The conversion each unit gives:
12,000 g = 12 kg
120 cm = 1200 mm
1.2 L = 1200 mL
1,200 cm = 12 m
0. 12 m = 120 mm
How to convert from one unit to another?
Conversion of units is the process of converting between different units of measurement for the same quantity through conversion factors.
1000 g = 1 kg. Thus,
12,000 g = 12 kg
1 cm = 10 mm. Thus,
120 cm = 1200 mm
1L = 1000 mL. Thus,
1.2 L = 1200 mL
100 cm = 1 m. Thus,
1,200 cm = 12 m
1 m = 1000 mm. Thus,
0. 12 m = 120 mm
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find f f . f ' ' ( x ) = 20 x 3 12 x 2 4 , f ( 0 ) = 7 , f ( 1 ) = 3 f′′(x)=20x3 12x2 4, f(0)=7, f(1)=3
The values of C1 and C2 back into f(x), we get the final expression. The function f(x) is given by \(f(x) = x^5 - x^4 + 2x^2 - 6x + 7\).
]we get:3 = - 4(1)⁵ + 8(1)⁴ - 4(1)³ + 4(1) + C∴ C = 3 + 4 - 8 + 4 - 3 = 0
∴ f(x) = - 4x⁵ + 8x⁴ - 4x³ + 4x + 0
∴ f(x) = - 4x⁵ + 8x⁴ - 4x³ + 4x
Hence, the value of f(x) is - 4x⁵ + 8x⁴ - 4x³ + 4x.
The given function is f f . f ' ' ( x ) = 20 x 3 12 x 2 4 , f ( 0 ) =
7 , f ( 1 )
= 3
We need to find f(x).
Given function is f f . f ' ' ( x ) = 20 x 3 12 x 2 4 , f ( 0 ) = 7 , f ( 1 ) = 3
We know that f′(x) = f(x)f′′(x)
Differentiating both sides with respect to x,
we get: f′′(x) = f′(x) + x f′′(x)
Let's substitute the given values :f(0) = 7; f(1) = 3;
f′′(x) = 20x³ - 12x² + 4
From f′′(x) = f′(x) + x f′′(x),
we get: f′(x) = f′′(x) - x f′′(x)
= 20x³ - 12x² + 4 - x(20x³ - 12x² + 4)
= - 20x⁴ + 32x³ - 12x² + 4xf′(x)
= - 20x⁴ + 32x³ - 12x² + 4
Let's integrate f′(x) to get
f(x):∫f′(x) dx = ∫(- 20x⁴ + 32x³ - 12x² + 4) dx
∴ f(x) = - 4x⁵ + 8x⁴ - 4x³ + 4x + Cf(0) = 7
∴ 7 = C Using f(1) = 3.
Given:
\(f''(x) = 20x^3 - 12x^2 + 4\)
f(0) = 7
f(1) = 3
First, let's integrate f''(x) once to find f'(x):
f'(x) = ∫\((20x^3 - 12x^2 + 4)\) dx
= \((20/4)x^4 - (12/3)x^3 + 4x + C_1\)
=\(5x^4 - 4x^3 + 4x + C_1\)
Next, let's integrate f'(x) to find f(x):
f(x) = ∫\((5x^4 - 4x^3 + 4x + C_1)\) dx
=\((5/5)x^5 - (4/4)x^4 + (4/2)x^2 + C_1x + C_2\)
= \(x^5 - x^4 + 2x^2 + C_1x + C_2\)
Now, we'll apply the initial conditions to determine the values of the constants C1 and C2:
Using f(0) = 7:
7 = \((0^5) - (0^4) + 2(0^2) + C_1(0) + C_2\)
7 = \(C_2\)
Using f(1) = 3:
3 = \((1^5) - (1^4) + 2(1^2) + C_1(1) + C_2\)
3 = 1 - 1 + 2 + \(C_1\) + 7
3 = \(C_1\) + 9
\(C_1 = -6\)
Now, substituting the values of C1 and C2 back into f(x), we get the final expression for f(x):
\(f(x) = x^5 - x^4 + 2x^2 - 6x + 7\)
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Label the missing side and angle measurements
Which expressions are polynomials?
Select each correct answer.
Answer:
b and d option are correct
Answer:
B, D
Step-by-step explanation:
B, D
x cannot be in a root. (A)
x cannot be in the denominator. (C)
If two lines are perpendicular, their slopes are negative reciprocals
Answer:
true
Step-by-step explanation:
Answer:
True
Both slopes have to be negative reciprocals for the two lines to be perpendicular.
Hope this Helps!
Four out of nine dogs weigh less than 20 pounds.
