Radio sources are harder to find due to the effectively collect and focus the long-wavelength radio waves to achieve better resolution and sensitivity.
Compared to optical telescopes, radio telescopes are built large primarily because radio waves have very long wavelengths. Due to their long wavelengths, radio waves require larger telescopes to effectively collect and focus the incoming signals. This is necessary to achieve a sufficient level of resolution and sensitivity to detect and study radio sources, which can sometimes be harder to find than optical sources.
The size of a radio telescope is not mainly because they're less expensive to make than optical telescopes. While it is true that radio telescopes do not require the same level of precision and material quality as optical telescopes, building a large radio telescope can still be quite expensive.
Atmospheric turbulence is more of a problem for optical telescopes, as it can distort the incoming light and reduce the clarity of the observed image.
However, radio telescopes are less affected by atmospheric turbulence because radio waves can generally pass through the atmosphere with less distortion.
Lastly, while radio waves can be absorbed by certain parts of the atmosphere, especially at higher frequencies, this is not the primary reason for building larger radio telescopes.
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A source produces 20 crests and 20 troughs in 4 seconds. The second crest is 3 cm away from the first crest.Calculate :
i. Wavelength [ Ans : 3 × \( {10}^{ - 2} \) m ]
ii. Frequency [ Ans : 5 Hz ]
iii. Wave speed [ Ans : 1.5 × \( {10}^{ - 1} \tt{ {ms}^{ - 1}} \) ]
Show your workings !
*Irrelevant / Random answers will be reported!
Answer:
Solution given:
No of waves[N] =20crests & 20 troughs
=20waves
Time[T]=4seconds
distance[d]=3cm=0.03m
Now
Wave length=3cm=3 × \( {10}^{ - 2}m \)
Frequency=\( \frac{No of waves}{time}\)
=\( \frac{20}{4} \)=5Hertz
and
Wave speed:wave length×frequency=3 × \( {10}^{ - 2}m \)×5=1.5 × \( {10}^{ - 1} \tt{ {ms}^{ - 1}} \).
Drag each label to the correct location on the table. Sort the sentences based on whether they describe radio waves, visible light waves, or both. They have colors. They can travel in a vacuum. They have energy. They’re used to learn about dust and gas clouds. They’re used to find the temperature of stars. They’re invisible.
Based on the given sentences, let's sort them into the correct categories: radio waves, visible light waves, or both.
Radio waves:
- They're used to learn about dust and gas clouds.
Visible light waves:
- They have colors.
- They're used to find the temperature of stars.
Both radio waves and visible light waves:
- They can travel in a vacuum.
- They have energy.
- They're invisible.
Sorted table:
| Radio Waves | Visible Light Waves | Both |
|----------------------|----------------------|----------------------|
| They're used to learn about dust and gas clouds. | They have colors. | They can travel in a vacuum. |
| - | They're used to find the temperature of stars. | They have energy. |
| - | - | They're invisible. |
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a uniform e-field of magnitude e and directed horizontally fills a region of space. points a through e are all inside the uniform field and form a rectangle with purely horizontal length d and purely vertical height h. point c is in the center of this rectangle. a line from a to c makes an angle of θ with the direction of the e-field. only. Particle 2 is moved by an external force (call it "us") from D to C so that it both starts at rest and ends at rest.
Which of the following statements about particles 1 and 2 are TRUE? You may select more than one.
a. The net work done on particle 1 by the field is zero.
b. The Coulomb force exerted on both particles by the source of the E-field increases as they move fro start to finish.
c. Particle 1 loses electrical potential energy from start to finish. The electrical potential energy of particle 2 does not change from start to finish.
d. The net work done on particle 2 by the field and by us is zero.
e. Both particles lose electrical potential energy from start to finish.
f. The E-field at point A when particle 1 is at point A has less magnitude than the E-field at point C when particle 2 is at point C.
g. Both particles are at rest when they reach points A and C respectively.
h. Both particles move through the same potential difference from start to finish.
i. The Coulomb force exerted on particle 2 by the source of the E-field is larger in magnitude that the Coulomb force exerted on particle 1 by the source of the E-field.
The correct answers are a, d, f, g, and h. The net work done on particle 1 by the field is zero because the electric field is uniform, so the electric force acting on particle 1 is constant.
What is Coulomb force?Coulomb force is an electrostatic force of attraction or repulsion between two particles that have an electric charge. It is proportional to the product of the charges and inversely proportional to the square of the distance between them.
