Consider the matrices. B=[−4025] and C=[0340−11] What is product matrix ​BC​ ? Enter your answer by filling in the boxes.

Answer:

rational

Step-by-step explanation:

a rational number can be expressed in the form

\(\frac{a}{b}\) where a and b are integers

\(\frac{-20}{2}\) is in this form and is therefore rational

Answer:

rational

Step-by-step explanation:

Rational Numbers    :  

                                   It is expressed in the ratio, where both numerator and                             denominator are the whole numbers

y = (At + B) e^(rt)

where A = -r/2 and B = 3r/2, as expected.

When the two roots of the characteristic equation are both equal to r, we say that the roots are equal or repeated. In this case, the general solution to the corresponding second order linear homogeneous ODE with constant coefficients is of the form:

y = (At + B) e^(rt)

where A and B are constants to be determined by the initial or boundary conditions.

However, the form given in the question, (at+b)âe^rt, is not correct. The â symbol is not standard notation for mathematical expressions and its meaning is unclear. It is possible that it was intended to represent a coefficient or parameter, but without more information, we cannot determine its value or significance.

To see why the correct form of the solution is y = (At + B) e^(rt), we can use the method of undetermined coefficients. Suppose that y = e^(rt) is a solution to the homogeneous ODE with repeated roots. Then, we can try the solution y = (At + B) e^(rt) and see if it satisfies the ODE.

Taking the first and second derivatives of y, we get:

y' = A e^(rt) + r(At + B) e^(rt) = (Ar + r(At + B)) e^(rt)

y'' = A r e^(rt) + r^2(At + B) e^(rt) = (Ar^2 + 2rAt + r^2B) e^(rt)

Substituting y, y', and y'' into the homogeneous ODE with repeated roots, we get:

(Ar^2 + 2rAt + r^2B) e^(rt) = 0

Since e^(rt) is never zero, we can divide both sides by e^(rt) to get:

Ar^2 + 2rAt + r^2B = 0

This is a linear equation in A and B, and we can solve for them by using the initial or boundary conditions. For example, if we are given that y(0) = 1 and y'(0) = 0, we have:

y(0) = A e^(0) + B e^(0) = A + B = 1

y'(0) = (Ar + rB) e^(0) + A e^(0) = Ar + A = 0

Solving this system of equations, we get:

A = -r/2, B = 3r/2

Therefore, the general solution to the homogeneous ODE with repeated roots is:

y = (-rt/2 + 3r/2) e^(rt)

which can be rewritten as:

y = (At + B) e^(rt)

where A = -r/2 and B = 3r/2, as expected.

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By completing the table for the function x³ + 343x + 7, we can observe the behavior of k(x) as x approaches -7. The values of k(x) decrease as x gets closer to -7, indicating that the limit of k(x) as x approaches -7 is negative infinity.

To find the limit of k(x) as x approaches -7, we complete the table by evaluating the function x³ + 343x + 7 for values of x that are approaching -7.

When x is -7.1, we substitute this value into the function and calculate k(x) = (-7.1)³ + 343(-7.1) + 7, resulting in a negative value. As x becomes progressively closer to -7, we observe a trend of increasingly negative values for k(x).

For x values such as -7.01, -7.001, and -6.999, we can calculate the corresponding k(x) values by substituting them into the function. As x approaches -7 from the left side, k(x) continues to decrease, indicating that the function approaches negative infinity as x approaches -7.

In conclusion, the values of k(x) in the table show a decreasing trend as x approaches -7. This behavior suggests that the limit of k(x) as x approaches -7 is negative infinity.

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Answer:

4.625

Step-by-step explanation:

5/8 = 0.625

To find 5/8, simply divide it.

So 4 and 5/8

= 4.625

Hey there,

We have,

f(x) = x² + 11x + 30g(x) = x + 6

Now,

(f.g)(x) = f(g(x))

Substituting...

g(x) = x + 6f(g(x)) = f(x + 6)

Now,

f(x + 6)= (x + 6)² + 11(x + 6) + 30= x² + 12x + 36 + 11x + 66 + 30= x² + 23x + 132

So,The value is x² + 23x + 132

The set of integers for which p(k) is true is all even integers for which p(k) is proved true if we also prove that p(k)^p(k 2)=> p(k-2).

