Answer:
Whats the sentence
Explanation:
Answer:
Atoms form chemical bonds to satisfy the octet rule and to become stable.
Got it right on Edg. 2020, hope this helps!
What is the mass of a sample of NH3 containing 3. 80 × 10^24 molecules of NH3?
Answer:
107g
Explanation:
First convert the number of molecules to moles using avogadro's number.
There are 6.02 x 10^23 molecules in 1 mol.
3.8 x 10^24 molecules NH3 ÷ 6.02 x 10^23 molecules / mol
= 6.31 mol NH3
Now that we have moles of NH3 we can multiply it by NH3's molecular mass.
NH3 molecular mass = Mass of N + Mass of H x 3
14.007g/mol + 1.008g/mol * 3
= 17.031 g NH3/ mol
6.31 mol NH3 * 17.031 g NH3 / mol
= 107g NH3
Values for the molar mass of hydrogen, oxygen, and water molecules are
given in the table below. What mass of water is formed when 2 moles of
hydrogen react with 1 mole of oxygen to form water?
Molecule
Molar mass (g/mol)
H2
2.02
02
32.00
H20
18.01
A.9.00 g
B. 36.02 g
C. 2.00 g
D. 18.01 g
Answer:
36.02g bbbbbbbbbbb hbbnjkkkj
Answer:
36.02g
Explanation:
Hope this helps!
Hawaii, which sits over a hot spot located near the center of the Pacific
plate, is which type of volcano?
In the dessert presentation, what should be taken into consideration? Give one (1) and discuss briefly.
In dessert presentation one important aspect to consider is the visual appeal and aesthetics of the dessert.
The presentation of a dessert plays a crucial role in creating an enticing and memorable dining experience. The appearance of the dessert can greatly impact the perception and anticipation of its taste and quality. Therefore, attention should be given to factors such as color, texture, arrangement, and garnishments. For instance, color coordination is important to create an appealing visual impact. Harmonious color combinations can make the dessert more visually appealing. Additionally, textures should be varied to add interest and dimension to the presentation, such as incorporating crunchy elements with smooth components. Garnishments and decorations should be carefully chosen to complement the flavors and add a touch of elegance or playfulness, depending on the style and theme of the dessert. They can include edible flowers, chocolate shavings, fruit slices, or artistic drizzles of sauce. By considering the visual appeal in dessert presentation, it enhances the overall dining experience and creates an irresistible desire to indulge in the dessert.
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What can be represented on paper or computer by using the Lewis Dot structure?
A. the electrons orbital
B. the position of an element in the periodic table
C. the valence electron shells of atoms
D. the number of total electrons
Answer:
option C is correct
Explanation:
A magnet is different from a piece of iron that is not magnetic because
Answer:
Under normal conditions, a magnetic material like iron doesn't behave like a magnet because the domains don't have a preferred direction of alignment. On the other hand, the domains of a magnet (or a magnetized iron) are all aligned in s specific direction.
Explanation:
1.
At constant pressure. 50 milliliters (mL) of a gas
at 20°C is heated to 30° C. The new volume of
the gas in milliliters (ml) is equal
Answer:
\(\boxed {\boxed {\sf V_2=75 \ mL}}\)
Explanation:
Since the pressure is constant, the only variables we need to work with are temperature and volume. We will use Charles's Law, which states the volume of a gas is directly proportional to the temperature. The formula is:
\(\frac{V_1}{T_1}=\frac{V_2}{T_2}\)
Originally, the gas was 50 milliliters at 20 degrees celsius. Substitute these values into the left side of the equation.
\(\frac{50 \ mL}{20 \textdegree C}=\frac{ V_2}{T_2}\)
We don't know the volume of the new gas, but we know the temperature was changed to 30 degrees celsius.
\(\frac{50 \ mL}{20 \textdegree C}=\frac{ V_2}{30 \textdegree C}\)
Since we are solving for the new volume, we must isolate the variable. It is being divided by 30 °Cand the inverse of division is muliplication. Multiply both sides by 30 °C.
