Consider the following reaction: COCl2(g) ⇌CO(g) + Cl2(g) Kc = 7.3x10-4 Calculate [CO]eq, [Cl2eq], and [COCl2]eq, respectully, if [COCl2]init=0.730M Group of answer choices no correct answer 0.0216; 0.0216; 0.708 0.229; 0.229; 0.501 0.0416; 0.0416; 0.688 0.0229; 0.0229; 0.707

Answer:

Here you go

Explanation:

Answer:

ok, here is your answer

Explanation:

AI-generated answer

To find the mass of oxygen that reacted, we need to use the Law of Conservation of Mass, which states that in a chemical reaction, the mass of the reactants equals the mass of the products.

First, we need to find the number of moles of hydrogen that reacted:

Molar mass of hydrogen (H₂) = 2.016 g/mol

Number of moles of H₂ = mass/molar mass = 46.2 g/2.016 g/mol = 22.92 mol

Next, we need to use the balanced chemical equation to find the number of moles of water produced:

hydrogen + oxygen → water

2H₂ + O₂ → 2H₂O

From the equation, we can see that for every 2 moles of H₂, 1 mole of O₂ is required to produce 2 moles of H₂O. Therefore, the number of moles of O₂ required to produce 22.92 moles of H₂O is:

Number of moles of O₂ = 1/2 x 22.92 mol = 11.46 mol

Finally, we can find the mass of oxygen that reacted by using its molar mass:

Molar mass of oxygen (O₂) = 32.00 g/mol

Mass of oxygen = number of moles x molar mass = 11.46 mol x 32.00 g/mol = 366.72 g

Therefore, the mass of oxygen that reacted is 366.72 g.

Hey there!

Mass = ?

volume = 105 mL

Density = 2.26 g/mL

Therefore:

D = m / V

2.26 = m / 105

m = 2.26 * 105

m = 237.3 g

Hope this helps!

Answer:

the answer is b,.........

Answer:

Unsaturated

Explanation:

Answer:

hope its help you

Explanation:

2.600 × 10^-5 × 6.100 × 10^-5 = 1.586 × 10-9

To calculate the molar ratio of NaF to HF required to create a buffer with pH=4.20, we need to use the Henderson-Hasselbalch equation, which relates the pH of a buffer solution to the dissociation constant (Ka) of the weak acid (HF) and the ratio of the concentrations of the weak acid and its conjugate base (F-):

pH = pKa + log([F-]/[HF])

We know the pH and Ka of the buffer, so we can rearrange the equation to solve for [F-]/[HF]:

[F-]/[HF] = 10^(pH - pKa)

[F-]/[HF] = 10^(4.20 - 6.8) = 0.005012

The molar ratio of NaF to HF required to create this buffer depends on the concentration of the buffer solution, which is not specified in the question. However, we can assume that the buffer is made with equimolar concentrations of NaF and HF, in which case the ratio of their molar amounts would be:

mol NaF : mol HF = [F-] x Vol : [HF] x Vol

where Vol is the total volume of the buffer solution in liters.

Since we assume equimolar concentrations of NaF and HF, we can set [F-] equal to [HF]:

[F-] = [HF]

Therefore:

mol NaF : mol HF = [F-] x Vol : [HF] x Vol = 0.005012 x Vol : 1 x Vol

mol NaF : mol HF = 0.005012 : 1

mol NaF : mol HF = 1 : 199.2

Therefore, the molar ratio of NaF to HF required to create a buffer with pH=4.20 and Ka(HF)=6.8x10^-4 is approximately 1:199.2.

Considering the definition of percentage by mass, 448 grams of a 12.5 % sugar solution contain 56.0 g of sugar

The percentage by mass expresses the concentration and is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.

The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage:

percent by mass= (mass of solute÷ mass of solution)×100%

In this case, you know:

Replacing in the definition of percent by mass:

12.5%= (56 g÷ mass of solution)×100%

Solving:

12.5%÷ 100%= 56 g÷ mass of solution

12.5%÷ 100%= 56 g÷ mass of solution

0.125= 56 g÷ mass of solution

0.125× mass of solution= 56 g

mass of solution= 56 g÷ 0.125

mass of solution= 448 g

Finally, the mass of solution is 448 grams.

