Complete the description of a real-world situation that might involve three linear equations in three variables.

you are trying to find the ages of three people. you know the sum of all three ages, the sum of the first two ages and blank (the answer choices are twice the third or the third age squared), and the sum of the first and third ages and blank (the answer choices are twice the second or the square root of the second)
* just to be clear there are two blanks and two possible answer choices for each

Answer:

x=81

y=33

z=9

SEE THE IMAGE FOR SOLUTION

The area between the large loop and the enclosed small loop of the curve r=24cos(3) is approximately 8.75 square units.

To find the area between the large loop and the enclosed small loop, we need to first determine the values of θ where the loops occur. The polar equation r=24cos(3) has two loops, with the smaller loop enclosed within the larger one. The smaller loop occurs when cos(3)=0, which happens when theta is a multiple of π/6. The larger loop occurs when r=0, which happens when cos(3)=-1/2 or when theta is a multiple of π/3. To calculate the area between the loops, we can integrate the area of the sector between two adjacent θ values and subtract the area of the smaller loop from the larger loop. This gives us an approximation of 8.75 square units for the area between the loops. The actual value can be obtained by using calculus to calculate the definite integral of the difference in the areas of the two loops.

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Answer:

72 degree

Step-by-step explanation:

It is given that :

Sports   Hours

Soccer     5

Jogging   20

Walking    10

Skiing        5

Football   10

                50 hours

The total hour is given as 50 hours. Out of which walking is 10 hours.

Therefore, in degree the portion of walking will be :

  \($=\frac{10}{50} \times 360^\circ$\)

 \($=72^\circ$\)

The lock can be solved by examining the asset allocation of each mutual fund and identifying its type according to the given key.

The correct series of numbers can then be obtained by concatenating the numbers corresponding to the mutual funds in the order in which they appear.

To solve the lock, we need to examine the asset allocation of each mutual fund and identify its type according to the given key. The key may include categories such as large-cap stocks, small-cap stocks, international stocks, bonds, and cash. Based on the asset allocation of each mutual fund, we can determine its type and assign a number from the key to it.

For example, if a mutual fund has an asset allocation of 60% large-cap stocks, 20% small-cap stocks, 10% international stocks, 5% bonds, and 5% cash, we can identify it as a large-cap stock fund and assign it the number 1 from the key. Similarly, if a mutual fund has an asset allocation of 30% small-cap stocks, 50% international stocks, 10% bonds, and 10% cash, we can identify it as an international stock fund and assign it the number 3 from the key.

Once we have identified the type of each mutual fund and assigned a number from the key to it, we can concatenate the numbers corresponding to the mutual funds in the order in which they appear to obtain the correct series of numbers for the lock.

For example, if the mutual funds in the order in which they appear are a large-cap stock fund, a bond fund, an international stock fund, and a cash fund, and their corresponding numbers from the key are 1, 4, 3, and 5 respectively, then the correct series of numbers for the lock would be 1435.

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4444444444444444444 4444444

Answer:

4

Step-by-step explanation:

A P E X:L E A R N I N G

The required perimeter of the given figure will be 60.84 m.

We have been given the figure which is made up of a rectangle and half a circle.

We have to determine the perimeter of the given figure.

As per the given figure, the required solution would be as:

The required perimeter = 2 × (rectangle's length) + rectangle's width + circumference of half a circle

The required perimeter = 2 × 15 + 12 + π × 6

The required perimeter = 30 + 12 + 3.14 × 6

The required perimeter = 30 + 12 + 18.84

Apply the addition operation, and we get

The required perimeter = 60.84 m

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If you enroll in college at age 19, you will likely be in your first year, sometimes known as your "freshman year." You will normally be in your third year or "junior year" at the age of 22 .

You could still be admitted into college at age 16, even though applicants to colleges are normally at least 17 years old. You will probably need to complete additional documentation and obtain your parents' or guardians' written authorization because you are a younger person.

Attending college is never too late. In actuality, there is no upper age limit for applicants, albeit older ones would need to go through a separate admissions procedure. Today's higher education institutions give adult and returning students the chance to further their studies on their own.

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The value of the expression (8 1/5 + 4 1/5) - (6 6/8 - 6 2/4) is 243/20.