\(30 \textdegree C*\frac{50 \ mL}{20 \textdegree C}=\frac{ V_2}{30 \textdegree C}* 30 \textdegree C\)
\(30 \textdegree C*\frac{50 \ mL}{20 \textdegree C}= V_2\)
The units of degrees celsius cancel, so we are left with milliliters as the units.
\(30*\frac{50 \ mL}{20}= V_2\)
\(\frac{1500 \ mL}{20}= V_2\)
\(75 \ mL=V_2\)
The new volume of the gas is 75 milliliters.
You observe a car parked on the side of the road. If the car started to move, Which conclusion could you make?
The forces were balanced when the car was parked, but one or more forces changed. The total forces became unbalanced, causing it to move.
The forces were unbalanced when the car was parked. When the car moved, they became balanced.
The forces were balanced when the car was parked. The forces stayed balanced when it moved.
The forces were unbalanced when the car was parked, and two or more forces changed. The forces stayed unbalanced and caused the car to move.
Answer:
it was stable because of it was in Potential energy and unstable because it was in kinetic energy or vice Versa. im somehow confused
A cube, with a mass of 21 g is dropped in a graduated cylinder with 10 mL
water. The water level rises to 24 mL when the cube is added. What is the
cube's density (don't forget units)
Answer:55ml
Explanation:
What is the cause of rejection of classical concept of oxidation and reduction reaction?
Answer:
Oxidation is the loss of electrons or an increase in the oxidation state of an atom, an ion, or of certain atoms in a molecule. Reduction is the gain of electrons or a decrease in the oxidation state of an atom, an ion, or of certain atoms in a molecule.
Explanation:
To solve such this we must know the concept of redox reaction. Therefore, The cause of rejection of classical concept of oxidation and reduction reaction is in any process, oxidation can occur only if reduction is also taking place side by side and vice versa.
What is chemical reaction?Chemical reaction is a process in which two or more than two molecules collide in right orientation and energy to form a new chemical compound. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, double displacement reaction.
Oxidation and reduction reaction involves gain of electron and loss of electron simultaneously. This type of reaction is called redox reaction. The cause of rejection of classical concept of oxidation and reduction reaction is in any process, oxidation can occur only if reduction is also taking place side by side and vice versa.
Therefore, the cause of rejection of classical concept of oxidation and reduction reaction is in any process, oxidation can occur only if reduction is also taking place side by side and vice versa.
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help!!!!!!!!!!!!!!!!!!!!!!!!!
The mass of gallium that can be formed from the reaction of 198 g of strontium with excess molten gallium (III) nitrate is 105 g (Option C)
How do I determine the mass of gallium formed?The mass of gallium that can be formed from the reaction can be obtained as follow:
3Sr + 2Ga(NO₃)₃ → 3Sr(NO₃)₂ + 2Ga
Molar mass of Sr = 87.62 g/molMass of Sr from the balanced equation = 3 × 87.62 = 262.86 g Molar mass of Ga = 69.72 g/molMass of Ga from the balanced equation = 2 × 69.72 = 139.44 gFrom the balanced equation above,
262.86 g of Sr reacted to form 139.44 g of Ga
Therefore,
198 g of CrCl₂ will react to form = (198 × 139.44 ) / 246.86 = 105 g of Ga
Thus, the mass of Ga formed is 105 g (Option C)
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how wide does this grating need to be to allow you to resolve the two lines 589.00 and 589.59 nanometers, which are a well known pair of lines for sodium, in the second order ( m
A. n = 105 lines/mm = 105000 lines/m
d*sin θ = m*λ
(1/105000) * sin θ = 1*498*10^-9 ⇒ θ = 3.0 degree
Also (1/105000) * sin θ = 1*569*10^-9 ⇒ θ = 3.43 degree
Δθ = 3.43° – 3.0°
Δθ = 0.43°
b) Chromatic Resolving power, R = λ / Δλ
λ / Δλ = m (width) n
589 /0.59 = 2 (width) (105000)
Width = 4.75 mm
Diffraction gratings can split beams of different wavelengths into a spectrum of related lines through the principle of diffraction. In certain directions, only waves of certain wavelengths have obtained the rest are destroyed by their respective interference. other.
