Complete the reaction, which is part of the electron transport chain. the abbreviation q represents coenzyme q. use the appropriate abbreviation for the product.

FADH2+Q →

Answer:

124225.91 g of Na₃PO₄

Explanation:

From the question given above, the following data were obtained:

Number of atoms of Na₃PO₄ = 4.56×10²⁶ atoms

Mass of Na₃PO₄ =?

From Avogadro's hypothesis,

6.02×10²³ atoms = 1 mole of Na₃PO₄

Next, we shall determine the mass of 1 mole of Na₃PO₄. This can be obtained as follow:

1 mole of Na₃PO₄ = (23×3) + 31 + (16×4)

= 69 + 31 + 64

= 164 g

Thus,

6.02×10²³ atoms = 164 g of Na₃PO₄

Finally, we shall determine the mass of Na₃PO₄ that contains 4.56×10²⁶ atoms. This can be obtained as follow:

6.02×10²³ atoms = 164 g of Na₃PO₄

Therefore,

4.56×10²⁶ atoms = (4.56×10²⁶ × 164)/6.02×10²³

4.56×10²⁶ atoms = 124225.91 g of Na₃PO₄

Therefore, 124225.91 g of Na₃PO₄ contains 4.56×10²⁶ atoms

True/false questions require a statement to be either true or false, but the given prompt is incomplete and does not form a statement. Therefore, it cannot be classified as true or false.

However, to provide some clarification, the prompt seems to be asking for a synthesis pathway starting with ethanol and ethyl butanoate. Ethanol (\(C_2H_5OH\)) and ethyl butanoate (\(C_6H_{12}O_2\)) are organic compounds that can be used in organic synthesis to produce other chemicals. One possible pathway for the synthesis of a compound starting with these two compounds is:

Convert ethanol to ethene (\(C_2H_4\)) by dehydrating it with a strong acid such as sulfuric acid.

This synthesis pathway is just one example, and there can be multiple ways to synthesize a compound starting with different starting materials.

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Answer: mgbr2 magnisum bromide

KCI potassium chloride

AI2S3 aluminum sulfide

MG3p2 magnisum phosphide

CaO calcium oxide

BaO barium oxide

Explanation:I did this one time

121 mol CH₄

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Organic

Atomic Structure

Step 1: Define

7.31 × 10²⁵ molecules CH₄

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

\(\displaystyle 7.31 \cdot 10^{25} \ molecules \ CH_4(\frac{1 \ mol \ CH_4}{6.022 \cdot 10^{23} \ molecules \ CH_4} ) = 121.388 \ mol \ CH_4\)

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

121.388 mol CH₄ ≈ 121 mol CH₄

we find the energy to be approximately \(3.41 * 10^-19\) Joules is the answer.

To calculate the wavelength of a photon with a frequency of 61.7 MHz, we can use the formula: wavelength = speed of light / frequency. The speed of light is approximately\(3 * 10^8\) meters per second.

Converting the frequency to Hz (\(1 MHz = 10^6 Hz\)), we have \(61.7 * 10^6\)Hz.

Plugging these values into the formula, we get: wavelength =\((3 * 10^8 m/s) / (61.7 * 10^6 Hz).\)

Simplifying, we find the wavelength to be approximately 4.862 meters.

Now, to calculate the energy of a photon with a wavelength of 582.8 nm, we can use the equation: energy = Planck's constant × speed of light / wavelength.

Planck's constant is approximately \(6.63 * 10^-34\) Joule-seconds.

Converting the wavelength to meters (\(1 nm = 10^-9 m\)), we have \(582.8 * 10^-9 m.\)

Plugging these values into the equation, we get: energy =\((6.63 * 10^-34J·s) * (3 * 10^8 m/s) / (582.8 * 10^-9 m).\)

Simplifying, we find the energy to be approximately \(3.41 * 10^-19\) Joules.

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Answer:

A. They cause heat to flow from the system to the surroundings.

Explanation:

Answer:

A. They cause heat to flow from the system to the surroundings.

Explanation:

a p e x , just took the quiz

39.20 g of water are theoretically yield produced when 25.34 g of C4H10 are burned.

