Answer:
294.524 m^3
Explanation:
The volume of a cylinder is given by the formula ...
V = πr^2h
For a radius of 2.5 m and a length of 15 m, the volume is ...
V = π(2.5 m)^2(15 m) = 93.75π m^3 ≈ 294.524 m^3
The volume is about 294.52 cubic meters.
Paragraph Styles Question 4 A condenser is used to condense substances from gaseous to liquid state, typically by cooling it. In this problem, a stream of humid air (58.0 mol % water), 8.8 mol % O₂ and the remaining N₂ enters a condenser at 150°C. 80% of the water vapor in the humid air is condensed and removed as pure liquid water. Both gas and liquid phase streams leave the condenser at 30°C. Nitrogen (N₂) gas leave the condenser at the rate of 5.18 mol/s. (a) Draw and label a flowchart of the process. (4 marks) 1 (b) Solve the total flow rate of the feed stream and both streams leaving the condenser. (c) Taking [N₂ (g, 30°C), O2 (g, 30°C), and H₂O (g, 30°C)] as reference for enthalpy calculations, prepare and fill in the inlet-outlet enthalpy table and calculate the heat transferred to or from the condenser in kilowatts (Neglect the effects of pressure changes on enthalpies)
(a) Flowchart: A condenser process flowchart is provided, illustrating the inputs and outputs of the humid air stream, O₂, N₂, and the condensed liquid water. (b) Total flow rate: The total flow rate of the feed stream entering the condenser is 5.296F mol/s, considering the flow rates of water vapor, O₂, and N₂. (c) Enthalpy and heat transfer: The enthalpy changes for water vapor and O₂ are calculated, resulting in a heat transfer of -0.072 kF kW, indicating heat removal by the condenser. the heat transferred by the condenser is -0.072 kF kW.
(a) Flowchart:
(b) Total flow rate of the feed stream:
The flow rate of N2 leaving the condenser is given as 5.18 mol/s.
The flow rate of water vapor entering the condenser is 58.0 mol% of F.
80% of the above water vapor is condensed and removed, leaving 20% remaining.
So, 20% of the above water vapor remaining in the humid air after condensation is 0.116F mol/s.
The flow rate of O2 is given as 8.8 mol% of F.
The total flow rate of the feed stream is the sum of the flow rates of water vapor, O2, and N2:
Total flow rate = Flow rate of water vapor + Flow rate of O2 + Flow rate of N2
= 0.116F + 0.088F + 5.18
= 5.296F mol/s
(c) Inlet-Outlet Enthalpy Table:
To calculate the heat transferred by the condenser, we need to determine the enthalpy changes for water vapor (H3 to H4) and O2 (H5).
The enthalpy change for water vapor can be calculated as:
ΔH_vap = Enthalpy of water vapor at 30°C - Enthalpy of water vapor at 150°C
= [40.657 + 0.119 × (30 - 0)] - [40.657 + 0.119 × (150 - 0)]
= -13.607 kJ/kmol
Enthalpy of water leaving the condenser (H4) can be calculated as:
H4 = Enthalpy of water vapor at 30°C = 40.657 kJ/kmol
Enthalpy of O2 leaving the condenser (H5) can be taken as:
H5 = Enthalpy of O2 at 30°C = 0.102 kJ/kmol
The heat transferred by the condenser (q) can be calculated as:
q = Total flow rate × ΔH
= (5.296F mol/s) × (-13.607 kJ/kmol) × 10⁻³ kW/J
= -0.072 kF kW (where kF is the constant conversion factor 10⁶)
Therefore, the heat transferred by the condenser is -0.072 kF kW.
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What is a mechanical advantage?
Answer:
B
Explanation:
A Mechanical Advantage is when you use a piece of machinery to help you do work, and it is an easy advantage.
Which is a limitation of using cellulose?
its lack of mass production
its lack of biodegradability
3
its harm to landfills
O its high cost to recycle
Answer:
Its lack of mass production
Explanation:
Your Welcome;)
The limitation of using cellulose is its lack of mass production.
Cellulose is a polymer of glucose. It is obtained from glucose by condensation polymerization to yield a long chain.
Cellulose materials have a high potential of being quite useful as important materials for diverse applications.
However, the problem with cellulose materials is that they can not really be mass produced. This limitation has long encumbered the possibility of using cellulose materials for various applications in material science.
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Choose the option below that is not necessarily true of a system at equilibrium.