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What reaction is used to remove one phosphate group from ATP?A. hydrolysis reactionB. redox reactionC. combustion reactionD. neutralization reaction
Answer:
A. hydrolysis reaction.
Explanation:
Chemical Reactions.
First, let's review each concept of the group of answer choices:
- hydrolysis: is a reaction in which the net reaction is an organic compound reacting with water to give either two molar equivalents of a single product or more than one product.
- redox: is a type of chemical reaction that involves a transfer of electrons between two species.
- combustion: is a reaction in which a substance reacts with oxygen gas, releasing energy in the form of light and heat.
- neutralization: is a reaction that occurs when an acid and a base react to form water and a salt and involves the combination of H+ ions and OH- ions to generate water.
The problem is asking for the reaction that removes a phosphate group from ATP, so let's see the structure of ATP with one phosphate group:
What is enclosed in the red box is the phosphate group.
The reaction that removes this phosphate group represents a rupture of the structure and based on the logic of the definitions of the given concepts, the answer would be that the reaction to remove one phosphate group from ATP is A. hydrolysis reaction. This reaction looks like this:
ATP + water (H2O) -> ADP + Pi,
where ADP is the same molecule of ATP but it has two phosphate groups and Pi is the phosphate group removed.
which example has particles that can be drawn closer to occupy smaller volume
One example of particles that can be drawn closer to occupy a smaller volume is a gas.
Understanding Gaseous StateIn the gaseous state, particles have high kinetic energy and are not strongly attracted to each other. They move freely and randomly, colliding with each other and the container walls.
Since there are minimal intermolecular forces holding them together, gas particles can be compressed or drawn closer together by reducing the volume of the container.
By decreasing the volume of a gas, such as by compressing it in a cylinder or container, the particles have less space to move around. They collide with each other more frequently, increasing the frequency of intermolecular collisions. As a result, the gas particles are drawn closer together, and the overall volume occupied by the gas decreases.
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Which area of your house did you observe the strip of paper turned the darkest in color?
Explain your answer. Q2. Which area of your house did you observe the strip of paper changed in color the least?
The area of a kitchen in a house is observed to change the strip of paper turned the darkest color, while that of a bathroom changed it the least.
The darkest color represents the dust and the presence of smoke in a specific area of your home. A kitchen has smoke and dust may come from various activities. The area where you observed the strip of paper change in color the least is an area in your house where there is no or less dust and smoke.
Smoke is a heterogenous mixture which contain dust and many other kinds of particles. Dust can come from many sources such as dirt, skin cells, fabric fibers, books, carpet, rugs, upholstered furniture, fireplaces, pets and many other things. Smoke can come from cooking or burning candles. However, you can reduce dust in your house by cleaning regularly and using an air purifier.
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A 35.40 gram hydrate of sodium carbonate, Na2CO3•nH2O, is heated to a constant mass. Its final weight is 30.2 g. What is formula for the hydrate?A. Na2CO3∙1H2OB. Na2CO3∙2H2OC. Na2CO3D. Na2CO3∙3H2O
First, we have to calculate the molecular weights of each molecule:
\(\begin{gathered} Na_2CO_3\text{ : 23*2+12+16*3= 106 g/mol} \\ H_2O\text{ : 1*2+16= 18 g/mol} \end{gathered}\)Then, we have to calculate the number of grams of water. We can calculate them because the process of evaporation lets us know the water amount that was retired:
\(g\text{ H}_2O\text{ = 35.40 g - 30.2 g=5.2 g H}_2O\)Then, we're gonna convert the grams of sodium carbonate alone (30.2 g) and the grams of water to moles:
\(\begin{gathered} 30.2\text{ g Na}_2CO_3\text{ * }\frac{1\text{ mol}}{106\text{ g}}=\text{ 0.2849 mol Na}_2CO_3\text{ }\approx0.3\text{ mol Na}_2CO_3 \\ \\ 5.2\text{ g H}_2O\text{ * }\frac{1\text{ mol}}{18\text{ g}}=\text{ 0.288 mol H}_2O\text{ }\approx\text{ 0.3 mol H}_2O \end{gathered}\)It means that the mole relation is 1:1 approx, as it is the same amount for both. Then, the formula is going to be:
\(Na_2CO_3\text{ . 1H}_2O\)It means that the answer is A.
