Calculation of specific volume for both initially and final state. The specific volume of a substance is defined as the volume occupied by unit mass of the substance.
The specific volume can be calculated as:
v = V/m Where: v = Specific volume V = Volume of the substance m = Mass of the
substance Initial state: Pressure = 200 kPa Temperature = 355 K
The pressure and temperature of the initial state can be used to find the specific volume of the initial state using the ideal gas law.
PV = m R T Where: P = Pressure V = Volume of the gas specific gas constant (R)
T = Temperature m = Mass of the gas V = m RT/Pv1 = (mass of the gas × specific gas constant × temperature)
Pressurev1 = (m × R × T1)/P1Final state: Pressure = 400 kPa Temperature = 700 K
Calculation of exponent (n) of the polytropic process The polytropic process is defined as a process in which pressure and volume of the gas change in such a way that PV n = constant Where:
P = Pressure of the gas V = Volume of the gas n = Exponent of the polytropic process
The exponent of the polytropic process can be found using the initial and final states of the gas.The specific work is defined as the work done by unit mass of the substance.
W = h1 - h2Where:W = specific workh1 = Enthalpy at the initial stateh2 = Enthalpy at the final state
The specific work of the process can be found using the enthalpy values of the initial and final state.
W = Cp(T2 - T1)/(1 - n)W = (specific heat capacity × (final temperature - initial temperature))/(1 - n)
The final expression of each of the calculated parameters is given below:
v1 = (m × R × T1)/P1v1 = (m × 287 × 355)/(200 × 10³)v1 = 1.43 m³/kg
v2 = (m × R × T2)/P2v2 = (m × 287 × 700)/(400 × 10³)v2 = 0.72 m³/kg
(T2 - T1)/(1 - n)W = (1.005 × (700 - 355))/(1 - 1.268)W = 169.92 kJ/kg
The specific volume of the initial state is 1.43 m³/kg, the specific volume of the final state is 0.72 m³/kg, the exponent of the polytropic process is 1.268 and the specific work of the process is 169.92 kJ/kg.
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A commercial aircraft is in steady flight. The overall lift to drag coefficient is 25. The other flight data are: (i)Weight of aircraft (including crew and passengers) = 70,000 kg (ii) Flight speed 400 km/hr (iii) Average wing span = 50 m (iv) Average wing chord = 7 m When in operation 20% of fuel power is lost. Find the power required for this steady flight. (5M)
Explanation:
weight of aircraft including crew and passengers is equal to 70000 kg therefore option is a thecorrect answer
with the aid of a labbled diagram describe the operation of a core type single phase transformer
Answer:
A simple single-phase transformer has each winding being wound cylindrically on a soft iron limb separately to provide a necessary magnetic circuit, which is commonly referred to as “transformer core”. It offers a path for the flow of the magnetic field to induce voltage between two windings.
1. The term lefty loosey, righty tighty is used to prevent what?
Answer:
Used to recall the direction a standard screw
Lynx eat snowshoe hares, and snowshoes hears eat plants. Which term can be applied to the lynx in this food chain example? Primary consumer predator secondary consumer
Answer:
primary consumer because YES
Answer:predator and secondary consumer
Explanation:
A mass attached to the end of a spring is stretched a distance x0 from equilibrium and released.
a. At what distance from equilibrium will it have velocity equal to half its maximum velocity?
b. At what distance from equilibrium will it have acceleration equal to half its maximum acceleration? Answer in terms of x0
.
a. The mass will have a velocity equal to half its maximum velocity at a distance of 0.707x0 from equilibrium.
b. The mass will have an acceleration equal to half its maximum acceleration at a distance of 0.5x0 from equilibrium.
The motion of a mass attached to a spring is described by the equation:
x = A cos(ωt + φ)
where x is the displacement from equilibrium, A is the amplitude of the motion, ω is the angular frequency (ω = sqrt(k/m) where k is the spring constant and m is the mass), t is time, and φ is the phase angle.