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By removing the need to build additional transmission lines and equipment, energy storage may reduce costs for utilities and their customers.

By removing the need to build additional transmission lines and equipment, energy storage may reduce costs for utilities and their customers. Energy storage's inherent ability to offer backup power in the event of grid failure is a feature that both residential consumers and commercial owners find highly desirable.

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Answer:

C

Explanation:

Answer: B. CFCl3

Explanation:

Look at the amount of moles in the compound.

1 mol C (Carbon)
1 mol F (Fluorine)
3 mol Cl (Chlorine)

You can see that the ratio is 1:1:3 according to the subscripts and moles of each element.

Also, I took the exam and got it right!

Answer:

D

Explanation:

The ratio of C6H12O6 (which will be referred to as "the carb") to oxygen is 1 to 6, so if we find an answer which has the same ratio, it should be chosen. A is 1:3
B is even worse with a ratio of the carb to oxygen of 1:2
C is the same as B, 1:2
D has a ratio of the carb to oxygen of 1:6, which is what we are looking for.

Answer:

what's the answer choices

Explanation:

huh

The concentration of acetic acid in the initial solution is 0.267M

Concentration is a measure of the amount of solute that has been dissolved in a given amount of solvent or solution

Here given data is

Acetic acid = 35.00 mL

8.75 mL of 0.0500 M Sr(OH)₂ for its neutralization

We have to calculate concentration of acetic acid in the initial solution = ?

So the reaction is

CH₃CO₂H + NaOH → CH₃CO₂Na + H₂O

That means the moles of NaOH added = moles acetic acid in the solution

So, to solve this problem we need to find the moles of NaOH added to find the mole of acetic acid and its concentration using its volume as follow

Moles of NaOH

18.75 mL = 0.01875 ×(0.0500mol/L) = 0.009375 mole of NaOH = mole of acetic acid

So the molarity of acetic acid =  0.009375 mole /0.035L = 0.267M

So the concentration of acetic acid in the initial solution is 0.267M

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The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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The combined Gas Law equation is represented by B) P1V1 / T1 = P2V2 / T2.

The combined gas law is the law that combines Charles’s law, Gay-Lussac’s law, and Boyle’s law.

Combined gas law can be mathematically expressed as

k = PV/T

Where,

P = pressure

T = temperature in kelvin

V = volume

K  = constant (units of energy divided by temperature)

When two substances are compared in two different conditions, the law can be stated as,

P1V1/T1 = P2V2/T2

Where,

P1 = initial pressure

V1 = initial volume

T1 = initial temperature

P2 = final pressure

V2= final volume

T2 = final temperature

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ΔLatticeU = ΔLatticeH – pΔVm is the lattice energy of wurtzite.  Ionic compounds often have flat surfaces that meet at distinctive angles and are stiff, brittle, crystalline materials.

Remember that when a metal reacts with a nonmetal, often an ionic compound results from the transfer of electrons form the metal (the reductant) towards the nonmetal (the oxidant). Ionic compounds often have flat surfaces that meet at distinctive angles and are stiff, brittle, crystalline materials. They melt at rather high temperatures and are not easily distorted.   ΔLatticeU = ΔLatticeH – pΔVm is the lattice energy of wurtzite.

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Answer:

Organism B produces pyruvic acid at a faster rate as the temperature increases than Organism A.

Explanation:

The following data were obtained when a sample of barium chloride hydrate was analyzed as described in the Procedure section. Mass of empty test tube Mass of test tube and hydrate (before heating) Mass of test tube and anhydrous salt (after heating) 18.42 g 20.75 g 20.41 g Calculate :

Note: The percent water in the hydrate should not be negative, so this calculation must be incorrect.

Important terms in studying hydrated water are as follows: 1. Anhydrous salt is a salt that has lost water molecules, this salt is formed from the decomposition of heated hydrate salts 2. Hydrate salts are salts that have a fixed number of water molecules in each molecule.

Compounds that contain water of crystals are called hydrates, while compounds that do not contain water of crystals are called anhydrous compounds

The word element in Greek is stoicheion, while stoichiometry or stoichiometry has the meaning of measuring elements which include several things, namely atomic mass, molecular mass, empirical formula, molecular formula, concentration, number of moles, reaction equations and everything related to chemical reactions. The number of particles present in a substance in stoichiometry is called moles.

