Answer:
Seconds...
Explanation:
What is the transfer of energy from a wave to the medium through which travels
Answer:
'Wave' is a common term for a number of different ways in which energy is transferred: In electromagnetic waves, energy is transferred through vibrations of electric and magnetic fields. In sound waves, energy is transferred through vibration of air particles or particles of a solid through which the sound travels.
which planet has a moon named after a continent on earth
Answer: Jupiter II
Explanation: Jupiter II, is the smallest of the four Galilean moons orbiting Jupiter, and the sixth-closest to the planet of all the 92 known moons of Jupiter.
The planet that has a moon named after a continent on Earth is Saturn.
Saturn's moon is named "Titan," and it is the largest moon of Saturn and the second-largest moon in the entire solar system. The name "Titan" was chosen to reflect its significance and size.
The name "Titan" is derived from Greek mythology. In Greek mythology, the Titans were a race of powerful gods who ruled during the Golden Age.
They were considered to be the ancestors of many important gods and goddesses. The name "Titan" signifies strength, power, and importance.
While Titan is not directly named after a specific continent on Earth, it is worth noting that Titan is named after the Titans of Greek mythology, which is a cultural reference and not specifically related to a geographic location on Earth.
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Stephen learned that any two objects exert a gravitational force on each other. If the distance between two objects triples, the gravitational force between them will change by a factor of what?.
The gravitational force between them will change by a factor 1/9.
We need to know about gravitational force to solve this problem. The gravitational force is the force caused by two masses objects. The magnitude of gravitational force can be determined as
F = G.m1.m2 / R²
where F is the gravitational force, G is the gravitational constant (6.674 × 10¯¹¹ Nm²/kg²), m1 and m2 are the mass of the object and R is the radius.
From the question above, we know that
R2 = 3R1
By substituting the following parameters, we get
F2/F1 = G.m1.m2 / R2² / G.m1.m2 / R1²
F2/F1 = G.m1.m2 / (3R1)² / G.m1.m2 / R1²
F2/F1 = 1/9
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Why do mass numbers have a trailing decimal? use the following words describe for credit isotopes protons neutrons electrons in carbon 13
HELP ME
Answer:a number without a decimal are generally not significant. Isotopes are atoms of same element which have the same atomic number but different number of neutrons. Isotopes of elements are represented in the following way: In an atom, the number of protons is equal to its atomic number.. An atom of an element is neutral in nature so atom contains the same number of protons and electrons.
Explanation:
what gauge pressure is required in the city water mains for a stream from a fire hose connected to the mains to reach a vertical height of 17.0 m ? (assume that the mains have a much larger diameter than the fire hose.)
The required gauge pressure in the city water mains for the fire hose stream to reach a vertical height of 17.0 m is approximately 166,600 Pa (or 166.6 kPa).
To determine the required gauge pressure in the city water mains for a stream from a fire hose to reach a vertical height of 17.0 m, we can use the equation:
pressure = density × gravity × height
Given that the height (h) is 17.0 m and assuming the density of water (ρ) is approximately 1000 kg/m³ and the acceleration due to gravity (g) is approximately 9.8 m/s², we can substitute these values into the equation:
pressure = 1000 kg/m³ × 9.8 m/s² ×17.0 m
Simplifying the calculation:
pressure ≈ 166,600 Pa (or N/m²)
Therefore, the required gauge pressure in the city water mains for the fire hose stream to reach a vertical height of 17.0 m is approximately 166,600 Pa (or 166.6 kPa).
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Physics
1. Compute the resistance of a hardened copper rod 2 meters long and 8 mm
The resistance of the hardened copper rod is approximately 0.677 ohms.
To compute the resistance of a hardened copper rod, we need to use the formula for resistance:
Resistance (R) = Resistivity (ρ) x Length (L) / Cross-sectional Area (A)
Convert length to meters:
The length of the rod is given as 2 meters, so no conversion is required.
Convert diameter to meters and calculate the cross-sectional area:
The diameter of the rod is given as 8 mm. To calculate the cross-sectional area, we need to convert the diameter to meters.
Diameter (d) = 8 mm = 8 x 10^(-3) meters (1 mm = 10^(-3) meters)
To calculate the cross-sectional area, we use the formula:
Area (A) = π x (diameter/2)^2
Plugging in the values:
A = π x (8 x 10^(-3) / 2)^2 = π x (4 x 10^(-3))^2 = π x 16 x 10^(-6) = 50.27 x 10^(-6) m^2
Determine the resistivity of copper:
The resistivity (ρ) of copper is a material property and is typically given in ohm-meters (Ωm). The resistivity of copper is approximately 1.7 x 10^(-8) Ωm.