What is the decimal equivalent for the number of dogs weighing less than 20 pounds
Answer:
.44 repeating would be your decimal of dogs that weigh under 20 pounds.
Step-by-step explanation:
Answer:
.44
Step-by-step explanation:
(10 POiNTS!!!)Find the value of x that makes this a true statement.
−3(x − 100) = −5(x − 100) + 6
Answer: x = 100
Step-by-step explanation:
A business company makes a net profit of Rs 80,00,000 in a year. The Board of Directors declares 12% cash dividend from the net profit. If the company has sold 000 shares, answer the following questions. i) Find the total cash dividend. (ii) Find the dividend for each share.
does 23 26 50 make a triangle
A fence is 10 feet tall. A stick leans against the fence as shown. What is the length of the stick?
a recurrence relation for the number of ways to deposit n dollars in the vending machine, where the order in which the coins and bills are deposited matters.
With these base cases and the defined recurrence relation, you can recursively calculate the number of ways to deposit any given amount of dollars, considering the order of coins and bills.
To formulate a recurrence relation for the number of ways to deposit n dollars in a vending machine, where the order of coins and bills matters, we can break it down into smaller subproblems.
Let's define a function, denoted as F(n), which represents the number of ways to deposit n dollars. We can consider the possible options for the first coin or bill deposited and analyze the remaining amount to be deposited.
1. If the first deposit is a coin of value d, where d is a positive integer less than or equal to n, the remaining amount to be deposited will be (n - d) dollars. Therefore, the number of ways to deposit the remaining amount, considering the order, would be F(n - d).
2. If the first deposit is a bill of value b, where b is a positive integer less than or equal to n, the remaining amount to be deposited will be (n - b) dollars. Similar to the coin scenario, the number of ways to deposit the remaining amount, considering the order, would be F(n - b).
To obtain the total number of ways to deposit n dollars, we sum up the results from both scenarios:
F(n) = F(n - 1) + F(n - 2) + F(n - 3) + ... + F(1) + F(n - b)
Here, b represents the largest bill denomination available in the vending machine. You can adjust the range of values for d and b based on the available denominations of coins and bills.
It's important to establish base cases to define the initial conditions for the recurrence relation. For example:
F(0) = 1 (There is only one way to deposit zero dollars, which is to deposit nothing)
F(1) = 1 (There is only one way to deposit one dollar, either as a coin or a bill)
With these base cases and the defined recurrence relation, you can recursively calculate the number of ways to deposit any given amount of dollars, considering the order of coins and bills.
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let c be the point on the line segment ab that is twice as far from b as it is from a. if a − oa l, b − ob l, and c − oc l, show that c − 2 3 a 1 1 3 b.
To show that\(\( \vec{c} = \frac{2}{3}\vec{a} + \frac{1}{3}\vec{b} \)\) , we can use the concept of vector addition and scalar multiplication.
We know that point vector c lies on the line segment \(\( \overline{ab} \)\) and is twice as far from point vector b as it is from point vector a .We can express the position vector of point vector c as a combination of vector a and \( \vec{b} \) using scalar multiplication and vector addition.
The distance ratio between vector c and \( \vec{b} \) is \( \frac{2}{3} \) (twice as far from \( \vec{b} \) as vector a .
Similarly, the distance ratio between vector c and vector a is \( \frac{1}{3} \) (half the distance between \( \vec{b} \) and vector a
Using these distance ratios, we can express the position vector vector c as \(\( \vec{c} = \frac{2}{3}\vec{a} + \frac{1}{3}\vec{b} \).\)
Hence, we have shown as desired.
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What is the value of the product (3 - 2i(3 + 2i?
Answer:
i is always positive
Step-by-step explanation:
if be multiply 3 by 3 and get 9, then you multiply -2i by 2i and get -4i squared
9-4i^2 is now easy to solve unless we do now know the value of i, but since i is squared, i is always positive
Answer:
13
Step-by-step explanation:
Assuming this is (3-2i)(3+2i)
Use the FOIL method
First: 3(3) = 9
Outter: 3(2i) = 6i
Inner: -2i(3) = -6i
Last: -2i(2i) = -4i²
Add all of them together:
9 + 6i - 6i - 4i²
= 9 - 4i² = 9 - 4(-1) = 9 + 4 = 13
*NOTE that i² = -1
A bouncy ball is dropped such that the height of its first bounce is 4.5 feet and each successive bounce is 73% of the previous bounce's height. What would be the height of the 10th bounce of the ball? Round to the nearest tenth (if necessary).
The height of the 10th bounce of the ball will be 0.6 feet.