The maximum velocity and acceleration occur at the equilibrium position (x=0) and are given by:
v_max = Aω
a_max = Aω^2
To find the distance from equilibrium where the velocity is half its maximum value, we can solve for the displacement x when v = v_max/2:
v = -Aω sin(ωt + φ) = v_max/2
sin(ωt + φ) = -1/2
ωt + φ = -π/6 or 7π/6
Substituting ω = sqrt(k/m) and t = T/4 (where T is the period of the motion) gives:
sqrt(k/m)T/4 + φ = -π/6 or 7π/6
Solving for A cos(φ) (which is the displacement from equilibrium) gives:
A cos(φ) = ±(sqrt(3)/2)A
Therefore, the distance from equilibrium where the velocity is half its maximum value is 0.707x0.
To find the distance from equilibrium where the acceleration is half its maximum value, we can solve for the displacement x when a = a_max/2:
a = -Aω^2 cos(ωt + φ) = a_max/2
cos(ωt + φ) = -1/2
ωt + φ = ±2π/3
Substituting ω = sqrt(k/m) and t = T/3 gives:
sqrt(k/m)T/3 + φ = ±2π/3
Solving for A cos(φ) gives:
A cos(φ) = ±0.5x0
Therefore, the distance from equilibrium where the acceleration is half its maximum value is 0.5x0.
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I need some help!
Thanks
Answer:
a c 1 museum is a patient who by think and pay the the price
A_____AH mean that the energy i____from a reaction taken deleted aborbed poitive negative
The increase in energy from a reaction that was taken, deleted, aborted, positive, or negative is indicated by the change in enthalpy.
The quantitative characteristic that is transferred to a body or to a physical system in physics is energy, which is visible in the performance of labor as well as in the form of heat and light. Energy is a resource that is conserved; it can only be changed from one form to another and cannot be created or destroyed, according to the law of conservation of energy. The unit of measurement for energy in the International System of Units is the joule. Common types of energy include the kinetic energy of an object in motion, the potential energy held by an object, the elastic energy held in a solid object, the chemical energy related to chemical reactions, the radiant energy carried by electromagnetic radiation, and the internal energy held within a thermodynamic system.
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Need help please due today ill give brainliest for non-irrelevant answers
Describe the quality control measures engineers likely will use for a newly introduced line of cars that use solar power to recharge high-capacity batteries. Propose at least three tests or processes that will be important to any quality assessment for such a vehicle system.
Answer:
make sure its safe make sure it works as inteded
Explanation:
yes
Also discuss how bandwidth is affected by increasing the number of signal elements.
Which saddle fusion stage is completed when you remove the heater plate face and visually inspect the heated ends, then join the fitting and pipe?
The stage of saddle fusion that is completed when you remove the heater plate face and visually inspect the heated ends, then join the fitting and pipe is the "heating and fusing" stage.
During the heating and fusing stage of saddle fusion, the heater plate is placed between the ends of the fitting and pipe, and they are heated to their melting point. Once the ends are heated, the heater plate is removed, and the ends are visually inspected to ensure that they have melted and are ready for joining.
After the ends have been inspected, the fitting and pipe are joined together by applying pressure to the molten plastic and holding them in place until the plastic cools and solidifies. This completes the heating and fusing stage of the saddle fusion process.
It is important to note that proper technique and equipment are crucial during this stage to ensure a strong, leak-free joint. Improper heating or fusing can result in a weak or defective joint, which can lead to leaks, contamination, or other problems. Therefore, it is essential to follow established procedures and use appropriate equipment when performing saddle fusion.
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Suppose a group of 12 sales price records has been sorted as follows: 5, 10, 11, 13, 15, 35, 50, 55, 72, 92, 204, 215; Partition them into three bins by each of the following methods:
(a) equal-frequency (equidepth) partitioning; (b) equal-width partitioning
a. The equal-frequency partitioning for the given sales price records would be as follows: Bin 1: 5, 10, 11, 13 Bin 2: 15, 35, 50, 55 Bin 3: 72, 92, 204, 215
How to explain the information(a) Equal-Frequency (Equidepth) Partitioning:
Equal-frequency partitioning divides the data into bins of equal frequency. In this case, we have 12 records, so we need to partition them into three bins.
Now, we can assign the records to the bins based on their order. Starting from the lowest value, we assign four records to each bin until all records are assigned. If there are any remaining records, we distribute them evenly across the bins.
