The overall voltage gain of a cascade amplifier is independent of the order of the stages, as long as the voltage gains of the individual stages remain the same.
In a cascade amplifier, the overall voltage gain is obtained by multiplying the voltage gains of the individual stages. When the first and second stages are interchanged, the overall voltage gain changes accordingly.
Let's assume that the voltage gains of the first and second stages are A1 and A2, respectively. The overall voltage gain when the first and second stages are in their original positions is:
Vo/Vs = A1 * A2
When the first and second stages are interchanged, the overall voltage gain becomes:
Vo/Vs = A2 * A1
Since multiplication is commutative, the overall voltage gain remains the same even when the first and second stages are interchanged:
Vo/Vs = A1 * A2 = A2 * A1
Therefore, the overall voltage gain obtained when the first and second stages are interchanged is the same as the overall voltage gain obtained in Example 1.3.
In conclusion, the overall voltage gain of a cascade amplifier is independent of the order of the stages, as long as the voltage gains of the individual stages remain the same.
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A field received 4.2 inches of rainfall per hour, which caused about 0.3 mm of soil loss. Compute:
1)soil loss in Mg ha-1 (Ton/ha) if the soil bulk density is 1.20 Mg m-3.
2)lbs/ac N lost with soil if the soil had 0.15% N?
3)Cost to replace the N lost per acre if N costs $0.65/lb.
1. The soil loss is 0.032004 Mg/ha (Metric tons per hectare).
2. The nitrogen (N) loss with the soil is 7.41315 lbs/ac (pounds per acre).
3. The cost to replace the lost N per acre is $4.82.
To compute the requested values, we'll use the following conversions:
1 inch = 25.4 mm
1 hectare (ha) = 2.47105 acres
1. Soil loss in Mg/ha:
First, let's convert the rainfall from inches per hour to millimeters per hour:
4.2 inches/hour×25.4 mm/inch = 106.68 mm/hour
To calculate soil loss in Mg/ha, we'll multiply the rainfall by the soil bulk density:
Soil loss = (106.68 mm/hour×0.3 mm)×(1.20 Mg/m³) × (1 ha/10,000 m²)
Soil loss = 0.032004 Mg/ha
Therefore, the soil loss is approximately 0.032004 Mg/ha.
2. Lbs/ac N lost with soil:
To calculate the nitrogen (N) loss in pounds per acre (lbs/ac), we'll first convert the soil area from hectares to acres:
1 ha × 2.47105 acres/ha = 2.47105 acres
Then we'll calculate the N lost using the percentage of N in the soil:
N lost = 2.47105 acres× 0.0015 (N fraction)×2000 lbs/ton
N lost = 7.41315 lbs/ac
Therefore, the nitrogen loss with the soil is approximately 7.41315 lbs/ac.
3. Cost to replace the N lost per acre:
To calculate the cost to replace the lost N per acre, we'll multiply the N lost by the cost per pound of N:
Cost to replace = 7.41315 lbs/ac × $0.65/lb
Cost to replace = $4.82/ac
Therefore, the cost to replace the N lost per acre is $4.82.
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A bakery wants to determine how many trays of doughnuts it should prepare each day. Demand is normal with a mean of 15 trays and standard deviation of 5 tray. If the owner wants a service level a at least 95%?
The number of trays that should be prepared if the owner wants a service level of at least 95% is; 7 trays
How to utilize z-score statistics?We are given;
Mean; μ = 15
Standard Deviation; σ = 5
We are told that the distribution of demand score is a bell shaped distribution that is a normal distribution.
Formula for z-score is;
z = (x' - μ)/σ
We want to find the value of x such that the probability is 0.95;
P(X > x) = P(z > (x - 15)/5) = 0.95
⇒ 1 - P(z ≤ (x - 15)/5) = 0.95
Thus;
P(z ≤ (x - 15)/5) = 1 - 0.95
P(z ≤ (x - 15)/5) = 0.05
The value of z from the z-table of 0.05 is -1.645
Thus;
(x - 15)/5 = -1.645
x ≈ 7
Complete Question is;
A bakery wants to determine how many trays of doughnuts it should prepare each day. Demand is normal with a mean of 15 trays and standard deviation of 5 trays. If the owner wants a service level of at least 95%, how many trays should he prepare (rounded to the nearest whole tray)? Assume doughnuts have no salvage value after the day is complete. 6 5 4 7 unable to determine with the above information.