Considering that p(- 2) and p(0) are valid and expecting that p(k)^p(k+2) => p(k-2), we can decide the arrangement of numbers k for which p(k) is valid by acceptance. In particular, we can show that p(k) is valid for all even numbers k by enlistment, as follows.

To begin with, since p(- 2) and p(0) are valid, the base instance of k = - 2 is valid.

Then, expect that p(k) is valid for some even number k. Then, at that point, utilizing the given ramifications, we have p(k+2) is valid.

At long last, utilizing a similar ramifications once more, we have that p(k-2) is valid. Accordingly, by acceptance, we have shown that p(k) is valid for all even numbers k.

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1)The time complexity of the Eratosthenes' Sieve algorithm in unary notation is O(n) + O(n) + O(n) + O(1) = O(n). 2)when implemented on a Turing machine with unary notation input, the Eratosthenes' Sieve algorithm runs in O(n) time complexity, not O(n^2)

In unary notation, a positive integer n is represented by a string of n ones, denoted as '1n'. For example, 5 is represented as '11111' and 10 is represented as '1111111111'.

Eratosthenes' Sieve is an algorithm used to determine whether a given number n is prime by checking its divisibility with integers up to √n. To analyze the time complexity of the Sieve when implemented on a Turing machine with unary notation input, we need to understand the steps involved in the algorithm.

1. Input: The input to the Sieve is the number n represented in unary notation, '1n'.

2. Initialization: Initialize a boolean array of size n, initially assuming all numbers as prime.

3. Sieve: For each number from 2 to √n, check if it is marked as prime. If it is prime, mark all its multiples as non-prime in the boolean array.

4. Primality Check: Finally, check if the number n is marked as prime in the boolean array. If it is, then n is prime; otherwise, it is not prime.

Let's analyze the time complexity of each step:

1. Input: Representing the number n in unary notation takes O(n) time.

2. Initialization: Initializing the boolean array of size n takes O(n) time.

3. Sieve: In unary notation, the value of n is represented by a string of n ones. So, iterating from 2 to √n would require iterating from '11' to '1√n'. Since we are considering unary notation, the number of iterations required will be proportional to n itself. Therefore, this step takes O(n) time.

4. Primality Check: Checking whether n is marked as prime in the boolean array takes constant time, i.e., O(1).

Overall, the time complexity of the Eratosthenes' Sieve algorithm in unary notation is O(n) + O(n) + O(n) + O(1) = O(n).

Therefore, when implemented on a Turing machine with unary notation input, the Eratosthenes' Sieve algorithm runs in O(n) time complexity, not O(n^2) as mentioned in the problem statement.

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Answer: 120 miles

Step-by-step explanation:

If a car goes 60 miles per hour then in two hours (60×2) it will go 120

Answer:

I think the answer is -4

Hi there! Hopefully this helps!

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

\((4-2)^{3} -3\times 4\)

First we subtract 2 from 4 to get 2.

\(2^{3} -3\times 4\)

Next we calculate 2 to the power of 3 and get 8.

\(8-3\times 4\)

Then we multiply 3 and 4 to get 12.

\(8-12\)

Lastly we Subtract 12 from 8 to get −4.

Explanation:

The drawer does not have any red socks in it, so the chances of picking a red sock are 0. A probability of 0 means "the event will never happen".

Therefore P(not red) = 1 = 100% to mean we know 100% that the sock won't be red.

All probabilities are between 0 and 1, including both endpoints.

Answer:

0

Step-by-step explanation:

It is a horizontal line.