What is geometric sequence?A geometric sequence is a sequence in which each term is found by multiplying the preceding term by the same value.
What is the formula for finding the nth term of geometric sequence?The nth term of the geometric sequence is given by
\(\sf T_n=ar^{n-1}\)
Where,
\(\sf T_n\) is the nth term.r is the common ratioa is the first termAccording to the given question.
During the first bounce, height of the ball from the ground, a = 4.5 feet
And, the each successive bounce is 73% of the previous bounce's height.
So,
During the second bounce, the height of ball from the ground
\(\sf = 73\% \ of \ 10\)
\(=\dfrac{73}{100}(10)\)
\(\sf = 0.73 \times 10\)
\(\sf = 7.3 \ feet\)
During the third bounce, the height of ball from the ground
\(\sf = 73\% \ of \ 7.3\)
\(=\dfrac{73}{100}(7.3)\)
\(\sf = 5.33 \ feet\)
Like this we will obtain a geometric sequence 7.3, 5.33, 3.11, 2.23,...
And the common ratio of the geometric sequence is 0.73
Therefore,
The sixth term of the geometric sequence is given by
\(\sf T_{10}=10(0.73)^{10-1\)
\(\sf T_{10}=10(0.73)^{9\)
\(\sf T_{10}=10(0.059)\)
\(\sf T_{10}=0.59\thickapprox0.6 \ feet\)
Hence, the height of the 10th bounce of the ball will be 0.6 feet.
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Solve forx.
(6+x)m=y
Answer:
x=y/m-6
Step-by-step explanation:
2. Rabbit Problem
When rabbits were first brought to Australia last
century, they had no natural enemies so their numbers increased
rapidly. Assume that there were 60,000 rabbits in 1865, and that by
1867 the number had increased to 2,400,000. Assume that the num-
ber of rabbits increased exponentially with the number of years that
elapsed since 1865.
Write the particular equation for this function,
b. How many rabbits would you predict in 1870?
c. According to your model, when was the first pair of rabbits in-
troduced into Australia?
According to the exponential function,
a) The function that models the given situation is f(rabbits) = 65000(√500/13)ˣ
b) The number of rabbits in 1870 is 6.5
c) According to your model, the first pair of rabbits introduced into Australia is 19th century
Here we have given that during the 19th century, here rabbits were brought to Australia.
And here we also know that the rabbits had no natural enemies on that continent, their population increased rapidly.
And we have given that there were 65,000 rabbits in Australia in 1865 and 2,500,000 in 1867.
Then according to the exponential function that could be used to model the rabbit population y in Australia in terms of x, the number of years since 1865 is to be determined.
Then the exponential function can be written as,
=> f(rabbits) = 65000(√500/13)ˣ
When we plot these on the graph then we get the graph like the following.
Through the graph we have identified that the value of rabbits in 1870 is 6.5
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Pls Help, I will give 5 star and thanks, Plus Brain to correct answer, Plus extra points if correct!!
The table shows the relationship between the participants walking and running for the week's cross-country practices.
Walk (laps) 3 B 15
Run (laps) 5 10 D
Total (laps) A C 40
At this rate, how many laps will the participants walk if the total distance is 32 miles? How many miles will they run?
They will walk 7 laps and run 17 laps for a total of 32 miles.
They will walk 12 laps and run 20 laps for a total of 32 miles.
They will walk 14 laps and run 18 laps for a total of 32 miles.
They will walk 10 laps and run 22 laps for a total of 32 miles.
Using proportional relationships, we can say that They will walk 12 laps and run 20 laps for a total of 32 miles.
What is the direct proportional relationship?In a direct proportional relationship, the output variable is found by the multiplication of the input variable and the constant of proportionality k, as follows:
y = kx.
Given that we know this, they walk 3/8 of the 8 miles that make up the complete distance. Run 5/8 of the route.
The following are the proportional relationships for the distances:
Walked = 3/8 x Total Distance.Ran = 5/8 x Total Distance.For a total distance of 32 miles, the distances walked and run are given:
Walked: 3/8 x 32 = 3 x 4 = 12 miles = 12 laps.Ran: 5/8 x 32 = 5 x 4 = 20 miles = 20 laps.therefore, They will walk 12 laps and run 20 laps for a total of 32 miles as per the proportional relation.
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a soccer team has 20 players on its roster. in how many ways can 11 players be chosen to form a starting lineup (ignoring the positions played)?
The ways to select the players from the total is 167960
How to determine the ways of selection?From the question, we have
Total number of players, n = 20
Numbers to selection, r = 11 players
The number of ways of selection could be drawn is calculated using the following combination formula
Total = ⁿCᵣ
Where
n = 20 and r = 11
Substitute the known values in the above equation
Total = ²⁰C₁₁
Apply the combination formula
ⁿCᵣ = n!/(n - r)!r!
