Answer:
The static "frictional force" and the "kinetic friction" will act on the box.
When A force is applied to a box to move it to the right across the kitchen floor, static friction force comes into play before start moving. When the box starts moving, dynamic friction force comes into play.
What is friction?
The resistance provided by surfaces in touch as they move past one another is known as friction.
To walk without slipping, traction is provided by friction. In most situations, friction is advantageous. They do, however, give a strong amount of opposition to the move.
When A force is applied to a box to move it to the right across the kitchen floor, static friction force comes into play until it starts moving. When the box starts moving, dynamic friction force comes into play.
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6.P.2.1 Matter: Properties and Changes Notes
The Theory ______
of Conservation
of
states:______
cannot be
or!____________
height
is anything that has
(weight) and height
(takes up space).
A
is the
in an object.
is the
an object takes
to add speaker notes
Answer:
The __law__ conservation
of state that either energy may produced nor destroyed
Why do you think the greater wax moth developed the ability to hear frequencies up to 300kHz?
Please be kind enough to help me thank you!!!!
Answer:
The greater wax moth developed the ability to hear frequencies up to 300kHz to trick bats, their chief predators.
Explanation:
Dogs commonly listen to frequencies of about 30 kHz. But nothing matches the moths 300-kHz maximum. Since there aren't any noises in an environment that get close, scientists hypothesize that greater wax moths developed super sensitive hearings to trick bats, their chief predators. it can hear wavelengths up to 300 kHz, well exceeding the range of any other creature and higher than any bat can sound.
A 17-N falling object encounters 9 N of air resistance. The magnitude of the net force on the object is
The magnitude of the net force on the object is 8 N. This is because the force of gravity, which is 17 N, is being opposed by the force of air resistance, which is 9 N. Therefore, the net force is 17 N - 9 N = 8 N.
Force is a push or pull on an object that is caused by an interaction between two objects. It has both magnitude, which is the strength of the interaction, and direction, which is the direction in which the force is being applied.
Net force is the sum of all the forces acting on an object. It is calculated by adding up all the forces that are acting on the object, taking into account their directions. This can be used to calculate the acceleration of an object, as the greater the net force, the greater the acceleration.
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A light bulb has a resistance of 360 . What is the current in the bulb when it has a potential difference of 120 V across it?
0.33 A
3 A
480 A
43,200 A
Answer:
333 mAmps .33 A
Explanation:
v = ir
v/r = i
120 v / 360 ohm = .3333 A
Answer:
A). 0.33A
Explanation:
Earthquakes are especially associated with ___ boundaries
what is the velocity of a ball right before it hits the ground if it falls from a 2.5 m bookshelf?
Answer:
vf = 7 m/s
Explanation:
The final velocity of the ball right before it hits the ground can be found by using the third equation of motion:
\(2gh = v_f^2 - v_i^2\)
where,
g = acceleration due to gravity = 9.81 m/s²
h = height = 2.5 m
vf = final velocity = ?
vi = initial velocity = 0 m/s
Therefore,
\(2(9.81\ m/s^2)(2.5\ m) = v_f^2 - (0\ m/s)^2\\v_f = \sqrt{49.05\ m^2/s^2}\\\)
vf = 7 m/s
Drift velocity (v) of the charge carriers is given by the equation...
The drift velocity (v) of charge carriers in a conductor is given by the following equation: v = I / (n \(\times\) A \(\times\) q).
v = I / (n \(\times\) A \(\times\) q)
where:
v is the drift velocity, measured in meters per second (m/s)
I is the current flowing through the conductor, measured in amperes (A)
n is the number of charge carriers per unit volume of the conductor, measured in per cubic meter (\(m^(-3)\))
A is the cross-sectional area of the conductor, measured in square meters (m^2)
q is the charge of a single carrier, such as an electron, measured in coulombs (C)
This equation relates the drift velocity of the charge carriers to the current flowing through the conductor, the number of charge carriers per unit volume, the cross-sectional area of the conductor, and the charge of a single carrier. The drift velocity represents the average velocity of the charge carriers as they move through the conductor in response to an applied electric field.
