest at Point A, the Kinetic Energy is zero.

mgh = mgh' + 0

gh = gh'

34.4 m/s = √(2 × 9.8 m/s² × h')

h' = (34.4 m/s)² / (2 × 9.8 m/s²) ≈ 60.3 m

d) The highest hill the coaster could have gotten over before Point A with no additional mechanical energy is the height at Point A, is calculated to be approximately 60.3 meters.

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If the disk is released from rest, Angular velocity (ω) of the disk is  \(245\frac{rad}{s}\)

In physics, the angular velocity or rotational velocity (ω or Ω) is also known as the angular frequency vector, is the rate at which an object's angular position or orientation changes over time (i.e., the object's rotation speed is a pseudo-vector representation. or spin relative to a point or axis).

The magnitude of the pseudovector represents the angular velocity, i.e. the speed at which the object rotates or rotates, and its direction is perpendicular to the current plane of rotation or angular displacement. Angular velocity direction is conventionally given by the right-hand rule.

Calculation :

Given : M = 2kg, t = 3s, r = 80mm

solution :

\(0 + Mgrt = \frac{3}{2} Mr^{2}\)ω

ω = \(\frac{2}{3} (\frac{g}{r} ) t\)

ω =         \(245\frac{rad}{s}\)

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Given

distance of the object  u = -40 cm.

radius of curvature of the refracting surface  R = -20 cm.

The height of the object  h = 1 cm.

To Find

The size of the image

Solution

We will now write the following data using the sign convention:

The object's distance is u = -40 cm.

The refracting surface has a radius of curvature of R = -20 cm.

The object's height is h = 1 cm.

We know that the lens maker formula is: n2vn1u=n2n1R.

v denotes the image formation distance.

The refractive index of the second medium is n2=1.33, and the refractive index of the first medium is n1=1.

In the preceding equation, we will now substitute the known values.

1.33v−1−40cm=1.33−1−20cmv=32.05cm

We know that the magnification ratio can be expressed as vu=Hh.

H denotes the height of the created image.

We'll now swap the given and obtained values.

⇒32.05cm divide by 40cm=H divide by 1cm

⇒H=0.6cm

As a result, the best choice is (B).

Further information: The rules of reflection apply to reflection from a concave mirror. The normal to the point of incidence is drawn along the radius of the mirror, that is, by connecting the point of incidence to the centre of curvature.

The development of an image in a concave mirror is mostly determined by the distance between the object and the mirror. The concave mirror produces both real and virtual images.  A virtual and magnified picture is generated when the object is placed very close to the mirror.

The complete question is -

Find the size of the image formed in the situation shown in figure.

photo

A) 0.5 cm

B) 0.6 cm

C) 1.2 cm

D) 1 cm

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Answer:

Explanation:

Loss of lives and property: Immediate impacts of flooding include loss of human life, damage to property, destruction of crops, loss of livestock, non-functioning of infrastructure facilities and deterioration of health condition owing to waterborne diseases. Flash floods, with little or no warning time, cause more deaths than slow-rising riverine floods.

Loss of livelihoods: As communication links and infrastructure such as power plants, roads and bridges are damaged and disrupted, economic activities come to a standstill, resulting in dislocation and the dysfunction of normal life for a period much beyond the duration of the flooding. Similarly, the direct effect on production assets, be it in agriculture or industry, can inhibit regularly activity and lead to loss of livelihoods. The spill over effects of the loss of livelihoods can be felt in business and commercial activities even in adjacent non-flooded areas.

Decreased purchasing and production power: Damage to infrastructure also causes long-term impacts, such as disruptions to clean water and electricity, transport, communication, education and health care. Loss of livelihoods, reduction in purchasing power and loss of land value in the flood plains lead to increased vulnerabilities of ties living in the area. The additional cost of rehabilitation, relocation of people and removal of property from flood-affected areas can divert the capital required for maintaining production.

