Complete the overall reaction catalyzed by the pyruvate dehydrogenase complex. Move the compounds and cofactors to the correct answer blanks. Two terms will not be used. CoA acetylCoA NADH NAD^+ ADP ATP pyruvate

Answer:

“You Asked” is a series where Earth Institute experts tackle reader questions on science and sustainability. Over the past few years, we’ve received a lot of questions about carbon dioxide — how it traps heat, how it can have such a big effect if it only makes up a tiny percentage of the atmosphere, and more. With the help of Jason Smerdon, a climate scientist at Columbia University’s Lamont-Doherty Earth Observatory, we answer several of those questions here.

Answer:

i think its C

Explanation:

The graph indicates that the reaction reaches equilibrium around 1.5 seconds. The graph shows how the concentrations of reactants and products change over time until they eventually become constant. So, the correct option is D.

Equilibrium is a state in a chemical process when forward and backward reactions occur at the same rate, meaning that the concentrations of reactants and products do not change with time. In other words, the forward reaction rate equals the reverse reaction rate.

In the example above, the graph indicates that the reaction reaches equilibrium in about 1.5 seconds. The graph shows how the concentrations of reactants and products change over time until they eventually become constant. This indicates that the reaction has reached equilibrium when obtained in approximately 1.5 seconds.

So, the correct option is D.

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Answer:

Use a ratio of 0.44 mol lactate to 1 mol of lactic acid  

Explanation:

John could prepare a lactate buffer.

He can use the Henderson-Hasselbalch equation to find the acid/base ratio for the buffer.

\(\text{pH} = \text{pK}_{\text{a}} + \log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}}\\\\3.5 = 3.86 + \log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}}\\\\\log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}} = 3.5 - 3.86 = -0.36\\\\\dfrac{\text{[A$^{-}$]}}{\text{[HA]}} = 10^{-0.36} = \mathbf{0.44}\)

He should use a ratio of 0.44 mol lactate to 1 mol of lactic acid.

For example, he could mix equal volumes of 0.044 mol·L⁻¹ lactate and 0.1 mol·L⁻¹ lactic acid.

Answer: hcl

Explanation:

Due to the trend of boiling points, the optimal order for elements within a group going from top to bottom is \(A, X_o, Z_w\).

From the given information we can see that the boiling points of the elements decrease from A to Xo to Zw. The highest boiling point (350°C) is of element A, followed by Xo (215°C) and Zw (285°C). We arrange the components in decreasing order of boiling points to get A, Xo and Zw.

It is important to remember that in this situation, the alphabetical order of the elements and their atomic weights are irrelevant considerations. A reasonable basis for arranging the components within the system is provided by the trend in boiling points.

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A precipitate is an insoluble solute formed in a solution. No precipitate will form when magnesium acetate and strontium chloride react as they produce a soluble salt.

A precipitate is an insoluble particle that is formed when the ionic compounds react to produce insoluble salt.

Reaction when magnesium acetate and strontium chloride reacts is shown as:

Mg(CH₃COO)₂ (aq) +SrCl (aq) → MgCl₂ (aq) +Sr(CH₃COO)₂ (aq)

The substance containing acetate in the compound is always soluble and hence cannot make precipitate. Also, chloride gets soluble with magnesium.

Therefore, no precipitate will be formed.

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One possible reason for cooler air temperatures in Christchurch during El Niño years is the shift in atmospheric circulation patterns.

During El Niño years, Christchurch may experience cooler air temperatures due to several factors associated with the El Niño phenomenon.

El Niño is characterized by the abnormal warming of the surface waters in the eastern tropical Pacific Ocean, which has global climatic implications. While El Niño is primarily associated with changes in oceanic conditions, its effects can extend to atmospheric patterns, leading to altered weather patterns and temperature variations.

One possible reason for cooler air temperatures in Christchurch during El Niño years is the shift in atmospheric circulation patterns. El Niño can disrupt the normal global atmospheric circulation, resulting in changes in the positioning and intensity of weather systems.