The number of charge carriers per unit volume (n) depends on the material of the conductor and the temperature. In metals, the charge carriers are typically electrons, and the number density is on the order of 10^28 to 10^29 electrons per cubic meter.
The cross-sectional area (A) of the conductor is the area of the cross-section of the conductor perpendicular to the direction of the current flow, and is a measure of the amount of material available for the charge carriers to move through.
The charge of a single carrier (q) is typically the charge of an electron, which is approximately 1.6 x \(10^{-19\) coulombs.
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What is the force on a 1000 kg elevator that is falling freely at 9. 8 m/sec2.
calculate the answer to the correct number of significant digits
0.055 * 5.1 =
Answer:
0.055 * 5.1 = 0.2805
Explanation:
I used a calculator so it should be accurate! yw!! :D
What's the weight of 1 gallon of water?
The weight of 1 gallon of water is 3.785 kilograms .(kg).
This is because 1 US gallon of water is equal to 3.785 liters, and 1 liter of water weighs 1 kilogram.A gallon is a unit of measurement used to measure volume.It is used to measure liquid volume, such as a gallon of milk or gasoline. It can also be used to measure dry volume, such as a gallon of popcorn.A gallon is a unit of measurement for liquid volume equal to 128 fluid ounces or 3.785 liters.Therefore, 1 US gallon of water weighs 3.785 kilograms. To calculate this, you can use the following equation: 1 US gallon \((3.785 liters) * 1 kilogram (per liter) = 3.785 kilograms\).
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The weight of 1 gallon of water is 3.785 kilograms .(kg).
This is because 1 US gallon of water is equal to 3.785 liters, and 1 liter of water weighs 1 kilogram.A gallon is a unit of measurement used to measure volume.It is used to measure liquid volume, such as a gallon of milk or gasoline. It can also be used to measure dry volume, such as a gallon of popcorn.A gallon is a unit of measurement for liquid volume equal to 128 fluid ounces or 3.785 liters.Therefore, 1 US gallon of water weighs 3.785 kilograms. To calculate this, you can use the following equation: 1 US gallon .\((3.785liters*1kilogtam(per liter)=3.785kilograms\)
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The rotational inertia of a pencil is greatest about an axis
a)about its end, like a pendulum.
b)about its midpoint, like a propeller.
c)along its length, where the lead is.
The rotational inertia of a pencil is greatest about an axis about its midpoint, like a propeller, option B.
What is a rotational inertia?""Rotational inertia," also known as "moment of inertia." Rotational inertia is a measure of an object's resistance to changes in its rotational motion, and is defined as the sum of the products of the masses of each particle composing an object and the square of their distances from a chosen axis of rotation.
The larger an object's rotational inertia, the harder it is to get it rotating, or to change its rotational speed.
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at 10° Celsius the gas in a cylinder has a volume of .250 L the gas is allowed to expand to point .285L what must the final temperature be for the pressure to remain constant
11.4°C
Answer:
Solution given:
temperature [T1]=10°c
temperature [T2]=?
volume [V1]=250L
at volume [V2]=285L
now
By using Charles law
V1/T1=V2/T2
250/10=285/T2
T2=285/25
T2=11.4°C
the final temperature must be 11.4°C for the pressure to remain constantwhat animal that does not eat meat
Answer:
An animal that doesn’t eat meat is called a herbivore. An few examples would be cows, rabbits, horses, and goats.
:)
You are on the steep edge of the Grand Canyon, which is miles deep. You fire an arrow at an 89-degree angle towards the canyon (nearly straight up, with no hope of reaching the other side) Describe the arrow's trajectory, in particular noting approximately when the arrow has the most deceleration, the most acceleration, and then why the shift begins to happen. Cover all major points in the trajectory from initial shot to final resting place. When is the arrow moving fastest?