The highest amount of a product that can be made from a specific quantity of reactants is known as the theoretical yield. Stoichiometry, which involves balancing a chemical equation and calculating the amount of product created using mole ratios, is used to determine it.

Let's start by balancing the provided equation.

C4H10 + 13/2 O2 4 CO2 + 5 H2O.

It is evident that five moles of water react with one mole of C4H10.

Therefore, we can determine the theoretical yield of water using the mole ratio of C4H10 and H2O.

Determine how many moles of C4H10 there are: C4H10 mass and molar mass are used to calculate moles of C4H10.moles of C4H10 are equal to 25.34 g/mol and 58.12 g/mol, respectively.

The mole ratio of C4H10 and H2O is as follows:5 moles of C4H10 equal 1 mole of H2O.moles of water equal 5 0.436 mol2.18 mol = 1 mole of water

Finally, we may use the mole-mass connection to get the mass of water.H2O's molar mass is equal to its molecular mass.mass of H2O = 39.20 g mass of H2O = 2.18 mol 18.02 g/mol

Therefore, 39.20 g of water should theoretically yield be produced when 25.34 g of C4H10 are consumed.

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If you are unsure which layer is which in an extraction procedure, there are a few steps you can take to try and identify them.

One approach is to carefully observe the physical properties of each layer, such as color, viscosity, and density. For example, the aqueous layer is typically clear or pale yellow in color, while the organic layer may be darker and more viscous.
You can also perform a simple test to determine which layer is which. One common method is to add a small amount of water to the mixture and observe which layer the water separates into. Since water is more polar than many organic solution, it will typically dissolve in the aqueous layer and not in the organic layer.
If you are still unsure which layer is which, you may need to consult a reference or an expert in the field to help you identify them. In any case, it is important to take care when working with extraction procedures, as improper identification of layers can result in loss of product or inaccurate analysis.

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A dam is a structure that is erected across a river or another body of water to produce a reservoir or water storage area behind it. The primary objective of a dam is to control the flow of water, either to prevent flooding or to guarantee a steady supply of water for uses such as irrigation, the production of hydroelectric power, and other uses.

A dam typically consists of a number of parts that work together to control the flow of water. These elements consist of:.

Spillway: A spillway is a channel or opening in the dam that permits extra water to drain from the reservoir during times of intense rainfall or snowmelt. The dam's spillway was built to keep the reservoir's water level from getting too high and possibly causing it to fail.

Outlet Works: A system of pipes, valves, and gates known as an outlet works enables water to be released from a reservoir for a variety of uses, such as irrigation or the production of hydroelectric power. The water level in the reservoir can also be managed using the outlet works.

An intake tower is a vertical shaft or pipe that is situated inside a reservoir and allows water to be drawn out for a variety of uses, including the production of hydroelectric power.

Control Gates: To control the flow of water through the dam, control gates are gates positioned at different points throughout the structure.

Water is kept behind the dam when the reservoir's water level rises. The intake tower or outlet works release water when the water level drops. The control gates can be opened or closed to manage the water level in the reservoir and the flow of water through the dam.

In general, a dam is a crucial piece of infrastructure that aids in controlling water flow, preventing floods, and providing a consistent supply of water for various human endeavors.

Answer:

Electrons

Explanation:

The source that gives the voltage (force) causes the electrons to move.

Answer:

The answer is Electron

Explanation:

Answer:

mass=?,volume=5.05,density=1200.

density=mass/volume.

1200=mass/5.05.

mass=1200×5.05=6060g

Answer:

\(\huge \boxed{\mathrm{6060 \ grams}}\)

Explanation:

\(\sf \displaystyle density = \frac{mass}{volume}\)

\(\sf \displaystyle 1200 = \frac{m}{5.05}\)

Multiplying both sides by 5.05.

\(\sf \displaystyle 1200(5.05) = \frac{m}{5.05}(5.05)\)

\(\sf 6060=m\)

The mass of the air is 6060 grams.

A model of the force between two negatively charged particles is attached in the image below.

Force is defined as a cause which is capable of changing the motion of an object. It can cause an object which has mass to change it's velocity. It is also simply a push or a pull . It has both magnitude as well as direction.Hence, it is a vector quantity.

It has SI units of Newton and is represented by'F'.Newton's second law states that force which acts on an object is equal to momentum which changes with time. If mass of object is constant, acceleration is directly proportional to net force acting on an object.