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Determine the mobility and the number of idle degrees of freedom for the mechanisms shown in Figure 1, in terms of number of body, number of joints, total connectivity, idle degree of freedom, and mobility of this system.
We must examine the number of bodies, joints, connectivity, and degrees of freedom of the system in order to calculate the mobility and number of idle degrees of freedom for the mechanisms depicted in Figure 1.
Count the total number of separate stiff bodies or linkages in the mechanism (number of bodies, B).
The total number of joints or connections between the bodies is indicated by the letter J. A point of restriction or relative mobility is represented by each joint.
Total connectivity (C): Add up the degrees of freedom that each joint contributes to determine the total connectivity. The degree of freedom is 1 for simple joints, such as revolute or prismatic joints. The degree of freedom is three for complicated joints, such as spherical or planar joints.
Idle degrees of freedom (IDF): In a system, the idle degrees of freedom are the unnecessary or unrestricted degrees of freedom. It is computed by deducting the system's degrees of freedom from the overall connection.
Mobility (M): Mobility is an indicator of how many independent input parameters are necessary to fully characterise a mechanism's setup. It is determined by subtracting the number of constraints or independent equations from the degrees of freedom.
These elements may be used to calculate the mobility and idle degrees of freedom for the mechanism depicted in Figure 1.
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Degree of freedom refers to the number of independent variables or parameters that define the position and orientation of a system. In the context of mechanical systems, degree of freedom represents the number of ways a system can move or be positioned.
In simple terms, degree of freedom can be thought of as the number of independent motions or variables that are required to fully describe the configuration of a system.
For example, consider a rigid body in three-dimensional space. It can have six degrees of freedom, typically represented as three translational degrees of freedom (movement along the x, y, and z axes) and three rotational degrees of freedom (rotation about the x, y, and z axes).
In more complex mechanisms or systems, the degree of freedom can vary based on the number and type of joints, constraints, and the overall structure of the system.
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Discuss in detail the manners of interaction with opposite gender
Answer:
8 Tips on Better Communication with the Opposite Sex
Put emotions away. Ladies, this one is more aimed at us, for the most part. ...
Forget your pride. In discussions, especially these days, people always want to be the one that prevails. .
Put yourself in their shoes. .
Listen. ...
Respond. ...
Actually communicate. ...
Be detailed. ...
Don't communicate too much.
Explanation:
Hey guys can anyone list chemical engineering advancement that has been discovered within the past 20 years
If you go to a restaurant and they offer 5 entrees, 4 vegetables, and 6 desserts, how many different combinations must the kitchen staff be ready to serve? all people must choose one from each category.
The kitchen staff must be ready to serve 120 different combinations.
How many combinations must the kitchen staff prepare?To calculate the number of different combinations the kitchen staff must be ready to serve, we can multiply the number of options in each category together:
Number of entrees = 5
Number of vegetables = 4
Number of desserts = 6
Total number of different combinations = Number of entrees × Number of vegetables × Number of desserts
Total number of different combinations = 5 × 4 × 6
Total number of different combinations = 120
Therefore, the kitchen staff must be ready to serve 120 different combinations.
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Following the megger test, wait for the voltage to bleed off prior to disconnecting the megger leads, otherwise what can happen?
a. nothing
b. a shock can result
c. false megger readings
d. one can damage the wire
The correct answer is b. A shock can result if the megger leads are disconnected before the voltage has had a chance to bleed off.
The megger test is used to measure the insulation resistance of electrical wiring or equipment. When the test is completed, the voltage stored in the wiring or equipment needs to be discharged before the leads are disconnected. If the leads are disconnected too quickly, the stored voltage can create a shock hazard, potentially causing injury or even death. It is important to wait for the voltage to bleed off completely before disconnecting the leads to avoid any electrical shock. Additionally, failing to discharge the voltage properly can result in false megger readings or damage to the wire or equipment being tested. It is important to always follow proper safety protocols when performing electrical tests to prevent accidents and ensure accurate results.