Answer:

undefined

Step-by-step explanation:

The slope of a line is found by

m = (y2-y1)/(x2-x1)

   = (-9 -10)/(-9 - -9)

   = -19/ (-9+9)

   = -19/0

We cannot divide by zero so the slope is undefined

Answer:

For the first picture:

1) Right angle

2)Acute

3)Obtuse

For the second picture:

W) Acute

Step-by-step explanation:

The noise in the medium is also a Gaussian distributed random variable with a mean of 0 and standard deviation of 7 (square root of 49). The probability of X being greater than 10 is very small, less than 0.001%.

In this communication system, the signal Θ is a Gaussian distributed random variable with a mean of 0 and standard deviation of 1. The noise in the medium is also a Gaussian distributed random variable with a mean of 0 and standard deviation of 7 (square root of 49).

The receiver observes X, which is the sum of 2Θ and W. Since Θ and W are independent, we can calculate the mean and variance of X as follows:

E[X] = E[2Θ + W] = 2E[Θ] + E[W] = 0 + 0 = 0

Var[X] = Var[2Θ + W] = 4Var[Θ] + Var[W] = 4(1) + 49 = 53

Therefore, X is also a Gaussian distributed random variable with a mean of 0 and standard deviation of √53 = 7.2801.

To find the probability of X taking a certain value, we can use the formula for the Gaussian probability density function:

f(x) = (1/√(2πσ^2)) * e^(-(x-μ)^2/(2σ^2))

where μ is the mean and σ is the standard deviation. For example, the probability that X is equal to 0 can be calculated as:

f(0) = (1/√(2π*53)) * e^(-(0-0)^2/(2*53)) = 0.0494

To find the probability of X being greater than a certain value, we can use the cumulative distribution function (CDF) of the Gaussian distribution. For example, the probability that X is greater than 10 can be calculated as:

P(X > 10) = 1 - Φ((10 - μ)/σ)

where Φ is the standard normal CDF. Substituting the values for μ and σ, we get:

P(X > 10) = 1 - Φ((10 - 0)/7.2801) = 0.00002

So the probability of X being greater than 10 is very small, less than 0.001%.
In the given communication system with Gaussian noise, the signal Θ is a Gaussian distributed random variable Θ∼N(0,1), and the noise W is also a Gaussian distributed random variable W∼N(0,49), independent of the signal. The receiver observes X = 2Θ + W. To provide accurate information, answers should be given to at least 4 decimal places.

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Answer:

57.5

Step-by-step explanation:

divide 92 by 1.6. I hope this helps

Answer:d

Step-by-step explanation:

The answer is d. None of the above is true.

To calculate velocity, we need to use the equation:

Velocity = M * P / Y

Given:

M = 1,000

P = 2.25

Y = 2,000

Plugging in the values:

Velocity = 1,000 * 2.25 / 2,000

Simplifying:

Velocity = 2.25 / 2

The result is:

Velocity = 1.125

Therefore, the correct answer is: d. None of the above is true.

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Using the concept of even function, it is found that the graph that represents an even function is the third option, given by:

On a coordinate plane, a parabola opens down. It goes through (-2, 0), has a vertex at (0, 4), and goes through (2, 0).

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Answer:

c) the parabola

Explanation:

Hope you have a great day!

Answer:

Step-by-step explanation:

It looks like you are trying to find a line to display the data. we know our slope equation is y = mx + b, and that b is our y axis. Start from 5 on the y axis we try each slope till one fits. -3/4 and -1/4 dont work, as those go the opposite way from our data since they are negative slopes. 1/4 is too much tot he right, but when we try 3/4 it works. Data is about equal on both sides of the line if we are to draw this slope. With 3 on one side and 2 on the other.

In statistical hypothesis testing, the P-value is a significant factor. It is the probability of obtaining a test statistic at least as extreme as the one calculated from the data, assuming the null hypothesis to be true. If the null hypothesis is false, the P-value is the probability of a type I error. It is the probability of rejecting the null hypothesis when it is true.

To interpret the P-value correctly, a P-value of 0.054 means that if the null hypothesis is correct, there is a 5.4% probability that the sample will produce a test statistic as extreme as, or more extreme than the one that was observed. If the calculated P-value is higher than the significance level, which is usually 0.05 or 0.01, we cannot reject the null hypothesis.