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Answer:

2Na + Br2 = 2NaBr

Explanation:

In order to balance a chemical equation you make the make sure both sides have the same number of atoms on each side, you do this by multiplying on both sides as if it was a algebraic equation.

Na+ Br2 = NaBr

Na × 2 = Na2

Na × 2 = Na2

Br × 2 = Br2

2Na + Br2 = 2NaBr

Hope this helps.

Answer:

The correct response is "3.127 weeks". A further explanation is given below.

Explanation:

As we know,

y = 1.3431x

Use, y = 4.2 cm

Now,

⇒ \(y = 1.3431x\)

On substituting the values of y, we get

⇒ \(4.2=1.3431x\)

⇒ \(x = \frac{4.2}{1.3431}\)

⇒    \(=3.127 \ weeks\)

There are total three laws of newtons, first law of newtons, second law of newton and third law of newton. Therefore, for every action there is an equal and opposite reaction.

Newton's first law is also called law of inertia. An object at rest remains at rest, and an object in motion remains in motion at constant speed and in a straight line unless acted on by an unbalanced force.

Third law of newton states  that for every action there is an equal and opposite reaction.

Therefore, for every action there is an equal and opposite reaction.

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The galvanic cell described in the question consists of two half-reactions: N2 + 4H2O + 4e- ⟶ N2H4 + 4OH-.

To analyze this cell, we can examine the standard reduction potentials of the half-reactions involved and determine the overall cell potential, as well as the direction of electron flow and the species undergoing reduction and oxidation.

Explanation:

To evaluate the galvanic cell, we need to consider the standard reduction potentials of the half-reactions involved:

N2 + 4H2O + 4e- ⟶ N2H4 + 4OH- (reduction)

The standard reduction potential for this half-reaction is not provided in the question. The standard reduction potential is a measure of the tendency of a species to gain electrons and undergo reduction. With the given information, we cannot determine the standard reduction potential and, consequently, the standard cell potential.

In a galvanic cell, the species undergoing reduction occurs at the cathode (positive electrode), while the species undergoing oxidation occurs at the anode (negative electrode). Without knowing the standard reduction potential, we cannot determine the direction of electron flow or which species is undergoing oxidation or reduction in this specific cell.

In summary, without the standard reduction potential for the given half-reaction, we cannot determine the standard cell potential or the direction of electron flow in the galvanic cell.

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The respective concentrations, in molarity, of sodium ions and sulfate ions afforded by dissolving 0.500 moles of sodium sulfate in water and diluting to 1.33 L are 0.375 M and 0.375 M respectively.

The formula for sodium sulfate is Na2SO4. It has 2 moles of sodium ions (Na+) and 1 mole of sulfate ions (SO42-) per mole of sodium sulfate. To find the molarity, we need to divide the moles by the volume in liters.Moles of Na2SO4 = 0.500 molVolume of solution = 1.33 L Number of moles of

Na+ = 2 × 0.500 mol = 1.00 molNumber of moles of SO42- = 1 × 0.500 mol = 0.500 molMolarity of Na+ = (1.00 mol) / (1.33 L) = 0.750 MMolarity of SO42- = (0.500 mol) / (1.33 L) = 0.375 M. Therefore, the respective concentrations, in molarity, of sodium ions and sulfate ions afforded by dissolving 0.500 moles of sodium sulfate in water and diluting to 1.33 L are 0.375 M and 0.375 M respectively.

To find the molarity of sodium ions (Na+) and sulfate ions (SO42-) afforded by dissolving 0.500 moles of sodium sulfate in water and diluting to 1.33 L, we need to first calculate the number of moles of each ion. We know that there are 2 moles of Na+ and 1 mole of SO42- per mole of sodium sulfate (Na2SO4).Hence, the number of moles of Na+ is given by:2 × 0.500 mol = 1.00 molAnd the number of moles of SO42- is given by:1 × 0.500 mol = 0.500 molNow, we can use the formula for molarity, which is:Molarity = Number of moles / Volume (in liters)We are given that the volume of the solution is 1.33 L. Therefore, the molarity of Na+ is: Molarity of Na+ = (1.00 mol) / (1.33 L) = 0.750 MAnd the molarity of SO42- is:Molarity of SO42- = (0.500 mol) / (1.33 L) = 0.375 MTherefore, the respective concentrations, in molarity, of sodium ions and sulfate ions afforded by dissolving 0.500 moles of sodium sulfate in water and diluting to 1.33 L are 0.375 M and 0.375 M respectively.

