Consider a single pane window in a room where the air is maintained at 25 deg C. The convection coefficient between the room air and the window is 6.2 W/m^2/K. The window pane is at 12 deg C. The window is 0.95 m tall and 1.5 m wide.


Required:

a. Estimate the rate at which heat is lost through this widow by convection.

b. Also estimate the radiation exchange between the room's walls and the window. The emissivity of glass at or around room temperature is 0.94. State any assumptions you might need to make before proceeding.

Answer:

okay it is faster and easier

Answer:the inflating Ballon expirement

Explanation:

The programming concepts covered in the scientific calculator project include object-oriented programming concepts such as objects and classes, control structures like loops and if-else statements.

The paragraph describes a project that involves developing a scientific calculator with various mathematical functions and a menu to select those functions.

The project requires the use of several fundamental programming concepts such as object and class, loops, if-else statements, arrays, inheritance, and switch statements.

These concepts are essential building blocks in programming and are commonly used in various programming languages. By incorporating these concepts into the project, students can gain a better understanding of how to structure and design their code effectively.

Additionally, this project provides a practical application of these concepts, allowing students to apply them in a real-world context and develop their problem-solving skills.

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The amount of gallons needed per minute to flow through the two water reservoirs are 9.7 gallons.

To calculate the number of gallons per minute flowing through the two water reservoirs, we can use the equation Q = (CdAh)2/3S1/2. Here, Q is the flow rate in gallons per minute (gpm), Cd is the coefficient of discharge, Ah is the cross-sectional area of the pipe in square feet, and S is the slope of the pipe in feet per foot.

To calculate the flow rate in gpm, we first need to calculate the coefficient of discharge and the slope of the pipe. The coefficient of discharge for a 8-in diameter commercial steel pipe is 0.86, and the cross-sectional area of the pipe is 0.206 square feet. The slope of the pipe can be calculated by dividing the difference in elevation (200 ft) by the length of the pipe (5000 ft), resulting in a slope of 0.04 ft/ft.

Plugging these values into the equation above, we get:

Q = (0.86 x 0.206)2/3 x (0.04)1/2 = 9.7 gpm

Therefore, 9.7 gallons per minute are flowing through the two water reservoirs.

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Answer:

somewhere around 34.2223 meters thick but that's what I am estimating.

A typical EGR pintle-position sensor is a potentiometer type of sensor. The EGR (Exhaust Gas Recirculation) system is responsible for controlling the amount of exhaust gas that is reintroduced into the engine's combustion chamber, reducing harmful emissions such as nitrogen oxides.

The pintle-position sensor detects the position of the EGR valve's pintle, which is a crucial component in managing the flow of exhaust gases.

Potentiometers are widely used in various applications due to their ability to provide variable resistance based on the position of a sliding contact or wiper. In the case of an EGR pintle-position sensor, the potentiometer's wiper moves in accordance with the pintle's position, changing the resistance and generating a corresponding voltage signal. This signal is then sent to the engine control module (ECM), which uses this information to adjust the EGR valve's operation and maintain optimal engine performance.

While other types of sensors, such as Wheatstone bridge, piezoelectric, and rheostat sensors, are utilized in various applications, they are not typically used for EGR pintle-position sensing. Wheatstone bridge sensors are commonly used for measuring strain and pressure, piezoelectric sensors are used for detecting vibrations or dynamic forces, and rheostats are primarily used to control electrical current. Therefore, a potentiometer is the most suitable type of sensor for accurately detecting the position of the EGR valve's pintle.

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Therefore, roughly 12 drain holes with a diameter of 0.4 inches would be required to prevent the sink from overflowing with water.

Two gal of water per minute enter the sink. The water will eventually go through the overflow drain holes if the drain is closed as opposed to over the edge of the sink. number of 0.4-in.

Equation: The rate of flow through a circular hole can be determined.

\(Q = C \times A \times \sqrt{(2gH) (2gH)}\)

Calculate the following to determine the cross-sectional area of a hole with dimension d:

\(A = \frac{\pi}{4} \times d^2\)

To prevent the water from overflowing the sink, we can set the flow rate through each hole to be equal to the incoming flow rate and solve for the necessary number of holes.

\(n = \frac{2}{(0.61 \times \frac{\pi}{4} \times 0.16 \times \sqrt{(64.4 \times 6)})}\)

  \(= \frac{2}{(0.61 \times \frac{\pi}{4} \times 0.16 \times 2.51)}\)

  ≈ 12

where,

2 gal/min

\(= n \times C \times \frac{\pi}{4} \times d^{2} \times \sqrt{(2gH)}\)

Now,

\(n = \frac{2}{C \times \frac{\pi}{4} \times d^{2} \times \sqrt{(2gH)}}\)

  \(= \frac{2}{(0.61 \times \frac{\pi}{4} \times (0.4^{2}\ i\ n^2) \times \sqrt{(2 \times 32.2 \times H)})}\)

  \(= \frac{2}{(0.61 \times \frac{\pi}{4} \times 0.16 \times \sqrt{(64.4 \times H)})}\)

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If the content of T4: 0.ACC is copied into N7: 0 through N7:4 memory locations, this process is considered a "word-to-word transfer" (Option A)

In programming, T4:0 is a time base. Whenever it is set to 1.0, it converts to the timer that counts in seconds.