Mass migration: Frequent flooding, resulting in loss of livelihoods, production and other prolonged economic impacts and types of suffering can trigger mass migration or population displacement. Migration to developed urban areas contributes to the overcrowding in the cities. These migrants swell the ranks of the urban poor and end up living in marginal lands in cities that are prone to floods or other risks. Selective out-migration of the workforce sometimes creates complex social problems.

Psychosocial effects: The huge psycho-social effects on flood victims and their families can traumatize them for long periods of time. The loss of loved ones can generate deep impacts, especially on children. Displacement from one’s home, loss of property and livelihoods and disruption to business and social affairs can cause continuing stress. The stress of overcoming these losses can be overwhelming and produce lasting psychological impacts.

Hindering economic growth and development: The high cost of relief and recovery may adversely impact investment in infrastructure and other development activities in the area and in certain cases may cripple the frail economy of the region. Recurrent flooding in a region may discourage long-term investments by the government and private sector alike. Lack of livelihoods, combined with migration of skilled labour and inflation may have a negative impact on a region’s economic growth. Loss of resources can lead to high costs of goods and services, delaying its development programmes.

Political implications: Ineffective response to relief operations during major flood events may lead to public discontent or loss of trust in the authorities or the state and national governments. Lack of development in flood-prone areas may cause social inequity and even social unrest posing threat to peace and stability in the region.

The correct answer is option D. That is, the branch of Physics that study the particles movement at any speed, including very high speeds is Relativity

Kinematic is a branch of Physics that deal with a study of particle's motion without considering the cause of the motion. While dynamics deals with the motion of a particle as well as the causes of the motion.

The branch of Physics that study the particles movement at any speed,

including very high speeds is Relativity.

We have relativity of mass, relativity of time and relativity of length. All deal with the speed of light which is the fastest speed on earth as of now.

Therefore, the correct answer is option D. That is, the branch of Physics that study the particles movement at any speed, including very high speeds is Relativity.

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Answer:

Distance = 6 m

Time = 5.2 sec

speed = x

formula to find speed is distance upon time

Now,

speed = 6/5.2

speed = 1.15

Answer:

flat lol, that's the answer

Answer:

W = 12 J

Explanation:

Given that,

Force, F = 4 N

The object moves in rightward direction for a distance of 3 m.

Work done on the object is given by :

\(W=F\times d\\\\=4\ N\times 3\ m\\\\=12\ J\)

So, the work done on the object is 12 J.

(a) The first block  moves at 4.0 m/s in the same direction right after colliding.

(b) the system's total kinetic energy changes by  28.75 J

(c) the system's total kinetic energy changes by -1.25 J

Given;

First block's mass, m1, is 5 kg.

u1 = 3.0 m/s is the first block's starting speed.

m2 weight of the second block is 10.0 kg.

u2 = 2.0 m/s is the second block's initial speed.

v2 = 2.5 m/s is the second block's final speed.

Immediately following the impact, the first block block's Part (A) velocity is as follows:

Apply the law of conservation of linear momentum: m1u1 + m2u2 = m1v1 + m2v2, where v1 is the speed of the first block after it collides.

(5 x 3.0) + (10 x 2.0) = 5.0v₁ + (10 x 2.5) (10 x 2.5)

35= 2.5v₁ + 25

2.5v₁ = 35-25

2.5v₁ = 10

v₁ = 10/2.5

v₁ = 4

2.5 m/s in the same direction for v1.

Change in the system's overall kinetic energy, part (B):

Final kinetic energy minus beginning kinetic energy equals the change in kinetic energy.

ΔK = (1/2m1v1^2 + 1/2m2v2^2) - (1/2m1u1^2 + 1/2m2u2^2)

ΔK is equal to (1/2 x 5 x 4^2 + 1/2 x 10 x 2.5^2) – (1/2 x 5 x 3^2 + 1/2 x 10 x 2^2).