we can find the molarity of sodium ions and sulfate ions by dividing the number of moles of each ion by the volume of the solution in liters. The respective concentrations, in molarity, of sodium ions and sulfate ions afforded by dissolving 0.500 moles of sodium sulfate in water and diluting to 1.33 L are 0.375 M and 0.375 M respectively.

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Answer:

c

Explanation:

If cal is titrating 52.5 ml of 0.304 m hbr with 0.344 m ba(oh)2. The amount of ml of ba(oh)2 that cal need to add to reach the equivalence point is :  92.79 ml.

In order to solve this problem, we can use the following equation that relates the moles of acid to the moles of base:

moles of acid = moles of base

We can rearrange this equation to solve for the volume of base needed to reach the equivalence point:

volume of base = moles of acid / concentration of base

First, let's calculate the number of moles of HBr in the solution:

moles of HBr = volume of HBr x molarity of HBr

moles of HBr = 52.5 ml x 0.304 mol/L

moles of HBr = 15.96 mmol

Since the reaction between HBr and Ba(OH)2 is a 1:2 acid-base reaction, we know that the number of moles of Ba(OH)2 needed to reach the equivalence point is twice the number of moles of HBr:

moles of Ba(OH)2 = 2 x moles of HBr

moles of Ba(OH)2 = 2 x 15.96 mmol

moles of Ba(OH)2 = 31.92 mmol

Finally, we can use the equation above to calculate the volume of Ba(OH)2 needed:

volume of Ba(OH)2 = moles of HBr / concentration of Ba(OH)2

volume of Ba(OH)2 = 31.92 mmol / 0.344 mol/L

volume of Ba(OH)2 = 92.79 ml

Therefore, Cal would need to add 92.79 ml of 0.344 M Ba(OH)2 to reach the equivalence point.

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Answer: The equilibrium constant for the reverse reaction at the same temperature is \(2.40 \times 10^{33}\).

Explanation:

The given reaction equation is as follows.

\(2HCl(g) \rightleftharpoons H_{2}(g) + Cl_{2}(g)\) ... (1)

It's equilibrium constant (K) value is \(4.17 \times 10^{-34}\).

Also, another reaction equation is as follows.

\(H_{2}(g) + Cl_{2}(g) \rightleftharpoons 2HCl(g)\)

This is the reverse of equation (1). Hence, its equilibrium value is calculated as follows.

\(K' = \frac{1}{K}\\= \frac{1}{4.17 \times 10^{-34}}\\= 2.40 \times 10^{33}\)

Thus, we can conclude that the equilibrium constant for the reverse reaction at the same temperature is \(2.40 \times 10^{33}\).

The original analyte solution tested had 1.5 x 10⁻⁴ moles of captopril present.
The correct answer is found to be (B) 1.5 x 10-4 moles.

This can be determined by performing a titration to measure the concentration of the analyte solution. In a titration experiment, the concentration of the analyte solution is determined by measuring the volume of a titrant solution of known concentration that is required to react completely with the analyte. The moles of the titrant can be calculated using the equation:

moles of titrant = concentration of titrant x volume of titrant

Since the moles of the titrant and the analyte are equal at the endpoint of the titration, the moles of the analyte can be determined using the same equation. By rearranging the equation, the concentration of the analyte can be calculated as:
the concentration of analyte = moles of analyte/volume of analyte

Using the given values in the question, the moles of captopril in the original analyte solution can be calculated and the

The correct answer is found to be (B) 1.5 x 10-4 moles.

Your question is incomplete but most probably your full question was:

Potentiometric titration is a useful means of characterizing an acid. Instead, the cell potential is measured across the analyte solution. When cell potential is plotted against titrant volume added, the equivalence point is the cell potential at the inflection point, the midpoint of the steep segment of the titration curve.

