Construct the context free grammar G and a Push Down Automata (PDA) for each of the following Languages which produces L(G). i. L1 (G) = {am bn | m >0 and n >0}. ii. L2 (G) = {01m2m3n|m>0, n >0}
Answers
Answer:
For language L1 (G) = {am bn | m >0 and n >0}, a context-free grammar can be constructed as follows: S → aSb | X, X → bXc | ε. Here, S is the starting nonterminal, and the grammar generates strings of the form am bn, where m and n are greater than zero.
To construct a pushdown automaton (PDA) for L1 (G), we can use the following approach. The automaton starts in the initial state with an empty stack. For every 'a' character read, we push it onto the stack. For every 'b' character read, we pop an 'a' character from the stack. When we reach the end of the input string, if the stack is empty, the input string is in L1 (G).
For language L2 (G) = {01m2m3n|m>0, n >0}, a context-free grammar can be constructed as follows: S → 0S123 | A, A → 1A2 | X, X → 3Xb | ε. Here, S is the starting nonterminal, and the grammar generates strings of the form 01m2m3n, where m and n are greater than zero.
To construct a pushdown automaton (PDA) for L2 (G), we can use the following approach. The automaton starts in the initial state with an empty stack. For every '0' character read, we push it onto the stack. For every '1' character read, we push it onto the stack. For every '2' character read, we pop a '1' character and then push it onto the stack. For every '3' character read, we pop a '0' character from the stack. When we reach the end of the input string, if the stack is empty, the input string is in L2 (G).
Explanation:
Related Questions
When should an additional vertical cable support a structure to make it more rigid? Can you give an example
Answers
When the structure is sagging, additional vertical cable support the structure to make it more rigid.
What are some examples of cable structures?The suspension bridge, the cable-stayed roof, and the bicycle-wheel roof are all examples of highly effective cable structures. Any string or cable stretched freely between two points will take the shape of a catenary, as evidenced by the beautiful arc of the enormous main cables of a suspension bridge.
Cable frameworks are a type of tensioned long-span construction that is supported by suspension cables. The suspension bridge, the cable-stayed roof, and the bicycle-wheel roof are all examples of highly effective cable structures.
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The most significant internal data sources for an MIS are the organization's _____ .
a. data from customers, suppliers, competitors, and stockholders c. Internet Web sites
b. various TPS and ERP systems and related databases d. various DSS and GSS systems and users
Answers
The most significant internal data sources for an MIS are the organization's various TPS (Transaction Processing Systems) and ERP (Enterprise Resource Planning) systems and related databases
The most significant internal data sources for an MIS (Management Information System) are the organization's various TPS and ERP systems and related databases. TPS are responsible for collecting and processing transactional data generated from routine business operations, such as sales, inventory, and financial transactions. ERP systems integrate data from different functional areas of the organization, providing a centralized database for managing core business processes.
These internal systems and databases contain valuable and up-to-date information about the organization's operations, resources, and performance. They serve as the primary data sources for generating meaningful management reports, analyzing trends, and supporting decision-making processes within the organization. By leveraging data from TPS and ERP systems, an MIS can provide accurate, timely, and relevant information to support planning, control, and strategic decision-making at various levels of the organization.
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Typical journal-to-bearing clearance is......
A) 0.00015 to 0.00018 inch
B)0.0005 to 0.0025 inch
C) 0.15 to 0.25 inch
D)0.02 to 0.035 inch
Answers
C
Why
I took the quiz
The typical journal-to-bearing clearance for engines is,
B) 0.0005 to 0.0025 inch
Given that,
To find the typical journal-to-bearing clearance for engines.
Now, The range 0.0005 to 0.0025 inch represents the recommended clearance between the rotating journal of the crankshaft and the bearing surface to ensure proper lubrication and minimal friction.
Hence, The correct option for typical journal-to-bearing clearance for engines is,
B) 0.0005 to 0.0025 inch.
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The circuit below is of an RC circuit . The switch has been open for a long time, and the switch closes at time t- 0 seconds. What is the time constant for the voltage across e cаpаcitor?
Answers
Answer:
100 μs
Explanation:
The Thévenin equivalent source impedance is the parallel impedance of the two resistors, so 50 ohms. The R·C product is then ...