It is key to note that when enumerated as T4:0 ACC, it is ascribed as an Accumulator address.

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Answer:

It does not take into consideration what the responsible party knew about the law or regulation they violated. Environmental criminal liability is triggered through some level of intent.

In regards to whether an employee can be held legally liable for environmental violations, this statement is False.

This means that if an employee notices that a company is responsible for environmental violations, and does nothing about it, they could be held legally responsible for the violation as well.

In conclusion, this is true.

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The increase in energy from a reaction that was taken, deleted, aborted, positive, or negative is indicated by the change in enthalpy.

The quantitative characteristic that is transferred to a body or to a physical system in physics is energy, which is visible in the performance of labor as well as in the form of heat and light. Energy is a resource that is conserved; it can only be changed from one form to another and cannot be created or destroyed, according to the law of conservation of energy. The unit of measurement for energy in the International System of Units is the joule. Common types of energy include the kinetic energy of an object in motion, the potential energy held by an object, the elastic energy held in a solid object, the chemical energy related to chemical reactions, the radiant energy carried by electromagnetic radiation, and the internal energy held within a thermodynamic system.

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Answer:

D) AND gate.

Explanation:

Given that:

A certain printer requires that all of the following conditions be satisfied before it will send a HIGH to la microprocessor acknowledging that it is ready to print

These conditions are:

1. The printer's electronic circuits must be energized.

2. Paper must be loaded and ready to advance.

3. The printer must be "on line" with the microprocessor.

Now; if these conditions are met  the logic gate produces a HIGH output indicating readiness to print.

The objective here is to determine the basic logic gate used in this circuit.

Now;

For NOR gate;

NOR gate gives HIGH only when all the inputs are low. but the question states it that "a HIGH is generated and applied to a 3-input logic gate". This already falsify NOR gate to be the right answer.

For NOT gate.

NOT gate operates with only one input and one output device but here; we are dealing with 3-input logic gate.

Similarly, OR gate gives output as a high if any one of the input signals is high but we need "a HIGH that is generated and applied to a 3-input logic gate".

Finally, AND gate output is HIGH only when all the input signal is HIGH and vice versa, i.e AND gate output is LOW only when all the input signal is LOW. So AND gate satisfies the given criteria that; all the three conditions must be true for the final signal to be HIGH.

Answer:

This one is false

Explanation:

I just took a test on it..

Most hazardous waste can be disposed of in a landfill. Thus, the above statement is true. Thus, option (A) is correct.

A hazardous waste is a waste that has characteristics that make it unsafe or allow it to negatively impact the environment or human health.

Wastes classified as hazardous have characteristics that make them unsafe or potentially damaging to the environment or human health. Liquid, solid, confined gas, and sludge are all examples of hazardous wastes.

Any source that could potentially cause injury, damage, or unfavorable health impacts to someone or something is a hazard.

The majority of hazardous garbage can be dumped in landfills. So, the aforementioned claim is accurate. Therefore, it can be concluded that option (A) is correct.

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The algorithm for creating a cubic spline approximation in C involves creating arrays xi and yi, determining the nth data point, and creating n-dimensional arrays hi, alpha, l, mu, and z.

Calculating hi involves subtracting consecutive xi values.

Alpha[0] is set to 0 and calculated as alpha[i] = (3/hi[i]) * (yi[i+1] - yi[i]) - (3/hi[i-1]) * (yi[i] - yi[i]).

Calculating l, mu, and z is done using formulas.

Creating n-dimensional arrays c, b, and d is done by setting c[n] to 0 and iterating from n-1 to 0 to find c[i].

Using formulas, b[i] and d[i] are calculated. An evaluateSpline function is defined to evaluate the spline and return the corresponding y value.

The function is then used to plot the cubic spline over the interval x [0, 3] using the calculated arrays.

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Answer:

A power supply unit (PSU) converts mains AC to low-voltage regulated DC power for the internal components of a computer. Modern personal computers universally use switched-mode power supplies

Answer:

Volt is the SI (Standard International) unit of electrical potential of the..

Explanation:

Answer:

ee

Explanation:

This is an over the top question

The program requires a sequence control structure; First, we get input for the variables, and then use the formula to calculate the amount of calories burnt.