Calculate the resistance:
Using the formula for resistance, we can substitute the values:
R = (1.7 x 10^(-8) Ωm) x (2 m) / (50.27 x 10^(-6) m^2)
Simplifying the expression:
R = 0.677 Ω
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If you are driving a vehicle at night, dim your lights by switching to low-beams before you are ____ ft from a vehicle coming toward you. A. 500 B. 200 C. 300
If you are driving a vehicle at night, dim your lights by switching to low-beams before you are 500 ft from a vehicle coming toward you.
Dimming your lights when a vehicle is approaching is important to prevent blinding the other driver and ensuring both drivers have clear visibility. When driving at night, it is recommended to switch to low-beams when you are approximately 500 ft away from an oncoming vehicle. This allows the oncoming driver to see the road clearly without being dazzled by your high-beam lights.
It is important to practice proper lighting etiquette to promote safe driving conditions for everyone on the road. Dimming your lights in a timely manner helps to avoid accidents and maintain a courteous and considerate approach towards fellow drivers. If you are driving a vehicle at night, dim your lights by switching to low-beams before you are 500 ft from a vehicle coming toward you.
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Can someone please help me, thanks.
If the surface of a moon is impacted by meteorites at a constant rate, the density, or quantity per unit of area, of impact craters on the moon’s surface will increase over time. How can this information be used to determine the relative age of a moon’s surface?.
The number of impact craters on a moon's surface can be used to determine the relative age of that surface. This is because the rate at which impact craters are formed is roughly constant over time. Therefore, the more impact craters a surface has, the older it is.
To determine the relative age of a moon's surface, scientists can compare the number of impact craters on that surface to the number of impact craters on other surfaces of known age. For example, the Moon's surface is covered in impact craters, and the oldest parts of the Moon's surface have the most impact craters. The youngest parts of the Moon's surface have the fewest impact craters.
Scientists can also use the size of impact craters to determine the relative age of a moon's surface. Larger impact craters are formed by more energetic impacts, and these impacts are less frequent than smaller impacts. Therefore, older surfaces are more likely to have larger impact craters.
The relative age of a moon's surface can also be determined by studying the composition of the surface material. Older surfaces are more likely to be covered in material that has been modified by the impacts of meteorites. This material is often more heavily cratered and has a different composition than the material on younger surfaces.
By combining all of these methods, scientists can get a good estimate of the relative age of a moon's surface. This information can be used to study the history of the moon and to understand the processes that have shaped its surface.
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describe the behavior of magnets
The maximum magnetic field strength of an electromagnetic field is 5×10^−6 T . Calculate the maximum electric field strength if the wave is traveling in a medium in which the speed of the wave is 0.75c.
The maximum electric field strength if the wave is traveling in a medium in which the speed of the wave is 0.75c is 4 × 10^2 V/m.
The electric field strength can be calculated using the formula E = cB, where c is the speed of light and B is the magnetic field strength. Substituting the values, we get E = (3 × 10^8 m/s) × (5 × 10^−6 T) = 1.5 × 10^2 V/m.
However, since the wave is traveling in a medium in which the speed of the wave is 0.75c, the electric field strength will be different. The speed of the wave in the medium affects the relationship between the electric and magnetic fields. When the speed of the wave decreases, the electric field strength increases and vice versa.
To calculate the electric field strength when the speed of the wave is 0.75c, we need to use the formula E = (c/v)B, where v is the speed of the wave in the medium. Substituting the values, we get E = (3 × 10^8 m/s / 0.75c) × (5 × 10^−6 T) = 4 × 10^2 V/m.
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What is the Kinetic Energy of a 5kg object traveling at 10 m/s?
Answer:
KE = 250 kg/m/s
Explanation:
use the formula: KE = 1/2 m (v^2)
KE = 1/2 (5) (10^2)
KE = (2.5) (100)
KE = 250 kg/m/s
rocket is moving at a speed of 200 m s-1 towards a stationary target. While moving it emits a wave of frequency 1000 Hz. Some of the sound reaching the target gets reflected as an echo. Calculate:
(i) the frequency of the sound as detected by the target and (ii) the frequency of the echo as detected by the target.
(i) The frequency detected by the target 2267 Hz
(ii) The frequency of the echo will also be 2267 Hz.