The equation shows reactants to a neutralization reaction.
ca2 + oh– arrow h+ no-
which describes what will happen to the h when these reactants form products?
a. h binds with no to make a salt.
b. h binds with ca2 to make an acid.
c. h binds with oh– to make water.
d. h binds with ca2 to make a base.
The equation shows reactants to a neutralization reaction.
Ca²⁺ + OH⁻ → H⁺ + NO⁻. Here H binds with OH⁻ to make water. So the option c is correct.
As the answer to the question is cleared from these reactions. Firstly calcium hydroxide combines with nitric acid to form the products as follows;
Ca(OH)₂ + 2HNO₃ → Ca(NO₃)₂ + 2H₂O
Now the reaction between ionic species will be as follows
Ca²⁺ + 2OH⁻ + 2H⁺ + 2NO₃⁻ → Ca²⁺ + 2NO₃⁻ + 2H₂O
Hence OH⁻ combines with H⁺ to make H₂O(water)
OH⁻ + H⁺ → H₂O
H⁺ binds with OH⁻ to make water
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1. At Time 1, a cool air mass is moving from Location 1 toward a stationary warm air mass at Location 2. After the cool air mass collides with the warm air mass at Time 2, clouds begin to appear over Location 2. The partial model below shows the two air masses at Time 1, but does not show their interaction at Time 2.
The warm and the cool air masses affects the formation of clouds and precipitation.
Does warm and cool air masses affect cloud formation?Warm and cool air masses can affect cloud formation. Clouds are formed when water vapor in the atmosphere rises and cools, condensing into tiny water droplets or ice crystals. The type and amount of clouds that form can be influenced by the temperature and moisture content of the air masses.
In general, the interaction between warm and cool air masses can result in cloud formation and precipitation.
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In what type of reaction or process does heat flow into the system?
combustion
exothermic
condensation
endothermic
The reactions in which flow of heat takes place into the system is known as endothermic process.
What is heat flow?Heat flow is a process in which transfer of heat takes place from one system to other or from outside to inside or vice-versa.
In in any chemical reaction for the completion of reaction if we have to absorb heat or flow of heat takes place from the outside into the system then that reaction is known as endothermic reaction.
Hence resultant process will be endothermic.
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Answer D. endothemic
Explanation: just took the quiz
Consider a group of 5 students, each of whom makes a potassium chloride (74.55 mol/g) solution in the lab. Individually, each student weighs out an amount of sodium chloride and a volume of water, according to the following table. Use this information to calculate the solution concentration (in moles/liter) each student makes, the average concentration, and the standard deviation for the concentration.
fill out the chart pls
Normal Concentration = 18.09 moles/L Standard Deviation = 1.89 moles/L
What is Concentration?The capacity for sustained attention on a single thing, activity, or work without being sidetracked is known as concentration. It is the key to success in most endeavors, as it requires a person to ignore any extraneous thoughts, feelings, or stimuli and instead focus on the task at hand. Concentration is a mental skill that can be developed and improved with practice, such as with mindfulness, meditation, and various cognitive exercises. Concentration can also be adversely affected by poor physical health, lack of sleep, and stress, so it is important to maintain a healthy lifestyle if one wants to stay focused.
Student | Weight (g) | Volume (L) | Concentration (moles/L)
1 | 5.0 | 0.25 | 19.82
2 | 8.0 | 0.50 | 15.89
3 | 4.0 | 0.20 | 20.23
4 | 7.0 | 0.30 | 18.52
5 | 6.0 | 0.40 | 16.96
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22.37 compounds a, b, and c are isomers of xylene (dimethylbenzene). when each of these isomers undergoes a single nitration, compound a produces just one product, b produces a mixture of two products, and c produces a mixture of three products. identify which of compounds a, b, and c is the ortho isomer, which is the meta isomer, and which is the para isomer.isomer(s) of tetramethylbenzene could the starting material have been?
