Consider the reaction below for the following question. 2Na + H2O= Na2O + H2
a. If you start with 25.0 g of sodium and 45.5 g of water how many grams of Sodium Hydroxide will be produced. Show all work please. Thank You!

Answer:

1- Product of powers rule.

2- Quotient of powers rule.

3- Power of a power rule.

4- Power of a product rule.

5- Power of a quotient rule.

6- Zero power rule.

7- Negative exponent rule.

Step-by-step explanation:

Hope I helped! ^v^

Answer:

5/12

Step-by-step explanation:

5/6/2

skip flip multiply

5/6*1/2

5/12

hopes this helps

Answer:

\(\frac{5}{12}\)

Step-by-step explanation:

\(\frac{5/6}{2}=\frac{5}{6 \cdot 2}=\frac{5}{12}\)

Answer:

Let's say x is the number of quarters. Then the number of nickels is x + 3.

The total value of the quarters is 0.25x, and the total value of the nickels is 0.05(x + 3).

The total value of both types of coins is 4.35:

0.25x + 0.05(x + 3) = 4.35

0.25x + 0.05x + 0.15 = 4.35

0.3x + 0.15 = 4.35

0.3x = 4.2

x = 14

So Sofia has 14 quarters and 17 nickels.

Answer:

.25q + .05(q - 3) = 4.35

Step-by-step explanation:

Let q = the number of quarters

Let n = the number of nickels

.25q + .05n = 4.35

n = q- 3

Substitute q - 3 for n

.25q + .05(q - 3) = 4.35

Answer:

Answer in explanation

Step-by-step explanation:

Part A

Addition will result in the greatest solution

The reason why multiplication will not result in this case is because 0.86 is less than 1. So the result we will get by multiplying will be less than what we have from addition

Part B

Yes there is

By dividing the first term by the scribe term, we shall get a number that is greater than the result we would have obtained if we added or multiplied

Answer:

If a function repeats over at a constant period we can call it a periodic function. According to periodic function definition the period of a function is represented like f(x) = f(x + p), p is equal to the real number and this is the period of the given function f(x). Period can be defined as the time interval between the two occurrences of the wave.

Step-by-step explanation:

please tell me if im incorrect, i'll fix it asap.

The equation of the graph in the figure is f(x) = |x - 3| + 5

Given that the graph is an absolute value graph

We start by calculating the vertex of the graph

In this case, the graph has it minimum point located at the coordinate (3, 5)

This coordinate can then be interpreted as

(h, k) = (3, 5)

As a general rule, the general representation of the equation of an absolute value function is f(x) = |x - h| + k

Substitute the known values in the above equation

So, we have the following equation

f(x) = |x - 3| + 5

Hence, the equation of the graph is f(x) = |x - 3| + 5

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Answer:

abc- 130

ebd-130

abe-50

Step-by-step explanation:

Answer:

35,887.1 because 38300×93.7 ➗ 100

Given:

The expression is:

\(\left(\dfrac{1}{7}-4\sqrt{3}\right)^3+\left(\dfrac{1}{7}+4\sqrt{3}\right)^3 \)

To find:

The simplified form of the given expression.

Solution:

Formulae used:

\((a-b)^3=a^3-3a^2b+3ab^2-b^3\)

\((a-b)^3=a^3+3a^2b+3ab^2+b^3\)

Adding this formulae, we get

\((a-b)^3+(a+b)^3=2a^3+6ab^2\)            ...(i)

We have,

\(\left(\dfrac{1}{7}-4\sqrt{3}\right)^3+\left(\dfrac{1}{7}+4\sqrt{3}\right)^3 \)

Using formula (i), the given expression can be written as:

\(=2\left(\dfrac{1}{7}\right)^3+6\left(\dfrac{1}{7}\right)\left(4\sqrt{3}\right)^2\)

\(=2\times \dfrac{1}{343}+6\left(\dfrac{1}{7}\right)48\)

\(=\dfrac{2}{343}+\dfrac{288}{7}\)

\(=\dfrac{2+14112}{343}\)

\(=\dfrac{14114}{343}\)

Therefore, the simplified form of the given expression is \(\dfrac{14114}{343}\).