What is the frequency of the sound as detected by the target?
The frequency detected by the target will be different from the frequency emitted by the rocket because of the Doppler effect.
(i) To calculate the frequency detected by the target, we can use the formula:
f' = f(v + u) / (v - us)
where;
f is the frequency emitted by the rocket, f' is the frequency detected by the target, v is the speed of sound in air, u is the speed of the rocket, and s is the distance between the rocket and the target.In this case, f = 1000 Hz, v = 343 m/s (at room temperature and atmospheric pressure), u = 200 m/s, and s = 0 (since the rocket is emitting the sound directly towards the target).
Plugging in the values, we get:
f' = 1000 * (343 + 200) / (343 - 200*0) = 2267 Hz
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Quick please I'll give you brainliest.
Answer:
its c
Explanation:
A ball thrown vertically from ground level is caught 3.0 s later by a person on a balcony which is 14 m above the ground. Determine the initial speed of the ball.
The initial speed of the ball, considering its upward direction, is approximately -10.03 m/s., considering the height of the balcony and the time it takes for the ball to reach it.
Let's assume the initial speed of the ball is denoted by "v." Since the ball is thrown vertically upward and caught by a person on a balcony, its final displacement will be 14 m (the height of the balcony) above the ground. The time taken for the ball to reach the balcony is given as 3.0 s.
Using the equation of motion for vertical motion:
\(h = ut + (1/2)gt^2\)
Substituting the known values:
\(14 = v(3.0) + (1/2)(9.8)(3.0)^2\)
Simplifying the equation:
14 = 3v + 44.1
Rearranging the equation:
3v = 14 - 44.1
3v = -30.1
Dividing both sides by 3:
v = -30.1/3
Therefore, the initial speed of the ball, considering its upward direction, is approximately -10.03 m/s. The negative sign indicates that the ball was thrown upward against gravity.
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e. Observe: notice or perceive
f. Infer:
g. Repetition:
h. Replication:
i. Data
The synonym of a word( observe, infer, repetition, replication and data) means another word that is nearest in meaning to the given word.
The synonym of the words given from the question is given below:
Observe: This means to notice or perceive something. Therefore the synonym is notice or perceive.Infer: This means to conclude something based on evidence and not from explicit statements. Therefore the synonym is deduce or conclude.Repetition: This means doing or saying something again. Therefore the synonym is recurrence.Replication: This means the process of reproduction. Therefore the synonym is duplicate.Data: This means information that is used to make decisions. The synonym is facts.Therefore, synonym of a word means another word that is nearest in meaning to the given word.
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What is the Zenith angle at 45 degrees North during the Spring Equinox?
2. Calculate the Zenith angle, Solar elevation angle, and beam spreading at a site located at 45 Degrees North on the Autumnal eqinox on September 22nd.
3. At what latitude does daylight hours have the least variability?
4. true or false: The greater the solar angle (from 0 degrees to 90 degrees), the less spread out the solar beam is and the more concentrated solar radiation will be at that point.
The Zenith angle at 45 degrees North during the Spring Equinox is 45 degrees.
The Zenith angle is measured as the angle between the vertical line (directly overhead) and the line connecting the observer to the Sun. During the Spring Equinox, when the Sun is directly above the Equator, the Zenith angle at any latitude is equal to the latitude itself.
To calculate the Zenith angle, Solar elevation angle, and beam spreading at a site located at 45 degrees North on the Autumnal equinox (September 22nd), additional information is needed, such as the time of day and the observer's exact location (longitude). These factors affect the position of the Sun in the sky. The Zenith angle is the angle between the vertical line and the line connecting the observer to the Sun. The Solar elevation angle is the complement of the Zenith angle (90 degrees minus the Zenith angle). Beam spreading refers to the divergence of the solar beam as it travels through the atmosphere, which is influenced by factors such as atmospheric conditions and the Sun's position.
The latitude at which daylight hours have the least variability is the Equator (0 degrees latitude). At the Equator, the length of daylight hours remains relatively constant throughout the year, with minimal variation. In contrast, as you move farther away from the Equator towards the poles, the variability in daylight hours becomes more pronounced, with significant changes between the seasons.
False. The spread of the solar beam, known as beam spreading, is actually greater at higher solar angles (closer to 90 degrees) compared to lower solar angles (closer to 0 degrees). At higher solar angles, the solar beam covers a larger area due to the greater incidence angle, resulting in a larger spread of solar radiation. As the solar angle decreases and approaches 0 degrees, the solar beam becomes more concentrated and focused on a smaller area, leading to a higher intensity of solar radiation at that point.