Using this method, the equal-frequency partitioning for the given sales price records would be as follows:
Bin 1: 5, 10, 11, 13
Bin 2: 15, 35, 50, 55
Bin 3: 72, 92, 204, 215
(b) Equal-Width Partitioning:
Equal-width partitioning divides the data into bins of equal width or range. In this case, we need to determine the range of the data and then divide it into three equal-width bins.
The range of the data is the difference between the maximum and minimum values, which is 215 - 5 = 210.
Each bin will have a width of 210 / 3 = 70. Starting from the minimum value, we assign the records to the bins based on their value falling within the corresponding width range.
Using this method, the equal-width partitioning for the given sales price records would be as follows:
Bin 1: 5, 10, 11, 13, 15, 35
Bin 2: 50, 55, 72, 92
Bin 3: 204, 215
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Calcule la entropía de 2 moles de un gas ideal que realiza una expansión libre al triple de su volumen inicial, utilice: ∆S =n・R・ℓn (Vf / Vi)
The entropy of 2 moles of and ideal gas expanding freely to 3 times it's initial volume is 18.3J/k
How did we arrive at the above?The following formula is required:
∆S = nx R x ℓn x (Vf/Vi)
Where
n = number of moles of gas (n = 2)
R = gas constant (R = 8.314 J/(mol * K))
Vf = final volume (Vf = 3.V1)
Vi = intial volume
Vi = 1L (Asumption )
∆S = 2 x 8.314 x 1.099
∆S =18.3 j/K
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Translation:
Calculate the entropy of 2 moles of an ideal gas expanding freely to three times its initial volume, use: ∆S =n・R・ℓn (Vf / Vi)
If vapor compression cooling machine uses 1 kW of electric energy to provide 4 kW of cooling, what is the COP for cooling
Mathematically, it is given as:the COP for cooling of the vapor compression cooling machine is 4.
COP for cooling = Cooling output / Energy input
In this case, the cooling output is 4 kW and the energy input is 1 kW. Therefore, the COP for cooling can be calculated as:
COP for cooling = 4 kW / 1 kW = 4 The Coefficient of Performance (COP) for cooling of a vapor compression cooling machine is defined as the ratio of the cooling output to the energy input.
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1. A diode laser has a band gap of eV0, where V0 is a voltage. The laser has an efficiency of 30%, meaning 30% of the power input is converted to laser light output. We run an electrical current I through the diode, where I is in amps.a. What is the wavelength of the photons produced by the laser
Answer:
Hence wavelength of the photons produced by the laser is
\(\frac{hc}{eV_0}\)
Explanation:
Given
Efficiency of laser - 30%
As we know
\(eV_0 = \frac{hc}{\Lambda}\)
h = plank's constant
c = speed of light
eV0 = band gap
Hence wavelength of the photons produced by the laser is
\(\Lambda= \frac{hc}{eV_0}\)
What kind of plan or development of road can be done to avoid traffic?
Answer: Breakdown Lanes
Reason: With breakdown lanes when a car needs to stop it can go to the backdown lane and fix its issue.
(b) (i) Draw the circuit diagram of the input protection circuitry of a 74HC-series CMOS inverter and briefly explain the need for such a circuit and its operation. (Assume VDD = 5 V)
(ii) Assuming that the voltage at the input is momentarily at +20 V, show how the circuit protects the inverter.
(iii) Show how the circuit protects the inverter when the input is momentarily at -25 V.
(a) The 74HC CMOS IC family stands for high-speed CMOS integrated circuit logic.
This is a high-performance CMOS version that offers the lowest power consumption of all CMOS families.
This device is designed for usage in high-speed computing, memory, and microprocessor applications.
(b) (i) The circuit diagram of the input protection circuitry of a 74HC-series CMOS inverter is as follows:
Here, the need for such a circuit and its operation can be explained as follows:
An input protection circuit is often included in the input stage of a circuit to safeguard the sensitive input section from damage or malfunction as a result of overvoltage or static discharge.
This circuit provides a low-impedance path for currents resulting from transient input voltages that exceed the voltage supply rails of the circuit.
