Consider this reaction:

2Cl2O5 —> 2Cl2 + 5O2

At a certain temperature it obeys this rate law.
rate = (2.7.M^-1•s^-1) [Cl2O5]^2

Suppose a vessel contains Cl2O5 at a concentration of 0.600M. calculate how long it takes for the concentration of Cl2O5 to decrease by 94%. you may assume no other reaction is important. round your answer to two digits

Answer:

a. The Zn and HCl both retained their identity.

Answer:

\(pH=4.6\)

Explanation:

Hello,

In this case, the dissociation of hypochlorous acid is:

\(HClO_4\rightleftharpoons H^++ClO_4\)

Therefore, the law of mass action for equilibrium is written as:

\(Ka=\frac{[H^+][ClO_4^-]}{HClO_4} =3.00x10^{-8}\)

And can also be written introducing the reaction extent (\(x\)):

\(3.00x10^{-8}=\frac{x*x}{0.0200-x}\)

Thus, solving for \(x\) we obtain:

\(x=2.45x10^{-5}M\)

Which is also equal to the concentration of H⁺ in the solution. Thereby, the pH turns out:

\(pH=-log([H^+])=-log(2.45x10^{-5})\\\\pH=4.6\)

Which is substantiated by the fact it is about an acid (pH lower than 7).

Regards.

pH=4.6  

Given:

Ka= \(3.00*10^{-8}\)

[HClO]=0.0200 M

The dissociation of hypochlorous acid is:

\(HOCl\) ⇌  \(ClO^- +H^+\)

Therefore, the law of mass action for equilibrium is written as:

\(K_a= \frac{[H^+] [ClO^-]} {[HOCl]} \\\)

At equilibrium \([H^+] \text{and} [ClO^-]\)be x and [HClO] be [0.0200-x]

On substituting the values in given equation we will get:

\(3.00 * 10^{-8}=\frac{[x]*[x]}{[0.0200-x]}\\\\3.00 * 10^{-8}=\frac{x^2}{[0.0200-x]}\\\\x=2.45*10^{-5} M\)

This is also equal to the concentration of H⁺ in the solution. Therefore, the pH turns out:

\(pH= -log[H^+] \\\\pH= -log [2.45 * 10^{-5}]\\\\pH=4.6\)

Hence, the pH of an aqueous solution is 4.6.

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The substance begins to boil at 2750⁰C, the substance begins to melt at 1500⁰C, the temperature at which the substance is both a liquid and a gas at 2750⁰C, temperature is the substance both a solid and a liquid​ at 1500⁰C.

Heating curves are the graphical correlations between heat added to a substance. When viewed from a cooling perspective, ie. loss of heat, it is the cooling curve.

The gradient of the cooling curve is related to the heat capacity, the thermal conductivity of the substance, and the external temperature. The more heat is required to change the temperature of the substance, the slower it cools, so the smaller the gradient of the curve. The higher the thermal conductivity, the faster heat is transferred, so the faster the substance cools.

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Answer: Yo! hope this helps you dude

When ice is placed into a beaker filled with water, the water level does not drop because of the concept of displacement. When the ice is added, it displaces an amount of water equal to its own volume. This means that the ice takes up space in the beaker, pushing out an equal amount of water to make room for itself. Therefore, the total volume of water and ice in the beaker remains the same, and the water level does not drop.

This is due to the fact that the density of ice is lower than that of water and when the ice is placed into the water, it will float on the surface, pushing out an amount of water equal to its own volume.

Additionally, when the ice melts, it will release the same amount of water it displaced before and the water level will not change.

Explanation:

Answer:

One

Explanation:

An element is a pure substance in which there are only one kind of atom. Elements are distinct substances that cannot be split up into simpler substances.

Such substances consists of only one kind of atom. There are over a hundred known elements to date.

Generally, as a pure substance, the composition of an element is definite and they are homogenous in all parts.

Photosynthesis is a chemical reaction in which energy from sunlight is used to convert carbon dioxide and water into glucose and oxygen. This process occurs in the chloroplasts of plant cells and is essential for the survival of plants, as well as for many other organisms that depend on plants for food.