ΔG∘=0
ΔG∘=−RTlnK
Q=K
ΔG=0
This statement is not necessarily true at equilibrium. ΔG = 0 indicates that the system is at thermodynamic equilibrium, where there is no tendency for the reaction to proceed in either direction.
The option that is not necessarily true of a system at equilibrium is: ΔG = 0 At equilibrium, the Gibbs free energy change (ΔG) of a system is not necessarily zero. The other three options are commonly associated with equilibrium conditions. ΔG∘ = 0: This is true for a system at standard conditions (ΔG∘ represents the standard Gibbs free energy change), but it does not hold true for all equilibrium situations. ΔG∘ = -RTlnK: This equation is the standard Gibbs free energy change equation at equilibrium, where ΔG∘ represents the standard Gibbs free energy change, R is the gas constant, T is the temperature, and K is the equilibrium constant.
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Describe What would happen to the temperature of boiling water if you added energy?
When thermal energy is added to a substance, its temperature increases, which can change its state from solid to liquid (melting), liquid to gas (vaporization), or solid to gas (sublimation).
If the liquid is a mixture, as the more volatile components boil off, the boiling point rises, so adding energy causes the temperature to go up. If you add enough energy, all the liquid evaporates, so there is no liquid temperature
An eagle carrying a trout flies above a lake along a horizontal path. The eagle drops the trout from a height of 6.1 m. The fish travels 7.9 m horizontally before hitting the water.
What is the velocity of the eagle? Round at the end of the calculation to the nearest tenth.
Answer:
7.1 m/s
Explanation:
The fish goes 6.1 m vrtically....calc the time to fall this far
d = 1/2 a t^2
6.1 = 1/2 ( 9.81)(t^2) shows t = 1.12 sec
It flies 7.9 m in 1.12 sec = 7.9/1.12 = 7.1 m/s
Answer: 7.1 m/s
Explanation:
A whale swims at a constant speed of 8 m/s for 17 s. What distance did the whale travel in km?
Answer:
0.136 kmExplanation:
whale speed = 8 m/s for 17 sec.
find distance traveled in km
distance = velocity x time
= 8 m/sec. x 17 sec.
= 136 meters x 1 km
1000 meters
= 0.136 km
which of the following is the best example of an object being absorbing light
Lyla walks three times per week for 45 minutes at a speed of 4.0 miles per hour. She wants to increase her time what should she do
Answer:
C. Walk four times per week
Explanation:
If she wants to increase her time then, she has to walk four times per week.
What is speed?The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is a meter/second. The generally considered unit for speed is a meter per second.
The mathematical expression for speed is given by
speed = total distance /Total time
As given in the problem Lyla walks three times per week for 45 minutes at a speed of 4.0 miles per hour. She must walk four times a week if she wants to extend her time.
Thus, the correct answer is option C.
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The question is incomplete, the complete question is,
Lyla walks three times per week for 45 minutes at a speed of 4.0 miles per hour. She wants to increase her time. What should she do?
A. Walk at 4.5 miles per hour.
B. Walk for 50 minutes.
C. Walk four times per week.
D. Walk up and down more hills.
the gauge pressure of a pneumatic cylinder reads 50lb/in^2. assume standard atmospheric pressure(14.7 psi). absolute pressure is 64.7 before and after. what is the volume in the cylinder after the gas is compressed
The new volume of the cylinder after the gas is compressed is 7.03 cubic inches.
Measure atmospheric pressure.
The pressure the atmosphere is exerting at a certain location is known as atmospheric pressure. Normal measurement is done at 14.7 psi, or sea level.
Atmospheric pressure = 14.7 psi
Figure out the gauge pressure.
Gauge pressure = 50 lb/in2
The absolute pressure should be calculated.
Absolute pressure = 64.7 psi
Determine the cylinder's new volume.
New volume = (Absolute pressure - Atmospheric pressure) / Gauge pressure
New volume = (64.7 - 14.7) / 50
New volume = 7.03 cubic inches
Hence, the cylinder's new volume is 7.03 cubic inches.
Complete Question:
What is the volume of the cylinder after the gas is compressed if the gauge pressure of the pneumatic cylinder reads 50lb/in^2 and the absolute pressure is 64.7psi before and after?
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Describes depolarizing vs nondepolarizing neuromuscular blockers
Acetylcholine and non-depolarizing blockers battle it out for receptors in order to function. They assist with surgery and mechanical ventilation. Depolarizing substances.