The circuitry works in the following manner:In normal operation, the clamping diodes prevent the voltage at the input from exceeding VDD + 0.5 V and GND - 0.5 V.
These diodes offer protection against transient voltages of a polarity similar to that of VDD and GND (positive for VDD and negative for GND).
(ii) The circuit protects the inverter when the input is momentarily at +20 V in the following way:
When the voltage applied at the input is positive and exceeds VDD + 0.5 V, the protection circuitry becomes active.
The current flow will be in the direction of the +5V rail and away from the input when this occurs.
The current flows through the diode D1 to the 5V supply and from there to the ground.
(iii) The circuit protects the inverter when the input is momentarily at -25 V in the following way:
Similarly, when the voltage applied at the input is negative and exceeds GND - 0.5 V, the protection circuitry becomes active.
In this case, the current will flow from the ground to the input.
It will flow through diode D2 and into the ground.
The diode D2 will limit the voltage to -0.5 V, preventing any harm to the inverter.
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1. the internal combustion engine in an car emits 0.35Kg of CO
per liter of gas burned; How much CO does a 2018 equinox FWD emit
in a year?
The 2018 Equinox FWD has a gas tank capacity of 14.9 gallons, which is equivalent to 56.43 liters.
\(0.35 Kg CO/liter of gas x 56.43 liters of gas = 19.74 Kg CO\) per fill-up We can use this value to calculate the annual CO emissions of the car, assuming that it is driven an average of 12,000 miles per year and gets an average fuel efficiency of 28 miles per gallon.
which is equivalent to 1622.29 liters of gas. the annual CO emissions of the 2018 Equinox FWD would be:\(19.74 Kg CO per fill-up x (1622.29 liters of gas / 56.43 liters of gas per fill-up) = 567.5 Kg CO\) per year So the 2018 Equinox FWD emits approximately 567.5 Kg of CO per year.
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Differential Leveling
correct BS rod reading and correct FS rod reading for curvature and refraction before computing HI and elevation of TP1
BM A elevation = 462.43'
BS (plus) rod reading = 8.23'
Horizontal distance to BS rod from instrument = 1,791.62'
FS (minus) rod reading = 2.54'
Horizontal distance to FS rod from instrument = 1,118.57"
What is the elevation of TP1?
Round answer to 2nd decimal place
example answer 975.25
don't enter units.
The angular speed of the rod, when it lands on the horizontal surface is 1.61 rad/s.
(b) The the angular acceleration of the rod, just before it touches the horizontal surface is 1.06 rad/s² .
Angular acceleration of the rod
The angular acceleration of the rod is calculated as follows;
Apply the principle of conservation of angular momentum;
τ = Iα
where;
τ is torque
I is moment of inertial of the rod
α is the angular acceleration
τ = Fr = mg(L/2) cosθ
I = mL²/3
mg(L/2) cosθ = mL²/3(α)
g(1/2) cosθ = L/3(α)
(³/₂)g cosθ = L(α)
(³/₂ L)g cosθ = α
1.5Lg cosθ = α
1.5(2.1) cos (70.4) = α
1.06 rad/s² = α
Angular speed of the rod
ωf² = ω₁² + 2αθ
ωf² = 0 + 2(1.06)(70.4π/180)
ωf² = 2.605
ωf = √2.605
ωf = 1.61 rad/s
Thus, the angular speed of the rod, when it lands on the horizontal surface is 1.61 rad/s.
The the angular acceleration of the rod, just before it touches the horizontal surface is 1.06 rad/s² .
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need urgent help!!
Determine the point(s) P on the line e with equation x−6 = ( y−3)/4 = ( 1−z)/3
for which the line connecting P with Q(2, −6, 5) is perpendicular to e.
The quartiles divide a set of observations into four portions, each representing 25% of the observations, together with the minimum and maximum values of the data set. The interquartile range, a measurement of variation around the median, is calculated using quartiles.
