Answer:
Based on the scientific notation ,
4.372896 x10^-7 is the answer.
What are fitness assessments designed to do?
diagnose medical conditions
screen for risk of heart disease
treat injuries
identify specific injuries
Answer: Fitness assessments are designed to screen for risk of heart disease.
Explanation:
Fitness assessments are medical examinations that are designed to measure a person's physical fitness and identify any health risks they may have. These assessments may include tests of strength, endurance, flexibility, and cardiovascular fitness. One of the primary objectives of a fitness assessment is to screen for the risk of heart disease, which is a major health concern that can be prevented or treated through exercise and other lifestyle changes. While fitness assessments may identify specific injuries or medical conditions, their primary focus is on evaluating a person's overall health and fitness.
Two blocks, 1 and 2, are connected by a massless string that passes over a massless pulley. 1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. 2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105
. The figure illustrates the configuration.
A system of two blocks connected by a rope passing over a pulley. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle. Box M subscript 1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M sub 1 and the surface is mu subscript 1. Box M subscript 2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle. The coefficient of friction between box M sub 2 and the surface is mu subscript 2.
The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.
The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.
The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.
The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.
The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).
The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).
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Equipotential Surfaces: A region of space contains a uniform electric field directed in the positive x direction as shown. Among the following the correct statements about the electric potential is: Select one: VYYc b. V₁ V₂ Ve d. We can't judge
The true statement about the electric potential for the equipotential surface is \(V_A = V_B = V_C\)
What is equipotential surface?A surface with an equipotential potential is one where all points on the surface have the same electric potential. .
That is an equipotential surface is that surface at every point of which, the electric potential is the same.
The formula for the potential across every point on the surface is given as;
V = F/Q x R
V = ER
where;
E is the electric field across the surfaceR is the distance or position of the chargeSince the surface is equipotential with uniform electric across the surface, the electric potential at any point across the surface will be the same.
So \(V_A = V_B = V_C\)
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GIVING BRAINLIEST
Which best describes what happens between meiosis I and meiosis II?
Crossing over occurs.
Cells enter into interphase.
Cells directly enter prophase II.
The number of chromosomes is doubled.
Answer:
The correct answer is A. Crossing over occurs
What types of physical education program modifications need to be made for individuals with Down syndrome who have atlantoaxial instability?
Answer:
Excuse me wot? That is so confoosing
Explanation:
A system consists of two uncharged metal spheres, each suspended on an insulating string and connected to the other by a thin
conducting wire. A positively charged rod is brought near, but does not touch, the left sphere, and the sphere is attracted to the rod. Which
of the following is correct about the net charge on the right sphere as a result?
The right sphere will acquire an equal and opposite net positive charge to balance the negative charge on the left sphere.
Electrostatic attractionSince the left sphere is attracted to the positively charged rod, it means that the left sphere acquires a temporary negative charge due to induction.
The positive charge on the rod repels electrons in the left sphere, causing them to move away from the rod side and accumulate on the opposite side, resulting in a net negative charge on the left sphere.
According to the principle of charge conservation, the net charge on the system must remain zero. Therefore, the right sphere acquires an equal and opposite net positive charge to balance the negative charge on the left sphere.
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period T= time of one revolution measured in seconds
Need the answer please
F = k Q.q/r²
F≈1/r²
r = doubled ⇒ F₂ = 1/4 F₁
Which of the following can refer to the form of exercise that uses free weights, weight machines, resistance bands, or the weight of the body to put stress on the muscles? A. Strength training B. Weight training C. Resistance training D. All of the above
Answer:
option C...
resistance training is the correct answer
List all the instrument for the Seven base quantities
Answer:
time,
length,
mass,
electric current,
thermodynamic temperature,
amount of substance,
and luminous intensity.
A pipe of constant radius carried water at 3.25 m/s. Please answer in PA.
Pipe of constant radius, we can use Bernoulli's equation, which relates the pressure, velocity, and height of a fluid at two points in a flow system.the pressure of water in the pipe is approximately 105,142 Pa.
What is a system?System refers to a collection of related components or parts that work together to achieve a specific goal or purpose. The concept of a system can be applied to a wide range of fields and disciplines, including science, engineering, economics, and social sciences.