On the other hand, result in prolonged activation and consequent desensitisation of the receptors.
Non-depolarizing neuromuscular blockers (nNMBs) are given as adjuvant therapy in the management of critically sick patients as well as as primary therapy to facilitate endotracheal intubations. nNMBs (rocuronium, vecuronium, pancuronium, atracurium, cisatracurium, mivacurium) are primarily used during routine and emergency intubations to facilitate airway management and lower the risk of laryngeal injury. This activity describes the indications, mode of action, administration techniques, significant adverse effects, contraindications, monitoring, and toxicity of nNMBs so that healthcare professionals can guide patient therapy towards the best results possible during anaesthesia and other medical procedures where nNMBs are beneficial therapeutically.
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Which part of the scapula articulates with the clavicle?.
The part of the scapula that articulates with the clavicle is called the acromion process. The acromion process is a bony projection located at the lateral end of the scapula, and it forms a joint called the acromioclavicular joint (AC joint) with the medial end of the clavicle. This joint allows for movement and stability between the scapula and the clavicle, contributing to the overall mobility of the shoulder.
In addition to the acromion process, there is another part of the scapula that articulates with the clavicle. It is called the lateral end of the clavicle. The lateral end of the clavicle forms a joint called the sternoclavicular joint with the medial end of the clavicle. This joint connects the clavicle to the sternum and allows for movement and stability of the shoulder girdle.
To summarize, the scapula articulates with the clavicle at two different joints: the acromioclavicular joint (AC joint) formed by the acromion process of the scapula and the medial end of the clavicle, and the sternoclavicular joint formed by the lateral end of the clavicle and the sternum. These joints play a crucial role in shoulder movement and stability.
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Was Michael Jean Cazabon a local or regional artist?
Answer:
artist
Explanation:
Una cuerda de 20 pies se estira entre dos arboles. Un peso W cuelga del centro de la cuerda hace que el punto medio de la misma y baja 2 pies. Si la tensión resultante en la cuerda es de 200 lb,¿cual es la manigtud de la masa?
Answer:
La magnitud de la masa del peso es 78.447 libras-masa.
Explanation:
La tensión es una fuerza de reacción de la cuerda causada por la acción de una fuerza externa. En este caso, esa fuerza externa es el peso que cuelga en el centro de la cuerda. Abajo hemos adjuntado una representación simplificada del enunciado.
Por las leyes de Newton, tenemos la siguiente ecuación de equilibrio conformada por tres fuerzas:
\(\vec T_{1} + \vec T_{2} + \vec W = (0, 0)\, [N]\) (1)
Donde:
\(\vec T_{1}\), \(\vec T_{2}\) - Tensiones a cada lado de la cuerda, en newtons.
\(\vec W\)- Peso, en newtons.
Si sabemos que \(\vec T_{1} = T\cdot (\cos \alpha, \sin \alpha)\), \(\vec T_{2} = T\cdot (-\cos \alpha, \sin \alpha)\) y \(\vec W = W\cdot (0, -1)\), entonces tenemos la siguiente ecuación vectorial:
\(T\cdot (\cos \alpha, \sin \alpha) + T\cdot (-\cos\alpha, \sin \alpha) + W\cdot (0, -1) = (0,0)\)
\(T\cdot (0, 2\cdot \sin \alpha) = W\cdot (0, 1)\)
Esto permite reducir la anterior expresión a una fórmula escalar:
\(2\cdot T\cdot \sin \alpha = W\)
Donde \(\alpha\) es el ángulo de inclinación de la cuerda, medido en grados sexagesimales.
El ángulo de inclinación de la cuerda se determina mediante la siguiente fórmula trigonométrica inversa es:
\(\alpha = \tan^{-1} \left(\frac{2\,ft}{10\,ft}\right)\)
\(\alpha \approx 11.310^{\circ}\)
Si conocemos que \(\alpha \approx 11.310^{\circ}\) y \(T = 200\,lbf\), entonces la magnitud del peso es:
\(W = 2\cdot (200\,lb)\cdot \sin 11.310^{\circ}\)
\(W \approx 78.447\,lbf\)
En el Sistema Imperial, las fuerzas son medidas en forma gravitacional, entonces la magnitud de la fuerza gravitacional del peso equivale a la magnitud de su masa. En síntesis, la magnitud de la masa es \(78.447\,lbm\).