The program in python is as follows, where comments (in italics) are used to explain each line.

#This gets input for age, in years

age = int(input("Age (years): "))

#This gets input for weight, in pounds

weight = int(input("Weight (pounds): "))

#This gets input for heart rate, in beats per minutes

heart_rate = int(input("Heart Rate (beats per minutes): "))

#This gets input for time, in minutes

time = int(input("Time (Minutes) : "))

#This calculates the calories burnt for men

calories_man = ((age * 0.2017) - (weight * 0.09036) + (heart_rate * 0.6309) - 55.0969) * time / 4.184

#This calculates the calories burnt for women

calories_woman = ((age * 0.074) - (weight * 0.05741) + (heart_rate * 0.4472) - 20.4022 ) * time / 4.184

#This prints the calories burnt for men

print('Men: %0.2f calories' % calories_man)

#This prints the calories burnt for women

print('Women: %0.2f calories' % calories_woman)

Please note that the program does not check for valid inputs

See attachment for program output

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Answer:

24 i believe

Explanation:

Answer:

1.2 Newtons upwards

Explanation:

because the friction is opposite of the magnitude.

Answer:

Explanation:

Civil engineers have become experts in creating sustainable and environmentally friendly buildings and systems. Multiplied over many communities, the energy and emissions savings can make a real difference in the environment. Other life-improving functions can also make communities better places to live.Jul 19, 2017

The common workplace for both science and math pathways, with engineering and technology in laboratories and ships. Thus, option A is correct.

A workplace is given as the location or the place at which the employee are performing their jobs and tasks.

The science or technology-mediated employees are related to research where they perform the tests in laboratories, as well as the ships are the location for the engineering and the math candidates for the analysis of the studies and to perform the job.

Hence, the location in the workplace common for both engineering and technology candidates has been the laboratories and the ships. Thus, option A is correct.

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Answer:B

Explanation: Dead Grass more flammable than wood and Green grass contains water.

Answer:

or is the strongest evenger she hulk

Explanation:

?????????

Answer:

Thor!

Explanation:

In Thor: Ragnarok he beat the Hulk in order for Hulk to win thor had to be electrocuted and in Avengers: Endgame Thor is seen holding open the  "Floodgates" and withstanding the radiation from a dying star, also the fact that Thor is a god means that he is all powerful and the rightful heir to the throne to Asgard, plus the fact that he has defeated Loki multiple times a feat that not even the Hulk has done.

If x(t) = Vs(t) and y(t) = Vc(t), where Vs(t) is the input voltage and Vc(t) is the voltage across the capacitor, we can derive the differential equation relating the two.

In the RLC circuit, we have a resistor (R), an inductor (L), and a capacitor (C) cnnected in series.

Using Kirchhoff's voltage law, we can write the equation:

Vs(t)  VR(t) + VL(t) + VC(t)

Where VR(t) is the voltage across the resistor, VL(t) is the voltage across the inductor, and VC(t) is the voltage across the capacitor.

Since y(t) = Vc(t), we can rewrite the equation as:

Vs(t) = VR(t) + VL(t) + y(t)

ow let's express each component of the circuit in terms of its voltage and current.

\(VR(t) = IR(t) * RVL(t) = L * dI(t)/dtVC(t) = (1/C) ∫[0 to t] I(t') dt'\)

Substituting these expressions back into the equation, we have:

\(Vs(t) = IR(t) * R + L * dI(t)/dt + (1/C) ∫[0 to t] I(t') dt' + y(t)\)

Rearranging the equation and assuming ideal components, we get:

\(L * dI(t)/dt + IR(t) * R + (1/C) ∫[0 to t] I(t') dt' + y(t) = Vs(t)\)

Differentiating both sides of the equation with respect to time, we get:

\(L * d²I(t)/dt² + R * dI(t)/dt + (1/C) * I(t) + dy(t)/dt = dVs(t)/dt\)

This is the derived differential equation relating the input x(t) = Vs(t) and the output y(t) = Vc(t) for the given RLC circuit. If x(t) = Vs(t) and y(t) = I(t), where Vs(t) is the input voltage and I(t) is the current flowing through the circuit, we can derive the differential equation relating the two.

Using Kirchhoff's voltage law, we can write the equation:

\(Vs(t) = VR(t) + VL(t) + VC(t)\)

Since y(t) = I(t), we can rewrite the equation as:

\(Vs(t) = VR(t) + VL(t) + (1/C) ∫[0 to t] y(t') dt'\)

Now let's express each component of the circuit in terms of its voltage andcurrent.

