Option fourth "The functions are not inverses because, for each ordered pair (x, y) for one function, there is no corresponding ordered pair (y, x) for the other function." is correct.
What is a function?It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
We have two tables shown in the picture.
Table (A) have values of x and a(x)
Table (B) have values of d and r(d)
As we know if the function has an inverse of it and (x, y) satisfies the function then (y, x) must satisfy the inverse of a function.
Thus, the option fourth "The functions are not inverses because, for each ordered pair (x, y) for one function, there is no corresponding ordered pair (y, x) for the other function." is correct.
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square root 2x-7 = 1
Answer:
4
Step-by-step explanation:
To solve for x in the equation:
√(2x - 7) = 1
We can start by isolating the square root by squaring both sides of the equation:
(√(2x - 7))^2 = 1^2
2x - 7 = 1
Next, we can isolate the variable by adding 7 to both sides of the equation:
2x = 8
Finally, we can solve for x by dividing both sides by 2:
x = 4
Therefore, the solution to the equation √(2x - 7) = 1 is x = 4.
what does it mean when the second derivative equals zero
When the second derivative of a function equals zero, it indicates a possible point of inflection or a critical point where the concavity of the function changes. It is a significant point in the analysis of the function's behavior.
The second derivative of a function measures the rate at which the slope of the function is changing. When the second derivative equals zero at a particular point, it suggests that the function's curvature may change at that point. This means that the function may transition from being concave upward to concave downward, or vice versa.
Mathematically, if the second derivative is zero at a specific point, it is an indication that the function has a possible point of inflection or a critical point. At this point, the function may exhibit a change in concavity or the slope of the tangent line.
Studying the second derivative helps in understanding the overall shape and behavior of a function. It provides insights into the concavity, inflection points, and critical points, which are crucial in calculus and optimization problems.
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When the second derivative of a function equals zero, it indicates a critical point in the function, which can be a maximum, minimum, or an inflection point.
The second derivative of a function measures the rate at which the slope of the function is changing. When the second derivative equals zero, it indicates a critical point in the function. A critical point is a point where the function may have a maximum, minimum, or an inflection point.
To determine the nature of the critical point, further analysis is required. One method is to use the first derivative test. The first derivative test involves examining the sign of the first derivative on either side of the critical point. If the first derivative changes from positive to negative, the critical point is a local maximum. If the first derivative changes from negative to positive, the critical point is a local minimum.
Another method is to use the second derivative test. The second derivative test involves evaluating the sign of the second derivative at the critical point. If the second derivative is positive, the critical point is a local minimum. If the second derivative is negative, the critical point is a local maximum. If the second derivative is zero or undefined, the test is inconclusive.
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let be an integral domain with a descending chain of ideals . suppose that there exists an such that for all . a ring satisfying this condition is said to satisfy the descending chain condition, or dcc. rings satisfying the dcc are called artinian rings, after emil artin. show that if satisfies the descending chain condition, it must satisfy the ascending chain condition.
As before, it follows that A3 is a maximal ideal of R, contradicting the fact that the chain is infinite. Therefore, R satisfies the ACC.
It is given that be an integral domain with a descending chain of ideals. Suppose that there exists an n such that for all i ≥ n, then ai = an. A ring satisfying this condition is said to satisfy the descending chain condition or DCC. Rings satisfying the DCC are called Artinian rings, after Emil Artin.
The statement to be proved is if R satisfies the descending chain condition, it must satisfy the ascending chain condition. Suppose, by contradiction, that R satisfies the DCC but does not satisfy the ACC. Then, there is an infinite ascending chain: A1 ⊂ A2 ⊂ A3 ⊂ A4 ⊂ ···.
Note that if R is an integral domain and if a ∈ R, then (a) is either (0) or is a maximal ideal in R. Hence, (0) is a minimal element in the collection of all proper ideals of R. Suppose A1 is a proper ideal of R that is maximal with respect to not being finitely generated. Since R satisfies the DCC, A1 cannot be infinite. Therefore, A1 is a finite set. Suppose A1 is not principal.
Then there exist two elements a, b ∈ A1 that do not belong to (a) and (b) respectively. This means that (a, b) is a proper ideal of R, properly containing A1, which contradicts the maximality of A1. Thus, A1 is a principal ideal generated by an element a1 ∈ A1.Suppose A2 = (a1, a2, a3, · · · , am) is a proper ideal properly containing A1. If A2 is finitely generated, then A2 ⊃ (a1) ⊃ (0) is a finite descending chain of ideals, which contradicts the DCC.