La magnitud de la masa del peso es 78.447 libras-masa.
what is the wavelength in picometers of light with a frequency of 9.3 × 1018 hz?
The wavelength in picometers of light with a frequency of 9.3 × 1018 hz would be 32 pm.
How is frequency related to wavelength?Wavelength is the separation between a wave's starting point and its ending position. The frequency is the quantity of waves passing through a spot every second.
Wavelength and frequency have a connection to energy just as they do to light. Higher frequency and shorter wavelengths are correlated with more energy. Hence, lower energy is produced when the wavelengths are longer and the frequency is lower.
Indirect proportionality exists between frequency and wavelength. Greater wavelengths result in lower frequencies, and vice versa. The relationship between frequency and wavelength is explained by the fact that the speed of a wave is equal to the product of these two numbers.
Let the equation be v = c/λ
Frequency of 9.3 × 1\(0^{18\)
9.3 × 1\(0^{18\) = 3.00*1\(0^8\) / λ
simplifying the equation, we get
λ = 3.001\(0^8\) / 9.3 × 1\(0^{18\)
= 3.2 1\(0^{25\) m 1pm/ 1\(0^{-12\)
= 3.2 1\(0^{37\)
= 32 pm
Therefore, the wavelength in picometers of light with a frequency of 9.3 × 1018 hz would be 32 pm.
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50 points due tomorrow!!!
A person walks 100 m North, 200 m South, 150 m South, 50 m North, 75 m North, 400 m South, and 25 more meters South in 500 seconds...
Determine the person's
Show work for all of these and report all results to the tenths place...
4. Distance
5. Displacement
6. Speed
7. Velocity
8. Determine how long it should theoretically take this person to walk a metric mile.
9. If it takes the person 880s to actually walk a metric mile, determine the person's %error.
10. Determine the acceleration of a Porsche 911 GT3 in mph/s to the tenths place.
11. Determine how long it should take that Porsche to reach its top speed if it starts from 60 mph?
Answer:
4.
Distance:
Total distance traveled is the sum of the distances for each leg of the journey:
Distance = 100 + 200 + 150 + 50 + 75 + 400 + 25 = 1000 m
Therefore, the person traveled a total distance of 1000 m.
5.
Displacement:
Displacement is the straight-line distance from the starting point to the ending point, taking into account direction.
To find the displacement, we need to add up all the distances traveled in the North direction and subtract the distances traveled in the South direction:
Displacement = (100 + 50 + 75) - (200 + 150 + 400 + 25) = -550 m
The negative sign indicates that the person ended up 550 m South of the starting point.
6.
Speed:
Speed is the distance traveled divided by the time it took to travel that distance:
Speed = Distance / Time
The total time taken is 500 seconds, and the total distance traveled is 1000 m, so:
Speed = 1000 / 500 = 2 m/s
Therefore, the person's average speed was 2 m/s.
7.
Velocity:
Velocity is the displacement divided by the time it took to travel that distance:
Velocity = Displacement / Time
The displacement is -550 m, and the total time taken is 500 seconds, so:
Velocity = -550 / 500 = -1.1 m/s
The negative sign indicates that the person was traveling Southward.
Therefore, the person's average velocity was -1.1 m/s.
8.
Time to walk a metric mile:
A metric mile is 1609.34 m.
The person's average speed was 2 m/s, so the time it should take to walk a metric mile is:
Time = Distance / Speed = 1609.34 / 2 = 804.67 seconds
Therefore, it should take the person 805 seconds or 13 minutes and 25 seconds to walk a metric mile.
9.
Percent error:
The actual time taken to walk a metric mile was 880 seconds. The percent error is:
% Error = [(Theoretical Time - Actual Time) / Theoretical Time] x 100%
% Error = [(805 - 880) / 805] x 100% = -9.3%
The negative sign indicates that the actual time taken was faster than the theoretical time. The percent error is 9.3%.
10.
Acceleration of a Porsche 911 GT3:
The acceleration of a Porsche 911 GT3 is reported to be 0-60 mph in 2.7 seconds.
To convert this to mph/s, we need to divide the change in velocity (60 mph) by the time (2.7 s):
Acceleration = 60 / 2.7 = 22.2 mph/s
Therefore, the acceleration of a Porsche 911 GT3 is 22.2 mph/s.
11.
Time to reach top speed:
The top speed of a Porsche 911 GT3 is reported to be 198 mph.