ΔK = 71.25 J - 42.5 J

ΔK = 28.75 J

Change in part (C) of the system's total kinetic energy if the second block accelerates to 5.2 m/s

Determine the final speed of the first block using the conservation of linear momentum: m1u1 + m2u2 = m1v1 + m2v2 (5 x 3.0) + (10 x 2.0) = 5v1 + (10 x 4)

35 = 2.5v₁ + 40

2.5v₁ = -5

2.5v₁ = - 5 v₁ = - 5 / 2.5 \s v₁ = -2 m/s

Final kinetic energy minus beginning kinetic energy equals the change in kinetic energy.

K = (1/2m1v12 + 1/2m2v22) - (1/2m1u12 + 1/2m2u22)

K is equal to (1/2 x 5 x 22 + 1/2 x 10 x 2.52) - (1/2 x 5 x 3 + 1/2 x 10 x 2).

ΔK = 41.25 - 42.5 J

ΔK = -1.25 J

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Answer:

C. Displacement

Explanation:

If a satellite is to orbit at a constant distance from Earth at a circular radius of 8,300,000, the required velocity of the satellite is 8239m/s.

What is a satellite?

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Answer:

The main force is wind or air

Explanation:

Answer:

The horse father from the center has a greater tangential speed. Although both horses complete one circle in the same time period, the one farther from the center covers a greater distance during that same period.

Explanation:

In the Roman soldier model for refraction, the first soldier who hits the muddy stream would slow down and turn slightly. Option B is correct.

The Roman soldier model is a simplified model used to explain the behavior of light when it passes from one medium to another. In this model, a group of Roman soldiers is marching across a field towards a muddy stream. The soldiers represent light rays, and the muddy stream represents the boundary between two media with different refractive indices.

When the first soldier hits the muddy stream, they slow down because the speed of light decreases when it passes from a medium with a lower refractive index to a medium with a higher refractive index. Additionally, the soldier turns slightly because the direction of the light ray changes as it passes through the boundary between the two media. This change in direction is called refraction, and it occurs because the speed of light changes when it passes through a medium with a different refractive index.

The amount of refraction that occurs depends on the angle at which the light ray hits the boundary between the two media and the difference in refractive indices between the two media. The Roman soldier model is a useful tool for understanding the basics of refraction, but it has limitations and cannot fully explain all aspects of the phenomenon. Option B is correct.

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The change in position of an object over time is known as velocity. The thing in question is traveling correctly. Vector c has the largest magnitude of all the vectors. And as demonstrated, a half-arrow can be used to represent this vector.

Everything that is readily apparent or palpable and has a stable form. An object of study in medicine is anything, anyone, or anything to which action or thinking is focused.

A person or thing that the verb directs its action toward is called an object. A noun, pronoun, or noun phrase that is impacted by the action verb is referred to as an object. A sentence is also finished by it.

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The average speed of a car that travels 140 km for 2 hours then travels 235 km west for 3 hours is 75km/hr.

Average speed is the rate of motion or action, specifically the magnitude of the velocity; the rate distance is traversed in a given time.

The average speed of a moving object can be calculated by dividing the distance moved by the time taken to move the distance.

According to this question, a car travels 140 km for 2 hours then travels 235 km west for 3 hours.

Average speed = 375km ÷ 5hr = 75km/hr

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The length of one of the cube's sides is 3.97 mm.

The area of the cube is calculated by applying the following formula as shown below.

Young's modulus is equal to ratio of shear stress to shear strain.

E = Shear stress / Shear strain

Shear stress = F / A

where;

Shear strain = e / L

Shear strain =  tanθ

E = Shear stress / ( tanθ )

E = ( F/Atanθ )  

A = ( F / Etanθ )

Young's modulus of brass = 1 x 10¹¹ Pa

A = ( 1650 / 1 x 10¹¹  x   tan(0.06)

A = 1.576 x 10⁻⁵ m²

The length of a side of the cube is calculated as follows;

L² = A

L = √ A

L = √ (1.576 x 10⁻⁵ )

L = 3.97 x 10⁻³ m

L = 3.97 mm

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