So, we have
Total = 20!/(11! * 9!)
Evaluate
Total = 167960
Hence, the number of ways is 167960
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suppose u is a uniform(0, 1) random variable. consider f-1(u), where f-1(.) is the inverse of the cdf of the random variable x. so, f-1(u) is a transformation of u. assume f-1(.) is strictly increasing. what is the distribution of f-1(u)?
The distribution of the given function is a uniform distribution.
A strictly increasing function is the one which increases continuously in a given interval. If f-1(u) is a strictly increasing function of u, then the distribution of f-1(u) is the same as that of u. This is because a strictly increasing function preserves the rank ordering of its input, so if u-1 and u-2 are two random variables with a uniform distribution on the interval (0,1), then the rank order of f-1(u-1) and f-1(u-2) will be the same as the rank order of u-1 and u-2. Since the uniform distribution is defined by the rank order of its values, this means that the distribution of f-1(u) is also uniform on the interval (0,1).
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7
Which of the following representions are functions?
2
I. {(0,9), (3, 12), (-5, 10), (5, 10)}
II. y = x2 + 10
Х
10
-1
10
8
-2
III.
y
5
8
-5
-9
-4
O Tonly
+
O II only
o I and II only
O I, II, and III
Answer:
1,11,111 I don't know how I know it I just know it
Choose the that seems to be congruent to the given one.
ABD=
AFC
AEC
DFA
Triangle AFC is the triangle that appears to be consistent with triangle AFD.
Shapes that are identical to one another are said to be congruent. Both the matching sides and the corresponding angles match. There is an obtuse angle, or angle AFD, same like in the give triangle AFD.
Therefore, the opposite triangle must have an obtuse angle in order to be a congruent triangle. Only triangle AFC, out of the three that are given, has an acute angle. Additionally, they both support the same side, increasing the likelihood of congruence. There is no obtuse angle in the triangles BFC and DFE.
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Evaluate 3x + 1 when x = 2.
A. 5
B. 6
C. 7
Answer:
The correct answer:
C. 7
3(2) + 1 = 6 + 1 = 7
Step-by-step explanation:
So the question is 3x+1. We are given the information that x=2. Therefor we would plug in 2 to where x is. 3(2)+1. Now we would multiply first for 6+1. Add to get 7. 7 would be our answer giving us C.
I will give 30 points if u help now
Answer:
3. x=16
4. x=51
Step-by-step explanation:
3. 3x-8=x+24
2x=32
x=16
4. 2/3(x+27)= 180-(3x-25)
2/3x+18=180-3x+25
11/3x=187
11x=561
x=51
Step-by-step explanation:
Excercise 3:
By Alternate Exterior angles,
(x + 24)° = (3x - 8)°.
=> 2x = 32, x = 16.
Excercise 4:
By C-angles,
2/3 * (x + 27)° + (3x - 25)° = 180°.
=> 2x/3 + 18 + 3x - 25 = 180
=> 11x/3 = 187
=> x = 187 * (3/11) = 51.
Sophia is going to eat a round lollipop that has a diameter of 12 centimeters. What is the lollipop's radius?
Answer:
The radius is 6.
Step-by-step explanation:
If you have a diameter, you simply divide it by 2. so 12/2 is 6. Hope it helps :)
Menaha traveled 86km 520m by train and 11km 480m by car What ditance did he travel in all?
In total, Menaha traveled 97km 1000m (97.1km).
What is distance?Distance is a numerical measurement of how far apart two objects, points, or places are in space. Distance can be measured in linear units such as meters, kilometers, feet, miles, etc. It can also be measured in angular units such as degrees or radians.
Distance can also refer to the space between two points in time, such as the time between two events. Distance can be used to measure physical distance, time, or even emotional distance.
To calculate this, the two distances must be added together.
The train distance is =86km 520m (86.52km)
and the car distance is =11km 480m (11.48km).
When added together, =86km 520m+11km 480m = 97.52km.
However, since the distances are measured in km and m,
it is necessary to convert the measurements into a single unit of measurement.
To do this, the measurements must be converted into metres.
The train distance is 86,520 metres
And the car distance is 11,480 metres.
When added together,
the total distance is 97,000 metres (97km).