How are quartiles determined?In order to quartile a set of data with n items (numbers), we choose the n/4th, n/2nd, and n/4th items. Interpolation between the adjacent items is used if indexes n/4, n/2, or 3n/4 are not integers.For instance, the first quartile Q1 of ordered data is the 25th item, the second quartile Q2 is the 50th item, and the third quartile Q3 is the 75th item. The fourth quartile Q4 would be the highest item of data, and the zeroth quartile Q0 would be the minimum item; however, these extreme quartiles are referred to as the minimum and maximum of a set, respectively.Calculation:Statistical file: {2, -6, 5}
Quartile Q1: -6
Quartile Q2: 2
Quartile Q3: 5.
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how many pairs of wires get switched when making a gigabit ethernet crossover cable
Answer:ALL FOUR PAIRS
Explanation: first major difference is the gigabit standards require the use of all four pairs (all eight wires), unlike Fast Ethernet which only utilizes two pairs of wires. As a result, in Gigabit Ethernet, all four pairs must be crossed when building a Crossover cable
When making a Gigabit Ethernet crossover cable, two pairs of wires get switched. Ethernet cables are used to connect computer networks that enable communication between different devices. The two most popular types of Ethernet cables are crossover and straight cables.
Ethernet cables use four pairs of wires to transmit data, out of which two pairs are utilized for transmitting and two pairs are used for receiving. In a straight-through Ethernet cable, the wire arrangement is identical at both ends. For this reason, a straight-through cable is employed to connect devices that belong to the same category. In contrast, a crossover Ethernet cable is employed to connect devices belonging to different categories. A crossover cable reverses the transmitting and receiving pairs, allowing the devices to communicate with one another. In a Gigabit Ethernet crossover cable, two pairs of wires are swapped or switched. These pairs are Pins 1-2 (White and Orange) and Pins 3-6 (White and Green). Therefore, we can conclude that two pairs of wires get switched when making a Gigabit Ethernet crossover cable.
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10. State four possible combinations of service equipment that meet the requirements of
110.9 and 110.10 of the Code.
a.
b.
C.
d.
However, assuming it pertains to the National Electrical Code (NEC), four possible combinations of service equipment that meet the requirements of 110.9 and 110.10 of the NEC could.
Based on the references to "110.9" and "110.10 of the Code," it appears that this question pertains to the National Electrical Code (NEC). Section 110.9 of the NEC states that "equipment intended to interrupt current at fault levels shall have an interrupting rating sufficient for the nominal circuit voltage and the current that is available at the line terminals of the equipment." Section 110.10 requires that "all electrical equipment and materials shall be listed or labeled."
Given these requirements, four possible combinations of service equipment that meet the NEC's requirements could include:
A listed and labeled circuit breaker panel with a suitable interrupting rating and a listed and labeled transfer switch.A listed and labeled switchgear assembly with a suitable interrupting rating and a listed and labeled generator transfer switch.A listed and labeled fused disconnect switch with a suitable interrupting rating and a listed and labeled distribution panel.A listed and labeled molded case circuit breaker with a suitable interrupting rating and a listed and labeled meter socket.It's important to note that these are just a few possible combinations that could meet the NEC's requirements, and the specific combination required will depend on the specific installation and its requirements. A qualified electrical professional should always be consulted to ensure compliance with all applicable codes and standards.
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Draw the shear and moment diagrams for the loaded beam. After you have the diagrams, answer the questions as a check on your work. 16 KN 3 kN/m 5 kN/m A B 6 m +3m +3m + 12 m when x = 10, V=Blank 1kN, M=Blank 2kNm Absolute Vmax=Blank 3kN Absolute Mmax-Blank 4kNm Round your answers up to 3 decimal places.
Shear and moment diagrams for the loaded beam are shown below: {image}Let the two different forces of the beam be F1 = 16kN,
w1 = 3kN/m, and
w2 = 5kN/m. Therefore, the reactions at point A are
RA = 3.25kN and
MA = 3.25kNm. At the same time, the reactions at point B are
RB = 18.75kN and
MB = 78.25kNm. For x > 0, the value of V is equal to (RA - w1x) and for x > 6, the value of V is equal to (RB - w1x).