Answer: 67.5

Explanation:

Brainliest pls

Answer:

\(E=2.85\times 10^{-23}\ J\)

Explanation:

Given that,

The frequency of light, \(f=4.3\times 10^{10}\ Hz\)

We need to find the energy of light. The formula for the energy is given by :

\(E=hf\) Where h is Planck's constant

Putting all the values of h and f, we get :

\(E=6.63\times 10^{-34}\times 4.3\times 10^{10}\\\\E=2.85\times 10^{-23}\ J\)

So, the energy of light is \(2.85\times 10^{-23}\ J\).

a. The chemical equation for the electrolysis of water is:

2H2O(l) → 2H2(g) + O2(g)

b. The gas obtained at the anode during the electrolysis of water is oxygen (O2).

c. The volume of gas obtained at the anode is 0.002232 moles or approximately 0.05 L of oxygen gas.

a. The chemical equation for the electrolysis of water is:

2H2O(l) → 2H2(g) + O2(g)

b. The gas obtained at the anode during the electrolysis of water is oxygen (O2).

c. According to the balanced chemical equation, for every 2 moles of water (H2O) electrolyzed, 1 mole of oxygen gas (O2) is obtained. Since 1 mole of any gas occupies 22.4 L at standard temperature and pressure (STP), we can use the stoichiometry of the reaction to determine the volume of oxygen gas produced.

Given that 50 cm³ of gas is obtained at the anode, we need to convert this volume to liters:

50 cm³ = 50/1000 L = 0.05 L

Using the stoichiometric ratio of the balanced equation, we find that 2 moles of water produce 1 mole of oxygen gas. Therefore, 0.05 L of oxygen gas is equivalent to:

0.05 L × (1 mole/22.4 L) = 0.002232 moles

Thus, the volume of gas obtained at the anode is 0.002232 moles or approximately 0.05 L of oxygen gas.

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The number of mole of oxygen needed is of 0.080 mole.

To solve this question, we'll begin by writing the balanced equation for the reaction. This is illustrated below:

From the balanced equation above,

2 moles of O₂ reacted to produce 2 moles of H₂O.

Finally, we shall determine the number of mole of O₂ needed to produce 0.080 mole of H₂O. This can be obtained as follow:

From the balanced equation above,

2 moles of O₂ reacted to produce 2 moles of H₂O.

Therefore,

0.080 mole of O₂ will also react to produce 0.080 mole of H₂O.

Thus, 0.080 mole of oxygen, O₂, is needed for the reaction.

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Answer:

0.916g/mL is the density of the liquid

Explanation:

Density is defined as the mass of a substance in a determined volume (Usually grams per mililiter).

The only difference between the first and second measurements is the volume of the liquid:

19.7mL - 10.2mL = 9.5mL is the difference in volume of the liquid between first and second weighs.

This volume, 9.5mL, weighs:

58.20g - 49.50g = 8.7g

As density is the ratio between mass in grams and volume in mL:

Density: 8.7g / 9.5mL

The molar mass of the sugar is 1350 g/mol.

We define the osmotic pressure as the pressure that needs to be applied to  effect the movement of the solvent across a semi permeable membrane.

Number of moles of the sugar solution = 0.459 g/MM

Where MM = molar mass

We know that the osmotic pressure is obtained from;

π = icRT

i = Van't Hoff factor

c = concentration

R = molar gas constant

T = temperature

Let us obtain the concentration;

c = π/iRT

c =  0.0824 atm/ 1 * 0.082 * 298

c = 0.0034 M

Now;

Concentration = Number of moles/volume

Volume = 100.0 mL or 0.1 L

0.0034 = 0.459/MM/0.1

0.0034 = 0.459/0.1MM

0.0034 * 0.1MM = 0.459

MM = 0.459/ 0.0034 * 0.1

MM = 1350 g/mol

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Answer:

The time required to decompose the substance is 360 seconds.

Answer:

methane

Explanation: methane is obtained from the decaying of flora and fauna mostlyunder damp

We can see here that the catalytic cycle for the hydrogenation of alkenes using Wilkinson's catalyst involves several steps.