Thus, A2 is not finitely generated. By the maximality of A1, A2 must be principal, generated by an element a2 ∈ A2. It follows that a2 = c1a1 + c2a2 + · · · + cmam, where ci ∈ R for all i. Hence, (1 − c2)a2 = c1a1 + · · · + cmam, which means that a2 ∈ (a1). Therefore, (a1) = A1 = A2, and it follows that A2 is a maximal ideal of R.
Suppose A3 is a proper ideal properly containing A2. If A3 is finitely generated, then A3 ⊃ A2 ⊃ (0) is a finite ascending chain of ideals, which contradicts the ACC. Thus, A3 is not finitely generated. By the maximality of A2, A3 must be principal, generated by an element a3 ∈ A3.
As before, it follows that A3 is a maximal ideal of R, contradicting the fact that the chain is infinite. Therefore, R satisfies the ACC.
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Find the average runtime complexity of binary search
procedure binary search (x: integer, a1,a2,..., an: increasing integers)
i := 1 {i is the left endpoint of interval}
j := n {j is right endpoint of interval}
while i < j
m := ⌊(i + j)/2⌋
if x > am then i := m + 1
else j := m
if x = ai then location := i
else location := 0
return location
Binary search has an average runtime complexity of O(log n). It repeatedly divides the search interval in half, efficiently reducing the search space and quickly finding the target element.
The binary search algorithm has an average runtime complexity of O(log n), where n is the number of elements in the input array. The algorithm starts by setting the left and right endpoints of the search interval. It repeatedly divides the interval in half and compares the middle element with the target value.
If the target value is greater than the middle element, the left endpoint is updated to be one position after the middle element. Otherwise, if the target value is less than or equal to the middle element, the right endpoint is updated to be the middle element. This process continues until the left endpoint becomes equal to or greater than the right endpoint.The algorithm terminates by checking if the target value is equal to the element at the left endpoint. If it is, the location of the target is returned; otherwise, the location is set to 0, indicating that the target was not found. This process efficiently reduces the search space by half at each iteration, resulting in the logarithmic time complexity.
Therefore, Binary search has an average runtime complexity of O(log n). It repeatedly divides the search interval in half, efficiently reducing the search space and quickly finding the target element.
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1) Louis is dilating triangle ABC at right. He
multiplied each x-coordinate and y-coordinate of
triangle ABC by -2.
a. What are the new coordinates of the points?
To find the new coordinates of the points after Louis multiplied each x-coordinate and y-coordinate of triangle ABC by -2, we can use the following formulas:
New x-coordinate = -2 * old x-coordinate
New y-coordinate = -2 * old y-coordinate
Let's apply these formulas to each point in triangle ABC:
Point A: (-3, 4)
New x-coordinate of A = -2 * (-3) = 6
New y-coordinate of A = -2 * 4 = -8
New coordinates of A: (6, -8)
Point B: (1, 1)
New x-coordinate of B = -2 * 1 = -2
New y-coordinate of B = -2 * 1 = -2
New coordinates of B: (-2, -2)
Point C: (5, -2)
New x-coordinate of C = -2 * 5 = -10
New y-coordinate of C = -2 * (-2) = 4
New coordinates of C: (-10, 4)
Therefore, the new coordinates of the points after Louis multiplied each x-coordinate and y-coordinate of triangle ABC by -2 are:
A: (6, -8)
B: (-2, -2)
C: (-10, 4)
The monthly profit of an artist co-op store if she were equally on the 13 orders if the profit one month is 3849 which is the best estimate of each owner share
Answer:
The best estimate of each owner share is 296
Step-by-step explanation:
Now, we know that that the profit was shared equally and we have 13 recipients of the share
The best estimate for each owner’s share is to divide the amount shared in the month by the number of the recipients
That would be 3,849/13 = 296.08
This is best estimated as 296
1-A student studies math for 1 5/7 hours and science for 3 1/19 hours over the weekend. How much time, in hours, did this student study for math and science altogether?
2-A metal alloy is made by mixing 99/17 ounce of Metal A with with 3/11 pound of Metal B. What is the total weight of the alloy in pounds?