The methyl groups in this isomer are placed at the 1,2-positions, giving the nitro group three possible positions: 3, 4, or 5.
We can identify the isomers of xylene (dimethylbenzene) as follows:
Compound A is the para isomer, as it produces just one product upon nitration. In this case, the methyl groups are positioned at the 1,4-positions, which leaves only one possible position for the nitro group.
Compound B is the meta isomer, as it produces a mixture of two products upon nitration. Here, the methyl groups are located at the 1,3-positions, allowing the nitro group to occupy either the 2 or 5 positions.
Compound C is the ortho isomer, as it produces a mixture of three products upon nitration.
Constitutional isomers are types of structural isomers with the same chemical formula but distinct bonding patterns and structures. Counting the number of carbon atoms and the degree is the simple method for determining a constitutional isomer. Stereoisomers are isomers with the same composition but a different orientation in space. It comes in diastereomers and enantiomers varieties. Enantiomers create the non-superimposable mirror images. Although diastereomers cannot be superimposed, they are not mirror images.
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Temperature Mixing:
In this problem we will build a model for mixing problems with dif-
ferent temperatures of water. Throughout we will assume that mixing
happens instantaneously and no heat is lost to the surroundings.
(a) Suppose we have v liters of water at temperature T in an urn and
we pour in u liters of water at temperature S. What is the tem-
perature of the mixture? (This is going to be a weighted average.)
b. Let v(t) denote the volume of the water at time t, T(t) denote the temperature at time t. Suppose after Gt seconds Gu gallons of water are added to the urn. Compute T(t+Gt)-T(t). Now assume the water is pouring in at a constant rate and temperature and use the limit definition of the derivative to compute dT/dt in term of du/dt,S,T and v(t)
Alright, let's take it step by step!
(a) When you mix water with different temperatures, the final temperature is like a weighted average. Imagine you have `v` liters of water at temperature `T` and `u` liters of water at temperature `S`. The amount of thermal energy in the first batch is `v*T` and in the second batch it's `u*S`. When you combine them, the total thermal energy is `v*T + u*S`. Since the total volume is now `v + u`, the average energy per liter (which is the final temperature) is `(v*T + u*S) / (v + u)`.
In equation form:
Final Temperature, F = (v*T + u*S) / (v + u).
(b) Now let's move to the changing volumes and temperatures. Let `v(t)` be the volume at time `t`, and `T(t)` the temperature at time `t`. Let's say that in `Gt` seconds, `Gu` gallons of water are added at temperature `S`. We’ll assume that 1 gallon is the same as 1 liter for simplicity, though in reality they are slightly different.
The new volume after `Gt` seconds is `v(t) + Gu`, and the total thermal energy is `v(t)*T(t) + Gu*S`. The new average temperature is:
T(t+Gt) = (v(t)*T(t) + Gu*S) / (v(t) + Gu).
Now, T(t+Gt) - T(t) = [(v(t)*T(t) + Gu*S) / (v(t) + Gu)] - T(t).
Now, let's think about water pouring at a constant rate. Let's use the limit definition of the derivative. Instead of `Gu` gallons in `Gt` seconds, let's say a tiny amount of water `du` is added in a tiny amount of time `dt`. So, `du/dt` is the rate at which water is poured into the urn.
Using the limit definition:
dT/dt = lim (dt -> 0) [(v(t)*T(t) + du*S) / (v(t) + du) - T(t)] / dt
= [(v(t)*T(t) + du*S) / (v(t) + du) - T(t)]' (derivative with respect to t)
= [v'(t)*T(t) + v(t)*T'(t) + du/dt*S - v'(t)*T(t) - v(t)*T'(t)] / (v(t) + du) (using product rule)
= (du/dt*S) / (v(t) + du).