Let's simplify the addition within the parentheses:

8 1/5 + 4 1/5 = (8 + 4) + (1/5 + 1/5) = 12 + 2/5 = 12 2/5

Next, let's simplify the subtraction within the parentheses:

6 6/8 - 6 2/4 = (6 - 6) + (6/8 - 2/4) = 0 + (3/4 - 1/2) = 0 + 1/4 = 1/4

Now, we can substitute the simplified terms back into the original expression:

(8 1/5 + 4 1/5) - (6 6/8 - 6 2/4) = 12 2/5 - 1/4

To subtract mixed numbers, we need to find a common denominator. The common denominator for 5 and 4 is 20. Converting both terms:

12 2/5 = 12 * 5/5 + 2/5 = 60/5 + 2/5 = 62/5

1/4 = 1 * 5/5 * 5/20 = 5/20

Now we can subtract:

62/5 - 5/20 = (62 * 4)/(5 * 4) - 5/20 = 248/20 - 5/20 = (248 - 5)/20 = 243/20

Therefore, the value of the expression (8 1/5 + 4 1/5) - (6 6/8 - 6 2/4) is 243/20.

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Are 5,040 different possible settings for the suitcase lock if all four digits have to be different.

For the first dial, there are 10 possible digits (0 to 9) that can be set. For the second dial, there are 9 remaining digits to choose from (since we cannot repeat the digit from the first dial). For the third dial, there are 8 remaining digits to choose from (since we cannot repeat any of the digits from the first two dials). Finally, for the fourth dial, there are 7 remaining digits to choose from.

Therefore, the total number of possible settings for the suitcase lock with all four digits different is:

10 × 9 × 8 × 7 = 5,040

There are 5,040 different possible settings for the suitcase lock if all four digits have to be different.

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The data includes a concave mirror with a radius of curvature of +31.5 cm and magnification of m = 3.40. The formula for magnification is m = v/u, and the focal length is f = r/2. Substituting the values, we get u = v/m, and using the mirror formula, the distance of the object from the mirror is 10.15 cm.

Given data: Radius of curvature of a concave mirror, r = +31.5 cm Magnification produced by the mirror, m = 3.40

We know that the formula for magnification is given by:

m = v/u where, v = the distance of the image from the mirror u = the distance of the object from the mirror We also know that the formula for the focal length of the mirror is given by :

f = r/2where,f = focal length of the mirror

Using the mirror formula:1/f = 1/v - 1/u

We know that a concave mirror has a positive focal length, so we can replace f with r/2.

We can now simplify the equation to get:1/(r/2) = 1/v - 1/u2/r = 1/v - 1/u

Also, from the given data, we have :m = v/u

Substituting the value of v/u in terms of m, we get: u/v = 1/m

So, u = v/m Substituting the value of u in terms of v/m in the previous equation, we get:2/r = 1/v - m/v Substituting the given values of r and m in the above equation, we get:2/31.5 = 1/v - 3.4/v Solving for v, we get: v = 22.6 cm Now that we know the distance of the image from the mirror, we can use the mirror formula to find the distance of the object from the mirror.1/f = 1/v - 1/u

Substituting the given values of r and v, we get:1/(31.5/2) = 1/22.6 - 1/u Solving for u, we get :u = 10.15 cm

Therefore, the distance of the mirror from the face is 10.15 cm. The units are centimeters (cm).Answer: 10.15 cm.

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Yes, the boxplot represent the information given in the histogram. (option a)

Based on the information given, the boxplot has a left whisker extending from about 7 to 14, the left part of the box extending from about 14 to 23, the right part of the box extending from about 23 to 26, the right whisker extending from about 26 to 34, and a point at 55. To determine if the boxplot represents the information given in the histogram, we need to compare the two graphs.

In conclusion, based on the given options, the correct answer is A) Yes, but we cannot determine if the boxplot accurately represents the information given in the histogram without seeing the histogram.

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Solution of the given algebraic expression (f-g)(x) is equal to 4x³+6x²-7x-1

Algebraic equations are defined as mathematical statements in which two algebraic expressions are set equal to each other. An algebraic expression usually consists of  variables,  coefficients and  constants. Algebraic equations can be of many types, such as monomial algebraic equations, binomial algebraic equations, quadratic algebraic equations, polynomial equations.  

Given in the question that the value of f(x) is equal to 4x³+6x²-3x-4

and the value of g(x) is equal to 4x-3.

Subtracting g(x) from f(x) we get,

(f-g)(x)= 4x³+6x²-3x-4-4x+3

4x³+6x²-7x-1

Therefore, solution of the given algebraic expression (f-g)(x) is equal to 4x³+6x²-7x-1.