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The current flowing into the collector lead of a certain bipolar junction transistor (BJT) is measured to be 1 nA. If no charge was transferred in or out of the collector lead prior to t = 0, and the current flows for 1 min. calculate the total charge which crosses into the collector.
Answer:
the total charge which crosses into the collector is 60 nC
Explanation:
Given the data in the question;
current flowing into the collector lead of the bipolar junction transistor (BJT); i = 1 nA = 10⁻⁹ A
no charge was transferred in or out of the collector lead prior to t = 0
the current flow time t = 1 min = 60 sec
Now we write the relation between current, charge, and time;
i = dq / dt
where i is current, q is charge and t is time. { d refers to change }
Now,
\(q=\int\limits^t_{t=0} {i(t)} \, dt\)
\(q=\int\limits^{t=60}_{t=0} { (10^{-9}) } \, dt\)
\(q = ( 10^{-9}) (t)_0^{60\)
\(q = ( 10^{-9}) ( 60 - 0 )\)
q = 60 × 10⁻⁹ C
q = 60 nC
Therefore, the total charge which crosses into the collector is 60 nC
when must a competent person conduct an inspection of a sling?
Before each use and at least once every 12 months, a sling must be inspected by a qualified person.
What is a sling?An arm that has been hurt is supported with a sling, a bandage. Applying a sling Hold the arm still above and below the injury.
To create the sling, place the triangle bandage beneath the hurt arm and over the shoulder that is not hurt. Sling ends should be tied at the side of the neck.
A competent person should also examine a sling following any incident that might compromise its integrity, such as dropping it or exposing it to a potentially damaging environment.
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A competent person inspects a sling before each use and upon change in application. Periodic inspections are conducted based on frequency and conditions of use. If wear or damage is detected, the sling is removed from service.
Explanation:A
competent person
must conduct an inspection of a sling before each shift begins and whenever there is a change in the sling's application that could affect its operation. Additionally, a
periodic inspection
should be performed at intervals based on frequency of use, severity of service conditions, nature of lifts being made, and experience gained from the service life of slings used in similar circumstances. Factors to consider include visible damage, wear, deformation and increase in length. If any of these are detected, the sling should be removed from service.
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A part has been tested to have Sut = 530 MPa, f = 0.9, and a fully corrected Se = 210 MPa. The design requirements call for the part to be loaded at three different fully-reversed loads and cycled at each one for a set number of cycles. First, it will be loaded at ±350 MPa for 5,000 cycles. Then, it will be loaded at ±260 MPa for 50,000 cycles. Finally, it will be loaded at ±225 MPa until it fails. How many cycles do we expect the part to last at the final loading? Use Miner's method. :g
Answer:
126984 cycles
Explanation:
Given data :
Sut = 530 MPa
f = 0.9
fully corrected Se = 210 MPa
using Miner's method attached below is the detailed solution of the given problem
when loaded with ± 225 MPa the number of cycles before it fails will be
≈ 126984
A horizontal piston/cylinder arrangement is placed in a constant-temperature bath. The piston sides in the cylinder with negligible friction and an external force holds it in place against an initial gas pressure of 14 bar. The initial gas volume is 0.03 m3. The external fore on the piston is reduced gradually and the gas expands isothermally as its volume triples. If the volume of the gas is related to its pressure so that the product PV is constant.
(a) What is the work by the gas in moving the external force?
(b) How much work would be done if the external force were suddenly reduced to half its initial value instead of being gradually
reduced?
Answer:
\(W=46141.72~J\)
Explanation:
Given:
initial pressure, \(P_1=14~bar=1.4\times10^6~Pa\)
initial volume, \(V_1=0.03~m^3\)
After isothermal expansion:
final volume, \(V_2=3V_1=0.09~m^3\)
a)
We have the work done in isothermal process as:
\(W=P_1.V_1\ln(\frac{V_2}{V_1} )\)
\(W=1.4\times10^6\times 0.03\ln(\frac{0.09}{0.03} )\)
\(W=46141.72~J\) is the work by the gas in moving the external force
b)
When the force on piston is suddenly reduced to half the initial value then the process becomes near to adiabatic.