3-A baker mixes 3.1 ounces of butter with 227.6 grams of flour. What is the total weight of the mixture in grams?
4-A carpet cleaner charges $0.99 per square foot to clean carpet. In the next house he is going to clean, the client reveals a perfectly circular carpeted room. If the room measures 45 feet in diameter, how much will he charge?
Answer:
1. \(4\frac{102}{133}\)
2. \(6\frac{18}{187}\)
3. 230.7
4. $1,574.53
good luck, i hope this helps :)
4•(2+5)^2 -5^2 how do I solve this?
Answer:
4•(2+5)^2 -5^2 = 171
Step-by-step explanation:
Do BIDMAS
(brackets, indices, division, multipy, add, sub)
so brackets
4*7^2-5^2
then do the indices
4*49-25
then the multiply
196-25
= 171
Hope this helps
Answer: Brackets => 4 x (7)^2 - 5^2
Indices/Orders => 4 x 49 - 25
Multiplication => 196 - 25
Subtraction => 171
Mark buys a wooden board that is feet long. The cost of the board is $1.50 per 5 1/4 foot, including tax. What is the total cost, in dollars, of Mark’s board
A pole 6 feet tall is used to support a guy wire for a tower, which runs from the tower to a metal stake in the ground. After placing the pole, Ian measures the distance from the pole to the stake and from the pole to the tower, as shown in the diagram below. Find the length of the guy wire, to the nearest foot.
The length of the guy wire will be 34.24 feet.
What is trigonometry?The branch of mathematics that sets up a relationship between the sides and the angles of the right-angle triangle is termed trigonometry.
The trigonometric functions, also known as circular, angle, or goniometric functions in mathematics, are real functions that link the angle of a right-angled triangle to the ratios of its two side lengths.
Given that the height of the pole is 6ft. The distance of the pole from the tower is 15ft and the distance of the pole from the guy wire end is 4 ft.
The length of the guy wire will be calculated as:-
First, we will calculate the angle of the guy wire,
tanθ = 6 / 4
θ = tan⁻¹(6/4)
θ = 56.3°
Now the length of the guy wire will be,
cosθ = Base / Hypotenuse
cosθ = ( 19 ) / ( L )
L = 19 / cos(56.3)
L = 34.24 ft
Therefore, the length of the guy wire will be 34.24 feet.
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Since 1950, the growth in the world population in millions closely fits the exponential function A(t) = 26000.018t, where t is the number of years since 1950. Estimate the population in the year 2018 to the nearest million.
Answer:
vhvjh648585869786
Step-by-step explanation:
A home has a rectangular kitchen. If listed as ordered pairs, the corners of the kitchen are (8, 4), (−3, 4), (8, −8), and (−3, −8). What is the area of the kitchen in square feet?
20 ft2
46 ft2
132 ft2
144 ft2
If the corners of the kitchen are (8, 4), (−3, 4), (8, −8), and (−3, −8), the area of the kitchen is 132 square feet. So, the correct option is C.
To find the area of the rectangular kitchen, we need to use the formula for the area of a rectangle, which is A = L x W, where A is the area, L is the length, and W is the width.
From the given ordered pairs, we can determine the length and width of the rectangle. The length is the distance between the points (8,4) and (-3,4), which is 8 - (-3) = 11 feet. The width is the distance between the points (8,4) and (8,-8), which is 4 - (-8) = 12 feet.
Now that we know the length and width, we can find the area by multiplying them together:
A = L x W = 11 x 12 = 132 square feet
Therefore, the correct answer is C.
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Answer C. 132 fT2
Step-by-step explanation:
In an accounting class of 200 students, the mean and standard deviation of scores was 70 and 5, respectively. Use the empirical rule to determine the number of students who scored less than 65 or more than 75.
Approximately 64 students in the accounting class scored less than 65 or more than 75.
To solve this, we'll use the Empirical Rule, which states that for a normal distribution:
1. Approximately 68% of the data falls within one standard deviation of the mean.
2. Approximately 95% of the data falls within two standard deviations of the mean.
3. Approximately 99.7% of the data falls within three standard deviations of the mean.
In your accounting class, the mean score is 70, and the standard deviation is 5. We want to find the number of students who scored less than 65 (one standard deviation below the mean) or more than 75 (one standard deviation above the mean).