The Coulomb force exerted on both particles by the source of the E-field increases as they move from start to finish, but the electrical potential energy of particle 2 does not change from start to finish. The E-field at point A when particle 1 is at point A has less magnitude than the E-field at point C when particle 2 is at point C because the magnitude of the electric field decreases with distance from the source. Both particles are at rest when they reach points A and C respectively, and both particles move through the same potential difference from start to finish. Lastly, the Coulomb force exerted on particle 2 by the source of the E-field is larger in magnitude than the Coulomb force exerted on particle 1 by the source of the E-field since particle 2 is closer to the source of the electric field.
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De acuerdo al calendario ecológico 2020, escriba cuanto CO2 produce el Ecuador y en un resumen máximo de 7 líneas, determine porque son importante los humedales en la biodiversidad.
Answer:
43,919.66 Kilotones de Co2 en 2016.
Explicación:
Ecuador produce 43,919.66 Kilotones de Co2 en 2016. Las tierras húmedas son muy importantes para la biodiversidad porque proporcionan hábitat a millones de animales. Alrededor del 35 por ciento de todas las especies amenazadas y en peligro vive en estas tierras húmedas. Estas tierras húmedas son altamente productivas y tienen la capacidad de mejorar la calidad del agua, prevenir la degradación del suelo y proporcionar alimentos a los animales que viven en estas tierras húmedas.
What is the weight of a 200 kg mass?
Answer:
W 1920 N
Explanation:
200kg at a location where g=9.6m/s^2
1. A visitor to the observation deck of a skyscraper manages to drop a penny over the edge. As the penny falls faster, the force due to air resistance increases. How does this affect the acceleration of the penny?
The acceleration remains zero.
The acceleration remains constant and not zero.
The acceleration increases.
The acceleration decreases.
2. A plane flies along a straight line path after taking off, and it ends up 90.0 km farther east and 200.0 km farther north, relative to where it started. In what direction did it fly on the straight line path?
66° north of east
27° north of east
45° north of east
24° north of east
Please explain your answer :)
Answer:
Its either 24 or 27 I'm confident its 24 my explanation is that from estimate it's near the 20s
An object is placed on a surface. A student tries to apply various combinations of forces on the object. Which pair of forces will not move the object?
Answer:
See Explanation
Explanation:
The question is incomplete, as there are no diagrams or options to provide more information to the question.
The general explanation is as follows:
For the object not to move
(1): The forces acting on the object must opposite each other. i.e. if force A acts at the right (or positive direction), force B will act at the left (or negative direction).
(2) The two forces must be equal.
So, for instance:
If the pair of forces are 5N and 5N in opposite directions, the object wil not move.
However, if one of the forces is greater, the object will move towards the direction of the greater force.
Prove that acceleration=v/time
Answer:
Explanation:
Main Answer:
The equation acceleration = v/time can be proven using the fundamental definitions of acceleration, velocity, and time. Acceleration is defined as the rate of change of velocity, and velocity is the rate of change of displacement with respect to time. Let's consider an object moving with an initial velocity v0 and final velocity v in a time interval t.
Explanation:
The change in velocity, Δv, can be calculated as the final velocity minus the initial velocity, Δv = v - v0. Similarly, the change in time, Δt, is the final time minus the initial time, Δt = t - t0.
By substituting these values into the equation for acceleration, we have:
acceleration = Δv/Δt
Now, substituting Δv = v - v0 and Δt = t - t0, we get:
acceleration = (v - v0)/(t - t0)
Since v0 and t0 represent the initial velocity and time, respectively, we can rewrite the equation as:
acceleration = (v - v0)/t
By rearranging the equation, we find:
acceleration = v/t
Thus, we have proved that acceleration is equal to v/time.
Internal Link:
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if a piece of jewelry were electroplated with gold for 25 seconds at 1.5 a, how many grams of gold would be plated? (note: 1 a
The mass of gold plated can then be calculated using the molar mass of gold and the charge passed through the solution is 0.005 g.
What is molar mass?Molar mass is the mass of one mole of a substance. It is measured in grams per mole (g/mol) and is equal to the molecular weight of the substance. The molecular weight is the sum of the atomic weights of all the atoms in the molecule. Molar mass can be used to calculate the number of moles in a given mass of a substance. It is also used in stoichiometry calculations to determine the amounts of reactants and products in a chemical reaction.
