Consider a 2D plate with surface area A = 100 cm2
that we charge with a certain
charge Q. How large does Q need to be for the field of the plate to levitate a load of m = 100 kg
that has charge q = 25 µC?

The current flowing in the 2Ω and 1Ω is 1.14 A and the current flowing in the 3Ω and 4Ω is 0.286 A.

The value of the current in each resistor is calculated by applying Kirchoff voltage law as follows;

The total voltage in loop 1 is calculated as;

2 + 4 - I₁R₁ - (I₁ - I₂)R₂ - I₁R₃ = 0

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

The current flowing in loop 2 is calculated as;

I = V/R

I₂ = ( 6 V - 4 V ) / (3 + 4)

I₂ = 0.286 A

The value of the current flowing in loop 1 is calculated as;

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

6 - 2I₁ - 3(I₁ - 0.286) - 1₁ = 0

6 - 3I₁ - 3₁ + 0.858 = 0

-6I₁ = -6.858

I₁ = 6.858 / 6

I₁ = 1.14 A

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Answer:

No, positive charges cannot be liberated by the photoelectric effect.

Explanation:

The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

First, we shall list out the given parameters from the question. This is shown below:

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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ANSWER AND EXPLAINATION:
To calculate the impulse imparted on the baseball, we can use the impulse-momentum principle, which states that the impulse experienced by an object is equal to the change in momentum of the object. Mathematically, it can be expressed as:

Impulse = Change in momentum

The momentum of an object is given by the product of its mass and velocity:

Momentum = mass × velocity

In this case, the baseball has an initial mass of 0.14 kg and an initial velocity of 32 m/s. After being struck by the bat, it travels in the opposite direction at a velocity of 49 m/s.

Therefore, the change in momentum is given by:

Change in momentum = (mass × final velocity) - (mass × initial velocity)

Change in momentum = mass × (final velocity - initial velocity)

Change in momentum = 0.14 kg × (49 m/s - (-32 m/s))

Change in momentum = 0.14 kg × (49 m/s + 32 m/s)

Change in momentum = 0.14 kg × 81 m/s

Change in momentum = 11.34 kg·m/s

So, the impulse imparted on the baseball is 11.34 kg·m/s.

An insulating vessel contains 80 g of a block of ice at -12 °C. If 450 g of water at 60 °C is added to the ice in the vessel, Energy required for complete melting = \(80 g X (3.33 X 10^3 J/kg)\).

To determine whether the ice will soften absolutely and calculate the final temperature of the system, we need to do not forget the strength transferred among the ice and water at some stage in the procedure.

(i) To decide if the ice will melt completely, we need to examine the energy won by using the ice to the electricity required for complete melting.

Energy received by way of the ice = mass of ice × particular heat capacity of ice × alternate in temperature

Energy won by using the ice = eighty g × 2100 J/(kg·°C) × (final temperature - (-12°C))

Energy required for complete melting = mass of ice × latent warmth of fusion of ice

Energy required for whole melting = 80 g × (3.33 × 10^3 J/kg)

If the strength received via the ice is extra than or same to the electricity required for entire melting, the ice will soften completely.

(ii) To calculate the very last temperature of the gadget, we want to keep in mind the power transferred between the ice and water.

Energy won by the water = mass of water × unique heat ability of water × trade in temperature

Energy received by using the water = 450 g × 4200 J/(kg·°C) × (final temperature - 60°C)

Since electricity is conserved inside the machine, the power gained by means of the ice and water need to be identical:

Energy gained through the ice = Energy won by the water

Using the equations above, we will installation the following equation:

80 g × 2100 J/(kg·°C) × (very last temperature - (-12°C)) = 450 g × 4200 J/(kg·°C) × (very last temperature - 60°C)

Thus, this the final temperature of the system.

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If the given compound has a molar mass of 123.22 g/mol then, SrS is the molecular formula of a substance that has this molar mass. Therefore, option c is the correct answer according to the given information.

The molecular formula is defined as the number of atoms present in the molecules of a chemical compound when the two molecules of different substances are combined together. The molecular mass is the mass of a given molecule measured in daltons.

The molar mass of Strontium = 87.22g/mol

The molar mass of Sulfur = 32 g/mol.

The total molecular mass of these two combined compounds

= Strontium + Sulfur = SrS

SrS = 87.22 + 32 = 123.22g/mol.