Using the Empirical Rule, we know that about 68% of students scored between 65 and 75 (within one standard deviation of the mean). Therefore, the remaining 32% of students scored either less than 65 or more than 75.
Since there are 200 students in the class, we can calculate the number of students who scored less than 65 or more than 75:
0.32 * 200 = 64 students
So, approximately 64 students in the accounting class scored less than 65 or more than 75.
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Suppose that a, b, c, d are positive real numbers such that a/b < c/d . What can you say about the fraction (a+c)/(b+d) ? Is it always, sometimes, or never between the fractions a/b and c/d ? Provide evidence of your claim. (If always or never, give an algebraic proof, otherwise, give two quadruples values of a, b, c, d in which one quadruple has (a+c)/(b+d) between a/b and c/d and the other does not.)
Answer: (a−c)(b−c)>0
Step-by-step explanation:
ab>1 and ac<01. a>0 if c<0 and also b>02. a<0 if c>0 and also b<0
how i did it:
At the vert first, write the inequality as an equation.
Solve the provided equation for one or more values.
Now, display all the values obtained in the number line.
Use open circles to show the excluded values on the number line.
Find the interim.
At the moment, take any random value from the interval and substitute it in the inequality equation to check whether the values reassure the inequality equation.
Intervals that reassure the inequality equation are the solutions of the given inequality equation.
en una granja hay comida para alimentar a 300 conejos durante 60 días. Cuántos conejos hay que vender si se quieren alimentar durante 15 días más?
The number of rabbits that must be sold if they want to be fed for 15 more days is 150 rabbits.
In a farm, there is food to feed 300 rabbits for 60 days.
Let x be the number of rabbits that must be sold if they want to be fed for 15 more days.
From the given data, we have the following equation:
300 * 60 = (300 - x) * 75
The equation represents the amount of food for 300 rabbits that can last 60 days is equal to the amount of food for 300 - x rabbits that can last 75 days.
Solving for x, we get:
x = 150 rabbits
Hence, the number of rabbits that must be sold if they want to be fed for 15 more days is 150 rabbits.
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How to solve this plsssss
Answer:
Hope this helps you
Answered by G a u t h m a t h
PLS HELP URGENT!!!
.
.
.
.
.
.
.
Answer:
D.
Step-by-step explanation:
Answer: D is the correct answer
Step-by-step explanation:
I learned this last year and got a 100 on the subject
Please help me I don’t understand this!
Okay, I'm going to assume that the part you're confused about is the part about how to use the number line to get the answer since the answer is given to you (it's -3).
So what you want to do is plot a point on -7. Since the line ends at -5, extend the line by drawing 2 vertical lines about to represent -6 and -7 (if you're reading it from left to right the -7 would come before -6 because it is a smaller value). Then you would want to hop 4 lines to the right, starting on -7. You would land on -3 which is the answer.
What is the slope of the line on the graph?
i’ll give brainliest
Step-by-step explanation:
The area of triangle is 13.5
A=1/2bh
=1/2*3inc*9inc
=13.5inc^2
the first step in developing a competency model is:
The first step in developing a competency-model is to gather background information and analyze the existing standards within the workplace.
The first-step involves conducting a thorough examination of the organization's goals, strategies, and the specific job roles or positions for which the competency-model will be developed.
By gathering background information, organizations can understand the context in which the competency-model will be applied.
Analyzing existing standards within the workplace involves assessing the current performance expectations, competencies, and criteria used for evaluating employees in their respective roles.
The purpose of this step is to identify any gaps or areas for improvement in the existing standards and to ensure that the development of the competency model aligns with the organization's overall objectives.
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The first step in developing a competency model is conducting a job analysis.
developing a competency model is a systematic process that helps organizations define the key competencies needed for their employees. The first step in this process is conducting a job analysis.
A job analysis involves gathering information about the job, such as its purpose, tasks, responsibilities, and required qualifications. This information can be collected through methods like interviews, observations, and surveys. By analyzing the job, organizations can identify the critical competencies that are necessary for effective job performance.
These competencies can then be used to guide various HR processes, including recruitment, selection, training, and performance management. By aligning the competencies with job requirements, organizations can ensure that they have the right people with the right skills in the right positions.