Answer:

A vector graphic consists of a set of instructions for creating a picture is a true statement.

Step-by-step explanation:

A vector graphic is an image format that represents images as a set of mathematical instructions or geometric primitives such as lines, curves, and shapes. Instead of using a grid of pixels like raster graphics, vector graphics define images based on mathematical formulas and coordinates.

These instructions or mathematical representations describe the shapes, colors, and other visual attributes of the image. They allow the image to be scaled, resized, and manipulated without loss of quality since the instructions can be recalculated and redrawn at any resolution or size.

Vector graphics are often created and edited using specialized software such as Adobe Illustrator, CorelDRAW, or Inkscape. They are commonly used for logos, illustrations, diagrams, typography, and other graphical elements where scalability and flexibility are important.

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Hello !

\(3x + 4 = 2x - 1\\\\3x - 2x = -1 - 4\\\\x = -5\)

x = -5

Answer:

\(\sf{x=-5}\)

Step-by-step explanation:

Let's solve this equation.

Our equation is:

\(\sf{3x+4=2x-1}\)

Rearrange the terms

\(\sf{3x-2x+4=1}\)

\(\sf{3x-2x=-1-4}\)

Combine

\(\sf{x=-5}\)

Therefore, x = -5

The probability that a given class period runs between 50.5 and 51.25 minutes is 15%.

Probability defines the likelihood of occurrence of an event. There are many real-life situations in which we may have to predict the outcome of an event. We may be sure or not sure of the results of an event. In such cases, we say that there is a probability of this event to occur or not occur. Probability generally has great applications in games, in business to make probability-based predictions, and also probability has extensive applications in this new area of artificial intelligence.

The probability of an event can be calculated by probability formula by simply dividing the favorable number of outcomes by the total number of possible outcomes. The value of the probability of an event to happen can lie between 0 and 1 because the favorable number of outcomes can never cross the total number of outcomes. Also, the favorable number of outcomes cannot be negative.

\(P(50.5 < = X < = 51.25) =\frac{51.25-50.5}{54-49 } = \frac{0.75}{5} = 0.15\)

P = 0.15 means that the probability is 15%.

Thus, the probability that a given class period runs between 50.5 and 51.25 minutes is 15%.

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Answer:

Not all the means are equal.

Step-by-step explanation:

In an ANOVA table, a sum of squares for the independent variable divided by its respective degrees of freedom.

So if the omnibus null hypothesis is rejected it means that there is sufficient evidence to conclude that not all the means are equal.

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If the omnibus null hypothesis is rejected in a one-factor ANOVA, then, we can conclude that at least one of the population means is different from at least one other population mean.

ANOVA table gives us the total sum of squares ( TSS ), the residual sum of squares ( RSS ) and the estimated sum of squares ( ESS ).

It establishes the relation that:

ESS + RSS = TSS.

If we reject the omnibus null hypothesis, then it means that:

at least one of the population means is different from at least one other population mean.

Therefore, we get that, if the omnibus null hypothesis is rejected in a one-factor ANOVA, then, we can conclude that at least one of the population means is different from at least one other population mean.

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Answer:

Almost 8 times greater

Step-by-step explanation:

113.1 is the original volume if you double both dimensions the new volume is 904.78

Answer:

sikeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Step-by-step explanation:

Answer:

u r girl

khdlhdohdkhdohdohdlgdogdkgdkgdkgskgdkgskgskydoysoydoydoydoydoydlydoydoydoydpydoydpyd

Answer:

20 years

Step-by-step explanation:

We start by writing an exponential equation;

FV = PV( 1 + r)^t

FV is the future value = 1,000,000

PV is present value = 372,000

r is rate = 5% = 5/100 = 0.05

t is time which we are looking for

1,000,000 = 372,000(1 + 0.05)^t

1.05^t = 1,000,000/372,000

1.05^t = 2.688

t ln 1.05 = ln 2.688

t = ln 2.688/ln 1.05

t = 20 years

Answer:

12 units

Step-by-step explanation:

1st, I found the distance for the two parallel sides on the hexagon. I counted the lines to be 2 units each, which makes 4 units. And since all sides of a hexagon are equal. All the sides make 12 units, or centimeters. Therefore, the perimeter is 12 units

The shortest distance between the skew lines with parametric equations is |−74s/17 + 23/17|.