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if star a has an apparent magnitude of +5, and star b has an apparent magnitude of +10, then
Star A is 100 times brighter than star B.
Apparent magnitude is a measure of the brightness of a star as seen from Earth. It is determined by the amount of light that reaches the Earth from the star. The brighter the star, the lower its apparent magnitude. So, if star A has an apparent magnitude of +5 and star B has an apparent magnitude of +10, then star A is brighter than star B.
However, the difference in brightness between the two stars is not just a factor of 5. Apparent magnitude is a logarithmic scale, which means that a difference of 5 in apparent magnitude corresponds to a difference of 100 in brightness. So, star A is 100 times brighter than star B. This is because each increase of one magnitude corresponds to a decrease in brightness by a factor of 2.512.
In conclusion, the difference in apparent magnitude between star A and star B is significant, and it indicates that star A is much brighter than star B. The magnitude system is an important tool for astronomers to measure the brightness of stars and other celestial objects.
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64. an express train passes through a station. it enters with an initial velocity of 22.0 m/s and accelerates opposite to the motion at a rate of 0.150m/s2 as it goes through. the station is 210.0 m long. (a) how fast is it going when the nose leaves the station? (b) how long is the nose of the train in the station? (c) if the train is 130 m long, what is the velocity of the end of the train as it leaves? (d) when does the end of the train leave the station?
Therefore, the final velocity of the train when the nose leaves the station is 27.4 m/s. Therefore, the nose of the train is in the station for 4.32 seconds. Therefore, the velocity of the end of the train as it leaves the station is 20.5 m/s. Therefore, the end of the train leaves the station after 15.74 seconds.
What is velocity?The primary indication of an object's position and speed is its velocity. It is defined as the distance traveled by an item in one unit of time. The displacement of an item in unit time is defined as velocity. The directional speed of an item in motion as an indicator of its rate of change in position as perceived from a certain frame of reference and measured by a specific standard of time (e.g., 60 km/h northbound) is known as velocity. Simply put, velocity is the rate at which something travels in a certain direction. For example, the speed of a car driving north on a highway or the speed of a rocket after launch.
Here,
(a) To find the final velocity of the train when the nose leaves the station, we can use the equation:
v² = u² + 2as
where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled. We can split the distance traveled into two parts: the distance covered while accelerating, and the length of the station.
For the distance covered while accelerating, the initial velocity is 22.0 m/s, the acceleration is -0.150 m/s² (opposite to the motion of the train), and the distance is the length of the station minus the initial distance covered by the train:
s₁ = (210.0 m - 0 m) - (130.0 m + 22.0 m/s × t) = 80.0 m - 22.0 m/s × t
where t is the time taken to cover the distance.
For the distance covered in the station, the initial velocity is the final velocity from the acceleration phase, and the acceleration is 0 (since the train is no longer accelerating):
s₂= 130.0 m
The total distance traveled is the sum of s₁ and s₂:
s = s₁+ s₂ = 80.0 m - 22.0 m/s × t + 130.0 m
Substituting the given values into the first equation, we get:
v² = (22.0 m/s)² + 2 × (-0.150 m/s²) × [80.0 m - 22.0 m/s × t + 130.0 m]
Simplifying, we get:
v² = 22.0² - 0.3t + 2.0 × 130.0
v² = 484 - 0.3t + 260
v² = 744 - 0.3t
Taking the square root of both sides, we get:
v = √(744 - 0.3t)
At the moment when the nose of the train leaves the station, the distance traveled is 210.0 m. Therefore, we can set s = 210.0 m and solve for t:
210.0 = 80.0 m - 22.0 m/s × t + 130.0 m
Simplifying, we get:
t = 4.32 s
Substituting this value into the expression for v, we get:
v = √(744 - 0.3 × 4.32)
v = 27.4 m/s
Therefore, the final velocity of the train when the nose leaves the station is 27.4 m/s.
(b) The time that the nose of the train spends in the station is the time it takes to travel the length of the station at a constant speed, which is the time between the end of the acceleration phase and the moment when the nose leaves the station. From part (a), we know that the acceleration phase lasts for:
t₁= (v - u) / a = (27.4 m/s - 22.0 m/s) / (-0.150 m/s²) = 36.67 s
Therefore, the total time it takes for the nose to leave the station is:
t₂ = t₁ + 4.32 s = 41.0 s
The time that the nose of the train spends in the station is:
t_station = t₂- t₁ = 4.32 s
Therefore, the nose of the train is in the station for 4.32 seconds.