The charge passed through the solution in this case can be calculated using the current and the time:
Charge = Current x Time = 1.5A x 25s = 37.5 C
The mass of gold plated can then be calculated using the molar mass of gold and the charge passed through the solution:
Mass of gold plated = Charge x Molar mass of gold / (6.241 x 10¹⁸ e-) = 37.5 C x 196.967 g/mol / (6.241 x 10¹⁸e-) = 0.005 g.
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How can you use a screen to
determine whether an image is real or virtual?
This problem explores what happens to the resting steady state of a membrane, after the ion pumps are suddenly turned off, say by addition of a neurotoxin. Namely, sodium ions are far from equilibrium in the resting state. The concentration of sodium inside the cell is 12mM, while outside the cell it is 145mM; the membrane voltage is Vmem = -90 mV. This means that when pumps are turned off, sodium will rush into the cell
Using Ohm's law, find the current per unit area carried by sodium ions just after the pumps have been shut off (5 points). For the conductance of sodium channels per unit area, take the measured value of 0.13Ω-1 m-2. Reexpress your answer as current per unit length along a giant axon, assuming a diameter of 1 mm.
The current per unit length along the giant axon, assuming a diameter of 1 mm, is approximately -9.18 x \(10^{(-15)\) A/m.
To find the current per unit area carried by sodium ions just after the pumps have been shut off, we can use Ohm's law, which states that current (I) is equal to the conductance (g) multiplied by the voltage (V). In this case, the conductance is the conductance of sodium channels per unit area, given as 0.13 Ω\(^{(-1)} m^{(-2)\). The voltage is the membrane voltage, given as -90 mV.
Given:
Conductance per unit area (g) = 0.13 Ω^\(^{(-1)}m^{(-2)\)
Membrane voltage (V) = -90 mV
Axon diameter = 1 mm = 0.001 m
1. Calculate the current per unit area (I):
I = g * V
I = (0.13 Ω\(^{(-1)} m^{(-2)\) * (-90 mV)
I = -0.0117 A/m²
2. Calculate the cross-sectional area of the axon (A):
A = π * (\(radius)^2\)
radius = 0.001 m / 2 = 0.0005 m
A = π *\((0.0005 m)^2\)
A ≈ 7.85398 x \(10^{(-7)\) m²
3. Calculate the current per unit length along the axon (I'):
I' = I * A
I' = (-0.0117 A/m²) * (7.85398 x \(10^{(-7)\) m²)
I' ≈ -9.18 x\(10^{(-15)\) A/m
Therefore, the current per unit length along the giant axon, after the pumps have been shut off, is approximately -9.18 x \(10^{(-15)\)A/m.
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Francium-233 has a half-life of 22 minutes.A Geigor counter gives a reading of 58 counts per minute (cpm) from a sample of francium-233.What will the reading be 22 minutes later?You can ignore background radiation
Answer:
The reading of the Geiger counter, 22 minutes later = 29 counts per minute (cpm)
Explanation:
Half life is defined as the time taken for the amount ( or activity) of a substance to reduce to half its original value.
As stated in the question, the half life of Francium-233 is 22 minutes, \(t_{1/2} = 22 minutes\). This means that it takes 22 minutes for the activity of Francium-233 to reduce to half of its original value.
The original activity of Francium-233 = 58 counts per minute (cpm)
By the end of 22 minutes, the activity measured by the counter would have halved.
Activity of Francium-233 after 22 minutes = 58/2
Activity of Francium-233 after 22 minutes = 29 counts per minute (cpm)
A wire of resistance R is cut into ten equal parts which are then connected in parallel. The equivalent resistance of the combination is
Answer:
The equivalent resistance of the combination is R/100
Explanation:
Parallel Connection of Resistances
If resistances R1, R2, R3,...., Rn are connected in parallel, the equivalent resistance is calculated as follows:
\(\displaystyle \frac{1}{R_e}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+...+\frac{1}{R_n}\)
The electric resistance of a wire is directly proportional to its length. If a wire of resistance R is cut into 10 equal parts, then each part has a resistance of R/10.