(50 ohms)(2 microfarads) = 100 microseconds
A low-altitude meteorological research balloon, temperature sensor, and radio transmitter together weigh 2.5 lb. When inflated with helium, the balloon is spherical with a diameter of 4 ft. The volume of the transmitter can be neglected when compared to the balloon's size. The balloon is released from ground level and quickly reaches its terminal ascent velocity. Neglecting variations in the atmosphere's density, how long does it take the balloon to reach an altitude of 1000 ft?
Answers
Answer:
12 mins
Explanation:
The summation of the forces in vertical direction
= Fb - Fd - w = 0 ∴ Fd = Fb - w ----- ( 1 )
Fb ( buoyant force ) = Pair * g * Vballoon ------- ( 2 )
Pair = air density , Vballoon = volume of balloon
Vballoon = \(\frac{\pi D^3}{6}\) , where D = 4 ∴ Vballoon = 33.51 ft^3
g = 32.2 ft/s^2
From property tables
Pair = 2.33 * 10^-3 slug/ft^3
μ ( dynamic viscosity ) = 3.8 * 10^-7 slug/ft.s
Insert values into equation 2
Fb = ( 2.33 * 10^-3 ) * ( 32.2 ) *( 33.51 ) = 2.514 Ib
∴ Fd = 2.514 - 2.5 = 0.014 Ib ( equation 1 )
Assuming that flow is Laminar and RE < 1
Re = (Pair * vd) / μair -------- ( 3 )
where: Pair = 2.33 * 10^-3 slug/ft^3 , vd = ( 987 * 4 ) ft^2/s , μair = 3.8 * 10^-7 slug/ft.s
Insert values into equation 3
Re = 2.4 * 10^7 ( this means that the assumption above is wrong )
Hence we will use drag force law
Assume Cd = 0.5
Express Fd using the relation below
Fd = 1/2* Cd * Pair * AV^2
therefore V = 1.39 ft/s
Recalculate Reynold's number using v = 1.39 ft/s
Re = 34091
from the figure Cd ≈ 0.5 at Re = 34091
Finally calculate the rise time ( time taken to reach an altitude of 1000 ft )
t = h/v
= 1000 / 1.39 = 719 seconds ≈ 12 mins
We lack awareness of many of our bodies' systems for maintaining homeostasis. The sensations, movements, and secretions of organs such as the heart and intestines are governed by the
Answers
The sensations, movements, and secretions of organs such as the heart and intestines are governed by the autonomic nervous system (ANS).
These processes occur automatically and do not require conscious thought or effort. Therefore, we do not typically perceive the sensations, movements, and secretions of these organs as they are regulated by the body's internal systems.
The ANS is a part of the peripheral nervous system and regulates involuntary bodily functions, such as heart rate, digestion, and respiration. It is divided into two branches: the sympathetic and parasympathetic nervous systems. The sympathetic system is responsible for the "fight or flight" response, while the parasympathetic system is responsible for the "rest and digest" processes.
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Generic Motors (GM) is making plans for its weekly operation for next year. GM makes three lines of
cars: Luxury (L), Mid-sized (M), and Economy (E). They have divided the country into four regions:
Northeast (NE), Northwest (NW), Southeast (SE) and Southwest (SW). They have two factories that can
ship to the four distribution center via train. Each distribution center will need to provide cars to the
dealers in that region; this is done via trucking. Note that since customers need their cars within a week,
everything is built on a weekly production and shipment schedule. The following information is included:
1) Production costs and capacities at the two factories for the three lines.
2) Retail cost of the three lines.
I
3) A weekly demand model for each of the four regions.
4) Shipping information from the factories to the distribution center of the four regions.
5) Shipping information from the distribution center to the dealers.
You have been asked to maximize the expected weekly profit for GM.
Make sure the spreadsheet is well documented! Use the color coding and headers we used all
semester long. You do not need to reproduce the spreadsheet in the report except the decision tree,
and a summary of your results.
Answers
C++ Character operations
A 2-character string, userPassword, is read from input. Replace each character in userPassword that is not alphabetic with '#'. Otherwise, userPassword is not changed.
Ex: If the input is 2q, then the output is:
#q
Code:
#include
#include
#include
using namespace std;
int main() {
string userPassword;
getline(cin, userPassword);
(input goes here)
cout << userPassword << endl;
return 0;
}
Answers
A password is a string of characters used to verify the identity of a user during the authentication process.
#include <iostream>
int main() {
int n = 2;
char userPassword[n];
for(int i = 0; i<n; i++){
std::cin>>userPassword[i];
if(isdigit(userPassword[i]))
userPassword[i]='*';
}
return 0;}
A password is a group of letters and numbers that is used to confirm a user's identity throughout the authentication process. Passwords are frequently used in conjunction with usernames; they are intended to be kept secret and unique to the user and grant access to a device, application, or website.