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The heat that is absorbed by the system is  1363 J. Option B

We know that in a chemical reaction that there could be the absorption or the evolution of heat. We say that there is the evolution of heat when heat has been lost from the system and there is the absorption of heat when heat has been gained by the system.

Number of moles of the barium hydroxide hydrate = 3.15 g/203 g/mol

= 0.015 moles

Number of moles of the ammonium thiocyanate = 1.52/76 g/mol

= 0.02 moles

If 1 mole of barium hydroxide hydrate reacts with 2 moles of  ammonium thiocyanate

0.015 moles of barium hydroxide hydrate reacts with 0.015 * 2 moles/1 mole

= 0.03 moles

Hence the limiting reactant is the ammonium thiocyanate.

Now the heat that is absorbed is;

H = mcdT

m = mass of the water

c = Heat capacity

dT = Temperature change

H = 100 * 4.20 * 3.1

H = 1363 J

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Answer:

Density is mass/volume d=m/v   so volume = m/d or mass divided by density.

That would be 23 / 0.7893 = 29.1397 or 29.14 mL.  Grams cancels out

Explanation:

The volume of ethanol is 20.27 g/ml.

The area occupied by a three-dimensional object is its volume. It can be determined using density and mass. Liters are used to measure it. The overall weight of a thing is its mass. M designates it.

The mass per unit volume is known as density. The capital letter D and the symbol rho stand for density. You can figure it out by dividing the mass by the volume.

rho = m / V

rho = density

m = mass

V = volume

Given the mass of the sample of ethanol weighs 16 g

The density of 0.7893 g/mL

Putting the values in the equation

Volume = 16 / 0.7893 = 20.27

Thus, the volume of ethanol is 20.27 g/ml.

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Answer:

I can say that knowledge of separating mixtures can help us in daily life and within society in the following ways:

1. Purification of water: Separation techniques are used to purify water for drinking and industrial purposes. It is essential to remove impurities from water to prevent diseases.

2. Recycling: Separation techniques are used to separate materials for recycling. This helps reduce the amount of waste in landfills and helps conserve resources.

3. Food industry: Separation techniques are used in the food industry to separate unwanted particles from food products. This helps ensure that the food we eat is safe and free from contaminants.

4. Medicine: Separation techniques are used in the pharmaceutical industry to separate and purify chemicals for use in medicine. This helps ensure that medicines are safe and effective.

5. Environmental protection: Separation techniques are used to remove pollutants from the environment. This helps protect our natural resources and prevent pollution-related health problems.

6. Oil and gas industry: Separation techniques are used to separate crude oil and natural gas into their various components. This helps in the production of energy and other useful products.

In summary, knowledge of separating mixtures is essential in our daily lives and within society. It helps ensure that we have access to safe and clean water, food, medicine, and energy, and also helps protect the environment.

Explanation:

The chloride ion (Cl-) has a single negative charge and a full octet of electrons in its outermost shell. It has a tetrahedral shape, with three equatorial lone pairs and one axial bond to a hydrogen or other positively charged ion.

The conjugate acid of chloride ion is HCl (hydrogen chloride), which is formed when the chloride ion accepts a proton (H+) from an acid. The resulting molecule has a positive charge and a linear shape, with a single bond between the hydrogen and chlorine atoms.

The conjugate acid of chloride ion, HCl, is a strong acid that readily donates a proton (H+) to a base to form the chloride ion. In water, HCl dissociates completely to form H+ and Cl- ions. The hydrogen ion (H+) has a positive charge and no electrons, while the chloride ion (Cl-) retains its original tetrahedral shape and three lone pairs of electrons.

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Answer:

Your answer will be 342 gmol.

Explanation:

Correct me if I'm wrong. Have a good day :)

The pressure inside the tire is approximately 1.970796 newtons per square centimeter (N/cm²) when measured in those units.

To convert the pressure from pounds per square inch (psi) to newtons per square centimeter (N/cm²), we need to use the conversion factors between these units.