\(P_1V_1^{\gamma}=P_2V_2^{\gamma}\)
\(14\times 0.03^{1.4}=P_2\times 0.09^{1.4}\)
\(P_2=3~bar\)
Now, using the formula for work done in adiabatic process:
\(W=\frac{P_1V_1-P_2V_2}{\gamma-1}\)
\(W=\frac{1.4\times10^6\times 0.03-3\times10^5\times 0.09}{1.4-1}\)
\(W=3750~J\)
Describe the Types of Interactions That Determine the Extent to Which a Solute Dissolves in Solution Question What will happen if one tries to form a solution where the enthalpy of solvation is positive and very large and the entropy of solvation is positive, but small? Select the correct answer below O A solution will form and the temperature will increase as a result O A solution will form and the temperature will decrease as a result. O A solution will form and the temperature will remain constant. O A solution will not form.
The correct answer is Solute-solute interactions, solvent-solvent interactions, and solute-solvent interactions are the three attractive interactions that are significant in the formation of solutions.
Computers play a hugely important role in our lives, to be sure. It enables us to convert information and facts into useful data. It has the capacity to hold a large amount of data and aids in storing and organising data in a consistent way. Only with the aid of these computers do we employ software applications to store, access, alter, calculate, and analyse data and information. Our entire way of life is built on internet services and goods, which are only accessible through computers. Commodore International introduced the all-time best-selling personal computer in 1982. Almost 17 million Commodore 64 consoles were sold. The 64 KB of Memory gave the C64 its name.
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When an object is made of the plastic polyester (PET), it uses antimony as a catalyst. After production, antimony can leach into food and drink stored in PET containers. Usually, if stored correctly for a short amount of time, the amount of antimony found in liquids is well below the safety limits. However, there have been reports of as much as 44.7 micrograms per liter [µg/L] of antimony found in fruit juice concentrates. How much antimony, in units of moles [mol], could be found in one gallon [gal] of fruit juice concentrate at this level of contamination? The molecular mass of antimony is 121.76 grams per mole [g/mol].
Answer:
1.39 µmol
Explanation:
(1 gal) × (44.7 µg/L)/(121.76 g/mol)(3.785411784 L/gal) = 1.39 µmol
Ashrae standard 15 -2013 require that each machinery room activate an alarm and mechanical ventillation?
ASHRAE Standard 15 - 1994 requires that each machinery room must activate an alarm and mechanical ventilation before refrigerant concentrations exceed the TLV-TWA (Threshold Limit Value - Time Weighted Average).
What is ASHRAE Standard 15 - 1994?The key standards guiding refrigerant identification and usage developed by ASHRAE have been revised to comply with government regulations and achieve improved performance. Standards 15 and 34 provide critical guidance to manufacturers, design engineers, and operators who must stay up to date on new air conditioning and refrigeration requirements.Standard 34 describes a shorthand method of naming refrigerants and assigns safety classifications based on toxicity and flammability data, whereas Standard 15 establishes procedures for operating equipment and systems when those refrigerants are used.Before refrigerant concentrations exceed the TLV-TWA, each machinery room must activate an alarm and mechanical ventilation, according to ASHRAE Standard 15 - 1994 (Threshold Limit Value - Time Weighted Average).Therefore, ASHRAE Standard 15 - 1994 requires that each machinery room must activate an alarm and mechanical ventilation before refrigerant concentrations exceed the TLV-TWA (Threshold Limit Value - Time Weighted Average).
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The correct question is given below:
ASHRAE Standard 15 - 1994 requires that each machinery room must activate an alarm and mechanical ventilation before refrigerant concentrations exceed:
What did Congress do in 1787 to settle land disputes among the settlers?
Answer:
On July 13, 1787, Congress enacts the Northwest Ordinance, structuring settlement of the Northwest Territory and creating a policy for the addition of new states to the nation. ... In 1781, Virginia began by ceding its extensive land claims to Congress, a move that made other states more comfortable in doing the same
Answer:
They divided up the Northwest Territory into acre squares and sold them.