This can lead to the advection of cooler air masses from the south or southeast towards Christchurch, resulting in cooler temperatures.

Another factor is the influence of El Niño on regional rainfall patterns. El Niño often leads to drier conditions in the South Island of New Zealand, including Christchurch.

Reduced cloud cover and less moisture in the air can contribute to cooler temperatures as there is less insulation from the sun's radiation and less evaporative cooling. Additionally, the absence of significant rainfall can result in less moisture in the soil, leading to cooler conditions as less energy is used for evaporation.

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Answer:

Hello. The answer is C

Explanation:

Elements in group number 2 are:

Be _ Mg _Ca_Sr_Ba_Ra

All these elements elecrical final shell has 2 electrons so

It is easier for them to lose 2 electrons to get stable.

Answer:

C

Explanation:

Its right?

Answer:

Bohr's Model postulates-

I postulate - The electrons in an atom orbit around the nucleus in definite circular paths called orbits or shells.

II Postulate - Each shell or orbit represents a specific amount of energy.

III Postulate - By emitting or absorbing energy, an electron may shift from one stationary energy orbit to another.

Three main Limitations -

1- It adjusts to the hydrogen atom's spectrum but not to the spectra of other atoms.

2 - In the definition of the electron as a tiny particle that spins around the atomic nucleus, the wave properties of the electron are not described.

3- Bohr is unable to understand why classical electromagnetism is inapplicable to his model. That is why, when electrons are in a stationary orbit, they do not emit electromagnetic radiation.

Explanation:

About Bohr's postulates-

1 - The electron spins in circling circles around the nucleus, emitting no energy. The orbital angular momentum is constant in these orbits.

Only certain radii of orbits, corresponding to certain given energy levels, are required for electrons in an atom.

2- Not every orbit is possible. However, whenever an electron is in a legal orbit, it is in a state of unique and constant energy and does not emit energy (stationary energy orbit).

For example - The energies allowed for electrons in the hydrogen atom are given by the following equation: The Rydberg constant for the hydrogen atom is \(-2.8\times10^-^1^8\) in this equation, and n = quantum number will range from 1 to ∞. For each of the values of n, the electron energies of a hydrogen atom produced by the above equation are negative. As n rises, the energy becomes less negative and thus rises.

3- By emitting or absorbing energy, an electron may shift from one stationary energy orbit to another.

The energy difference between the two states would be equal to the energy released or consumed. This energy E is in the form of a photon, and it can be measured using the following formula:

    \(E=h\)\(v\)

E is the energy (absorbed or emitted) in this equation, and h is the Planck constant (its value is \(6.63\times10^-^3^4 Js\)) and v denotes the frequency of light, which is calculated in 1/ s.

The mass(in grams) of iron, Fe produced from the 92.5g of iron (ii) oxide, FeO is 71.9 grams

The mass of Fe produced from the 92.5g of iron (ii) oxide, FeO can be obtained as follow:

2FeO → 2Fe + O₂

From the balanced equation above,

143.7 g of FeO reacted to produce 111.7 g of Fe

Therefore,

92.5 g of Fe will react to produce = (92.5 × 111.7) / 143.7 = 71.9 g of Fe

Thus, the mass of Fe produced from the reaction is 71.9 grams

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Complete question:

How many grams of Fe are produced from 92.5 g of FeO given the following reaction 2FeO → 2Fe + O₂

The structure of fatty acids involves long carbon-based chains with a carboxyl group (―COOH) located in the end, triglycerides phospholipids contain a phosphate group and glycerol, while steroids are cyclic and they contain C atoms linked via 4 fused rings.

Lipids are a broad category of biomolecules that include fatty acids, triglycerides phospholipids, and steroids. For example, fatty acids are long carbonated chains that contain exactly identical CH2 groups in the interior of the molecule and a carboxyl group (―COOH) located at one extreme side.

Triglycerides phospholipids are composed of three fatty acids chains linked to a glycerol backbone and also a phosphate group that may confer polar properties to the molecule.