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The difference of the same side interior angles of two parrelels lines is 50 degrees find all angles
Answer:
Angle 1 = 115 degrees
Angle 2 = 65 degrees
Step-by-step explanation:
Angle 1: Same-side interior angle of Line 1
Angle 2: Same-side interior angle of Line 2
We know that the difference between the angles is 50 degrees. Since the angles are supplementary, we can write the equation:
Angle 1 + Angle 2 = 180
Now, we need to express the difference between the angles in terms of Angle 1 or Angle 2. We can choose either angle, so let's express it in terms of Angle 1:
Angle 1 - Angle 2 = 50
We can rewrite this equation as:
Angle 1 = 50 + Angle 2
Now substitute this expression for Angle 1 into the first equation:
(50 + Angle 2) + Angle 2 = 180
Combine like terms:
2Angle 2 + 50 = 180
Subtract 50 from both sides:
2Angle 2 = 130
Divide by 2:
Angle 2 = 65
Now substitute this value back into the equation for Angle 1:
Angle 1 = 50 + Angle 2
Angle 1 = 50 + 65
Angle 1 = 115
Therefore, the angles are as follows:
Angle 1 = 115 degrees
Angle 2 = 65 degrees
Let A and B be nxn matrices. Show that if AB is invertible, then B is invertible. (Note that IMT stands for Invertible Matrix Theorem.) a. Let W be the inverse of AB. Then WAB=B. Therefore we can write B as the product of two invertible matrices Wand AB, and this makes B invertible. The product of two invertible matrices is invertible by Theorem 6 in Section 2.2. b. Since AB is invertible, then (AB)T is invertible by the IMT. Therefore the matrix Bis invertible by part (1) of the IMT. c. Since AB is invertible, this means that A= B-1 and B = A-1 by the IMT. Therefore B is invertible. d. Let W be the inverse of AB. Then WAB=I and (WA)B=l. Therefore, the matrix Bis invertible by part (j) of the IMT by letting C=WA.
Let W be the inverse of AB. Then WAB = I and (WA)B = l. Therefore, matrix B is invertible by part (j) of the IMT by letting C = WA.
We have A and B are two n × n matrices and AB is invertible. We have to prove that B is invertible by showing a valid reason given by one of the four options:
Option (a) False:
The first option is not valid proof. since W is the inverse of A B would imply WAB = I, as multiplying a matrix by its inverse will produce the identity matrix of the corresponding order. Here stated that WAB = B, which is invalid.
Option (b) False:
It is true that AB invertible implies \($(A B)^{\top}$\) is invertible but this does not imply B is invertible (not a valid statement).
Option (c) False:
A B is invertible does not mean \($A=B^{-1}$\). Since \($A=B^{-1}$\) implies AB = I, but AB need not be only the identity matrix. So these statements are invalid.
Option (d) True:
W being inverse of AB, this gives WAB = I
(WA) B = I since matrix multiplication is associative.
WA is the inverse of B, as multiplying WA by B produces the identity matrix I. Hence, this is valid proof to show that B is invertible.
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please help, and i will mark you BRAINLIEST
Twenty less than the product of 6 and a number *
A. 20 - 6n
B. 6/n - 20
C. 6n - 20
D. 20 - 6/n
Answer:
It will option C this is correct answer 6n-20
Answer:
c
Step-by-step explanation:
Tommy and his friend went to go buy pie at Delicious Orchards. After paying seven dollars for the pie, Tommy
has ninety-five dollars left, his friend has forty dollars. How much money did Tommy have before buying the
ple.
Answer:
$102
Step-by-step explanation:
if Tommy spent 7 dollars on pie, that means he had more money than that amount before.
So before he spent 7 dollars, he had those 7 dollars.
Add 7 with 95
95 + 7 = 102
Aaron bought 8 red flags for the parade. Large flags cost $20 each. Medium flags cost $12 each. Aaron spent $112 in all. How many large flags (L) and how many medium flags (M) did he buy?
Answer:
Step-by-step explanation:
Price assuming he bought all large flags: \(20*8=160\)
Amount of money more: \(160-112=48\)
Difference of price in both flags: \(20-12=8\)
Medium Flags: \(48\div8=6\)
Large Flags: \(8-6=2\)
----------------------------------
The reason why this works, is because the amount of money more comes from the difference between both flags.
There are 30 giraffe and 6 penguin at the zoo. Which tatement correctly compare the two quantitie?
To compare the two quantities, divide the number of giraffes by the number of penguins There are 5 times as many giraffes as penguins at the zoo.
To compare the two quantities, you need to divide the number of giraffes by the number of penguins.
30 giraffes / 6 penguins = 5
This means that there are 5 times as many giraffes as penguins at the zoo.
There are 5 times as many giraffes as penguins at the zoo. To compare the two quantities, divide the number of giraffes by the number of penguins (30/6 = 5). This means that there are 5 times more giraffes than penguins at the zoo.
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