Starting from 60 mph, the change in velocity required to reach the top speed is:
Change in velocity = 198 - 60 = 138 mph
To find the time it takes to reach this change in velocity, we can use the following equation:
Change in velocity = Acceleration x Time
Solving for time:
Time = Change in velocity / Acceleration = 138 / 22.2 = 6.2 seconds
Therefore, it should take the Porsche 911 GT3 6.2 seconds to reach its top speed if it starts from 60 mph.
Surface tension of aqueous solution of polymers A, B, C and D are respectively 75 dynes/cm, 72 dynes / cm, 68 dynes/ cm and 64 dynes/cm. Which of these polymers will have the most tendency to interact with an anionic surfactant such as SDS?
Choices:
O Polymer A
O Polymer B
O Polymer C
O Polymer D
The polymer with the highest surface tension, in this case, is Polymer A with a surface tension of 75 dynes/cm. Therefore, Polymer A will have the most tendency to interact with an anionic surfactant such as SDS.
Surface tension is a measure of the cohesive forces between molecules at the surface of a liquid.
A higher surface tension indicates stronger intermolecular forces and greater resistance to disruption of the liquid's surface.
Anionic surfactants, such as SDS (sodium dodecyl sulfate), have a negatively charged hydrophilic head group. They are attracted to positively charged or polar surfaces, promoting adsorption and reducing surface tension.
Since Polymer A has the highest surface tension among the given polymers, it suggests that it has stronger cohesive forces and a higher degree of interaction between its molecules.
This increased tendency to interact makes Polymer A more favorable for the adsorption of an anionic surfactant like SDS.
Polymers B, C, and D have progressively lower surface tensions, indicating weaker intermolecular forces and reduced interaction with anionic surfactants compared to Polymer A.
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A simple harmonic oscillator has a mass m=2.0 kg and a spring constant k=800 N/m.a) What is the frequency of oscillations?b) If the oscillator has a maximum speed of v=10.0 m/s, what is the maximum oscillation amplitude?c) What length would a simple pendulum need to be in order to oscillate at the same frequency?
a)
In order to calculate the frequency of oscillations of a simple harmonic oscillator, first let's calculate the period, using the formula:
\(\begin{gathered} T=2\pi\sqrt[]{\frac{m}{k}} \\ T=2\pi\sqrt[]{\frac{2}{800}} \\ T=2\pi\sqrt[]{\frac{1}{400}} \\ T=2\pi\cdot\frac{1}{20} \\ T=\frac{\pi}{10}=0.31416\text{ s} \end{gathered}\)Since the frequency is the inverse of the period, we have:
\(\begin{gathered} f=\frac{1}{T} \\ f=\frac{1}{\frac{\pi}{10}} \\ f=\frac{10}{\pi}=3.183\text{ Hz} \end{gathered}\)b)
In order to calculate the maximum oscillation amplitude given the maximum speed, let's use the formula below:
\(\begin{gathered} v_{\max }=X\sqrt[]{\frac{k}{m}} \\ 10=X\cdot\sqrt[]{\frac{800}{2}} \\ 10=X\cdot20 \\ X=\frac{10}{20}=0.5\text{ meters} \end{gathered}\)c)
The formula for the pendulum frequency is:
\(\begin{gathered} f=\frac{1}{T} \\ f=\frac{1}{2\pi\sqrt[]{\frac{L}{g}}} \\ f=\frac{\sqrt[]{\frac{g}{L}}}{2\pi} \end{gathered}\)Then, for f = 3.183 and g = 9.81, we have:
\(\begin{gathered} 3.183=\frac{\frac{\sqrt[]{9.81}}{\sqrt[]{L}}}{2\pi} \\ \frac{\sqrt[]{9.81}}{\sqrt[]{L}}=3.183\cdot2\pi \\ \frac{3.132}{\sqrt[]{L}}=20 \\ \sqrt[]{L}=\frac{3.132}{20} \\ \sqrt[]{L}=0.1566 \\ L=0.3957 \end{gathered}\)So the length is 0.3957 m or 39.57 cm.
5. There is a bell at the top of a tower that is 45 m high. The bell's mass is 200 kg. The bell has energy. Calculate it.
45000
900000 J
9000 J
88200 J
Answer:
Explanation:
Since the bell is at rest in an elevated position, we can assume that it only has potential energy.