In science, a system is often defined as a portion of the universe that is being studied or analyzed. This can include anything from a single atom or molecule to an entire ecosystem or planet. By defining the boundaries of a system, scientists can focus their attention on understanding the interactions and relationships between the various components within that system.
In engineering, a system refers to a collection of components that are designed to work together to perform a specific function or task. This can include everything from simple mechanical systems like gears and pulleys to complex electrical or computer systems.
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what do magnetic field lines look like when two magnets attract?
Answer:
Explanation:
If 2 magnets are attracting, then the north pole of one magnet is facing the south pole of the other. The magnetic field lines between the two magnets are connected and the direction of flow is north to south.
How much amount of water can be decomposed
through electrolysis by passing 2 F charge?
Answer:
So, with 2 Faraday of electricity, we can decompose (2/4 × 2) = 1 mole of water. So 18 grams of water is decomposed.
A liquid X at 25°C is poured to a height of 40cm in a thin capillary tube of length 70cm anc diameter of 1cm. Assume that the volume of the capillary tube does not change with temperature. Find the initial volume of the liquid in cm³
The level within a capillary tube with a radius of 0.45 mm rises to a height of 3 cm above the water's surface when submerged in it.
What is the capillary pressure equation?When water saturation decreases, Pnw outside the pore throat is larger than Pw within the pore throat, resulting in a positive pressure (Pc=PnwPw), which is the definition of capillary pressure.
A micron is equal to 0.001 mm in diameter, therefore the capillaries are just big enough for red blood cells to travel through in a single line. Endothelial cells, which also make up the smooth channel surface of the bigger vessels, are the single layer of cells that make up their walls.
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For the statements based on whether they are described as outcomes of results from thermal energy being added or removed particles move faster particles move slower temperature increases temperature decreases kinetic energy increases kinetic energy decreases thermal energy added thermal energy removed
4. How many excess electrons does a balloon that was rubbed on a child's hair and
now has a charge of 4.0 x 107 Coulombs?
9. Which of these tissues hold bones together at movable joints? O ligaments O cartilage O tendons O disks
Answer:
The tissue that holds bones together at movable joints is ligaments. Ligaments are strong, fibrous connective tissues that connect bones to other bones, providing stability and limiting excessive movement at the joints. They help to maintain the proper alignment and function of the joints while allowing for controlled movement.
Explanation:
The tissue that holds bones together at movable joints is ligaments. Ligaments are strong, fibrous connective tissues that connect bones to other bones, providing stability and limiting excessive movement at the joints. They help to maintain the proper alignment and function of the joints while allowing for controlled movement.
Answer:
The answer is ligaments!
Explanation:
Hope this helps!! :)
Hmmm... Who can answer this question?
How did life begin?
Just a practice
Answer:
The earliest known life-forms are putative fossilized microorganisms, found in hydrothermal vent precipitates, that may have lived as early as 4.28 Gya (billion years ago), relatively soon after the oceans formed 4.41 Gya, and not long after the formation of the Earth 4.54 Gya.
Explanation:
Is this what your looking for?
What happens to the acceleration of a system when the mass of the system increases but the net force stays constant?
Explanation:
acceleration is inversely proportional to mass so acceleration will decrease if mass increases
If the mass of the system will increase, then the acceleration of the system will decrease because mass and acceleration are inversely proportional to each other.
What is Acceleration?In mechanics, acceleration refers to the rate at which the velocity of an object changes in relation to time. The magnitude of accelerations as a vector. The acceleration of an object depends on the direction of the net force acting on it.
It is a vector quantity because acceleration has both a magnitude and a direction. Additionally, velocity is a vector quantity. The change in the vector of velocity during a period of time divided by the period of time is the definition of acceleration.
There are several types of acceleration :
Uniform AccelerationNon-Uniform AccelerationAverage AccelerationWhen the mass of the system will increase it will become heavy, and it will affect the acceleration of the body because due to this the acceleration of the body will decrease because both mass and acceleration are inversely proportional to each other.
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what is the equivalent resistance of the circuit shown below?
The equivalent resistance of the circuit shown is 23 ohms.
Option A is correct.
What is resistance?Resistance is described as the opposition that a substance offers to the flow of electric current.
In a series circuit, all components are connected end-to-end to form a single path for current flow.
In a parallel circuit, all components are connected across each other with exactly two electrically common nodes with the same volt.