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The complete question is-

A compound has a molar mass of 123.22 g/mol. what is the molecular formula of a substance that has this molar mass?

A. CoH4

B. PSF3

C. SrS

D. ZrO2

Answer:

215.5 m/s

Explanation:

Given that:

the wavelength λ = 668 km

distance (d) = 3180 km

time t = 4.81 hr

\(a) speed (v) =\dfrac{distance}{time}\)

\(speed (v) =\dfrac{3180}{4.1}\)

\(speed (v) =775.61 \ km/h\)

\(speed (v) =(\dfrac{775.61\times 1000 }{3600}) \ m/s\)

\(speed(v) = 215.5 \ m/s\)

The frequency is:

\(f = \dfrac{v}{\lambda}\)

\(f = \dfrac{215.5 }{668 \times 1000}\)

\(f = 3.226 \times 10^{-4} \ Hz\)

c)

The period:

\(T = \dfrac{1}{f}\)

\(T = \dfrac{1}{3.226 \times 10^{-4}}\)

T = 3099.8 seconds

Answer:

B. Ecosystem B, because its high species diversity could have resulted from increased competition among its members.

Explanation:

This is because, in the  ecosystem with varying level of biodiversity, Ecosystem B has medium level of species diversity found in them with High medium level of habitat diversity which causes increasing competitions among them.

Answer:

I am pretty sure it is C

Explanation:

It can be found all over the universe

Since no work is done, the power exerted is zero. Therefore, the man exerts no power on the wall.

In physics, force is defined as any action that can change the motion of an object or cause an object to accelerate. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction. The unit of force in the International System of Units (SI) is the Newton (N), which is defined as the amount of force required to accelerate a mass of one kilogram at a rate of one meter per second squared (1 N = 1 kg × 1 m/s^2). Force can be measured using a variety of instruments, such as spring scales, strain gauges, or force plates. Some common types of forces include gravitational force, electromagnetic force, frictional force, and normal force. The study of forces and their effects on the motion of objects is known as mechanics and is a fundamental concept in physics.

Here,

a. The man does not do any work on the wall because the wall does not move. Work is only done when there is a displacement in the direction of the force applied.

b. Since no work is done, no energy is used or transferred.

c. The power exerted by the man can be calculated using the formula:

Power = Work / Time

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Answer:

10 seconds

Explanation:

As it starts from rest, then u=0

and by III rd equation of motion:

Answer:

10.23m/s^2

Explanation:

GIven data

mass of elevator = 2125 kg

Force= 21,750 N

Required

The maximum acceleration upward

F= ma

a= F/m

a=21,750/2125

a= 10.23m/s^2

Hence the acceleration is 10.23m/s^2

speed is a scalar quantity and velocity is a vector quantity

Answer:

A. h = 2.15 m

B. Pb' = 122 KPa

Explanation:

The computation is shown below:

a)  Let us assume the depth be h

As we know that

\(Pb - Pat = d \times g \times h \\\\ ( 119 - 101) \times 10^3 = 856 \times 9.8 \times h\)

After solving this,  

h = 2.15 m

Therefore the depth of the fluid is 2.15 m

b)

Given that  

height of the extra fluid is

\(h' = \frac{2.35 \times 10^{-3}}{ area} \\\\ h' = \frac{2.35 \times 10^{-3}} { 66.2 \times 10^{-4}}\)

h' = 0.355 m

Now let us assume the pressure at the bottom is Pb'

so, the equation would be

\(Pb' - Pat = d \times g \times (h + h')\\\\Pb' = 856 \times 9.8 \times ( 2.15 + 0.355) + 101000\)

Pb' = 122 KPa

(A)  The depth of the fluid is 2.14 m.

(B)  The new pressure at the bottom of container is 121972 Pa.

Given data:

The cross-sectional area of the container is, \(A =66.2 \;\rm cm^{2}=66.2 \times 10^{-4} \;\rm m^{2}\).

The density of fluid is, \(\rho = 856 \;\rm kg/m^{3}\).

The container pressure at bottom is, \(P=119 \;\rm kPa=119 \times 10^{3} \;\rm Pa\).

The atmospheric pressure is, \(P_{at}=101 \;\rm kPa=101 \times 10^{3}\;\rm Pa\).

(A)

The given problem is based on the net pressure on the container, which is equal to the difference between the pressure at the bottom and the atmospheric pressure. Then the expression is,

\(P_{net} = P-P_{at}\\\\\rho \times g \times h= P-P_{at}\)

Here, h is the depth of fluid.