Finally, steroids are another important class of lipids composed of several carbon-based fused rings.

Therefore, we can conclude that fatty acids, triglycerides phospholipids, and steroids are structurally different lipids that are mainly composed of carbon-based structures.

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Answer:

\(\boxed {\boxed {\sf 1.6 \times 10^{24} \ atoms \ Si}}\)

Explanation:

We are asked to find how many atoms are in a sample of 75 grams of silicon.

First, we must convert grams to moles using the molar mass. This is the mass of 1 mole of a substance. The molar mass is found on the Periodic Table because it is equal to the atomic mass, but the units are grams per mole instead of atomic mass units.

Look up the molar mass of silicon.

We convert using dimensional analysis, so we must set up a conversion factor.

\(\frac {28.085 \ g \ Si}{1 \ mol \ Si}\)

We are converting 75 grams of silicon to moles, so we multiply by this value.

\(75 \ g \ Si*\frac {28.085 \ g \ Si}{1 \ mol \ Si}\)

Flip the conversion factor so the units of grams of silicon cancel.

\(75 \ g \ Si*\frac {1 \ mol \ Si}{28.085 \ g \ Si}\)

\(75 *\frac {1 \ mol \ Si}{28.085 }\)

\(\frac {75}{28.085} \ mol \ Si\)

\(2.670464661 \ mol \ Si\)

Next, we convert moles to atoms using Avogadro's Number, or 6.022 ×10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this problem, the particles are atoms of silicon.

Set up another conversion factor, this time with Avogadro's Number.

\(\frac {6.022 \times 10^{23} \ atoms \ Si}{1 \ mol \ Si}\)

Multiply by the number of moles we found.

\(2.670464661 \ mol \ Si*\frac {6.022 \times 10^{23} \ atoms \ Si}{1 \ mol \ Si}\)

The units of moles of silicon cancel.

\(2.670464661 *\frac {6.022 \times 10^{23} \ atoms \ Si}{1 }\)

\(2.670464661 * {6.022 \times 10^{23} \ atoms \ Si}\)

\(1.60815382 \times 10^{24} \ atoms \ Si\)

The original value of grams (75) has 2 significant figures, so our answer must have the same. For the number we found, that is the tenths place. The 0 in the hundredths place tells us to leave the 6 in the tenths place.

\(1.6 \times 10^{24} \ atoms \ Si\)

Answer:

the answer is pressure is less then 1atm

Explanation:

Denver is located exactly one mile above sea level, which means the normal atmospheric pressure is less than 1 atm. As a result,  water boil at a lower temperature of 95 degree Celsius.

There are small molecules of air in the atmosphere and these molecules combine and forms different layer in the atmosphere which creat some kind of pressure.

The pressure create by the air molecule layer is known to be the atmospheric pressure which is exerted or eel by the everything in the atmosphere and less pressure will decreases the temperature for water boiling point.

Therefore, boil at a lower temperature of 95 degree Celsius as Denver is located exactly one mile above sea level, which means the normal atmospheric pressure is less than 1 atm.

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Answer:

A) Electrons orbit the nucleus in shells at fixed distances

Answer:

the answer is A

Explanation:

Answer:

The r.a.m. value is used to determine how many isotopes an element has.

Explanation:

In order to find the empirical formula of this compound, we need to find the number of moles of each element present in this molecule, we can do that by using the given information if the question, and the molar mass of each element:

90 grams of Carbon, molar mass = 12 grams/mol

11 grams of Hydrogen, molar mass = 1 gram/mol

35 grams of Nitrogen, molar mass = 14 grams/mol

Now let's start with Carbon:

12g = 1 mol

90g = x moles

x = 7.5 moles of Carbon in 90 grams

Hydrogen:

1g = 1 mol

11g = x moles

x = 11 moles of Hydrogen in 11 grams

Nitrogen:

14g = 1 mol

35g = x moles

x = 2.5 moles of Nitrogen in 35 grams

Now we have 7.5 moles of C, 11 moles of H and 2.5 moles of N, according to the rules on building the molecular formula of a compound, we can not use decimal numbers to build it, therefore we need to multiply all the values for 2