Note:

It’s similar to regular hydration where you add a base, and we have an equivalence point. But we’re also adding in this ability to measure the voltage with the electric potential. And so that’s why it’s a potentiometric or potentio-measuring thing. And so that’s telling us when we reach this equivalence point, rather than looking at the actual indicator.

Continuation of Passage…

For polyprotic acids, acidic hydrogen will produce an inflection point only if it is not very weakly acidic and if its ionization constant differs from that of any other acidic hydrogen of the acid by at least a factor of 104.

Captopril (molecular weight: 217.29 g/mol), shown in Figure 1, is a competitive inhibitor of angiotensin-converting enzyme (ACE).

Figure 1 Captopril

Students studying captopril were provided the following in vivo IC50 values (the minimum plasma concentration need to inhibit 50% of target enzyme activity in vivo) for captopril inhibition of ACE under different pH conditions.

Note:

IC50 is the minimum concentration of whatever it is that we’re talking about needed to inhibit 50%. So it’s the inhibitory concentration at 50%.

Table 1 Captopril IC50 values

pH range IC50 (mean 士 standard deviation)

1.5-3.7 0.058 士 0.013 pM

3.8-9.5 0.012 士 0.004 pM

9.6-12.5 0.069 士 0.017 pM

Note:

The pKa for the salt hydro group is 9.8. And the pKa of the carboxylic acid is 3.7, which are those middle points in those pH ranges. They have the pH up to 3.7, from there to 9.6, and then above 9.6. So they’re telling us that what’s happening at these different points is we’re dealing with the molecule.

IC50 is the amount of the drug we need to shut down 50% of the ACE enzymes. And so a smaller number is a more powerful drug because I don’t need very much of it to shut down 50% of angiotensin-converting enzyme.

While bigger IC50 is actually a less powerful drug. And so that’s something that seems counterintuitive, where the smaller the number, you need less of it because it’s telling you how much you need to shut down the enzymes.

Students then performed a potentiometric titration of captopril in order to determine the captopril content contained in a tablet formulation. Two tablets were ground and homogenized, producing 104.4 grams of fine powder. The powder was then dissolved in 100 mL of water and titrated with a solution of 2x 10-2 M NaOH. The potentiometric titration curve obtained, along with a plot of the rate of change of potential during the titration, is shown in Figure 2.

Figure 2 (a) Potentiometric titration curve of captopril in NaOH solution; (b) Rate of change of cell potential

Note:

You could see the traditional titration curve appearance with that s-shaped curve. And then we have this sharp peak of the cell potential, right around 7.5 or something like that. It’s telling us that that’s probably where the equivalence point is happening.

Remember from the first paragraph that they told us that we get this indicator through the potential when we hit the equivalence point rather than using an indicator. And so they use that and Figure 2.

How many noles of captopril were present in the original analyte solution tested?

(A) 7.5 x 10-5 moles

(B) 1.5 x 10-4 moles

(C) 7.5 x 10-3 moles

(D) 1.5 x 10-2 moles

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The product obtained when ethyne (also known as acetylene) is treated with KMnO4/H+ is two carboxylic acids.

when ethyne reacts with KMnO4 in the presence of an acid catalyst (H+), it undergoes oxidative cleavage, resulting in the formation of two carboxylic acids. The reaction involves the addition of two molecules of water across the triple bond of ethyne. The intermediate formed is glyoxal, which further undergoes oxidation to yield two molecules of carboxylic acids. The mechanism of the reaction starts with the addition of two molecules of water across the triple bond of ethyne, forming an enol intermediate. The enol tautomerizes to the corresponding ketone, which is further oxidized by KMnO4/H+ to form a carboxylic acid. This process is repeated for the second molecule of ethyne, resulting in the formation of two different carboxylic acids.

It's important to note that the specific carboxylic acids obtained will depend on the reaction conditions and the nature of the substituents on the ethyne molecule. The oxidation of the ketone intermediate can lead to the formation of various carboxylic acids, depending on the functional groups present. Therefore, without further information about the specific reactants and reaction conditions, it is not possible to determine the exact carboxylic acids formed in this reaction.

In summary, when ethyne is treated with KMnO4/H+, the main product obtained is two carboxylic acids. The reaction proceeds through the oxidative cleavage of the triple bond, resulting in the formation of two different carboxylic acids. The specific carboxylic acids produced will depend on the reaction conditions and the substituents present in the ethyne molecule.