Here's an overview of the catalytic cycle, including the necessary details:

i. Chemical structure of the catalyst:

Wilkinson's catalyst, also known as chloridotris(triphenylphosphine)rhodium(I), has the following chemical structure: [RhCl(PPh3)3]

ii. Molecular geometry of the catalyst:

The Wilkinson's catalyst has a trigonal bipyramidal geometry around the rhodium center. The three triphenylphosphine (PPh3) ligands occupy equatorial positions, while the chloride (Cl) ligand occupies an axial position.

iii. Type of reactions involved:

The catalytic cycle involves several reactions, including:

iv. Starting material, reagent, and solvent:

The starting material is an alkene, and the reagent is Wilkinson's catalyst ([RhCl(PPh3)3]). The reaction is typically carried out in a suitable solvent, such as dichloromethane (CH2Cl2) or tetrahydrofuran (THF).

v. Major and minor end-products:

The major end-product of the hydrogenation reaction is the fully saturated alkane, resulting from the addition of hydrogen across the double bond. The minor end-product may include cis- or trans-configured alkanes if the original alkene substrate possesses geometric isomers.

vi. Intermediates:

The intermediates in the catalytic cycle include:

These intermediates play a crucial role in facilitating the hydrogenation reaction and enabling the catalytic cycle to proceed.

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Answer:

Explanation:

The most significant difference between the static and current electricity is that in static electricity the charges are at rest and they are accumulating on the surface of the insulator. Whereas in current electricity the electrons are moving inside the conductor.

We need more information to solve this problem. Specifically, we need to know the volume (or concentration) of HCl used to react with the Mg. Without that information, we cannot determine how many grams of Mg reacted.

Answer:

The amount of water that can be heated by 1,000.0 J of heat energy depends on the mass of water and the specific heat capacity of water.

Assuming the water is at an initial temperature of 20.0°C, we can use the formula:

Q = mcΔT

Where:

Q = heat energy (Joules)

m = mass of water (in grams)

c = specific heat capacity of water (4.184 J/g°C)

ΔT = change in temperature (final temperature - initial temperature)

Rearranging the formula to solve for the mass of water:

m = Q / (c*ΔT)

Plugging in the given values:

m = 1000 J / (4.184 J/g°C * (final temperature - 20.0°C))

Assuming the final temperature is 100.0°C (the boiling point of water at standard pressure), the calculation becomes:

m = 1000 J / (4.184 J/g°C * (100.0°C - 20.0°C))

m = 1000 J / (4.184 J/g°C * 80.0°C)

m = 2.39 grams

Therefore, 1,000.0 J of heat energy can heat 2.39 grams of water from 20.0°C to 100.0°C.

Answer:

Explanation:

Given pinene has a (temperature, vapor pressure) relation (K, torr) = {(373, 135), (429, 760)}, you want the heat of vaporization in kJ/mol and the vapor pressure at room temperature (23 °C).

The Clausius–Clapeyron equation can be used to find the heat of vaporization:

  \(\ln{P}=-\dfrac{\Delta H_{\text{vap}}}{R}\left(\dfrac{1}{T}\right)+C\)

Solving for ∆H, we find ...

  \(\Delta H_{\text{vap}}=-\dfrac{R\cdot\ln{\dfrac{P_1}{P_2}}}{\dfrac{1}{T_1}-\dfrac{1}{T_2}}\\\\\\\Delta H_{\text{vap}}=-\dfrac{8.314\cdot\ln{\dfrac{760}{135}}}{\dfrac{1}{429}-\dfrac{1}{373}}\approx 41052.8\)

The heat of vaporization of pinene is about 41 kJ/mol.

Rearranging the above equation to give P1, we have ...

  \(\ln{\dfrac{P_1}{P_2}}=-\dfrac{\Delta H_\text{vap}}{R}\left(\dfrac{1}{T_1}-\dfrac{1}{T_2}\right) \\\\\\P_1=P_2\cdot e^{-\frac{\Delta H_\text{vap}}{R}\left(T_1^{-1}-T_2^{-1})}\)

Using the same P2 and T2 as above, we find the vapor pressure at room temperature (296.15 K) to be ...

  P1 ≈ 4.349 . . . . . torr

The vapor pressure of pinene at room temperature is about 4 torr.

Answer:

No and Yes

Explanation:

This is both possible and impossible. When you put your mind to what you believe, you can achieve it through patience and minded values. Your mind can either be your Greatest enemy or your Best Ally.

Answer:

1.525834 (1.53 when accounting for significant figures).