Solving as,

\(856\times 9.8 \times h= (119-101) \times 10^{3}\\\\h=\dfrac{ (119-101) \times 10^{3}}{856\times 9.8}\\\\h= 2.14 \;\rm m\)

Thus, the depth of the fluid is 2.14 m.

(B)

For an additional volume of \(2.35 \times 10^{-3} \;\rm m^{3}\) to the liquid, the new depth is,

\(V=A \times h'\\\\h'=\dfrac{2.35 \times 10^{-3}}{66.2 \times 10^{-4}}\\\\h'=0.36 \;\rm m\)

Now, calculate the new pressure at the bottom of the container as,

\(P'-P_{at}= \rho \times g \times (h+h')\\\\\P'-(101 \times 10^{3})= 856 \times 9.8 \times (2.14+0.36)\\\\P'=121972 \;\rm Pa\)

Thus, we can conclude that the new pressure at the bottom of container is 121972 Pa.

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Hooke's Law can be given as follows sometimes:

The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:

F = -kx

Where, F = Restoring force of a spring (Newtons, N)

k = Spring constant (N/m)

x = Displacement of the spring (m)

The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.

Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.

The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.

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Use the work-energy theorem. The total work done on the plane is equal to the change in its kinetic energy:

W = ∆K

W =  1/2 (1.5 kg) (6 m/s)² - 1/2 (1.6 kg) (8 m/s)²

W = -21 J

(Note that the work must be negative since the "braking" force opposes the direction in which the plane is moving.)

The density of gold can also be used in various scientific and industrial applications, such as in the manufacturing of electronic components and medical implants.

The density of a material is defined as its mass per unit volume. In this case, we have a block of gold with a mass of 170g and a volume of 9 cm^3. To find the density, we can simply divide the mass by the volume:

Density = Mass / Volume

Density = 170g / 9 cm^3

Density = 18.89 g/cm^3

Therefore, the density of the gold block is 18.89 g/cm^3. This means that for every cubic centimeter of the block, there is a mass of 18.89 grams. Gold is a dense material, and its high density is one of the reasons why it is valued in jewelry and other decorative items.

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\(\sf\large \green{\underbrace{\red{Answer⋆}}}:\)

(a) R2, R3 are parallel and series with R1

(b) R1, R2 and R3 are in parallel

Explanation:

\( \sf R_1 = 2 \: ohm\\ \sf R_2 = 3 \: ohm \\ \sf R_3 = 6 \: ohm\)

(a)

\( \sf R_2 \: and \: R_3 \: are \: in \: parallel \\ \sf so \: let \: the \: total \: of \: R_2 \: and \: R_3 \: be \: R_a\)

\( \sf \large \frac{1}{R_a} = \frac{1}{R_2} + \frac{1}{R_3} \: as \: they \: are \: in \: parallel\)

\( \sf R_a = \frac{1}{3} + \frac{1}{6} \\ \\ \sf \frac{1}{R_a} = \frac{2 + 1}{6} \\ \\ \sf \frac{1}{R_a} = \frac{3}{6} \\ \\ \sf \frac{1}{R_a} = \frac{1}{2} \\ \\ \sf R_a = 2 \: ohm\)

Ra and R1 is in series

And there total will be R

\( \sf R = R_a + R_1 \\ \\ \sf R = 2 + 2 \\ \\ \sf R = 4 \: ohm\)

(b)

\( \sf R_1 R_2 \: and \:R_3 \: are \: in \: parallel \: so \: total \: be \: R\)

\( \sf \frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} \\ \\ \sf \frac{1}{R} = \frac{1}{2} + \frac{1}{3} + \frac{1}{ 6} \\ \\ \sf \frac{1}{R} = \frac{3+ 2 +1 }{6} \\ \\ \sf \frac{1}{R} = \frac{6}{6} \\ \\ \sf R = 1 \: ohm\)

The energy conversion is; Chemical → Mechanical → Thermal

A gasoline engine converts the chemical energy stored in the fuel (gasoline) into mechanical energy that can be used to power a vehicle or other machinery.

Overall, the energy conversion in a gasoline engine is not perfectly efficient, as some of the energy is lost to heat and other forms of waste. However, modern gasoline engines are designed to optimize the combustion process and minimize energy losses, in order to achieve higher fuel efficiency and lower emissions.