As dt approaches 0, du becomes very small, and thus we can ignore it in comparison to v(t), so:
dT/dt ≈ (du/dt*S) / v(t).
This is the rate of change of temperature with respect to time, in terms of the rate at which water is poured, the temperature at which it is poured, and the volume of water already in the urn.
which enzyme would be most efficient in an environment where the ph level can fluctuate between acidic and basic
The pH range between 0.5 and 2.5 is optimal for the activity of pepsin, a common enzyme present in the stomach.
What pH would the enzyme work best at?Around pH 6 to 8, many enzymes found in higher species function quite effectively.But there are lots of exceptions. Alkaline phosphatase is most effective at a pH range of 8.5 to 9.5, although some enzymes, such pepsin, function well at a pH range of 1.5 to 2.The pH range between 0.5 and 2.5 is optimal for the activity of pepsin, a common enzyme present in the stomach.The ideal pH is where enzyme activity is highest. Enzyme activity declines as pH values rise above or fall below the ideal pH range.To learn more about enzymes refer to:
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A student conducts a titration to determine the molarity of a hydrochloric acid solution. HCl(aq), by reacting it with a standardized stock solution of sodium hydroxide NaOH(aq). The student uses 10 mL of the unknown acid and titrates to the end point of the indicator. The student calculate the percent error of the molarity of the acid to be 35%. which of the following could account for the largest percent error?
The acetic acid in vinegar has a molar concentration of 0.530 M.
How much molar concentration is there?When the chemical formula and molecular weight of the drug are known, the concentration can be calculated. Any substance's molar concentration in a solution can be simply calculated.
Molar concentration is the measurement of a solution's concentration as the No. of moles of a solute inside a liter of a solution.
The following equation can be used to compute the concentration or volume of the solutions:
M₁V₁ = M₂V₂
where M1, V1, M2, and V2 represent the volume and concentration of the concentrated & diluted solution, respectively.
Given a NaOH concentration, M1 = 0.1931 M (which should be necessary to apply the broth dilution),
and to calculate the molar concentration of acetic acid)
The volume of NaOH, V1, is 27.48 mL.
V2 = acetic acid volume in milliliters
In equation (1), substitute the values of V1, M1, and V2 as well as volume:
(0.1931) X (27.48) = (10) X (V₂)
V₂ = 0.530 M
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How many molecules are in one mole of H2SO4
Answer:
I think it is 20
Explanation:
Answer: 20, Hope this helped!
Explanation:
Consider the intensities of the sounds listed below.
A 2 column table with 12 rows. The first column is labeled sound in decibels with entries 140, 130, 120, 110, 100, 90, 80, 70, 60, 50, 40, 30, 20. The second column is labeled noise source with entries jet engine at 25 meters, jet aircraft at 100 meters, rock and roll concert, pneumatic chipper, woodworking machines, chainsaw, heavy truck traffic, business office, conversational speech, library, bedroom, secluded woods, whisper.
Which lists the amplitudes of sound waves from these sources in order from greatest to least?
busy roadway, kids whispering, average home
chainsaw, diesel truck, rustling leaves
kids whispering, vacuum cleaner, jet airplane
library, conversational speech, music from speaker
The amplitudes of sound waves from these sources in order from greatest to least is chainsaw, diesel truck, rustling leaves.
What are sound waves?A sound wave is described as the pattern of disturbance caused by the movement of energy traveling through a medium (such as air, water or any other liquid or solid matter) as it propagates away from the source of the sound.
The amplitude of the sound wave is described as the maximum displacement of the particles from their resting position. That means that higher the amplitude equals high sound.
So the sound of a chainsaw is high, hence its amplitude will be great and after that the amplitude of diesel truck is high and rustling leaves have the lowest amplitude.
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Aluminum forms alloys with lithium(LiAl),gold(AuAl2),and titanium(Al3Ti). based on their crystal structures, each of these alloys is considered to be a substitutional alloy. The radii of the atoms are: Al: 143pm, Li = 152pm, Au = 144pm, and Ti= 147pm.