It's known the 10 parts or resistance R/10 were connected in parallel, thus the electric resistance is:
\(\displaystyle \frac{1}{R_e}=\frac{1}{R/10}+\frac{1}{R/10}+\frac{1}{R/10}+...+\frac{1}{R/10}\)
Note the sum consists of 10 equal terms. Operating on each term:
\(\displaystyle \frac{1}{R_e}=\frac{10}{R}+\frac{10}{R}+\frac{10}{R}+...+\frac{10}{R}\)
The sum of 10 identical fractions yields 10 times each fraction:
\(\displaystyle \frac{1}{R_e}=10\frac{10}{R}=\frac{100}{R}\)
Solving for Re needs to take the reciprocal of both sides of the equation:
\(R_e=R/100\)
The equivalent resistance of the combination is R/100
An object is 10 m above Earth’s surface, and has a potential energy of 490 joules. What is the object’s mass?
Explanation:
Taking g=10m/s²
P.E= mgh
490J= m×10×10.
490J=100m
m. = 490J/100
m. =4.9kg
PLEASE ANSWER
Krishne wants to measure the mass and volume of a key. Which tools should she use?
A. a balance and a beaker of water
B. a balance and a meter stick
C. a beaker of water and a ruler
D. a ruler and a meter stick
Answer:
A balance and a beaker of water!
Explanation:
Krishne wants to measure the mass and volume of a key. The tools that are to be used are – a balance and a beaker of water.
Mass will be represent with the amount of matter that is in an object. This will be measured in terms of kilogram. The mass can easily be measured with balance.
Volume is the quantity of matter that is in the object. This is measured in terms of cubic meter. If you drop the key in a beaker of water, the water inside the beaker will increase and this increases the volume of water that will be equal to volume of key.
If I do 100 Joules of work to lift my backpack, then half of everything falls out so that I can lift it using half the force, how much work will I do to lift it the same distance?
50J work will do to lift it the same distance
How much energy is wasted during a fall?
When an object is falling freely, its velocity rises because of the acceleration caused by gravity. In the instance of a body that is falling freely, the kinetic energy thus rises while the potential energy falls as the height of the object decreases.
When an object is descending at its terminal velocity, the force of gravity and air resistance are equal, and the object no longer accelerates. The amount of labor done is equal to the sum of the object's displacement and the gravitational force. The modification of the object's potential energy brought on by gravity can also be used to calculate it.
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a metal cube of density 2700 kg/m³ has an edge length of 10cm. what is the mass of the metal?
Answer:
The mass of the metal is 2.7 Kg.
Explanation:
As we know the mass of an object is:
m = ρ * v .........(i)
where ρ is the density of the metal cube, &
v is the volume of the cube
Now as per the question:
Density of metal cube, ρ = 2700 kg/m³
Edge Length, l = 10 cm
∵ 1 m = 100 cm
∴ edge length, l = 0.1 m
∴ Volume, v = (l)³ = (0.1)³ = 0.001 m³
Now putting all the values in equation (i), we get
m = 2700 * 0.001 kg
m = 2.7 kg
∴ A metal cube of density 2700 kg/m³ and edge length 10 cm has a mass of 2.7 kg.
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The hyper-loop is a proposed concept that involves a train traveling at 360 meters per second. How long does it take to travel one mile?
Answer:
t = 4.47 seconds
Explanation:
Given that,
Speed of a train, v = 360 m/s
We need to find the time taken by the train to cover 1 mile. For this first we must know 1 mile equal to how many meters.
1 mile = 1609.34 m
Let t is time.
Speed = distance/time
\(t=\dfrac{d}{v}\\\\t=\dfrac{1609.34\ m}{360\ m/s}\\\\t=4.47\ s\)
So, it will take 4.47 seconds to travel one mile.
magnetic moment is scaler or vector??
A standing wave is observed to have the following characteristics: 3rd harmonic, f=42hz, wavelength=1.33m. calculate the following: frequency of the 9th harmonic, wavelength of the 7th harmonic, harmonic # if f=210hz, and speed of wave
The frequency of the fundamental is not provided, so we cannot calculate the harmonic number.
What is the formula to calculate the frequency of a harmonic?The 3rd harmonic has a frequency of 42 Hz, which means that each complete cycle of the wave occurs 3 times per second. To find the frequency of the 9th harmonic, we multiply the frequency of the 3rd harmonic by 9, resulting in 378 Hz.
The wavelength of the 3rd harmonic can be determined by dividing the speed of the wave by the frequency. Since the speed is not given, we cannot calculate the wavelength of the 7th harmonic.