Answer:
a. The arrow follows a parabolic path
b. As the arrow hits the ground,
Explanation:
a Describe the arrow's trajectory, in particular noting approximately when the arrow has the most deceleration, the most acceleration, and then why the shift begins to happen. Cover all major points in the trajectory from initial shot to final resting place.
This is because, the arrow is a projectile and its path follows a parabolic curve as it goes from initial shot to final resting place.
Its equation of motion is governed by y = ut - 1/2gt² where y = parabolic path, u = initial speed of arrow, t = time and g = acceleration due to gravity.
As the arrow rises, it undergoes the most deceleration. This is because as it rises, its speed decreases until it gets to the peak of its path, where its velocity is momentarily zero.
Also, as the arrow drops, it undergoes the most acceleration. This is because as it drops from its peak, its speed increases until it gets to the bottom of its path, where its velocity is maximum and given by v = u' - gt where u' = velocity at peak = 0 m/s. So, v = 0 - gt = -gt.
b. When is the arrow moving fastest?
As the arrow hits the ground, its velocity is highest (maximum), so it is fastest at this point.
Can someone please help me with this I am quite stuck thanks
Answer:
The mass remains the same since stoichiometrically one mole reacts and one mole is formed
Explanation:
Calcium chloride is reacting with Sodium sulphate to form a white precipitate of calcium sulphate.
\({ \sf{CaCl _{2} + Na_{2} SO_{4} → CaSO _{4} + 2NaCl}}\)
From the equation, 1 mole of calcium chloride forms 1 mole of calcium sulphate.
R.F.M of CaCl2 = 40 + (35.5×2) = 111
R.F.M of CaSO4 = 40 + 32 + (16×4) = 136
R.F.M of Na2SO4 = (23×2) + 32 + (16×4) = 142
R.F.M of 2NaCl = 2[23 + 35.5] = 117
\({ \sf{(r.f.m \: of \: rectants) = (r.f.m \: of \: products)}} \\{ \sf{ (mass \: of \: rectants) = (mass \: of \: products)}} \\ \\ { \sf{(111 + 142) = (136 + 117)}} \\ { \sf{300.23 = x}} \\ \\ { \sf{x = \frac{300.32}{(111 + 142)} \times (136 + 117) }} \\ \\ { \sf{x = \frac{300.32}{253} \times 253 }} \\ \\ { \sf{x = 300.32}}\)
Answer:
The mass remains the same
Explanation:
Planet
P
Note: Figure not drawn to scale.
In the figure above, a spaceship (not shown) from point P is traveling along the dashed
line towards the planet. The net gravitational force at point P is 4.0 x 1010 N. Assume that
any motion of the planet is negligible.
If the spaceship stops halfway between the planet and point P, what happens to the magnitude of the net gravitational force exerted on the spaceship by the planet?
o The net gravitational force stays constant.
o The net gravitational force is half as great.
o The net gravitational force is twice as great.
The net gravitational force is four times as great
If the spaceship stops halfway between the planet and point P, the net gravitational force is four times as great.
Gravitational force between two objects
The gravitational force between two objects is determined from Newton's second law of universal gravitation.
F = GmM/R²
where;
R is the distance between the spaceship and the planet.when the distance halved
F = GmM/(0.5R)²
F = GmM/(0.25R²)
F = 100GmM(25R²)
F = 4GmM/R²
Fnet = 4F
Thus, if the spaceship stops halfway between the planet and point P, the net gravitational force is four times as great.