(c) The velocity of the end of the train as it leaves the station can be found using the same kinematic equation:
v² = u²+ 2as
where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance.
In this case, the initial velocity is 22.0 m/s, the acceleration is -0.150 m/s², and the distance is the length of the station:
s = 210.0 m
Substituting these values, we get:
v² = (22.0 m/s)² + 2(-0.150 m/s²)(210.0 m)
v² = 484.0 m²/s² - 63.0 m²/s²
v² = 421.0 m²/s²
Taking the square root of both sides, we get:
v = 20.5 m/s
Therefore, the velocity of the end of the train as it leaves the station is 20.5 m/s.
(d) To find the time when the end of the train leaves the station, we can use the same kinematic equation used in part (b):
s = ut + (1/2)at²
where s is the displacement of the end of the train, which is 210.0 m + 130.0 m = 340.0 m, u is the initial velocity of the train, and a is the acceleration of the train.
Substituting the given values, we get:
340.0 m = (22.0 m/s)t + (1/2)(-0.150 m/s²)t²
Simplifying and solving for t, we get:
t = 15.74 s
Therefore, the end of the train leaves the station after 15.74 seconds.
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how freezing could be used to remove sugar from a mixture of sugar and water.
A student's room has a TV (250 W) ,heater (1150 W) and lamp (200 W) Electricity costs 10 fills per KWh. Calculate how much it would cost to run these three appliances for a total of 2 hour 30 minutes
Answer:
Cost = 40 fills
Explanation:
First, we will calculate the total power consumed by all appliances:
\(Power = P_{TV}+P_{heater}+P_{lamp}\\Power = 250\ W+1150\ W+200\ W\\Power = 1600\ W = 1.6\ KW\)
Now, we will calculate the energy required:
\(Energy = (Power)(Time)\\Energy = (1.6\ KW)(2.5 h)\\Energy = 4 KWh\\\)
Now, for the cost we use the following formula:
\(Cost = (Energy)(Unit\ Cost)\\Cost = (4\ KWh)(10\ fills/KWh)\\\)
Cost = 40 fills
How far does an object travel if it is moving at a speed of 4 m/s for 3.2 seconds?
SOMEONE PLEASE HELP ME
Answer:
12.8 metres
Explanation:
distance = speed x time
distance = 4 x 3.2
distance = 12.8
Increasing the distance between an electromagnet and the compass will cause the observed effect of the compass to _____.
Increasing the distance between an electromagnet and the compass will cause the observed effect of the compass to decrease in strength
What would the Increasing the distance between an electromagnet and the compass cause?
The strength of the magnetic field produced by an electromagnet decreases as the distance from the electromagnet increases. This means that if the distance between the electromagnet and the compass increases, the magnetic field that the compass is experiencing will weaken.
As a result, the observed effect of the compass will decrease in strength as the distance between the electromagnet and the compass increases.
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A 2-kilogram box on a horizontal frictionless surface is acted upon by a 9-newton horizontal force to the left and a 1-newton horizontal force to the right. The acceleration of the box is
(1) 5 m/s^2 to the right
(2) 5 m/s^2 to the left
(3) 4 m/s^2 to the right
(4) 4 m/s^2 to the left
The acceleration of the box is 4 m/s² to the left.
option 4 is the correct answer.
What is the acceleration of the box?
The acceleration of the box is calculated by applying Newton's second law of motion as follows;
∑F = ma
where;
∑F is the net forcem is the mass of the boxa is the acceleration of the boxF₁ - F₂ = ma
1 N - 9 N = ( 2 kg ) a
-8 N = ( 2 kg ) a
divide both sides by 2
- 8 / ( 2 kg ) = a
- 4 m/s² = a
Thus, the acceleration of the box will be directed to the left which has greater force.
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Describe an experiment the student could do to measure the specific heat capacity of a metal
Answer:
Steps to determine the specific heat capacity.
1. Place a beaker on a balance and press zero.
2. Now add the oil to the beaker and record the mass of the oil.
3. Read the starting temperature of the oil.
4. Connect a joulemeter to the immersion heater.
5. Time for thirty minutes.
6. Read the number of joules of energy that passed into the immersion heater.
7. Read the final temperature of the oil.
8. Use the following formula to calculate the specific heat capacity.
Explanation:
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in a circus performance, a monkey on a sled is given a initial speed of 4.0 m/s up a 25 degree incline. the combined mass of the monkey and the sled is 20.0 kg and the coefficient of kinetic friction between the sled and incline is .20 how far up the incline does the sled move before it comes to rest
The sled moves 160.97 meter up the incline before it comes to rest.