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I'm so confused to this question
What is the difference between Science and Engineering?
Answers
Explanation:
Science is the body of knowledge that explores the physical and natural world. Engineering is the application of knowledge in order to design, build and maintain a product or a process that solves a problem and fulfills a need (i.e. a technology).
Answer:
Generally, Science is the study of the physical world, while Engineering applies scientific knowledge to design processes, structures or equipment.
What is the maximum number of points a player can score during a frame of snooker while curving around at a 45 degree angle going at a speed of 2 miles per hour with the wind speed of 2 mph on a rug coated snooker table?
Answers
In snooker, the maximum number of points that can be scored during a single frame is 147. This is achieved by potting all 15 red balls, each worth 1 point, and subsequently potting the colored balls in sequence: yellow (2 points), green (3 points), brown (4 points), blue (5 points), pink (6 points), and black (7 points). Each color is then returned to its original position and can be potted again for additional points.
The angle and wind speed mentioned in your question are not relevant to determining the maximum number of points in a snooker frame. The speed and direction of the balls are controlled by the player's shots, and the rug coating on the table doesn't affect the scoring.
So, regardless of the angle, wind speed, or table surface, the maximum number of points that can be scored in a frame of snooker is 147.
What cell type has no membrane-bound organelles, has DNA that is found in an area called the
nucleoid, and is very small?
A. Eukaryotic cell
B. Prokaryotic cell
C. Animal cell
D. Plant cell
Answers
Answer:
Prokaryotic cell
Explanation:
1. which of the following parameters should be collected in an assessment of common dysphonia? a. videostroboscopic evaluation b. acoustic voice parameters c. aerodynamic voice parameters d. all of the above
Answers
D. All of the above is the correct answer for this question becuase ideostroboscopic evaluation, acoustic voice parameters, aerodynamic voice parameters are the parameters that are used to assess common dysphonia.
What is Dysphonia?
An Otolaryngologist (Nose, Ear, and Throat physician) who treats voice disorders in collaboration with a speech pathologist provides the best evaluation for dysphonia. A physician and speech pathologist can better understand the voice disorder if they have an accurate report of when the dysphonia started and what the voice problems are.
The speech pathologist conducts a voice assessment in which the patient or parent answers questions about how the dysphonia affects daily activities. In addition, the patient is asked to speak into a microphone, which records the voice and produces measurements that are compared to vocal standards.
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Of the following, which is not a consideration that must be addressed in determining inspection intervals for AST's?
A) Corrosion prevention systems
B) Inspection Interval of other equipment located near the tank under consideration
C) Changes in service(Including changes in water bottoms)
D) Previous inspection results
Answers
Answer:
B) Inspection Interval of other equipment located near the tank under consideration is not a consideration that must be addressed in determining inspection intervals for AST's.
Explanation:
question write and solve an addition equation to find x. perimeter = 132 in. an addition equation for this problem is =132. the solution is x= inches.
Answers
The number of X is 33 inches.
A perimeter became the closed path that encompasses, surrounds, or outlines each a two-dimensional shape or a one-dimensional length. The perimeter of a circle or an ellipse is known as its circumference. Calculating the perimeter has numerous practical applications. The perimeter moreover says the length of the definition of a shape. To find out the edge of a rectangle or square you want to add the lengths of all four sides.
To determine the amount of X, we will use the method below:
X + X + X + X = 132 or 4x = 132.
Then we will discover the result for X with the step below:
4x = 132
Divide both side by 4
Hence
x = 132 : 4 = 33
x = 33
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The allowable shearing stress is 15 ksi In the 1.5-in.-diameter steel rod AB and 7.6 ksi In the 1.8-in.-diameter brass rod BC. Neglecting the effect of stress concentrations, determine the largest torque T that can be applied at A. (Round the final answer to two decimal places.) Steel The largest torque T that can be applied at As k ip-in.
Answers
Now, let's determine the maximum shear stress that can be applied to the steel rod AB. Max shear stress in steel rod AB = (Allowable shear stress in steel) / (Factor of safety) = 15 ksi / 2 = 7.5 ksi
How can I determine the most torque?The Maximum Torque is calculated using the formula below. Divide 5252 by the maximum rotational speed, and then multiply the result by the maximum horsepower to determine the maximum torque.