A) which alloys fit the general size requirements for substitutional alloys? check all that apply
Al3Ti
LiAl
AuAl2
Both Al3Ti and LiAl fit the general size requirements for substitutional alloys, as they have similar atomic radii. (A,B)
Al3Ti consists of aluminum and titanium atoms, which have atomic radii of 143pm and 147pm respectively, which are fairly close in size.
Similarly, LiAl consists of aluminum and lithium atoms, which have atomic radii of 143pm and 152pm respectively, which are also close in size. Because the atomic radii of both alloys are close, the atoms are able to fit into the lattice structure of the other atoms.
This allows for the atoms to substitute for each other, making for a substitutional alloy.
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A student was asked to formulate a hypothesis about what would happen if 100. mL of 0.1 M NaOH(aq) at
25°C was combined with 100. mL of 0.1 M MgCl₂(aq) at 25°C. Which of the following hypotheses indicates
that the student thought a chemical change would occur?
Answer:
There will be the formation of a Common salt (NaCl) and Mg(OH)2 which is a base after the reaction between the two chemicals
What is the ph of a 3.97x10^-2 m aqueous solution of hx if its ka is equal to 3.0x10^-3?
The pH of a 3.97x10^-2 m aqueous solution of hx if its ka is equal to 3.0x10^-3 is 1.96.
What is pH?pH is defined as the concentration of hydrogen ion in the solution.
Given,
Ka = 3.0x10^-3
As we know that,
Ka =( [H+] [X-])/[HX]
Let the concentration of [H+] = [X-] = x at any time t.
At the same time, concentration of [HX] = (0.0397-x)
Ka = x^2/(0.0397-x)
3.0x10^-3 = x^2/(0.0397-x)
x^2 = 0.1191 × 10^-3
x = 1.09×10^(-2)
x = 0.0109
The concentration of [H+] = 0.0109.
As we know that,
pH = -log[H+]
pH = -log(0.0109)
pH = -(-1.96)
pH = 1.96
Thus, we calculated that the value of pH of a 3.97x10^-2 m aqueous solution of hx if its ka is equal to 3.0x10^-3 is 1.96.
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7.70 mol of a monatomic ideal gas, kept at the constant pressure 1.62E+5 Pa, absorbs 3870 J of heat. If the change in internal energy is zero and this process occurs with a change in temperature 24.2 °C, How much did the volume of the gas change during this process?
The volume of the gas changed by approximately 0.280 m³ during the process.
To find the change in volume of the gas during the process, we can use the equation:
ΔQ = nCvΔT
where: ΔQ is the heat absorbed (3870 J),
n is the number of moles of the gas (7.70 mol),
Cv is the molar heat capacity at constant volume,
ΔT is the change in temperature (24.2 °C = 24.2 K).
Since the change in internal energy is zero (ΔU = 0), we know that ΔU = ΔQ + ΔW, where ΔW is the work done by the gas. In this case, since the process is at constant pressure, we can write ΔW = PΔV, where P is the pressure (1.62E+5 Pa) and ΔV is the change in volume.
Now, using the ideal gas law, we can express ΔV in terms of ΔT:
ΔV = (nRΔT) / P
where R is the ideal gas constant (8.314 J/(mol·K)).
Substituting the given values into the equations:
ΔQ = nCvΔT
3870 J = 7.70 mol × Cv × 24.2 K
From the equation ΔV = (nRΔT) / P, we have:
ΔV = (7.70 mol × 8.314 J/(mol·K) × 24.2 K) / (1.62E+5 Pa)
Simplifying the equations and performing the calculations:
ΔQ = nCvΔT
3870 J = 7.70 mol × Cv × 24.2 K
Cv ≈ 2.00 J/(mol·K) (calculated from the above equation)
ΔV = (7.70 mol × 8.314 J/(mol·K) × 24.2 K) / (1.62E+5 Pa)
ΔV ≈ 0.280 m³
Therefore, the volume of the gas changed by approximately 0.280 m³ during this process.
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