To find the harmonic number if the frequency is 210 Hz, we divide the given frequency by the frequency of the fundamental (1st harmonic). However, the frequency of the fundamental is not provided, so we cannot calculate the harmonic number.
The speed of the wave cannot be determined with the given information, as it depends on the medium through which the wave is propagating.
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An electrical motor is used to raise an object. The object transfers 150J of useful energy when the motor is supplied with 250J of electrical energy.
A) what is total energy supplied to the motor?
B)what is the useful energy transfer?
C) what is the efficiency?
Answer:
A) 250 J
B) 150 J
C) The efficiency = 0.6 and the percentage efficiency = 60%
Explanation:
The question relates to definition of terms in energy transfer and the calculation of efficiency
The parameters of the given are;
The energy the object transfers = 150 J
The amount of electrical energy supplied to the motor = 250 J
Therefore, we have;
A) The total energy supplied to the motor = The amount of electrical energy supplied to the motor = 250 J
B) The useful energy transferred = The energy used to do work = 150 J
C) The efficiency = (Useful energy transferred (out))/(Total energy supplied (in)
\(The \ efficiency = \dfrac{Useful \ energy \ transferred \ (out)}{Total \ energy supplied \ (in)} = \dfrac{150 \, J}{250 \, J} = 0.6\)
The percentage efficiency is given as follows;
\(The \ percentage \ efficiency = \dfrac{Useful \ energy \ transferred \ (out)}{Total \ energy supplied \ (in)} \times 100\)
\(\therefore The \ percentage \ efficiency = \dfrac{150 \, J}{250 \, J} \times 100 = 0.6 \times 100 = 60\%\)
Answer:
A) 250 J
B) 150 J
C) efficiency = 0.6, percentage efficiency = 60%
Explanation:
The sum of two component vectors is referred to as the
vector.
Addition
Quantitative
Subtraction
Resultant
What is the space between to items
Answer:
A Gap is the space between
Answer: distance, a gap
Explanation:
If the voltage of a circuit is 6V, and the power is 4W, what is its resistance?
Answer:
9 ohms
Explanation:
P = V²/R
R = v²/p = 6²/4 = 36/4 = 9 ohms.
The resistance is 9 Ohm.
To find the resistance, we need to know about the power in term of resistance and voltage.
What is the value of power in terms of resistance and voltage?We know that power=work/timeElectrostatics work is given as voltage ×charge. So, power=(Voltage×charge)/timeAgain, charge/time is given as current. So, power = Voltage×currentFrom Ohm's law, we know that current=voltage/resistance. So, power= voltage ²/resistance. What is the resistance, if power is 4W and voltage is 6V?Resistance in term of power and voltage is given as Resistance= voltage ²/powerSo, resistance=6²/4=36/4= 9 OhmThus, we can conclude that the resistance is 9 Ohm.
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A computer’s hard drive spins at 7200 RPM. What is the angular velocity in rad/s? What is the
velocity in m/s of the hard drive at a radius of 0. 0889 m?
The angular velocity in rad/s is 753.9 rad/s.
The velocity in m/s of the hard drive at a radius of 0.0889 m is 67.02 m/s.
How to calculate the angular velocity?In Mathematics and Physics, the angular velocity of a physical object can be calculated by using this formula:
ω = θ/t
Where:
ω is the angular velocity.θ is the angle.t is the time.In order to convert the unit revolutions per minute (RPM) to radians per seconds (rad/s), we would multiply the value by 2π and then divide by 60 as follows;
Angular velocity in rad/s = 7200 × 2π/60
Angular velocity in rad/s = 753.9 rad/s.
At a radius of 0.0889 meters, the velocity of the hard drive in m/s can be calculated as follows;
Velocity = radius × angular velocity
Velocity = 0.0889 × 753.9
Velocity = 67.02 m/s.
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a student is sitting on the right side of a school bus when it makes a right turn. we know that the force of gravity acts downwards and a normal force from the seat acts upwards. if the student stays in place when the bus turns, we also know that there must be a. no other force on the student. b. a force parallel to the seat directed forward on the student. c. a force parallel to the seat directed to the left on the student. d. a force parallel to the seat directed to the right on the student. e. a force parallel to the seat in a direction between forward and left on the student.
When a student is sitting on the right side of a school bus when it makes a right turn, a force parallel to the seat directed to the left on the student. The correct option is c.