To find the distance between the skew lines, we need to find the shortest distance between any two points on the two lines. Let P be a point on the first line with coordinates (1t, 36t, 2t) and let Q be a point on the second line with coordinates (12s, 414s, −35s).

Let's call the vector connecting these two points as v:

v = PQ = <1−2s, 3−10s, 2+5s>

Now we need to find a vector that is orthogonal (perpendicular) to both lines. To do this, we can take the cross product of the direction vectors of the two lines.

The direction vector of the first line is <1, 6, 0> and the direction vector of the second line is <2, 14, −5>. So,

d = <1, 6, 0> × <2, 14, −5>

d = <−84, 5, 14>

We can normalize d to get a unit vector in the direction of d:

u = d / ||d|| = <−84/85, 5/85, 14/85>

Finally, we can find the distance between the two lines by projecting v onto u:

distance = |v · u| = |(1−2s)(−84/85) + (3−10s)(5/85) + (2+5s)(14/85)|

Simplifying this expression yields:

distance = |−74s/17 + 23/17|

Therefore, the distance between the two skew lines is |−74s/17 + 23/17|. Note that the distance is not constant and depends on the parameter s.

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I will use the quadratic formula to solve and find the solutions of the equation:

In the case of 4x^2 - 28x + 130:

a = 4

b = -28

c = 130

Thus:

The first solution will be:

The second solution will be:

Answer:

The simplified expression is -22 degrees (rounded to the nearest degree).

What is Trigonometry?

Trigonometry is a branch of mathematics that deals with the relationships between the sides and angles of triangles, and the functions that describe those relationships. It has applications in fields such as engineering, physics, astronomy, and navigation.

We can use the following trigonometric identity to simplify the expression:

arctan(x) + arctan(y) = arctan[(x+y) / (1-xy)]

In this case, we can substitute x = 5 and y = 6 to get:

arctan 5 + arctan 6 = arctan[(5+6) / (1 - 5*6)]

Simplifying the denominator, we get:

arctan 5 + arctan 6 = arctan(11/-29)

To find the degree measure of this angle, we can use a calculator to evaluate the inverse tangent of -11/29 and convert the result to degrees.

The result is approximately -22 degrees (rounded to the nearest degree).

Therefore, the simplified expression is:

arctan 5 + arctan 6 = -22 degrees (rounded to the nearest degree).

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Answer:

8/5 or 1.6. I think this is the correct answer?

Step-by-step explanation:

2*4=8

8/5 or 1.6

A bicycle repair shop that offers two service packages: a tune-up and a complete overhaul.

The shop operates for 60 hours per week and receives an average of 180 bicycles each week. To analyze the capacity and utilization of the process, we need to consider the time taken at each stage and the demand for each service option. We'll break down the problem into multiple parts and provide a detailed explanation using mathematical terms.

a) Creating the Demand Matrix:

To create a demand matrix, we need to determine the number of bicycles going through each stage of the process. Let's denote the demand for tune-up as T and the demand for additional services as A.

Given that the average number of bicycles received per week is 180 and 25% of customers opt for additional services, we can calculate the demands as follows:

Demand for tune-up (T) = Total demand - Demand for additional services

T = 180 - (0.25 * 180)

T = 180 - 45

T = 135

Demand for additional services (A) = 0.25 * Total demand

A = 0.25 * 180

A = 45

Now, we can create a demand matrix based on the demand for each service option:

Demand Matrix:

Tune-up Additional Services Wheel Balancing

Tune-up  [135  0  0]

Additional [0  45  0]

Services

Total [ 135  45  0 ]

The demand matrix shows the number of bicycles flowing through each stage of the process.

b) Daily Capacity at Each Stage:

To calculate the daily capacity at each stage, we need to consider the time taken for each service option. Given that the shop operates for 60 hours per week, we can calculate the daily capacity at each stage:

Tune-up technician time per bicycle (\(T_{tuneup}\)) = 75 minutes

Additional services technician time per bicycle (\(T_{additional}\)) = 72 minutes

Wheel balancing specialist time per bicycle (\(T_{balancing}\)) = 20 minutes

Daily Capacity (C) = (60 hours * 60 minutes) / (\(T_{tuneup}\) + \(T_{additional}\) + \(T_{balancing}\))

Substituting the given values:

C = (60 * 60) / (75 + 72 + 20)

C = 21600 / 167

C ≈ 129.34 bicycles per day

Therefore, the daily capacity at each stage of the process is as follows:

Tune-up: 129 bicycles per day

Additional Services: 129 bicycles per day

Wheel Balancing: 129 bicycles per day

c) Implied Utilizations:

To find the implied utilizations, we need to compare the demand and the capacity at each stage of the process. Utilization can be calculated as the demand divided by the capacity.

Implied Utilization (U) = Demand / Daily Capacity

For the Tune-up stage:

\(U_{tuneup}\) = 135 / 129 ≈ 1.05

For the Additional Services stage:

\(U_{additional}\) = 45 / 129 ≈ 0.35

For the Wheel Balancing stage:

\(U_{balancing}\) = 0 / 129 = 0

The implied utilizations show how efficiently each stage of the process is being utilized. Utilization values greater than 1 indicate that the stage is operating beyond its capacity.

d) Weekly Capacity of the Process:

To calculate the weekly capacity of the process, we multiply the daily capacity by the number of days the shop is open per week:

Weekly Capacity = Daily Capacity * Number of days shop is open per week

Given that the shop is open for 60 hours per week, the number of days the shop is open per week can be calculated as follows:

Number of days shop is open per week = 60 hours / 24 hours per day = 2.5 days

Therefore, the weekly capacity of the process is:

Weekly Capacity = Daily Capacity * Number of days shop is open per week

Weekly Capacity = 129 bicycles per day * 2.5 days

Weekly Capacity = 322.5 bicycles per week

e) Flow Rate and Constraint Analysis:

To determine if the flow rate of the process is capacity-constrained or demand-constrained, we compare the weekly capacity to the demand for each service option.

Demand for Tune-up (\(T_{demand}\)) = 135 bicycles per week

Demand for Additional Services (\(A_{demand}\)) = 45 bicycles per week

Comparing the demands with the weekly capacity:

\(T_{demand}\) < Weekly Capacity (135 < 322.5)

\(A_{demand}\) < Weekly Capacity (45 < 322.5)

Since both the demands for tune-up and additional services are less than the weekly capacity, the flow rate of the process is demand-constrained. This means the shop has the capacity to handle the current demand without operating beyond its limits.

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Volume of Revolution can be defined as the volume obtained by rotating a region about an axis. Here are the solutions for each part of the question.

The shaded area in the given figure will be rotated about the y-axis to generate a solid.


It is a solid with a hole in the center. The outer radius is given by x = 3. The inner radius is given by x = 1.The area of a slice of the solid is given by dV = π(R^2-r^2)dy where R and r are the outer and inner radii, respectively and y is the height.The outer radius is given by R = 3 and the inner radius is given by r = 1/y.

Then, the volume of the solid is \(V= ∫ [0,1] π(R^2-r^2)dy=π∫ [0,1] (3^2-(1/y)^2)dy=30π units^3.2.\)

Find the volume of the solid formed by revolving the region bound by \(x^2+y^3=4 and x=0 and x=2 and y=0\) about the y-axis.A sketch of the region is given below.

The solid generated by revolving the region will be a torus.

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The interval on which f is increasing is (0, π/4) U (5π/4, 2π), the interval on which f is decreasing is (π/4, 5π/4), the local minimum value of f is 4.975 at x = tan⁻¹(1/10) and the local maximum value of f is 5 at x = 0 and x = 2π.

(a) The given function is f(x) = 5sin(x) + 5cos(x), 0 ≤ x ≤ 2.