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23. In addition to the fulcrum, every lever uses a____
to move the____
Answer:
i think its a load to move a object,
Explanation:
im taking this to and it isnt in the lesson
Advanced Wireless Services (AWS) is a wireless telecommunications spectrum band used for mobile voice and data services, video, and messaging. The AWS band uses frequencies in several segments: from 1695 to 2200 MHz. a) Determine the corresponding range of wavelengths used by the AWS mobile devices. b) To what region/band of electromagnetic spectrum does the range belong
Given data
*The given frequency is
\(f_1_{}=1695\text{ MHz}=1695\times10^6\text{ Hz}\)*The another given frequency is
\(f_2=2200\text{ MHz=}2200\times10^6\text{ Hz}\)*The given speed of light is c = 3.0 × 10^8 m/s
(a)
The formula for the wavelength is given as
\(\lambda_1=\frac{c}{f_1}\)Substitute the known values in the above expression as
\(\begin{gathered} \lambda_1=\frac{(3\times10^8)}{(1695\times10^6)^{}} \\ =0.176\text{ m} \end{gathered}\)The another wavelength for the another frequency is calculated as
\(\begin{gathered} \lambda_2=\frac{c}{f_2} \\ =\frac{(3.0\times10^8)}{(2200\times10^6)} \\ =0.136\text{ m} \end{gathered}\)(b)
Radio spectrum is an electromagnetic spectrum where the frequency range belongs of wireless telecommunication.
What is the reason for a stone sink in the water but a plastic floats?
Select one:
A.
The density of plastic is greater than stone
B.
Mass of the stone is greater than mass of plastics.
C.
The density of plastic is greater than water.
D.
The density of stone is greater than water.
Experiment 1: what volume would the gas sample occupy at 50. 0 °c?
Both the initial amount and the kind of gas play a role. However, the pressure and the quantity of gas present also have a role in this relationship.
Charles' Law states that a gas's volume is directly proportionate to its temperature. However, the pressure and the quantity of gas present also have a role in this relationship. Hence, we would need to know the starting volume, pressure, and number of moles of a gas sample in order to calculate its volume at 50.0 °C. The type of gas would also be a role in deciding its final volume at 50.0 °C because different gases behave differently at various temperatures. Ideal gas perfectly obeys the gas law. Thus, the correct answer to the question is Ideal gas.
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what should have happened to the grand unified force as the universe expanded and cooled at an age about
Grand unified force thermodynamically isolated its internal energy as the universe expanded and cooled at an age about.
The universe's evolution has been split into eras by cosmologists and astronomers.The Planck Era was followed by the Grand Unified Theory Era, which is the third stage of the evolution of the universe.Every era saw significant changes, so it is crucial to investigate what transpired there.Between 10-43 seconds and 10-35 seconds, the Grand Unified Theory Era took place. Such a brief period of time. This brief period of time is hard to imagine.Light has not yet been created in this era. Because of certain circumstances, such as high temperature and high pressure, particles and molecules still cannot bind.To learn about universe's evolution-
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how far do you have to descend in air to experience the same increase in pressure as descending 10ft deep in water?
We have to descend 33 feet in air to experience the same increase in pressure.
The pressure exerted by water on a unit surface area is known as hydrostatic pressure. The pressure varies with the depth of water. For every 33 feet of depth which is equal to 10 meters, the hydrostatic pressure increases by 1 atmosphere (atm).
There are many animals that live in the greater hydrostatic pressure such as - whales they can withstand thousands atmosphere of pressure. Going deeper into the water ca cause some problems such as blocking of ear drums, squeezing of lungs, feeling a heavy load on chest and etc.
The divers face these consequences while they go deep into the ocean. The pressure increases and they feel their ear getting blocked.
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A student walks to the right 25-m along the 800 hall in 15-s. They turn around and walk 15-m to the left in 8.0-s. Calculate the average speed and the average velocity
Answer:
Explanation:
Total distance covered = 25 + 15 = 40 m
Total time = 15 + 8 = 23 s
Average speed = total distance covered / total time
= 40 / 23
= 1.74 m / s
Total displacement = 25 - 15 = 10 m
Total time = 15 + 8 = 23 s
Average velocity = total displacement / total time
= 10 / 23
= .434 m / s to the right .