In the given situation, the sample provides insufficient evidence to reject the owner's claim that the mean weight of Gala apples this year is heavier than usual because the calculated P-value is higher than the significance level. Hence, the correct option is that the P-value suggests that there is not sufficient evidence to reject the null hypothesis.

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The rate of increase of the y-coordinate as it approaches the point (1, 5) is 4 cm/s.At that instant, the x-coordinate of the point is not changing; it is staying at 1.

When a point reaches a certain coordinate, it means that the point is not changing anymore. In this case, the point has reached the coordinate (1, 5), which means that the x-coordinate (1) is not changing, while the y-coordinate (5) is increasing at a rate of 4 cm/s. Therefore, the x-coordinate of the point is not changing at that instant.

x = 1

Rate of Change (x-coordinate) = 0 cm/s

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Answer: A

Step-by-step explanation:

There is 3 ticks until it hits the whole number 1. it is on the first tick. 1/3

Answer:

b i really hope im right

Step-by-step explanation:

The minimum value between s and t is min_val = 0.6. Therefore, Cov(N(0.6), N(0.8)) = 0.6 * 0.4 = 0.24.

To calculate Cov(N(s), N(t)) given s, t, and λ = 0.4 in a Poisson process, we can use the formula for the covariance of two Poisson random variables:

Cov(N(s), N(t)) = min(s, t) * λ

Given that λ = 0.4, we need to determine the minimum value between s and t. Let's denote it as min_val.

If min_val is equal to s, then Cov(N(s), N(t)) = s * λ.

If min_val is equal to t, then Cov(N(s), N(t)) = t * λ.

Therefore, we need to calculate min_val and use it to compute the covariance.

Let's consider an example where s = 0.6 and t = 0.8:

min_val = min(0.6, 0.8) = 0.6

Cov(N(0.6), N(0.8)) = 0.6 * 0.4 = 0.24

So, in this example, Cov(N(0.6), N(0.8)) is equal to 0.24.

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Benji made par or better on 7 holes in his round so far.

the ratio of holes with par or better to total holes played is equal to 0.4. We need to determine on how many of the holes Benji has made par or better. Table that shows the number of holes Benji has played during his round so far is shown below: Number of holes played in round so far Holes played 6 12 18Number of holes with par or better Number of holes played

2x 6 0.4

The ratio of the number of holes with par or better to the total number of holes played is 0.4.So, (Number of holes with par or better) /

(Number of holes played) = 0.4

Number of holes with par or better

/ (6 + 12 + 18) = 0.42x / 36 = 0.4

Cross-multiplying the above equation, we get,

2x = 0.4 x 36 = 14.4Dividing by 2 on both sides, we get x = 7.2

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Answer:

Step-by-step explanation:

One Piece is the name the world gave to the treasure found by the Pirate King Gol D. Roger. It is a mysterious treasure that once belonged to Joy Boy during the Void Century. The treasure is said to be of unimaginable value, and is currently located on the final island of the Grand Line: Laugh Tale.

The area of the composite figure is 80 square units

From the question, we have the following parameters that can be used in our computation:

The composite figure (see attachment)

The total area of the composite figure is the sum of the individual shapes

So, we have

Area = 2 * Trapezoid + Rectangle

This gives

Area = 2 * 1/2 * (6 + (6 + 2 + 2)) * 2 + 8 * 6

Evaluate

Area = 80

Hence, the total area of the figure is 80 square units

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Answer:

x=34

Step-by-step explanation:

132-64=

68/2=

34

PLEASE MAKE ME BRAINLIEST

The title of the work introduced is Rechnung nach der lenge/auff den Linien und Feder.

In mathematics, an operation is a function that takes zero or more input values to a well-defined output value.

Adam Riese developed the signs + and - as mathematical operations and the title of the work introduced is Rechnung nach der lenge/auff den Linien und Feder.

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Answer:

It goes this way 4,10,16,22,28

Answer:

(8x - 1) - (3x + 6)

hope this helps