Explanation:
An AM signal having a carrier frequency of 460 kHz is to be mixed with a local oscillator signal at a frequency of 1135 kHz. What does the output of the IF amplifier consist of
Answer:
the output of the IF amplifier consist of 675 kHz
Explanation:
Given the data in the question;
AM signal carrier frequency \(_{RF\) = 460 kHz
Local oscillator frequency\(_{lo\) = 1135 kHz
Now, The output of the IF amplifier consists of difference of local oscillator frequency & AM carrier signal frequency;
FREQUECY\(_{IF\) = FREQUECY\(_{lo\) - FREQUECY\(_{RF\)
so we substitute in our given values
FREQUECY\(_{IF\) = 1135 kHz - 460 kHz
FREQUECY\(_{IF\) = 675 kHz
Therefore, the output of the IF amplifier consist of 675 kHz
inspections may be_____ or limited to a specific area such as electrical or plumbing
A. Metering
B. General
What is one of the reasons to consider implementing a blockchain solution?
Blockchain is often used often in the verification and locating of multistep transactions. One of the reasons to consider implementing a blockchain solution is the ability to work on different versions of the same data.
Blockchain solution is known to keep transactions safe, limit compliance costs, and speed up data transfer processing. It is known to back up the accuracy of the data.In Blockchain, all node can see all transactions that are taking place in the system and all will get a copy of each of them to update its data and approve it.
See full question below
What is one of the reasons to consider implementing a blockchain solution?
Options:
1.inability to track simultaneous updates by multiple users
2. ability to work on different versions of the same data
3.ability to verify that data has not been tampered with since its creation
4.inability to trace and access data of other users
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Coal containing 21% ash is completely combusted, and the ash is 100% removed in a water contact scrubber. If 10,000 kg of coal is burned per hour with a scrubber flow rate of 1.0 m3/min, the weight percentage of the ash in the water/ash stream leaving the scrubber is most nearly:_______.
a. 3.4
b. 14.3
c. 25.9
d. 67.7
Answer:
Weight Percentage of Ash = 3.4
Explanation:
Given - Coal containing 21% ash is completely combusted, and the ash is 100% removed in a water contact scrubber. If 10,000 kg of coal is burned per hour with a scrubber flow rate of 1.0 m3/min.
To find - the weight percentage of the ash in the water/ash stream leaving the scrubber is most nearly ?
Solution -
Given that,
Coal Burned Rate = 10,000 kg/hr
= \(\frac{10,000}{60 min} * 1 hr *\frac{kg}{hr}\)
= 166.6666 kg/min
⇒Coal Burned Rate = 166.6666 kg/min
Now,
Given that,
Ash content in coal = 21 %
⇒Ash in (coal that burned) = 166.6666 × \(\frac{21}{100}\) kg/min
= 34.9999 ≈ 35 kg/min
⇒Ash in (coal that burned) = 35 kg/min
Now,
We know,
Density of water = 1000 kg/m³
Now,
Water flow Rate = \(1\frac{m^{3} }{min} * density\)
= 1000 kg/min
⇒Water flow Rate = 1000 kg/min
Now,
Total Mass flow Rate of (Water + Ash stream) = ( 1000 + 35) kg/min
= 1035 kg/min
⇒Total Mass flow Rate of (Water + Ash stream) = 1035 kg/min
So,
Weight Percentage of Ash = (Weight of Ash ÷ Total weight of Stream) × 100
= (35 ÷ 1035) × 100
= 3.38 ≈ 3.4
∴ we get
Weight Percentage of Ash = 3.4
What cycle time would match capacity and demand if demand is 300 units a day, there are three shifts of 420 minutes each, and workers are given four half – hour breaks during each shift.
In a production line, the cycle time refers to the time needed to complete one process or a unit of the item being manufactured. For instance, if an assembly line manufactures 300 units per day, and they operate 3 shifts a day, then they must make sure that their cycle time aligns with the demand.