U=mgh is the formula for potential energy where U=potential energy, m= mass, g=acceleration due to gravity, and h=height.
Plug in known variables....
U=200kg*9.8m/s^2*45m
U=88200 joules of potential energy or letter D.
1. A point charge of 10 nC is located at (2, 10, 3) while line Y= 2, Z=2 carries a uniform charge of 5 nc/m.
Estimate the Potential V at (4, 5, 6) taking the V = 0 V at (0,0,0)
The estimated potential at point P (4,5,6) taking V = 0 V at (0,0,0) is 12.204 V.
Electric potential at point P due to a point charge q is given as; V=kq/r Where V is the electric potential, q is the charge of the particle producing electric potential, k is the Coulomb's constant and r is the distance between the point charge and the point where electric potential is to be determined. At point P (4,5,6), the distance from the point charge of 10nC to P is given as;
√[(4−2)^2+(5−10)^2+(6−3)^2] = √54 = 7.348m.
So, the potential due to the point charge at point P is;
V1=kq/r1 = 9×10^9 × 10 × 10^−9/7.348 V1=12.2 V.
Now, for the potential at point P due to the line of charge, we will need to first calculate the linear charge density (λ) of the line of charge.λ=q/l, Where λ is the linear charge density, q is the total charge on the line and l is the length of the line. For the line of charge Y=2, Z=2, the total charge is given as; Q=λlWhere Q is the total charge and l is the length of the line. Since the line is infinite, we cannot use the length of the line, we will use the length of the portion of the line from (0,2,2) to (0,-2,2) which is 4 units long. We can then find the length of the portion of the line from (-∞,2,2) to (0,2,2) which is half of the entire line. Using the Pythagoras theorem, the length of this portion is given by;
√[4^2+(2−2)^2+(2−2)^2] = √16 = 4m. Then the linear charge density is;
λ=Q/l = 5×10−9 C/4m = 1.25×10−9 C/m. The electric potential at point P due to the line of charge can be determined using the equation below; V2=λ/2πε0. ln(b/a) Where V2 is the electric potential, λ is the linear charge density, ε0 is the permittivity of free space, b is the distance between point P and the end of the line of charge and a is the distance between point P and the other end of the line of charge. To calculate V2, we will need to find b and a. The distance between point P and the end of the line of charge is given as;
√[(0−4)^2+(2−5)^2+(2−6)^2] = √45 = 6.708m.
The distance between point P and the other end of the line of charge is given as;
√[(0−4)^2+(−2−5)^2+(2−6)^2] = √74 = 8.602m.
So, V2 is; V2=1.25×10−9/2π×9×10^9 ln(8.602/6.708) V2=0.004 V
The total electric potential at point P is the sum of the electric potential due to the point charge and that due to the line of charge.
Thus; VT=V1+V2 = 12.2+0.004 = 12.204 V
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Since 1901, global surface temperatures have risen at an average rate of 0.13oF every ten years. In which way could the average increase in global temperatures influence Earth?
Answer:
The correct answer is "By increasing the amount of flooding because of rising sea levels".
Explanation:
The global temperature chart reflects an approximation across the whole planet's atmosphere. Owing to relatively stable entertain as well as the difficult-to-predict wind but instead, weather patterns structures, the temperature changes we perceive domestically as well as in brief periods could vary dramatically.Doubling the volume of floods due to rising water levels might also significantly affect the ordinary increase in energy consumption on Earth.honeybees acquire a charge while flying due to friction with the air. a 100 mg bee with a charge of 23 pc experiences an electric force in the earth's electric field, which is typically 100 n/c, directed downward.
Therefore, the electric force experienced by the 100 mg bee with a charge of 23 pc in the Earth's electric field is 2.3 × 10⁻¹⁰newtons, directed downward.
When a honeybee flies through the air, it acquires a charge due to friction with the air. In this case, the bee has a charge of 23 pc (picocoulombs) and weighs 100 mg (milligrams). The bee experiences an electric force in the Earth's electric field, which is typically 100 N/C (newtons per coulomb), directed downward.
To calculate the electric force experienced by the bee, we can use the formula:
Electric force = charge × electric field
Substituting the given values into the formula, we have:
Electric force = (23 pc) × (100 N/C)
Now, we need to convert the charge from picocoulombs to coulombs. One picocoulomb is equal to 10^-12 coulombs. Therefore, 23 pc is equal to 23 × 10⁻¹² C.