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a frosting machine can fill 60 jars of chocolate frosting in 3 minutes how many jars can it fill in one hour
Answer:
120
Step-by-step explanation:
60:3=20
1 minute - 20
20×60=120
Answer:
60÷3=20 each minute
60 min in hour so,
20×60=1200 jars in an hour
Answer is 1200
Help plssss and thank you
Answer:
\(y=\frac{1}{4}x +3\)
Step-by-step explanation:
slope (rise over run) choose 2 points that are easy to figure out. Count up and over to get the slope
(0,3) and (4,4)
3 to 4 is 1
0 to 4 is 4
slope is 1/4
y intercept is b- so +3
y=\(y=\frac{1}{4} x+3\)
help me pleasee, my brain won't work
The given fractions have equal value, so Liam is correct.
How to find the equivalent fractions?Equivalent fractions are defined as fractions that have different numerators and denominators but the same value. For example, 2/4 and 3/6 are equivalent fractions because they are both equal to 1/2. A fraction is part of a whole. Equivalent fractions represent the same part of a whole.
Liam is claiming that the fraction -(5/12) is equivalent to 5/-12.
Thus, we can say that:
The fraction -(5/12) can be described as the opposite of a positive number divided by a positive number. A positive number divided by a positive number always results in a positive quotient and its' opposite is always negative.
The fraction 5/-12 can be described as a positive number divided by a negative number which always results in a negative quotient
The fractions have equal value, so Liam is correct
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factoring trinomials with a leading coefficient. ac method
10p^2-p-2
The factored trinomial expression is (5p + 2)(2p - 1)
How to factor the trinomial expressionFrom the question, we have the following parameters that can be used in our computation:
10p^2-p-2
To factor the trinomial 10p^2 - p - 2, we can use the method of finding two numbers that multiply to -20p^2 and add to -p.
We can use these numbers to write the trinomial as a product of two binomials:
So, we have
10p^2 - p - 2 = 10p^2 - 5p + 4p - 2
Factorize
10p^2 - p - 2 = 5p(2p - 1) + 2(2p - 1)
This gives
10p^2 - p - 2 = (5p + 2)(2p - 1)
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help pls i am comfused
A chord consists of notes that sound good together. The C major chord starting at middle C has the following frequencies: C - 262 Hz E - 330 Hz G - 392 Hz determine the ratio of the frequency of E to C. Express the answer in a simple integer ratio. How many E waves will fit in the length of four C waves. a. 2 b. 3
Answer:
The frequency of note E is:
f(E) = 330 Hz
The frequency of note C is:
f(C) = 262 Hz
The ratio of the frequency of note E to the frequency of note C is just the quotient of these two frequencies:
r = f(E)/f(C) = 330Hz/262Hz = 330/262 = 1.26
Now, we want to find how man E waves will fit in the length of four C waves.
Note that here the word "length" is used, so we need to work with the wavelengths, not with the frequencies.
For waves, we have the relationship:
v = f*λ
where:
v = velocity (in this case, velocity of the sound = 343 m/s)
f = frequency
λ = wavelength.
So, the length of a single E wave is:
λ(E) = (343 m/s)/(330 1/s) = 1.04 m
And the length of a single C note is:
λ(C) = (343 m/s)/(262 1/s) = 1.30 m
In four C waves, the length is:
4*λ(C) = 4*1.30m = 5.2m
The number of E waves that fit in the length of four C waves is equal to the quotient between the length of four C waves and one E wave:
N = (4*λ(C))/(λ(E) ) = (5.2 m)/(1.04m) = 5.14
So we can fit 5 E waves into four C waves.
Answer:
The ratio of the frequency of E to C can be found by dividing the frequency of E by the frequency of C:
330 Hz / 262 Hz ≈ 1.26
To express the answer in a simple integer ratio, we can divide both 330 Hz and 262 Hz by their greatest common factor, which is 2:
330 Hz / 2 = 165 Hz
262 Hz / 2 = 131 Hz
So the ratio of the frequency of E to C is:
165 Hz / 131 Hz = 15/12 ≈ 1.25
This ratio is approximately equal to 5/4
Therefore, the answer is (A) 5 to 4
The state of a spin 1/2 particle in Sx basis is defined as (Ψ) = c+l + x) + i/√7 l - x) a) Find the amplitude c+ assuming that it is a real number and the state vector is properly defined. b) Find the expectation value . c) Find the uncertainty △SX.