T AB is equal to (pi/16)*tau max*d3.
T AB = (pi/16)*7.5 ksi*1.5 in3 = 131.20 kip-in (rounded to two decimal places)
The brass rod BC's torque is calculated as follows:
T BC = (pi/16) * tau max * d3, where d is the rod's diameter.
T BC = (pi/16)*3.8ksi*1.8in3 = 94.18 kip-in (rounded to two decimal places)
T max = min(T AB, T BC) = min(131,20,94,18 kip-in) = 94,18 kip-in (rounded to two decimal places)
Hence, 94.18 kip-in is the maximum torque that can be applied at point A.
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Which of the following workers are not likely to be paid during an election?
campaign press secretary
volunteer coordinator
poll worker
director of communications
Answers
Answer:
volunteer coordinator
Explanation:
because they are volunteering for that and in most of the cases they do not expect to be paid
The steel shaft has a diameter of 40 mm and is fixed at its ends A and B . If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa.
Q6/
Answers
Answer:
See explanation.
Explanation:
Since no figure was given I solved a problem that was similar to the one you described that I worked in my mechanics of materials class. The method should be very similar for your figure. See attached image for my work.
If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.
What we need to perform?We need to perform a two step process to obtain the maximum shear stress on the shaft. For the solid shaft,
P=2×pi×N×T/60 or T=60×p/2×pi×N
Where P=power transmitted by the shaft=50×10³W
N=rotation speed of the shaft in rpm=730rpm
Pi=3.142
T is the twisting moment
By substituting the values for pi, N and P, we get
T=654Nm or 654×10³Nmm
Also, T=pi×rho×d³/16 or rho=16×T/pi×d³
Where rho=maximum shear stress
T = twisting moment=654×10³Nmm
d= diameter of shaft= 40mm
By substituting T, pi and d
Rho=52Mpa
b. For a hollow shaft, the value for rho is unknown
T=pi×rho(do⁴-di⁴/do)/16
Rho=T×16×do/pi×(do⁴-di⁴)
Where
T= twisting moment=654×10³Nmm gotten above
do=outside shaft diawter=40mm
di= inside shaft diameter =30mm
Pi=3.142
Substituting values for pi, do, di and T.
Rho=76Mpa
Therefore, If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.
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A cylindrical specimen of some metal alloy having an elastic modulus of 106 GPa and an original cross-sectional diameter of 3.9 mm will experience only elastic deformation when a tensile load of 1660 N is applied. Calculate the maximum length of the specimen before deformation if the maximum allowable elongation is 0.41 mm.
Answers
Answer:
L= 312.75 mm
Explanation:
given data
elastic modulus E = 106 GPa
cross-sectional diameter d = 3.9 mm
tensile load F = 1660 N
maximum allowable elongation ΔL = 0.41 mm
to find out
maximum length of the specimen before deformation
solution
we will apply here allowable elongation equation that is express as
ΔL = \(\dfrac{FL}{AE}\) ....................1
put here value and we get L
L = \(\dfrac{0.41\times 10^{-3}\times \dfrac{\pi}{4}\times (3.9\times 10^{-3})^2\times 106\times 10^9}{1660}\)
solve it we get
L = 0.312752 m
L= 312.75 mm
Can someone help me plz!!
Answers
Match the item on the left with the process or technique on the right with which it is most closely related A. spiral model B. unified model C. version control D. integration testing E. system test F, regression test G.regression testing H. software configuration management . risk expected fail mock objects record and playback
Answers
A - Risk
B - Unified Model
C - Version Control
D - Integration Testing
E - System Test
F - Regression Test
G - Regression Testing
H - Software Configuration Management
A. Risk - The spiral model is a software development process that emphasizes risk management throughout the project. It involves identifying and mitigating risks at each iteration of the development cycle.
B. Unified Model - The unified model, also known as the Unified Modeling Language (UML), is a standardized modeling language used for software design and development.
C. Version Control - Version control is a technique used to manage changes to source code or other files in a collaborative software development environment. It helps track changes, resolve conflicts, and maintain a history of revisions.
D. Integration Testing - Integration testing is a process of testing the interaction between different software components to ensure they work together correctly.
E. System Test - System testing is a level of software testing where the complete system is tested as a whole to verify that it meets the specified requirements.
F. Regression Test - Regression testing is the process of retesting a software system to ensure that modifications or bug fixes have not introduced new issues or regression.
G. Regression Testing - Regression testing is a type of software testing that focuses on verifying that previously developed and tested software still performs as expected after changes have been made.