Substituting the converted charge value into the formula, we have:
Electric force = (23 × 10⁻¹² C) × (100 N/C)
Simplifying the calculation, we get:
Electric force = 2.3 × 10⁻¹⁰ N
Therefore, the electric force experienced by the 100 mg bee with a charge of 23 pc in the Earth's electric field is 2.3 × 10⁻¹⁰newtons, directed downward.
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which planet has a moon called titan?
Answer:
Titan is the largest moon in Saturrn
Explanation:
And only Jupiter's moon Ganymede is larger by 2 percent
A cyclist races around a circular track at the constant speed of 20 m/s. The radius of the track is 50 m. The acceleration of the cyclist is
A. zero.
B. 8 m/s2, toward the center of the track.
C. 10 m/s2, downward.
D. 20 m/s2, in the direction of travel.
The correct option is A. zero.
Acceleration is a vector quantity that represents the rate of change of an object's velocity with respect to time. It is a physical quantity that measures how much the speed and/or direction of an object changes per unit time.Acceleration and velocity in circular motion A cyclist races around a circular track at a constant speed of 20 m/s. As the cyclist is moving in a circle, it has a velocity vector that is constantly changing in direction. As a result, the cyclist has an acceleration.The acceleration of an object in circular motion is always directed towards the center of the circle. Because the cyclist is moving in a circle, the direction of the cyclist's acceleration is towards the center of the circle.The magnitude of the acceleration of an object moving in a circle is given by the following equation:a = v2/r where
:a is acceleration is velocity is the radius of the circle For the given cyclist, the speed is given as 20 m/s and the radius of the circular track is 50 m. Using the equation, we geta = (20 m/s)2/50 m= 400/50= 8 m/s2Thus, the acceleration of the cyclist is 8 m/s2, directed towards the center of the circular track.
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The inner planets have a smaller diameter than the outer planets.
True
False
Answer:true
Explanation:
A runner covers the last straight stretch of a race in 8s.During that time he speeds up from 7 m/s to 9m/s. What is the acceleration
Given
Time taken is t=8 s.
The initial speed is u=7 m/s
The final speed is v=9 m/s.
To find
The acceleration
Explanation
We know the acceleration is the ratio of the difference in the speed to the time taken.
Thus,
\(\begin{gathered} a=\frac{v-u}{t} \\ \Rightarrow a=\frac{9-7}{8} \\ \Rightarrow a=\frac{2}{8}=\frac{1}{4}=0.25\text{ m/s}^2 \end{gathered}\)Conclusion
The acceleration is
\(0.25\text{ m/s}^2\)What’s an example of potential energy? I WILL CROWN YOU PLS HELP
A
Water behind a dam
B
A dart stuck in a dartboard
C
Plants using photosynthesis
D
A cow chewing grass
A. Water behind a dam an example of potential energy
What are some illustrations of kinetic and potential energy?The energy an individual or an item has as a result of motion—in this case, the motion of the falling apple—is known as kinetic energy. Potential energy, which exists in a bike that is parked on top of a hill, is converted to kinetic energy when you start riding it downhill.
Kinetic energy may be observed in anything that moves around the house. This might happen when a glass breaks after falling off the counter, a fan circulates air on a warm day, or a cue ball rolls on a pool table. Kinetic energy is used by on-turning electrical equipment as well as by individuals moving around the house.
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Yash traveled 8 miles West and then 12 miles North, How far is he from his starting point?
A. 10 miles
B. 14.42 miles
C. 20 miles
D. 8.94 miles
(iii) Suggest why the lamp is safe to use, even though its cable only has two wires.
Answer:
it is safe because the make it so that the wires use a small amount of enerygy and electricity at the same time. this is safe because it will make it so that the eletrical current is not doverwelming the wires.
The field between two charged parallel plates is kept constant. If the two plates are brought closer together, the potential difference between the two plates.
Since the electric field between the plates is constant, If the two plates are brought closer together, the potential difference between the two plates decreases
The relation between potential difference and the electric field is given by ΔV = E.d
Since the electric field is maintained constant, the potential difference is directly inversely proportional to the distance between the plates.
The potential difference between the plates will therefore likewise decrease if the distance between the plates is reduced, we will state in this case.
The energy required to move a unit charge, or one coulomb, from one point to the other in a circuit is measured as the potential difference between the two points. Potential difference is measured in volts or joules per coulomb.
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