There are four fundamental forces: the strong force, the weak force, the electromagnetic force, and the gravitational force. The strong force and the weak force operate only on subatomic particles, whereas the electromagnetic force and the gravitational force act on macroscopic (i.e., everyday) objects.
A force is any interaction that alters or maintains the motion of an object. It's a vector quantity because it has both a magnitude and a direction. The SI unit for force is newtons (N). The forces acting on a student sitting on the right side of a school bus when it makes a right turn are: a force of gravity that acts downwards, a normal force that acts upwards due to the seat, a force parallel to the seat directed to the left on the student if the student stays in place when the bus turns.
So, the correct option is C) a force parallel to the seat directed to the left on the student.
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How do you identify accelerated idioventricular rhythm?
While the rate is lower than 60 bpm, idioventricular rhythm is extremely comparable to ventricular tachycardia. Accelerated idioventricular rhythm is characterised by a rate of 50 to 100 bpm.
Regular rhythm, three or more ventricular complexes with QRS complex > 120 milliseconds, ventricular rate between 50 and 110 beats per minute, and sporadic fusion or capture beats are all electrocardiogram features of AIVR. A heart rhythm known as an idioventricular rhythm has a pace of less than 50 beats per minute (bpm), no P waves, and a broadening of the QRS complex. Accelerated idioventricular rhythm is used to describe heart rates between 50 and 110 bpm, while ventricular tachycardia is used to describe rates beyond 120 bpm. For this reason, an idioventricular rhythm is commonly called a "slow ventricular tachycardia".
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You start walking from a point on a circular field of radius 0.5 km and 1 hour later
you are at the same point. What is your average speed for the whole journey?
Answer:
1). average velocity= displacement/time
= here displacement is zero
= 0/1
= 0 m/s
2). average speed= total distance/time
=2πr/1
=(2×22/7×5/10)/1
22/7
3.14 km/h
hope it helps you
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Explanation:
Answer:
\(\sf \fbox{speed = 3.14 kmph}\)
Explanation:
Given:
Radius of circular field (r) = 0.5 Km
Time taken to complete one round of field (t)= 1 hour
To find:
Average speed for the whole journey=?
Solution:
To find the average speed we will have to find the actual distance covered in given time, & the actual distance covered would be equal to the
\( \sf \: perimeter \: of \: circular \: field = 2 \pi r \\ \sf 2 \pi r = 2 \times 3.14 \times 0.5 = 3.14 \: km\)
Distance covered in 1 hour is 3.14 km,
\(\small \sf Average \: speed = \frac{Distance}{Time} = \frac{3.14}{1} \\ \small \sf \fbox{speed = 3.14 kmph}\)
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A force of 250N is applied on an object causing it to move for 6m at uniform velocity of 32m/s. Determine the (I) work done (ii)power developed
The power developed is 8000 W.
Given data:
Force = 250 N
Distance traveled = 6 m
Velocity = 32 m/s
Let's find out the work done on the object by the applied force.
Work done is given by the product of force and distance covered:
W = F × s
W = 250 × 6 = 1500 J
Thus, the work done on the object by the applied force is 1500 J.
Next, let's determine the power developed.
Power is defined as the rate at which work is done, i.e.,
P = W / t
where P is power, W is work done, and t is time taken to do that work.
We know that velocity = distance / time. Rearranging the above expression, we get:
t = d / v
Substituting the given values, we get:
t = 6 / 32
P = W / t
Substituting the calculated value of W and t, we get:
P = 1500 / (6 / 32)
P = 8000 W
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Which refers to the rate of change in velocity? speed acceleration direction magnitude I need this answer i cant figure it out!!
Answer: Acceleration
Explanation: In this case its most likely acceleration as it has the definition of quick change in velocity. Therefore, the answer is acceleration.
Acceleration refers to the rate of the change in the velocity , therefore the correct answer is option B .
What is acceleration ?The rate of change of the velocity with respect to time is known as the acceleration of the object. Generally, the unit of acceleration is considered as meter/seconds².
As given in the problem statement we have to find out which terminology from the given list of options refers to the rate of change in velocity .
Speed refers to the rate of the change in the distance, while magnitude refers to the numerical quantity of any measured quantity .
The acceleration of any material = rate of the change of the velocity of the material
Thus , Acceleration refers to the rate of the change in the velocity, therefore the correct answer is option B.
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