The average speed of the student is approximately 1.74 m/s, and the average velocity is approximately -1.74 m/s (to the left).
Given:
Distance to the right = 25 m
Time taken to the right = 15 s
Distance to the left = 15 m
Time is taken to the left = 8.0 s
To calculate the average speed and average velocity, we need to use the following formulas:
Average speed = Total distance traveled ÷ Total time taken
Average velocity = Displacement ÷ Total time taken
Calculate the total distance traveled:
Total distance = Distance to the right + Distance to the left
Total distance = 25 + 15 = 40 m
Calculate the total time taken:
Total time = Time taken to the right + Time taken to the left
Total time = 15 + 8.0 = 23 s
Calculate the average speed:
Average speed = Total distance ÷ Total time
Average speed = 40 ÷ 23 = 1.74 m/s
Calculate the displacement:
Displacement = Final position - Initial position
Displacement = (-15 ) - 25 = -40 m
Calculate the average velocity:
Average velocity = Displacement ÷ Total time
Average velocity = -40 ÷ 23 ≈ -1.74 m/s
So, the average speed of the student is approximately 1.74 m/s, and the average velocity is approximately -1.74 m/s (to the left). The negative sign in the average velocity indicates that the student's net direction is to the left.
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A 21.1 kg person climbs up a uniform ladder with negligible mass. The upper end of the ladder rests on a frictionless wall. The bottom of the ladder rests on a floor with a rough surface where the coefficient of static friction is 0.14 . The angle between the horizontal and the ladder is θ . The person wants to climb up the ladder a distance of 0.88 m along the ladder from the ladder’s foot. What is the minimum angle θmin (between the horizontal and the ladder) so that the person can reach a distance of 0.88 m without having the ladder slip? The acceleration of gravity is 9.8 m/s 2 . Answer in units of ◦
The minimum angle so that the person can reach a distance of 0.88 m without having the ladder slip is 8⁰.
What is the weight of the person?The weight of the person is calculated by applying the following formula.
W = mg
where;
m is the mass of the persong is acceleration due to gravityW = ( 21.1 kg x 9.8 m/s² )
W = 206.78 N
The force of friction is calculated as;
Ff = μW
where;
μ is coefficient of frictionFf = 0.14 x 206.78
Ff = 28.95 N
If the person must not fall, the clockwise moment must be equal to anticlockwise moment.
28.95 x 0.88 x cosθ = 206.78 x 0.88 x sinθ
28.95 x cosθ = 206.78 x sinθ
28.95 / 206.78 = sinθ / coθ
28.95 / 206.78 = tanθ
θ = arc tan ( 28.95 / 206.78 )
θ = 8⁰
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An incline plane is 12-m long and 4-m high. A block is pulled up the ramp with a spring scale. The reading on the spring scale is 70-N. How many Newtons would the block actually weigh if you had to lift it the 4-m height?
Answer:
W = 210 N
Explanation:
For an ideal machine:
\(Work\ In = Work\ Out\\(P)(L)=(W)(H)\)
where,
P = Effort = Spring Scale Reading = 70 N
L = Effort Arm = Length of inclined plane = 12 m
W = Actual Load (Weight) to be lifted = ?
H = Load Arm = Height = 4 m
Therefore,
\((70\ N)(12\ m) = (W)(4\ m)\\\\W = \frac{(70\ N)(12\ m)}{4\ m}\)
W = 210 N
To most efficiently solve this problem, you should divide the rod into pieces of charge that consist of
To most efficiently solve this problem, you should divide the rod into pieces of charge that consist of Thin slices of the rod cut perpendicular to the axes of the rod. Option C.
What is electric potential created by a punctual charge?
The electric potential is a magnitud used to obtain a measure of the electric field that a charge located at a point A can acquire.
