Compare the wavelength of an electron traveling at a speed of 1.0* 10^7m/s with that for a ball of mass 0.10kg traveling at 35m/s

In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.

To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.

Given:

Resistance of the coil, R1 = 4 ohm

Resistance of the other resistor, R2 = 8 ohm

Current passing through the 8-ohm resistor, I = 2A

First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.

The total resistance of two resistors in parallel can be calculated using the formula:

1/Rp = 1/R1 + 1/R2

Substituting the given values, we have:

1/Rp = 1/4 + 1/8

1/Rp = 2/8 + 1/8

1/Rp = 3/8

Rp = 8/3 ohm

Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).

R_total = R_internal + Rp

R_total = 0.5 + 8/3

R_total = 1.833 ohm

Now, we can find the emf of the cell using Ohm's Law:

emf = I * R_total

emf = 2 * 1.833

emf ≈ 3.667 volts

Therefore, the emf of the cell is approximately 3.667 volts.

However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.

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Explanation:

m = 4kg

u = 20m/s

t = 10s

v = 60m/s

initial momentum = mass × initial velocity

= 4 × 20 = 80kgm/s

Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.

Frequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).

Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.

Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.

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The angle to the horizontal the ball was launched at can be determined using trigonometry. Once you have the initial horizontal and vertical velocities, you can use the tangent function to calculate the launch angle.

Velocity is a physical quantity that describes the rate at which an object changes its position. It is a vector quantity, which means it has both magnitude and direction. The magnitude of velocity is the speed of the object, while its direction is the direction of motion.

Time is a concept that refers to the sequence of events that occur in a continuous progression, from the past, through the present, and into the future. It is a way to measure the duration or the length of events or periods, and it is a fundamental aspect of our experience and understanding of the world.

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The maximum velocity of the collar is 0.335 m/s.

The maximum velocity of a simple harmonic motion occurs when the object is in equilibrium position.

K.E = U

¹/₂mv² = ¹/₂kx²

mv² = kx²

where;

\(v = \sqrt{\frac{kx^2}{m} } \\\\v = \sqrt{\frac{316.36 \times 0.0254^2}{1.81} }\\\\v = 0.335 \ m/s\)

Thus, the maximum velocity of the collar is 0.335 m/s.

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Answer:

Explanation:

Answer:

Explanation:

If we ASSUME that the mop has no acceleration, then the applied force must be acting parallel to the length of the handle.

a) 80.0cos40 = 61.3 N

b) 80.0sin40 =  51.4 N

In terms of the amount of light years energy received, star A should appear 100 times brighter than star B. This is due to the fact that received energy diminishes according to squared distance.

Contact binaries are binary star systems with members whose distance from one another is so great that their outer envelopes actually touch. This structure can actually be rather stable, with typical lifetimes measured in millions or even billions of years, which may surprise you.

When the Earth is at the other end of the star's orbit, six months later, astronomers take another measurement of the star's position. This results in a base line that is equal to the sum of the two angles used to measure the star and the double distance from Earth to the Sun's center (about 300,000,000 km). The distance to a nearby star can be calculated using these three variables in a very straightforward trigonometric manner.

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Answer:

The  value \(y = 0.0349 \ m\)

Explanation:

From the question we are told that

   The  distance of the screen is  \(D = 2.30 \ m\)

   The  width of the slit is  \(d = 0.0368 \ nm = 0.0368 *10^{-3} \ m\)

   The  wavelength is  \(\lambda = 558 \ nm = 558 *10^{-9} \ m\)

The  width of the central diffraction peak is  mathematically represented as

        \(k = 2 * y\)

Where  y is the distance from the center to the high peak which  is mathematically represented as

       \(y = \frac{\lambda * D }{d }\)

substituting values

      \(y = \frac{ 558 *10^{-8} * 2.30 }{0.0368 *10^{-3} }\)

      \(y = 0.0349 \ m\)

Over the time period from t₁ to just before t₃, the two-block-spring system is linear momentum does not change because there are no external forces acting on the system to change its momentum.