We then 1/R = 1/100 + 1/100 + 1 /(50+ 50) + 1 /(50+ 50)
I/R = 0.04
R = 25 ohms.
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A quarterback throws a pass at an angle of 35° above the horizontal with an initial speed of 25 m/s. The ball is caught by the receiver 2.55 seconds later. Determine the distance the ball was thrown.
The distance the ball was thrown is 52.22m by A quarterback throws a pass at an angle of 35° above the horizontal with an initial speed of 25 m/s. The ball is caught by the receiver 2.55 seconds later.
How to calculate distance?Every motion under constant acceleration is projectile motion
Angle above horizontal Ф = 35°, initial speed v1 = 25m/s , time 2.55s
Substituting value in the below equation
x=x₁ + (v₁*cosθ)(t)+1/2 *a*t²
a= 0 as acceleration in horizontal direction is zero
x= 25*cos(35)*2.55
x=52.22 m
Projectile motion is a form of motion in which object influenced when it is launched into the gravitational force from the surface of Earth along a curved path.
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Mixed Martial Artists (MMA fighters) can really pack a punch. The average fighter can generate
5,000 N of force. This means that the fighters arm and fist has to decelerate at 877 m/s/s. How
much mass does the fighters arm have?
The mass of the fighter's arm, given that it can generate 5000 N of force is 5.7 Kg
How to determine the mass of the fighter's armForce, mass and acceleration are related according to the following formula:
Force = mass × acceleration
With the above formula, we can determine the mass of the figter's arm. This is illustrated below:
Force (F) = 5000 NAcceleration (a) = 877 m/s/sMass (m) =?Force = mass × acceleration
5000 = mass × 877
Divide both sides by 877
Mass = 5000 / 877
Mass = 5.7 Kg
From the calculation made above, we can conclude that the mass of the fighter's arm is 5.7 Kg
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A hypothetical planet has a radius 1.8 times that of Earth but has the same mass. What is the acceleration due to gravity near its surface?
The acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².
The formula for acceleration due to gravity is:
g = GM/r² Where, g = acceleration due to gravity G = universal gravitational constant M = mass of the planet r = radius of the planet
In this case, since the mass of the hypothetical planet is the same as that of Earth, we can use the mass of Earth instead of M.
Therefore, g is proportional to 1/r².
So, using the ratio of radii given (1.8), we can write:
r = 1.8 x r Earth, where r Earth is the radius of Earth.
Substituting this value of r in the formula for acceleration due to gravity, we get:
g = GM/(1.8 x r Earth)² = GM/(3.24 x rEarth²) = (1/3.24)GM/rEarth²
We know that the acceleration due to gravity on Earth (g Earth) is 9.8 m/s².
Therefore, we can calculate the acceleration due to gravity on the hypothetical planet (gh) as follows:
gh = (1/3.24) x g Earth = 3.02 m/s²
Thus, the acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².
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with a mass if 74 kg, is a moving with a velocity of 11m/s, what is the kinetic energy ?
Answer:
4477 JExplanation:
The kinetic energy of an object can be found by using the formula
\(k = \frac{1}{2} m {v}^{2} \\ \)
m is the mass
v is the velocity
From the question we have
\(k = \frac{1}{2} \times 74 \times {11}^{2} \\ = 37 \times 121\)
We have the final answer as
4477 JHope this helps you
Which of the following combinations would result in the least acceleration?O 12N and 1.0 kgO 60N and 2.0 kgO IN and 0.20 kgO5N and 0.35 kg
Given that four pairs of force and mass.
(1) Force, F1 = 12 N and mass, m1 = 1 kg
(2) Force, F2 = 60 N and mass, m2 = 2 kg
(3) Force, F3 = 1 N and mass, m3 = 0.2 kg
(4) Force, F4 = 5 N and mass, m4 = 0.35 kg
To find the least acceleration among these.
In order to find the least acceleration, we have to find the acceleration of each pair.
According to Newton's second law,
\(a\text{ = }\frac{F}{m}\)Here, a is acceleration, F is force and m is the mass.