First, let's convert pounds to newtons:

1 pound = 0.45359237 kilograms

1 kilogram = 9.80665 newtons

Next, let's convert square inches to square centimeters:

1 square inch = 6.4516 square centimeters

Now, we can perform the conversion:

1 psi = (0.45359237 kg) × (9.80665 N/kg) / (6.4516 cm²)

≈ 0.070307 N/cm²

Therefore, the pressure inside the tire of 28.0 psi is approximately equal to 28.0 × 0.070307 N/cm², which is approximately 1.970796 N/cm².

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Answer:12668 J.

Explanation:

First of all, steam is there so in order to convert it into water it must have to release latent heat of vaporization which is equal to approximately 2450 kJ/kg or 2450 J/g.

So, the calculation is given below.

Heat released during conversion of steam at 100°C to water at 100°C= m*L

= 5*2450= 12250 J.

Heat released during conversion of water at 100°C to water at 80°C= m*Cp*(∆T)

= 5*4.18*20= 418 J.

So total heat released= 12668 J.

hope this helps:)!!!

The heat energy released or absorbed by a system can be calculated using calorimetric equation. The heat is released when 60.0 g of steam at 235°C is converted to water at 100°C is 33858 J or 338 KJ.

Calorimetry is an analytical tool used to determine the heat energy q absorbed or released in a reaction system. The calorimetric equation connecting mass of the reactant m, specific heat capacity c and temperature difference ΔT is related by the expression:

q = mcΔT.

The mass of steam is given 60 g and temperature difference is from 235 to 100 °C thus 135 °C and the specific heat capacity of  water or steam is 4.18 J/°C. The heat energy released is calculated as follows:

q = 60 g × 4.18 J/°C × 135 °C

  = 33858 J

Hence, heat is released when 60.0 g of steam at 235°C is converted to water at 100°C is 33585 J.

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Answer:

Explanation:

H+ = 1 X 10^-7.41 = 3.89 X 10^ -8

POH = 14-7.41 = 6.59

OH- = 1 x 10 ^-6.59 = 2.57 X 10^ -7

The [H+] and [OH−] concentrations of the solution are approximately 2.38 × 10^(-7) M, and the pOH is 6.59.

The pH of a solution is a measure of the concentration of hydrogen ions ([H+]) in the solution. The pH scale ranges from 0 to 14, with a pH of 7 considered neutral. A pH of 7.41 indicates that the solution is slightly basic. To calculate the [H+], [OH−], and pOH of the solution, we can use the relationship:

pH + pOH = 14

Given that the pH is 7.41, we can subtract it from 14 to find the pOH:

pOH = 14 - 7.41 = 6.59

Since pH + pOH = 14, we can also determine the [OH−] by taking the antilogarithm of the pOH value:

[OH−] = 10^(-pOH)

[OH−] = 10^(-6.59)

[OH−] ≈ 2.38 × 10^(-7) M

Since the solution is neutral, the concentration of [H+] will be equal to the concentration of [OH−]:

[H+] = [OH−] ≈ 2.38 × 10^(-7) M

Therefore, the [H+] and [OH−] concentrations of the solution are approximately 2.38 × 10^(-7) M, and the pOH is 6.59.

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Answer:

We need 0.585 grams of NaCl to make a 100 ml solution with a concentration of 0.10 M.

Explanation:

To determine the number of grams of NaCl necessary to make up 100 ml of a 0.10 M (molar) solution, we need to use the formula:

mass = moles x molar mass

where "moles" is the number of moles of NaCl required to make the solution and "molar mass" is the mass of one mole of NaCl.

First, we need to determine the number of moles of NaCl required to make a 0.10 M solution in 100 ml:

0.10 M = 0.10 moles/liter

Since we want to make a solution with a volume of 100 ml, or 0.1 liters, we can calculate the number of moles of NaCl as:

moles = 0.10 moles/liter x 0.1 liters = 0.01 moles

Next, we need to determine the molar mass of NaCl:

NaCl = 23.0 g/mol (for Na) + 35.5 g/mol (for Cl) = 58.5 g/mol

Now we can use the formula to find the mass of NaCl:

mass = moles x molar mass

mass = 0.01 moles x 58.5 g/mol = 0.585 g

Therefore, we need 0.585 grams of NaCl to make a 100 ml solution with a concentration of 0.10 M.