What cycle time would match capacity and demand if demand is 300 units a day, there are three shifts of 420 minutes each, and workers are given four half – hour breaks during each shift.To figure out the cycle time, the first step is to determine the total number of production minutes available in a day, which is:420 minutes per shift x 3 shifts = 1260 minutes per day There are 4 half-hour breaks, so in total, there is a 2-hour break, which is equivalent to 120 minutes:420 x 3 - 120 = 1240 minutes available for production. If the demand is 300 units, the production line must produce one unit every:1240/300 = 4.133 minutes or 4 minutes and 8 seconds In conclusion, the cycle time that would match capacity and demand if the demand is 300 units a day, there are three shifts of 420 minutes each, and workers are given four half – hour breaks during each shift is 4 minutes and 8 seconds.For more such question on equivalent
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Turn the matlab code down below into C code
C Code:
#include <stdio.h>
#include <math.h>
#define W 8
#define H 8
int main() {
// generate basis vector for 2D-DCT
double x[H][W], basis_vector[H][W][H][W];
for (int u = 0; u < H; u++) {
for (int v = 0; v < W; v++) {
for (int r = 0; r < H; r++) {
for (int c = 0; c < W; c++) {
basis_vector[r][c][u][v] = cos(M_PIu(2r+1)/2/H) * cos(M_PIv*(2*c+1)/2/W);
x[r][c] = 127.5 + 127.5 * basis_vector[r][c][u][v];
}
// bmp_x = uint8(x);
// fn = sprintf('basis(u=%d,v=%d).bmp', u, v);
// imwrite(bmp_x, fn);
}
}
}
// read image
// houses = imread('../houses.bmp');
// f = houses(:,:,1); // spatial domain
// figure(1);
// imshow(f);
int M = 512/H, N = 512/W;
// 2D-DCT
double F[H][W][M][N]; // frequnecy domain. M: # of blocks vertically.
// N: # of blocks horizontallly
double beta[H];
beta[0] = 1/sqrt(2);
for (int i = 1; i < H; i++) beta[i] = 1;
for (int m = 0; m < M; m++) { // loop for # of blocks vertically
for (int n = 0; n < N; n++) { // loop for # of blocks horizontally
// target_8x8 = double(f(((m-1)*H+1):(m*H),((n-1)*W+1):(n*W)));
// target_8x8 = target_8x8 - 128; // substract 128
for (int u = 0; u < H; u++) { // loop for frequencies regarding vertical direction
for (int v = 0
Suppose you are planning a party, and your objective is to have an enjoyable party for all guests. An outdoor barbecue would be the best but only if the sun shines; rain would ruin the barbecue. On the other hand, you could plan an indoor party. This would be a good party, not as nice as an outdoor barbecue in the sunshine but better than a barbecue in the rain. Of course, it is always possible to forego the party altogether!
Construct an influence diagram and a decision tree for this problem.
The decision tree is continuing support for judgment, that utilizes a tree-like decision model, and its possible effects, such as the chance event results, resources as well as utility costs. It is a way of displaying an automated system containing the only conditional statement of control, and the further discussion can be defind as follows:
To make it pleasant for all guests concerned, the host needs to decide on the course of the barbeque party.Plan and draw up a decision tree that will show the potential results based on the different site conditions. The weather conditions that will prevail at the site on that particular day of the party are the factor of concern about the decision.Start the tree with such a single node the day of the party which will provide a view of the weather.Please find the diagram in the attachment file.
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Which of the following is NOT part of a car's drive train?
A axle
B rotor
C differential
D transmission
Answer:
B. rotor
Explanation:
The correct answer Is rotor because the others are part of a cars drivetrain
The drive train system exists as a critical element of a vehicle and the transmission exists as an integral part of the drive train. B rotors NOT part of a car's drive train.
Which is not part of the drive train?A drive train exists not really a single part of your car – it's a set of drive train components that interact with the engine to drive the wheels and different regions of the vehicle to thrust it into motion. These components often contain the transmission, differential, driveshaft, axles, CV joints, and wheels.
Therefore, the correct answer is option B rotors.