For the first pair,
\(\begin{gathered} a1=\frac{12}{1} \\ =12m/s^2 \end{gathered}\)For the second pair,
\(\begin{gathered} a2=\frac{60}{2} \\ =30m/s^2 \end{gathered}\)For the third pair,
\(\begin{gathered} a3=\frac{1}{0.2} \\ =5m/s^2 \end{gathered}\)For the fourth pair,
\(\begin{gathered} a4=\frac{5}{0.35} \\ =14.28m/s^2 \end{gathered}\)On Comparing all the values of acceleration, the third pair (force=1 N and mass m=0.2 kg ) has the least acceleration of 5 m/s^2.
A rocket sled accelerates to 50 m/s. When the rocket engine stips, the sled skids along its rails. If the coefficient of friction is 0.5, how fast is the sled moving after 2.50 s?
The sled's speed can be calculated by considering the acceleration, frictional force, and time. After substituting the given values and performing the calculations, the final speed is determined to be 12.25 m/s.
To calculate the speed of the sled after 2.50 seconds, we can use the equations of motion and consider the forces acting on the sled.
Let's denote the initial speed of the sled as v0, the final speed as vf, the acceleration as a, the time as t, and the coefficient of friction as μ.
Initially, the rocket sled is accelerating, so we can use the equation:
vf = v0 + at
Since the sled is skidding along its rails after the rocket engine stops, the only horizontal force acting on the sled is the force of friction. The frictional force can be calculated using the equation:
frictional force = coefficient of friction * normal force
Since the sled is moving horizontally, the normal force is equal to the weight of the sled, which can be calculated as:
weight = mass * gravity
Now, we can determine the acceleration of the sled using Newton's second law:
frictional force = mass * acceleration
Combining the equations and substituting the values, we have:
vf = v0 + (frictional force / mass) * t
To find the frictional force, we need to calculate the weight of the sled and then multiply it by the coefficient of friction:
frictional force = (mass * gravity) * coefficient of friction
Substituting this back into the previous equation, we get:
vf = v0 + ((mass * gravity * coefficient of friction) / mass) * t
Simplifying further, we have:
vf = v0 + (gravity * coefficient of friction) * t
Now we can substitute the given values into the equation. Assuming the acceleration due to gravity is approximately 9.8 m/s², the coefficient of friction is 0.5, the initial speed is 0 m/s (since the sled starts from rest), and the time is 2.50 s, we can calculate the final speed:
vf = 0 + (9.8 * 0.5) * 2.50
vf = 12.25 m/s
Therefore, the sled is moving at a speed of 12.25 m/s after 2.50 seconds.
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(1 Point)
A truck's speed increases uniformly from 15 km h to 60 km/h in 20 s. Determine (a) the average
speed
Answer:
0.625 m/s
General Formulas and Concepts:
Unit 0
SI unit (distance) - metersSI unit (time) - secondsKinematics
Average Speed Formula: \(\displaystyle \frac{total \ distance}{time}\)Explanation:
Step 1: Define
[Given] Initial speed: 15 km/h
[Given] Final speed: 60 km/h
[Given] time: 20 s
[Solve] Average speed
Step 2: Convert
Initial speed
Set up conversion: \(\displaystyle \frac{15 \ km}{h}(\frac{1000 \ m}{1 \ km})(\frac{1 \ hr}{60 \ min})(\frac{1 \ min}{60 \ s})\)Multiply/Divide [Cancel out units]: \(\displaystyle \frac{25}{6} \ \frac{m}{s}\)Final speed
Set up conversion: \(\displaystyle \frac{60 \ km}{h}(\frac{1000 \ m}{1 \ km})(\frac{1 \ h}{60 \ min})(\frac{1 \ min}{60 \ s})\)Multiply/Divide: \(\displaystyle \frac{50}{3} \ \frac{m}{s}\)Step 3: Solve
Set up: \(\displaystyle \frac{\frac{50}{3} \ \frac{m}{s} - \frac{25}{6} \ \frac{m}{s}}{20 \ s}\)Subtract: \(\displaystyle \frac{\frac{25}{2} \ \frac{m}{s}}{20 \ s}\)Divide: \(\displaystyle \frac{5}{8} \ \frac{m}{s}\)Naming covalent compounds
P4S5
Answer:
what the heck is sakurfa
Explanation:
Graph. See text version for more detail.
The graph above represents the nuclear decay of a radioactive element, measured using a radiation-detecting device. What is the half-life, in days, of this hypothetical element?