Explain why the linear momentum of the two-block–spring system is either constant or not during the time period between t₁ and the time just before t₃?

The linear momentum of the two-block-spring system remains constant from t₁ until just before t₃.

Prior to the collision at time t₂, block A has a momentum to the right that is Pa = ma ×va, whereas block B has a momentum that is Pb = 0 because it is at rest. Because there is no external force acting on the system, its overall momentum is conserved.

All out Ptotal = Dad + Pb = mama × va

Expect there is immaterial erosion between each block and the surface. Take into consideration the spring, block A, and the system for parts (a) to (d).

Following the collision at time t₂, block B experiences a velocity of vb to the right and comes to a stop. Because the collision is elastic, all of the system's kinetic energy is conserved, but momentum is still conserved:

The two-block system is moving to the right at a constant velocity vb from time t₂ to just before time t₃, so the momentum of the system is constant. Ptotal = ma₀ plus mbvb plus mb ×vb

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Answer:

The correct answer is d.

Theories are constructed after there is numerous data collected during the experiment.

Explanation:

hope it helps

Answer:

( About ) 6.8nC

Explanation:

We are given the equation |Q2| = mgd^2 / kQ1. Let us substitute known values into this equation, but first list the given,

Charge Q2 = +45nC = (45 × 10⁻⁹) C

mass of charge Q2 = 4.5 μg, force of gravity = 4.5 μg × 9.8 m/s² = ( 4.41 × 10^-5 ) N,

Distance between charges = 25 cm = 0.25 m,

k = Coulomb's constant = 9 × 10^9

_______________________________________________________

And of course, we have to solve for the magnitude of Q2, represented by the charge magnitude of the charge on Q2 -

(4.41 × 10^-5) = [(9.0 × 10⁹) × (45 × 10⁻⁹) × Q₂] / 0.25²

_______________________________________________________

Solution = ( About ) 6.8nC

Answer:

B

Explanation:

The specific heat of the solid phase is 0.333 joules per gram-degree Celsius.

The specific heat of the liquid phase is 0.593 joules per gram-degree Celsius.

In this case, we need to determine that specific heat for solid and liquid states of matter. By Heat Physics, we understand that specific heat is contained in the slopes of the two sensible phases in the following form:

\(\frac{\Delta T}{\Delta Q} = \frac{1}{m\cdot c}\) (1)

Where:

Solid phase

If we know that \(m = 9.80\,g\), \(T_{1} = 40\,^{\circ}C\), \(T_{2} = 235\,^{\circ}C\), \(Q_{1} = 183\,J\) and \(Q_{2} = 819\,J\), then the specific heat of the solid phase is:

\(c = \frac{\Delta Q}{m\cdot \Delta T}\)

\(c = \frac{819\,J-183\,J}{(9.80\,g)\cdot (235\,^{\circ}C - 40\,^{\circ}C)}\)

\(c = 0.333\,\frac{J}{g\cdot ^{\circ}C}\)

The specific heat of the solid phase is 0.333 joules per gram-degree Celsius.

Liquid phase

If we know that \(m = 9.80\,g\), \(T_{3} = 230\,^{\circ}C\), \(T_{4} = 471\,^{\circ}C\), \(Q_{3} = 1470\,J\) and \(Q_{4} = 2870\,J\), then the specific heat of the liquid phase is:

\(c = \frac{\Delta Q}{m\cdot \Delta T}\)

\(c = \frac{2870\,J - 1470\,J}{(9.80\,g)\cdot (471\,^{\circ}C - 230\,^{\circ}C)}\)

\(c = 0.593\,\frac{J}{g\cdot ^{\circ}C}\)

The specific heat of the liquid phase is 0.593 joules per gram-degree Celsius.