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All MOS devices are subject to damage from:________
a. excessive heat
b. electrostatic discharge
c. excessive voltage
d. all of these
Answer:
d. all of these
Explanation:
Electrostatic discharge will generally produce excess voltage in a local area that results in excessive current and excessive heat. It will blast a crater in an MOS device, or melt bond wires, or cause damage of other sorts. In short, MOS devices are subject to damage from "all of these."
If substance A has molecules moving at a high rate and substance B has molecules moving at a low rate, which substance has the lower temperature?
Answer:
substance B
Explanation:
you lost control of your drone and crashed it, destroying it completely, beyond repair. fortunately, there were no human or other third-party injuries.
The correct answer is the remote pilot in command you lost control of your drone and crashed it, destroying it completely, beyond repair. fortunately, there were no human or other third-party injuries.
(a) A civil small unmanned aircraft system may only be operated by someone if it is in a safe operating state. The tiny unmanned aircraft system must be inspected by the remote pilot in command before each flight to make sure it is fit for safe operation. An autonomous pilot should. systematically fixate for brief (10° or less) periods on various sky regions. focus on any relative movement you might see in your peripheral vision. In the A/FD, pilots can obtain information about traffic patterns and constraints like noise abatement. 1. Approach the runway's centerline in level flight and climb to pattern height. Unless specified differently, the acceptable pattern altitude is (1,000' AGL).
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Alex loves to build things and wants to study robotics. He needs to get a job over the summer but the only one he can find is at a fast food restaurant. Does taking the job mean that Alex cannot pursue a career in robotics? Explain your answer.
Answer:
He can take the job at the fast food restaurant to make money in order to pursue his career in robotics it doesnt mean he cant pursue it just he needs to make money for it first.
A chemist mixed two substances together: a colorless liquid with a strong smell and a white solid with no smell. The substances' repeating groups of atoms are shown above on the left. After they were mixed, the chemist analyzed the results and found two substances. One ending substance had the repeating group of atoms shown above on the right. Is the ending substance the same substance as the colorless liquid? What happened to the atoms of the starting substances when the ending substances formed? Be sure to explain your answers to both of these questions.
Answer:
[a]. It is the same substance as the colorless liquid with a strong smell.
[b]. the substance with colorless liquid with a strong smell and a white solid with no smell are being used up to produce the ending substance had the repeating group of atoms shown above on the right and the other ending substance.
Explanation:
Atoms are referred to be the smallest units of a substance although it can be sub-divided into smaller units such as proton, neutron and electron. When atoms combines in group they form a molecule.
From the question above it is seen that two substances were mixed together to give two ending substances that is:
substance A [ colorless liquid with a strong smell] + substance B[white solid with no smell] ---------> substance C[ repeating group of atoms shown above on the right] + substance D.
The ending substance that is, substance C is the same substance as substance A which is the colorless liquid with a strong smell.
When the substance A reacted with substance B, it gives substance C and D that is the ending substances are the products of the reaction between A and B.
Hence, the substance with colorless liquid with a strong smell and a white solid with no smell are being used up to produce the ending substance had the repeating group of atoms shown above on the right and the other ending substance.
What is the main use of this type of time line
Answer:
The main use of a timeline in engineering is for project management, product development, and historical analysis. It helps engineers to plan and track progress, ensure requirements are met, and understand the context and history of their field.
An elevation is.... * 10 points a. A detailed description of requirements, composition and materials for a proposed building. b. A view of a building seen from one side, a flat representation of one façade. This is the most common view used to describe the external appearance of a building. c. The development of the last remaining lots in an existing developed area, the new development within an area already served by existing infrastructure and services, or the reuse of already developed, but vacant properties. d. The practice of creating structures and using processes that are environmentally responsible and resource-efficient throughout a building's life-cycle from siting to design, construction, operation, maintenance, renovation and deconstruction.
Answer:
b. A view of a building seen from one side, a flat representation of one façade. This is the most common view used to describe the external appearance of a building.
Explanation:
An elevation is a three-dimensional, orthographic, architectural projection that reveals just a side of the building. It is represented with diagrams and shadows are used to create the effect of a three-dimensional image.
It reveals the position of the building from ground-depth and only the outer parts of the structure are illustrated. Elevations, building plans, and section drawings are always drawn together by the architects.