If the half-life of a given substance is 65 days, how long will it take for a 100-gram sample of the substance to decay until there is only 25 grams of the radioactive material remaining?
If a sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams, what is the half-life of the isotope? Hint: First, determine how many times the sample has lost half of its mass, which tells you how many half-life cycles have occurred.
If a 500.0 g sample of technetium-99 decays to 62.5 g of technetium-99 remaining in 639,000 years, what is the half-life of technetium-99?
The half-life of hypothetical element technetium-99 is 210,936 years.
Half-life of the hypothetical element From the graph provided in the question, the half-life of the hypothetical element can be obtained by finding the time taken for the element to reduce to half its original quantity. Here, it can be seen from the graph that the quantity of the element reduces from 40 to 20 on day 4. Therefore, the half-life of the hypothetical element is 4 days.2. Time taken for a sample to decay from 100 grams to 25 gramsIf the half-life of a given substance is 65 days, then the quantity of the substance reduces to half every 65 days. From 100 grams to 50 grams, it takes one half-life cycle. From 50 grams to 25 grams, it will take another half-life cycle.
Therefore, it will take two half-life cycles, which is 2 × 65 = 130 days, for a 100-gram sample of the substance to decay until there is only 25 grams of the radioactive material remaining.3. Half-life of a sample that decays from 200 grams to 50 grams in 60 minutesIt is given that the sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams. To find the half-life, we need to determine how many times the sample has lost half of its mass, which tells you how many half-life cycles have occurred.At 30 minutes, the sample reduces to half its original quantity, which is 100 grams. At 45 minutes, it reduces to 50 grams, which is half of 100 grams. Therefore, it takes two half-life cycles to reduce from 200 grams to 50 grams in 60 minutes. Hence, the half-life of the isotope is 15 minutes.4. Half-life of technetium-99 that decays from 500.0 g to 62.5 g in 639,000 yearsIt is given that a 500.0 g sample of technetium-99 decays to 62.5 g of technetium-99 remaining in 639,000 years. We can use the half-life formula to find the half-life of technetium-99.t1/2 = (t × log2) / log(N0 / Nt) Where,t1/2 = half-life of the substanceN0 = initial quantity of the substance Nt = quantity of the substance left after time t (in years)t = time (in years)From the given data,t1/2 = (639000 × log2) / log(500.0 / 62.5)t1/2 = 210,936 years.
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If a ball is thrown into the air with a velocity of 42 ft/s, its height in feet t seconds later is given by y = 42t − 16t2. What is the average velocity for 0.5, 0.1, 0.05, and 0.01 seconds when t=2?
The average velocities for time intervals of 0.5, 0.1, 0.05, and 0.01 seconds when t=2 are -18 ft/s, -59.6 ft/s, -75 ft/s, and -31.6 ft/s, respectively.
At time t=2 seconds, the height of the ball is given by y = 42(2) - 16(2)^2 = 44 feet.
For a time interval of 0.5 seconds, the height of the ball at the beginning and end of the interval is,
y(2) = 44 feet
y(2.5) = 42(2.5) - 16(2.5)^2 = 35 feet
The displacement during this interval is 35 - 44 = -9 feet (negative because the ball is moving downward). The average velocity during this interval is,
average velocity = displacement / time interval
average velocity = (-9 feet) / (0.5 seconds)
average velocity = -18 ft/s
Similarly, for time intervals of 0.1, 0.05, and 0.01 seconds, we can find the height of the ball at the beginning and end of the interval, calculate the displacement and the average velocity,
For a time interval of 0.1 seconds:
y(2) = 44 feet
y(2.1) = 42(2.1) - 16(2.1)^2 = 38.04 feet
Displacement = 38.04 - 44 = -5.96 feet
Average velocity = -5.96 / 0.1 = -59.6 ft/s
For a time interval of 0.05 seconds:
y(2) = 44 feet
y(2.05) = 42(2.05) - 16(2.05)^2 = 40.25 feet
Displacement = 40.25 - 44 = -3.75 feet
Average velocity = -3.75 / 0.05 = -75 ft/s
For a time interval of 0.01 seconds:
y(2) = 44 feet
y(2.01) = 42(2.01) - 16(2.01)^2 = 43.684 feet
Displacement = 43.684 - 44 = -0.316 feet
Average velocity = -0.316 / 0.01 = -31.6 ft/s
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