7.5 * 2 = 15 moles of Carbon

11 * 2 = 22 moles of Hydrogen

2.5 * 2 = 5 moles of Nitrogen

Now we have all the number in the integer form

To find the empirical formula, we need to divide all the values by the smallest value of moles:

15/5 = 3 moles

22/5 = 4.4 moles

5/5 = 1 mol

Therefore the final empirical formula is C3H4N

The partial charges on each fluorine atom are negative. Option B) The central O atom is the correct answer. Option B

The partial charges in a molecule are determined by the electronegativity values of the atoms involved. Electronegativity is the ability of an atom to attract electrons towards itself in a chemical bond. In the case of \(F_2O\), fluorine (F) is more electronegative than oxygen.

Fluorine is the most electronegative element on the periodic table, meaning it has a high ability to attract electrons. Oxygen is also relatively electronegative but less so than fluorine. When fluorine atoms bond with oxygen, the shared electrons will be pulled more towards the fluorine atoms, creating a polar covalent bond.

In \(F_2O\), each fluorine atom will pull the shared electrons towards itself, resulting in a higher electron density around the fluorine atoms. This creates a region of partial negative charge around the fluorine atoms.

Conversely, the oxygen atom will have a region of lower electron density and, therefore, a partial positive charge. This is because the shared electrons spend more time around the fluorine atoms due to their higher electronegativity.

Option B

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Ancef (Cefazolin) is a first-generation cephalosporin antibiotic that is used to treat bacterial infections. Cefazolin is available in several formulations, including injectable, intravenous, and powder for injection.

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Answer:

1 and 4

Explanation:

in both pictures the temperature is cooling down

Answer:

C

Explanation:

the answer has 5 Numbers

Answer:

4.83 km

Explanation:

Let's consider the following subtraction.

4.910 km - 0.08 km

For an addition or a subtraction, the rule for significant figures is as follows: limit the reported answer to the rightmost column that all numbers have significant figures in common, in this case, 2 figures after the decimal point.

4.910 km - 0.08 km = 4.83 km

Answer:

[Ni(CN)4]2- square planar

[NiCl4]2- tetrahedral

Explanation:

For a four coordinate complex such as [Ni(CN)4]2- and [NiCl4]2-, we can decide its geometry by closely considering its magnetic properties. Both of the complexes are d8 complexes which could be found either in the tetrahedral or square planar crystal field depending on the nature of the ligand.

CN^- being a strong field ligand leads to the formation of a square planar diamagnetic d8 complex of Ni^2+. Similarly, Cl^- being a weak field ligand leads to the formation a a tetrahedral paramagnetic d8 complex of Ni^+ hence the answer given above.

Answer:

+4

Explanation:

Treatment of the ammonium metavanadate with hot hydrochloric acid partly reduces the vanadium to the +4 oxidation state in the form of the VO2+ ion.

In vanadium oxide we increase both sides by 4. And we discover that x is equal to five. The vanadium's oxidation number is + 5.

Loss of electron is called as oxidation. and addition of oxygen molecule is also the oxidation.

When an object comes into touch with oxygen or another oxidizer, a chemical reaction occurs. Rust and the brown color of a sliced apple are both examples of oxidation.

Antoine Lavoisier used the term "oxidation" to describe the reaction of a material with oxygen. The meaning was later expanded to cover additional reactions in which electrons are lost, regardless of whether oxygen was present, after it was realized that the substance loses electrons when it is oxidized.

Thus,  the oxidation number of vanadium in V₂O₅ is + 5.