What is law of conservation of energy?Energy cannot be created or destroyed, according to the law of conservation of energy.
According to conservation of energy:
initial kinetic energy = potential energy + work done against friction
1/2 × 20.0 × 4.0² = 20.0 × 9.8 ×h + 0.20 × 20.0 × 9.8 ×h
h = (1/2 × 20.0 × 4.0²) ÷ {(1 +0.20) × 20.0 × 9.8}
h = 68.03
Hence, l = 68.03/sin25° meter = 160.97 meter
Hence, the sled moves 160.97 meter up the incline before it comes to rest.
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What 4 pieces of information should be included any time you give a written
description of motion?
Answer:
In physics, motion is the phenomenon in which an object changes its position over time. Motion is mathematically described in terms of displacement, distance, velocity, acceleration, speed, and time. ... One can also speak of motion of images, shapes, and boundaries.
Explanation:
The critical angle for a beam of light passing from the water (n= 1.33) into the air (n=1) is 48 degrees. This means that all light rays with an angle of incidence in the water that is greater than 48 degrees will be:
(a) totally absorbed by the water.
(b) totally reflected.
(c) partially reflected.
(d) partially transmitted.
(e) totally transmitted.
Show your calculations.
The critical angle (θc) is given by the equation: sin θc = n2/n1, where n1 is the refractive index of the medium from which the light is coming (in this case, water) and n2 is the refractive index of the medium into which the light is entering (in this case, air).
Using the given values, we have: sin θc = 1/1.33, which gives us θc = 48.19 degrees (rounded to two decimal places).
Any light rays with an angle of incidence in the water that is greater than 48.19 degrees will be totally reflected (option b). This is because at angles greater than the critical angle, the refracted ray would have to bend away from the normal, which is not possible in this case. Therefore, all of the incident light is reflected back into the water.
Option a (totally absorbed by the water) is incorrect because absorption is not relevant in this situation. Option c (partially reflected) is incorrect because all of the incident light is reflected, not just a portion. Option d (partially transmitted) is incorrect because no light is transmitted beyond the critical angle. Option e (totally transmitted) is also incorrect for the same reason.
Therefore, the correct answer is (b) totally reflected.
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Fighter jets on aircraft carriers are accelerated down a 270 foot "runway" in two seconds when they are taking off. A fully loaded, combat ready F-15 has a maximum take-off weight of 62,000 pounds. To ensure the pilot can reach sufficient velocity within 2 seconds a pneumatic cannon propels the plane down the runway. If this same cannon was used to launch your Toyota Corolla (mass is 2646lbs), how fast in miles per hour would you be going after reaching the end of the runway?
The speed of the Toyota Corolla would have been 143.9 mph.
What is the acceleration of the F-15?
The acceleration of the F-15 can be calculated as follows:
Acceleration = Velocity Change / Time = (Take-off Speed) / Time
where;
Take-off Speed = √(2dg /t²)
Take-off Speed = √(2 x (270 ft) x 32.2 ft/s² / (2 s)²)
T = √(17496) = 131.6 ft/s
Acceleration = Velocity Change / Time
= (131.6 ft/s) / (2 s) = 65.8 ft/s²
We can use the same acceleration to launch the Toyota Corolla, and calculate its final velocity:
Final Velocity = Initial Velocity + Acceleration x Time
where;
Initial Velocity = 0 (because the car is not moving initially), Time = 2 sFinal Velocity = 0 + (65.8 ft/s²) * (2 s) = 131.6 ft/s
Finally, we can convert the velocity from feet per second to miles per hour:
Velocity (mph) = Velocity (ft/s) x (1 hour/3600 s) x (5280 ft/mile)
= 131.6 ft/s x (1 hour/3600 s) x (5280 ft/mile)
= 143.9 mph
Learn more about average acceleration here: https://brainly.com/question/26246639
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I NEED SOMEONE TO HELP ME WITH THIS ONE PLEASE!!
-Car A that has a mass of 2000 kg is moving at 8 m·s-1 to the west. It collides with Car B that has a mass of
4000 kg moving at 1 m-s-1 to the east. Calculate the velocity of car B, if car A moves with a velocity of 4 m.s-1
After the collision.
Explanation:
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