Explanation:

This problem relies on the Ideal Gas Law, PV = nRT, where P is pressure, V is volume, n is moles, R is a specific constant, and T is temperature. In this problem, we are solving for n, moles, so we would rewrite it as n = PV/RT. Since the units here are moles, liters, atmospheres, and kelvin, R would be the value in atmosphere liter per mole kelvin, or 0.0821. From here, you just enter the values in the fraction and calculate.

For the significant figures, I followed the measurement of 34.2 L, giving 3, although an argument could be made for 1 significant figure from 1 atm, I imagine your professor would want something more specific than 2.

The total mass of the balloon and its content is 1521.17 g, the number of moles of CO₂ in the balloon is 34.15 mol, and the number of CO₂ molecules in the balloon is 2.06 x 10²⁵ molecules.

a) The molar mass of CO₂ is 44.01 g/mol. To find the total mass of the balloon and its content, we need to add the mass of the balloon (20g) to the mass of the CO₂ inside the balloon.

Mass of CO₂ = number of moles of CO₂ x molar mass of CO₂

Since the balloon is at STP (standard temperature and pressure), we can use the molar volume of a gas at STP (22.4 L/mol) to find the number of moles of CO₂ in the balloon:

Volume of CO₂ = Volume of balloon = 765 L (at STP)

Number of moles of CO₂ = volume of CO₂ / molar volume of a gas at STP

                                          = 765 L / 22.4 L/mol

                                          = 34.15 mol

Mass of CO₂ = 34.15 mol x 44.01 g/mol

                       = 1501.17 g

Total mass of balloon and its content = 20 g + 1501.17 g

                                                               = 1521.17 g

b) Number of moles of CO₂ in the balloon is 34.15 mol

c) To find the number of CO₂ molecules in the balloon, we need to use Avogadro's number (6.02 x 10²³ molecules/mol).

Number of CO₂ molecules = number of moles of CO₂ x Avogadro's number

                                           = 34.15 mol x 6.02 x 10²³ molecules/mol

                                           = 2.06 x 10²⁵ molecules

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Answer:

+3

Explanation:

NH₄F

=> N + 4H + F = 0

=> N + 4(+1) + 1(-7) = 0

=> N = 7 - 4 = +3

Temperature to reach the pressure : 2657 °C

Gay Lussac's Law  

When the volume is not changed, the gas pressure is proportional to its absolute temperature  

\(\tt \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}\)

P₁=605 torr

T₁=20 + 273 = 293 K

P₂=6050 torr

\(\tt T_2=\dfrac{T_i\times P_2}{P_1}\\\\T_2=\dfrac{293\times 6050}{605}\\\\T_2=2930~K=2657~^oC\)

The solubility of a substance tells us the amount of solute that is capable of dissolving a given amount of solvent at a given temperature. We speak that a solution is.

Now, if the amount is less than the statement says, it will be an unsaturated solution.

When the amount is greater, the solution is supersaturated and a precipitate of solute will form in the solution.

According to what has been explained, the solution described by the statement is an unsaturated solution.

Answer: Unsaturated

Answer:

\(\frac{P_{solution}}{P_{solvent}^{vap}} =0.75\)

Explanation:

Hello there!

In this case, since the solvation of a nonvolatile-nondissociating solute in a volatile solvent is modelled via the Raoult's law:

\(P_{solution}=x_{solvent}P_{solvent}^{vap}\)

Thus, we can calculate the ratio of the vapor pressure of the solution to that of the pure solvent, mole fraction, as shown below:

\(x_{solvent}=\frac{P_{solution}}{P_{solvent}^{vap}} =\frac{n_{solvent}}{n_{solute}+n_{solvent}}\)

Thus, we plug in the moles of solvent and solute to obtain:

\(\frac{P_{solution}}{P_{solvent}^{vap}} =\frac{3}{3+1}\\\\ \frac{P_{solution}}{P_{solvent}^{vap}} =0.75\)

Regards!

When these ions are created, they enter the solution and have the ability to conduct charge by travelling anticlockwise to the circuit's electrons.

Because their ions were free to move around, ionic substances conduct electricity if they are molten (liquid) or even in aqueous (dissolved in water). Ions in ionic compounds are maintained in fixed locations and are unable to move, therefore they cannot conduct electricity while solid.

Ions are all charged. As a result, anions travel in the direction of positively charged electrode whereas ions with positive charges move in the opposite direction. The charge moves together with the motion of the ions. Current is created by this charge movement

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