H. Software Configuration Management - Software configuration management is the process of managing and controlling changes to software artifacts, including source code, documentation, and other related files. It involves version control, release management, and change management.The process or technique on the right is most closely related to the item on the left.
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Metal and dirt are not considered contaminants to oil. a) trueb) false
Answers
Answer:
False, metal and dirt ARE considered contaminants!
Explanation:
i ride motocross! trust me!
The statement "Metal and dirt are not considered contaminants to oil" is false. The correct option is B.
What are metals?Metals are chemical elements that have high thermal and electrical conductivity, and they are soft and ductile. Magnesium, helium, gold, and silver are metals. They are very reactive, and they contain both gas and solids.
Oil and dirt are considered contaminated to oil. It causes a chemical reaction in the oil, that's why it is a problem with contamination of the oil. It causes reactions like depletion or oxidation.
In motor oils, there are many chances of pollution with dirt and metals, and other oxides. This causes debris and leads to degradation of work of lubrication of engine parts, which causes friction.
Thus, the statement is true. The correct option is B.
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It is desired to produce and aligned carbon fiber-epoxy matrix composite having a longitudinal tensile strength of 630 MPa. Calculate (a) the critical fiber length, and (b) the volume fraction of fibers necessary if (1) the average fiber diameter is 0.030 mm, (2) the average fiber length is 2.4 mm, (3) the fiber fracture strength is 5100 MPa, (4) the fiber-matrix bond strength is 17 MPa, (5) the matrix stress at fiber failure is 17.5 MPa.
Answers
Answer:
The answer is below
Explanation:
Given that:
Diameter (D) = 0.03 mm = 0.00003 m, length (L) = 2.4 mm = 0.0024 m, longitudinal tensile strength \((\sigma_{cd})=630\ MPa = 630*10^6\ Pa\), Fracture strength
\((\sigma_f)=5100\ MPa=5100*10^6\ Pa,fiber-matrix\ stres(\sigma_m)=17.5\ MPa=17.5*10^6\ Pa,matrix\ strength=\tau_c=17\ MPa=17 *10^6\ Pa\)
a) The critical length (\(L_c\)) is given by:
\(L_c=\sigma_f*(\frac{D}{2*\tau_c} )=5100*10^6*\frac{0.00003}{2*17*10^6}=0.0045\ m=4.5\ mm\)
The critical length (4.5 mm) is greater than the given length, hence th composite can be produced.
b) The volume fraction (Vf) is gotten from the formula:
\(\sigma_{cd}=\frac{L*\tau_c}{D}*V_f+\sigma_m(1-V_f)\\\\V_f=\frac{\sigma_{cd}-\sigma_{m}}{\frac{L*\tau_c}{D}-\sigma_{m}} \\\\Substituting:\\\\V_f=\frac{630*10^6-17.5*10^6}{\frac{0.0024*17*10^6}{0.00003} -17.5*10^6} \\\\V_f=0.456\)
which one of these reduce fraction?
Answers
Thermal energy storage systems commonly involve a packed bed of solid spheres, through which a hot gas flows if the system is being charged, or a cold gas if it is being discharged. In a charging process, heat transfer from the hot gas increases thermal energy stored within the colder spheres; during discharge, the stored energy decreases as heat is transferred from the warmer spheres to the cooler gas. Consider a packed bed of 75 -mm-diameter aluminum spheres (rho=2700 kg/m3,c=950 J/kg⋅K,k= 240 W/m⋅K ) and a charging process for which gas enters the storage unit at a temperature of Tg,i=300∘C. If the initial temperature of the spheres is Ti=25∘C and the convection coefficient is h=75 W/m2⋅K, how long does it take a sphere near the inlet of the system to accumulate 90% of the maximum possible thermal energy? What is the corresponding temperature at the center of the sphere? Is there any advantage to using copper instead of aluminum?
Answers
The corresponding temperature at the center of the sphere after approximately 0.309 seconds is approximately 198.83°C.
To determine the time required for a sphere near the inlet of the system to accumulate 90% of the maximum possible thermal energy, we can use the concept of thermal diffusion through a sphere. The time required can be calculated using the equation for the thermal diffusion time constant:
τ = (ρ * c * r^2) / (4 * k)
where:
τ is the thermal diffusion time constant,
ρ is the density of the sphere material (in this case, aluminum) = 2700 kg/m^3,
c is the specific heat capacity of the sphere material (in this case, aluminum) = 950 J/kg⋅K,
r is the radius of the sphere (diameter/2) = 75 mm / 2 = 37.5 mm = 0.0375 m,
k is the thermal conductivity of the sphere material (in this case, aluminum) = 240 W/m⋅K.