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Answer:

55 and (-3)

Step-by-step explanation:

The range is the difference between the smallest number and the biggest number.

If we take 4 as the smallest number, X would be the biggest number:

4 + 51 = 55

If we take 48 as the biggest number, X would be the smallest number:

48 - 51 = -3

The measure of each angle formed by the three support beams for a bridge is 45 degrees.

The question states that three support beams for a bridge form a pair of complementary angles. Complementary angles are two angles that add up to 90 degrees.

Let's denote the angles as Angle A and Angle B. Since the angles are complementary, we can set up the following equation:

Angle A + Angle B = 90 degrees.

To find the measure of each angle, we need to divide 90 degrees by 2 since there are two angles.

Angle A = Angle B = 90 degrees / 2 = 45 degrees.

Therefore, each angle measures 45 degrees.

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The measure of each angle is 45 degrees.

To find the measure of each angle, we need to understand what complementary angles are. Complementary angles are two angles that add up to 90 degrees.

In this case, we have three support beams for a bridge that form a pair of complementary angles. Since the angles are complementary, their sum is 90 degrees.

Let's assume the measure of one angle is x degrees. The other angle will be (90 - x) degrees, as their sum is 90 degrees.

Since the three support beams form a pair of complementary angles, we can set up the equation:

x + (90 - x) = 90

By simplifying the equation, we have:

90 - x + x = 90

90 = 90

This equation is true for any value of x. Therefore, the measure of each angle can be any value, as long as their sum is 90 degrees.

So, the measure of each angle is not fixed, but it will always add up to 90 degrees.

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To find the width of Todor's area model for the expression 10x² - 5x + 15x, we first factored out the GCF 5x. The factors of the GCF are 5, x, and -1/111, which we wrote in an area model. We then added the absolute values of the coefficients of the factors to get a width of 1 + (1/37).

The expression to factor is 10x² - 5x + 15x

Find the GCF of the terms in the expression

We can factor out 5x from all three terms

10x² - 5x + 15x = 5x(2x - 1 + 3)

The GCF of the expression is 5x.

Write the factors of the GCF with their coefficients in the area model

We can write the area model as in image.

To Find the width of the area model

The width of the area model is the sum of the absolute values of the coefficients of the factors. So, we can add the absolute values of the coefficients in the third row of the area model

|(-5/555)| + |1| + |(-1/111)| = (5/555) + 1 + (1/111) = 1 + (1/37)

Therefore, the width of Todor's area model is 1 + (1/37).

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--The given question is incomplete, the complete question is given

"Todor was trying to factor 10x²-5x+1510x

, x, squared, minus, 5, x, plus, 1510x. He found that the greatest common factor of these terms was 555 and made an area model:

What is the width of Todor's area model?"--

Answer:

40

Step-by-step explanation:

product means multiplication

so -5×-8 = 40

(the negative are calceled)

Answer:its A or C

Step-by-step explanation:i hope this helps

Answer: 1 + 1 = 2

2-1 = 1

Step-by-step explanation:

basic math stuff

Lets check how?

Factors of 3=1,3

Max value possible=1+3=4

Minimum value=-1-3=-4

So Verified

Answer: x2 – 10x + 25 = (x – 5)(x – 5)

                      = (x – 5)2

Answer:

Refer to the attachment \(\Huge {\nearrow}\)

\(\setlength{\unitlength}{1cm}\begin{picture}(20,15)\thicklines\qbezier (1,0)(1,0)(7,0)\qbezier(1,0)(1,0)(2,3)\qbezier (7,0)(7,0)(2,3)\put (0.5,-0.2){\sf X}\put(7.1,-0.2){\sf Y}\put(2,3.2){\sf Z}\end{picture}\)

Answer:

All answers expect CD

Step-by-step explanation:

A circle is a shape that has a fixed point(called the center) that is equal from any point on the circle arc. A radius is from the center of the circle to the circumference( the circle's arc) and is half of the diameter.. Using those logic, AC,AD  are a radius  because it half of diameter,  AE, AG, AB are one because it goes from the center of the circle to its point on the circle arc. C

CD is the diameter.

Answer:

Tarea:

Ana compró una cartera cuyo precio es x dólares con el 10% de descuento y un perfume con precio original en dólares con un descuento del 15%. ¿Cuánto gastó Ana en total?

- Solución:

El precio estará en lenguaje algebraico, ya que no nos dan el dato de cuánto costó cada artículo.