The electric potential, V, of the electric field created by a point charge Q is obtained by means of the following expression,
V = k (Q/R)
Where
V is the electric potential,Q is the chargeR is the distanceK is a constantThe electric potential can be created by one or many punctual charges.
If it is caused by many punctual charges in the electric field, the total electric potential, Vt, results from the addition of the electric potentials, Vn, at that point created by each of the charges separately.
Vt = V1 + V2 + V3 + .... + Vn
In the exposed example, there is a lineal distribution of charges along the rod.
So there is a rod of length L. This rod has a possitive charge Q distributed along its length.
There is an A point placed at a distance D from one of the rod extremes.
We need to find the way to calculate the Electric potential, V.
Vt = ∫ K dQ/R
where dQ is a charge differential = λ dL
So we need to place a charge differential, dQ, at any place along the rod. Then R will be the distance from the dQ to the point A.
The total V is the addition of many puntual V.
The best way to calculate it is option C. Thin slices of the rod cut perpendicular to the axes of the rod.
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Why are astronomers interested in building observatories capable of detecting neutrinos, cosmic rays, and gravitational waves?.
Astronomers are interested in building observatories capable of detecting neutrinos, cosmic rays, and gravitational waves because these are not forms of light, they can provide information about the objects that emit them that light cannot.
Astronomers study the heavens at X-ray wavelengths using satellites and earth-orbiting observatories. Because X-rays and gamma rays are absorbed high in the Earth's atmosphere, instruments to observe this radiation must be placed in orbit above the atmosphere.
Astronomy relies on electromagnetic radiation to help us see the universe. It allows us to see (visual light) on Earth. Pulsars, for example, emit X-rays but not visible light, which is how we know they exist. Neutrinos are also made up of energy, but they are made up of radioactive decay.
This enables scientists to measure them despite the fact that they can pass through almost anything without being noticed. Gravitational waves are disturbances caused by the curvature of space that expand at a specific rhythm or "force" that travels at the speed of time. Because they can all be measured without being light, they are ideal for being found in space to create more knowledge about the universe.
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The default setting shows two people holding one object each. The mass of the blue object is 50 kilograms and the red one is 200 kilograms. Note that the value of force each object applies on the other is the same (0.000000041712 newtons), but in the opposite direction. This value is written in standard notations. Express this value in scientific notation.
Please help
The value of 0.000000041712 N written in standard notations can be expressed as 41.712 × \(10^{-9}\) N in scientific notation.
Scientific Notation in ScienceThis is a way of expressing large and small quantity as a simple number. The number will be multiply by a power of ten which is known as multiplying factor
Given that the value of force each object applies on the other is the same which is 0.000000041712 newtons, but in the opposite direction. This value is written in standard notations.
This number can be expressed as
0.000000041712 N = 41.712 nN
That is, 41.712 nano Newton
The multiplying factor of nano is \(10^{-9}\)
To express this value in scientific notation, multiply the number 41.712 by the multiplying factor. That is,
0.000000041712 N = 41.712 × \(10^{-9}\) Newtons
Therefore, the value of 0.000000041712 N of force each object in scientific notation is 41.712 × \(10^{-9}\) N
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a common 5-l metal can will float in air if it is
A common 5-liter metal can will float in air if it is filled with a lighter-than-air gas, such as helium or hydrogen.
In order for a 5-liter metal can to float in air, it needs to have an overall density less than that of air. This can be achieved by filling the can with a lighter-than-air gas, such as helium or hydrogen. These gases have lower densities than air, which results in a decreased overall density of the can when it is filled with one of these gases.
The buoyant force exerted on the can by the surrounding air is determined by the weight of the displaced air. If the weight of the can and the gas inside is less than the weight of the air displaced, the can will float. Helium and hydrogen, being lighter than air, can create this effect, allowing the can to float in air. However, safety concerns must be taken into account, as hydrogen is highly flammable and can pose a risk if not handled properly.
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Help me with this quesiton