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Deprotonation of phenol by NaOHPhenol is a weak acid with a pKa value of 10, so it is not very acidic but it can be deprotonated with a strong base like sodium hydroxide (NaOH). The mechanism for this reaction is a simple acid-base reaction where NaOH acts as a base and removes the proton (H+) from phenol.

The curved arrow mechanism is shown below:Here, the Na+ ion comes in and removes the H+ ion from the O-H bond in phenol and forms water as a by-product. The major organic product is phenoxide ion (C6H5O−) which is formed after the deprotonation reaction.SN2 reaction of phenoxide with chloroethane Phenoxide ion is a good nucleophile because it has a negative charge on the oxygen atom which is able to attack the positively charged carbon atom in chloroethane. The mechanism for this reaction is a nucleophilic substitution (SN2) reaction where the phenoxide ion acts as a nucleophile and replaces the chloride ion in chloroethane. The curved arrow mechanism is shown below:Here, the phenoxide ion attacks the carbon atom in chloroethane, and the chloride ion leaves as a leaving group. The major organic product is ethyl phenyl ether (C6H5OC2H5) which is formed after the SN2 reaction.

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Answer:

It is already balanced

Explanation:

hbr     +    khco3  ===>  h20 + kbr + co2     IS BALANCED

The orbital hybridization on the central atom for a molecule with a square pyramidal molecular geometry is sp3d. This hybridization occurs when a central atom has five hybrid orbitals that are used to form bonds with other atoms.

In the case of square pyramidal geometry, the central atom is surrounded by five ligands and one lone pair, resulting in a trigonal bipyramidal arrangement.

The hybridization process involves the mixing of the central atom's s, p, and d orbitals to form five hybrid orbitals with equivalent energy levels. These hybrid orbitals have different orientations in space, with three orbitals arranged in a trigonal plane and two orbitals oriented perpendicular to the plane.

The five hybrid orbitals then overlap with the ligand orbitals to form five σ bonds. The lone pair occupies one of the hybrid orbitals, resulting in a square pyramidal molecular geometry.

This type of hybridization is common in molecules with a coordination number of five and results in strong and stable bonding between the central atom and its ligands.

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Answer:

hope it helps.

Explanation:

Zinc metal dissolves slowly in dilute sulphuric acid to form solutions containing the aquated Zn(II) ion together with hydrogen gas, H2.

Carbon dioxide gas will be more soluble in 100g of water at 25°C when the pressure is higher.

To answer this question, we need to consider how pressure affects the solubility of carbon dioxide gas in water at a given temperature (25°C in this case). According to Henry's Law, the solubility of a gas in a liquid is directly proportional to the pressure of the gas above the liquid.

So, at a higher pressure, carbon dioxide gas will be more soluble in 100g of water at 25°C. Specifically, as the pressure of carbon dioxide above the water increases, more CO₂ molecules will dissolve in the water, resulting in increased solubility.

In summary, carbon dioxide gas will be more soluble in 100g of water at 25°C when the pressure is higher.

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As per the information provided in the question, the compound that is the limiting reagent is "B". And the starting materials were "more polar" than the reaction product.

The limiting reagent is the one that gets consumed completely in the reaction. The other reactant is left behind in excess. The reaction's speed is determined by the amount of the limiting reagent present. In the given reaction, compound B is the limiting reagent. We can prove this by comparing the number of moles of compounds A and B. We can see that compound B has fewer moles. Therefore, it is the limiting reagent. 2 moles of compound A react with 1 mole of compound B. We have 2 moles of A and 1 mole of B in this reaction mixture. Hence, compound B is the limiting reagent. Starting materials are more polar than the reaction product. When a chemical reaction occurs, the reactants combine to form a new compound or product. The product's properties are often different from those of the starting materials. In this reaction, the starting materials are more polar than the reaction product. This can be seen by observing the reaction mixture's lane. We can see that the reaction product has moved ahead of the starting materials on the chromatogram. The starting materials are more polar than the reaction product.

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Answer:

The mass number (A), also called atomic mass number or nucleon number, is the total number of protons and neutrons (together known as nucleons) in an atomic nucleus. The mass number is different for each different isotope of a chemical element.