• Hallamos el precio de la cartera con el descuento:

El precio original es x, entonces:

Regla de tres:

100 % --------> x

10 % -----------> ?

10 . x : 100 = ?

10x/100 = ?

El 10% del precio de la cartera es 10x/100.

Entonces el precio de la cartera es (x-10x/100).

• Hallamos el precio del perfume con el descuento:

El precio original es y, entonces:

Regla de tres:

100% -------> y

15 % --------> ?

15.y/100

El 15% del perfume es 15y/100.

Entonces el precio del perfume con el descuento es (y-15y/100).

Entonces lo que gastó en total es:

(x - 10x/100) + (y - 15y/100)

Step-by-step explanation:

pls give me brainless

The correct description for the distribution of the sample proportion of adults in the sample who don't have health insurance is X - B(120, 0.15).

B(120, 0.15) represents a binomial distribution with parameters n = 120 (the sample size) and p = 0.15 (the population proportion of adults without health insurance).

The binomial distribution is appropriate in this case because we have a fixed sample size and each individual in the sample can either have health insurance (success) or not have health insurance (failure). The sample proportion of adults without health insurance can be calculated by dividing the number of adults without health insurance by the total sample size.

Therefore, the correct description is X - B(120, 0.15).

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There should be q icon that says give answer, to find new questions in that section refresh the page

Answer:B

Step-by-step explanation:

Its b,i swear on my doggie

Answer:

A and D

Step-by-step explanation:

Given that EFGH is a scaled copy of ABCD, EFGH is similar to ABCD. The ratio of the corresponding lenght of their segments are equal, and therefore have the same scale factor.

This means: \( \frac{EF}{AB} = \frac{FG}{BC} = \frac{GH}{CD} = \frac{EH}{AD} \)

We are given only the length of segment GH = 12. GH corresponds with segment CD = 6, therefore:

Scale factor = \( \frac{GH}{CD} = \frac{12}{6} = 2 \).

This implies that all length segments of ABCD was increased by 2 to get a scale copy of EFGH.

Angles in EFGH will have the same measures of degree as the corresponding angles in ABCD, because, it would have the same shape but only different in size.

The following statements are therefore true:

A. Segment EF is twice as long as segment AB. (Scale factor = 2)

D. The length of segment EH is 16 units. (EH = 2*AD = 2*8 = 16)

Answer:

27

Step-by-step explanation:

factors are numbers that divide exactly into a number , leaving no remainder.

then the only factor of 27 from the list is 27

Answer:

Step-by-step explanation:

-3/8y = -24

-3y = -24 (8)

y = -192 / -3

y = 64

The probability that both Event A (coin lands on heads) and Event B (die is 5 or greater) will occur is 1/6.

To find the probability that both Event A (coin lands on heads) and Event B (die is 5 or greater) will occur, we need to determine the individual probabilities of each event and then multiply them together since the events are independent.

Event A: The coin lands on heads

A fair coin has two equally likely outcomes, heads or tails. Since we are interested in the probability of heads, there is only one favorable outcome out of two possible outcomes.

P(A) = 1/2

Event B: The die is 5 or greater

A fair six-sided die has six equally likely outcomes, numbers 1 through 6. Out of these six outcomes, there are two favorable outcomes (5 and 6) for Event B.

P(B) = 2/6 = 1/3

To find the probability of both events occurring (A and B), we multiply the individual probabilities:

P(A and B) = P(A) * P(B) = (1/2) * (1/3) = 1/6

Therefore, the probability that both Event A (coin lands on heads) and Event B (die is 5 or greater) will occur is 1/6.

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Each child would get 1/12 th part of the whole watermelon.

For given question,

8 children have to share two thirds of a watermelon equally .

This means we need to equally distribute 2/3 of whole watermelon to 8 children.

To divide 2/3 part of of a watermelon equally into 8 parts, we need to divide 2/3 by 8.

(2/3) ÷ 8

= \(\frac{(\frac{2}{3} )}{8}\)

We know that in 8 = 8/1

So, we rewrite the denominator of above fraction as,

\(\frac{(\frac{2}{3} )}{8} \\\\= \frac{(\frac{2}{3} )}{(\frac{8}{1} )} \\\\=\frac{2}{3} \times \frac{1}{8} \\\\=\frac{1}{12}\)

This means, each child will get 1/12 part of the whole watermelon.

Therefore, each child would get 1/12 part of the whole watermelon.

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