Substituting these values into the equation, we can calculate the thermal diffusion time constant:
τ = (2700 kg/m^3 * 950 J/kg⋅K * (0.0375 m)^2) / (4 * 240 W/m⋅K)
Now we can solve for τ:
τ ≈ 0.309 seconds
The thermal diffusion time constant represents the time required for a sphere to reach approximately 63.2% of the maximum possible thermal energy. To calculate the time required to accumulate 90% of the maximum energy, we can use the following relation:
t = τ * ln((90% - 63.2%) / (100% - 63.2%))
Substituting the values into the equation:
t = 0.309 seconds * ln((90% - 63.2%) / (100% - 63.2%))
t ≈ 0.309 seconds * ln(0.271 / 0.368)
t ≈ 0.309 seconds * ln(0.736)
t ≈ 0.309 seconds * (-0.305)
t ≈ -0.094 seconds
The negative value obtained implies that 90% of the maximum possible thermal energy cannot be accumulated within a sphere near the inlet of the system. This suggests that the system may need additional time or adjustments to reach the desired energy level.
To calculate the corresponding temperature at the center of the sphere, we can use the concept of one-dimensional transient heat conduction through a sphere. The equation for this scenario is:
T = Ti + (Tg,i - Ti) * (1 - exp(-t / τ))
where:
T is the temperature at the center of the sphere at time t,
Ti is the initial temperature of the spheres = 25°C,
Tg,i is the gas temperature at the inlet of the system = 300°C,
t is the time,
τ is the thermal diffusion time constant calculated earlier.
Let's calculate the corresponding temperature at the center of the sphere when t = 0.309 seconds
T = 25°C + (300°C - 25°C) * (1 - exp(-0.309 / 0.309))
T ≈ 25°C + 275°C * (1 - exp(-1))
T ≈ 25°C + 275°C * (1 - 0.3679)
T ≈ 25°C + 275°C * 0.6321
T ≈ 25°C + 173.8275°C
T ≈ 198.8275°C
Therefore, the corresponding temperature at the center of the sphere after approximately 0.309 seconds is approximately 198.83°C.
Now, let's consider the advantage of using copper instead
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If current flowing through a conductor is 10 mA. how many electrons travel through it in 10 s?
Answers
6.25×10⁻¹⁸ electrons will flow through a copper wire.
What are electrons?Electrons can be defined as the sum of atomic particles that is the career of negative charge, they are responsible for the chemical property of an element, the electrons are present in the shell.
Use formula ( I = ne/t )
Here,
number of electron
electron =1.6 x 10¯¹9 C
We have a relation between charge and current as
Charge = Current×time i.e
Q = i×t.
Now we have current = 10 amp & time = 10sec from given data.
Therefore charge Q = 10×1 = 100 coulombs.
Again we have a relation between charge and no of electrons
I.e no of electrons= total charge / 1.6×10⁻¹⁹
So, no of electrons = ( 100C/1.6×10⁻¹⁸ )
= 6.25×10⁻¹⁸ electrons.
Therefore, 6.25×10⁻¹⁸ electrons will flow through a copper wire carrying 10 amps current for 10 sec
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compare or contrast absolute and secondary instruments
Answers
Answer:
contrast absolute
Explanation:
Answer: The difference between absolute and secondary instruments are tabulated below. The values of the quantity to be calculated in terms of physical constants and their deflection are given by Absolute Instruments. Secondary instruments are tools whose production is calculated to give the quantity's value.
How are deltas formed?
erosion of softer rock
connection of channels
deposition from flow into a lake or an ocean
creation of large, flat areas by flooding deposits
Answers
Answer:
It is created from deposition from flow into a lake or an ocean like the Missisippi delta
Explanation:
Answer:
C: deposition from flow into a lake or an ocean
Explanation:
deposition from rivers creates a variety of features, delta deposits created by flow into lake or ocean, is one of them.
8. What is the density of an object with a mass of 290.5 g and volume of 83 cm 3?
Answers
The density would be 218.5
Which three items below should a driver be able to identify under the hood of a car?
Answers
Answer:
Engine oil level.
Brake fluid.
Power steering fluid.
What problem solving strategies don’t gaurentee solutions but make efficient use of time