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Explanation:

To determine the molar mass of the gas, we need to use the ideal gas law equation:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature. We can rearrange this equation to solve for the number of moles:

n = (PV) / (RT)

We are given the mass of the gas (0.643 g), the volume (125 mL), the pressure (60. cm Hg), and the temperature (25°C). To use these values in the ideal gas law equation, we need to convert the volume to liters and the pressure to atmospheres (atm) and the temperature to Kelvin (K):

V = 125 mL = 0.125 L

P = 60. cm Hg = 0.789 atm (using the conversion factor 1 atm = 760 mm Hg and 1 cm Hg = 1.33322 mm Hg)

T = 25°C + 273.15 = 298.15 K

Substituting these values into the ideal gas law equation and solving for n gives:

n = (PV) / (RT) = (0.789 atm x 0.125 L) / (0.0821 L·atm/mol·K x 298.15 K) = 0.00314 mol

To find the molar mass, we can use the formula:

molar mass = mass of sample / number of moles

molar mass = 0.643 g / 0.00314 mol = 204.46 g/mol

Therefore, the molar mass of the gas is approximately 204.46 g/mol.

Answer:

To determine the molar mass of the gas, we need to use the ideal gas law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. We can rearrange this equation to solve for n:

n = PV/RT

First, we need to convert the pressure to atmospheres (atm) and the volume to liters (L):

cm Hg = 0.788 atm (using the conversion factor 1 atm = 760 mm Hg)

125 mL = 0.125 L

Next, we can substitute the given values into the equation and solve for n:

n = (0.788 atm)(0.125 L)/(0.0821 L·atm/mol·K)(298 K) = 0.00472 mol

Finally, we can calculate the molar mass by dividing the mass of the sample by the number of moles:

molar mass = 0.643 g/0.00472 mol = 136 g/mol (rounded to three significant figures)

Therefore, the molar mass of the gas is approximately 136 g/mol.

CuI2 is not a known compound. Copper compounds typically have different oxidation states for copper, resulting in various compound names.

Copper(II) oxide (CuO): It is a black solid compound where copper is in the +2 oxidation state. It is commonly used as a pigment and in catalytic reactions.

Copper(II) sulfate (CuSO4): It is a blue crystalline compound in which copper is in the +2 oxidation state. It is used in various applications such as agriculture, electroplating, and as a laboratory reagent.

Copper(I) oxide (Cu2O): It is a red crystalline compound in which copper is in the +1 oxidation state. It is used as a pigment, in solar cells, and as a catalyst.

Copper(II) chloride (CuCl2): It is a greenish-brown solid compound in which copper is in the +2 oxidation state. It is utilized in various chemical processes, including etching and catalyst synthesis.

Copper(II) nitrate (Cu(NO3)2): It is a blue crystalline compound where copper is in the +2 oxidation state. It is commonly used in the production of catalysts, as a coloring agent, and in electroplating.

These are just a few examples of copper compounds with different oxidation states and properties. It's important to note that the compound CuI2 mentioned in the question, if it exists, would be an exception to the typical nomenclature for copper compounds.

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2265 g Fe₃O₄

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[RxN - Balanced] Fe₃O₄ + 4H₂ → 3Fe + 4H₂O

[Given] 705.0 g H₂O

Step 2: Identify Conversions

[RxN] 4 mol H₂O → 1 mol Fe₃O₄

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Fe - 55.85 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

Molar Mass of Fe₃O₄ - 3(55.85) + 4(16.00) = 231.55 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 4 sig figs.

2264.74 g Fe₃O₄ ≈ 2265 g Fe₃O₄

The balanced chemical equation for the combustion of propane with oxygen is: C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

To balance the equation, first balance the carbon atoms on both sides of the equation. There are three carbon atoms in the propane molecule and three in the carbon dioxide molecule, so balance the carbon atoms by putting a coefficient of 3 in front of the CO₂ molecule.

C3H8 + 5O2 → 3CO₂

Next, balance the hydrogen atoms. There are eight hydrogen atoms in the propane molecule and four in the water molecule, so balance the hydrogen atoms by putting a coefficient of 4 in front of the H₂O molecule.

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

Finally, balance the oxygen atoms. There are five oxygen atoms on the left side and 10 on the right side, so balance the oxygen atoms by putting a coefficient of 5 in front of the O₂ molecule.

Therefore, the correct whole number coefficient for propane, C3H8, is 1.

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