\(VR(t) = IR(t) * RVL(t) = L * dI(t)/dtVC(t) = (1/C) ∫[0 to t] I(t') dt'\)

Substituting these expressions back into the equation, we have:

\(Vs(t) = IR(t) * R + L * dI(t)/dt + (1/C) ∫[0 to t] I(t') dt'\)

Differentiating both sides of the equation with respect to time, we get:

\(L * d²I(t)/dt² + R * dI(t)/dt + (1/C) * I(t) = dVs(t)/dt\)

This is the derived differential equation relating the input x(t) = Vs(t) and the output y(t) = I(t) for the given RLC circuit.

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i. The given metal has a crack of length 3.6 × 10−2 mm and the radius of curvature is 1.8 × 10−4 mm. The tensile stress of the metal is given as 20 MPa.

The maximum stress of the metal can be calculated by using the formula:
\(σ_max = σ_applied × (√(π × a))\)where,σ_max = maximum stressσ_applied = applied stressa = radius of curvature/2 = 1.8 × 10−4/2 = 9 × 10−5 mmThe value of a should be in meters, so we convert 9 × 10−5 mm to meters.
a = 9 × 10−8 m.
Substituting the given values,\(σ_max = 20 × 106 × (√(π × 9 × 10−8))σ_max = 94.76 MPa\)
Therefore, the maximum stress of the given metal is 94.76 MPa.

ii. The modulus of elasticity of the metal is given as 100 GPa and the specific surface energy is given as 3.5 J/m2.
The critical stress of the metal can be calculated by using the formula:
\(σ_c = 2 × γ × (√(π × a))\)/Ewhere,σ_c = critical stressγ = specific surface energyE = modulus of elasticitya = radius of curvature/2 = 1.8 × 10−4/2 = 9 × 10−5 mmThe value of a should be in meters, so we convert 9 × 10−5 mm to meters. a = 9 × 10−8 m.
Substituting the given values,\(σ_c = 2 × 3.5 × (√(π × 9 × 10−8))/100 × 109σ_c = 13.93 MPa\)

Therefore, the critical stress of the given metal is 13.93 MPa.

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Explanation:

Dempwolf created by John Augustus, Among the most prominent innovative solutions in Southern California Pennsylvania was established by Dempwolf with  brother Reinhardt or uncle's son Frederick entered the company of J.A. Dozens of structures in 10 states were engineered by Dempwolf.

Answer:

The answer is below

Explanation:

Given that:

ρ = 800 kg/m3, c = 600 J/kg-K,  k = 40 W/m-K, Initial temperature = Ti = 1150,

Environment temperature = T = 450 K, Final temperature = T∞ = 325 K

Diameter = 10 mm = 0.01 m, A = 6

The estimated time for cooling process (t) is given as:

\(t=\frac{\rho dc}{hA} ln\frac{T_i-T_\infty}{T-T_infty}=\frac{7800*0.01*600}{25*6} ln\frac{1150-325}{450-325}\\ \\t=589\ s\\t=0.1635\ h\)

The estimated cooling time is 589 s

Answer:

Car Payments. Making payments on your car is the biggest, most obvious expense of your vehicle. ...

Insurance. Insurance is another primary expense to consider when budgeting for a new car. ...

Gas. ...

Maintenance. ...

Fees & Taxes.

Explanation:

Answer:

Owning a car is expensive. Between the price of the vehicle, financing costs, insurance, taxes, and maintenance, owning one —let alone two — cars can drain your bank account quickly.

Explanation:

The magnitude of the velocity vector represents the object's current speed.The velocity vector points in the same general direction as the motion of the object.

The vector quantity velocity (v), denoted by the equation v = s/t, quantifies displacement (or change in position, s), over change in time (t).

A hanging mass of 25 kg will exert a force of:

25 * 9.81 = 254.25 Newtons on the string

Thus, during rotation, the force exerted should remain less than this. Force on an object in circular motion is given by:

F = (m * v^2) / r

F = mv2/r = 3.0(v2)/0.8 = (25)9.8 = 245

v = sqrt(245 x 0.8 / 3.0) = 8.1 m/s

v is from 0 to 8.1 m/s

Thus, the magnitude of the velocity should not exceed 8.1  meters per second.

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Answer:

10.007

Explanation:

Assuming we have to find out the compression ratio of the engine

Given information

Cubic capacity of the engine, V = 245 cc

Clearance volume, V_c = 27.2 cc

over square-ratio = 1.1

thus,

D/L = 1.1

where,

D is the bore

L is the stroke

Now,

Volume of the engine V =\(\frac{\pi}{4} D^2L\)

plugging values we get

245 = \(\frac{\pi}{4} D^3/1.1\)

Solving we get D =7 cm

therefore,  L= 7/1.1 =6.36 cm

Now,

the compression ratio is given as:

r =(V+V_c)/V_c

on substituting the values, we get

r = (245+27.2)/27.2 =10.007

Hence, Compression ratio = 10.007