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Answer:

PE = 137.2931 J

Explanation:

PE = 137.2931 J

Answer:

magnitude of the Coriolis acceleration is 44.235 ft/s² and the direction of the acceleration is along the axis of transmission

Explanation:

Given the data in the question;

Speed of carousel N = 24 rpm

From the diagram below, selected path direction defines the Axis of slip.

Hence, The Coriolis is acting along the axis of transmission

Now, we determine the angular speed ω of the carousel.

ω = 2πN / 60

we substitute in the value of N

ω = (2π × 24) / 60

ω = 2.5133 rad/s

Next, we convert the given velocity from mph to ft/s

we know that; 1 mph = 1.4667 ft/s

so

\(V_{slip\) = 6 mph = ( 6 × 1.4667 ) = 8.8002 ft/s

Now, we determine the magnitude of the Coriolis acceleration

\(a_c\) = 2( \(V_{slip\) × ω )

we substitute

\(a_c\) = 2( 8.8002 ft/s × 2.5133 rad/s )

\(a_c\) = 44.235 ft/s²

Hence, magnitude of the Coriolis acceleration is 44.235 ft/s² and the direction of the acceleration is along the axis of transmission

We know

\(\boxed{\sf E=hv}\)

\(\\ \sf\longmapsto E=6.63\times 10^{-34}J\times 3.6\times 10^{15}s^{-1}\)

\(\\ \sf\longmapsto E=23.86\times 10^{-19}J\)

\(\\ \sf\longmapsto E=2.38\times 10^{-18}J\)

\(\\ \sf\longmapsto E=2.4\times 10^{-18}J\)

Answer:

D!!!!!

Explanation:

Answer:

Explanation:

The magnitude of the net force acting on an object is equal to the mass of the object multiplied by the acceleration of the object, as shown in this formula. We find its magnitude using the Pythagorean Theorem or the distance formula, and we find its direction using the inverse tangent function. Given a position vector →v=⟨a,b⟩, the magnitude is found by |v|=√a2+b2. The direction is equal to the angle formed with the x-axis, or with the y-axis, depending on the application.

We will have that the measurement shown is 1.0 cm.

Answer:

32mi

Explanation:

If 1lb contains 3,500 Cal

It means the number of hours required to burn 3500cal would be;

3500/331 = 10.57hours

But a brisk walk is 3.0 mi/h,

It means a distance of 3.0 × 10.57 mi would be covered = 31.71 miles

32miles{ approximated to the nearest whole}

Note Distance = speed × time

The little number you see to the right of the symbol for an element is called a subscript. That number indicates the number of atoms of that element present in the compound.

Answer:

60km/hr due east

Explanation:

Given parameters:

Displacement = 60km East

Start time  = 10am

End time  = 11am

Unknown:

Average velocity  = ?

Solution:

The average velocity is the displacement divided by the time taken.

 For this journey, the time taken is;

              11am  -  10am  = 1hr

 So;  

 Average velocity  = \(\frac{60km}{1hr}\) = 60km/hr due east

Answer:

please follow me sir..............

Work is the energy transferred by the force.

Power is the rate of doing work.

1 KWH is the unit of energy.

Work is the amount of energy used/transferred to move an object. Its unit is J.

W = F s cos θ

W = Work

F = Force

s = Displacement

θ = Angle between direction of force and displacement

Work can be positive, negative or even zero based on the displacement of the object.

Power is the amount of energy transferred in a given amount of time. Its unit is W.

P = W / t

p = Power

W = Work

t = Time

1 KWH is the amount of energy produced by a 1 KW power source in a duration of 1 hour. It is an unit of energy.

1 KWH = 1000 W * 3600 s

1 KWH = 3600000 J / s * s

1 KWH = 3.6 * \(10^{6}\) J

1 KWH = 3.6 MJ

Therefore,

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Answer: wow that’s hard

Explanation:

The energy is lost in friction between the box and the inclined plane while pushing the box up the plane and into her truck.

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Answer:

Newton

Explanation:

Newton's are the standard unit of force.