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The magnitude of the resultant vector to round the answer to the nearest tenth, we look at the digit in the hundredth's place. If this digit is 5 or greater, we round up. If it is less than 5, we round down.

In the study of physics, we use vectors to represent quantities that have both direction and magnitude. It is often the case that we want to add two or more vectors together to obtain a single vector that represents the net result of these additions. The process of adding two or more vectors together is known as vector addition.The magnitude of the resultant vector is the length of the line that represents it on a scale drawing.

When we add two or more vectors together, the resultant vector is the vector that represents the net result of these additions. To find the magnitude of the resultant vector, we use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.

In the case of vector addition, the hypotenuse is the resultant vector, and the other two sides are the component vectors. If we have two vectors a and b, the magnitude of the resultant vector is given by the following equation:|R| = √(ax2 + bx2)where R is the resultant vector, a and b are the component vectors, and x is the angle between the vectors.

For example, if the answer is 12.345, we would round it to 12.3.

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Answer:

A

Explanation:

Answer: 0.50 m/min

Explanation:

(30 m/hr)(1 hr/60 min) = 0.50 m/min

The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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We have

vi=initial velocity=10.2 m/s

θ=25°

a)

We have that for

Then for

For vy

For the magnitude of the velocity

For the direction of the velocity

For part b)

For the magnitudeof the velocity

For the direction of the velocity

For c)

Because of the negative sign that we obtain in the velocity, we can say that the greatest height is located before the 0.5 m

The equation that expresses the post-collision velocity as a function of the pre-collision velocity and the masses of the moving and the stationary objects is: v_f = ((m1-m2)/(m1+m2))v_i

where v_f is the final velocity, v_i is the initial velocity, m1 is the mass of the moving object, and m2 is the mass of the stationary object.

Claim: This equation is known as the conservation of momentum equation and is based on the principle that the total momentum of a system is conserved during a collision, assuming no external forces act on the system.

What is collision?

Collision refers to the event in which two or more objects come into contact with each other, often resulting in a change in the velocity, direction, or shape of the objects involved. Collisions can occur between particles, atoms, molecules, and larger objects, and can be either elastic or inelastic, depending on whether or not kinetic energy is conserved during the collision.

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Complete question is: The equation that expresses the post-collision velocity as a function of the pre-collision velocity and the masses of the moving and the stationary objects is: v_f = ((m1-m2)/(m1+m2))v_i

Energy conservation is the principle that energy is neither created nor destroyed, but can only be converted or transferred. It involves using energy-efficient appliances and transitioning to renewable energy sources to reduce consumption and environmental impact.

Energy conservation refers to the principle that energy cannot be created or destroyed; it can only be converted from one form to another or transferred between systems. This principle is based on the law of conservation of energy, also known as the first law of thermodynamics. In other words, the total amount of energy in a closed system remains constant over time.

One example of energy conservation is the use of energy-efficient appliances in households. By using appliances that are designed to minimize energy waste, such as energy-saving light bulbs, efficient refrigerators, or insulated windows, individuals can reduce their energy consumption and lower their electricity bills. These appliances are designed to convert electrical energy into useful forms, such as light or heat, with minimal energy losses.

Additionally, energy conservation plays a crucial role in sustainable practices and environmental preservation. For instance, reducing reliance on non-renewable energy sources like fossil fuels and transitioning to renewable energy sources such as solar or wind power helps conserve natural resources and reduces greenhouse gas emissions.

In summary, energy conservation is the principle that states energy cannot be created or destroyed but can only be converted or transferred between different forms. By adopting energy-efficient practices and utilizing renewable energy sources, individuals and society can contribute to conserving energy and mitigating environmental impact.

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The question probable may be:

Explain the concept of energy conservation and provide an example of how it applies in real-life situations.

Answer:

Using sold paper is better than to burn it because burning paper may cause pollution.

Explanation:

Hope it will help ^_^

Answer:

57.1 km/hr

Explanation:

To find the average speed you take the total distance divided by the total elapsed time.

So, the total distance is 140 + 60 = 200

the total elapsed time is found by taking 140/70=2 and 60/40=1.5

2+1.5=3.5

The plug the numbers into the equation,

200/3.5=57.1

Answer:

Force = 50 N

Explanation:

Force = 50 N

Formula: Force = mass x acceleration

Answer: Force = 10kg x 5m/s²

Force = 50 N