1) The amplitude c+ is c+l
2) The expectation value is 0
3) The uncertainty ΔSX is √(3/7) c+.
Now, we know that any wave function can be written as a linear combination of two spin states (up and down), which can be written as:
Ψ = c+ |+> + c- |->
where c+ and c- are complex constants, and |+> and |-> are the two orthogonal spin states such that Sx|+> = +1/2|+> and Sx|-> = -1/2|->.
Hence, we can write the given wave function as:Ψ = c+|+> + i/√7|->
Now, we know that the given wave function has been defined in Sx basis, and not in the basis of |+> and |->.
Therefore, we need to write |+> and |-> in terms of |l> and |r> (where |l> and |r> are two orthogonal spin states such that Sy|l> = i/2|l> and Sy|r> = -i/2|r>).
Now, |+> can be written as:|+> = 1/√2(|l> + |r>)
Similarly, |-> can be written as:|-> = 1/√2(|l> - |r>)
Therefore, the given wave function can be written as:Ψ = (c+/√2)(|l> + |r>) + i/(√7√2)(|l> - |r>)
Therefore, we can write:c+|l> + i/(√7)|r> = (c+/√2)|+> + i/(√7√2)|->
Comparing the coefficients of |+> and |-> on both sides of the above equation, we get:
c+/√2 = c+l/√2 + i/(√7√2)
Therefore, c+ = c+l
The amplitude c+ is a real number and is equal to c+l
The expectation value of the operator Sx is given by: = <Ψ|Sx|Ψ>
Now, Sx|l> = 1/2|r> and Sx|r> = -1/2|l>
Hence, = (c+l*) + (c+l) + (i/√7) - (i/√7)(c+l*)= -i/√7(c+l*) + i/√7(c+l)= 2i/√7 Im(c+)
As c+ is a real number, Im(c+) = 0
Therefore, = 0
The uncertainty ΔSX in the state |Ψ> is given by:
ΔSX = √( - 2)
where = <Ψ|Sx2|Ψ>and2 = (<Ψ|Sx|Ψ>)2
Now, Sx2|l> = 1/4|l> and Sx2|r> = 1/4|r>
Hence, = (c+l*) + (c+l) + (i/√7) - (i/√7)(c+l*)= 1/4(c+l* + c+l) + 1/4(c+l + c+l*) + i/(2√7)(c+l* - c+l) - i/(2√7)(c+l - c+l*)= = 1/4(c+l + c+l*)
Now,2 = (2i/√7)2= 4/7ΔSX = √( - 2)= √(1/4(c+l + c+l*) - 4/7)= √(3/14(c+l + c+l*))= √(3/14 * 2c+)= √(3/7) c+
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a first order reaction goes to half completion in 79 hours. what is the rate constant for this reaction? a) 7.9 × 10–3 h–1 b) 8.77 × 10–3 h–1 c) 79 h d) 39.5 h
The rate of constant for the above-given first-order reaction is b.) 8.77 × 10–3 h–1.
The half-life of a first-order reaction can be calculated using the equation t1/2 = ln(2)/k, where t1/2 is the half-life and k is the rate constant.
In this case, we know that the reaction goes to half completion in 79 hours. Therefore, the half-life is also 79 hours.
Plugging this into the equation, we get:
79 = ln(2)/k
Solving for k, we get:
k = ln(2)/79
Using a calculator, we can evaluate this expression to get:
k = 8.77 × 10–3 h–1
Therefore, the correct answer is b) 8.77 × 10–3 h–1.
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Un ciclista tarda 3horas y 25 minutos en recorrer 150km ¿cuantos minutos tardará en recorrer 238km si lleva una velocidad constante?
Answer :
The time it will take to travel a distance of 225km is t = 9 h
What is MRU?
MRU are the acronyms that define the uniform rectilinear movement which is the movement that maintains a variation of the distance with respect to time always constant since the acceleration is null.
We will calculate the speed you have in cyclist with the initial data of traveling a distance of 125km in a time of 5 hours:
Speed = distance / time
Speed = 125km/5h
Speed = 25 km/h
We now determine a time for a 225km course
25 km/h = 225km/t
t = 225km / 25km/h
t = 9 h