To find the interval(s) on which f is increasing,

we need to find f′(x).

f′(x) = d/dx [5sin(x) + 5cos(x)]

= 5cos(x) - 5sin(x)

Now, we need to find the values of x where

f′(x) > 0, because that's where f is increasing.

f′(x) > 0

⇒ 5cos(x) - 5sin(x) > 0

⇒ cos(x) > sin(x) ⇒ tan(x) < 1

⇒ x ∈ (0, π/4) U (5π/4, 2π)

Thus, f is increasing on the interval (0, π/4) U (5π/4, 2π).

(b) To find the interval(s) on which f is decreasing,

we need to find the values of x where

f′(x) < 0, because that's where f is decreasing.

f′(x) < 0 ⇒ 5cos(x) - 5sin(x) < 0

⇒ cos(x) < sin(x)

⇒ tan(x) > 1

⇒ x ∈ (π/4, 5π/4)

Thus, f is decreasing on the interval (π/4, 5π/4).

(c) To find the local minimum and maximum values of f,

we need to find the critical points of f.

To find the critical points, we need to solve f′(x)

= 0.5cos(x) - 5sin(x)

= 0cos(x)/sin(x)

= tan(x)

= 1/10

Let x = α be the solution to the above equation on the interval [0, 2π]. Then,α = tan⁻¹(1/10)α ≈ 0.0997 rad.

Now, we need to check the values of f at the critical points and at the endpoints of the interval

[0, 2π].

f(0) = 5sin(0) + 5cos(0)

= 5f(α)

= 5sin(α) + 5cos(α)

≈ 4.975f(2π)

= 5sin(2π) + 5cos(2π)

= 5f(x) has a local minimum value of 4.975 at x = α, and a local maximum value of

5 at x

= 0 and

x = 2π.

Thus, the interval on which f is increasing is (0, π/4) U (5π/4, 2π),

the interval on which f is decreasing is (π/4, 5π/4),

the local minimum value of f is 4.975 at

x = tan⁻¹(1/10) and the local maximum value of f is 5 at

x = 0 and x = 2π.

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The dimensions that minimize the length of fencing needed are approximately 28.28 feet by 28.28 feet, creating a square-shaped playground.

To minimize the length of fencing needed for the enclosure, we need to find the dimensions that maximize the area of the playground. Since one side of the playground is already bordered by the school building, we can focus on the remaining three sides.

Let's assume the length of the playground parallel to the school building is L, and the width perpendicular to the school building is W. The area of the playground can be expressed as A = L * W.

Given that the total area of the enclosure is 800 square feet, we have the constraint L * W = 800.

To minimize the length of fencing needed, we want to maximize the area A. This occurs when the length and width are as close as possible to each other. In other words, we want to find the dimensions that form a square shape.

In a square, the length and width are equal, so we can solve the constraint equation L * L = 800.

Taking the square root of both sides, we find L = √800 ≈ 28.28 feet.

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Answer:

3\15

Step-by-step explanation:

hope this helps

Answer:

\(\frac{2}{8}and\frac{5}{20}\)

Step-by-step explanation:

\(\frac{3}{15}=\frac{1}{5}\)

\(\frac{2}{8}=\frac{1}{4}\)

\(\frac{5}{20}=\frac{1}{4}\)

\(\frac{11}{40}=\frac{11}{40}\)

Answer: = 7 i believe

Step-by-step explanation:

2^3 (2 power by 3) x - 1 for 1 which is 7

By the distribution property 6(1/2 + 2/3+3/4) = 23/2    

According to the distributive property, multiplying the difference or aum of numbers will be equivalent to multiplying the individual parts of the difference or sum.

The expression that can explain the above rule is A ( B+ C) = AB + AC

Here we have

6(1/2 + 2/3+3/4)    

By distribution property

=> 6(1/2 + 2/3+3/4)  

= 6(1/2) + 6(2/3)+ 6(3/4)  

= 3 + 2(2) + 3(3/2)          

= 3 + 4 + 9/2

= 7 + 9/2

=  (14+9)/2        [ add 7 and 9/2 by taking 2 as LCM ]

=  23/2  

Therefore,

By the distribution property 6(1/2 + 2/3+3/4) = 23/2    

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Complete Question:

1. Find the value of this fraction computation: 6(1/2 + 2/3+3/4)