Therefore, the shear force diagram for the given loaded beam is shown below: {image}The moment diagram for the given loaded beam is shown below:
Answers to the given questions are as follows:
When x = 10,
V = -4.25 kN, 1kN ≤ Absolute Vmax ≤ 10kN,
Absolute Vmax = 13.5 kN. When
x = 10,
M = -10.5 kNm, 1kNm ≤ Absolute Mmax ≤ 10kNm,
Absolute Mmax = 78.25 kNm.
Thus, the shear and moment diagrams of the loaded beam have been drawn and the given questions have been answered as well.
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What needs to be done before joining a fitting and pipe using socket fusion?
Before joining a fitting and pipe using socket fusion, it is important to ensure that both the fitting and pipe are clean and free from any debris or contaminants. Additionally, the correct size fitting and pipe must be used to ensure a proper fit.
Socket fusion is a method of joining plastic pipes and fittings together by heating the material and then pressing the heated ends together to form a strong bond. Before the socket fusion process begins, it is important to prepare both the fitting and pipe by ensuring they are clean and free from any debris or contaminants.
This can be achieved by using a specialized cleaning tool or wiping the surfaces with a clean cloth. Additionally, it is crucial to use the correct size fitting and pipe to ensure a proper fit and prevent any leaks or issues in the future. Proper preparation of the materials is crucial to ensuring a successful socket fusion joint.
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How would you describe good communication? Why and when do we need it?
Select the correct answer from each drop-down menu. Choose the correct words to complete the sentence to name the technique described. is the technique of adjusting the spaces between words to add more characters in a line, while is the technique of adjusting the spaces between specific character pairs to improve readability.
The technique of adjusting the spaces between words to add more characters in a line is called justification, while the technique of adjusting the spaces between specific character pairs to improve readability is called kerning.
Justification is commonly used in publishing, where it is important to have evenly spaced lines of text. Kerning is used to make sure that certain character combinations, such as "WA" or "To", do not have too much or too little space between them, which can affect the overall readability of the text.
Both techniques are important in typesetting and can significantly improve the overall appearance and legibility of printed or digital text.
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The wall is 15 ft high and consists of 2 x 4 in. studs, plastered on one side. On the other side there is 4-in. clay brick. Determine the average load in lb>ft of length of wall that the wall exerts on the floor.
Answer:
645 lb/ft
Explanation:
The height of the wall = 15 ft
For the 2 x 4 in. studs:
The minimum dead load for a 2 x 4 in. studs (from table 1-3) = 4 psf = 4 lb/ft²
Therefore for a 15 ft tall wall, the dead load for a 2 x 4 in. studs = 15 ft × 4 lb/ft² = 60 lb/ft
For the 4 in. clay brick:
The minimum dead load for a 4 in. clay brick (from table 1-3) = 39 psf = 39 lb/ft²
Therefore for a 15 ft tall wall, the dead load for a 4 in. clay brick = 15 ft × 39 lb/ft² = 585 lb/ft
Therefore the average load = load for the 4 in. clay brick + load for the 2 x 4 in. studs = 585 lb/ft + 60 lb/ft = 645 lb/ft
Answer every question of this quiz
Please note: you can answer each question only once.
Which number shows the intake valve?
OK
I'd say number 4, number 3 looks like an exhaust valve
determine the application of star connected network
Answer:
fijixuc uckyc7fmtjjr hcumffjmfumfnng
Answer:
a method of connecting polyphrase circuits in which one end of each phase line is connected to a common neutral point that may be connected to the earth as protection against lightning or to a wire to which all the other neutral points of the system are connected
Explanation:
Can some help me with this !!! Is 26 points!!
Assignment: Explain any three
ways that research can facilitate
the work of building technicians.
The three ways that research can facilitate the work of building technicians is that:
They will know the timeframe to start and complete the buildingThey will know the type and right materials to use.It will help them in the area of budgeting of equipment, tools and building materials needed.What do building technicians do?Building technicians are known to be people who help with some tasks around construction projects and building works.
Note that building technician overseeing a scope of tasks such as monitoring build progress and as such The three ways that research can facilitate the work of building technicians is that:
They will know the timeframe to start and complete the buildingThey will know the type and right materials to use.It will help them in the area of budgeting of equipment, tools and building materials needed.Learn more about technicians from
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